Answer:
a) Magnitude = 1.03 m/s², Direction: south
b) [tex]V_{f} = 8.16 m/s [/tex]
Explanation:
a) The magnitude and direction of the acceleration can be calculated using the following equation:
[tex] V_{f} = V_{0} + at [/tex] (1)
Where:
[tex]V_{f}[/tex]: is the final speed = 9.40 m/s
[tex]V_{0}[/tex]: is the initial speed = 13.0 m/s
t: is the time = 3.50 s
Solving equation (1) for a, we have:
[tex] a = \frac{V_{f} - V_{0}}{t} = \frac{9.40 m/s - 13.0 m/s}{3.50 s} = -1.03 m/s^{2} [/tex]
Hence, the magnitude of the acceleration is 1.03 m/s² and the direction of the bird's acceleration is the opposite of the initial velocity direction, which means that the bird is decelerating.
b) The final velocity of the bird can be found using the same equation 1:
[tex] V_{f} = V_{0} + at [/tex]
[tex] V_{f} = 13.0 m/s + (-1.03 m/s^{2})*(3.50 s + 1.20 s) = 8.16 m/s [/tex]
Therefore, the bird’s velocity after an additional 1.20 s has elapsed is 8.16 m/s.
I hope it helps you!
Convert 47 meters to gigameters
Answer: 4.7× 10-8 gigameter.
Exgiga meter. Hope this helps :)
Rank the below combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the right as positive and forces pointing to the left as negative.1.a. q1= +1nCb. q2= -1nCc, q3= -1nC2.a. q1= -1nCb. q2= +1nCc, q3= +1nC3. a. q1= +1nCb. q2= +1nCc, q3= +1nC4. a. q1= +1nCb. q2= +1nCc, q3= -1nC5. a. q1= -1nCb. q2= -1nCc, q3= -1nC6. a. q1= +1nCb. q2= -1nCc, q3= +1nC
Answer:
Explanation:
The electric charges are placed on a line .
1 a ) q1= +1 nC q2= -1 nC q3= -1 nC
here q₁ will be attracted by both q₂ and q₃ so net force on q₁ will be positive
2 a ) q1= -1 nC q2= +1 nC q3= + 1 nC
here q₁ will be attracted by both q₂ and q₃ so net force on q₁ will be positive
3 a ) q1= +1 nC q2= +1 nC q3= + 1 nC
here q₁ will be repelled by both q₂ and q₃ so net force on q₁ will be negative.
4 a ) q1= +1 nC q2= +1 nC q3= - 1 nC
q2 will repel and q3 will attract so net force will be towards left but it will be weakened .
5 a ) q1= -1 nC q2= -1 nC q3= - 1 nC
Both q₁ and q₂ will repel so net force will be towards left and negative .
6 a ) q1= +1 nC q2= -1 nC q3= + 1 nC
q2 will attract and q3 will repel so net force will be towards right but it will be weakened . It will be positive .
Largest positive force to lowest positive force
2 a ) = 1 a ) > 6 a )
Largest negative force to lowest positive force
5a )= 3 a ) > 4a )
What forces are acting on a book sitting on a table? Are action - reaction force involved in this situation? Newton's third law
Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.
Explanation: I think I'm very stupid
Specialized visual receptors that assist mostly in nighttime vision are __________. A. cones B. rods C. fovea D. optic disks Please select the best answer from the choices provided A B C D
Answer:
B
Explanation:
EDGE 2020
The rod photoreceptor cell type, which is found in the retina, transmits low-light vision and is primarily in charge of the neural transmission of night vision. Thus, option B is correct.
What visual receptors that assist mostly in nighttime vision?We can see at night thanks to rods, and we can see color during the day thanks to cones. Although daylight vision is far more important for us, the topic of why there are roughly 20 times more rods than cones in a human retina has typically been met with a shrug.
Rods function in extremely dim lighting. Because just some light particles (photons) may trigger a rod, we employ these for night vision. Because rods hinder color vision, we experience a grayscale world at night. More than 100 million rod cells make up the human eye.
Therefore, The retina's rod photoreceptor cell type conveys vision in low light and is principally in charge of the neuronal activity of night vision.
Learn more about vision here:
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If vector A has components Ax and Ay and makes an angle θ with the +x axis, thena. Ax +Ay (where A is magnitude of A)b. θ= Ay/Axc. Cosθ= Ax/ √ (Ax^2+ Ay^2)d. Tanθ= Ax/Ay
Answer:
c. Cos θ = [tex]A_{x}[/tex] / [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]
Explanation:
A vector is any quantity that has both magnitude and direction. The given vector A has components [tex]A_{x}[/tex] and [tex]A_{y}[/tex], and makes angle θ with +x axis.
Thus;
Resultant of the vector, A = [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]
Therefore, the components, angle and resultant of vector A can be represented in magnitude and direction by the three sides of a right angled triangle.
Applying the appropriate trigonometric function to the triangle for vector A, we have;
Cos θ = [tex]A_{x}[/tex] ÷ [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]
⇒ Cos θ = [tex]A_{x}[/tex] / [tex]\sqrt{(A_{x} ^{2} + A_{y} ^{2}) }[/tex]
The correct option is C.
Question 9 of 10
How does Newton's third law explain how a rocket is launched upward?
A. The force of Earth's gravity balances with the force of the rocket
engines.
B. The rocket will remain motionless on the launchpad until an
unbalanced force is applied.
C. The mass of the rocket determines how much force is needed to
move it into orbit.
OD. The force it exerts on its exhaust gases is equal to the force the
exhaust gases exert on the rocket.
Answer: C “The force it exerts on its exhaust gases is equal to the force the exhaust gases exert on the rocket.”
You are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distance between the two of you remains the same, so you deduce that you are walking at the same speed of 1.25 m/s. Suddenly, you notice a wallet on the ground. You pick it up and realize it belongs to the person in front of you. To catch up, you start running at a speed of 2.75 m/s. It takes you 12.5 s to catch up and deliver the lost wallet. How far ahead of you was this person when you started running
Answer:
18.8m
Explanation:
This implies calculating the relative speed first then find the distance d
So
relative speed = 2.75- 1.25 = 1.5 m/s
So assume the distance between them to be say d
so, d/1.5= 12.5
d = 18.8m
5 problem associated with PopulationCensus
Answer:
1. High Illiteracy Rate in a Nation has a Negative Impact on the Conducting of Census
2.Corruption Interferes with Census
3.Traditional and Religious Beliefs can Interfere with the Census Exercise
4.insufficient and Ineffective Census Educational Campaign
5.Insufficient Census Experts
Explanation:
An observer in frame S sees lightning simultaneously strike two points 100 m apart. The first strike occurs at xx1 = yy1 = zz1 = tt1 = 0 and the second at xx2 = 100 mm, yy2 = zz2 = tt2 = 0. (a) What are the coordinates of these two events in a frame S’ moving in the standard configuration (motion along the common xx − xx’ axis) at 0.70c relative to S? (b) How far apart are the events in S’? (c) Are the events simultaneous in S’? If not, what is the difference in time between the events, and which event occurs first?
Answer:
a) 0, = -0.33 us
b) 140m
c) No, The event are not simultaneous i.e they did not occur at the same time, the second even (-0.33 usec) occurs 0.33 usec earlier than the first event.
Explanation:
a)
the lorentz factor expression is written as;
y = 1₀ / √(1 - (v²/c²))
where v is the relative speed of an observer and c is the speed of light
so we were given that relative speed to be o.7c
therefore
y = 1 / √(1 - ((0.7c)² / c²))
y = 1 / √(1 - (0.49c² / c²))
y = 1 / √(1 - 0.49)
y = 1 / 0.7141
y = 1.4
1 - the coordinates of the first event, the s' frame of reference is,
x1 ' = y(x1 - vt1) = 0
y1 ' = y1, z1' = z1 and
t1 ' = y [t1 - v/c²x1]
= 0
2 - the coordinates of the second event, the s ' frame of reference is'
x2 ' = y(x2-vt2)
= 1.4(100m - 0)
= 140m
y2 ' = y2, z2 ' = z2
t2 ' = y [ t2 - v/c²x2 ]
= 1.4 [ 0 - 0.7c/c²(100) ]
using speed of light c as 3*10^8
1.4 [ 0 - (0.7*3*10^8) / (3*10^8)²(100) ]
= -0.33 us
b)
distance between
delltaX' = X2' - X1'
= 140m - 0
= 140m
c)
No, The event are not simultaneous i.e they did not occur at the same time.
the second even (-0.33 us) occurs 0.33 us earlier than the first event.
How could you create an investigation to determine the pitch of this wave?
Answer:
In order to make a sound wave have a higher pitch you increase the frequency.
In order to increase the volume of a sound wave, you have to increase the amplitude.
Hope this helps!
Match each principle with the phrase that best defines it.
the federal system
Government power is limited and based
on popular vote
constitutional democracy
Power is divided among legislative,
executive, and judicial branches,
branches of government
Power is divided between state, local,
and federal governments
Answer:
1: 2
2: 1
3: 3
Explanation:
Answer:Federal System->Power Is divides between state, local etc.
Branches of government-> Power is divided among legislative, executive
Constitutional democracy-> Government power
Explanation:
A charged object is immersed in a 17 N/C E-field. Then the total charge on the object increases by a factor of 22 over 10 s. During this time, the electrostatic force on the object remains constant. Determine the magnitude of the E-field after the total charge has changed.
Answer:
Eu = 0.65 N/C (Approx)
Explanation:
Given:
Time taken = 10 sec
E-field (Initial)(Ei) = 17 N/C
Find:
E-field (Final)
Assume;
Initial charge = Qi
Initial immersed force (Fi) = QiE
Fi = Qi(17)
After 10 sec
Fu = (26)(Qi)(Eu)
So
Fi = Fu
So,
Qi(17) = (26)(Qi)(Eu)
Eu = 17 / 26
Eu = 0.65 N/C (Approx)
Given :
Initial electric field , [tex]E_i=17\ N/C[/tex] .
The total charge on the object increases by a factor of 22 .
To Find :
The magnitude of the E-field after the total charge has changed .
Solution :
Let , initial charge is q .
Therefore , final charge is 22q .
Electrostatic force F is given by :
[tex]F=qE[/tex]
It is also given that the force remains constant .
Therefore ,
[tex]F_i=F_f\\\\qE_i=22qE_f\\\\E_f=\dfrac{E_i}{22}\\\\E_f=\dfrac{17}{22}\ N/C\\\\E_f=0.78\ N/C[/tex]
Hence , this is the required solution .
How long is a bus route across a small town
Answer:
4 kilometers
Explanation:
Why are chemical processes unable to produce the same amount of energy flowing out of the sun as nuclear fusion?
Answer:
Explanation:
One of the major differences between nuclear reactions and chemical reactions is that nuclear reactions involve larger amount of energy than chemical energy. This is because the force between the protons and neutrons in the nucleus of an atom is much higher than the force of attraction between electrons and the positively charged nucleus, hence nuclear reactions involves/requires a larger amount of energy (because it's reactions involve the nucleus) than chemical reactions (because it's reactions involve the electrons).
Thus, during nuclear fusion, two light nuclei are bombarded against one another to produce a larger/heavier nuclei with the release of large amount of energy (because the forces between the protons and neutrons are much higher) unlike when two atoms/molecules are chemically combined together to form a new molecule with the rearrangement of electrons in the valence shells of the participating molecules.
sovle it please help me
Explanation:
(a)
F = (GM1M2)/r²
F = (6.7 X 10^-11 x 30.3 x 40.17)/0.5²
F = 326.197 x 10^-⁹N
(b)
F =750N
G = 6.7 x 10^-11
M1 = 2050kg
r = 70.3m
M2 = ?
F = (GM1M2)/r²
F x r² = GM1M2
(F x r²)/GM1 = M2
M2 = (750 x 70.3²)/(6.7 x 10^-11 x 2050)
M2 = 26.99kg
Which answer best explains why a physicist would study the heat given off by the Sun? O O A. Heat is a form of energy. B. The Sun is an interesting shape. OPlant cells need heat from the Sun. OPhysics is the study of astronomy.
Can someone help me please
Answer:
A. Heat is a form of energy.
Explanation:
The Sun emits heat, which is a form of energy. This heat energy is supplied to the Earth by the sun, when the solar energy is converted to heat energy. The study of heat energy and its conversion from one form to another is a branch of physics called THERMODYNAMICS.
Hence, a physicists will be interested in studying the heat given off by the sun because it is one of the several forms of energy.
Answer:
A. Heat is a form of energy.
Explanation:
What are the steps to the scientific method
Answer:
question, report, observe, research, draw conclusions, hypothesize, test hypothesis, experiment
Explanation:
You walk to the corner store at 2 m/s for a total time of 76 seconds. What is the distance to the store?
Answer:
152.
Explanation:
2 x 76 = 152
bruh its not that hard
Answer:
152 m
Explanation:
Distance = Speed x Time
[tex]2 \times 76 \\ 152[/tex]
Thus the distance is equal to 152 m.
a light bulb is a kind of lever is the statement true or false
Answer:
False
Explanation:
It would be a screw
PLZZ HELP:) When a star is moving away from Earth, does the color of the star actually change? Explain
Answer:
Yes.
Explanation:
If a star is moving away from earth, it's color will shift to in the visible spectrum will turn to Red.
If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d = A + Bt^2, the SI units of A and B must be:_______
Answer:
The SI units of the “A” is m (meters)
The SI units of the “B” is m/s^2
Explanation:
Given the distance = d meters.
Time taken to travel = t (seconds)
Function of the distance, d = A + Bt^2
Now we have given the above information and from the given distance function, we have to find the SI units of the A and B. Here, below are the SI units.
Thus, the SI units of the “A” is = m (meters)
The SI units of the “B” is = m/s^2
a plane being propelled due east is actually moving at 225mph an angle of 40 degrees north of east, how fast is the crosswind that is blowing due north (relative the ground?
Answer:
144.63 mph
Explanation:
225 sin (40)
how does thermal energy impact enthalpy
Answer:
The concentrations of the reactants and the products. The temperature of the system. The partial pressures of the gases involved (if any)
Explanation:
Point charges q1=− 4.40 nC and q2=+ 4.40 nC are separated by distance 3.10 mm , forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle of 36.4° with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 8.00×10^−9 N⋅m ?
Answer:
988.39 N/C
Explanation:
First, we start by finding the magnitude of the electric dipole moment, as it's going to be needed
p = 4.40*10^-9 * 3.10*10^-3
p = 1.364*10^-11 Cm
The charges are in a uniform electric field E whose direction makes an angle of 36.4° with the line connecting the charges.
Magnitude of torque exerted on the dipole,
t = 8.0×10−9 N.m
pEsinO = t, making E subject of formula
E = t / psinO
E = 8.0*10^-9/1.364*10^-11 (sin36.4)
E = 8.0*10^-9/1.364*10^-11 * (0.5934)
E = 8.0*10^-9 / 8.094*10^-12
E = 988.39 N/C
the magnitude of this field is E = 988.39 N/C
missile is fired from ground level with an initial velocity of v(0) = 1000, 1400, 368 measured in ft/sec, with the engine shutting off just after launch. If the only external force acting on the missile is the gravitational force, find the trajectory of the missile. (Use g = 32 ft/sec2. Your instructors prefer angle bracket notation < > for vectors.)
Answer:
the trajectory for the missile [tex]\mathbf{r(t) = \langle1000t,1400t, 368t -16t^2 \rangle}[/tex]
the downrange of the missile R = 39570.6973 ft
Explanation:
Suppose the initial velocity v(0) = <1000, 1400, 368 > ft/sec
The single force which is acting over the missle is the gravitational force.
a (t) = <0, 0, -32> ft/sec²
We are to determine the trajectory and the downrange for the missle
Consider the motion of a given object r(t) to be:
[tex]r(t) = v_it + \dfrac{1}{2}at^2[/tex]
[tex]r(t) = \langle1000,1400,368 \rangle t + \dfrac{1}{2} \langle 0,0, -32\rangle t^2[/tex]
[tex]r(t) = \langle1000t,1400t,368t \rangle + \langle 0,0, -16 t^2 \rangle[/tex]
[tex]r(t) = \langle1000t,1400t, 368t -16t^2 \rangle[/tex]
Thus, the trajectory for the missile [tex]\mathbf{r(t) = \langle1000t,1400t, 368t -16t^2 \rangle}[/tex]
To determine the downrange of the missile,
[tex]v(0) = \langle 1000,1400,368 \rangle[/tex]
where;
the horizontal vel. of the missle [tex]v_h= \sqrt{1000^2+1400^2}[/tex]
= 1720.4651 ft/s
the vertical vel. of the missile is [tex]v_v = 368 \ ft/s[/tex]
The time required to reach the ground [tex]t =\dfrac{2 \times v_v}{g}[/tex]
[tex]t =\dfrac{2 \times 368}{32}[/tex]
t = 23 sec
Finally, the downrange of the missile [tex]R = v_h \times t[/tex]
R = 1720.4651 × 23
R = 39570.6973 ft
The trajectory of the missile as a function of time is obtained as
[tex]r(t)= <100t, 1400t, 368t-16t^2>[/tex].
Projectile MotionGiven that the initial velocity is;
[tex]v(0) = <1000, 1400, 368>\,ft/sec[/tex]
The acceleration of the missile is provided by the gravitational force.
[tex]a = g = <0, 0, -32>\,ft/sec^2[/tex]
The trajectory of the object at time 't' is given by;
[tex]r(t)=v(0)\,t+\frac{1}{2} at^2= <100, 1400, 368>t\,+\frac{1}{2} <0, 0, -32>t^2[/tex]
[tex]\implies r(t)= <100t, 1400t, 368t-16t^2>[/tex]
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A model airplane is flying North with a velocity of 15 m/s. A strong wind is blowing East at 12 m/s
Answer:
19.21 m/s^2
Explanation:
Given that a model airplane is flying North with a velocity of 15 m/s. A strong wind is blowing East at 12 m/s.
The resultant velocity can be calculated by using pythagorean theorem.
Velocity = sqrt( 15^2 + 12^2 )
Velocity = sqrt ( 225 + 144 )
Velocity = sqrt ( 369 )
Velocity = 19.21 m/s^2
Therefore, the plane will be travelling at velocity of 19.21 m/s^2
What is the source of gravity at the heart of many galaxies?
a. dark matter
b. fusion
c. black holes
d. neutrinos
What is the speed of an airplane that travels 4500 miles in 6 hours?
Answer:
750 miles / hour
Explanation:
velocity = distance / time
= 4500 miles / 6 hours
= 750 miles / hour
Given:-
Speed of the airplane (s) = 4500 miles Time taken (t) = 6 hTo Find: Speed (v) of the particle (airplane).
We know,
s = vt
where,
s = Distance,v = Speed &t = Time taken.Similarly,
v = s/t
→ v = (4500 miles)/(6 hours)
→ v = 750 miles/hour ...(Ans.)
PLEASE HELP!! Solve for Y 12=2xY
Answer:
The answer is 6, because 2×y is equal to 12.
Jesseca Kusher wants to manufacture and sell her new material. Help her marketing campaign by providing a catchy name for the material, an advertising slogan, and a simple picture for the product label. For the name and slogan, use the drawing tool’s text box feature. lol
Answer: the picture is the answer
Explanation:
