τ=Fd
In this instance, it will
τ=Fballdball+Farmdcenter of mass
τ = 4*9.81*.7 + 4*9.81*.35 = 41.2
and both of our forces have a magnitude of 4g*cos(55), but they are located in different places.
τ = 4g*cos(55)*(.35+.7) = 23.6
The term "magnitude" refers to an object's greatest size and direction. Scalar and vector quantities both use magnitude as a common factor.
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a) You are trying to lift a woolly mammoth (5000 kg). You put a long piece of metal under the mammoth and place a large rock 2 m from the mammoth to serve as a fulcrum. You can supply about 2000 N of force. How far away from the fulcrum will you have to apply your force?
b) With the answer in part a), what is the practical issue with this answer (think about how a long thin rod behaves mechanically)? What might you do to be able to lift the mammoth, if you have friends to help? Be specific.
a. The force should be applied 5 m from the fulcrum
b. The issue is that deformation of the rod will occur.
In order to avoid this deformation, with the help of friends, the distance from the can be reduced and more force applied.
What is the principle of moments?The principle of moments states that for a system in equilibrium, the sum of the clockwise moments about a point of rotation is equal to the sum of the anticlockwise moments about that point.
Mathematically;
clockwise moments = anticlockwise momentsThe moment of a force is the product of the force and the perpendicular distance from its point of action.
Moment = force * perpendicular distanceFrom the data provided:
Let the woolly mammoth move in a clockwise direction and the applied force in an anticlockwise direction.
Let d be the perpendicular distance of the applied force from the fulcrum
5000 * 2 m = 2000 * d
d = 5 m
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which city or cites have 24 hours of daylight during the sunlight
Answer:
Abisko, Sweden
Abisko is home to the Aurora Sky Station and epicenter for aurora experiences in northern Sweden. During summer months, the sun bathes the town in up to 24 hours of sunlight per day. Between late June and mid-July, the Aurora Sky Station offers scenic chairlift rides up the mountains.
An increase in which property would cause an electromagnetic waves energy to increase ?
Answer:
wavelength.
Explanation:
Explanation: Frequency = speed of light/wavelength. The frequency of an electromagnetic wave increases as wavelength decreases
A hot air balloon weighs 3100kg. The hot air in the balloon creates an upward force of 30,000N. What is the magnitude AND direction of the acceleration of the air balloon?
The magnitude and direction of the acceleration of the air balloon, with a mass of 3100 kg and a force of 30000 N acting on it is 9.68 m/s² upward.
What is acceleration?Acceleration can be defined as the rate of change of velocity.
To calculate the magnitude and direction of the acceleration, we use the formula below.
Formula:
a = F/m............. Equation 1Where:
F = Upward forcem = Mass of the balloona = Acceleration of the ballonFrom the question,
Given:
F = 30000 Nm = 3100 kgSubstitute these values into equation 1
a = 30000/3100a = 9.68 m/s² upward.Hence, the magnitude and the acceleration of the air balloon is 9.68 m/s² upward.
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why is DE parallel to BC ?
Answer:
Given, DE is parallel to BC. From the figure, in ADE and ABC ∠ A = ∠ A (Common angle) Since, DE is parallel to BC therefore the below angles will be equal because they are corresponding angles. ⇒ ∠ D = ∠ B (Corresponding angles) and (Corresponding angles) Therefore, by AAA congruence criteria, the triangles ADE and ABC
Explanation:
A 1 kg block is placed near the top of an inclined plane that is at an angle of 30 degrees with respect to the ground, as shown above. By
correctly determining the effect of gravity, a student predicts that the acceleration of the block will be 5 m/s². After allowing the block to
slide down the inclined plane, the student finds that the acceleration is actually 4 m/s². What type of force did the student most likely not
account for when predicting the acceleration of the block, and what is the magnitude of that force?
Option b) is correct answer. b)Force of friction is approximately 1N
What is frictional force?Friction is that force which resists the relative motion of solid surfaces, fluid layers and material elements sliding against each other.
When only gravity is considered then the force on block is written as :
F= mgsin = ma
a= gsin
=g sin30
=9.8 *1/2
=4.9 m/s²
a= 5 m/s²
When friction considered is 4 m/s² that is given,
Then frictional force is in opposite direction
It is given as, F= mgsin - F
ma =mgsin- ma friction
4= 5 - a friction
afriction = 1 m/s²
Ffriction = 1N, hence option b is correct
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NEED HELP ASAP
Two objects of masses and 5 are moving toward each other along the -axis with the same initial speed. They undergo an elastic collision such that is scattered to move downward after the collision, perpendicular to its initial direction.
(a) Find the final speeds of the two objects.
(b) What is the angle at which the object with mass 5 is scattered, measured with respect to its velocity prior to the collision?
The final velocity is equal to the product of the square root of two, and the initial velocity and the angle at which the object with mass 5 is scattered, are measured with respect to its velocity prior to the collision [tex]35^o[/tex].
What is Speed?Speed is a unit used to describe how quickly an object is moving. The fact that speed is a scalar denotes that it is a measurement with a magnitude but no direction.
Something that travels at a fast rate of speed and covers a lot of distance quickly. A slow-moving object, on the other hand, travels a relatively little distance in the same length of time when moving at a low pace. An item with zero speed is completely immobile.
(a) Let the initial velocity is [tex]V_1[/tex] and the final velocity is [tex]V_2[/tex], then by applying conservation of momentum, we get the formula of
[tex]V_2 = \sqrt{2} V_1[/tex]
Therefore, the final velocity is equal to the product of the square root of two, and the initial velocity.
(b) Let the θ is the angle of scattering, then,
tanθ = [tex]V_1 / \sqrt{2} V_1[/tex]
θ = [tex]tan^-1/\sqrt{2}[/tex]
θ = [tex]35^o[/tex]
Therefore, the angle at which the object with mass 5 is scattered, measured with respect to its velocity prior to the collision is [tex]35^o[/tex].
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What is the momentum of an 8 kg bowling ball rolling at 2 m/s straight to the pins?
The momentum of an 8 kg bowling ball rolling at 2 m/s straight to the pins is 16 kg m/s.
What is momentum?As momentum depends on both velocity and the direction of the body's motion, it is quantified by "mass velocity". Since velocity is a vector and mass is a scalar, momentum is a vector quantity. It is given by the formula:
p = mv
p = 8 × 2
p = 16 kg m/s
What is velocity?Velocity can be defined as the rate at which something moves in a specific direction. as the speed of a car driving north on a highway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.
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An airplane is flying with a force of 800 N. It experiences a force of air resistance of 40 N and a wind force of 60 N, both acting in the opposite direction that the plane is traveling. What is the net force on the airplane?
A) 700 N
B) 900 N
C) 660 N
D) 840 N
According to the given statement 700 N is the net force on the airplane.
The correct option is A.
Why is it called net force?The total amount of pressures exerted on an object is referred to as its net force. The total of N pressures applied on an item is given in the equation below. The total force operating on an item, which could include a variety of forces, is known as the net force acting on an object.
Briefing:Airplane flight force (F1) equals 800 N
Which two forces are opposing each other
40 N of air resistance
Force of wind = 60 N
Net force is equal to
F1 - 40 - 60 = 800 - 100 = 700 N.
The airplane will be subject to a net force of 700 N.
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Edward swings his tennis racket to return a serve. His 10 kg racket swings forward with a speed of 8 m/s and after colliding with the tennis ball it is
slowed to 4 m/s. The 1 kg tennis ball was served toward Edward with a speed of 20 m/s. How fast was the tennis ball moving after the collision with
the racket?
The final velocity of the tennis ball after the collision is 20 m/s in opposite direction.
What is the final velocity of the tennis ball?
The final velocity of the tennis ball is determined by applying the principle of conservation of linear momentum as shown below.
Mathematically, the formula is given as;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the racket = 10 kgu₁ is the initial velocity of the racket = 8 m/sm₂ is the mass of the tennis ball = 1 kgu₂ is the initial velocity of the tennis = 20 m/sv₁ is the final velocity of the racket = 4 m/sv₂ is the final velocity of the tennis ball = ?(10 x 8) + (-20)(1) = 10(4) + (1)v₂
80 - 20 = 40 + v₂
80 - 20 - 40 = v₂
20 m/s = v₂
Thus, the final velocity of the tennis ball is in opposite direction.
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A toy gun works by compressing a spring with a constant of 350.N/m a distance of 0.0300m. How high can it shoot a 0.0125kg toy bullet?
The height to which the toy gun can shoot a 0.0125 Kg toy bullet is 1.29 m
How to determin the heightWe'll begin by determine the energy of the spring. This can be obtained as follow:
Spring constant (K) = 350 N/mCompression (e) = 0.0300 mEnergy (E) =?E = ½Ke²
E = ½ × 350 × 0.03²
E = 175 × 0.0009
E = 0.1575 J
Finally, we shall determine the height. This is illustrated below:
Mass (m) = 0.0125 KgEnergy (E) = 0.1575 JAcceleration due to gravity (g) = 9.8 m/s² Height (h) = ?E = mgh
0.1575 = 0.0125 × 9.8 × h
0.1575 = 0.1225 × h
Divide both sides by 0.1225
h = 0.1575 / 0.1225
h = 1.29 m
Thus, the height is 1.29 m
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7. Using the idea of Impulse, explain why a field goal kicker should 'kick through the ball', meaning extend their foot
as high up as possible at the end of the kick.
Answer:
Impulse is the amount of force put on an object in a certain amount of time. Therefore when kicking a ball and "kicking through it" it extends the period of time this force is applied in turn increasing its impulse. Impulse is equal to change in momentum. momentum is equal to mass times velocity and since mass of the ball doesn't change therefore the velocity is increased and performance increased.
A car is travelling at 30m/s. Suddenly, the driver sees a danger ahead and decides to do an emergency stop. The driver's reaction time is 0.6 s. Calculate how far the car travels before the driver starts pressing the brake pedal.
Answer:
Explanation:
Given:
V =30 m/s
t = 0.6 s
_________
D - ?
Distance:
D = V·t = 30·0.6 = 18 m
Answer:
The car travels 18 meters before the driver starts pressing the brake pedal.
Given:
Speed of the car = 30 m/s
Reaction time = 0.6 s
To Find:
Distance travelled by the car before the driver starts pressing the brake pedal.
Formula:
[tex] \boxed{ \rm Distance= Speed \times Time}[/tex]
By substituting the value in the formula we get:
[tex]Distance= 30 \times 0.6 \\ \\ = 18 \: m[/tex]
4. The angle of projection at which a projectile attains the minimum range is A. 45⁰ B. 60⁰ C. 76⁰ D. 90⁰ E. None
Explanation:
Free Solutions to GR BATHLA & SONS BIOLOGY (HINGLISH) Class 12 book Chapters, Questions, Answers and Solutions 2022
The "Open" sign at your local deli flashes on and off all day long at 2.0 s intervals. The aliens spying on you from space are watching the same neon sign you are but they are moving towards Earth at a speed of 0.90c. How long is the interval flash (in s) for the aliens?
Answer:
Interval t = 0.87 s
Explanation:
Given:
t₀ = 2.0 s
V = 0.90c
_________
t - ?
Relativistic clock slowdown:
[tex]t = t_0\cdot \sqrt{1-(\frac{V}{c} )^2} \\[/tex]
[tex]t = 2\cdot\sqrt{1 - (\frac{0.90c}{c})^2 } = 2\cdot\sqrt{1 - 0,90^2}= 2\cdot\sqrt{0.19} = 0.87 s[/tex]
When the height of the cylinder increased by a factor of 5, from 100 m to 500 m, what happened to the cylinder's
gravitational potential energy?
O It decreased by a factor of 10.
O It decreased by a factor of 5.
O It increased by a factor of 5.
OIt increased by a factor of 10.
Option c) Increase by 5 times
The cylinder's gravitational potential energy increases 5 times
What is gravitational potential energy ?
Gravitational energy or gravitational potential energy is the potential energy that an object with mass has with respect to another object with mass due to gravity. It is the potential energy associated with the gravitational field that is released (converted into kinetic energy) as objects fall toward each other.
Objects have gravitational potential energy if they are at altitudes above (or below) zero altitude. A body has elastic potential energy if it is in a non-equilibrium position on an elastic medium.
Formula for calculating gravitational potential energy
gravity P.E = m g h
m = mass
g = gravitational acceleration = 9.81 m/s²
h = height
GPE' = new gravity P.E
m g h ' / m g h = GPE' / GPE
mg500/mg100 = GPE' / GPE
deletion mg
500/100 = GPE' / GPE
5 = GPE' / GPE
GPE' = 5GPE
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A Carnot engine performs work at the rate of 510 kW while using 930 kcal of heat per second.
a) If the temperature of the heat source is 600 ∘C , at what temperature is the waste heat exhausted?
The temperature of waste heat exhausted is 483.83 °C.
A Carnot heat engine is a heat engine that operates at the Carnot cycle. The simple version of this engine turned into evolved by Nicolas Léonard Sadi Carnot in 1824.
The Carnot engine is a theoretical thermodynamic cycle proposed by means of Leonard Carnot. It estimates the maximum possible efficiency that a heat engine all through the conversion manner of heat into work and, conversely, operating between reservoirs can possess.
calculation:-
1 kcal = 4.186 k J.
So the engine efficiency eta = 510/930 × 4.186 = 0.13305
T hot = 600 + 273.15 = 873.15 K
From the Carnot equation = (T hot-T cold) /T Hot,
so
T cold = T hot(1-eta)
= 873.15 × (1-0.13305) =756.98 K
= 756.98 K = 483.83 °C
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____is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid____
to a temperature below___F.
Impact ice is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid water to a temperature below 32°F.
What is meant by impact ice ?Impact ice, a kind of induction icing, may form wherever that the temperature is close to or below zero degrees Celsius. Even on a fuel-injected engine, impact ice can clog the air filter and prevent the engine from getting the necessary air for combustion. As instructed by your POH/AFM, turn on alternative air or carburetor heat if you detect impact ice.Carburetor icing (ice that forms in the carburetor) happens when the venturi's decline in air pressure causes the moisture-filled air to cool quickly or as a result of gasoline evaporation.The ensuing ice buildup in the intake tube of the carburetor can significantly lower engine performance. In extreme circumstances, the intake flow might be so low that the engine can stall.Learn more about Liquid water refer to :
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An experimenter would like to construct a 99% confidence interval with a width at most 0. 5 for the average resistance of a segment of copper cable of a certain length. If the experimenter knows that the standard deviation of such resistances is 1. 55. How big a sample should the experimenter take from the population? what happens if the standard deviation and the width of the confidence interval are both doubled?.
Sample should be 256 , which the experimenter can take from the population . If the standard deviation and the width of the confidence interval are both doubled , the size will be same .
What is resistance ?
Resistance is the resistance that a substance offers to the flow of electric current. Represented by a capital R. The standard unit of resistance is the ohm, sometimes written as a word or represented by the Greek letter omega. If a current of 1 ampere flows through a component with a potential difference (voltage) of 1 volt, the resistance of that component is 1 ohm. The electrical resistance per unit length, area, or volume of matter is known as resistance. Resistance values are often given in ohms per kilometer of copper and aluminum wire.
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A copper (Young's modulus 1.1 x 1011 N/m) cylinder and a brass (Young's modulus 9.0 x 100 N/m) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.19 cm. A compressive force of F-5000 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Let xc for the copper cylinder, xb for the brass cylinder.
The total compression will be xc + xb
Young modulus Y of a material is given Y = FL/ADL
A = area
DL = change of length
L = original length
F = force
so here we apply the same Force for both copper and brass
so F/A = 9200/(3.14 * 0.0022* 0.0022)
F/A = 695.35 MN/m^2
For the copper cylinder:
strain = 695.35e6/(1.1e11 ) = 6.32 *10^-3
xc = strain*length = 3*6.32 e -3 = 18.96
For the brass cylinder
strain =695.35 e6/ 9.e 10 = 7.77 *10^-3
xb = 31.8
Total change in length = xb + xc = 50.76 *10^-3 cm.
The stack decreases from bottom to top when smaller items need to be removed from the stack before moving new items. Otherwise, it increases from bottom to top. For example, a mono-decreasing stack. Every time a function is called, the machine allocates stack space for that function. When a new local variable is declared, more stack space is allocated for this function to store the variable. Such allocations keep the stack low.
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An 80-cm-long, 1. 0-mm-diameter steel guitar string must be tightened to a tension of 2000 n by turning the tuning screws.
The correct answer is there is a stretch in the string 0.010m.
The string is and it is long.
The string's radius is
The string's tension is
the Young's modulus
Stretching out of the string
Young's modulus can be found in.
The string is longer than usual.
Consequently, the string gets shortened.
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Two insects A and B fly in space with a uniform velocity VA= i+4j+3k and VB =4i+2j-4k in m/s. With respect to a stationary observer at the origin. Show the insect fly at right angles to each other and determine their distance apart after 50
Distance travelled by insects A and B is respectively 50√26 unit and 300 unit.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given parameters:
Uniform velocity of insect A: [tex]\bold{v_A}[/tex] = i+4j+3k unit.
Uniform velocity of insect B: [tex]\bold{v_B}[/tex] = 4i+2j-4k unit.
Now dot product of two velocity vector is:
[tex]\bold{v_A}[/tex]·[tex]\bold{v_B}[/tex] = 50 (i+4j+3k)·50( 4i+2j-4k).
= 2500(4 + 4×2 + 3×(-4))
= 0.
Hence, the velocity vectors of two insects are perpendicular to each other. So, the insect fly at right angles to each other.
After time t = 50 unit, Position of insect A: [tex]\bold{X_A}[/tex] = time* velocity
= 50 (i+4j+3k) unit.
After time t = 50 unit, Position of insect B: [tex]\bold{X_B}[/tex] = time* velocity
= 50( 4i+2j-4k).
So, After time t = 50 unit, insect A travels a distance = 50 ×√(1²+4²+3²) = 50√26 unit.
After time t = 50 unit, insect B travels a distance = 50 ×√(4²+2²+(-4)²) = 300 unit.
Hence, distance travelled by insects A and B is respectively 50√26 unit and 300 unit.
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Which rule always applies when drawing a trend line for a set of data points?
The trend line always connects the first and last data points
The trend line connects all of the data points dot-to-dot
The trend line should follow the overall pattern of the data
The trend line is always a straight line
The rule that applies when drawing a trend line for a set of data points is "the trend line is always a straight line".
Option D is correct answer.
What is a trend line?
A trend line is a straight line drawn over pivot highs or under pivot lows to show the prevailing direction of price.
There are about three rules to follow when drawing a trend line and they include the following;
to draw a trend line in an up trend, two lows must be connected by a straight line. to draw a trend line in a down trend line, two highs must be connected by a straight line. a trend line should be connected by at least three highs or lows to make it valid.Thus, we can conclude that, the basic rule or constant rule that must apply to a trend line is a straight line connecting two lows or two highs for down trend and up trend respectively.
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name two different objects you could use to light a room if you have a power cut. for each object describe the energy transfer and changes to energy stores that occur when it lights up the room
Answer:
candle and hand torch
Explanation:
we can find a light energy and heat energy from the candle but only light energy for hand torch
Based on the nasa institute for space studies climate model, observed temperature increases are best represented when it includes the influences of.
Using information from the NASA Institute for Space Studies The best representation of observed temperature increases in climate models is when orbital movements are taken into account.
solar variationshuman-made aerosolsgrowth in greenhouse gas emissionsgrowth in greenhouse gas emissionsWhat is climate model?
Since 1960, scientists have been aware that people are increasing the atmospheric concentration of chemicals that trap heat.Climate changes will worsen if greenhouse gas emissions continue. A warmer atmosphere, a warmer and more acidic ocean, higher sea levels, and more significant changes in precipitation patterns are anticipated in the future.Climate prediction models' fundamental finding is that human activity enhances global warming and boosts the average global temperature.Hence solar variations, human-made aerosols, growth in greenhouse gas emissions, growth in greenhouse gas emissions is a correct answer.
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6. A constant net force acts on a magnitude of all of the following quantities pertaining to
the body EXCEPT
(A) Acceleration
(B) Kinetic Energy
(C) Momentum
(D) Speed
(E) Velocity
In the periodic table in the image below, which of the following atoms is
classified as a metalloid?
OA. Fluorine (F)
OB. Antimony (Sb)
OC. Cadmium (Cd)
OD. Radon (Rn)
Answer:
OB
Explanation:
Antimony is a chemical element with as symbol Sb and atomic number 51
how to calculate final speed when the mass is 40,000kg height id 2.5km and 500,000N of force
The final speed when the mass is 40,000kg height is 2.5km and 500,000N of force is 176.8 m / s
According to Newton's second law of motion,
F = m a
F = Force
m = Mass
a = Acceleration
m = 40000 kg
F = 500000 N
a = F / m
a = 500000 / 40000
a = 12.5 m / s²
a = v / t
v = d / t
v = Velocity
t = Time
d = Distance
d = 2.5 km = 2500 m
a = d / t²
12.5 = 2500 / t²
t² = 200
t = 14.14 s
v = 2500 / 14.14
v = 176.8 m / s
Therefore, the final speed is 176.8 m / s
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a 4500 kilogram truck travels in a straight line at 10 ms what is its momentum
40,000 kg m/s will be the momentum if the truck at a truck mass of 4500kg and velocity of 10 m/s.
Given mass of a truck = 4000 kg
truck mass = 4 grams
velocity = 10 m/s
The formula of momentum will be:
p = mv
where, p = momentum
m = truck mass
v = velocity
substituting the values, we get:
momentum = 4000 × 10
momentum = 40000 kg m/s
Thus the momentum of the truck is 40,000 kg m/s
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A rightward force of 12.0 N is applied to a 2.0-kg object to accelerate it across a horizontal
surface. The object encounters 8.0 N of friction. What is the object's acceleration?
Answer:
below
Explanation:
Net accelerating force becomes 12-8 = 4 N
F = ma
4 = 2 * a
a = 2 m/s^2
The object encounters 8.0 N of friction. The object's acceleration is 2 m/s².
What is acceleration?Acceleration is the rate at which the speed and direction of a moving object change over time. A point or object moving straight ahead is accelerated when it accelerates or decelerates.
Even if the speed is constant, the motion on a circle accelerates because the direction is constantly shifting.
The word "force" has a specific meaning in science. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains."
Net accelerating force becomes 12 - 8 = 4 N
The formula for force is
Force = mass x acceleration
F = ma
4 = 2 x a
a = 2 m/s²
Therefore, the object's acceleration is 2 m/s².
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