Answer:
(1)540 J
(2)67.5 J/s or 67.5W
(3)look at underline statement in explanation
Explanation:
(1) acceleration = change in speed ÷ time
= (9-5)m/s ÷ 8s
= 0.50 m/s²
resultant force of object during motion
= mass(in kg) × acceleration
= 6 × 0.50 = 3 N
displacement of force applied
= area under speed time graph(when sketched out, it's a trapezium)
= ½ × (5+9) × 8
= 180m
work done is measured in joules
= force × displacement of force applied
= 3N × 180m
= 540 J
detailed explanation:
altho the final unit for the work done should be Nm, but J is equal to Nm.
(2) Power is measured by J/s
therefore power = 540 J ÷ 8s = 67.5 J/s or 67.5 W
(3) the object accelerates constantly along a straight road
water flows through a 4.0-cm-diameter horizontal pipe at a speed of 1.3 m/s. the pipe then narrows down to a diameter of 2.0 cm. part a ignoring viscosity, what is the pressure difference between the wide and narrow sections of the pipe? ignoring viscosity, what is the pressure difference between the wide and narrow sections of the pipe? 850 pa 3400 pa 9300 pa 12700 pa 13500 pa
The pressure difference between the wide and narrow sections of the pipe is 12.675 kPa.
Fluid pressure is the size of the force in keeping with a unit place on an object inside the fluid or on the surface of a closed field. This pressure may be resulting from gravity, acceleration, or by means of forces outside a closed container. in view that fluid has no specific shape, its pressure applies in all directions.
Pressure is defined as pressure carried out in line with the unit vicinity. Mathematically it is given by way of, P=FA. wherein F is the pressure performing perpendicular to the surface place A. the same old unit of pressure is the pascal (Pa), equivalent to at least one newton according to meter squared (N/m 2 ).
A1 v1 = A2 v2 ;
v1 / v2 = A2 / A1 ;
1.3 / v2 = ( 2 / 4 ) ^2 ; since area is proportional to diameter square :
v2 = 5.2 m /s
Using bernouli principle ,
P1 + ρ v1^2 / 2 = P2 + ρ v2^2 / 2 ;
P1 + 1000 * 1.3^2 / 2 = P2 + 1000 * 5.2^2 / 2 ;
ΔP = 12675 Pa
or ΔP = 12.675 kPa
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. a diverging lens has a focal length that has a magnitude of 33.0 cm. an object is placed 21.0 cm in front of this lens. calculate the magnification.
A diverging lens has a focal length that has a magnitude of 33.0 cm. an object is placed 21.0 cm in front of this lens. The magnification will be -12.833 cm
diverging lens = concave lens
focal length = - 33 cm
u = - 21 cm
magnification = image distance / object distance
using lens formula
1/v - 1/u = 1/f
1/v = 1/f + 1/u
= 1/-33 -1/21
v = -12.833 cm
A diverging lens has a focal length that has a magnitude of 33.0 cm. an object is placed 21.0 cm in front of this lens. The magnification will be -12.833 cm
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3. A luxury ship cruises at Miami, Florida at 150 mph and is brought to a stop uniformly by a motor
boat in 500 ft. Find the (a) acceleration and (b) the time required to stop.
Given:
a) Acceleration is calculated as 29.54 m/s^2
b) Time required to stop is calculated as 2.27 seconds
What is acceleration?The rate of change of the velocity of an object with respect to time is called as acceleration and it is a vector quantity. Acceleration is the rate at which velocity changes with time in terms of both speed and direction. An object moving in a straight line is accelerated if it's speed goes up or down.
Given, speed = 150 mph
1mph = 0.447 m/s
150mph = 67.056 m/s
and distance = 500 ft
1ft = 0.30 m
500 ft= 152.4 m
time= distance / speed
= 152.4/ 67.056
= 2.27 sec
Acceleration= velocity/ time
= 67.056/2.27
Acceleration = 29.54 m/s^2
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. A stone is thrown from ground level vertically upwards with a velocity of 40 m/s.
Find the maximum height to which the stone rises and its total time of flight, neglecting
air resistance.
Explanation:
maximum height to which the stone can reach is 80 m
h=80
total distance = 2h
= 160 m
The total distance travelled by the stone would be the distance it covered while moving up and then the distance it covered while coming back down.
how much work must be done to stop a 900- kg car traveling at 110 km/h ? express your answer to two significant figures and include the appropriate units.
The work that is needed to be done to stop the car is 419.96 KJ
WorkWork in physics is the amount of energy given to move an object or objects.
We have,
The mass of the car, m = 900 kg
The initial velocity of the car, v₀ = 110 km/h = 30.55 m/s
Since the vehicle has to be stopped, the final velocity will be v' = 0.
Now, we know that
The work done to stop the car will be = Kinetic energy possessed by the car
W = Δ K.E
W = [Final K.E.] – [Initial K.E.]
= ½ (m) {(v')² - (v₀)²]
Substituting the given values in the above formula, we get
= ½ (900) {(0)² - 30.55)²]
= (450) (933.30)
= 419,986.12 J = 419.96 KJ
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The ability of a covalently bonded atom to attract the shared electrons is called.
Electronegativity is the ability of covalently bonded atom to attract the shared electrons .
What is covalent bond ?
Covalent bond, in chemistry, an interatomic bond formed by sharing a pair of electrons between two atoms. Bonding occurs through the electrostatic attraction of atomic nuclei to the same electrons. A covalent bond is formed when the combined atoms have a lower total energy than the atoms separating them. Covalently bonded molecules include the inorganic substances hydrogen, nitrogen, chlorine, water, and ammonia (H2, N2, Cl2, H2O, NH3) and all organic compounds. In structural representations of molecules, bonds are indicated by solid lines connecting pairs . Covalent bonds are directional. That is, the bonded atoms prefer a particular orientation to each other. This gives the molecule a particular shape, like the angled (bent) structure of the H2O molecule.
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A hypothetical wave has 6. 6 j of energy. What is its hypothetical, approximate frequency?.
The approximate frequency is 9.96 × ³³ s-1
Solution:
Hypothetical wave energy = 6.6 J
Hypothetical wave frequency =?
E = HV
v = E / h
Where,
E = energy in joules
h = plank's constant & = 6.626 × 10-34 J.s
v = frequency in s-1
On substituting the values in the above formula :
v = E / h
v = 6.6 J / 6.626 × 10-34 J.s
v = 0.996 × 1034 s-1
v = 9.96 × 1033 s-1
Hence hypothetical wave frequency is = 9.96 × 10³³ s-1.
Count the markers to determine the frequency of each class. The relative frequency of a data class is the percentage of data items in that class. A joule is a unit of energy in the International System of Units. This is the work done when a force of 1 Newton displaces a mass 1 meter in the direction of the applied force.
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when the sampling rate increases and approaches the signal frequency, what will happen to the waveform captured? (read carefully)
The greater the number of samples captured, the more detail about where the waves rise and fall is recorded
What happens if the sample frequency is increased?
The greater the number of samples captured, the more detail about where the waves rise and fall is recorded, and the higher the audio quality. Furthermore, the form of the sound wave is more precisely represented. What factors influence sampling frequency.
The sampling frequency or sampling rate, fs, is the average number of samples obtained in one second, so fs = 1/T. Its units are samples per second or hertz, for example. 48 kHz equals 48,000 samples per second.
The greater the number of samples captured, the more detail about where the waves rise and fall is recorded, and the higher the audio quality. Furthermore, the form of the sound wave is more precisely represented.
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how do atomic structures determine the properties of a substance?
Answer:
the number of protons (atomic number) determines the chemical properties of the atom
Explanation:
Answer:
The number of protons in an atom determines its chemical properties.
Explanation:
An atom is composed of a nucleus and electrons that go around it. The nucleus is composed of protons with a positive charge and neutrons without charge, and the number of protons (atomic number) determines the chemical properties of the atom (element type)
a current of 6.51 a6.51 a in a solenoid of length 11.0 cm11.0 cm creates a 0.341 t0.341 t magnetic field at the center of the solenoid. how many turns does this solenoid contain?
The number of turns this solenoid contains is 4422 turns.
The magnetic field is the location around a magnet wherein the effect of magnetism is felt. We use the magnetic subject as a device to explain how the magnetic force is distributed inside the space around and within some thing magnetic in nature.
The Earth's magnetic field does now not directly affect human health. human beings advanced to live on the earth. high altitude pilots and astronauts can experience higher degrees of radiation for the duration of magnetic storms, however, the risk is due to the radiation, no longer the magnetic area itself.
Magnetic fields are produced via transferring electric powered fees. the entirety is made up of atoms, and every atom has a nucleus fabricated from neutrons and protons with electrons that orbit around the nucleus. for the reason that orbiting electrons are tiny moving costs, a small magnetic field is created around every atom.
Calculation:-
B = uNI/L
⇒ 339 = (4pi X 10^-7)(6.71)(N)/.11
⇒ N = 4422 turns
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a measurement was made of the magnetic field due to a tornado, and the result was 15.50 nt to the north. the measurement was made at a position 8.70 km west of the tornado. what was the magnitude (in a) and direction of the current in the funnel of the tornado? assume the vortex was a long, straight wire carrying a current.
674.25 A current is flowing along the funnel of tornado.
Explain magnetic field around a current carrying straight wire?All known magnetic fields are due to current charges (or charges in motion). A wire carrying current produces a magnetic field due to the movement of charges within the conductor. Magnetic field lines around a long wire carrying current form concentric circles around the wire.
Assuming the vortex was a long, straight wire carrying a current,
Magnetic field (B) = 1.55 × 10⁻⁸ T
Radius of tornado (R) = 8700 m
Current in the funnel (I) = ?
For a current carrying straight conductor:
∫BΔL = μ₀I
B(2πr) = μ₀I
I = B(2πr)/μ₀
μ₀ = 4π × 10⁻⁷ H/m
I = 1.55 × 10⁻⁸ (2×3.14×8700)/4π × 10⁻⁷
I = 674.25 A
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predict how you think two inductors in series will act as an equivalent inductor. will they add together, add as 1/l or some other relationship?
The total inductance of inductors connected in series is equal to the sum of the inductances of the individual inductors.
Briefing:
The amount of voltage dropped across an inductor for a specific rate of current change through it is the undisputed indicator of inductance.
The total voltage reduced as a result of a change in current will be additive with each inductor if inductors are linked in series (sharing the same current and experiencing the same rate of change in current), resulting in a higher total voltage than either of the individual inductors alone. Greater inductance results from higher voltage at the same rate of current change.
As a result, the overall inductance of a series of inductors is greater than the sum of the inductances of each individual inductor. Similar to how series resistances are calculated, the series total inductance formula takes the same form:
L(total) = L1+L2+L3….Ln
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in this problem, we didn't address the effect of possible differences in the heights of the pistons. if the column of fluid is higher in the small piston, the fluid weight assists in supporting the car, reducing the necessary applied force. if the column of fluid is higher in the large piston, both the car and the extra fluid must be supported, so additional applied force is required. question if the radius of the output piston is doubled, the output force increases by a factor of:
The output force increases by a factor of F2 = 14, 148. 207 N.
Solution:
To find fr let's plug in the value of Fr, Yi¹ Ye in Og f¹
825/(8.51)² = f₂/(33.6)²
F2 = 14, 148. 207 N
The force which is applied to an object by another object. A person pushing a barrel is an example of applied force. When the person pushes the barrel then there is an applied force acting upon the barrel. An applied force is a force that is applied to an object by a person or another object.
If a person is pushing a desk across the room then there is an applied force acting upon the object. The applied force is the force exerted on the desk by the person. Applied forces can be broadly divided into two types: contact and non-contact forces. Contact forces are those where the interaction between two or more objects occurs while the objects are in physical contact, whereas non-contact forces exist between objects that are not in physical contact.
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1 how much work must denise do to drag her basket of laundry of mass 5.0kg a distance of 5.0 m along a floor, if the forse she exerts is a constant 30.0 n at an angle of 60.0 degrees with the horizontal?
The amount of work done by denise to drag her basket of laundry of mass 5 kg is 75 J.
Work is defined as the product of distance and force.
To calculate the amount of work done by denise to drag the basket, we use the formula below.
W = Fd cosθ
where, W is the work done by the denise
F is the force applied to the basket
d is the distance
θ is the angle made with the horizontal
Given that, F = 30 N
d = 5 m
θ = 60°
Substituting the values in the above equation,
W = 30* 5* cos 60° = 75 J
Thus, work done by the denise is 75J.
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when the ball is at its lowest point, is the tension in the string greater than, less than, or equal to the ball's weight?
When the ball is at its lowest point, the tension in the string is greater than the ball's weight.
Stretching, stretching behaviour, or the state of being stiffly stretched. muscle tensing: stress perception 1b. : one or both of two counteracting forces that induce or tend to cause extension.
Compression force's opposite is tension. All of the things in the scene that are in contact with one another apply forces to one another. The best demonstration of a tension force is when a rope is being pulled. The rope builds up a lot of tension when a pull force is applied to it.
The pressure inside a vessel, such as the pressure in the blood vessels (blood pressure). For instance, hypertension is the medical term for high blood pressure. Stress, particularly when it manifests as tensed scalp muscles, bottled-up emotions, or anxiety.
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if the car speeds up at a steady 1.7 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?
Using the theories of centripetal acceleration, we got that 9.388 sec after the starting magnitude of its centripetal acceleration equal to the tangential acceleration.
We know that centripetal acceleration is given by =v²/r,
where v is the velocity along curved road and r is the radius of the curved road.
We have from the question, Acceleration (a) = 1.7m/sec²
Radius(R) = 150 m
Therefore,
a=v²/r
=>1.7=v²/150
=>v²=1.7×150
=>v²=255.0
=>v = 15.96 m/sec
Now, we know that the formula for tangential acceleration is the product of acceleration and its time ,which means
v = a x t
15.96 = 1.7 x t
t = 9.388 sec.
Hence, if the car speeds up at a steady 1.7 m/s2 , the time after starting when the magnitude of its centripetal acceleration equal to the tangential acceleration is 9.388 sec
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Brain waves that are lowest in frequency and highest in amplitude are called _____________ waves.
Brain waves that are lowest in frequency and highest in amplitude are called delta waves.
What are brain waves?Brain waves such as alpha waves or delta waves refer to the oscillations in the electrical differential of potential from different parts of the brain, which occur as a differential due to the action that an individual is making and it may indicate the brain areas working in a particular activity such as sleep.
Therefore, with this data, we can see that brain waves depend on the differential electrical potential that produces oscillations in the brain in response to the activity of different parts of our brain.
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a rigid rod of length and mass has small point like masses and attached as shown. here 0.08 kg, 0.6 m. the rod is spinning in a horizontal plane about a vertical axis passing through the smaller mass . the linear speed of mass is 2.5 m/s. find the angular momentum of the rod and masses system with respect to the point on the fixed axis that intersects with the rod.
The angular momentum of the rod and masses system is 2.5 ms.
Angular momentum is the rotational analog of linear momentum. it is an essential bodily quantity due to the fact it is a conserved amount—the entire angular momentum of a closed device remains constant. Angular momentum has both a route and a value, and both are conserved.
Angular momentum is defined as The property of any rotating item given via second of inertia instances angular velocity. it's far the property of a rotating frame given with the aid of the made of the instant of inertia and the angular pace of the rotating item.
Calculation:-
The moment of inertia of the system about the basics is,
I e mos + (2m) [2 = me+ 2m22 3
= 7(0-0819) 0.6m) 2
= 0.0672 LG. ma ✓
= 2.5 ms
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describe the path created by time safari inc. what is the purpose of this path? 4. what might happen if someone steps off of the path?
What is path?
Distance is the term used to describe how far an automobile will go to get from one place to another; it is also referred to as the path length. If it chooses the shortest route, though, it becomes the displacement. A car's displacement is sometimes defined as the difference between its original and final positions.Everywhere we turn, we can see things moving. Children play, birds soar, animals forage for food, people stroll or run, cars speed down the highway, rivers flow, etc. In essence, motion exists everywhere in the cosmos.However, The body's actual path length between its initial and final positions is known as the path length.
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54(a) Define the capacitance of a capacitor
(b) State:
three factors on which the capacitance of
a parallel plate capacitor depends.
(ii) two uses of capacitors.
(c) The plates of a parallel - plate capacitor
are 5mm apart and 2m² in area. The places
are in vacuum. A potential difference of 1k
is applied across the capacitor.
Calculate the:
(i)
Capacitance
ii) charge on each plate
iii) electric intensity in the space between them
iv) energy stored in the capacitor
[NECO,2000] [Permitivity of free space.
ε =8.85x10-¹2 Nm²C²]
Capacitance is the ability of an electrical conductor and insulator system to store electric charge when there is a potential difference between the conductors.
Capacitance is 3.54×[tex]10^{-9}[/tex] F, energy stored is [tex]2*10^5NC^{-1}[/tex].charge on each plate is 3.54×[tex]10^{-6[/tex] C.
What's the meaning of capacitance?Capacitance is the ability of an electrical conductor and insulator system to store electric charge when there is a potential difference between the conductors. C is the symbol for capacitance. Capacitance is defined as the ratio of the stored electrical charge to the voltage across the conductors.The area of the plates, the distance between them, and the nature of the insulating material or dielectric between them are the three elements that impact the capacitance of a parallel-plate capacitor.The farad (abbreviated F) is the unit of electrical capacitance named after the English physicist and chemist Michael Faraday. The capacitance C of a capacitor is defined as the ratio of the stored charge Q to the applied dc voltage U: C = Q/U.a parallel - plate capacitor are 5mm apart and 2m² in area.
potential difference = 1k
d=5×[tex]10 ^ {-3}[/tex]m,
A=2[tex]m^2[/tex],
V=1000 volt,
Capacitance, C=∈[tex]_0\frac{A}{d}[/tex]
=(8.85×[tex]10^{-12}[/tex]×2)/5×[tex]10^{-3}[/tex]
=3.54×[tex]10^{-9}[/tex] F
charge on each plate , q=CV=3.54×[tex]10^{-9}[/tex]×1000
=3.54×[tex]10^{-6[/tex] C
energy stored ,E=σ/∈0
=Q/(A∈0)
=(CV)/(A∈0)
=[tex]\frac{3.54*10^{-9}*1000}{2*8.85*10^{-12}}[/tex]
=[tex]2*10^5NC^{-1}[/tex].
Capacitance is 3.54×[tex]10^{-9}[/tex] F, energy stored is [tex]2*10^5NC^{-1}[/tex].charge on each plate is 3.54×[tex]10^{-6[/tex] C.
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A body of mass M moving with velocity V collides head on with another body of mass 2M which is initially at rest. Determine the ratio of kinetic energy of colliding bodies before and after collision 
The ratio of kinetic energy of colliding bodies before and after collision is 9:1
What is kinetic energy?Kinetic energy refers to be the energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.
Kinetic energy of the body before collision (KE₁): ¹/₂ mv²
Velocity (v') after collision:
v' = [(m₁ - m₂)/(m₁ + m₂)] v
Since, m₁ = 2m
m₂ = m
Substitute the values in the formula:
v' = [m/3m]v
v' = v/3
Now, kinetic energy after collision (KE₂): ¹/₂ mv'²
= ¹/₂ m(v/3)²
= ¹/₂ m(v²/9)
Now the ratio of kinetic energies:
KE₁ / KE₂ = (¹/₂ mv²) / (¹/₂ m(v²/9))
KE₁ / KE₂ = 9/1
Or 9:1
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in order to generate a torque of 2.5 n-m, what magnitude of force must be applied at a perpendicular distance of 0.8 m from the axis of rotation?
In order to generate a torque of 2.5 n-m , 3.125 N force must be applied at a perpendicular distance of 0.8 m from the axis of rotation
torque = Force * distance from the axis of rotation
given
torque = 2.5 Nm
distance from the axis of rotation (d) = 0.8 m
Force = torque / d = 2.5 / 0.8 = 3.125 N
In order to generate a torque of 2.5 n-m , 3.125 N force must be applied at a perpendicular distance of 0.8 m from the axis of rotation
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when a 2.5 g penny is placed on a turntable rotating at 33 rpm (revolutions per minute), it is found that the farthest away from the center of the turntable that it can be located without slipping off is 10 cm. what is the coefficient of static friction between the penny and the surface of the turntable?
The coefficient of static friction between the penny and the durcae of the turntable is 11.9.
The mass of the penny on the turntable rotating at 33 rpm is 2.5 grams. The penny was found to be located at a distance of 10cm from the center of the turntable.
Now, friction force on the penny will be.
Fr = uW
W is the weight of the penny,
u is the coefficient of friction.
The centripetal force on the penny will be,
F = Mw²r
m is the mass of penny,
w is the angular speed,
r is the distance of the penny from the center.
Now, if the penny stops,
Fr = F
so, we can write,
uW = Mw²r
Putting values,
u(2.5 x 10) = 2.5 x (3.45)² x 0.10
u = 11.9
The value of the coefficient of static friction between the penny and the surface of the turntable is 11.9.
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a professional quarterback needs to be able to throw a football the entire length of the field. what is the minimum initial velocity needed to get the ball 91 m down field? assume that air resistance is negligible. recall that the time of flight for projectile motion when the object lands at the height it is launched from is?
the minimum initial velocity needed is 30.17 m/s and time of flight for projectile motion is 4.27 seconds.
Given parameters:
Horizontal range of the projectile; H = 91 m.
Let, acceleration due to gravity = 10 m/s².
Then minimum initial velocity required is = √gR = √(10×91) m/s = 30.17 m/s.
And, Time of flight in this case: T = √2×u/g = √2×30.17/10 = 4.27 seconds.
Hence, the minimum initial velocity needed is 30.17 m/s and time of flight for projectile motion is 4.27 seconds.
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The basic requirement for a cloud to collapse to form a star is that __________.
Answer:
Explanation:
The interstellar gas cloud will remain in hydrostatic equilibrium as long as the kinetic energy of the gas pressure is in equilibrium with the potential energy of the internal gravitational force.
To maintain equilibrium, the potential gravitational energy must be twice the internal thermal energy. If the cloud is so massive that the gas pressure is insufficient to maintain it, the cloud undergoes gravitational collapse.
According to newton’s first law of motion, an object in motion will stay in at the same speed and direction unless acted upon by what kind of force?.
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.
A force is an effect that can alter an object's motion according to physics. When a mass-containing object increases its velocity, such as when it travels away from rest, a force can cause it to accelerate. A push or a pull is a straightforward method to explain force.
A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P).
The net force acting on an object is equal to the rate at which its momentum changes over time, according to Newton's second law in its original formulation.
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if it requires 5.0 j of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be required to stretch it an additional 4.0 cm ?
2.5 J work will be required to stretch it an additional 4.0 cm.
Work done is elaborated in such a manner that it consists of each force exerted on the frame and the full displacement of the frame. This block is preceded by using a regular force F. The purpose of this pressure is to transport the body a certain distance d in an immediate course inside the path of the pressure.
The work is stated to be accomplished while force is implemented on an object's movements via a distance within the route of the utility of pressure. Scientists use the joule to measure work. One joule is the same as the paintings achieved by way of a force of one newton to move an item one meter in the path of the force.
Calculation:-
Work done is inversely proportional to the distance,
W₁/W₂ = L₂/L₁
W₂ = W₁L₁/L₂
= 5 × 2 /4
= 2.5 J
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If the sprinter from the previous problem accelerates at that rate for 20. 00 m and then maintains that velocity for the remainder of a 100. 00-m dash, what will her time be for the race?.
The time taken to finish the race by using uniform motion is 120 /v seconds.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
s = 20 m
x = 100 m
vo = 0 m/s
Assume that the final velocity is v
vt = v m/s
Find the time needed to reach the velocity
s = vo . t + 1/2 . a . t²
20 = 0.t + 1/2 . v/t . t²
20 = v . t/2
t = 40 / v seconds
remaining distance = x - s
remaining distance = 100 - 20 = 80 m
remaining time = remaining distance / v
remaining time = 80 / v
Find the time taken to finish all of the race
total time = t + remaining time
total time = 40/v + 80/v
total time = 120 /v seconds
where v is the terminal velocity.
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A 1. 0 newton metal disk rests on an index card that is balanced on top of a glass. What is the net force acting on the disk?.
The net force acting on the metal disk is equal to 1 Newton.
According to the third law of motion proposed by newton,
Each and every action of force has an equal and opposite reaction force.
This reaction force will be equal in magnitude of the action force but will be in the opposite direction.
So, here in this case, the metal disk is balanced on the top of the glass.
The metal disk is applying a force of one Newton on the glass. So, the glass will also apply an equal force on the metal disk,
This net force working on the disk is called the normal force, so the net force on the metal disk is 1 Newton.
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how fast does water flow from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water? ignore viscosity.
The speed of water flowing from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water is 11.29 m / s
v = √ 2 g h
v = Speed of water
g = Acceleration due to gravity
h = Height
g = 9.8 m / s²
h = 6.2 m
v = √ 2 * 9.8 * 6.5
v = √ 127.4
v = 11.29 m / s
This is derived from an equation of motion,
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
u = 0
v² = 2 a s
v = √ 2 a s
Therefore, the speed of water flowing from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water is 11.29 m / s
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