An object of mass 5 kilograms is moving across a surface in a straight line with a speed of 3.5 meters/second. what amount of force would be
required to keep the object in motion if you ignore the surface friction?
a 0 newtons
b 175 newtons
c 35 newtons
d 5 newtons

Explanation:

first change m/s to km/hr and time 1 year to hour b/c we are asked the to give in km. so,

v=17,000 m/s = 17000×3600/1000 = 61,200 km/hr

t= 1 year= 365 days =365day×24 hr/day = 8,760hr

therefore, V = s/t from this s = v×t =61200×8760 =536,112,000 Km

Answer:

Force = 9600N

Explanation:

If this is the right question, there should have been a question before about the what the change in the momentum of the ball was. The answer to that was 9.6kg m/s. For this part, we divide this by the time taken which was 0.001s which give us the resultant force.

resultant force = change in momentum ÷ time

= 9.6kgm/s ÷ 0.001s

= 9600N

Answer:

The image is formed by a convex lens with the object at 2F.

Sample Response: The image created by the object is located on 2F behind the lens, real, inverted, and the same size as the actual object. 

Explanation: EDGE.

Answer:

Newton's second law states that force is directly proportional to the product of mass and acceleration.

so if you hit a baseball with a bat it will accelerate according to the applied force.

Answer:

[tex]\huge\boxed{\sf \lambda = 2 m}[/tex]

Explanation:

Frequency = f = 200 Hz

Velocity = v = 400 m/s

Wavelength = λ = ?

v = fλ

Put the givens in the formula

400 = (200)λ

Divide 200 to both sides

400/200 = λ

2 m = λ

λ = 2 m

[tex]\rule[225]{225}{2}[/tex]

a protostar will continue to collapse due to gravity until it reaches the main sequence, and then gravitational collapse will stop when fusion of hydrogen begins.

A protostar serves as a very young star which is very small in mass and still developing its mass from parent molecular cloud.

However, it can be affected by gravity because , when there is not  collapse on the gravity, if there is fusion of hydrogen begins in it.

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Answer:

[tex]\boxed {Density = 4800 kg/m^{3}}[/tex]

Explanation:

Formula :

[tex]\boxed {Density = \frac{Mass (kg)}{Volume (m^{3})}}[/tex]

Convert volume into standard unit :

⇒ 250000 cm³ × 10⁻⁶

⇒ 0.25 × 10⁶ × 10⁻⁶

⇒ 0.25 m³

Solve for density :

⇒ Density = 1200 kg / 0.25 m³

⇒ Density = 1200 × 4 kg/m³

⇒ Density = 4800 kg/m³

The generated statements that set the properties of the labels, buttons, and forms end up automatically within the InitializeComponent() method.

The InitializeComponent method in programming is the that have code that works with codes that  creates and initializes the creates and initializes the user interface objects .

Conclusively, when a statement is generated, to  when set the properties of the labels , it will definitely been felt in the InitializeComponent() method automatically.

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Answer:

B

Explanation:

F=[tex]\frac{Gm1m2}{r^2}[/tex]

F=(6.67 x 10^-11)[tex]\frac{63.7X9,750.6}{7.5^2}[/tex]

F=7.36502254e-7

Answer:

19.55 m/s

Explanation:

Here is HOW to get the answer:

Speed = wavelength * freq

           = 1.7 * 11.5 = 19.55 m / s

Answer:

[tex]\fbox {D. Isobaric}[/tex]

Explanation:

The process during which pressure remains constant is called an isobaric process.

The local group of galaxies which the Milky Way belong to is the Virgo Supercluster. C

The Virgo Supercluster as known as the Local Supercluster is a mass concentration of galaxies that contains the Virgo Cluster and Local Group which in turn contains the Milky Way and Andromeda galaxies, as a host as others galaxies.

Therefore, the local group of galaxies which the Milky Way belong to is the Virgo Supercluster.

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She can use the information of redshift of a celestial body is to find the age and distance of the object.

'Red shift' is a critical idea for astronomers. The frequency of the light is increased, so the light is observed as moving towards the red side of the range.

Tabitha knows the redshift value of a particular celestial object. She uses this information to observe the consequence of the redshift.

Thus, the red shift value is used to determine the age and distance of the object.

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Answer:

A (the age and distance of the object)

Explanation:

Answer:

10^2 + 10^2 = x^2

x = 14.2 m NW

Explanation:

Hello, nice to meet you.

this answer will help for you

The time of motion of the track star is determined as 0.837 s.

The time of motion of the track star is calculated as follows;

T = (2u sinθ)/g

where;

T = (2 x 12 x sin20)/9.8

T = 0.837 s

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A driver have to stop for a school bus when the red lights are flashing and there is no barrier between his/her vehicle and the bus.

Traffic rules are rules that are expected to follow by the road users for the safety of everyone using the road.

For instance, when the red lights are flashing , it simply means to stop, while the green light means that the vehicle can continue to move, and yellow light means to be at alert to move.

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Answer:

3 767 400 joules

Explanation:

4.186 J/g-C   is the specific heat of water

25  to 115  is 90 degrees C change

10 000 g   is 10 kg of water

10 000 * 90 * 4.186 = 3 767 400 Joules

Explanation:

v=u+at, where v,u,a and t are the final velocity, initial velocity, acceleration and time, respectively.

For t=0 s to t=30 s , a =8 m/s 2.

For t=30 s to t=50 s , a = 5 m/s 2.

For t=50 s to t=110 s , a = 0 m/s 2.

For t=110 s to t=130 s , a is such that the body comes to rest at the end of this period.

For t=0 s to t=30 s ,v=0+8t⇒v=8t m/s.

At t=30s,v=8×30=240 m/s.

For t=30 s to t=50 s ,v=240+5(t−30)⇒v=90+5t m/s

At t=50s,v=90+5×50=340 m/s.

For t=50 s to t=110 s ,v=340 m/s.

For t=110 s to t=130 s ,v=340+a(t−110).

The body comes to a halt at t=130 s ⇒0=340+a(130−110).

0=340+20a⇒a=−34020=−17 m/s2.

For t=110 s to t=130 s ,v=340−17(t−110)=2210−17t m/s.

26.676 × 10³ kg is the weight of the aluminum rod.

Given:

Length of cylindrical rod (h) = 45 cm

Diameter of a cylindrical rod = 4.53 cm

Radius of a cylindrical rod (r) = 2.3 cm

The density = 3.7*10^3kg/m^3

Volume of a cylindrical rod = πr²h

                                             = 3.14× (2.3)² × 45

                                             = 747.89 cm

                                             = 7.4789 m

To find weight ;

                         ρ = [tex]\frac{Mass}{Volume}[/tex]                  ; ρ = Density

                        Mass = ρ × Volume

                                  = 3.7 × 7.48 × 10³

                                  =27.676 × 10³ kg

Therefore, the weight of the aluminum rod is 27.676 × 10³ kg.

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The cornea is shaped like a dome and bends light to help the eye focus. Some of this light enters the eye through an opening called the pupil (PYOO-pul). The iris (the colored part of the eye) controls how much light the pupil lets in. Next, light passes through the lens (a clear inner part of the eye).

Answer:

To check whether a chemical equation is balanced or not we usually look if elements on the product side are numerically equal to the reactant side or not.

A. Na + MgCl₂ → NaCl + Mg

Reactant Product

Na = 1 1

Mg = 1 1

Cl = 2 1

Unbalanced

B. 2LiOH + H₂S → Li₂S + 2H₂O

Reactant Product

Li = 2 2

S = 1 1

O = 2 2

H = 4 4

Balanced

C. AgNO₃ + NaCl → NaNO₃ + AgCl

Reactant Product

Ag = 1 1

N = 1 1

Na = 1 1

Cl = 1 1

O = 3 3

Balanced

D. 3PBr₃ + 2Cl₂ → 3PCl₃ + 2Br₂

Reactant Product

P = 3 3

Br = 9 4

Cl = 4 9

Unbalanced

Therefore, equations B and C are balanced chemical equations.

Answer:

Distance is the total length travelled, or in other words, it is a measure of how far apart two objects are.

Displacement, on the other hand, the difference between the starting and and ending positions of an object.

For example, if a person walks 10m forwards, then 7m backwards, thereby ending up where he started, he will have travelled a distance of

10 + 7 = 17m .

But the difference between his starting and finishing positions is

10 - 7 = 3m.

If, however, the man walked 10m forwards and then 10m backwards, the distance he covered would be 10 + 10 = 20m, but the displacement would've been 0 as there would be no difference between his starting and ending positions.

Let me know if you still don't understand.

The speed of the car moving after 7 seconds will be 31.5 m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the car = 1289  Kg.

u is the initial velocity  = 0 m/sec

a is the acceleration in m/sec²

v is the velocity after 7 seconds =?

The power developed is;

P =FV

F=ma

P=maV

183831=1289 kg × a × V

a = 142.61 / V

From Newton's second equation of motion;

V=u+at

V=0+at

V=(142.61/V)t

V²=142.61 × 7

V=31.5 m/sec

Hence, the speed of the car moving after 7 seconds will be 31.5 m/sec.

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The speed of Vc at the instant bead collide is 1.38 m/s and the instant speed of Vd at the instant bead collide is 0.106 m/s.

The force of attraction on the beads are due to both gravitational force and electrostatic force

As gravitational force is very weak force as compared to electrostatic force the net force will be due to electrostatic force only.

Net Force = Electrostatic force

Net Force = K q1 q2 / r²

Net Force = (9 × 10⁹) (2.5 × 10⁻⁹) (1 × 10⁻⁹) / (14 × 10⁻³) (as distance between there centre of mass is 14 mm)

Net Force = (9 × 2.5 × 10⁻⁶) / 14

Net Force = 1.6 × 10⁻⁶

For bead c

Force = Mc × Ac = 1.6 × 10⁻⁶

(1 × 10⁻³) × Ac = 1.6 × 10⁻⁶

Ac = 1.6 × 10⁻³

Acceleration of bead C is 1.6 × 10⁻³ m/s²

For bead d

Force = Md × Ad = 1.6 × 10⁻⁶

(1.7 × 10⁻³) × Ad = 1.6 × 10⁻⁶

Ad = 0.94 × 10⁻³

Acceleration of bead D is 0.94 × 10⁻³ m/s²

Let us suppose bead C travels y distance before collision

So bead D should travel 12-y distance before collision

So speed of both the beads before the collision can be find out by using newton third law of motion

For bead C

Vc² - Uc² = 2 Ac s

Vc² = 2 × 1.6 × 10⁻³ × y

Vc² = 3.2 × 10⁻³ × y

Vc = √(3.2 × 10⁻³ × y)

For bead D

Vd² - Ud² = 2 Ad s

Vd² = 2 × 0.94 × 10⁻³ × (12-y)

Vd² = 1.88 × 10⁻³ × (12-y)

Vd = √(1.88 × 10⁻³ × (12-y))

Applying energy conservation

initial = final

0 + 0 = (1/2)McVc² - (1/2)MdVd²

(1/2)McVc² = (1/2)MdVd²

McVc² = MdVd²

1 × 10⁻³ × 3.2 × 10⁻³ × y = 1.7 × 10⁻³ × 1.88 × 10⁻³ × (12-y)

3.2 × y = 3.2 × (12-y)

y = 12-y

2y = 12

y = 6

Putting the value of y in Vc and Vd

Vc = √(3.2 × 10⁻³ × y)

Vc = √(3.2 × 10⁻³ × 6)

Vc = √(19.2 × 10⁻³)

Vc = √0.0192

Vc = 1.38 m/s   (approximately)

Vd = √(1.88 × 10⁻³ × (12-y))

Vd = √(1.88 × 10⁻³ × (12-6))

Vd = √(1.88 × 10⁻³ × 6)

Vd = √(11.28 × 10⁻³)

Vd = √0.01128

Vd = 0.106 m/s   (approximately)

So the speed of Vc at the instant beads collide will be approximately 1.38 m/s and Vd at the instant speed the beads collide will be approximately 0.106 m/s.

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They cannot be divided and still keep the properties of the element true about all of these atoms. Option D is corect.

The atom consists of matter that may be split without releasing electrical charges.

It's also the smallest unit of matter with chemical element features. As a result, the atom is the fundamental unit of science.

In the nucleus proton and the neutron is exists. The condition of the atom to be electrically neutral is that the number of the proton and electron should be the same.

They cannot be separated while still maintaining the element's characteristics for each and every one of these atoms.

Hence, option D is corect.

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Answer:

The correct answer is d, they cannot be divided and still keep the properties of the element.

Explanation:

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The maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.

The poles of the earth are the North and South poles.

The North is taken as the reference point.

The true north is a fixed point on the globe and gives the true North and South poles.

The Magnetic north is the direction that a compass needle points to as it aligns with the Earth's magnetic field and gives the magnetic North and South poles.

The maximum maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.

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