are the radiating electric field lines around a charged particle straight lines when the particle moves at constant velocity?

Answers

Answer 1

No, the radiating electric field lines are not around a charged particle straight lines when the particle moves at constant velocity.

An electric property that is connected with any location in space where a charge exists in any form is electric field. The electric force per unit charge is also termed as electric field. The formula for electric field is: E=F/Q

Where, The electric field is denoted by E, force by F and charge is Q.

When a charged particle is moves with a constant velocity then it is equivalent to an electric current which creates the magnetic field and electric field both around it. An electromagnetic field is generated when charged particles are accelerated. A stationary charge will produce an electric field in the surrounding space.

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Related Questions

The electric potential along the x-axis is V=100e−2xV, where x is in meters.

What is Ex at x=1.0m?

Ex?

What is Ex at x=2.0m?

Ex?

Answers

The electric field at x = 1.0 m is 12.18.

The electric field at x = 2.0 m is 0.135.

The electric potential at a point is a scalar quantity that is used to describe the electric potential energy per unit charge at that point. In the equation you provided, V is the electric potential at a point along the x-axis and x is the position along the x-axis. To find the electric field, which is denoted by Ex, you can use the equation Ex = -dV/dx, where dV is the change in electric potential and dx is the change in position along the x-axis.

To find the electric field at x = 1.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*1.0) = 50e^(-2) = 12.18.

To find the electric field at x = 2.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*2.0) = 50e^(-4) = 0.135.

In both cases, the electric field is positive, indicating that the electric field is directed away from the origin.

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section 9.4) a plane flies on a bearing of 315 degrees at a speed of 400 mph when it encounters a wind blowing in the direction of n10e at a speed of 30 mph. find the true direction and speed of the plane with the wind.

Answers

In both cases, y and x components are solved and added. The resulting speed hypotenuse is then computed and its direction calculated.

Airplane:

Ф = 270 - 265 = 5°

Hypotenuse, h = 400 mph

y component = 400 Sin Ф = 400 Sin 5 = 36.61 mph

x component = 400 Cos Ф = 400 Cos 5 = 418.40 mph

Wind

Ф = 315 -210 = 60°

Hypotenuse, h = 30 mph

y component = 30 Sin 60 = 25.98 mph

x component = 30 Cos 60 = 15 mph

Total y = 36.61+25.98 = 62.59 mph

Total x = 418.40+15 = 433.40 mph

Resulting speed of airplane = Sqrt (y^2+x^2) = Sqrt (62.59^2+433.40^2) = 437.9 mph

Direction = 270 -[tan^-1 (y/x)] = 270 -[tan^-1(62.59/433.40)] = 261.78°

Therefore, the resulting speed is 437.9 mph in the direction of 261.78°

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A motorcycle accelerates from rest at 6.0 m/s2. How much farther will it travel during the second 3.0 s of its motion than during the first 3.0 s.

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Solving the acceleration is S=ut +1/2at^2, S=27

How do you calculate distance using final speed and acceleration?Solving for Final Velocity from Distance and Acceleration

v 2 = v 0 2 + 2 a ( x − x 0 ) ( constant a ).

Sn = u + a (n – ½). Hence, the formula for distance travelled in nth second is given by, Sn = u + a (n – ½).

distance = speed × time.

Where an is acceleration, v is the change in velocity, and t is the time it took for that change to occur, we can write a = v / t. Meters per second per second, or m/s2, is the unit used to measure acceleration.Using the equation S=ut +1/2at^2

Where

S is displacement

u is initial velocity =0 (as the body is at rest)

a is acceleration

t is time taken

So,

S=1/2at^2

S=1/2 ×6×3 ×3

S=3×3 ×3

S=27

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for the circuit diagram below: a. find the voltage vout and the current ix. b. find the current iy. c. how much power is delivered by the 6 v source? d. find the power dissipated in the 8 kw resistor.

Answers

A. In the ideal Amp, V⁺ = V⁻

B. [tex]V_{out} = -2v[/tex]

C. [tex]P_{8K} = 4.5 m watts[/tex]

Solution:

[tex]V_{out} = 3-5 = -2v = V_{out} = -2v\\\\I_{y} = \frac{V_{out} }{500} = \frac{-2}{500} = I_{y} = -4ma[/tex]

Power delivered by 6v = P6v = (6)(1) (6)(m) -6mworth = = 6 V Vgk = (8k) (a) = (8k) (0,75 mA)

Power dissipated in the 8k = P₁₁ = (6v) (ia) = (6) (0.75 m) = 4.5 mwatts.

A schematic is a graphical representation of an electrical circuit. Schematics uses simple images of components, and schematics use standardized symbolic representations to show circuit components and connections. A schematic is a simplified representation of the components of an electrical circuit using either pictures of individual parts or standard symbols.

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what is the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second? assume no other forces act upon the object * 1 point captionless image a) 100 joules b) 500 joules c) 1000 joules d) 50,000 joules

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The kinetic energy of the object with a mass of 10 kilograms traveling at a speed of 10 meters per seconds is 500 Joules.

Newton’s laws are encapsulated in what may be the second most famous equation in physics: F = ma, which states that a force F applied to a mass m results in an acceleration a.

Since the mass is accelerating, its velocity v is not constant, but since the acceleration is constant, and acceleration is the rate of change of velocity, the rate at which v is changing is constant and is equal to the acceleration a.

Since the work done by the force is just the energy imparted to the mass, we will use the letters K.E to stand for this work. Then we get,

K.E = ½ × m × v²

Where;

K.E = kinetic energy

m = mass

v = speed

K.E = ½ × 10 × 10²

K.E = 5 × 100 =  500 J

Hence, the correct option is b.

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Why is it important to shift gears correctly when driving a vehicle?

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Shifting gears correctly is important when driving a vehicle to ensure that the car is operating at its most efficient level.

By selecting the correct gear, you can ensure that the engine works at its optimal speed, allowing it to produce the most power with the least fuel. This helps you save money on fuel costs and reduces your car’s environmental impact.

Shifting gears correctly allows you to control the speed of your car. When accelerating, you need to select a higher gear so that the engine produces more torque, enabling your car to accelerate faster. When slowing down, you should select a lower gear to reduce the engine’s revolutions per minute (RPM), allowing you to slow down quickly and safely.

Finally, correctly shifting gears also ensure your passengers' safety, including yourself. If you shift gears too quickly or at the wrong time, you increase the risk of your car stalling, which can be dangerous in certain situations. In addition, selecting the wrong gear for your traveling speed can lead to acceleration and braking, leading to an uncomfortable and potentially difficult ride.

In conclusion, it is important to shift gears correctly when driving a vehicle to ensure efficient fuel use, control the speed of the car, and keep you and your passengers safe.

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jasper and gemma are going to play on a teeter totter. gemma gets on first. when jasper gets on, gemma moves into the air, but she does not move to the top. a girl sits on the left side of a black line resting at its middle on a brown triangle and a boy on the right. which statement could correctly explain the forces acting on the teeter totter? the forces are balanced because jasper weighs the same as gemma. the forces are unbalanced because jasper weighs the same as gemma. the forces are balanced because jasper weighs more than gemma. the forces are unbalanced because jasper weighs more than gemma.

Answers

The forces are balanced because Jasper weighs the same as Gemma.

Force:

A force is an influence that can alter an object's motion according to physics. A force can cause an object with mass to accelerate when it changes its velocity, such as when it moves away from rest. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F.Since forces are perceived as pushes or pulls, this can offer a simple explanation of how forces are described.

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a water supply pipe of diameter 2.50 cm carries water from the water main to a sprinkler that is at the top of a small hill. the sprinkler nozzle is 0.50 cm in diameter and the water exits the sprinkler nozzle with a speed of 10.0 ms-1 . if the sprinkler is 8.00 m above the supply pipe, find:

Answers

The volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

What is Bernoulli's equation?

According to Bernoulli's principle of fluid dynamics, a fluid's speed increases at the same time as its static pressure or potential energy decreases. The Bernoulli equation is regarded as the definition of energy conservation for flowing fluids. This is thought to be the qualitative behaviour that reduces pressure in high-velocity zones. Also, referred to as the Bernoulli effect.

Calculations:

Using continuity equation, Bernoulli's equation.

A1×V1 = A2×V2

Where,

A1 = area of the supply pipe

V1 = volume of supply pipe

A2 = area of sprinkler

V2 = volume of sprinkler

Given,

Diameter of supply pipe = 2.5cm therefore radius = 1.25cm.

Diameter of sprinkler = 0.5cm therefore radius = 0.25cm.

V1 = (A2×V2) /A1

V1 = (π [tex]r_{2}[/tex]²× V2) / (π [tex]r_{1}[/tex]²)

V1 = {π (0.25) ² × 8} / { π (1.25) ²}

V1 = 0.32m/s.

Hence, the volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

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a ruby laser emits an intense pulse of light that last a mear 10 nm. the light has a wavelength of 690nm, and each pulse has an energy of 500 mj: a) how many photons are emitted with each pulse? b) what is the rate of photon emission, in photons per second, during the 10ns that the laser is on?

Answers

Making a few assumptions like uniformity and flatness of the universe we have :

A. [tex](\frac{a}{a} )^{2} = \frac{8\pi gs+\pi }{3}[/tex]

B. [tex]\frac{a}{a} = - \frac{4\pi G}{3} (S+3P)+\frac{\pi }{3}[/tex]

where is 'a' is a scale factor which tells us how expanded the Universe is. And it's the first derivative gives the rate of expansion and its second derivative gives the acceleration of the universe.

So if G increases, due to the mass of neutrons. Then the acceleration would have a negative value which would mean slowing down.

All the above however does not consider dark energy, which would modify the equations. We still have to understand the nature of dark matter to be able to predict how much in the long run would gravity affect acceleration.

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the work function for lead is 4.14 ev. ultraviolet light of wavelength 153 nm is incident on the clean surface of a lead sample. we wish to predict the stopping voltage we will need for electrons ejected from the surface. (a) what is the photon energy of the ultraviolet light?

Answers

speed of the electron is v= 1.371 x 10⁶ m/s.

briefly:-

wavelength of the ultraviolet light beam ARE , λ = 130 nm = 130 x 10⁻⁹ m

the work function of molybdenum surface IS, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

energy of the incident light is :-

E = hf

where;

Planck's constant h= 6.626 x 10⁻³⁴ J/s

f = c / λ

E = hν = hc/λ

E =15.29810-19 J

Photo electric effect equation is;-

E = W₀ + K.E

Where;

K.E =the kinetic energy of the emitted  are electron K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J *- 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of  emitted electron is ;

K.E = ¹/₂mv²

where;

m =mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

K.E. = 1/2 m v2.

V=1.371 x 10⁶ m/s.

speed of the electron is v=1.371 x 10⁶ m/s.

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what parameters do hubble's law relate to each other

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Answer:

Hubble's law is considered a fundamental relation between recessional velocity and distance. However, the relation between recessional velocity and redshift depends on the cosmological model adopted and is not established except for small redshifts.

Explanation:

The relationship between recessional distance and velocity is thought to be governed by Hubble's law. Although it is not confirmed save for minor redshifts, the relationship between recessional velocity and redshift relies on the cosmological model used.

What is Hubble's Law?

Although Hubble was a real person, a spacecraft that was launched into space was given his name. He found that the galaxies that seem to be farthest from us are accelerating their distance from us, while the galaxies that are nearer to us are lagging.

Hubble's law is therefore that. If you study higher-level astronomy, you can do a mathematical operation known as Hubble's law. You can determine a mathematical relation that says that anything moves quicker the further distant it is from you.

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two charged particles 1.0 m apart exert an attractive electric force on each other with magnitude 104 n. the magnitudes of the charge on each particle are equal. the separation is then doubled to 2.0 m. what is the magnitude of the force at this distance?

Answers

The magnitude of the force at this distance of 2.0 m is 25.6 N.

The force between two charges q1 and q2 separated by a distance r is given by Coulomb's law:

F = k (q1 q2)/r^2

where k is the electrostatic constant (9 x 10^9 Nm^2/C^2).

In this problem, the distance is 1.0 m and the magnitude of the force is 104 N, so we can solve for the charge on each particle:

104 N = (9 x 10^9 Nm^2/C^2) (q1 q2) / 1.0 m^2

q1 q2 = 104 N / (9 x 10^9 Nm^2/C^2)

q1 q2 = 1.2 x 10^-7 C^2

Since the magnitudes of the charges are equal, q1 = q2 = q, so we can solve for q:

q^2 = 1.2 x 10^-7 C^2

q = 3.4 x 10^-4 C

Now that we know the charge on each particle, we can calculate the force when the separation is doubled to 2.0 m:

F = (9 x 10^9 Nm^2/C^2) (q1 q2) / (2.0 m)^2

F = (9 x 10^9 Nm^2/C^2) (3.4 x 10^-4 C)^2 / (2.0 m)^2

F = 25.6 N

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a reflecting telescope is built with a 10-cm-diameter mirror having a 1.00 m focal length. it is used with a 5× eyepiece. you may want to review (pages 1005 - 1007) .

Answers

A reflecting telescope is built with a 10-cm-diameter mirror having a 1.00 m focal length. it is used with a 5× eyepiece. F/10.

What is Magnification?

Magnification of the[tex]$M_{\text {tellicops }}=\frac{\text { Focallength of the objective }}{\text { focal length of the eyepiece }}$[/tex]

Focal length of the objective [tex]$=1.0 \mathrm{~m}=100 \mathrm{~cm}$[/tex]

For a magnifier, magnification [tex]$M=\frac{10}{\text { Focal length }}$[/tex]

Where the focal length must be in inches

Magnification of eyepiece [tex]$M=5 X$[/tex]

Focal length of the eyepiece[tex]$=\frac{10}{5}=2$ inches $=5.08 \mathrm{~cm}$[/tex]

There for magnification of the telescope

[tex]$$\begin{aligned}& M_{\text {telescope }}=\frac{100}{5.08} \\& M_{\text {telesccpe }}=19.68 \approx 20 \mathrm{X}\end{aligned}$$[/tex]

f number of the telescope[tex]$\mathrm{N}=\frac{f}{D}$[/tex]

f is the focal length of the objective[tex]$=1 \mathrm{~m}=100 \mathrm{~cm}$[/tex]

[tex]$\mathrm{D}$[/tex] is the diameter of the objective[tex]$=10 \mathrm{~cm}$[/tex]

[tex]N=\frac{100}{10}=f / 10$$[/tex]

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Which of the following is a classic challenge of emerging adulthood? O needing to financially support oneself O getting along with a spouse O taking on adult roles with ease O raising children

Answers

A typical problem of becoming an adult is getting along with our partner.

Adulthood is the stage of life when a person has fully developed physically and intellectually. Adulthood is typically assumed to start around 20 or 21 years old. Old age begins at the age of 60 and follows middle age, which starts around the age of 40.

The topic of adult development is briefly discussed after that. See human development and human behaviour for a comprehensive discussion.

Early and middle adulthood are physically characterised by slow, steady losses in body functioning, which quicken when old age is reached. Through the mid-20s, muscular mass continues to rise before progressively declining after that. Up until around age 30, the skeletal mass grows; after that, it starts to diminish, first in the core skeleton (the pelvis and spine), then in the peripheral skeleton.

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Help please like actually someone help me PLEASE

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The final speed of the motorcycle is: 67 m/sec

What is speed?

Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route. In other words, although velocity is a vector, speed is a scalar quantity.

Given that,

initial speed of the motorcycle, u=25 m/sec

Acceleration of the motorcycle, a = 7 m/sec²

According to the equation of motion,

v = u + at

v = 25 m/sec + (7m/sec²) × (6 sec)

v = 67 m/sec

Thus, final speed of the motorcycle is: 67 m/sec

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moons that show few craters probably

Answers

Moons that display few craters presumably. They all pass straight over the equator of the globe. Uranus's five biggest moons. have the closest magnetic field axis.

Which 4 moons are known?

There are many fascinating moons around the globe, but the Galilean satellites—Io, Europa, Ganymede, and Callisto—the first four moons identified beyond Earth—hold the most scientific curiosity.

Can Earth have Two moons?

Moon and Earth

The basic explanation is that Earth only has one moon, that we name “the moon”. It is the biggest and brightest object in the night sky, and the only solar system body except Earth that humanity have visited in our space travel activities.

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Use the formula for the law of universal gravitation to calculate the gravitational force between the large ball and the small ball.

Answers

The gravitational force between the large ball and the small ball, given their respective masses is 1.2×10¯¹³ N

How do I determine the gravitational force?

Gravitational force between two objects is given as shown below:

F = GM₁M₂ / r²

Where

F is the force of attraction G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apart

Using the above formula, we can obtain the gravitational force between the the large and small ball as follow:

Mass of small ball (M₁) = 5.0×10⁻³ KgMass of large ball (M₂) = 9.0×10⁻² KgDistance apart (r) = 0.5 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.0×10⁻³ × 9.0×10⁻²) / 0.5²

F = 1.2×10¯¹³ N

Thus, the gravitational force is 1.2×10¯¹³ N

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what is the far point in m of a person whose eyes have a relaxed power of 53.3 d? (assume a lens-to-retina distance of 2.00 cm.)

Answers

According to the question the far point in m of a person's eye is 0.30m.

what is the far point?

In terms of the space the eye can accommodate, this refers to the farthest distance from which an item can be positioned for its picture to be mirrored on the retina. It can also be thought of as the distance from the eyes at which pictures are clearly visible. The units are meters, or m.

Briefing:

P = relaxed power of the eye

F =far point

Given in the question:

The power of the eye is given as

P = 1/di + 1/do

P is power of the eye

di is the distance between eye lens and the image

d₀ is distance between eye lens and image

Given that,

P =53.3d

Take note that the power unit "d" stands for "dioptre," which means "per meter."

If the person can see clearly, the separation between the eye lenses and the picture (di), which is 2 cm, must be identical to that distance.

Thus, di = 2cm = 0.02m

P = 1/di + 1/d₀

1/d₀ = P — 1/di

1/d₀ = 53.3 — 1/0.02

1/d₀ = 53.3—50

1/d₀ = 3.3m

taking reciprocal

d₀ = 1/3.3

d₀ =0.3030m

Then, d₀ = 0.3030m

d₀≈ o.30m

The far point the person can see is 0.30m

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what wavelengths appear in the system's emission spectrum?

Answers

The possible wavelengths that appear In the emission spectrum of the system are [tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Given:

The quantum energy levels allowed In the system are:

[tex]$$\begin{aligned}& E_1=1.0 \mathrm{eV} \\& E_2=2.0 \mathrm{eV} \\& E_3=4.0 \mathrm{eV} \\& E_4=7.0 \mathrm{eV}\end{aligned}$$[/tex]

What is wavelength of the emission?

As the transition of electron takes from one energy level to another, there is an emission of particular wavelength from the transition. The relation between the wavelength of the emission and the energy of the energy level Is expressed as:

[tex]$$E_f-E_i=\frac{h c}{\lambda}$$[/tex]

Here, [tex]$E_f$[/tex] is the final energy level, [tex]$E_i$[/tex] is the Initlal energy level and [tex]$\lambda$[/tex] is the wavelength of emlsslon.

(1). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_2$[/tex] energy level:

[tex]$$\begin{aligned}E_2-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(2-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =1.244 \times 10^{-6} \mathrm{~m} \\& \approx 1200 \mathrm{~nm}\end{aligned}$$[/tex]

(2). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

(3). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-31}\right) \times\left(3 \times 10^8\right)}{(7-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.207 \times 10^{-6} \mathrm{~m} \\& \approx 210 \mathrm{~nm}\end{aligned}$$[/tex]

(4). Transition of electron from [tex]$E_2$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.621 \times 10^{-6} \mathrm{~m} \\& \approx 620 \mathrm{~nm}\end{aligned}$$[/tex]

(5). Transition of electron from[tex]$E_2$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_1-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.248 \times 10^{-6} \mathrm{~m} \\& \approx 250 \mathrm{~nm}\end{aligned}$$[/tex]

(6). Transition of electron from [tex]$E_3$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_3 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-4)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

Thus, The posslble wavelengths that appear in the emisslon spectrum of the system are[tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Complete question: The allowed energies of a quantum system are 1.0 ev, 2.0 ev, 4.0 ev, and 7.0 ev. what wavelengths appear in the system's emission spectrum

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A current flows through a circular coil of wire. How will the strength of the magnetic field change in the center of the coil if three turns of a radius three times smaller are made from this coil?

Answers

Answer:

bhai what is yhis? i dont understand

what does it mean to say that a beam of light is polarized? the beam has a magnetic field, but no electric field. the beam itself is charged, carrying either positive or negative charge. the direction of the beam's electric field alternates between two possibilities. the beam has an electric field, but no magnetic field.

Answers

Plane polarized light consists of waves that has magnetic field in which the direction of vibration is the same for all waves.

Polarization, in Physics, is defined as a phenomenon caused due to the wave nature of electromagnetic radiation.Sunlight travels through the vacuum to reach the Earth, which is an example of an electromagnetic wave. These waves are called electromagnetic waves because they form when an electric field interacts with a magnetic field.Light is the interaction of electric and magnetic fields travelling through space. The electric and magnetic vibrations of a light wave occur perpendicularly to each other. The electric field moves in one direction and the magnetic field in another ‘perpendicular to each other. So, we have one plane occupied by an electric field, another plane of the magnetic field perpendicular to it, and the direction of travel is perpendicular to both.

Plane polarized light consists of waves in which the direction of vibration is the same for all waves.The process of transforming unpolarized light into polarized light is known as polarization.

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a student pushes a 51.5 kilogram bookshelf across a smooth floor with a net force of 67 n. what is the approximate acceleration of the bookshelf?

Answers

The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

What is acceleration?

An item is said to be accelerated if there is a change in its velocity. The change in the velocity of an item could be an increment or decrement in speed or a change in the direction of motion. A few examples of acceleration are the falling of an orange, the earth orbiting around the sun, or when a car is stopped at the traffic lights. Through these examples, we can deem that when there is a change in the direction of a moving item or an increment or decrement in speed, acceleration occurs.

The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

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A 1,193 kg car moving at 27.6 m/s hits a stationary truck with a mass of 4,302 kg. If the two vehicles become stuck together in the collision, how fast do they move away from the point of impact?

use units and work out

Answers

The final momentum will be the sum of the initial momentum of the two vehicles. The final velocity of the combined mass will be 5.9 m/s.

What is collision?

Collision is a short range force exerted by an object on other object make them move either to the same side or opposite sides based on their mass.

Momentum of a moving body is the product of its mass and velocity. During a collision, the initial momentum will be equal to the final momentum.

The momentum of the car  = mass × velocity

                                             = 1193 Kg × 27.6 m/s

                                             = 32926 kg m/s

The initial momentum of the truck is zero because it was stationary.

The final momentum with the velocity v, of the combined mass is equal to the total initial momentum i.e. 32926 kg m/s.

32926 kg m/s =  (1193 Kg  + 4302 Kg) v

v = 32926 kg m/s /   (1193 Kg  + 4302 Kg)

  = 5.9 m/s.

Therefore, the final velocity of the vehicles when they stuck together is 5.9 m/s.

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a balloon originally had a volume of 0.439 l at 44°c and a pressure of 729 torr. to what temperature must the balloon be cooled to reduce its volume to 378 ml if the pressure remained constant?

Answers

According to Charles' Law, the V/T = k, V1/T1=V2/T2, in case v1= 4.39, T1= 44C=317 K (being O C= 273 K) V2=3.78 L T2=?. Charles law, 4.39L/317K = 3.78L/T2. T2x=4.39L/317K = 3.78 L. T2= 3.78L/4.39/317k, T2=273K=0 C

How do you determine a balloon's new volume?

Place the bucket into the larger container, fill it with water, then submerge the inflated balloon completely. After that, remove the bucket, pour the water from the larger container into the measuring container, and measure the volume of the water.

What are the two-volume calculation formulas?

The basic formula for volume is length, breadth, and height, as opposed to length, width, and height for the area of a rectangular shape. The calculation is unaffected by how you refer to the various dimensions; for instance, you can use "depth" instead of "height."

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gravity on the surface of the moon is only 1 6 as strong as gravity on the earth. what is the weight of a 31 kg object on the earth? the acceleration of gravity is 10 m/s2 . answer in units of n.

Answers

The weight of a 31 kg object on the earth is 304.017 newtons.

Briefly:-

Weight equals (mass of the thing) x (acceleration of gravity in that place).

— The acceleration of gravity on Earth is approximately 9.807 m/s2.

31 kilograms of mass has a weight of (31 kg) x (9.807 m/s2) = 304.017 newtons.

— On the Moon, the gravitational acceleration is approximately 1.623 m/s2.

The identical mass of 31 kg has a weight of (31 kg) x (1.623 m/s2) = 5.313 newtons.

Why is lunar gravity only one-sixth that of Earth's?

The Moon is significantly lighter in mass than the Earth. The Moon is not just smaller than the Earth, but it is also only around 60% as dense. As a result, a person weighs less on the Moon than they do on Earth due to the significantly lower gravitational attraction there.

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a string is compressed 1.0 cm. how far must you compress a spring with twice the spring constant to store the same amoutn ofe nergy

Answers

The spring constant for storing the same amount of energy is given as x = 0.707 cm.

What does a string mean?

A string is a computer data type that is similar to an integer and a floating point unit, except it represents text instead of numbers. It is made up of a series of symbols that may also include spaces and numerals.

briefing :

E = /kx2 is the energy that has been stored.

E1 = E2

1/2 k(1.0)² = 1/2 (2k)x²

x^2 = 1/2 (1.0)²

x = 1.0/√2 cm

x = 0.707 cm

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after protecting the goal, a 90 kg goalie celebrates by leaping 110 cm off the ground. how much work was done in the celebration?

Answers

A 90 kg goaltender celebrate by jumping 110 cm into the air after defending the goal. 970.20 J was work done throughout the celebration.

What is work done?

The sum of the displacement as well as the components of the force applied of the object in the displacement direction is the work done by a force. The body moves with certain acceleration when we push a blocks with certain force, and work is completed.

Briefing:

m = mass of the body = 90 kg

g = gravitational force

h = height = 110cm

Formula -

work done = mgh

                   = 90 × 9.8 × 110

                   = 970.20 J

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g water is pumped a vertical distance of 38 m at the rate of 25 1/s. how much work is done in 2.5 min?

Answers

16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

What do you understand by work done?

The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force. Work is accomplished when we push a block with some force; the body moves more rapidly.

What is the distance?

Distance is the sum of an object's movements, regardless of direction. The distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

Calculation:

Given,

Distance= 38m

Rate = 25mL/s = 0.25L/s

To find work done in 2.5mins Or 150seconds

Potential energy (P.E) = (mgh) /t

P.E = (mgh) /t

     = (0.25 Ls-¹ * 9.81 * 38m) / 1sec

     = 93.195 Watts

For 1 sec 93.195 watt is used

For 2.5mins Or 180 seconds = 93.195 × 180= 16775 watts or 16.7kW power is used for the work done.

Hence, 16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

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a player catches a ball. consider the action force to be the impact of the ball against the player's glove. what is the reaction to this force?

Answers

When then the ball is stopped by the hand due to reaction force by the hand which is equal in magnitude but is opposite in direction to the force applied by the ball.

According to Newton's third law of motion, the reaction would be equal and opposite to the person pushing on the ball, so the ball pushing on the person.

When a ball is thrown on the floor or a wall, it bounces back. The force exerted by the ball on the ground or wall is the action force. The force that the ground or wall exerts on the ball in response to the action force causes the ball to jump or bounce back.

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a thin, circular hoop is released at the top of an incline that is 8:0 mlong and makes an angle of 370 above the horizontal. what is its speed at the bottom of the incline? assume it rolls without slipping. a. 5:5 m

Answers

The speed at the bottom of the incline is  6.87 m per second.

What is conservation of energy?

The conservation of the energy is a fundamentally law of physics, chemistry stating that the total of the energy of an isolated by the system is constant despite internally changes. It is mostly common expressed as “energy can neither to be created nor destroyed”, and it is the basis of the first-ever law of the thermodynamics.

As per the given question

The length of the inclined plane L= 8.00m

angle of inclination is = 37°

Height of the inclined plane h= L sin ø

     (8.00m) sin 37°

     =4.814 m

Let's take m= mass of hoop

Let's take r=radius of hoop

Let's v be the velocity of the hoop bottom to the inclined plane.

Now we can apply conservation of energy at the top of the inclined plane  and at to the bottom of the inclined plane.

mgh = ¹/₂ mv²

mgh = ¹/₂ mv² + ¹/₂ Iω²

Where, I = moment of inertia

ω = angular velocity

I = L/ω

mgh = ¹/₂ mv² + ¹/₂ (L/ω)ω²

mgh = ¹/₂ mv² + ¹/₂ Lω

mgh = ¹/₂ mv² + ¹/₂ mvrω

ω = vr

mgh = ¹/₂ mv² + ¹/₂ mvrvr

gh = ¹/₂ v² + ¹/₂ (vr)²

gh = ¹/₂v² (1 + r²)

v=gh

v=√(9.8m/s^2)(4.814m)

v=6.87 m/s

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