Approximate 23 by following the steps below.
V23 must lie between the whole numbers
and
You must answer all questions above in order to submit.

Answer:

Step-by-step explanation:

Verify if the ratio of corresponding sides is same:

Since the ratios are same the triangles are similar

Answer:

-27/2

Step-by-step explanation:

3/8 × -36

(3×-36)/8

-108/8

-27/2

Answer:

Step-by-step explanation:

Answer:

They are called quadrants

Hope it helps:)

Answer:

f^(-1)(x) = e^(x/3)

Step-by-step explanation:

1.  Replace 'f(x)' by 'y:'  y = 3ln x

2. Interchange x and y:  x = 3ln y => x/3 = ln y

3. Solve for y:  

   e^(x/3) = y

4.  Replace this 'y' with 'f^(-1)(x)'

    Then f^(-1)(x) = e^(x/3)

Answer:

its going up by 5 every time

Step-by-step explanation:i think that would help i dont know if it was obvious

Answer:

[tex]\huge\boxed{x > 1}[/tex]

Step-by-step explanation:

-4(x - 2) + 5 < 9

Subtract 5.

-4(x - 2) < 4

Divide by -4 (Flip the sign when dividing by a negative number).

x - 2 > -1

Add 2.

x > 1

Hope it helps :) and let me know if you want me to elaborate.

Answer:

x>1

Step-by-step explanation:

I had that same question hope that helped

Answer:

15 is the answer

Step-by-step explanation:

If it was designed as an alternate angle, then it would 63 degrees

Answer:

imagine cheating on your star assessment but same tho the answer is c

Step-by-step explanation:

because i solved it on paper

Answer:

Step-by-step explanation:

C

Answer:

see explanation

Step-by-step explanation:

If a polynomial f(x) is divided by (x - r) then the remainder is f(r)

Answer:

X=9

Step-by-step explanation:

3x+3=2x+12

3x-2x=12-3

x=9

Answer:

x = 7

Step-by-step explanation:

Add 4 on both sides to get 2x = 14, then divide 2 on both sides to get x = 7.

Hope this helps :)

Answer:

Should look like this

Step-by-step explanation:

y-intercept = 2

slope = 1

Answer:

616

Step-by-step explanation: hope it helps :)

Answer:665,830 my answer

Step-by-step explanation:

so. what have you got so far?

How can a digit have no value?

Answer:

B: BC ≅EC

Step-by-step explanation:

You know that the two angles starting in C are congruent (they're opposite by vertex C).

Given that the B angle and the E angle are congruent, in order for the two triangles to be congruent by A(ngle)S(ide)A(ngle) you want the side inbetween to be congruent. That is BC and EC. Option B

Answer:

8-(2/x)

Step-by-step explanation:

Answer:

tttttttttttttttttttttttttttttttttttttttttttttt

Answer:

I'm assuming the equation "Ax) = ax + bx² + cx+d" is really meant to read:

A(x) = ax^3 + bx² + cx+d

A(x) = x^3 + x^2 -4x -4

Step-by-step explanation:

(x+2)*(x+1)*(x-2)      [This reflect the fact that x= -2, x=-1, x=2 all result in a zero]

Multiply this out to get A(x) = x^3 + x^2 -4x -4

Using the concept of probability, the probability of not landing on yellow or red at all is 1/4.

Creating a square model of the two spins :

___ R ___ B ___ G ___ Y

R_ RR __ RB __ RG __ RY

B_ BR __ BB __ BG __ BY

G_ GR __GB __ GG __GY

Y_ YR __ YB __ YG __ YY

Combinations without red and yellow :

Recall :

P(without Red or Yellow) = 4/16 = 1/4

Hence, the probability of not landing on yellow or red at all is 1/4.

Learn more : https://brainly.com/question/14605518

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

Slope = (4-7)/(7-1)

Slope = -3/6

Slope = -1/2

Answer:

The slope is -4. The amount of money left goes down by 4 with each comic book.

Step-by-step explanation:

The answer is D

Answer:

700 -6% =658 and 658-7%=611.94

It looks like given matrices are supposed to be

[tex]\begin{array}{ccccccc}\begin{bmatrix}3&2\\2&3\end{bmatrix} & & \begin{bmatrix}1&-1\\2&-1\end{bmatrix} & & \begin{bmatrix}1&2&3\\0&2&3\\0&0&3\end{bmatrix} & & \begin{bmatrix}3&1&1\\1&3&1\\1&1&3\end{bmatrix}\end{array}[/tex]

You can find the eigenvalues of matrix A by solving for λ in the equation det(A - λI) = 0, where I is the identity matrix. We also have the following facts about eigenvalues:

• tr(A) = trace of A = sum of diagonal entries = sum of eigenvalues

• det(A) = determinant of A = product of eigenvalues

(a) The eigenvalues are λ₁ = 1 and λ₂ = 5, since

[tex]\mathrm{tr}\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3 + 3 = 6[/tex]

[tex]\det\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3^2-2^2 = 5[/tex]

and

λ₁ + λ₂ = 6   ⇒   λ₁ λ₂ = λ₁ (6 - λ₁) = 5

⇒   6 λ₁ - λ₁² = 5

⇒   λ₁² - 6 λ₁ + 5 = 0

⇒   (λ₁ - 5) (λ₁ - 1) = 0

⇒   λ₁ = 5 or λ₁ = 1

To find the corresponding eigenvectors, we solve for the vector v in Av = λv, or equivalently (A - λI) v = 0.

• For λ = 1, we have

[tex]\begin{bmatrix}3-1&2\\2&3-1\end{bmatrix}v = \begin{bmatrix}2&2\\2&2\end{bmatrix}v = 0[/tex]

With v = (v₁, v₂)ᵀ, this equation tells us that

2 v₁ + 2 v₂ = 0

so that if we choose v₁ = -1, then v₂ = 1. So Av = v for the eigenvector v = (-1, 1)ᵀ.

• For λ = 5, we would end up with

[tex]\begin{bmatrix}-2&2\\2&-2\end{bmatrix}v = 0[/tex]

and this tells us

-2 v₁ + 2 v₂ = 0

and it follows that v = (1, 1)ᵀ.

Then the decomposition of A into PDP⁻¹ is obtained with

[tex]P = \begin{bmatrix}-1 & 1 \\ 1 & 1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1 & 0 \\ 0 & 5\end{bmatrix}[/tex]

where the n-th column of P is the eigenvector associated with the eigenvalue in the n-th row/column of D.

(b) Consult part (a) for specific details. You would find that the eigenvalues are i and -i, as in i = √(-1). The corresponding eigenvectors are (1 + i, 2)ᵀ and (1 - i, 2)ᵀ, so that A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1+i & 1-i\\2&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}i&0\\0&i\end{bmatrix}[/tex]

(c) For a 3×3 matrix, I'm not aware of any shortcuts like above, so we proceed as usual:

[tex]\det(A-\lambda I) = \det\begin{bmatrix}1-\lambda & 2 & 3 \\ 0 & 2-\lambda & 3 \\ 0 & 0 & 3-\lambda\end{bmatrix} = 0[/tex]

Since A - λI is upper-triangular, the determinant is exactly the product the entries on the diagonal:

det(A - λI) = (1 - λ) (2 - λ) (3 - λ) = 0

and it follows that the eigenvalues are λ₁ = 1, λ₂ = 2, and λ₃ = 3. Now solve for v = (v₁, v₂, v₃)ᵀ such that (A - λI) v = 0.

• For λ = 1,

[tex]\begin{bmatrix}0&2&3\\0&1&3\\0&0&2\end{bmatrix}v = 0[/tex]

tells us we can freely choose v₁ = 1, while the other components must be v₂ = v₃ = 0. Then v = (1, 0, 0)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}-1&2&3\\0&0&3\\0&0&1\end{bmatrix}v = 0[/tex]

tells us we need to fix v₃ = 0. Then -v₁ + 2 v₂ = 0, so we can choose, say, v₂ = 1 and v₁ = 2. Then v = (2, 1, 0)ᵀ.

• For λ = 3,

[tex]\begin{bmatrix}-2&2&3\\0&-1&3\\0&0&0\end{bmatrix}v = 0[/tex]

tells us if we choose v₃ = 1, then it follows that v₂ = 3 and v₁ = 9/2. To make things neater, let's scale these components by a factor of 2, so that v = (9, 6, 2)ᵀ.

Then we have A = PDP⁻¹ for

[tex]P = \begin{bmatrix}1&2&9\\0&1&6\\0&0&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1&0&0\\0&2&0\\0&0&3\end{bmatrix}[/tex]

(d) Consult part (c) for all the details. Or, we can observe that λ₁ = 2 is an eigenvalue, since subtracting 2I from A gives a matrix of only 1s and det(A - 2I) = 0. Then using the eigen-facts,

• tr(A) = 3 + 3 + 3 = 9 = 2 + λ₂ + λ₃   ⇒   λ₂ + λ₃ = 7

• det(A) = 20 = 2 λ₂ λ₃   ⇒   λ₂ λ₃ = 10

and we find λ₂ = 2 and λ₃ = 5.

I'll omit the details for finding the eigenvector associated with λ = 5; I ended up with v = (1, 1, 1)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}v = 0[/tex]

tells us that if we fix v₃ = 0, then v₁ + v₂ = 0, so that we can pick v₁ = 1 and v₂ = -1. So v = (1, -1, 0)ᵀ.

• For the repeated eigenvalue λ = 2, we find the generalized eigenvector such that (A - 2I)² v = 0.

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}^2 v = \begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}v = 0[/tex]

This time we fix v₂ = 0, so that 3 v₁ + 3 v₃ = 0, and we can pick v₁ = 1 and v₃ = -1. So v = (1, 0, -1)ᵀ.

Then A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1 & 1 & 1 \\ 1 & -1 & 0 \\ 1 & 0 & -1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}5&0&0\\0&2&0\\0&2&2\end{bmatrix}[/tex]

Answer:

it's "2+6556_789*4236+8765/987"

Step-by-step explanation:

Answer:

I am pretty sure the correct answer is never true

Step-by-step explanation:

This is because when,

Δ JKL ≅ Δ MNP

Then, ∠J ≅ ∠M

∠K ≅ ∠N

∠L ≅ ∠P

so ∠L ≠ ∠N

i hope this is right haha

Answer: x>3

Step-by-step explanation:

3x + 2 > X + 8

2x  > + 8 - 2

2x > 6

x > 3

Answer:

Range: 6,500

The difference between the largest and the smallest number.

Mode: 12,000

The number that appears most.

Mean: 11,000

Because its the average of all numbers

Median: 9,500

The middle number