Answer:
The average acceleration is [tex]8\ m/s^2[/tex]
Explanation:
Uniform Acceleration
When an object varies its velocity at the same rate, the acceleration is constant.
The relation between the initial and final speeds is:
[tex]v_f=v_o+a.t[/tex]
Where:
vf = Final speed
vo = Initial speed
a = Constant acceleration
t = Elapsed time
The acceleration can be calculated by solving for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The Indy 500 race car increases its speed from vo=4 m/s to vf=36 m/s in t=4 s. Thus, the average acceleration is:
[tex]\displaystyle a=\frac{36-4}{4}=8\ m/s^2[/tex]
The average acceleration is [tex]8\ m/s^2[/tex]
HOW TO PROTECT OUR SELF FROM THUNDER STORM
Which phrase best describes a bird's skeleton
what is a stars brightness known as?
what is the brightest star in our night sky?
stars are identified by their color; what does the color indicate?
Answer:
1.
Astronomers define star brightness in terms of apparent magnitude — how bright the star appears from Earth — and absolute magnitude — how bright the star appears at a standard distance of 32.6 light-years.
2.
Sirius, also known as the Dog Star or Sirius A, is the brightest star in Earth's night sky. The name means "glowing" in Greek — a fitting description, as only a few planets, the full moon and the International Space Station outshine this star.
Answer:
Sirius is the brightest star in the night sky
Explanation:
The name means 'glowing' in greek
6th grade science please help !
Answer:
i cant see it just put the question
Explanation:
GIVING BRAINIEST
which graph accurately shows the relationship between kinetic energy and speed as speed increases?
Answer:
B
Explanation:
A student rings a brass bell with a frequency of 100 Hz. The sound wave travels through brass, air, and glass. What is the wavelength of the wave in brass? A. 0.021 m B. 4.7 m C. 0.21 m D. 47 m
If a student rings a brass bell with a frequency of 100 Hz. The sound wave travels through brass, air, and glass, then the wavelength of the wave in brass would be 47 meters, therefore the correct answer is option D.
What is a sound wave?It is a type of mechanical wave composed of the disturbance caused by the movements of the energy. A sound wave travels through compression and rarefaction in an elastic medium such as air.
As given in the problem if a student rings a brass bell with a frequency of 100 Hz. The sound wave travels through brass, air, and glass, then we have to find out what is the wavelength of the wave,
The wave velocity = Frequency of the wave ×wavelength
4700 = 100 × wavelength
Wavelength = 4700 / 100
=47 meters
Thus, the wavelength of the wave would be 47 meters .
To learn more about sound waves from here, refer to the link;
brainly.com/question/11797560
#SPJ5
a 28 kg ball is rolling across the top of a 0.75 m tall table. the ball has 350 J of kinetic energy. how fast is the ball moving
Q1) An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours.To cover the same distance in 1(2/3) hours, it must travel at a speed of;
A)300kmph
B)360kmph
C)600kmph
D)720kmph
Explain how you got the answer
Answer:
D) 720 kmph
Explanation:
First, let's find what distance this aeroplane covered. Distance (d) is the product of speed and time - here, we have a speed of 240 kmph and a time of 5 hours, gives us
[tex]d=240\cdot5=1200[/tex] km
Using that same fact, we can set up a new equation to solve for speed (s) when we have a distance of 1200 km and a time of 1 2/3 hours. For the sake of cleanliness, I'm gonna rewrite 1 2/3 as the improper fraction 5/3:
[tex]1200=(5/3)s[/tex]
Multiplying both sides of the equation by 3/5:
[tex]s=(3/5)(1200)=720[/tex] kmph
So our answer is D.
Answer: 720km/h
Explanation:
Compared to the cells in a healthy body, Elisa’s cells are getting far fewer ____________________ molecules.
Answer:
glucose
Explanation:
the length of iron rod at 100 C is 300.36 cm and at 159 C is 300.54 cm.Calculate its length at 0 c and coefficient of linear expansion of iron
Answer:
The length at 0 °C is 300.05 cm
Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹
Explanation:
From the question given above, the following data were obtained:
Length (L₁) at 100 °C = 300.36 cm
Temperature 1 (θ₁) = 100 °C
Length (L₂) at 159 °C = 300.54 cm
Temperature 2 (θ₂) = 159 °C
Length (L₀) at 0 °C =?
Coefficient of linear expansion (α) =?
L₁ = L₀ (1 + θ₁α)
300.36 = L₀ (1 + 100α) ....(1)
L₂ = L₀ (1 + θ₂α)
300.54 = L₀ (1 + 159α) ..... (2)
Divide equation (2) by (1)
300.54 / 300.36 = L₀ (1 + 159α) / L₀ (1 + 100α)
1.0006 = (1 + 159α) / (1 + 100α)
Cross multiply
1.0006 (1 + 100α) = (1 + 159α)
1.0006 + 100.06α = 1 + 159α
Collect like terms
1.0006 – 1 = 159α – 100.06α
0.0006 = 58.94α
Divide both side by 58.94
α = 0.0006 / 58.94
α = 1.02×10¯⁵ C¯¹
Substitute the value of α into anything of the equation to obtain L₀. Here we shall use equation (2).
300.54 = L₀ (1 + 159α)
α = 1.02×10¯⁵ C¯¹
300.54 = L₀ (1 + 159 ×1.02×10¯⁵)
300.54 = L₀ (1 + 0.0016218)
300.54 = L₀ (1.0016218)
Divide both side by 1.0016
L₀ = 300.54 / 1.0016
L₀ = 300.05 cm
Summary:
The length at 0 °C is 300.05 cm
Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹
ILL MARK BRAINLEST
Question 13: A food web of the Yellowstone National Park ecosystem is
provided below. If a sudden outbreak of disease severely reduced the
number of wolves in Yellowstone National Park very rapidly, what are two
changes that might happen to the local food web? Fully explain using
claim, evidence, and reasoning.
Answer:
they all will die and so will we
Explanation:
Answer:
3 animals will thrive better
Explanation:
If the number of wolves is reduced, 3 animal species usually eaten by the wolves will have a better chance of survival.
I really need some help with this. The question is in the photo
hey hey i need help finding out the speed !! someone help
Answer:
v = 5.4 m/s
Explanation:
We use conservation of mechanical energy, that is all potential energy in the initial state, and all kinetic energy in the final state:
[tex]m*g*h=\frac{1}{2} m*v^2\\g*1.5=\frac{1}{2} v^2\\v^2=3*g=29.4\\v=\sqrt{29.4} \\v=5.42\,m/s[/tex]
which rounded to one decimal is
v = 5.4 m/s
(in agreement with the third answer on the list)
You have a transformer with 50 turns in the primary coil if you want to increase the voltage from 5V26V how many times should be in the secondary coil
Correct question:
You have a transformer with 50 turns in the primary coil if you want to increase the voltage from 5V to 6V how many turns should be in the secondary coil ?
Answer:
the number of turns in the secondary coil is 60 turns.
Explanation:
Given;
number of turns in the primary coil, P = 50 turns
primary voltage, Ep = 5V
secondary voltage, Es = 6V
The number of turns in the secondary coil is calculated as;
[tex]\frac{N_s}{N_p} = \frac{E_s}{E_p} \\\\\frac{N_s}{50} = \frac{6}{5} \\\\N_s = \frac{50\times 6}{5} \\\\N_s = 60 \ turns[/tex]
Therefore, the number of turns in the secondary coil is 60 turns.
An earthquake is a vibration of the Earth produced by a rapid release of energy. This vibration usually begins when
there is a build-up of stress in the Earth's crust resulting in
A)
tectonic plates buckling up.
Eliminate
B)
rift zones under the oceans.
C)
plate movement at fault lines.
D)
convection currents within Earth's magma.
Answer:
C) plate movement at fault lines.
Explanation:
Earthquakes are vibrations that develop when there is a build-up of stress in the Earth's crust resulting in plate movement at fault lines. Most often, earthquakes occur at subduction zones.
How does the initial velocity of a projectile affect its range?
N - Projectiles with larger initial velocity will go farther
0 - Projectiles with larger initial velocities will not go as far
P-Initial velocity has no effect
Plzzz yaar guys help I really need this ( crying emoji )
Answer:
I believe it is the first one
Examine the picture of the screw on page 214. Explain how to calculate the mechanical advantage of the screw.
Answer:
1.4
Explanation:
PLEASEE GUYS HELP I BEG YOU
A satellite is in orbit 3.11106 m from the center of Earth. The mass of Earth is 5.981024 kg. Calculate the orbital
period of the satellite.
A student walks 160m in 150s. the student stops for 30s and then walks 120m father in 140s what is the average speed of the entire walk?
Answer:
Explanation:
Average speed is always: ( total distance traveled ) / ( time elapsed )
The time for the walk is +150+%2B+30+%2B+140+=+320+ s
The distance traveled is +160+%2B+210+=+370+ m
( total distance traveled ) / ( time elapsed ) = +370+%2F+320+=+1.156+ m/s
A 2160 kg car moving east at 10.4 m/s collides with a 3250 kg car moving east. The cars stick together and move east as a unit after the collision at a velocity of 5.16 m/s. a) What is the velocity of the 3250 kg car before the collision? Answer in units of m/s. 009 (part 2 of 2) 10.0 points b) What is the decrease in kinetic energy during the collision? Answer in units of J.
Answer:
Explanation:
10
A satellite is in orbit 3.110106 m from the center of Earth. The mass of Earth is 5.98011024 kg Calculate the orbital
period of the satellite.
Answer:
9194.4278 seconds
Explanation:
Orbital period is given by :
T² = (4π²r³) /GM
G = Gravitational constant = 6.67 * 10^-11
M = 5.9801 * 10^24 kg
r = (3.110 * 10^6 m + 6378000 m) =3110000 + 6378000 = 9488000 m
T² = (4π² * 9488000^3) / (6.67* 10^-11 * 5.9801*10^24)
T² = 3.37197 * 10^22 / 398872670000000
T² = 84537504.161415
T = sqrt(84537504.161415)
T = 9194.4278 seconds
PLS ASAP!
An airplane increases its speed at the average rate of 15 m/s2 . how much time does it take
to increase its speed from 100 m/s to 160 m/s ?
10 seconds
4 seconds
15 seconds
Answer:
it take 15 seconds
Explanation:
it take 15 seconds to increase it time
A baseball player throws a baseball with the same initial velocity 5 different times. Each time the ball is thrown at a different angle. The angles are: 45o, 15o, 60o, 25o, and 80o. (a) List the angles based on the amount of time in the air, from the shortest time to the longest time. (b) List the angles based on the horizontal range the baseball travels from the shortest distance to the longest distance.
Answer:
(a) The list of angles based on amount of time in the air; 15° < 25° < 45° < 60°, < 80°
(b) The list of angles based on distance = 80° < 15° < 25° < 60° < 45°
Explanation:
(a) The given parameters are;
The angles in which the ball is thrown, θ = 45°, 15°, 60°, 25°, and 80°
The velocity with which the ball is thrown each time = The same velocity
The amount of time the projectile is in the air given as follows;
[tex]2 \cdot t = \dfrac{2\cdot u \cdot sin (\theta) }{g}[/tex]
Where;
t = Half the amount of time the projectile is in the air
θ = The angle of flight of the projectile
u = The initial velocity of the projectile = Constant for all angles in which the ball is thrown
g = The acceleration due to gravity = 9.8 m/s² = Constant
Therefore, we have;
When θ = 45°;
[tex]2 \cdot t = \dfrac{2\cdot u \cdot sin (45^ {\circ}) }{g} = \dfrac{2\cdot u \cdot \dfrac{\sqrt{2} }{2} }{g} = \dfrac{\sqrt{2} \cdot u }{g}[/tex]
When θ = 15°;
[tex]2 \cdot t = \dfrac{2\cdot u \cdot sin (15^ {\circ}) }{g} \approx \dfrac{0.517638\cdot u }{g}[/tex]
When θ = 60°;
[tex]2 \cdot t = \dfrac{2\cdot u \cdot sin (60^ {\circ}) }{g} = \dfrac{2\cdot u \cdot \dfrac{\sqrt{3} }{2} }{g} = \dfrac{\sqrt{3} \cdot u }{g}[/tex]
When θ = 25°;
[tex]2 \cdot t = \dfrac{2\cdot u \cdot sin (25^ {\circ}) }{g} = \dfrac{0.8452365\cdot u }{g}[/tex]
When θ = 80°;
[tex]2 \cdot t = \dfrac{2\cdot u \cdot sin (80^ {\circ}) }{g} = \dfrac{1.9696155\cdot u }{g}[/tex]
Therefore, the list of the angles based on the amount of time in the air from the shortest time to the longest time is given as follows;
List of angles based on amount of time in the air; 15° < 25° < 45° < 60°, < 80°
(b) The horizontal range, R is given as follows;
[tex]R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}[/tex]
When θ = 45°
[tex]R = \dfrac{u^2 \cdot sin(2 \times 45 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(90 ^{\circ}) }{g} = \dfrac{u^2 }{g}[/tex]
When θ = 15°
[tex]R = \dfrac{u^2 \cdot sin(2 \times 15 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(30 ^{\circ}) }{g} = \dfrac{1}{2} \cdot \dfrac{u^2 }{g} = 0.5 \cdot \dfrac{u^2 }{g}[/tex]
When θ = 60°;
[tex]R = \dfrac{u^2 \cdot sin(2 \times 60 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(120 ^{\circ}) }{g} = \dfrac{u^2 }{g} \cdot \dfrac{\sqrt{3} }{2} =0.866025 \cdot \dfrac{u^2 }{g}[/tex]
When θ = 25°;
[tex]R = \dfrac{u^2 \cdot sin(2 \times 25 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(50 ^{\circ}) }{g} = \dfrac{0.7660444 \cdot u^2 }{g}[/tex]
When θ = 80°
[tex]R = \dfrac{u^2 \cdot sin(2 \times 80 ^{\circ}) }{g} = \dfrac{u^2 \cdot sin(160 ^{\circ}) }{g} = \dfrac{0.34202 \cdot u^2 }{g}[/tex]
Therefore the list of angles based on the horizontal range the baseball travels from the shortest distance to the longest distance is given as follows;
List of angles based on distance = 80° < 15° < 25° < 60° < 45°.
A 50 kg student holding a 7 kg backpack rides a 4 kg skateboard down the sidewalk at 3 m/s. What is the total momentum of the student, backpack, and skateboard?
Answer:
183 MLT^-1Explanation:
Mass = 50kg +7kg +4kg =61 kg
Velocity = 3m/s
Momentum = mass × velocity
[tex]p =61\times 3\\\\p =183MLT^-^1[/tex]
Answer:
Mass= 61 kg. Success to The homework.
How does the today's model of the atom DIFFER from the Rutherford’s model? 25 Points
Answer:
The Rutherford Model shows an atom with electrons orbiting a fixed, positively charged nucleus in set, predictable paths. The Bohr model shows electrons travel in defined circular orbits around the nucleus.
Explanation:
3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?
Answer:
3,200,000,000 J
Explanation:
Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation
[tex]W=Fs[/tex]
where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the displacement (in meters).
Here, we have F = 1,600,000 N and s = 2000 m, so our work will be
[tex]W=1.600.000(2.000)=3.200.000.000[/tex] J
a bottle of soft drink was moved from the refrigerator after sometime it was observed that his temperature has increased by 15 rakine what is the temperature change in Fahrenheit and Celsius
Answer:
8.333C 15F
Explanation:
15R in C - 0R in C = 8.3333C
15R in F - 0R in F = 15F
what could become faster If time would slow down(or even reversed)
Answer:Acceleration
Explanation:Acceleration
increases at time decreases
Answer:
Acceleration
Explanation:
Need help asapppp
Thanks + BRAINLIST only if you know correct answer
Electromagnetic waves are
a. forms of matter
b. forms of space
C. longitudinal waves
d. transverse waves
Answer:
hi have a nice day
Explanation:
i think forms of space
Answer:
Transverse waves
Explanation:
EM waves are made up of photons, which are massless particles. These waves propogate (travel) through space at the speed of light as transverse waves, waves that move back and forth perpendicular to the direction they're travelling in, as opposed to longitudinal waves, which move back and forth along the path of travel.
A car runs at a constant speed of 15ms-1 for 30secs, and then accelerates uniformly to a speed of 25ms-1 over a time of 20secs. this speed is maintain for the next 300secs before the car is brought to rest with uniform deceleration in 30secs.
a. draw the velocity time graph of the motion. and calculate
b. the total distance traveled by the car
c. average speed of the car
Answer:
a. Please find the attached velocity time graph of the car's motion created with Microsoft Excel
b. The total distance traveled by the car is 8,725 meters
c. The average speed of the car is 22.9605263 m/s
Explanation:
The given parameters of the motion are;
The initial speed of the car, v₁ = 15 m/s
The time during which the car runs at the initial speed, t₁ = 30 seconds
The new speed the car then accelerates at 'a₁' to, v₂ = 25 m/s
The duration it takes for the car to accelerate to the new speed = 20 seconds
The time during which the car runs at the initial speed = 300 seconds
The time it takes the car to be brought to rest with a deceleration, 'a₂' from the new speed (20 m/s) = 30 seconds
The final speed of the car at rest, v₃ = 0 m/s
The acceleration, a₁ = (v₂ - v₁)/t₁ = (25 - 15)/20 = 1/2 m/s²
The deceleration , a₂ = (v₃ - v₂)/t₁ = (0 - 25)/30 = -5/6 m/s²
a. Please find attached the drawing of the velocity time graph of the motion created with Microsoft Excel
b. The total distance traveled by the car, 'Δx', is given b the area under the velocity time graph as follows;
Area of trapezoid, A₁ = (320 + 300)/2 × 10 = 3,100
Area of rectangle, A₂ = 15 × 350 = 5,250
Area of triangle, A₃ = 1/2×30×25 = 375
The total area under the velocity time graph = A₁ + A₂ + A₃ = 3,100 + 5,250 + 375 = 8,725
The total area under the velocity time graph = The total distance traveled by the car, Δx = 8,725 meters
c. The average speed of the car is given as follows;
[tex]The \ average \ speed \ of \ the \ car, \overline v =\dfrac{\Delta x}{\Delta t} = \dfrac{The \ total \ distance \ traveled by \ the \ car}{The \ total \ time \ the \ car \ travels}[/tex]
Where;
Δt = The total time during which the car travels
∴ The average speed of the car = 8,725 m/(380 s) = 22.9605263 m/s
