? Anyone know the answer

(a) Electron domain geometry - Octahedral. (b) Molecular geometry - Square pyramidal. (c) Smallest bond angle - 90° (d) The polarity of BrF₅, best choice is: The molecule is polar and has polar bond. (e) AsH₃ is polar molecule.

A molecule's valence shell electrons are shown in a very simple manner via a Lewis structure. It serves as a visual representation of how the electrons surrounding certain molecules' atoms are positioned.

It demonstrates the bonds that exist between a molecule's atoms and its lone pairs of electrons. When used in conjunction with hybrid orbitals, Lewis structures can also be helpful in predicting molecular geometry.

(a) Electron domain geometry - Octahedral.

(b) Molecular geometry - Square pyramidal.

(c) Smallest bond angle - 90°

(d) The polarity of BrF₅, best choice is: The molecule is polar and has polar bond.

(e) AsH₃ is polar molecule.

Your question is incomplete most probably your full question was

a. What is the electron-domain (charge-cloud) geometry of BrF5? Enter the electron-domain geometry of the molecule.

b. What is the molecular geometry of BrF5?

c. Ignoring lone-pair effects, what is the smallest bond angle in BrF5?

d. Which choice best describes the polarity of BrF5?

The molecule is polar and has polar bonds.

The molecule is nonpolar and has polar bonds.

The molecule is polar and has nonpolar bonds.

The molecule is nonpolar and has nonpolar bonds.

e. Of the molecules below, only ________ is polar.

H2

SiS2

CH4

AsH3

PF5

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The an alpha helix amino fundamental structure Amino acid 1 two amino acids acid three −Glu−Leu−Ala−Lys−Phe− is the answer and three hydrogen bonds with water.

On a polypeptide chain, a -helix is a correct helix of amino-acid residues that normally has between 4 & 40 residues. The oxygen of the top coil (C=O) and the protons of the bottom coil (N-H) form hydrogen bonds that keep this coil together.

Alpha-helical and beta-sheet architectures of soluble (globular) proteins are known to be easily broken by the amino acid proline. This creates a structural conundrum because the Pro residue is frequently found in the presumed transmembrane helices of membrane proteins, deliver excellent proteins.

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The concentration terms are molality, normality and mole fraction. Molarity can be used to find out the ionic strength of any solution. Therefore, 0.49M is the molarity of the diluted solution.

Molarity can be calculated by dividing number of moles of solute by volume of solution in litre. Molarity is affected by temperature. Its unit is mole/liter. It measure the concentration of any solute in a solution.

Mathematically,

According to the neutralization law,

M₁V₁=M₂V₂

where,

M₁ = molarity of stock solution =4.9 M

V₁ = volume of stock solution = 4.0l

M₂ = molarity of dilute solution =M₂

V₂ = volume of dilute solution = 40l

substituting all the given values we get

M₁V₁=M₂V₂

4.9 ×4.0=M₂×40

M₂=0.49M

Therefore, 0.49M is the molarity of the diluted solution.

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pH in Part A is 9.16, pH in Part B is 5.56, and pH in Part C is 4.98.

a method for determining how basic or acidic something is. pH is measured on a scale from 0 to 14. On this scale, a pH of 7 denotes neutrality, meaning it is neither acidic nor basic. If the pH is less than or equal to 7, it is more acidic, and if it is greater than 7, it is more basic.

A pH value of no greater than 0 is produced by a hydrogen ion concentration of no more than 1M at the far end. On the opposite extreme, there are no more than 1M hydroxide ions, resulting in a pH of no more than 14.

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As per the aleks data tab the chemical species can be given as per the following: Ag<Zn<Mg<Na

This is not a redox reaction. None of the species are reduced and none are oxidized.

The decreasing power will be greater the lower the reduction potential.

A chemical reaction known as an oxidation-reduction (redox) reaction includes the exchange of electrons between two substances. An oxidation-reduction reaction is any chemical process in which a molecule, atom, or ion experiences a change in its oxidation number as a result of gaining or losing an electron.

Redox reactions are those in which one chemical is reduced and another is oxidized. Here, oxygen is being introduced, which causes C to oxidize into CO, and oxygen is being removed, which causes ZnO to decrease to Zn. It is a redox reaction as a result.

Redox reactions are those in which there is a change in the oxidation number, with both an increase and a drop in number.

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The base has a molarity of 0.5M if 25 milliliters of 0.80M HCl are used to fully neutralize 40 milliliters of NaOH solution.

The following expression can be used to determine a solution's molarity:

M1V1 = M2V2

Where M1 is the acid's molarity.

M2 stands for the base's molarity.

V1 is equal to the acid's volume.

V2 is the volume of the base.

25 × 0.80 = 40 × M2

20 = 40M2\sM2 = 20/40\sM2 = 0.5M

As a result, the molarity of the base is 0.5M if 25 milliliters of 0.80 M HCl are used to totally neutralize 40 milliliters of NaOH solution.

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The given conformer from the wedge-and-dash drawing into its Newman projection is attached below.

With the front atom represented by the point where three lines intersect (a dot) and the back atom represented by a circle, a Newman projection shows how a chemical bond will behave from front to back. The front atom is referred to as proximal, and the back atom as distal.

With a line representing the front atom and a circle representing the back carbon, the Newman projection, which is helpful in alkane stereochemistry, shows how a chemical bond will behave from front to back. It is referred to as proximal for the carbon atom in the front and distal for the one in the back.

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Complete question is attached below.

Condensation reduces a system's entropy by changing a gas into a liquid state while also dissipating heat outside the system.

Since heat (heat) is being released from the system into the environment, the entropy of a environment will rise.The subscript "systems" is frequently omitted from the heat in the previous iteration of this equation since heat is typically defined from the viewpoint of the system.

As the temperature rises, entropy increases.The kinetic energy of the substance's particles increases as temperature rises.

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0.1 m solution is diluted by three orders of magnitude. The new concentration is 0.0001M.

A homogenous mixture of one or more solutes that have been dissolved in a solvent is referred to as a solution. A solute dissolve in a solvent to form a homogenous mixture. Solute: A material that dissolves in a solvent to form a homogenous mixture.

In chemistry, a solution is a homogeneous mixture of two or more compounds in relative proportions that can be constantly changed up to what is referred to as the limit of solubility. Although the term "solution" is frequently used to refer to the liquid state of matter, solutions of gases and solids are also possible.

The new concentration will be 0.1/10x10x10 = 0.0001 m

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According to henry's law, The solubility of n2 gas in water, at the same temperature is, 141 mg/100 g water.

The maximum amount of a chemical which will dissolves in a volume of solvent at a given temperature is referred to as its solubility. Varying compounds have quite different solubilities, which is a characteristic of a specific solute-solvent pair.

Henry's Law says that the solubility of a gas is directly proportional to the pressure so:

S1/P1 = S2/P2

48 mg/100g / 2.04 atm = S2/6 atm

S2 = 141 mg/100 g water

solubility of n2 gas is 141 mg/100 g water

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Answer:

The  pH of a 0.20 m solution of NH₄Br at 25.0 ∘c is 4.96.

pH is defined as the measure of the concentration of H⁺ ions, the acidity as well as alkalinity of a solution. Aqueous solutions at 25 ° C with a pH of less than 7 are basic and acidic or the alkaline solutions are those having pH greater than 7. All the acids and bases does not react with the same chemical compound at the same rate. Some will react vigorously, some moderately while others not show any reaction.

Use the Ka=5.6x10^-10

NH₄+(aq)+H₂0(l)=NH₃(aq)+H₃O+(aq)

I    0.20                       0              0

C     -x                           +x            +x

E      0.20-x                    x              x

(x^2)/(0.20-x)=5.6x10^-10

x=0.000011=[H₃O+]

pH=-log[H₃O+]

-log(0.000011)

pH=4.96

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As the number of bonds between two carbon atoms increases, bond length decreases

The bond length is the separation among two bound atoms' centres. It represents the separation of the two atoms inside each nucleus along the potential energy curve at the lowest potential energy state of the system. Since there are more bonds between two carbon atoms, the electrons are shared more tightly and the bond length is shortened.

As an illustration, the average bond length for a single bond is about 154 pm, while the average bond length for a triple bond is about 120 pm. This is because numerous bonds have shorter bond lengths because of the stronger attraction of the electrons to the atom nuclei.

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The concentration of I- needed to begin precipitation will be [I⁻] = 3.77 x 10⁻¹³ M and (I)⁻² = 6.07 x 10⁻⁶.

Concentration is termed as the amount of a substance in a defined space.

2.2 x 10⁻⁴ M Ag⁺ (1)

1.3 x 10⁻³ M Pb₂⁺ (2)

1) Ag⁺ + NaI  →  AgI + Na⁺ (Ksp = 8.3 x 10⁻¹⁷)

2) Pb²⁺ + NaI →  PbI₂ + Na+ (Ksp = 7.9 x 10⁻⁹)

Ksp = [Ag⁺] [I⁻] = (2.2 X 10⁻⁴ M) (I⁻)

Ksp = [Pb²⁺] [I]² = (1.3 X 10⁻³M) (I⁻)²

(1) 8.3 X 10⁻¹⁷ = (2.2 X 10⁻⁴M) (I⁻)

(I-) = 3.77 X 10⁻¹³ M

(2) 7.9 X 10⁻⁹ = (1.3 X 10⁻³M) (I⁻)²

6.07 X 10⁻⁶ = (I⁻)²

(I⁻)² = 6.07 X 10⁻⁶

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For a fixed amount of gas at a fixed temperature, if the volume is doubled, the pressure will be doubled.

It is because according to the Ideal Gas Law, pressure and volume are directly proportional to each other. As one goes up, the other one goes up by the same degree. Formula for Ideal Gas Law is PV = nRT.

The Ideal Gas Law is the law in which the product of the pressure and the volume of one gram molecule of an ideal gas is equivalent to the product of the absolute temperature of the gas and the universal gas constant.

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A study guide found at the end of a chemistry chapter typically provides a summary of the key concepts and information presented in the chapter, as well as a list of key terms and definitions.

study guide may also include review questions and exercises designed to help students test their understanding of the material and identify areas where they may need additional practice or review. Additionally, it may also include some sample problems, tips for solving problems, and explanations of key concepts, as well as a summary of the key equations, formulas, and laws that were discussed in the chapter.In general, a study guide is a useful tool for students to use as they work their way through a chemistry textbook. It can help students to identify the most important information in the chapter, focus their study efforts, and check their understanding of the material. Additionally, it can also serve as a useful reference for students as they review for exams or complete homework assignments.

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Any

procedure

where the velocity varies is referred to as

object acceleration.

There are only two ways to accelerate

changing your

speed

or

changing your

direction

, or

changing both.

This is because

velocity

is both a speed and a direction.

No matter how quickly you're moving, you can't possibly be accelerating if you're not also altering your direction and speed.

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acceleration

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Nihonium (Nh) mass is 285.7 u, a synthetic element with atomic number 113, was the first synthesized chemical elements that do not exist in nature but can be created in laboratory.

Particle accelerators produce synthetic elements. Two tiny elements are propelled at breakneck velocities and crash with one another. Their nuclei combine to form one bigger element. Before it degrades, the element is examined using lab equipment.

Mass of Nb from the figure:

 => 10% x 284.2 + 30% 285.2 + 60% x 286.2

=> 285.7 u (atomic mass unit)

Transuranium elements and the actinoid series are typically found in period 7, along with occasionally created artificially. These elements can be utilised for detectors and spectrophotometers in addition to being the typical fuel for chemical reactors. Some are applied in the pharmaceutical sector.

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Chemical elements known as synthetic that do not exist in nature but = was elements_ Nihonium can be created in the laboratory are the first synthesized in 2004. (Nh), synthetic element with atomic number 113, hypothetical mass spectrum for sample of Nh containing 10 atoms shown in the picture. Using this spectrum information, calculate the mass of Nh in this sample

Answer:

285.7 u.

Explanation:

1 / 4

The equation for average atomic mass is

average atomic mass

=

∑

�

=

1

�

(

relative abundance

×

atomic mass

)

�

average atomic mass=

i=1

∑

n

​

(relative abundance×atomic mass)

i

​

start text, a, v, e, r, a, g, e, space, a, t, o, m, i, c, space, m, a, s, s, end text, equals, sum, start subscript, i, equals, 1, end subscript, start superscript, n, end superscript, left parenthesis, start text, r, e, l, a, t, i, v, e, space, a, b, u, n, d, a, n, c, e, end text, times, start text, a, t, o, m, i, c, space, m, a, s, s, end text, right parenthesis, start subscript, i, end subscript

We can use this equation, along with the relative abundances and atomic masses of each isotope in the mass spectrum, to calculate the average atomic mass of

N

h

Nh in the sample.

Hint #22 / 4

The mass spectrum shows three peaks, each corresponding to a different isotope of

N

h

Nh. We can determine the relative abundance of each isotope by dividing the number of atoms of that isotope present in the sample by the total number of atoms in the sample:

Isotope

N

h

-

284

Nh-284

N

h

-

285

Nh-285

N

h

-

286

Nh-286

Atomic mass (

u

u)

284.2

284.2284, point, 2

285.2

285.2285, point, 2

286.2

286.2286, point, 2

Relative abundance

1

a

t

o

m

10

a

t

o

m

s

=

.

1

10 atoms

1 atom

​

=.1

3

a

t

o

m

s

10

a

t

o

m

s

=

.

3

10 atoms

3 atoms

​

=.3

6

a

t

o

m

s

10

a

t

o

m

s

=

.

6

10 atoms

6 atoms

​

=.6

Hint #33 / 4

Plugging the relative abundances and atomic masses into the equation for average atomic mass, we get:

average atomic mass

=

∑

�

=

1

�

(

relative abundance

×

atomic mass

)

�

=

(

.

1

×

284.2

u

)

+

(

.

3

×

285.2

u

)

+

(

.

6

×

286.2

u

)

=

28.42

u

+

85.56

u

+

171.7

u

=

285.7

u

average atomic mass

​

=

i=1

∑

n

​

(relative abundance×atomic mass)

i

​

=(.1×284.2 u)+(.3×285.2 u)+(.6×286.2 u)

=28.42 u+85.56 u+171.7 u

=285.7 u

​

Hint #44 / 4

So, based on the mass spectrum, the average atomic mass of

N

h

Nh in the sample is

285.7

u

285.7 u.

Answer:

Pansy has measured the volume of a sample of oxygen gas and has found that she has a total of 13.44 moles of the gas. What is the mass of this

Explanation:

n=m/Mr. m= nxMr = 13.44 x 32 = 430.08 g of oxygen

Answer:

Noble gas

Explanation:

Noble gases are the most stable elements on the periodic table, so every element aims to bond in a way that will make them have the same number of valence electrons as the noble gases. Valence electrons are the electrons in the outer ring of an element. Noble gases have eight valence electrons, which is the most possible. All elements aim to be unreactive in this manner. Hope this helps!

At constant pressure the one  of these systems do work on the surroundings is the : C) A(g)  +  B(g)    ---->   3C.

The reaction is :

A(g)  +  B(g)    ---->   3C

The number of the moles of gaseous reactants :

n = 1 + 1 = 2

The number of the moles of gaseous of the products :

n = 3

Δn = 3 - 2 = 1

The work done is given as :

W = -Δn RT

W = - RT

Thus, the work is negative , so the systems do work on the surroundings. Therefore the system that works on the surroundings is the correct option is C) A(g)  +  B(g)    ---->   3C.

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I would use the information from both sets of cards to create a comprehensive table of elements that organizes the elements according to their properties. This table would allow for easy prediction of the properties of new elements based on their position within the table.

As a theoretical chemist and inventor of the periodic table, I would approach this task by first organizing the known elements based on their properties, such as atomic weight, melting point, boiling point, and valence. I would then look for patterns and trends in the properties of the known elements and group them together accordingly.

Next, I would examine the properties of the unknown elements and compare them to the known elements. I would try to find a place for each unknown element within the table of known elements, based on its properties. If the properties of the unknown element did not match any of the known elements, I would consider the possibility of a new element that should be added to the table.

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Therefore, C₁₄H₁₀O₂ + NaBH₄ = C₁₄H₁₄O₂ + Na₂ + B₄ is the balanced equation for sodium borohydride reduction.

Aldehydes, ketones, or acid chlorides can be reduced using sodium borohydride when other easily reducible functional groups are present. 32 The solvents employed for the reduction are indicative of sodium borohydride's comparatively low reactivity. converts ketones and aldehydes to the corresponding alcohols. Esters, epoxides, lactones, carboxylic acids, nitro compounds, and nitriles are not reactive to sodium borohydride; nonetheless, it decreases acyl chlorides.

In chemistry, sodium borohydride is a widely used reducing agent. Its formula is NaBH4, and its constituent elements are sodium (Na), boron (B), and hydrogen (H). Since it is a safer reagent for reduction than other options, it is frequently employed in chemistry labs. NaBH4 is primarily utilised in the production of Na2S2O4 (sodium dithionite), a bleaching agent for wood pulp that is also used to convert aldehydes and ketones to alcohols, from SO2.

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The operators were unable to restore the power level specified by the test program, which put the reactor in an unstable condition.

Project Reactor is a fully non-blocking foundation with back-pressure support included. It's the foundation of the reactive stack in the Spring ecosystem and is featured in projects such as Spring WebFlux, Spring Data, and Spring Cloud Gateway.

Light-water reactors (LWRs) are power reactors that are cooled and moderated with ordinary water. There are two basic types: the pressurized-water reactor (PWR) and the boiling-water reactor (BWR). In the PWR, water at high pressure and temperature removes heat from the core and is transported to a steam generator.

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The best way to find out what a chemical is in the lab is to consult the safety data sheet (SDS) for the chemical. An SDS will provide detailed information about the chemical, including its identity, hazards, and safe handling instructions.

If an SDS is not available, contact the supplier to request an SDS or consult a professional chemical reference book. Additionally, if there is a label on the container, it may provide the chemical identity. If the chemical is a mixture of multiple components, the best way to identify it is to run a chromatography analysis to separate and identify the components.

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Answer:Intermolecular forces

Explanation:See in a molecule these intermolecular forces hold the atoms together which decides the rigidity of the material.

I hope the answer was helpful

The starting pressure of CCl₄ at this temperature that will produce a total pressure of 1.2 atm at equilibrium pressure P is 0.69atm.

It is described as the ratio of the partial pressures of the reactants to those of the products, both raised to a power that is equal to the coefficients of the respective reactants and products in a balanced chemical equation. This indicates by Kp.

CCl₄ ⇄ C (s) + 2Cl₂

Initial     p          0  0

equilibrium p-x   0  2x

Total pressure at equilibrium = p - x + 2x = p + x = 1.2---eq(1)

Kp = 076 = Pc ×P²cl/Pccl₄

Kp = 0×(2x)²/p-x

Kp = 4x²/p-x ---eq(2)

Solving equation (1) and (2). we get x = 0.51

p + x = 1.2

p = 1.2 - 0.51 = 0.69 atm

The starting pressure of CCl₄ is 0.69 atm.

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The percent by mass of chlorine in C2H5Cl is  D) 54.94%.

In C2H5Cl, The molecular  weight of C2H5Cl is (12.01 + (2*1.01) + 35.45) = 64.47 g/mol

The weight of chlorine in the compound is 35.45 g/mol.

The mass percent of chlorine in the compound can be calculated by (mass of chlorine/total mass) x 100%.

Therefore, (35.45/64.47) x 100% = 54.94%

So, The percent by mass of chlorine in C2H5Cl is 54.94%.

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The activation energy for a reaction is changed from 237 kj/mol to 57.9 Kj/mol at 653 k by the introduction of a catalyst. of the uncatalyzed reaction takes about 2290 years to occur then about 1.64 * 10³yr⁻¹ will be consumed by uncatalyzed reaction if we assume the frequency factor a is constant and assume the initial concentrations are the same.

Activation energy for uncatalyzed energy,

Eₐ(1) = 237kJ/mol

Activation energy for catalyzed reaction,

57.9 kJ/mol

Time taken by uncatalyzed reaction,

t₁=2290 years

Temperature, T=653 K

First, we will find the rate constant for the uncatalyzed reaction:

k ∝ 1/t

k₁ = 1/2290yr=0.00040 yr⁻¹

The rate constant the catalyzed reaction (k2) is calculated as follows:

[tex]ln\frac{K_{2} }{K_{1} }[/tex] = [tex]\frac{E_{a(1) -E_{a(2)} } }{RT_{} }[/tex]

R=8.314 J/K⋅mol

K₂ = -6.08 * 10⁻⁴ yr⁻¹

Now, we will find time taken by catalyzed reaction:

t₂ = 1/k₂

t₂ = 1.64 * 10³yr⁻¹

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4.325% of 8.0 × [tex]10^{-3}[/tex] M butanoic acid be ionised, while only 0.018% of 8.0 ×[tex]10^{-3}[/tex] M butanoic acid be ionised in a solution that contains 8.0 ×[tex]10^{-2}[/tex] M sodium butanoate.

Ionization is any process that involves adding or removing electrons to change electrically neutral molecules or atoms (ions) into electrical charges atoms or molecules (ions).

A. [Butanoic acid] = 8.0*10−3 M

Ka = 1.5*10∧-5

Butanoic acid ionizes as:

HA ⇄ H+ + A-

Initially 8.0*10−3 0 0

Finally 8.0*10−3 - x x x

Ka = x*x / 8.0*10−3 - x

1.5*10−5 = x*x / 8.0*10−3

1.2*10^-7 = x*x

x = 3.46*10^-4 M

Percent ionization = (3.46*10^-4 / 8.0*10−3) * 100

= 4.325 %

B). [Sodium butanoate] = 8.0*10^-2 M

HA ⇄ H+ + A-

Initially 8.0*10−3 0 0

Finally 8.0*10−3 - x x 8.0*10^-2 + x

Ka = x*(8.0*10^-2 + x) / 8.0*10−3 - x

1.5*10−5 = x*8.0*10^-2 + x*x / 8.0*10−3

1.2*10^-7 = x*x + x*8.0*10^-2

x*x + x*8.0*10^-2 - 1.2*10^-7 = 0

x = 1.49*10^-6 M

Percent ionization = (1.49*10^-6 / 8.0*10−3) * 100

= 0.018 %

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