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Answer:

e

Explanation:

Answer:

the  ratio of r₂/r₁ is 1.37.

Explanation:

Given;

magnitude of electric field strength at a distance r₁, E₁ = 300 N/C

magnitude of electric field strength at a distance r₂, E₂ = 160 N/C

Electric field strength is given as;

[tex]E = \frac{kQ}{r^2} \\\\E_1r_1^2 = E_2r_2 ^2\\\\\frac{E_1}{E_2} = \frac{r_2^2}{r_1^2} \\\\\frac{E_1}{E_2} =( \frac{r_2}{r_1})^2\\\\\sqrt{\frac{E_1}{E_2} } = \frac{r_2}{r_1}\\\\\frac{r_2}{r_1} = \sqrt{\frac{300}{160} }\\\\\frac{r_2}{r_1} =1.37[/tex]

Therefore, the  ratio of r₂/r₁ is 1.37.

Answer:

a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s  d. +1

Explanation:

a. ym

Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm

b. k

We know k = wave number = 2π/λ where λ = wavelength.

Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.

So, λ = v/f = √(T/μ)/f

substituting the values of the variables into the equation, we have

λ = √(T/μ)/f

= √(19.6 N/0.512 kg/m)/76.9 Hz

= √(38.28 Nkg/m)/76.9 Hz

= 6.187 m/s ÷ 76.9 Hz

= 0.081 m

= 81 mm

So, k = 2π/λ

= 2π/0.081 m

= 77.6 rad/m

c. ω

ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz

So, ω = 2πf

= 2π × 76.9 Hz

= 483.18 rad/s

d. The correct choice of sign in front of ω?

Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.

The common characteristics  of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.

Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.

The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.

Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.

To find more on saturn, refer here:

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Answer: The difficulty comes in the modulation, and in the fact that X-rays can't be transmitted via wires or fiber.

Explanation: Mark me as brainlisti

Answer:

The sign of the velocity depends on the coordinate system chosen to define the position. A positive velocity simply means that the object is moving in the positive direction, as defined by the coordinate system, while a negative velocity means the object is traveling in the other direction.

- Hope this helps!

Answer:

98

Explanation:

Answer:

friction, air resistance

Explanation:

Answer:

The work done will be [tex]W=55.27\: J[/tex]

Explanation:

The work equation is given by:

[tex]W=F\cdot x[/tex]

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

[tex]F_{x-direction}=mgsin(28)[/tex]

Therefore, the work done will be:

[tex]W=mgsin(28)*3[/tex]

[tex]W=4*9.81*sin(28)*3[/tex]

[tex]W=55.27\: J[/tex]

I hope it helps you!

Answer:

It begins to increase

Explanation:

As the surfaces move slowly and then increase their relative speeds, the coefficient of kinetic friction begins to increase until it reaches it terminal value in which, it can no longer increase.

Answer:

Explanation:

For a string of length L clamped down on both ends , for fundamental mode of vibration

2 . λ / 4 = L

= λ / 2 = L

λ = 2 L

For other modes , the formula is

n . λ/2 = L where n is an integer .

λ = 2L / n

if n = 6

λ = 2L / 6

= L/3

So wavelength = L/3 is possible .

Answer:

Impulse. Impulse is when a force is applied to an object for an amount of time.

Explanation:

It can't be momentum because momentum is the motion of a moving body, that is measured as a product of its mass and velocity.

It' cant be inertia because inertia is when an object doesn't move/ it does nothing as well as an object remaining unchanged.

And it can't be acceleration because acceleration is when how fast an object can go/ there velocity.

And that leaves us with impulse, so that's the correct one.

Hope this helped!

Answer:

impulse

Explanation:

took the test

Answer:

75.84%

Explanation:

We were given Speed of the sports car, v as 80 mph , we can convert to m/s for unit consistency.

v=80mph= 35.76 m/s

The radius of curvature is given as , r = 540 m

✓ the normal weight can be denoted as Wn

✓ the apparent weight of the person can be denoted as Wa

Wn= normal weight= mg

Wa=apparent weight = (mg - mv^2/r)

g= acceleration due to gravity= 9.8m/s^2

The apparent weightand normal weight has a ratio of

Mn/Ma= [mg - mv^2/r]/mg ........eqn(1)

If we simplify eqn(1) we have

Mn/Ma=[g - vr^2/g].............eqn(2)

Then substitute the given values

Mn/Ma=9.8 - [(35.76^2)/540]/ 9.8

=0.758×100%

Mn/Ma=75.84%

Hence, the required fraction is 75.84%

Answer:

See explanation below.

Explanation:

The internal energy (kinetic energy) of the milk particles increases thus warming the milk up, while the internal energy of the coffee particles reduce their initial average speed as they are imparting energy to the slow milk particles.

Answer:

Δp = 620 N.s

Explanation:

       [tex]F = \frac{\Delta p}{\Delta t} (1)[/tex]

       for m= constant, it reduces to F= m*a.

       [tex]\Delta p = F* \Delta t = 62 N* 10.0 s = 620 N*s (2)[/tex]

Answer:

See the explanation below,

Explanation:

Momentum is defined as the product of mass by Velocity. In this way, we will replace the following equation in each of the cases.

[tex]P=m*v[/tex]

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

A)

[tex]P = 10000*0\\P=0[/tex]

B)

[tex]P=100*5\\P=500[kg*m/s][/tex]

C)

[tex]P=1200*15\\P=18000[kg*m/s][/tex]

D)

[tex]P=15*1000\\P=15000[kg*m/s][/tex]

From higher to lower momentum

C,D,B,A

Answer:

B. Evaporation

Explanation:

Because I am absolutely positive

Please give Brainlyest

Answer:

0m/s²

Explanation:

The acceleration of the given body whose motion has been described will be zero.

This is because the body moves with a constant velocity.

Acceleration is defined as the rate of change of velocity with time.

Since in this problem, the velocity is not changing per time, then the acceleration would be zero.

A body moving steadily implies that such body is not changing its motion by the virtue of its velocity and even direction.

Answer:

combustion reaction

glucose,oxygen

carbon dioxide,water,energy

8

no. required balanced equation is:

C6H12O6+6O2--->6CO2+6H2O+energy

endothermic as it needs heat in the form of sunlight.

Answer:

See the explanation below.

Explanation:

The force is a vector therefore we can decompose the force into components x & y. as we need the horizontal component of the force, we must use the cosine function of the angle.

[tex]F_{1x}=30.8*cos(20)\\F_{1x}=28.94[N]\\F_{2x}=34.3*cos(20)\\\\F_{2x}= 32.23[N][/tex]

Answer:

[tex]L=2.5*10^-^7m[/tex]

Explanation:

From the question we are told that

Frequency of light  [tex]f= 600 THz[/tex]

Generally the equation for wave is mathematically given as

[tex]\lambda=\frac{c}{\gamma}[/tex]

Where

[tex]1THz=10^1^2[/tex]

[tex]\lambda=\frac{3*10^8}{600*10^1^2}[/tex]

[tex]\lambda=0.5*10^-^6m[/tex]

Generally the equation for a fundamental Frequency  is mathematically given as

[tex]L=\frac{\lambda}{2}[/tex]

[tex]L=\frac{0.5*10^-^6}{2}[/tex]

Therefore the length of the smallest standing wave

[tex]L=2.5*10^-^7m[/tex]

Answer: The more massive one will have larger kinetic energy.

Explanation:

We know that when we drop an object, the acceleration of the object will be equal to the gravitational acceleration.

a(t) = -9.8m/s^2

And to get the velocity, we need to integrate over time, to get:

v(t) = (-9.8m/s^)*t + v0

Where v0 is the initial speed of the object.

You can see that the mass of the object does not affect the velocity of it.

Then when we drop two marbles of different masses from the same height, we know that the final velocity of them will be equal.

Now, we also know that the kinetic energy can be written as:

K = (m/2)*v^2

where m is the mass, and v is the velocity.

Then the kinetic energy of the marble with less mass can be written as:

k = (m/2)*v^2

And the kinetic energy for the more massive one is:

K = (M/2)*v^2

And we know that both of them have the same velocity, and M is larger than m, then we can conclude that the marble with larger mass will have larger kinetic energy.

Answer:

Explanation:

Let the velocity of firing be u at angle θ

At maximum height velocity will be equal to horizontal component of initial velocity or vcosθ

So , vtop = v cosθ

At height h/2

vertical component of velocity v₂

v₂² = (usinθ)² - 2 g . h/2

v₂² = u²sin²θ - gh

horizontal component of velocity at height h/2 = u cosθ

velocity at height h / 2

= √ ( u²sin²θ - gh + u² cos²θ)

Given

√ ( u²sin²θ - gh + u² cos²θ) = 2 vtop

u²sin²θ - gh + u² cos²θ = 4 v²top = 4 u² cos²θ

u²sin²θ - gh =  3 u² cos²θ

At height h , vertical component of velocity is zero

0 = u²sin²θ - 2gh

gh = u²sin²θ / 2

u²sin²θ - u²sin²θ / 2  =  3 u² cos²θ

u²sin²θ / 2  = 3 u² cos²θ

Tan²θ = 6

Tanθ = 2.45

θ = 68⁰ .  

Answer:

The answer is :(B) 1.9 N

please make my answer brainlist

Answer: the contents of this container weighs 4905 kg.m/s²

Explanation:

Given that;

volume of a container V = 0.5 m³

we know that standard gravitational acceleration g = 9.81 m/s²

specific volume of liquid filled in the container v = 0.001 m³/kg

now we express the equation for weight of the container.

W = mg

W = (pV)g

W = Vg / ν

so we substitute

W =  (0.5 m³)(9.81 m/s ) / 0.001 m³/kg

W = 4.905 / 0.001

W = 4905 kg.m/s²

Therefore, the contents of this container weighs 4905 kg.m/s²

Answer:

We know that the gravitational force F between two masses P and Q, that are separated by a distance R is:

[tex]F = G*\frac{P*Q}{R^2}[/tex]

Where G is the gravitational constant.

a) Mass P is doubled, then we have 2*P instead of P, the new force is:

[tex]F' = G*\frac{(2*P)*Q}{R^2} = 2*(G*\frac{P*Q}{R^2} ) = 2*F[/tex]

b) Now R is doubled, then instead of R, we have 2*R:

[tex]F' = G*\frac{P*Q}{(2*R)^2} = G*\frac{P*Q}{4*R^2} = G*\frac{P*Q}{R^2}*(1/4) = F/4[/tex]

c) Now we replace P by 2*P, and Q by 3*Q

[tex]F' = G*\frac{(2*P)*(3*Q)}{R^2} = 2*3*(G*\frac{P*Q}{R^2} ) = 6*F[/tex]

d) The entire mass of the system is increased by a factor of 4, then both of the individual masses are increased by a factor of 4.

Then we need to replace P by 4*P, and Q by 4*Q.

[tex]F' = G*\frac{(4*P)*(4*Q)}{R^2} = 4*4(G*\frac{P*Q}{R^2} ) = 16*F[/tex]

e) Now we replace R by R/2.

[tex]F' = G*\frac{P*Q}{(R/2)^2} = G*\frac{P*Q}{R^2/4}= 4*G\frac{P*Q}{R^2} = 4*F[/tex]

Answer:

For two waves of equal amplitude interfering constructively, the resulting amplitude is twice as large as the amplitude of an individual wave. For 100 waves of the same amplitude interfering constructively, the resulting amplitude is 100 times larger than the amplitude of an individual wave.

Answer:

the work that must be done to stop the hoop is 2.662 J

Explanation:

Given;

mass of the hoop, m = 110 kg

speed of the center mass, v = 0.22 m/s

The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;

W = ΔK.E

W = ¹/₂mv²

W = ¹/₂ x 110 x 0.22²

W = 2.662 J

Therefore, the work that must be done to stop the hoop is 2.662 J

The amount of work that must be done to stop a hoop of mass 110 kg moving with s speed of 0.220 m/s is 2.662 J

Work can be defined as the ability or the capacity to perform work. Work is also the measure of energy of a body. The S.I unit of work is Joules (J)

Formular for kinetic energy of the hoop is

EK = mv²/2.................... Equation 1

Where EK = Kinetic energy of the hoop, m = mass of the hoop, v = velocity of the hoop.

Given: m = 110kg, v = 0.220 m/s.

Substitute these values into equation 1

EK = 110(0.22)²/2

Ek = 2.662 J.

Therefore, The amount of work that must be done on the hoop to stop it is

Learn more about Work here: https://brainly.com/question/12106685

Answer:

Friction, Applied Force and Gravity