Answer the questions for 100 Points!

To solve this we must be knowing each and every concept related to environment. Therefore, the correct option is option B among all the given options.

An environment may be simply defined as a system that includes all abiotic and biotic components that have an impact on human life. All flora and animals are considered biotic, or living, elements, whereas water, sunshine, air, temperature, etc. are considered abiotic.

Any good, service, or feature that benefits people and society might be considered one of an environment's resources. They might be anything that fulfills a person's requirements on a daily basis. Amount of oxygen in the water is a biotic factor of an aquarium environment.

Therefore, the correct option is option B.

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Answer: B: Water Temperature

Explanation: k12 test 1.04 Science Life semester 2

Answer: 22.6g H2

Explanation:

You need to set up dimensional analysis starting with 11.2moles of H2O (the same as HOH).

First, you need to balance the equation. When balanced, it is:

2H2(g) + O2(g) --> 2H2O(g)

Starting with moles of H2O, you need to go from moles of H2O to moles of H2. To do so, you need to use the mole ratio that you can figure out from the balanced equation. In this case it will be 2mol H2/2mol H2O.

Then just convert to grams using the molar mass of H2 which is 2.016grams.

11.2 mol H2O x (2 mol H2 / 2 mol H2O) x (2.016g H2 / 1 mol H2) = 22.6g H2

When that equation is set up, all units except for grams of H2 will cancel and you'll be able to multiply across.

The energy diagram of the given reaction shows that, the activation energy of the reactants is less than that of the products. The transition state is having the highest activation energy.

An endothermic reaction is the reaction in which the reactants will absorb heat energy from the surroundings. The reactants will gain sufficient energy to overcome the barrier potential of the reaction and thereby they have less activation energy.

The given reaction of the decomposition  of hydrogen iodide is an endothermic reaction. Hence, HI has the least activation energy and the products hydrogen gas and iodine gas have the higher activation potential as shown in the diagram.

The activation energy of the transition state is indicated with the central arrow,

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The thermochemical equation of the reaction is CO (g) + 3H₂ (g) ⇒ CH₄ + H₂O. 48 KJ heat will be released during this reaction if 67.2 liters of methane.

A balanced stoichiometric chemical equation that includes the enthalpy change i.e, ΔH is called as thermochemical equation.

At STP,

1 mole of any gas occupies a volume of 22.4 L.

The volume of 67.2 L corresponds to  67.2 / 22.

= 3  moles.

1 mole of CO₂ obtained from 1 mole of methane.

3 moles of CH₄ will be obtained from 3 moles of CO₂.

The molar mass of methane = 16 g/mol.

Then, the mass of 3 moles of methane = 3 × 16

= 48 KJ

Thus,The thermochemical equation of the reaction is CO (g) + 3H₂ (g) ⇒ CH₄ + H₂O. 48 KJ heat will be released during this reaction if 67.2 liters of methane.

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Answer:

similar as they both have valency of 1

different as sodium is metal while chlorine is non metal

The density of the the wire is given 8.92 g/cm³. The mass is 0.200 cm. Thus, length of the copper wire will be 55.7 cm.

Density of a substance is the measure of its mass per unit volume. It describes how closely its particles are packed within a given volume. It is the ratio of mass to the volume.

Volume of an object is the space occupied by the object. For a rectangle block, volume is the product of length, width and height.

volume of wire  = πr²l

diameter = 0.200 cm

radius = 0.1 cm

volume =  3.14 × (0.1)² l = 0.0314 l

where l is the length of the wire.

Mass of the wire = 15.62 g

density = mass/ volume

d = 15.62 g/ 0.0314 l cm³

  =  8.92 g/cm³

Then, l = 55.7 cm.

Therefore, the length of the copper wire  is 55.7 cm.

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Answer: Sodium and Chlorine

Explanation: I think it's right

Below is a list of the temperature change solution.

The source of the temperature change is

Initial Temperature - Final Temperature

Temperature measurements

It is a gauge for determining how hot or chilly a body is.

To quantify temperature variations,

The water and iron's beginning and final temperatures are noted.

To Iron

Iron that has been heated up is submerged in water.

Water is at a lower temperature, so both of the temperatures will change.

These information is saved.

Final temperature minus initial temperature equals temperature change.

a) The difference in temperature for metal is 200 - 100 = 100 0C

Water temperature change = 22.5

Change in temperature for both = 23.3

b) 0.7 for water

Metal 76.6 for iron

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Complete Question -

Put the Metal in the Water and Measure

Temperature Changes (Lead)

Measure the initial temperature of the water to the

nearest 0.1°C. Record in the data table.

Initial temperature of metal =

Initial temperature of water

Final temperature of both = [

27

DONE

26

25

24

23

Intro

Continue

AL

250 ml

=பா-©

200

150

100

1

27

O

°C

°C

The normality of the acid solution is 0.53N.

The process by which an acid and a base neutralize one another. As a result of their reaction, an acid and a base produce heat as well as salt and water.

To calculate the normality of the acid solution, you need to know the number of moles of acid used in the neutralization reaction. Since the volume of the acid solution is given in cm³ and the molarity (normality) is in moles per liter, you will first need to convert the volume to liters.

1 cm³ = 0.001 liters

So, 50 cm³ = 0.05 liters

To find the number of moles of acid used, divide the volume in liters by the molarity:

moles acid = volume acid/molarity acid

Next, you can use the balanced equation for the neutralization reaction between KOH and the acid to find the number of moles of KOH that reacted.

1 mole KOH = 1 mole H+

The number of moles of KOH is 1.4/56.11

moles acid = volume acid / molarity acid = 0.05 / (1.4/56.11)

molarity acid = 0.05 / (1.4/56.11) = 0.53 n.

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Answer: 0.0023mol

Explanation:

Molar Mass of Water is 18.01g/mol

0.041g H2O*(mol/18.01g) = 0.0023mol

An unsaturated hydrocarbon propene undergoes Markovnikov's rule to give (A) 2- bromo, propane is formed. 2- bromo, propane is hydrolyzed with aqueous alkali to yield (B) propane is produced.

Markovnikov's rule states that when an asymmetrical substance is added to an asymmetrical alkene, then the negative part of the reagent will attach to the carbon atom containing less number of hydrogen atoms.

An unsaturated hydrocarbon propene undergoes Markovnikov's rule to give (A) 2- bromo, propane is formed. 2- bromo, propane is hydrolyzed with aqueous alkali to yield (B) propane is produced. When propane is treated with PBr3, compound (C) 1, bromo- propane is produced. 1, bromo- propane reacts with AgCN (alc.) to give another compound (D) 1 cyano propane. The compound (D) if reduced with LiAlH4, produce (E) propane.

When E react with nitrous acid nitro propane is formed.

Thus, 2- bromo, propane is hydrolyzed with aqueous alkali to yield (B) propane is produced.

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Answer:

Explanation: Tungsten carbide is formed by the reaction of tungsten (W) and carbon (C) to form tungsten carbide (WC). The balanced equation for the reaction is W + C → WC.

We know that the number of moles of a substance can be calculated using the formula:

moles = mass / molar mass

We also know that the law of conservation of mass states that the total mass of the reactants must equal the total mass of the products. We can use this principle to balance chemical equations.

In this case, we have 1.25 moles of carbon and an unknown number of moles of tungsten. We know that for every 1 mole of carbon, we need 1 mole of tungsten to produce 1 mole of tungsten carbide.

To determine the number of moles of tungsten carbide produced, we can set up the following proportion:

1.25 moles C / 1 mole C = x moles W / 1 mole W

Where x is the number of moles of tungsten needed.

Solving for x, we get x = 1.25 moles W

So, 1.25 moles of tungsten reacts with 1.25 moles of carbon to produce 1.25 moles of tungsten carbide.

To find the mass of Nitrogen (N) in 0.464 grams of N2H4 (hydrazine), we need to use the molar mass of N2H4 and the proportion of Nitrogen in the compound.

First, the molar mass of N2H4 is (14.01 + 2(14.01) + 4(1.01)) = 32.05 g/mol.

Next, we know that the proportion of Nitrogen in N2H4 is 2 moles of Nitrogen to 1 mole of N2H4, or 2/1.

So, to find the mass of Nitrogen in 0.464 grams of N2H4, we can use the following formula:

Mass of Nitrogen = (mass of N2H4) x (proportion of Nitrogen) / (molar mass of N2H4)

Plugging in the values:

Mass of Nitrogen = (0.464 g) x (2/1) / (32.05 g/mol)

Mass of Nitrogen = 0.028 grams

Therefore, the mass of Nitrogen in 0.464 grams of N2H4 is 0.028 grams.

C₂H₅OC₂H₅ (Diethyl ether) has the highest viscosity at same temperature.

The order of viscosity possessed by the different fluids at same temperature is given below.

C₂H₅OC₂H₅ (Diethyl ether)

H₂NCH₂CH₂NH₂ (Ethylene diamine)

CH₃CH₂Cl (Chloroethane)

CH₃CH₂CH₂NH₂ (propan-1-amine)

All the above molecules form hydrogen bonding. As, the viscosity could be directly related to hydrogen bonding tendency, ethylene diamine will be more viscous at a given temperature, as it could form hydrogen bonding through two NH₂ groups.

Viscosity is defined as the resistance of a fluid (liquid or gas) to a change in shape, or movement of neighboring portions relative to one another. Viscosity represents opposition to flow. The reciprocal of the viscosity is defined as the fluidity, a measure of the ease of flow.

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Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is a. 40 mM.

Using this formula to find the  final concentration of fructose

Final concentration of fructose  =Equilibrium from glucose/ Equilibrium constant

Where:

Equilibrium constant = 1.0

Equilibrium from glucose = 40 mM

Let plug in the formula

Final concentration of fructose  = 40mM / 1.0

Final concentration of fructose  =  40mM

Therefore we can conclude that the correct option is A.

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The complete question is:

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is

a. 40 mM

b. 20 mM

c. 10 mM

d. 0 mM​

According to the law of reciprocal proportions, they should combine in the ratio of 10.24:7.92:1.29 by mass.

According to the law of reciprocal proportions when two elements join to form more than one compound, the weights of one element that combine with a fixed weight of the another are in a ratio of small whole numbers.

In phosphine, phosphorus = 91.1 parts and hydrogen = 8.9 parts

So, 8.9 pads of hydrogen combine with phosphorus = 91.1 parts .

1 part of hydrogen combine =  91.1 / 8.9

= 10.24 parts

Similarly,

for water 88.8 / 11.2

= 7.92 parts of hydrogen

For Phosphorus tetra oxide

= 56.4 / 43.6

= 1.29 parts

Thus, According to the law of reciprocal proportions, they should combine in the ratio of 10.24:7.92:1.29 by mass.

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The number of mole in 68 grams of sulphur dioxide, SO₂ is 1.06 mole

The number of mole of a substance is defined by the following formula:

Mole = mass / molar mass

Using the above fromula, we can obtain the number of mole in 68 grams of sulphur dioxide, SO₂. This is shown below:

Mole = mass / molar mass

Number of mole of SO₂ = 68 / 64

Number of mole of SO₂ = 1.06 mole

Thus, we can conclude that the number of mole is 1.06 mole

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Answer:

hi

Explanation:

When burning magnesium is lowered in a gas jar full of carbon dioxide, the burning process continues because the carbon dioxide acts as an oxidizing agent.

A combustion reaction is a type of chemical reaction that occurs when a fuel, such as a hydrocarbon, reacts with an oxidizing agent, such as oxygen, to produce heat and light in the form of a flame. The basic equation for a combustion reaction is:

Fuel + Oxidant → Heat + Light + Products

In the case of burning magnesium, the fuel is magnesium and the oxidant is carbon dioxide. The products of the reaction are magnesium oxide and carbon dioxide. Combustion reactions are exothermic, meaning they release energy in the form of heat.

This means that the carbon dioxide provides the oxygen necessary for the combustion reaction to continue, allowing the magnesium to continue burning. Additionally, the carbon dioxide also helps to extinguish the flame by removing the heat and the oxygen from the combustion zone.

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Answer:

Explanation:

Since 1 gram of radium decays to 1/2 gram in 1622 years that means the half-life of radium is 1622 years.

So,  6 grams also decay to 3 grams in 1622years

Answer:

The number and variety of plants would increase.

Explanation:

A is incorrect because if deer eat plants and the population of deer are increased there wouldn't be an increase of plants. There would be a decrease of plants be ause there would be more deer eating plants. B is incorrect because if there are more deer, then the amount of plants will also decrease. C is correct because with a surplus of deer, the amount of plants would decrease because of all the deer. Therefore, the variety of plants would decrease because they are being eaten. D is incorrect because if there is a population growth of deer, that means more deer are eating the plants. So, the plant population would decrease.

Hope this helps! :)

In a forest, deer eat plants for survival.The number and variety of plants would increase in the deer population to affect the plant life of an ecosystem. Therefore, option A is correct.

An ecosystem is a geographical area in which plants, animals, and other organisms, as well as weather and landscape, coexist to form a life bubble. Ecosystems contain both biotic (living) and abiotic (nonliving) components.

An ecosystem is a group of living organisms (plants, animals, and microbes) in a specific location. The term 'eco' refers to a region of the world, and the term'system' refers to the organizing units.

Because deer eat a wide variety of plants, the plant population would suffer as a result. More deer necessitates more food. Plant predation by deer populations would reduce the population of other animals that eat plants and plant seeds.

Thus, option A is correct.

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Answer:

Explanation:

Atoms of sodium and chlorine are both elements, meaning they are made up of only one type of atom. Both have an atomic number of 11, which means they have 11 protons in their nucleus, but the number of neutrons and electrons differ. Sodium has 12 neutrons and 11 electrons, while chlorine has 17 neutrons and 17 electrons.

Atoms of sodium and chlorine are also both reactive, meaning they form chemical bonds with other elements. However, sodium is more reactive than chlorine, which is why it often forms compounds with other elements, such as sodium chloride (NaCl).

Atoms of sodium and chlorine are also similar in that they both have the same number of electrons in their outer shells. This means they can both form two covalent bonds with other elements. However, because the number of electrons and neutrons in each atom is different, the strength of the bonds they form will differ.

Overall, atoms of sodium and chlorine are similar in that they both have 11 protons and can form two covalent bonds, but they differ in their number of neutrons and electrons, which affects the strength of the bonds they form and their reactivity.

The empirical formula of the compound with 14.3% Nitrogen, 4.1% Hydrogen, and 81.6% Bromine would be [tex]NH_4Br[/tex].

The compound contains 3 atoms of different elements according to the following percentage:

Let's find the mole equivalent of each percentage:

Divide by the smallest mole:

Thus, the empirical formula of the compound is [tex]NH_4Br[/tex].

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Answer: Potassium bromide, KBr

Explanation:

Potassium gives a lilac flame in flame test and Bromide ions produce a cream precipitate when they react with Silver ions to form Silver bromide

The compound is non polar covalent in  its structure as said above.

Let us recall that the melting point has to do with the temperature at which there is the conversion of the solid to a liquid. We know that the melting point of the compound would depend on the structure of the compound.

If the compound would have a melting point that is about  20°C, the implication is that the compound is not be held by very strong intermolecular forces hence it must be covalent.

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We will utilise the water belongings tables from every state. Tables A-three, A-2, and A-five are used.

outline temperature ?

Temperature is a bodily amount that expresses quantitatively the

of hotness and coldness.

Part a

T = 179.nine and P = 10 br

Tables display that the T saturated is in addition 179.nine; hence, H20 exists as a two-segment liquid-vapor combination. Tsat-P = Tsat-P

See attachment 1 for similarly statistics on p-v and T-v.

Part b

T = one hundred fifty and P = 10 br

Tables display that the saturated T is 179.nine, implying that H20 exists withinside the sub-cooled liquid area. T. Tsat-P

Attachment 2 carries statistics on p-v and T-v.

Part c

P = 0.five br and T = one hundred ranges Celsius

According to temperature tables, the P saturated is 1.014 bar; hence, H20 exists withinside the super-heated area. Psat-T. Table A-2

Attachment three carries statistics on p-v and T-v.

Part d

P = 50 br and T = 20 ranges Celsius

According to temperature tables, the P saturated is 0.02339 bar; hence, H20 exists withinside the sub-cooled liquid area. Psat-T > Psat. A-2, Table

Attachment four carries statistics on p-v and T-v.

Part e

T = -6 C and P = 1 bar

According to temperature tables, the P saturated is 0.003689 br; hence, the H20 P > Psat-T strong due to the fact T is much less than the triple factor temperature. A5 Table

See

five for similarly statistics on p-v and T-v.

We will utilise the water property tables from each state. Tables A-3, A-2, and A-5 are used.

define temperature ?

Temperature is a physical quantity that expresses quantitatively the perceptions of hotness and coldness.

Part a

T = 179.9 and P = 10 br

Tables show that the T saturated is similarly 179.9; hence, H20 exists as a two-phase liquid-vapor combination. Tsat-P = Tsat-P

See attachment 1 for further information on p-v and T-v.

Part b

T = 150 and P = 10 br

Tables show that the saturated T is 179.9, implying that H20 exists in the sub-cooled liquid area. T. Tsat-P

Attachment 2 contains information on p-v and T-v.

Part c

P = 0.5 br and T = 100 degrees Celsius

According to temperature tables, the P saturated is 1.014 bar; hence, H20 exists in the super-heated area. Psat-T. Table A-2

Attachment 3 contains information on p-v and T-v.

Part d

P = 50 br and T = 20 degrees Celsius

According to temperature tables, the P saturated is 0.02339 bar; hence, H20 exists in the sub-cooled liquid area. Psat-T > Psat. A-2, Table

Attachment 4 contains information on p-v and T-v.

Part e

T = -6 C and P = 1 bar

According to temperature tables, the P saturated is 0.003689 br; hence, the H20 P > Psat-T solid because T is less than the triple point temperature. A5 Table

See  5 for further information on p-v and T-v.

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(2,0), This point is on the new line because it can be represented by the equation y=2x, which is the equation of the new line.

An equation is a mathematical statement that expresses the equality of two expressions. It establishes a relationship between the two expressions and shows that they are the same. An equation can contain any number of variables, ranging from zero to infinity. It can be used to solve problems involving unknown values, using a set of algebraic operations such as addition, subtraction, multiplication, division, and exponentiation. Equations can also be used to represent relationships between physical quantities, allowing us to understand how one quantity changes in relation to another. Equations are used in many fields, from engineering and science to economics and finance.

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Beaker 1 would have a temperature of 22 degrees Celsius and a volume of 50 mL.

Temperature is a physical property of matter that quantitatively expresses hot and cold. It is measured in Kelvin, Celsius, or Fahrenheit. Temperature is important in many physical, chemical, and biological processes. In thermodynamics, temperature is a measure of the average kinetic energy of the microscopic particles that make up a substance. It is related to the average energy of microscopic random motion of the particles that make up a substance. Increasing the temperature of a substance increases its average kinetic energy and vice versa. Temperature is a measure of the intensity of heat, and it is used to compare the relative hotness or coldness of an object. Temperature can also be used to measure the amount of energy being transferred between two objects or systems.

Beaker 2 would have a temperature of 20 degrees Celsius and a volume of 50 mL.

Beaker 3 would have a temperature of 15 degrees Celsius and a volume of 50 mL.

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Answer:

the evidence statement contains reasoning.

Explanation:

the reason that this piece of information is reasoning rather than evidence is because it doesn't tell us the temperatures of the other substances (if any.) if we look at this substance and it has the most constant temperature compared to the others, how will we know if it is the most constant if we don't know the other substances' data?

this is reasoning because the evidence should tell us more about the substance and the others.

Answer: 32g of oxygen and 4g of hydrogen were reacted in total.

Explanation:

To find out how many grams of reactants were reacted, we need to use the balanced equation of the reaction. The equation for the reaction between hydrogen and oxygen to produce hydrogen peroxide is:

2H2 + O2 --> 2H2O2

From the equation, we know that the reaction involves 2 moles of hydrogen and 1 mole of oxygen. We can use the balanced equation to determine the stoichiometry of the reaction, which tells us the relative number of moles of each reactant and product.

We know that 32g of oxygen was reacted, and since 1 mole of oxygen is equal to 16g, we can calculate the number of moles of oxygen by:

32g / 16g = 2 moles

We know that 2 moles of hydrogen are required for every mole of oxygen. so the number of moles of hydrogen is also 2 moles.

We know that 1 mole of hydrogen is equal to 2g, so we can calculate the number of grams of hydrogen by:

2 moles x 2g = 4g

Therefore, 32g of oxygen and 4g of hydrogen were reacted in total.