Due to the fixed ends, a wave that is propagating up the string in one direction will reflect at the end and return inverted. The standing wave on the string is created by these two similar waves moving in the opposite direction.
What are the standing waves on a string fixed?When two waves with the same frequency and amplitude move in opposition to one another and interfere with one another, a standing wave result.
The string's basic frequency is the lowest resonance frequency (n=1). As integer multiples of the fundamental frequency, all higher frequencies are referred to as harmonics. The strings on all stringed musical instruments are fastened at both ends.
The n frequency is related to the fundamental frequency by the eq.
[tex]f_{n}=nf_{1}[/tex]
or
[tex]f_{1}=\frac{f_{n}}{n} \: \: \: \: \: \:\: \: \: \: \: \: \: \: (1)[/tex]
besides, we know that,
[tex]f_{n+1}=(n+1)f_{1}[/tex]
or
[tex]f_{1}=\frac{f_{n+1}}{n+1} \: \: \: \: \:\: \: \: \: \: \: (2)[/tex]
matching eq. (1) to (2),
[tex]\frac{f_{n}}{n}=\frac{f_{n+1}}{n+1}[/tex]
[tex]f_{n}(n+1)=f_{n+1}n[/tex]
isolating n from this eq.,
[tex]n = \frac{f_n}{f_n+1- f_n} = \frac{15}{20- 15}[/tex]
Once got the n value, just insert in eq. (1) so you can know the fundamental frequency,
[tex]f_1= \frac{f_n}{n} = \frac{15Hz}{3} = 5Hz[/tex]
Therefore, 5Hz is the fundamental frequency.
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A simple circuit consists of a battery, a light bulb, a capacitor, a switch, and some wire. When the switch is turned on, charges are moved from one plate of the capacitor, through the battery, and all the way around to the other plate. Which of the following occur during that time?
I Chemical potential energy is decreased.
II Electrical potential energy is increased.
III Thermal energy is increased.
II only
I only
I and II only
All of the above
Chemical potential energy is decreased, electric energy is increased and thermal energy is increased. All the above is correct.
Conversion of energy Energy is transferred throughout electrical circuits as well. The battery's two sides convert the chemical energy inside it into electrical potential energy. This electrical potential energy is converted into electric energy in the electricity that circulates through the circuit.Energy is conserved in all circumstances, which is another thing we know. Energy, according to the principle of energy conservation, never creates nor destroys itself; instead, it just changes from one type or location to another. But from a circuit perspective,How does this operate?It's true that the two sides of the battery have a different electrical potential energy, as we previously mentioned. Or, to put it another way, the circuit's electrons originally possess electric potential energy before they begin to travel.For more information on conversion of energy kindly visit to
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part 1: a driver loses control of a car on ice, drives off a cliff, and lands in a canyon 6 meters below. the car was traveling at 12 m/s just before losing control of the car. assume there is no friction between the car and the icy road. what is the final velocity of the car just as it hits the bottom of the canyon?
Fall height, h = 6.0 m
Initially, u = 12 m/s
Let,
The final speed is v be $
Now, according to the equation of energy conservation, = Initial total energy=Final total energy entails
1 /2 muΛ2+mgh= 1/ 2 mvΛ2\ indicates vΛ2 = uΛ2 + 2mgh \suggests vΛ2 = 12Λ2+2\ times 9.81 times\ 6.0\ implies v = 16.18 m/s$
The decision and practice of using less energy is known as energy conservation. Turning off the light when you leave a room, unplugging equipment when not in use, and walking instead of driving are all ways to save energy. Renewable energy sources are natural resources that can be transformed into these sorts of clean, useable energy: biomass, geothermal resources, sunshine, water, and wind. Bioenergy. Consuming less energy or reducing power consumption reduces the demand for energy production. There will be fewer carbon dioxide emissions, which will contribute to climate change. As a result, it will produce cleaner and healthier air.
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What are the peaks in NMR?
Each proton resonance (or peak) is divided into N+1 parts, where N is the number of non-equivalent surrounding protons to which the atom links. If no hydrogen atoms are nearby, the resonance will be a single peak (singlet, s)
Its low-resolution NMR spectra will have three peaks because the hydrogen atoms reside in three separate habitats. Because the ratio of hydrogen atoms in the various surroundings is 3:2:3, the ratio of peak areas will be 3:2:3. There are two peaks because the hydrogens are in two separate environments: in the CH3 group and connected to oxygen in the COOH group. They reside in various parts of the spectrum because they require somewhat varying external magnetic fields to achieve resonance at a certain radio frequency.
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Answer:107
Explanation:TOOK THAT
what causes the direction of the wind to change from day to night?
The direction of the wind is largely influenced by the temperature differences in the atmosphere.
During the day, the sun heats up the Earth's surface, causing the air to warm and rise, leading to the formation of a low-pressure area. As the air rises, cooler air from higher atmospheric levels moves in to replace it, causing wind to blow towards the low-pressure area.
At night, the Earth's surface cools down, leading to a drop in temperature, and the air cools and contracts. The air near the ground becomes denser and heavier, causing a high-pressure area to form. The cool and dense air sinks, displacing the warmer air, and creating wind that blows from the high-pressure area to the low-pressure area.
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which has a greater luminosity, a star with absolute magnitude -4 or a star with absolute magnitude 6?
A star with an absolute magnitude of -4 is brighter than one with an absolute magnitude of 6.
No matter how far a star is from Earth, its absolute magnitude provides a measure of its inherent brilliance. A difference of 5 magnitudes corresponds to a 100-fold increase in brightness on the logarithmic magnitude scale. The result is that a star with a smaller absolute magnitude is more bright than a star with a bigger absolute magnitude. By a difference of 10 magnitudes, or a factor of 10,000 in luminosity, the star with absolute magnitude -4 is brighter than the star with absolute magnitude 6, in this instance. In other words, the star with absolute magnitude -4 is 10,000 times more brilliant than the star with absolute magnitude 6, according to this statement.
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Two stars are of equal luminosity. Star A is 3 times as far from you as star B. Star A appears _________ star B.
Choose one:
A. 3 times brighter than
B. 9 times brighter than
C. one-third as bright as
D. the same brightness as
E. one-ninth as bright as
Two stars are of equal luminosity. Star A is 3 times as far from you as star B. Star A appears the same brightness as star B.
The amount of energy that a star or other astronomical object emits is measured by its luminosity, which is typically expressed in terms of brightness. It depends on the star's surface area, temperature, and proximity to the observer. The evolution of a star and its ultimate fate are greatly influenced by its luminosity.
Two stars are therefore equally bright. Star A is three times farther away than star B. The brightness of star A and star B are comparable.
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Solve problem 2, answer C is not correct.
Answer:
A 220 N
Explanation:
it’s the only one not marked out on the photo. Hope this helps!
How does adding thermal energy to solid ice affect the molecules in the ice? Describe what happens to both their motion and spacing.
Once ice has been taken out of the freezer, its molecules start to travel more quickly when heat energy is supplied.
Motion and spacing Given that the ice is substantially colder than the air outside the freezer, heat energy will transfer from the air to the ice. The molecules' kinetic energy is increased by the heat input, which weakens the ice's structure. Hydrogen bonds that were keeping the ice together start to disintegrate when the ice warms up further, causing molecules to migrate more quickly. In time, the molecules will travel so swiftly that the ice will experience a phase shift and convert into water.For more information on heat energy kindly visit to
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A 100g mass is swung around a tube 50 times in 1 minute calculate the centripetal force necessary to sustain this motion
The centripetal force of the object with a mass of about 100g will be 31.42 Newtons.
What is Centripetal force?A centripetal force is a net force which acts on an object to keep it in the state of motion along a circular path.
The angular velocity is defined as "the angle changing over time."
From the given of the problem:
m = 100g
rate of revolution = 50 rev / min
Therefore, using the formula:
angular velocity = rate of revolution x 2*pi / revolution
Angular velocity = (50 revs / min) x (2*pi radians / rev) = 100*pi radians / min
Centripetal force = mass × angular velocity
Centripetal force = 0.1 × 100π
Centripetal force = 31.42 Newtons
Therefore, the centripetal force will be 31.42 Newtons.
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I need help on these pleaseee
1) Solar energy
2) Mechanical energy
3) Electrical energy and light energy
4) Mechanical energy
5) Heat and light energy
6) Electrical energy
What is energy transformation?Energy transformation, also known as energy conversion, is the process by which energy is transferred from one form to another. Energy exists in many forms, including thermal energy, light energy, kinetic energy, potential energy, and chemical energy. In any energy transformation, the total amount of energy remains constant, but its form changes.
The efficiency of an energy transformation is the percentage of the input energy that is transformed into useful output energy. In some cases, some energy is lost as heat or waste, decreasing the overall efficiency of the transformation.
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(ii) Atmospheric pressure on that day is 1.0 x 10^5Pa
Calculate the total pressure at the bottom of the pond
Answer:
Explanation:Force applied by atmosphere = atmospheric pressure × ares of table
F=P×A
F=1.013×[tex]10^{5}[/tex] ×(2×1)=2.026×[tex]10^{5}[/tex]N
How could you increase the precision and accuracy of your wavelength measurement?
To increase the precision and accuracy of a wavelength measurement, you can take the following steps:
Use a higher-quality measuring instrumentIncrease the number of measurementsHow to increase the precision and accuracy of a wavelength measurementUse a higher-quality measuring instrument: Using a higher-quality instrument that is designed to measure wavelength with high accuracy and precision can improve the results. For example, a high-quality spectrometer can be used to measure the wavelength of light.
Increase the number of measurements: Taking multiple measurements and averaging the results can reduce the effect of random errors and improve precision.
Minimize sources of error: Minimizing sources of error, such as fluctuations in temperature and pressure, can also improve the precision and accuracy of measurements.
Calibrate the instrument: Calibration of the instrument against a known reference can improve the accuracy of measurements.
Use appropriate units: Using appropriate units that are compatible with the instrument being used can prevent errors caused by unit conversions.
Overall, increasing precision and accuracy requires careful attention to the details of the measurement process, from the choice of instrument to the environmental conditions in which the measurement is made.
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6. Determine the work done by the external force when a charge = 20 nC is displaced from an initial point at potential 300 V to a final po…
a long uniform beam of length 4 is supported by a cable at its center. a 10 worker stands on the beam at one end. where should a 200 kg bucket of mix be suspended if the beam is to be equilibrium?
Dynamic equilibrium is a state in which bodies are moving at a constant speed as opposed to static equilibrium, which is a state in which bodies are at rest (rectilinear motion). The total amount of forces exerted on them in both situations is zero.
What are the characteristics of Static equilibrium?A system is said to be in a condition of static equilibrium when all of its parts are at rest and there should be no net force operating on it.
An object will be at rest since all the forces acting on it cancel one another. The branch of mechanics that studies forces acting on motionless things in an equilibrium state.
Static equilibrium means balanced torque, i.e. is
[tex]= T_1 + T_2 = 0[/tex]
[tex]= 100 \times 2 + 200 \times r = 0[/tex]
[tex]= r=1[/tex]
Therefore, [tex]r=1[/tex]Which means bucket should be placed at [tex]1 m[/tex] From centre of man on opposite site of steelworker.
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Water is pumped from a large reservoir to a point 20 m higher than the reservoir.
Calculate the pump head if 0.01 m3/s flows through a 0.15 m diameter pipe and the
total frictional head loss is given to be 35^2/2g?
Answer:
A pump draws water from reservoir A and lifts it to reservoir B as shown in Figure 4-10. The loss of head from A to 1 is 3 times the velocity head in the 150-mm pipe and the loss of head from 2 to B is 20 times the velocity head in the 100-mm pipe. Compute the horsepower output of the pump and the pressure heads at 1 and 2 when the discharge is: (a) 12 L/s; (b) 36 L/s.
Explanation:
Paki-check po kung tama, thank you :)
If you add 2.34 C to an object, how many electrons did you add?
DO NOT ROUND YOUR NUMBER
An example on how to type your number in in scientific notation 2.6e19
2.34 C corresponds to[tex]2.34 x 10^6[/tex] Coulombs, which is equal to [tex]2.34 x 10^6 x 6.24 x 10^18[/tex]electrons, or 1.44e25 electrons.
What is electron?Electron is a subatomic particle that is part of the atom. It carries a negative charge and is considered to be the primary carrier of electricity in nature. Electrons are found in the nucleus of an atom, and they are held together by a strong nuclear force. Electrons are also found in the outer shells of atoms, and they can move freely between different shells. Electron is considered a fundamental particle, which means it is not composed of any other particles. Electrons also have a mass of about 1/1836 of the mass of a proton. Electrons are extremely important in everyday life, as they are responsible for the electrical forces that power our devices and make them function. Electrons can also be used in various applications such as semiconductors, which are used in computers, cell phones, and other electronic devices.
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A spring extends by 10 cm when a mass of 630 g is attached to it. What is the spring
constant?
the spring constant was found to be as follows 61.74 N/m.
explain about spring constant ?
The spring constant, denoted by k, is a measure of the stiffness of a spring and is defined as the force required to extend or compress the spring by a certain distance. The formula for the spring constant is:
k = F / x
where F is the force applied to the spring and x is the resulting displacement. In this case, the spring extends by 10 cm when a mass of 630 g is attached to it, which means the displacement x is 0.1 m and the force F can be calculated as:
F = m * g
where m is the mass in kilograms and g is the acceleration due to gravity, which is approximately 9.8 m/s^2. Converting the mass of 630 g to kilograms gives:
m = 0.63 kg
So, the force F is:
F = 0.63 kg * 9.8 m/s^2 = 6.174 N
Now we can calculate the spring constant k:
k = F / x = 6.174 N / 0.1 m = 61.74 N/m
Therefore, the spring constant is 61.74 N/m.
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shows four equipotential surfaces. the positively charged particle located at point a can move to points b, c, or d by the paths indicated. along which path is the greatest work done on the particle by the electric field?
The depicted paths allow the positively charged particle at point a to travel to places b, c, or d. The electric field has the most influence over the particle along path a to b.
A charged particle is a particle that has an electric charge. The charge can be either positive or negative, and the unit of charge is the Coulomb. Charged particles can be found in nature and in man-made environments. For example, the nucleus of an atom contains positively charged protons, and electrons are negatively charged particles that orbit the nucleus. Other examples of charged particles include ions, which are atoms or molecules that have gained or lost one or more electrons, and free electrons, which are electrons that are not bound to an atom or molecule. Charged particles interact with electric and magnetic fields, and these interactions are fundamental to many areas of physics and engineering.
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The complete question is:
(Figure 1) shows four equipotential surfaces. The positively charged particle located at Point a can move to Points b, c, or d by the paths indicated. Along which path is the greatest work done on the particle by the electric field?
- Path a to b
- Path a to c
- The work done is equal along all three paths.
- Path a to d
QuestionThe kelvin scale has its ________set to absolute zero which is the _________possible temperature that exists in the universe.AzeroBlowest
As one scale for another, both scales are connected. One unit on the Kelvin scale is equivalent to one degree on the Celsius scale. The zero points of the thermometer are the only distinction between these two scales.
What is the kelvin scale?Because the zero point is the absolute limit of how cold anything can become, the Kelvin temperature scale is also known as the absolute temperature scale. i.e., the temperature at absolute zero is [tex]-273[/tex]Degrees Celsius (0 K).
Absolute zero (0 K) on the Kelvin scale is the temperature at which a gas's volume is zero. Since it is below zero on all temperature scales, it is the lowest possible temperature. Thus, -273.15 oC is the Kelvin scale's zero.
With the non-scientific temperature scales, absolute zero isn't even zero. The temperature is -273.15 degrees Celsius, or -459.67 degrees Fahrenheit.
Therefore, The kelvin scale has its zero set to absolute zero, which is the lowest possible temperature that exists in the universe.
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a centrifuge in a biology laboratory rotates at an angular speed of 3,800 rev/min, clockwise (when viewed from above). when switched off, it rotates through 48.0 revolutions before coming to rest. assuming it is constant, what is the magnitude of angular acceleration (in rad/s2)?
The magnitude of the angular acceleration of the centrifuge is 3.78 rad/s^2.
Convert the angular speed from revolutions per minute (rpm) to radians per second (rad/s).
1 revolution = 2π radians
ω = 3800 rev/min * (2π rad/rev) / (60 s/min) = 398.11 rad/s
[tex]\theta=\omega i t + (1/2)\alpha t^2[/tex]
where θ is the angular displacement, ω_i is the initial angular velocity, α angular acceleration, t time.
At the instant the centrifuge is switched off, its angular speed is 398.11 rad/s. Angular displacement is 48 revolutions * 2π radians/revolution = 301.59 radians.
[tex]\omega f = \omega i +\alpha t[/tex]
[tex]0 = -398.11 + \alpha t[/tex]
[tex]t = 398.11/\alpha[/tex]
[tex]θ = \omega_i t + (1/2)\alpha t^2[/tex]
[tex]301.59 = (-398.11)(398.11/\alpha) + (1/2)α(398.11/\alpha)^2[/tex]
Simplifying this equation, we get:
[tex]301.59 = -398.11^2/\alpha + 398.11^2/2\alpha[/tex]
Multiplying both sides by 2α and rearranging, we get:
[tex]\alpha = 2 * 398.11^2 / (301.59 + 398.11^2/\alpha)[/tex]
Solving for α, we get:
[tex]\alpha = 3.78 rad/s^2[/tex]
Therefore, the magnitude of the angular acceleration of the centrifuge is 3.78 rad/s^2.
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Consider the circuit in the diagram below.
The switch at the top is moved to the closed or on position, the lightbulb glows brightly for a moment, and then dims gradually until it is fully dark. The switch on the top leg is then moved to the open or off position. The switch on the central leg is then moved to the closed or on position. What would happen to the bulb.
The light bulb would light up and stay constant.
The light bulb would light up and gradually dim.
The light bulb would gradually brighten.
The light bulb would flash on and then immediately shut off.
Answer:
The light bulb would flash on and then immediately shut off.
Explanation:
EXPERIMENT: POLAR PROPERTIES
Perform the directions and Answer the following questions ….
These supplies are needed:
acetate (overhead transparency material) strip and tissue paper
vinyl strip and woolen cloth
slow, steady stream of water from a faucet
Follow these directions and answer these questions.
1. Rub the acetate strip with the tissue paper.
2. Bring the strip near a slow stream of running water.
What happened when the strip was brought near the stream?
From your ideas about charges on acetate and vinyl strips, predict what will happen if a charged vinyl strip is brought near the slow stream of water. (Review Unit 4.)
3. Test your hypothesis. Rub a vinyl strip with a woolen cloth.
4. Bring the charged strip near a slow stream of water.
HELP ASAP I NEED LEGIT ANSWERS:)
Charge is a fundamental physical property of matter that describes the degree to which it interacts with electromagnetic fields. It is an intrinsic property of subatomic particles, such as protons and electrons, that gives rise to electric and magnetic forces.
What is Charge?The basic unit of charge is the Coulomb (C), named after the French physicist Charles-Augustin de Coulomb, who first quantified the electric force between charged objects. A single proton or electron has a charge of approximately 1.6 x 10⁻¹⁹ Coulombs.
Rubbing the acetate strip with tissue paper transfers electrons from the tissue paper to the strip, giving the strip a negative charge.
When the negatively charged acetate strip is brought near a slow stream of running water, the water is attracted to the strip and bends towards it. This is because the water is polar, meaning it has a positive end and a negative end, and the negative end is attracted to the negatively charged acetate strip.
Predicted: When a charged vinyl strip is brought near the slow stream of water, the water should be attracted to the strip and bend towards it. This is because the vinyl strip is typically charged positively when rubbed with woolen cloth, so it will attract the negative end of the polar water molecules.
Rubbing the vinyl strip with a woolen cloth transfers electrons from the woolen cloth to the strip, giving it a positive charge. When the positively charged vinyl strip is brought near the slow stream of water, the water is indeed attracted to the strip and bends towards it, just as predicted.
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a mass/spring system is displaced from equilibrium by 5.0 cm and its period of motion is determined to be 3.0 seconds. what will the period be if it is displaced from equilibrium by 15.0 cm?
The period of motion when the mass-spring system is displaced from equilibrium by 15.0 cm is 6.0 seconds.
What is the mass-spring system?The period of a mass-spring system is given by:
[tex]T = 2pisqrt(m/k)[/tex]
where m is the mass and k is the spring constant.
The period of motion is not affected by the amplitude (displacement from equilibrium) of the oscillation for small amplitudes. However, for large amplitudes, the period does depend on the amplitude.
To find the period when the system is displaced from equilibrium by 15.0 cm, we need to find the new value of k, which depends on the displacement.
When the system is displaced by 5.0 cm, we have:
[tex]5.0 cm = A = x_max[/tex]
where A is the amplitude and [tex]x_max[/tex] is the maximum displacement from equilibrium.
When the system is displaced by 15.0 cm, we have:
[tex]15.0 cm = A = x_max[/tex]
The new spring constant k' can be found by:
[tex]k' = m*(2*pi/T')^2[/tex]
where T' is the period of motion when the system is displaced by 15.0 cm.
The energy of the system is conserved, so the potential energy at the maximum displacement is equal to the kinetic energy at the equilibrium position.
At the maximum displacement, all of the potential energy is converted into kinetic energy, so:
[tex]1/2 k' A^2 = 1/2 k x_max^2[/tex]
Solving for k' and substituting into the expression for the period, we get:
[tex]T' = 2pisqrt(m/k') = 2pisqrt(m/(k*(A/x_max)^2))[/tex]
Substituting the given values, we get:
[tex]T' = 2pisqrt(m/k*(15.0 cm/5.0 cm)^2) = 6.0 s[/tex]
Therefore, the period of motion when the mass-spring system is displaced from equilibrium by 15.0 cm is 6.0 seconds.
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a professor has to haul a cart up a ramp. the ramp has an angle of about 10 degrees and is about 5 meters long. his initial speed at the bottom of the ramp is 5.3 m/s, and the cart has a mass of about 100 kg. how hard does he have to push on the cart so that at the top of the ramp, its speed has not dropped below 4.4 m/s? neglecting friction, what is the magnitude of the minimum force he has to exert on the cart?
The magnitude of the minimum force the professor needs to exert on the cart is approximately 150 N.
The acceleration of the cart can be found by equating the final kinetic energy (at the top of the ramp) to the initial kinetic energy:
(1/2) m v_final^2 = (1/2) m v^2
Solving for the final speed, we get:
v_final = sqrt(v^2 - 2 g h)
Substituting the given values, we get:
v_final = sqrt((5.3 m/s)^2 - 2 x 9.81 m/s^2 x 1.42 m) ≈ 4.23 m/s
Since we want the final speed to be at least 4.4 m/s, the cart will need to be accelerated at the top of the ramp. The minimum force required to provide this acceleration can be found as follows:
F = m (v_final^2 - v_desired^2) / (2 h)
where v desired is the desired speed at the top of the ramp (i.e., 4.4 m/s). Substituting the given values, we get:
F = 100 kg x (4.23 m/s)^2 - (4.4 m/s)^2) / (2 x 1.42 m) ≈ 150 N
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What happens to the time period of a simple pendulum if the amplitude is doubled?
When producing modest swings, the amplitude frequently has no impact at all on the pendulum's period. There is a tiny but insignificant rise in the period when the pendulum's amplitude is greater.
What alter on time period pendulum if amplitude changed?The distance to travel increases as the amplitude rises, but when the restoring force rises as well, the acceleration rises correspondingly.
This implies that the mass can move faster and cover a bigger distance. Since these qualities cancel one another, amplitude has no bearing on period.
A straightforward harmonic oscillator's period is independent of its amplitude. with the graphs of acceleration and velocity produced by the time derivatives. These oscillators also show how kinetic and potential energy can be transferred.
Therefore, the length of time is unrelated to the vibration's magnitude. Time period is unchanged by doubling the oscillation's amplitude.
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what is the frequency of the oscillation? express your answer to two significant figures and include the appropriate units.
The frequency of the oscillation can be calculated as the inverse of the period: f = 1 / T = 1 / 4 units.
Based on the description, we can see that the waveform has a period of 4 units on the x-axis since it completes one full cycle over that distance.
Therefore, the frequency of the oscillation can be calculated as the inverse of the period:
f = 1 / T = 1 / 4 units
Expressing the frequency to two significant figures and including the appropriate units, we get:
f = 0.25 [tex]units^{-1}[/tex]
The frequency of this wave can be calculated by measuring the distance between two consecutive points of maximum amplitude, which in this case is one complete cycle.
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a penny is dropped from rest from the top of a very tall building. assuming the height of the building is 449 m and ignoring air resistance, find the speed with which the penny strikes the ground.
If the height of the building is 449 m and ignoring air resistance then, 93.8m/s is the speed with which the penny strikes the ground.
What is air resistance?
A type of friction (a force that resists motion) that happens between air and another object is air resistance, commonly referred to as drag. When a thing travels through the air, it experiences force. The two constant natural forces that affect every item on Earth are air resistance and gravity.
For instance, air particles pressing on an aircraft as it soars through the air make it more difficult for the aircraft to move. A feather's ability to fall is significantly influenced by air resistance.
Steps for calculation:
[tex]v^2=u^2+2gS \\where u=0, 2g=9.8m/s^2 and S=449m[/tex]
[tex]We get,\\ v^2 =2*9.8*449m^2 /s^2\\ v=93.8m/s[/tex]
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a cannonball is fired straight up into the air. the cannonball leaves the cannon at a speed of 37 m/s. determine how high the cannonball goes and how long it took to reach the peak. ignore air drag.
The cannonball goes as high a s69.84 m and time took for the cannonball to reach the peak is 3.77 seconds.
The rate of change of relegation is haste & the rate of change of haste is acceleration. using these two statements we decide equations called kinematic equations.
dv = ds/dt , da = dv/dt.
Derive equations are:
v = u + at
2as = v²−u²
s = ut + 1/2at²
For max height use the formula
vf² = vo² + 2ad
At the max height, the velocity is zero, so...
(0) = (37)² + 2(9.8)(d)
d = 69.84 m
So, cannonball reaches the height of 69.84 m
For the time to get to that height, apply
vf = vo + at
0 = 37 + (9.8)(t)
t = 3.77 sec
Time for it to reach the peak is 3.77 seconds.
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The speeds of a car travelling on a straight road are given below at successive intervals of 1 second. Time/s Speed/m/s 0 0 1 2 2 4 3 6 4 8 Calculate a the average speed of the car in m/s b the distance the car travels in 4s c the constant acceleration of the car. 2 If a train travelling at 10 m/s starts to accelerate at 1 m/s² for 15s on a straight track, calculate its final speed in m/s.
a. the average speed of the car is 15 m/s.
b. the car travels 60 meters in 4 seconds.
c. the constant acceleration of the car is 2 m/s².
d. we find the the final speed of the train as 25 m/s.
How do we calculate?a)
We find the total distance traveled by the car as:
0 + 2 + 8 + 18 + 32 = 60 meters.
Average speed = Total distance / Total time
= 60 meters / 4 seconds
= 15 m/s
b) The distance traveled by the car in 4 seconds = total distance traveled
= 60 meters
c)
Acceleration = (Final velocity - Initial velocity) / Time
Acceleration = (Final velocity - Initial velocity) / Time
Acceleration = (8 m/s - 0 m/s) / (4 s - 0 s)
Acceleration = 8 m/s / 4 s
Acceleration = 2 m/s²
d.
Final velocity = Initial velocity + (Acceleration * Time)
Final velocity = 10 m/s + (1 m/s² * 15 s)
Final velocity = 10 m/s + 15 m/s
Final velocity = 25 m/s
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Expected
Star: Vega
Star: Sirius
400
500
600
700
What is true about these stars?
Vega and Sirius are both well-known stars that are often mentioned in astronomical and popular culture.
What are the particulars of these stars?Vega is a bright, blue-white star located 25 light-years from Earth. It is one of the brightest stars in the night sky and is often used as a reference star in various astronomical studies.
Sirius, also known as the Dog Star, is the brightest star in the night sky and is located approximately 8.6 light-years from Earth. It is a binary star system, consisting of a main-sequence star (Sirius A) and a white dwarf star (Sirius B).
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