if f(x) = 4x - 3 and g(x) = x + 4, find (f - g)(x)
Answer:
3x - 7
Step-by-step explanation:
This questions asks about the subtraction of functions. To find the answer, we can subtract the same way we would subtract polynomials.
Subtracting Expressions
First, set up the subtraction problem by taking the expression for f(x) and subtracting the expression equal to g(x) from it.
This looks like:
(4x - 3) - (x + 4)Next, distribute the negative to the second binomial
4x - 3 - x - 4Then, combine like terms
3x - 7Since we are not given a x-value, this is the final answer.
Solving for an X-Value
If you are given an x-value, the best way to solve the equation is to first solve each function and then subtract.
For example, using the same rules for each function let's solve (f-g)(2).
First, solve for f(2) and g(2)
f(2) = 5g(2) = 6Then, subtract the 2 values
5 - 6 = -1Analyze the diagram below and answer the question that follows
How many faces does the solid have?
A. 4
B. 5
C. 6
D. 8
Answer:
C.6
Step-by-step explanation:
3x - [2 +3 (2-x) = S-(3-X)
Equation:
[tex]5 + 5 = 5x + 5 - 2[/tex]
Solve for x.
Answer:
x = [tex]\frac{7}{5}[/tex]
Step-by-step explanation:
To solve for x, we need to isolate it [get it alone on one side]
We should start by simplifying (combining the like-terms of our equation):
5 + 5 = 5x + 5 - 2
10 = 5x + 3
- 3 - 3 (subtract 3 from both sides to isolate x)
7 = 5x
÷5 ÷5 (divide both sides by 5 to find "1"x)
[tex]\frac{7}{5}=x[/tex]
So, x = [tex]\frac{7}{5}[/tex]
(x = 7/5)
hope this helps!!
5 + 5 = 5x + 5 - 2
Answer :
[tex]x = \frac{7}{5} [/tex]
Step-by-step explanation:
5 + 5 = 5x + 5 - 2
10 = 5x + 3
Take 3 to the other side
10 - 3 = 5x
7 = 5x
[tex] \frac{7}{5} = x[/tex]
or[tex]x = \frac{7}{5} [/tex]
The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. It goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4). Which graph represents g(x)? On a coordinate plane, a parabola opens up. It goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10). On a coordinate plane, a parabola opens up. It goes through (2, 8), has a vertex at (5, negative 11), and goes through (8, 8). On a coordinate plane, a parabola opens up. It goes through (negative 8, 10), has a vertex at (negative 5, 1), and goes through (negative 2, 10). On a coordinate plane, a parabola opens up. It goes through (negative 8, 8), has a vertex at (negative 5, negative 11), and goes through (negative 2, 8).
The transformation of a function may involve any change. When the graph of f(x) is transformed into 5 units to the right and one unit up, then the function g(x) is obtained.
How does the transformation of a function happen?The transformation of a function may involve any change.
Usually, these can be shifted horizontally (by transforming inputs) or vertically (by transforming output), stretched (multiplying outputs or inputs) etc.
If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:
Horizontal shift (also called phase shift):
Left shift by c units, y=f(x+c) (same output, but c units earlier)Right shift by c units, y=f(x-c)(same output, but c units late)Vertical shift
Up by d units: y = f(x) + dDown by d units: y = f(x) - dStretching:
Vertical stretch by a factor k: y = k \times f(x)Horizontal stretch by a factor k: y = f(x/k)Given the function f(x)=x², which is transformed to g(x)=(x-5)²+1, therefore, the graph of both the functions are given below.
When the graph of f(x) is transformed into 5 units to the right and one unit up, then the function g(x) is obtained.
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again help me pease
Answer:
See below ~
Step-by-step explanation:
1) a) 50 km / 2 h
⇒ 25 km/h
b) 540 kg / 3 days
⇒ 180 kg/day
c) 125 m / 5 min.
⇒ 25 m/min.
A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate…
a) 50km/2h
=> 25 kilometers per hour
b) 540kg/3d
=> 180 kilogram per day
c) 125m/5min
=> 25 meter per minute
Whats the answer… also thats1/3
The volume of a cubical box is
54.872 cm3. The length of the side of
the box is
(b) 3.6 cm
(c) 3.8 cm
(a) 3.4 cm
(d) 3.2 cm
The sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.
What is a cube?It is defined as three-dimensional geometry that has six square faces and eight vertices.
We have a volume of a cubical box is 54.872 cm³
V = 54.872 cm³
As we know the volume of the cube:
V = side³
54.872 = side³
Taking cube root on both sides:
side = 3.8 cm
Thus, the sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.
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Please help with the attached photo.
The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
In polar form:
r = √(x² + y²) and cosФ = x / √(x² + y²)
Hence:
r(1 - 2cosФ) = 1
√(x² + y²) [1 - 2(x / √(x² + y²))] = 1
√(x² + y²) - 2x = 1
Take square of both sides:
x² + y² - 4x√(x² + y²) + 4x² = 1
The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²) + 4x² = 1
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Two dice are thrown. Determine the probability of obtaining a score of at least 4.
11/36 would be the probability of getting 4 , when two dice are thrown simultaneously.
As there are 6 faces of die,
So Probability of Not getting four in one dice = [tex]5/6[/tex]
As both events are mutually exclusive, the probability of not getting four in two dice = [tex](5/6) * (5/6) = 25/36[/tex]
So probability of getting at least one four is = [tex]1-(25/36) = 11/36[/tex]
So probability = [tex]11/36[/tex]
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NEED HELP ASAP !!!!
Which graphs represents the compound inequality x≤ 5 orx≥ 5?
Answer:
b
Step-by-step explanation:
NS,
Word problem on unit rates associated with ratios of whole...
Answer each part. If necessary, round your answers to the nearest hundredth.
(a) Greg bought 16 pounds of sugar for $8.
C
How many dollars did he pay per pound of sugar?
dollars per pound
(b) It takes 76 pounds of seed to completely plant a 12-acre field.
How many pounds of seed are needed per acre?
pounds per acre
|||
Answer:
Define different tipes of discontuinity of a function .also,write the condition for increasing, decreasing and concave of function
Pleas help me please i dont know what this question is
Answer:
A = 6
B = 1
C = 14
Step-by-step explanation:
A = 25 - 19 = 6
B = 6 - 5 = 1
C = 19 - 5 = 14
give brainliest please! <3
is the square root of 10 a rational number
Answer:
No
Step-by-step explanation
The square root of 10 is irrational because it isn't a fraction
What is the simplified form of 12x/900x²y4z6?
O 30y²|xz³|
O 30x²y2z4
O 360xy²|xz³|
O 360xy²|z³|
Answer:
[tex]360xy^2|xz^3|[/tex]
Step-by-step explanation:
Given expression:
[tex]12x \sqrt{900x^2y^4z^6}[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:[/tex]
[tex]\implies 12x \sqrt{900}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}[/tex]
Replace 900 with 30² :
[tex]\implies 12x \sqrt{30^2}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:[/tex]
[tex]\implies 12x \cdot 30|x|\sqrt{y^4}\sqrt{z^6}[/tex]
[tex]\implies 360x|x|\sqrt{y^4}\sqrt{z^6}[/tex]
(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).
[tex]\textsf{Apply exponent rule} \quad \sqrt{a^m}=a^{\frac{m}{2}}:[/tex]
[tex]\implies 360x|x|\cdot y^{\frac{4}{2}}\cdot z^{\frac{6}{2}}[/tex]
Simplify:
[tex]\implies 360xy^2|xz^3|[/tex]
(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).
what point is not included in the solution set for the inequality (0,6) (1,5) (2,4) (3,2)
Answer:
(3, 2)
Step-by-step explanation:
To be considered part of a solution set for the inequality provided, a given point must lie within the shaded region that is graphed. Since we want to find the point that is not included in the solution set for the inequality, we need to find the point that does not lie in the shaded region.
Let's test each point to see which doesn't lie in the region. Refer to the image below if you're having trouble graphing the points:
(0, 6): This point lies in the shaded region, so it is not our answer.(1, 5): This point lies in the shaded region, so it is not our answer.(2, 4): This point lies in the shaded region, so it is not our answer.(3, 2): This point does not lie in the shaded region, so it is our answer.Hope this helps!
Help needed on this composition math problem
Given that f(x) = x/(x - 3) and g(x) = 1/x and the application of function operators, f ° g (x) = 1/(1 - 3 · x) and the domain of the resulting function is any real number except x = 1/3.
How to analyze a composed function
Let be f and g functions. Composition is a binary function operation where the variable of the former function (f) is substituted by the latter function (g). If we know that f(x) = x/(x - 3) and g(x) = 1/x, then the composed function is:
[tex]f\,\circ\,g \,(x) = \frac{\frac{1}{x} }{\frac{1}{x}-3}[/tex]
[tex]f\,\circ\,g\,(x) = \frac{\frac{1}{x} }{\frac{1-3\cdot x}{x} }[/tex]
[tex]f\,\circ\,g\,(x) = \frac{1}{1-3\cdot x}[/tex]
The domain of the function is the set of x-values such that f ° g (x) exists. In the case of rational functions of the form p(x)/q(x), the domain is the set of x-values such that q(x) ≠ 0. Thus, the domain of f ° g (x) is [tex]\mathbb{R} - \{\frac{1}{3} \}[/tex].
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which matrix equation represents the system of equations
Answer:
option B is correct
To write any equations in the form of matrix
first make a matrix of all coefficients of that equations.. here coefficients of first equation is 4 and - 2 and that of second is 0 ( as there is no value of X) and 3
then make second matrix of X and y
last of answer of the equations, here (-7 ) and 5
Help me with this question please!! :)
Answer: 13/69
Step-by-step explanation:
13 students are female and got a B out of a total of 69 students, so the probability is 13/69
evaluate 2/3 - 1/6 * 1/4
Answer: 0.625
Step-by-step explanation:
I will give lots of points please help.
In this course, we have studied two types of geometry: Euclidean and analytical.
In Euclidean geometry, we’ve explored the relationships between points, lines, and planes without any numerical measurement.
In analytical geometry, we’ve explored the relationship between algebra and geometry using positions of points in a Cartesian coordinate system.
Which approach to geometry do you prefer and why? What are some situations in which one approach to geometry would be more beneficial than the other?
The analytical approach is preferable because the primary issue with Euclidean geometry is that it is not enough to support all of the theorems that he claims to establish.
What is geometry?It is defined as the branch of mathematics that is concerned with the size, shape, and orientation of two-dimensional figures.
As we have given about the Euclidean and analytical geometry.
Without using any numerical measurements, we have investigated the connections between points, lines, and planes in Euclidean geometry.
In analytical geometry, we've looked at how the locations of points in a Cartesian coordinate system related to algebra and geometry.
The analytical approach is preferable because the primary issue with Euclidean geometry is that it is not enough to support all of the theorems that he claims to establish.
If the Euclidean geometry can be more advantageous in particular circumstances
Example: If using terrain or building chart),
Thus, the analytical approach is preferable because the primary issue with Euclidean geometry is that it is not enough to support all of the theorems that he claims to establish.
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If P(x) is a polynomial with lead term -x7, then
a) P(x) goes to negative infinity as x goes to negative infinity, and P(x) goes to infinity as x goes to infinity
b) P(x) goes to infinity as x goes to negative infinity, and P(x) goes to negative infinity as x goes to infinity
c) P(x) goes to negative infinity as x goes to negative infinity, and P(x) goes to negative infinity as x goes to infinity
d) P(x) goes to infinity as x goes to negative infinity, and P(x) goes to infinity as x goes to infinity
P(x) goes to infinity as x goes to negative infinity, and P(x) goes to negative infinity as x goes to infinity , Option B is the correct answer.
What is a Polynomial ?A polynomial is an expression which consists of variables , Coefficient , indeterminate and mathematical operations.
The polynomial given has lead term -x⁷
So when x --> ∞ , -x⁷---> - ∞
and when x ---> - ∞ , -x⁷ ----> ∞
Similarly for the function P(x)
So when x --> ∞ , P(x)---> - ∞
and when x ---> - ∞ , P(x) ----> ∞
P(x) goes to infinity as x goes to negative infinity, and P(x) goes to negative infinity as x goes to infinity
Therefore Option B is the correct answer.
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If a=(-1 -3 2 2 5 -1 -4 -5 -4) and b=(3 3 5 2 -5 2 -4 -1 1) find AB?
Answer:
what is the control ofprice floir or price celling then scplain one advantage an one dissvantage
14 men and 10 women started a pie eating contest. At the second round, 2 men and 2 women dropped out of the contest. What is the percentage of women that proceeded to the next round?
Answer: 80%
Step-by-step explanation:
Since only 2 out of 10 women dropped out, 10 - 2 = 8
One woman = 10%, 8 x 10% = 80%
The percentage of the women who moved to the next stage is 80%.
What is the percentage?Percentage can be described as a fraction out of an amount that is usually expressed as a number out of hundred.
Women who moved to the next stage: 10 - 2 = 8
(8/10) x 100 = 80%
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What is the asymptote of the graph of f(x)=5x−1?
The asymptotes of the graph of [tex]f(x) = \frac{5}{x - 1}[/tex] are as follows:
Vertical: x = 1.Horizontal: y = 0.What are the asymptotes of a function f(x)?The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.In this problem, the function is:
[tex]f(x) = \frac{5}{x - 1}[/tex]
For the vertical asymptote, we have that:
[tex]x - 1 = 0 \rightarrow x = 1[/tex].
For the horizontal asymptote, we have that:
[tex]y = \lim_{x \rightarrow \infty} f(x) = \frac{5}{\infty - 1} = 0[/tex].
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Choose the system of inequalities that best match the graph below.
The system of the linear inequality that fulfill the condition of the graph will be y ≥ 2x – 1 and y ≤ 1/3 x + 1. Then the correct option is A.
The complete question is attached below.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
The system of the linear inequality that fulfill the condition of the graph will be
y ≥ 2x – 1
y ≤ 1/3 x + 1
Then the correct option is A.
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Triangle A B C is shown as the path of a ferry. Side A B is 3.5 miles long. The ferry turns 75 degrees to side B C. Side B C is 6 miles long. Side C A has an unknown length d.
A ferry transports passengers to three different ports. From port A, the ferry travels east 3.5 miles to port B. The ship then turns 75° south and travels for 6 miles to reach port C. What is the distance d from port C to port A? Approximate to the nearest tenth of a mile.
miles
The length of C from A is 3.5 miles if AB=3.5 miles and BC is 6 miles .
Given The length of triangle ABC AB=3.5 miles , BC=6miles and AC=d
We have to find the value of d
First of all we have to draw a perpendicular from point A on side BC .
It forms two triangles ABE and AEC if E is the point where perpendicular stands on BC.
In triangle BEA
AE=[tex]\sqrt{3.5^{2} -3^{2} }[/tex]
=[tex]\sqrt{12.25-9}[/tex]
=[tex]\sqrt{3.25}[/tex]
=1.8
Now in triangle AEC
AC=[tex]\sqrt{1.8^{2} +3^{2} }[/tex]
=[tex]\sqrt{3.24+9}[/tex]
=[tex]\sqrt{12.24}[/tex]
=[tex]\sqrt{12.24}[/tex]
=3.49 MILES
By rounding off to the nearest tenth we will get 3.4 miles
Hence the value of d is 3.4 miles.
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Answer:its 7.7
Step-by-step explanation: i did it on edge
(7 x 10 ^5) + (4 x 10 ^2)
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{(7\times 10^5) + (4 \times 10^2)}\\\mathsf{= 7\times 10^5 + 4 \times 10^2}[/tex]
[tex]\large\textsf{Let's solve for the LEFT SIDE first}[/tex]
[tex]\mathsf{7\times 10^5}\\\\\mathsf{10^5}\\\mathsf{= 10\times10\times10\times10\times10}\\\mathsf{= 100 \times 100\times 10}\\\mathsf{= 10,000 \times 10}\\\mathsf{= 100,000}\\\\\mathsf{7\times100,000}\\\mathsf{= 700,000}[/tex]
[tex]\large\textsf{NEW EQUATION: }\bold{700,000} + {4}\times 10^2[/tex]
[tex]\large\textsf{Now, let's solve for the RIGHT SIDE last}[/tex]
[tex]\mathsf{4\times 10^2}\\\\\mathsf{10^2}\\\mathsf{= 10\times10}\\\mathsf{= 100}\\\\\mathsf{4\times100}\\\mathsf{= 400}[/tex]
[tex]\large\text{NEW EQUATION: 700,000 + \bf 400}[/tex]
[tex]\large\text{700,000 + 400}\\\\\large\text{SIMPLIFY IT!}\\\\\large\text{= 700,400}[/tex]
[tex]\huge\text{Therefore, the answer should be: \boxed{\mathsf{700,400}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Solve by completing the square:
x2 + 3x – 9 = 0
Answer:
[tex]x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]
Step-by-step explanation:
Given equation:
[tex]x^2+3x-9=0[/tex]
Completing the square
Move the constant to the right side by adding 9 to both sides:
[tex]\implies x^2+3x=9[/tex]
Add the square of half the coefficient of x to both sides:
[tex]\implies x^2+3x+\left(\dfrac{3}{2}\right)^2=9+\left(\dfrac{3}{2}\right)^2[/tex]
[tex]\implies x^2+3x+\dfrac{9}{4}=\dfrac{45}{4}[/tex]
Factor the trinomial on the left side:
[tex]\implies \left(x+\dfrac{3}{2}\right)^2=\dfrac{45}{4}[/tex]
Square root both sides:
[tex]\implies x+\dfrac{3}{2}=\pm\sqrt{\dfrac{45}{4}}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{45}}{\sqrt{4}}}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9 \cdot 5}}{2}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9} \sqrt{5}}{2}[/tex]
[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{3\sqrt{5}}{2}[/tex]
Subtract 3/2 from both sides:
[tex]\implies x=\pm\dfrac{3\sqrt{5}}{2}-\dfrac{3}{2}[/tex]
[tex]\implies x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]
which is the most appropriate Venn diagram...
The most appropriate Venn diagram is known to be option b in the image shown.
What is a common multiple?A Common multiples are known to be the multiples that are said to be common to two or that have more numbers in them.
The Least Common Multiple ( LCM ) is known to be a term that connote the Lowest Common Multiple ( LCM ) and also that has the Least Common Divisor ( LCD).
From the image shown the lowest multiples are 5², 2⁶, 3 while the greatest common factor is 2⁶.
Option B is correct because the greatest common factor which is 2⁶ can only be found in the middle and this was gotten when you add:
2³ . 2³
Collect like terms
2 ³⁺³
2⁶
Therefore, the greatest common factor which is 2⁶
To get the Least Common Multiple, one need to add all the factors in the Venn diagram which are therefore:
5², 2³ . 2³, 3
=5², 2 ³⁺³, 3
=5², 2⁶, 3
Therefore, The most appropriate Venn diagram is known to be option b in the image shown.
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