An old-fashioned single-play vinyl record rotates on a turntable at 45.0 rpm. What are (a) the angular velocity in rad/s and (b) the period of the motion? nand (h the period of the

Answers

Answer 1

The angular velocity in rad/s are 4.7124 rad/s and the period of the motion is 1.333s.

a) Find angular velocity

Given

45 rpm that is rotations per min  converting it in to rad/s

we know that the angular displacement for one rotation is  2pi rad

45 rpm = 45*2pi/60

            = 4.7124 rad/s

So,the angular velocity is W = 4.7124 rad/s

b) We have relation between the angular velocity and time period is  

W = 2pi /T

T = 2pi/W

T = 2pi/4.7124 s

T = 1.333 s

Angular velocity is a physical quantity that describes the rate of change of the angular displacement of an object with respect to time. It is a vector quantity, and its direction is perpendicular to the plane in which the object is rotating. The magnitude of the angular velocity is given by the ratio of the angular displacement of the object to the time taken to complete the displacement. It is measured in radians per second (rad/s).

Angular velocity is an important concept in physics and is used in the study of rotational motion. It is used to calculate the centripetal force required to maintain circular motion and is also used to describe the motion of planets and other celestial bodies. In addition, angular velocity is used in engineering and mechanics to design and analyze rotating machines and devices.

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Related Questions


A skier with a mass of 55 kg is skiing down a snowy slope that has an incline of 30°.
Find the coefficient of kinetic friction for the skier if friction is known to be 25 N.

Answers

The coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.

What is Kinetic friction?

Kinetic friction may be characterized as a type of force that considerably resists the relative movement of the surfaces once they're in motion. It is just the opposite of static friction.

According to the question,

The total weight of a skier = mass of a skier × gravity = 55 × 9.8

The angle at which it inclines = 30° i.e. θ = 30°.

Normal force, N = mgcosθ  

The friction force, F = kinetic friction (N)

25 N = Kf (55 × 9.8 × 30)

Kf = 0.463.

Therefore, the coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.

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You use a ruler marked with 1 mm increments to measure the lengths of the height h of a block and find h = 121 mm. According to the half least count rule, what is the uncertainty in your measurement of the height?

Answers

The uncertainty in height is, 0.5 mm.

The "half least count rule" states that the uncertainty in a measurement is equal to half of the smallest division on the measuring instrument. In this case, the ruler is marked in 1 mm increments, so the smallest division is 1 mm.

Using the half least count rule, the uncertainty in the measurement of the height is,

uncertainty = 1/2 * 1 mm = 0.5 mm

Therefore, the uncertainty in the measurement of the height is 0.5 mm. We can express the result as,

h = 121 ± 0.5 mm

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In which collision(s) is momentum conserved?
A.Elastic
B.Inelastic
C.Perfectly inelastic​

Answers

Momentum is conserved in both elastic and perfectly inelastic collisions.

In an elastic collision, the total momentum of the colliding objects is conserved before and after the collision. This means that the sum of the momentum of the objects before the collision is equal to the sum of the momentum of the objects after the collision.

In a perfectly inelastic collision, the two objects stick together after the collision, forming a single object with new momentum. In this case, the total momentum of the system is also conserved.

However, in an inelastic collision, momentum is not conserved, as some of the momenta are transformed into other forms of energy, such as heat or sound. This means that the total momentum of the objects before the collision is not equal to the total momentum of the objects after the collision.

Answer:

Explanation:

A

How much of the total energy in Problem 3 and 4 has been transformed to kinetic energy?

Answers

Answer:

Explanation:To find the change in kinetic energy, we subtract the initial energy from the final energy. This answer in positive because the car gains energy when it increases its velocity.

The energy of the flower pot is potential energy. The potential energy of the flower pot when it weighs 3 N in a height of 300 m is 900 J.

What is potential energy ?

Potential energy of an object is the energy generated by virtue of its position whereas, kinetic energy is the energy generated by virtue of its motion.

Potential energy = mass x gravity x height

Given the weight of the flower pot is 3N. That is the force by gravity. Then displacement = 300 m.

Thus, P = 3 m × 300 m = 900 J.

If the flower pot is placed at a height of 10 m, the potential energy reduces as follows:

Potential energy = 3 x 10 m = 30 J.

Remaining energy is converted to the kinetic energy

ie. 900 J - 30 J = 870 J

Therefore, 870 J is transformed to kinetic energy.

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Your question is incomplete. But your complete question probably was:

A flower pot weighing 3 newtons is sitting on a windowsill 300 meters from the ground is the energy of the flower pot potential of kinetic? How many joules is this?

When the flower pot in problem 3 is only 10 meters from the ground, what is its potential energy?

How much of the total energy in problems 3 and 4 has been transformed to kinetic energy?

What is the smallest possible value of the principal quantum number n for an s electron?

Answers

Answer:

The smallest possible value of the principal quantum number (n) for an electron in an atom is n = 1. This is referred to as the first energy level or the "1s" orbital, and it corresponds to the lowest energy state of an electron in an atom.

Explanation:

In general, the value of n determines the size and energy of the electron orbital. The larger the value of n, the larger the size of the orbital and the higher the energy of the electron. The smallest possible value of n is therefore always 1, and it corresponds to the electron being in its lowest energy state.

A glider of length 12.4 cm moves on an air track with
constant acceleration (Fig P2.31). A time interval of 0.628 s
elapses between the moment when its front end passes a
fixed point A along the track and the moment when its
back end passes this point. Next, a time interval of 1.39 s
elapses between the moment when the back end of the
glider passes the point A and the moment when the front
end of the glider passes a second point B farther down the
track. After that, an additional 0.431 s elapses until the
back end of the glider passes point B. (a) Find the average
speed of the glider as it passes point A. (b) Find the acceleration
of the glider. (c) Explain how you can compute the
acceleration without knowing
the distance between points A
and B.

Answers

[tex]19.7cm/s and 4.70 cm/s^2[/tex]  are the average speed and acceleration of the glider.

(a) As the glider's front end crosses point A, start a timer at t=0. The instantaneous speed at t=0.314s, halfway through the time interval, is [tex]12.4cm/(0.628s)=19.7cm/s[/tex], which equals the glider's average speed for the interval between t=0 and t=0.628s.

(b) The instantaneous speed at the point [tex]t=(2.02+2.45)/2=2.23s[/tex]. is equal to [tex]12.4cm/(0.431s)=28.8cm/s[/tex], which is the average speed of the glider for the time span between [tex]0.628+1.39=2.02s[/tex] and [tex]0.628+1.39+0.431=2.45s[/tex].

Now that we are aware of the velocities at two points, we can calculate the acceleration using the formula [tex][(28.8-19.7)cm/s]/[(2.23-0.314)s]=4.70cm/s2[/tex].

(c) The average velocity over a predetermined period of time is determined using the glider's length rather than the distance between points A and B.

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(17%) Problem 2: The drawing shows a small sphere of mass m=0.26 g that carries a charge of q = 85 x 10-10 C. The sphere is attached to one end of a very thin silk string of length L = 6.25 cm. The other end of the string is attached to a large vertical conducting plate that has a charge density of o = 30 x 10-6C/m². + + + + + + L m, A 25% Part (a) Write an expression for the magnitude of the electric field due to the charge distribution on the conductive plate. E = 0 Grade Summary Deductions 0% Potential 100% €0 B 0 Y b 0 Submissions Attempts remaining: 20 (% per attempt) detailed view d h ( 789 HOME 1456 1 23 + 0 END VO BACKSPACE GEL CLEAR g k j m n P S Submit Hline Feedback I give up! Hints: for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. Date Submission History All Date times are displayed in Eastern Standard Time Red submission date times indicate late work. Time Answer Hints Feedback 24 25% Part (b) Write an expression for the horizontal component of the net force acting on the charged sphere in terms of the tension T in the string, the electric field, and the given variables. A 25% Part (c) Write an expression for the vertical component of the net force acting on the charged sphere in terms of the tension T in the string and the given variables. 425% Part (d) What is the angle in degrees that the string makes with respect to the vertical?

Answers

θ = 39.7º is the angle in degrees that the string makes with respect to the vertical using Newtons law.

In each exercise, we construct the equations at the equilibrium point using Newton's second law for the sphere. We'll assume that plate 1 is on the left for this exercise.

Y Axis

    Y= -W = 0 = W

X axis

       X= - F_{e2} + Tₓ = 0

Let's utilize trigonometry to determine the tension's component parts. We gauge the angle in relation to the vertical

        sin θ = Tₓ / T

        cos θ = T_{y} / t

        Tₓ = T sin θ

        T_{y} = T cos θ

Gauss's law can be used to determine the electric field of each leaf. Since a cylinder forms a Gaussian surface, the component of the field perpendicular to the cylinder's base is the one containing electric flow.

 F = ∫ E. dA

The flow is towards both sides of the plate in this instance, and the scalar product is reduced to the algebraic product.

F = 2E A = q_{int} / ε₀

let's use the concept of surface charge density

       σ = q_{int} / A

we substitute

       2E A = σ A /ε₀

         E = σ / 2ε₀

    T cos θ = mg

         - q σ₁ / 2ε₀  - q σ₂ /2ε₀  + T sinθ = 0

we introduce t in the second equations

         - q /2 ε₀  (σ₁ + σ₂) + (mg / cos θ) sin θ = 0

         mg tan θ = q /2ε₀   (σ₁ + σ₂)

         θ = tan -1 (q / 2ε₀ mg (σ₁ + σ₂)

data indicates the mass of 0.26 g = 0.26 10⁻³ kg

give the charge density on plate 2, suppose ab = 10 10⁻⁶ C / m²

let's calculate

        θ = tan⁻¹ (9.0 10⁻¹⁰ (30 + 10) 10⁻⁶ / (2  (6.25 10⁻¹² *0.26 10⁻³ 9.8))

        θ = tan⁻¹ 8.3 10⁻¹)

        θ = 39.7º

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A child is riding on a merry go round. As the speed of the merry go round is doubled, the magnitude of the centripetal force acting on the childa. Remains the sameb. Is quadrupledc. Is doubledd. Is halved

Answers

A youngster is on a merry-go-round. The centripetal force acting on the toddler is quadrupled as the merry-go-speed round's is doubled. So, option B is correct.

What is centripetal force?

Centripetal force is a term used to describe a force that moves a body along a curved path. The centripetal force is always applied in the general direction of the path's instantaneous center of curvature and against the motion of the subject. According to Isaac Newton, it is "a force by which bodies are dragged or forced, or in any other way gravitate, towards a point as to a center." Gravity is the centripetal force that generates astronomical orbits, according to Newtonian mechanics theory.

As, the formula of Centripetal force,

[tex]F=\frac{mv^2}{r}[/tex],

We can see that, F is directly proportional to [tex]v^{2}[/tex], When the speed of the merry-go-round is doubled, the centripetal force acting on the child is multiplied by four.

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TRUE OR FALSE:  Increasing the time of impact during a collision increases the force experienced by the object. * True False ​

Answers

Answer:

False

Explanation:

I'm pretty sure increasing the time of impact actually decreases the force because it is being spread out.

Answer:

False.

Explanation:

Extending the time results in decreasing the force and thus minimizing the effect of the force in the collision.

An 8.7 hour trip is made at an average speed of 73.0 km/hr. If the first third of the trip (chronologically) was driven at 96.5 km/hr, what was the average speed for the rest of the journey?

Answers

The average speed for rest of the journey = (632.1 - 281.55) / 5.8  km/hr = 88.4 km/hr.

What is average speed?

Average speed is a measure of the rate of change of a certain distance traveled over a period of time. It is usually calculated by dividing the total distance traveled over time, usually in hours, minutes, or seconds. Average speed is a measure of the average rate of motion, not necessarily the actual speed at any given moment.

Let the total distance covered be D. Time taken for first third of the journey = 8.7/3 hrs = 2.9 hrs
Distance covered in first third of the journey = 2.9 * 96.5 km/hr = 281.55 km
Therefore, distance covered in rest of the journey = D - 281.55 km
Time taken for rest of the journey = 8.7 - 2.9 hrs = 5.8 hrs
Average speed for rest of the journey = (D - 281.55) / 5.8  km/hr
Substituting the value of D = 8.7 hrs * 73 km/hr = 632.1 km
Therefore, average speed for rest of the journey = (632.1 - 281.55) / 5.8  km/hr = 88.4 km/hr

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An asteroid is travelling through the solar system at a constant velocity. Which of the following
choices correctly models the forces acting on the asteroid?

Answers

Answer:

The forces acting on an asteroid include gravity from the Sun and other celestial bodies, radiation pressure from the Sun, and the pressure from interplanetary gas and dust. The gravitational forces will act to pull the asteroid towards the Sun, while the radiation pressure and interplanetary gas and dust will act to push it away. The net force acting on the asteroid will determine its path and velocity through the solar system.

Explanation:

Describe protons.
Location:
Charge:
Mass:

Answers

The protons location is nucleus of an atom, the Mass is 1 amu and the charge is positive.

What is protons?

Protons are subatomic particles with a positive electrical charge. They are found in the nucleus of atoms and are responsible for most of the atom’s mass. Protons are one of the three main subatomic particles, along with neutrons and electrons.

Location: Proton is located in the nucleus of an atom. The nucleus is the small, dense, positively charged center of an atom. The protons, along with the neutrons, make up the nucleus of the atom.

Mass: The mass of a proton is approximately 1.007276467 u (unified atomic mass units). It is slightly heavier than a neutron, which has a mass of approximately 1 u.

Charge: A proton has a positive charge of +1 elementary charge (e). This charge is what gives the proton its repelling force to other positively charged particles and its attractive force to negatively charged particles.

Hence, a proton is a positively charged subatomic particle with a mass of 1 amu, located in the nucleus of an atom.

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Answer:

Location:

✔ nucleus

Charge:

✔ positive

Mass:

✔ one amu

Explanation:

A particle moves in a straight line such that its displacement, x meters, from a fixed point 0 on the line at time t seconds is given by x = (t — 1)^3 -2t^2 +1 .
(a) Find the time when the particle is instantaneously at rest.
(b) Find the displacement of the particle from O when t=6 s.
(c) Find the total distance travelled during the first 6 seconds of its motion.

Answers

(a) The particle is instantaneously at rest at time, t = 3/2 seconds.

(b)  The displacement of the particle is 54 meters from the fixed point O at t = 6 seconds.

(c) The total distance travelled by the particle during the first 6 seconds of its motion is 52 meters.

What is the time when the particle is instantaneously at rest?

To find the time when the particle is instantaneously at rest, we need to find the time when its velocity is zero. The velocity of the particle can be found by taking the derivative of its displacement with respect to time, which gives us the velocity function, v(t) = d(x)/dt.

Taking the derivative of x = (t — 1)^3 -2t^2 +1 with respect to time t, we get:

v(t) = 3(t - 1)^2 - 4t

To find when the velocity is zero, we set v(t) = 0 and solve for t:

0 = 3(t - 1)^2 - 4t

3(t - 1)^2 = 4t

t = (3(t - 1)^2)/4

t = (3(t - 1)^2)/4

Solving this equation, we find t = 3/2 seconds. So, the particle is instantaneously at rest at t = 3/2 seconds.

To find the displacement of the particle from O when t=6 s, we simply substitute t = 6 into the displacement function:

x = (6 - 1)^3 - 2 * 6^2 + 1

x = 125 - 72 + 1

x = 54 meters

To find the total distance travelled during the first 6 seconds of its motion, we need to find the definite integral of the velocity function over the interval [0, 6].

x(t) = ∫v(t) dt

x(t) = ∫(3(t - 1)^2 - 4t) dt

x(t) = (t - 1)^3 - 2t^2 + C

where C is the constant of integration. We can determine the value of C by using the initial condition that x(0) = 0:

0 = 0 - 2 * 0^2 + C

C = 0

So, x(t) = (t - 1)^3 - 2t^2.

Finally, to find the total distance travelled during the first 6 seconds of its motion, we evaluate the definite integral of x(t) from 0 to 6:

d = x(6) - x(0)

d = [(6 - 1)^3 - 2 * 6^2] - [(0 - 1)^3 - 2 * 0^2]

d = 125 - 72 - 1

d = 52 meters

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A moving object has
kinetic energy
velocity.
speed.
all of these

Answers

It has all of these. everything has kinetic energy, it is moving so it will have both speed and velocity as well.

A car moving with an initial velocity of 25 m/s north has a constant acceleration of 5.5 m/s2 south. After 10 seconds its velocity will be

Answers

Answer:

80 m/s

Explanation:

v = v₀ + at

v = 25 m/s + (5.5 m/s²)(10 s) = 80 m/s

The diagram below shows three cubes of the same material and density. If the cubes all start out at 80°C, which cube will cool the most slowly? ​

Answers

Answer:

the cube that will slowly cool is 2

The cube 2 will cool the most slowly.

What is meant by cooling ?

The removal of heat from a system is known as cooling, and it usually leads to a decrease in temperature or a change in phase.

Here,

Three cubes of same material and density are given in the diagram. They all are said to be cooling starting from 80°C.

The three cubes have different volumes.

We know that, as the volume of the cube increases, the surface area of the cube decreases accordingly. That means, the volume of a cube is inversely proportional to its surface area.

V ∝ 1/A

According to the principle of cooling, the rate of cooling is directly proportional to the surface area. That means, the rate of cooling is higher for objects with higher surface area and slower for those with lower surface area.

So, the cube 2 is having the lowest volume among the three cubes and thus the highest surface area.

Therefore, it will take more time to cool down.

Hence,

The cube 2 will cool the most slowly.

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Lab: Newton's Laws of Motion

Answers

Newton's law of motion

Three newton's law of motion:-

1. An object will not change its motion unless a force acts on it.

2. The force of an object is equal to its mass time its acceleration.

3. When two objects interact , they apply forces to each other of equal magnitude and opposite direction.

Newton's law of motion are three basic laws of classical mechanics that describes the relationship between the motion of an object and the forces acting on it.

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Which of these is an example of acceleration?

Answers

Answer:

a bus triveling north at 25m/s

Without having the help of the moving pad, you and a friend have to move the very heavy
entertainment center. The kinetic friction opposing the motion is equal to 1600 N and your
maximum applied force is 1000N. How much force does your friend need to apply to make the
entertainment center move at a constant velocity?

Answers

The force needed by my friend to make the entertainment center move at a constant velocity is 600 N

How to find force application?

To find the force application in a specific situation, one needs to consider the forces that are acting on an object and the net force (the vector sum of all forces acting on an object) which determines the motion of the object.

In order to make the entertainment center move at a constant velocity, the sum of the applied forces must equal the force of kinetic friction. If the maximum applied force you can provide is 1000 N, then your friend needs to apply a force of 1600 N - 1000 N = 600 N.

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When a local house was on fire, the firefighters were able to save most of it by dousing the house with water. What will happen when forensic scientists investigate this fire?.

Answers

Forensic scientists will investigate the fire by looking for clues as to what caused it and how it spread. They will collect evidence such as burn patterns and debris, and analyze the scene to determine the origin of the fire.

What is debris?

Debris is any loose material (solid or liquid) that is scattered or discarded, such as the remains of a wrecked or destroyed structure or object. Common examples of debris include rubble, broken glass, fallen tree branches, discarded plastic, scrap metal, and other discarded materials. Debris can also include materials that are the by-product of a process, such as the dust created by grinding or sawing. Debris can also be the result of natural disasters or human activities. Debris can be found in any environment and can cause environmental or safety hazards if left unchecked.

Therefore, Forensic scientists will investigate the fire by looking for clues as to what caused it and how it spread. They will collect evidence such as burn patterns and debris, and analyze the scene to determine the origin of the fire.

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1. A car moves at 10m/s

a. Net Force on the car is zero
b. Force of friction is equal to the forward force applied by the engine
c. Both a and b are correct
d. a is correct but b is wrong

Answers

Answer:

d. a is correct but b is wrong.

Explanation:

A car that is moving at a constant speed of 10m/s is experiencing a net force of zero, meaning that the sum of all forces acting on the car is equal to zero. This means that the forward force applied by the engine is equal in magnitude but opposite in direction to the force of friction acting on the car.

The force of friction acts to slow down the car, but it does not equal the forward force applied by the engine. Instead, it is determined by factors such as the weight of the car, the road surface, and the tire traction. If the forward force applied by the engine is greater than the force of friction, the car will accelerate. Conversely, if the force of friction is greater than the forward force applied by the engine, the car will decelerate.

If two bowling balls were to collide head on stick to one another, with some loss in kinetic energy, the collision would be considered a(n) ___________ collision.*
A. Cushy
B.Perfectly Inelastic
C.Reversable
D.Elastic​

Answers

Answer: D

Explanation:An inelastic collision is one in which objects stick together after impact, and kinetic energy is not conserved. This lack of conservation means that the forces between colliding objects may convert kinetic energy to other forms of energy, such as potential energy or thermal energy.

ASAP I WILL GIVE BRAINLEST!!

A 3.0 kg object swings back and forth as a simple pendulum with a small amplitude. The potential energy U of the object as a function of distance x from its equilibrium position is shown above. This particular object has a total energy E of 0.4 J.

b) What is the farthest the object moves along the x-axis in the positive direction? Explain your reasoning.
c) Determine the object’s kinetic energy when its displacement is -8 cm.
d) What is the object’s speed at x = 0?

Answers

10cm is the farthest the object moves along the x-axis in the positive direction .0.15J is the object’s kinetic energy when its displacement is -8 cm. 0.316m/s is the object’s speed at x = 0.

Define kinetic energy.

Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.

Given,

Total energy is 0.4J

m is 3kg

The farthest the object moves along the x-axis in the positive direction would be as potential energy is 0.4J. So from given diagram, displacement will be 10cm

If displacement is -8cm , P.E from diagram will be 0.25J

According to energy conservation formula ,

ME ⇒ U+KE

KE ⇒ ME-U ⇒ 0.4-0.25 ⇒ 0.15J

At x ⇒ 0,

KE ⇒ 1/2 mv^2

0.15 ⇒ 0.5*3*v^2

v ⇒ 0.316m/s

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what is the difference in mechanical energy from point A to point C below?

Answers

Answer:

their speed maybe cause of the ups and downs

Learning Goal:
To understand the role of the internal resistance of various devices and the use of the ammeter and the voltmeter.
Consider the circuit shown.(Figure 1) All wires are considered ideal; that is, they have zero resistance. We will assume for now that all other elements of the circuit are ideal, too: The value of resistance R is a constant, the internal resistances of the battery (r) and the ammeter (RA) are zero, and the internal resistance of the voltmeter (RV) is infinitely large.

Answers

The internal resistance of devices like batteries, ammeters, and voltmeters can affect the overall current and voltage in a circuit.

To accurately measure these values, it's important to take into account the internal resistance of these devices and to use them correctly in the circuit. It's important to note that the internal resistance of devices can affect the overall performance of a circuit.

For example, the internal resistance of a battery can affect the voltage available to the circuit and the internal resistance of a speaker can affect its efficiency. Therefore, it's important to take into account the internal resistance of devices when designing and analyzing circuits.

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Blackbody Temperature 5800 K B GR Graph Values Labels Intensity 100 Sirius A o Spectral Power Density (MW/m/um) Sun Light Bulb 0 Earth Wavelength (m) 1 n = 1000 mm This simulation shows the amount of power opaque objects at different temperatures will emit at different electromagnetic wavelengths. Such spectra are known as blackbody spectra and it is the feature of the light emitted by any object due to its temperature. Stars, famously, produce blackbody spectra that affect the colors that they appear. The simulation starts with simulating the Sun's spectrum. Explore the simulation and search through the different options to determine the wavelength of light in micrometers where the Sun's blackbody spectrum peaks: micrometers Express this value in nanometers: nanometers What kind of electromagnetic radiation is this? infrared visible ultraviolet What is the solar intensity (the amount of power per unit area emitted by the Sun 10

Answers

The wavelength of light in micrometers where the Sun's blackbody spectrum peaks is approximately 0.5 micrometers or 500 nanometers.

The simulation provided allows the user to explore blackbody spectra emitted by opaque objects at different temperatures. Such spectra are the characteristic feature of light emitted by any object due to its temperature. The simulation begins by showing the blackbody spectrum of the Sun. By exploring the different options, the user can determine the wavelength of light in micrometers where the Sun's blackbody spectrum peaks, which turns out to be around 0.5 micrometers or 500 nanometers. This is within the visible spectrum of electromagnetic radiation, which is why we can see the Sun as a yellowish-white color. Additionally, the simulation provides information about solar intensity, which is the amount of power per unit area emitted by the Sun.

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To pick up a few staples from the table, a student wrapped copper wire around a nail and connected it to a battery. She was able use this device to pick up all staples. How was this possible?
A. The current moving through the wire made the nail into an electromagnet.
B. The staples are responding to the wire because it was made of copper.
C. The electricity from the wire was arcing to the staples.
D. The protons in the staples and are attracted to the electrons in the wire.

Answers

Answer:

The correct answer is A. The current moving through the wire made the nail into an electromagnet.

An electromagnet is created when a current is passed through a wire. The flow of electrons creates a magnetic field, which can attract or repel other magnetic objects. In this case, when the student wrapped the copper wire around the nail and connected it to a battery, the flow of electrons created a magnetic field around the nail. This magnetic field allowed the student to pick up the staples because they were attracted to the nail, which was now acting as an electromagnet.

A proton moving along the lines of force of a uniform electric
field, the intensity of which is 10 kV/m, increased its speed from 106 m/s
up to 1.1∙ 106 m/s. Find: 1) potential difference between points, 2)
acceleration of a proton, 3) path of a proton during acceleration, 4) work
electric field. The charge of a proton is 1.6 ∙ 10−19 K; the mass of a proton
1.67 ∙ 10−27 kg.

Answers

1) The potential difference between points is 100 V. 2) The acceleration of the proton is 10 kV/m. 3) The path of the proton during acceleration is a straight line in the direction of the electric field. 4) The work done by the electric field is 1.6E-19 * 100 = 1.6E-17 J.

The cart is given an initial push up the ramp. After this push, as the car moves up the ramp, the direction of the acceleration of the cart is_________the ramp. After ther turns around, and begins moving down the ramp, the direction of the acceleration of the cart is__________ eaches its highest point, the ramp. At the highest point the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is_________O down, down, zeroO up, down, nonzeroO down, down, nonzeroO up, down, zero

Answers

The correct answers to the blanks are 1. UP ,2. UP and 3. ZERO

When the cart is initially given a push up the ramp, the direction of the acceleration of the cart is up the ramp. This is because the net force acting on the cart is directed up the ramp, in the same direction as the component of the gravitational force that is parallel to the ramp. As a result, the cart accelerates up the ramp in the same direction as the net force.

When the cart turns around and begins moving down the ramp, the direction of the acceleration of the cart is still up the ramp. This is because the component of the gravitational force that is parallel to the ramp is still directed down the ramp, but the net force acting on the cart is directed up the ramp due to the normal force exerted by the ramp on the cart. As a result, the cart accelerates down the ramp in the opposite direction to the net force, which is up the ramp.

            At the highest point that the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is zero. This is because at this point, the cart is at the highest point on the ramp and has stopped moving. As a result, the velocity of the cart is zero, and therefore the acceleration of the cart is also zero.

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A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west..  After they collide, the two interlock and move together.  What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)*
A. 11.25 m/s west
B. 11.25 m/s east
C. 32.6 m/s east
D. 32.6 m/s west​

Answers

The final velocity of the truck after collision, given that the car and the truck interlock and move together is 11.25 m/s west (Option A)

How do I determine the final velocity of the truck?

The final velocity of the truck after the collision can be obtained as illustrated below:

Mass of car (m₁) = 1500 KgInitial velocity of car (u₁) = 20 m/sMass of truck (m₂) = 2500 KgInitial velocity of truck (u₂) = 11 m/sEast = Positvie directionWest = Negative directionFinal velocity (v) = ?

Momentum before = momentum after

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(1500 × 20) - (2500 × 30) = v(1500 + 2500)

30000 - 75000 = v × 4000

-45000 = v × 4000

Divide both sides by 4000

v = -45000 / 4000

v = -11.25 m/s

Recall => West is negative

v = 11.25 m/s west

Thus, the final velocity is 11.25 m/s west (Option A)

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