Astronauts measure their mass by measuring the period of oscillation when sitting in a chair connected to a spring. The Body Mass Measurement Device on Skylab, a 1970s space station, had a spring constant of 1.06 N/m. The empty chair oscillated with a period of 0.872 s.
The equation for the period of oscillation of a spring-mass system is given as,
T = 2π sqrt(m/k)Here, T = 1.5 s; k = 1.06 N/m;
Substitute the given values in the above equation and solve for m.
m = (T²k)/(4π²) = (1.5² × 1.06)/(4π²) ≈ 0.051 kg
Therefore, the mass of an astronaut who makes the Body Mass Measurement Device oscillate with a period of 1.500 s is approximately 0.051 kg.
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High-intensity focused ultrasound (HIFU) is one treatment for certain types of cancer. During the procedure, a narrow beam of high-intensity ultrasound is focused on the tumor, raising its temperature to nearly 90∘∘C and killing it. A range of frequencies and intensities can be used, but in one treatment a beam of frequency 4.0 MHz produced an intensity of 1500 W/cm2. The energy was delivered in short pulses for a total time of 2.5 s over an area measuring 1.6 mm by 6.4 mm. The speed of sound in the soft tissue was 1540 m/s, and the density of that tissue was 1058 kg/m3. What was the wavelength of the ultrasound beam? (Express your answer to two significant figures.) How much energy was delivered to the tissue during the 2.5-s treatment? (Express your answer to two significant figures.) ) What was the maximum displacement of the molecules in the tissue as the beam passed through? (Express your answer to two significant figures.)
The wavelength of the ultrasound beam: We know that,Speed of sound, v = 1540 m/s
Frequency, f = 4.0 MHz = 4.0 × 10 s
The wavelength of the ultrasound beam can be given by the formula;
wavelength, λ = v/fλ = 1540/4.0 × 106λ
= 3.9 × 10-4 m
Energy delivered to the tissue during the 2.5-s treatment: Given; Intensity, I = 1500 W/cmArea,
A = 1.6 mm × 6.4 mm
= 1.6 × 10 m × 6.4 × 10 m
= 1.024 × 10 mTime,
t = 2.5 s
Energy delivered is given by the formula; Energy = Power × Time
Energy = I × A × t
Energy = 1500 W/cm × 1.024 × 10 m × 2.5 s
Energy = 3.84 × 10 J
Maximum displacement of the molecules in the tissue as the beam passed through:Given;
Intensity, I = 1500 W/cm
Speed of sound, v = 1540 m/s
Density, ρ = 1058 kg/m
The maximum displacement of the molecules can be given by the formula; Maximum displacement, d = (2 × I/ρv)
d = (2 × 1500 W/cm/1058 kg/m × 1540 m/s)
d = 7.53 × 10 m
Therefore, the wavelength of the ultrasound beam is 3.9 × 10m, the energy delivered to the tissue during the 2.5-s treatment is 3.84 × 10 J and the maximum displacement of the molecules in the tissue as the beam passed through is 7.53 × 10 m.
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Example: Calculate the acceleration of an object that is initially travelling at 32 m/s [E] and after 12 s has a new velocity of 8 m/s [E].
We can calculate the change in velocity by subtracting the initial velocity from the final velocity. The time interval is also given as 12 seconds. Therefore, we can calculate the acceleration using the formula above:
acceleration= (8 m/s [E] - 32 m/s [E])/12 s
acceleration = -2 m/s² [E] (Note that the negative sign indicates that the object is decelerating or slowing down.)
The acceleration of the object is -2 m/s² [E]. This means that the object is slowing down at a rate of 2 meters per second squared in the East direction.
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QUESTION 2 A machinist turns the power on to a grinding wheel, at rest, at time t = 0 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 42 rad/s. The wheel is run at that angular velocity for 32 s and then power is shut off. The wheel slows down uniformly at 2.2 rad's until the wheel stops. In this situation, the total number of revolutions made by the wheel is closest to: o 210 250 310 © 280 410 QUESTION 2 A 0.24 kg blob of clay is thrown at a wall with an initial velocity of 20 m/s. If the clay comes to a stop in 91 ms, what is the average force experienced by the clay? 45 N 33 N 53 N 64 N QUESTION 1 At time t = 0 s, a wheel has an angular displacement of zero radians and an angular velocity of +26 rad/s. The wheel has a constant acceleration of 0.43 rad's2 In this situation, the time t (after t=0 s), at which the kinetic energy of the wheel is twice the initial value, is closest to: O 150 s O 60 s 130 s O 85 s O 110 s
The average force experienced by the clay is given by the formula,F = maWhere,a = acceleration = Change in velocity/time taken= [tex](v-u)/t[/tex]= (0 - 20)/0.091= -220.88 m/s^2The time t taken by the wheel to reach final angular displacement is approximately 60.465 seconds.
We know that force is a vector quantity and direction of force is opposite to that of the direction of motion of the clay. Thus, force experienced by the clay is a positive quantity.Force, F = ma= 0.24 × 220.88= [tex]52.77 N≈ 53[/tex]NTherefore, the average force experienced by the clay is 53 N.Question 1Initial angular displacement of the wheel, [tex]θ1 = 0[/tex] radiansFinal angular displacement of the wheel
we can write,Final angular velocity,[tex]ω2^2[/tex]= 2 × (Initial kinetic energy)/(Moment of inertia of the wheel)= 2 × [1/2 × Moment of inertia of the wheel × (Initial angular velocity)^2]/(Moment of inertia of the wheel)= (Initial angular velocity)^[tex]2ω2[/tex] = Initial angular velocity= 26 rad/sUsing the third equation of motion,[tex]ω2 = ω1 + αtω2 - ω1[/tex]= [tex]αt26 - 0.43t = 0t ≈ 60.465 s[/tex] The time t taken by the wheel to reach final angular displacement is approximately 60.465 seconds.
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Determine the height h of mercury in the multifluid manometer
considering the data shown and also that the oil (aceite) has a
relative density of 0.8.
The density of water (agua) is 1000 kg/m3 and th
A multi-fluid manometer is shown below:
Multi-Fluid Manometer The relative density of oil is given as 0.8. Therefore, its specific gravity is given as 0.8 × 9.81 m/s² = 7.848 N/kg.
The density of water is 1000 kg/m³.The height of mercury is given as 750 mm.
The pressure difference between the bottom and top of the manometer is given as:
ρ1 g h1 = ρ2 g h2 + ρ3 g h3
Therefore, ρ1 g h1 = ρ2 g h2 + ρ3 g h3 = 7.848 N/kg × h2 + 1000 kg/m³ × 9.81 m/s² × h3.
From the diagram, we know that h2 + h3 = 750 mm.
Converting 750 mm to meters, we get 0.75 m.
Substituting this value in the equation gives:
ρ1 g h1 = 7.848 N/kg × h2 + 1000 kg/m³ × 9.81 m/s² × (0.75 - h2)ρ1 g h1
= 7.848h2 + 7357.5 - 9810h2ρ1 g h1
= -1734.652h2 + 7357.5ρ1 g h1 + 1734.652h2
= 7357.5h2 = (7357.5 - ρ1 g h1)/1734.652
Substituting the given value of ρ1 = 13.6 × 10³ kg/m³ and g = 9.81 m/s² and the height of mercury h1 = 175 mm = 0.175 m in the equation above, we get:
h2 = (7357.5 - 13.6 × 10³ × 9.81 × 0.175)/(1734.652) = -0.2973 m
As h cannot be negative, this value is invalid and can be ignored. Since the height cannot be negative, the height of oil h3 is: h3 = 0.75 - h2 = 0.75 - (-0.2973) = 1.0473 m
Therefore, the height h of mercury in the multi-fluid manometer is approximately 0.175 m.
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Question 20: The synchronous reactance of a cylindrical rotor synchronous motor is \( 0.8 \) p.u. (per unit \( = \) p.u.) and is kept at this value, at voltage from an ideal source, without being adju
Cylindrical rotor synchronous motor:The synchronous reactance of a cylindrical rotor synchronous motor is 0.8 p.u. This value is constant as long as the ideal voltage source is maintained and not changed. This means that the motor impedance at the synchronous frequency is solely due to this reactance.
The armature winding is made of copper wire and is wound on a laminated core, just like a transformer. The armature winding is placed in the stator in slots that are punched into the laminated core. The rotor winding, on the other hand, is an electromagnetic coil that is excited by direct current.The rotor is cylindrical, as the name implies, and has no magnetic poles, unlike a wound rotor motor.
The cylindrical rotor motor's magnetic field is generated by electromagnets mounted on the rotor's surface. These electromagnets are also referred to as salient poles. The motor's magnetic field rotates as the rotor rotates at the same speed as the magnetic field in the stator windings. The motor will come to rest when the rotor is in line with a stator winding, with the magnetic field of the rotor in line with the magnetic field of the stator winding.The motor's output frequency is equal to the synchronous frequency in a cylindrical rotor synchronous motor. Because the rotor and stator magnetic fields rotate at the same speed, there is no relative movement between the rotor and stator magnetic fields. As a result, there is no emf induced in the rotor's conductors.
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describe the principle difference between real-time and non real-
time behaviour of plc
PLCs can operate in two modes: real-time and non-real-time. The principle difference between real-time and non-real-time behaviour of PLCs is that PLC in real-time mode must execute operations as quickly and predictably as possible.Real-time PLCs have a quicker response time than non-real-time PLCs.
When a program is executed in real-time, the PLC must complete each instruction within a predetermined time frame to ensure that critical processes are completed correctly and without error in a timely manner. A real-time system's performance is measured by how quickly it can respond to a specific event or signal.
Non-real-time PLCs do not operate in this manner and execute instructions without any time restrictions or deadlines. Non-real-time PLCs are intended for applications that do not require immediate or rapid responses and where timing is not a critical factor. The system's performance isn't measured by how quickly it can react to an event or signal, but by how well it can execute a task without taking into account the time required for completion.
In conclusion, the primary distinction between real-time and non-real-time behaviour of PLCs is the responsiveness of the system. The PLCs in real-time mode respond quickly and predictably to specific events or signals, while those in non-real-time mode are intended for applications where timing is not critical and execute tasks at a pace that is not constrained by time.
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Required information Tina is going to make iced tea by first brewing hot tea, then adding ice until the tea cools. Ice, at a temperature of -10.0°C, should be added to a 2.10 x 10-4 m3 glass of tea at 95.0°C to cool the tea to 10.0°C. The glass has a mass of 0.350 kg and the specific heat of the glass is 0.837 kJ/(kg-K). Specific heat capacity (15.0°C) of water is 4.186 kJ/(kg-K) and heat of fusion of water is 333.7 kJ/kg. Specific heat capacity of ice is 2.10 kJ/(kg-K). Find the mass of the ice required to cool the tea to 10.0°C, without ignoring the temperature change of the glass. 188 g
The mass of the ice required to cool the tea to 10.0°C, considering the temperature change of the glass, is approximately 173 g.
To find the mass of the ice required, we need to consider the heat transferred between the tea, the glass, and the ice.
First, let's calculate the heat transfer between the tea and the glass:
q1 = mcΔT1
q1 = (0.350 kg)(0.837 kJ/kg-K)(10.0°C - 95.0°C)
q1 = -80.32 kJ
Next, let's calculate the heat transfer between the ice and the glass:
q2 = mcΔT2
q2 = (0.350 kg)(0.837 kJ/kg-K)(10.0°C - (-10.0°C))
q2 = 23.38 kJ
Now, let's calculate the heat transferred during the phase change of the ice:
q3 = mhf
q3 = (m)(333.7 kJ/kg)
q3 = 333.7m kJ
Since the total heat transferred must be zero (assuming no heat is lost to the surroundings), we can set up the equation:
q1 + q2 + q3 = 0
Substituting the calculated values:
-80.32 kJ + 23.38 kJ + 333.7m kJ = 0
Simplifying the equation:
333.7m = 57.94
m ≈ 0.173 kg
Converting to grams:
mass of ice = 0.173 kg * 1000 g/kg
mass of ice ≈ 173 g
Therefore, the mass of the ice required to cool the tea to 10.0°C, considering the temperature change of the glass, is approximately 173 g.
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Write down a report about the heat losses of
collector
A solar collector is a device that is designed to collect solar radiation and convert it into heat energy. Heat losses can occur in the collector due to a variety of factors such as convection, radiation, and conduction. The heat loss is a significant factor that can impact the overall efficiency of the solar collector.
Convection heat losses occur due to the transfer of heat energy from the collector surface to the air or fluid that surrounds it. In order to minimize convection heat losses, the collector is typically designed with a glazing material that reduces the flow of air across the surface of the collector. This can be achieved through the use of a double-glazed or vacuum-sealed panel.
Radiation heat losses occur due to the emission of thermal radiation from the surface of the collector. This can be minimized through the use of materials that have low emissivity. These materials reflect a greater amount of solar radiation and reduce the amount of thermal radiation that is emitted from the surface of the collector.
Conduction heat losses occur due to the transfer of heat energy from the collector surface to the surrounding environment. This can be minimized through the use of insulation materials that prevent the transfer of heat energy.
Overall, the design and construction of the solar collector play a significant role in minimizing heat losses and increasing efficiency. By reducing heat losses, the collector can more effectively convert solar radiation into heat energy, which can then be used for a variety of applications such as heating water or generating electricity.
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An astronomer takes a spectrum of an object and see dark portions of the spectrum superimposed on a bright continuum. What kind of spectrum is this? a) Emission b) Blackbody c) Absorption d) Emission
The spectrum described, with dark portions superimposed on a bright continuum, is characteristic of an absorption spectrum. The correct answer is option (c).
In an absorption spectrum, the object being observed absorbs specific wavelengths of light, resulting in dark or absorption lines superimposed on a continuous or bright background. These dark lines indicate the wavelengths of light that have been absorbed by the object's outer layers or intervening medium. When white light passes through a cooler gas or a cooler object's outer layers, specific elements or compounds present in the object's atmosphere or composition absorb certain wavelengths of light, creating dark absorption lines.
These lines correspond to the specific energy transitions of the absorbing atoms or molecules. Absorption spectra provide valuable information about the composition and physical properties of celestial objects, such as stars, galaxies, and interstellar gas clouds, helping astronomers study their elemental abundances, temperature, and motion. Hence, option (c) is the correct answer.
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3) The Great Pyramid has a mass of 7 x 10⁹ kg and a center of mass 36.5 m above the surrounding desert. a) How much gravitational potential energy relative to the surrounding ground is stored in the pyramid? b) How does this energy compare with the daily food intake of a person? Express as the number of days it would take for a single person to complete the pyramid.
a) The gravitational potential energy stored in the Great Pyramid relative to the surrounding ground is approximately 2.64 x [tex]10^1^2[/tex] joules.
b) This energy is equivalent to the daily food intake of approximately 2.93 million people, which would take a single person around 7,214 years to consume.
Gravitational potential energy can be calculated using the formula: PE = mgh, where PE represents potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical distance. Given that the mass of the Great Pyramid is 7 x [tex]10^9[/tex] kg and its center of mass is 36.5 m above the desert, we can calculate the potential energy as follows: PE = (7 x [tex]10^9[/tex] kg) x (9.8 [tex]m/s^2)[/tex] x (36.5 m) = 2.64 x [tex]10^1^2[/tex] joules.To compare this energy with the daily food intake of a person, we need to determine the energy value of the food consumed. On average, an individual's daily food intake is around 2,000 kilocalories, which is equivalent to approximately 8.37 x [tex]10^6[/tex]joules.Dividing the gravitational potential energy of the pyramid (2.64 x [tex]10^1^2[/tex] joules) by the energy value of daily food intake, we find that it would take around 3.15 x [tex]10^5[/tex] days, or approximately 7,214 years, for a single person to consume the same amount of energy.Learn more about Gravitational potential energy
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in accordance with Newton's Universal The force of gravity is directly proportional to Law of Gravitation. the distance separating the two objects. the product of the masses of the two objects. the distance separating the two objects squared. the sum of the masses of the two objects.
In accordance with Newton's Law of Universal Gravitation, the force of gravity between two objects is directly proportional to product of the masses and inverse square of the distance separating two objects.
The product of the masses of the two objects: The force of gravity is directly proportional to the product of the masses of the two objects. In other words, if the masses of the objects increase, the gravitational force between them increases proportionally.
The inverse square of the distance separating the two objects: The force of gravity is inversely proportional to the square of the distance between the two objects. This means that as the distance between the objects increases, the gravitational force decreases, and vice versa.
So, the correct statement would be: The force of gravity is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance separating the two objects.
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A plain area (5 m by 5 m) is submerzed in water in such a way
that its centroid of area is at a depth of 41 from water surface.
Calculate the total force (in Newton) acting on the plan area.
Given, Length of the plain area = 5 m Breadth of the plain area = 5 m Centroid of area is at a depth of 41 m from water surface. The formula to calculate the total force acting on the plane area is given by:
Force = ρghA Where,
ρ = density of water
g = acceleration due to gravity
h = depth of centroid of plane area from water surface
A = area of plane area
The first step is to calculate the area of the plane area.
Area of plane area
= Length * Breadth
= 5 * 5
= 25 m²
Given, the depth of the centroid of the plane area from the water surface = 41 m The total force acting on the plane area can be calculated as follows:
Force = ρghA
= 1000 * 9.8 * 41 * 25
= 10,082,500 N
The total force acting on the plane area is 10,082,500 N, which is calculated using the formula Force = ρgh
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a) A particle moves along the x-axis so that the position s is given as a function of the time t at
s (t) = 10t2, t ≥ 0.
Position s and time t have denominations, meters and seconds, respectively.
i) What is the average velocity of the particle between t = 0s and t = 2s?
ii) What is the momentary velocity of the particle at time t = 1s?
b) (continuation of task a)
Assume that the particle has mass m = 2kg
How much net force (resultant force) acts on the particle at time t = 2s
c) You are on frictionless horizontal ice and standing still at a point A. Another point, B, is several meters away and you want to get there.
i) Can you manage to reach point B if you only take a strong enough rate?
Justify the answer briefly (the justification should be based on Newton's laws).
ii) Then assume that you take off your hat and stand on it when you make a bet.
Can you now manage to get to point B (without a hat)? Justify the answer briefly.
Average velocity of the particle between t = 0s and t = 2s is:Velocity = ∆distance / ∆timeTherefore, the average velocity is (s(2s) - s(0s)) / (2s - 0s) = (40m - 0m) / 2s = 20m/sii) Momentary velocity of the particle at time t = 1s is:v = ds/dtTherefore, the momentary velocity is v(1s) = ds/dt (1s) = 20t(1s) = 20m/sb).
Given that m = 2kg, we are required to calculate the net force (resultant force) acting on the particle at time t = 2s.We know that:F = m * awhere F is force, m is mass and a is acceleration of the particle. The acceleration is the second derivative of the position, which is
a = d2s/dt2.
We have:s(t) = 10t2∴ v(t) = ds/dt = 20t∴ a(t) = dv/dt = 20m/s2For t = 2s, the acceleration a(2s) = 20m/s2.
Therefore, the net force is
F = m * a = 2kg * 20m/s2 = 40 N
c) The first law of Newton states that if no external force is applied on a body, it will remain at rest or continue to move at a constant velocity in a straight line. The second law of Newton states that the net force acting on an object is proportional to the rate of change of its linear momentum. These laws can be used to answer the following:If you are on frictionless horizontal ice and standing still at a point A, and another point B is several meters away and you want to get there, can you manage to reach point B if you only take a strong enough rate?Justify the answer briefly (the justification should be based on Newton's laws).Yes, you can manage to reach point B if you only take a strong enough rate.
When you take a step on the ice, your feet push the ice backwards. As a result, the ice pushes your feet forwards. This reaction force allows you to move forwards. Since there is no external force on you, you will move at a constant velocity in a straight line until you reach point B.ii) Now assume that you take off your hat and stand on it when you make a bet. Can you now manage to get to point B (without a hat)? Justify the answer briefly.No, you cannot manage to get to point B without a hat. By taking off your hat and standing on it, you reduce your mass and increase your acceleration.
According to the second law of Newton, the net force acting on an object is proportional to the rate of change of its linear momentum. Since your mass has decreased, the force required to move you has decreased. Therefore, to maintain the same acceleration, you need to apply a smaller force. However, as there is no external force to propel you forward, the force of your feet pushing backwards will also be reduced. This means that your acceleration and hence velocity will decrease, and you will not be able to reach point B.
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L1 = L2 = L3= 1*10^-3 mm
W1 = W2 = 10^-3 mm
W3 = ?
For all the mosfets ->
Vt = 1V
kn' = 200um/V^2
a)
Assume that the transistor Q1 will be biased with a constant
current of 2mA thanks to the curre
In the circuit shown, all MOSFETs have a threshold voltage of 1V and a transconductance parameter (k_n') of 200 μA/V². L1 = L2 = L3 = 1 × 10⁻³ mm,
W1 = W2 = 10⁻³ mm, and W3 = ?
are given. A constant current of 2 mA will be applied to transistor Q1 thanks to the current source.I_D is defined as the drain current.
By setting the transistor in the saturation region, we can calculate the value of V_GS, which is as follows:
V_{GS} = V_{DS} = V_{DD} = 10 V
For all transistors, we have:
V_{ov} = V_{GS} - V_t = 9V
For all transistors, we have:
\begin{aligned}
I_{D} & =
\frac{1}{2}k_n^{\prime}(W/L)(V_{ov})^{2}
\\2 × 10^{-3} & =
\frac{1}{2} × 200 × 10^{-6} ×
\frac{W_1}{L_1} × (9)^{2} \\
W_1 & = 5.432 × 10^{-3} mm
\\W_1 & = W_2 = W_3
\end{aligned}
Therefore, W3 = 5.432 × 10⁻³ mm. This is the solution for the given problem.
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Two point charges q
1
and q
2
are 3.25 m apart, and their total charge is 20μC. Note that you may need to solve a quadratic equation to reach your answer. (a) If the force of repulsion between them is 0.077 N, what are the two charges ( in μC) ? smaller value ∝μC largér value \& μC (b) If one charge attracts the other with a force of 0.365 N, what are the two charges (in μC )? srrâaller value μC larger value xμC
If the force of repulsion between them is 0.077 N the two charges are q1 ≈ 3.87 μC and q2 ≈ 16.13 μC. If one charge attracts the other with a force of 0.365 N, the two charges are 4.44 μC and 24.44 μC respectively.
(a) Let q1 and q2 be the magnitudes of the charges, with q1 < q2. Given that the charges are 3.25 m apart and their total charge is 20 μC. Then we have
q1 + q2 = 20 -----------(1)
Also, the force of repulsion F1 between the charges is 0.077 N.
Then using Coulomb's Law,
F1 = k * q1 * q2 / r²0.077
= (9 * 10^9) * q1 * q2 / (3.25)²
where k = Coulomb's constant.
Squaring equation (1) above,
q1² + 2q1q2 + q2² = 400 -----------(2)
Also, q1q2 = (0.077 * 3.25) / (9 * 10^9)q1q2 = 2.79375 * 10^-11
Substituting q2 = 20 - q1 into the above equation and solving the resulting quadratic equation gives us q1 ≈ 3.87 μC and q2 ≈ 16.13 μC.
(b) Since one charge attracts the other, the charges must have opposite signs. Let q1 and q2 be the magnitudes of the charges, with q1 < q2. Then we have
q2 - q1 = 20 ------------(3)
Also, the force of attraction F2 between the charges is 0.365 N.
Then using Coulomb's Law,
F2 = k * q1 * q2 / r²0.365 = (9 * 10^9) * q1 * q2 / (3.25)²
Substituting q2 = q1 + 20 into the above equation and solving the resulting quadratic equation gives us q1 ≈ 4.44 μC and q2 ≈ 24.44 μC. Therefore, the smaller and larger values of q for part
(a) are 3.87 μC and 16.13 μC respectively, while those for part (b) are 4.44 μC and 24.44 μC respectively.
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D 1 pts Question 1 If the element with atomic number 52 and atomic mass 209 decays by beta plus emission. What is the atomic number of the decay product? 51 1 pts Question 2 If the element with atomic number 77 and atomic mass 190 decays by alpha emission. What is the atomic number of the decay product?
2) The atomic number of the decay product is 75.
Question 1:
If an element with atomic number 52 and atomic mass 209 undergoes beta plus (β+) emission, it means that a proton in the nucleus is converted into a neutron, resulting in the emission of a positron (β+) and a neutrino.
During beta plus decay, the atomic number decreases by 1 because a proton is converted into a neutron. Therefore, the atomic number of the decay product will be 52 - 1 = 51.
So, the answer to Question 1 is: The atomic number of the decay product is 51.
Question 2:
If an element with atomic number 77 and atomic mass 190 undergoes alpha (α) emission, it means that the nucleus emits an alpha particle, which consists of two protons and two neutrons.
During alpha decay, the atomic number decreases by 2 because an alpha particle, which contains two protons, is emitted. Therefore, the atomic number of the decay product will be 77 - 2 = 75.
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The 1st thermodynamic identity in terms of Gibbs Free energy is: dG = -SDT + VIP + udN Which of the following is a true statement about the chemical potential? For dT = dN = 0, V For dT = dP = 0, = - a O For dT = dN = 0, u = - 음 For dT = dN = 0, =
For dT = dP = 0, the chemical potential (u) equals zero.
The given expression dG = -SDT + VIP + udN represents the first thermodynamic identity in terms of Gibbs Free energy, where dG represents the change in Gibbs Free energy, S is the entropy, T is the temperature, V is the volume, P is the pressure, u is the chemical potential, and N is the number of particles.
To find the true statement about the chemical potential, we need to consider the values of dT and dN in the equation. In the options provided, we are given different combinations of values for dT and dN while keeping other variables constant.
When dT = dP = 0, it means there is no change in temperature (dT = 0) and no change in pressure (dP = 0). In this case, we are only considering changes in volume (dV) and the number of particles (dN).
The chemical potential (u) is a measure of the energy required to add an additional particle to a system while keeping the temperature, pressure, and other variables constant. When dT = dP = 0, there is no change in temperature or pressure, so the chemical potential becomes zero (u = 0).
Therefore, the true statement about the chemical potential is that for dT = dP = 0, the chemical potential (u) equals zero.
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#1 Converting units Convert the following physical quantities! a) 0.007605 psi into SI units with scientific and engineering notation b) What is your room size in m²? Convert it into square inches c) Check the performance of your favorite car (if you do not have a favorite, take an arbitrary)! What is the consumption in liters per 100 km? Convert this unit into miles per gallon. d) 1567.2 µm³ into scientific and engineering notation e) 2500 kWh into J using scientific and engineering notation
Converting 0.007605 psi into SI units with scientific and engineering notationPounds per square inch (psi) is the unit of pressure.1 psi = 6.89476 kPaUsing this conversion factor,0.007605 psi= 0.007605 × 6.89476= 0.052397 kPa= 5.2397 × 10³ Pa (scientific notation)= 52.397 × 10² Pa (engineering notation)b)
Converting room size from m² to square inchesSince we know that 1 square meter (m²) = 1550 square inches (in²)
Therefore,Room size = 25 m² = 25 × 1550= 38750 square inches (in²)c) Converting car's fuel consumption from liters per 100 km to miles per gallonTo convert liters per 100 km to miles per gallon, we need the following conversion factors:
1 km = 0.621371192 miles
1 L = 0.264172052
gallonsUsing these conversion factors,The fuel consumption of the car in liters per 100 km is 8 L/100 km.
= 0.08 L/km.
0.007605 psi= 5.2397 × 10³
Pa (scientific notation)= 52.397 × 10²
Pa (engineering notation)b) 25 m² = 38750 square inches (in²)
c) 8 L/100 km= 1.288 × 10⁻³ m
pg (scientific notation)= 1.288 × 10⁻³ m
pg (engineering notation)d) 1567.2 [tex]µm³[/tex] = 1.5672 × 10⁻³ mm³ (scientific notation)= 0.0015672 mm³ (engineering notation)e) 2500 k
Wh = 9 × 10⁹ J (scientific notation)= 9.0 × 10⁹ J (engineering notation)
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Please answer two of the following questions. Remember,
completeness and accuracy are important and will be used to
determine you grade! Make sure to read the rubric!!
Describe neutron stars, includi
Neutron stars are so dense that a sugar-cube-sized piece of neutron star matter would weigh around 100 million tonnes. Pulsars are a type of neutron star that emits electromagnetic radiation. They have a radius of about 10 km, but their mass is around 1.4 times that of the Sun. When neutron stars rotate, they emit radiation that is visible in the radio frequency range. Pulsars spin rapidly, emitting radiation in a regular pattern that can be detected and studied.
Relativity and its unusual properties. Time and space are relative and depend on the speed of the observer. Some of the unusual properties of relativity include time dilation, length contraction, and mass-energy equivalence.Time dilation occurs when time appears to pass more slowly for objects in motion than for objects at rest. Length contraction means that an object appears to be shorter when it is moving than when it is at rest. Mass-energy equivalence is the idea that mass and energy are equivalent, and that matter can be converted into energy.
Three interesting things about black holes
Black holes are regions of space where gravity is so strong that nothing, not even light, can escape.Black holes can form when massive stars run out of fuel and collapse under the force of their own gravity.Black holes can have different sizes and properties, depending on their mass and spin.They can be classified as stellar, intermediate, or supermassive black holes.
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Question 1. According to Fleming's Left Hand Rule, the direction of current is denoted by the finger. (2) a) Forefinger b) Thumb c) Center Finger d) None of these Question 2. The inductance of a coil
1) The correct option is C.
According to Fleming's left-hand rule, the forefinger points in the direction of the magnetic field, the center finger points in the direction of the current, and the thumb points in the direction of the force acting on the conductor carrying the current. Therefore, the direction of the current is denoted by the center finger.
Hence, the correct answer is option c) Center Finger.
2)
The inductance of a coil refers to its property of inducing an electromotive force (EMF) in itself when the current flowing through it changes. The unit of inductance is henry, symbol H. The inductance of a coil can be calculated using the following formula: L = Φ/I
Where, L is the inductance of the coil in henries,Φ is the magnetic flux in weber, and I is the current flowing in the coil in amperes.
Therefore, the formula to calculate the inductance of a coil is L = Φ/I, where L is the inductance in henries, Φ is the magnetic flux in weber, and I is the current flowing in the coil in amperes.
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Question 7
When the absolute pressure inside a liquid is measured to be 92 kPa, what is the gauge pressure, in the unit of kPa, at the same point in the liquid? Use Patm = 101 kPa for the atmospheric pressure. If the gauge pressure is negative, use the "-" (negative) sign for your answer.
Question 8
A container contains a liquid with density p = 1.2 g/cm³. The pressure at the surface of the liquid is Psurface = 0.25 kPa. What is the pressure, in the unit of Pa, at a point in the liquid where the depth is 2.3 cm from the surface of the liquid? Use g = 10 m/s² for the acceleration due to gravity. Be careful with units.
The pressure at a depth of 2.3 cm from the surface of the liquid is 526 Pa.
7) When the absolute pressure inside a liquid is measured to be 92 kPa, the gauge pressure at the same point in the liquid is given by:
gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 92 kPa - 101 kPa
= -9 kPa
Therefore, the gauge pressure is negative and its unit is kPa.
8) Pressure of the liquid at a depth of 2.3 cm from the surface of the liquid is given by:
P = P_surface + pgh
where
P = pressure at depth from the surface of the liquid
P_surface = pressure at the surface of the liquid
p = density of the liquid
g = acceleration due to gravity
h = depth from the surface of the liquid
At the surface of the liquid:
P_surface = 0.25 kPa
Convert density into SI units:
p = 1.2 g/cm³ = 1200 kg/m³
Substitute the values of P_surface, p, g, and h into the above equation and solve for P:
P = 0.25 kPa + 1200 kg/m³ × 10 m/s² × 0.023 m
P = 0.25 kPa + 276 Pa
P = 250 Pa + 276 Pa
P = 526 Pa
Therefore, the pressure at a depth of 2.3 cm from the surface of the liquid is 526 Pa.
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Question 5 16.67 pts Write the Maxwell equation most directly associated with the following statements and give a brief reason for each. Define the quantities used in each equation. 1. An alternating emf is induced in a coil that rotates in a uniform magnetic field. 11. The lines of the magnetic field circle round a steady current. III. The static electric field inside a conductor is zero.
The Maxwell equation most directly associated with alternating emf is induced in a coil that rotates in a uniform magnetic field.
Maxwell's equation associated with the following statements is as follows:
An alternating emf is induced in a coil that rotates in a uniform magnetic field:
Faraday’s law of electromagnetic induction is Maxwell's equation most directly associated with this statement. This law states that the emf induced in any closed loop equals the negative of the time rate of change of the magnetic flux enclosed by the loop, ε = -dΦ/dt. Here, ε is the induced emf, Φ is the magnetic flux and t is time. The quantity used in this equation is the magnetic flux, which is a measure of the number of magnetic field lines that pass through a surface.
The lines of the magnetic field circle around a steady current:
Ampere’s circuital law is Maxwell's equation most directly associated with this statement. This law states that the magnetic field around a closed loop is proportional to the current passing through the loop, B = μI. Here, B is the magnetic field, I is the current, and μ is the magnetic permeability of the medium in which the current is flowing. The quantity used in this equation is the magnetic permeability.
The static electric field inside a conductor is zero:
Gauss's law is Maxwell's equation most directly associated with this statement. This law states that the flux of the electric field through any closed surface is proportional to the charge enclosed by the surface, ΦE = Q/ε₀. Here, ΦE is the electric flux, Q is the charge enclosed by the surface and ε₀ is the permittivity of the vacuum.
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Calculate the gravity of a planet if a 4-meter pendulum has a period of 2 seconds. How many times greater is this than the gravity of the Earth?
To calculate the gravity of a planet, we can use the formula: gravity = (4 * π^2 * length) / period^2 In this case, the length of the pendulum is 4 meters and the period is 2 seconds.
So, the gravity of the planet is gravity = (4 * π^2 * 4) / 2^2 Simplifying this equation: gravity = (4 * π^2 * 4) / 4 gravity = 4π^2 To compare this gravity to that of Earth, we need to know the value of gravity on Earth. The acceleration due to gravity on Earth is approximately 9.8 m/s^2. To find how many times greater the gravity of the planet is compared to Earth, we divide the gravity of the planet by the gravity on Earth: gravity_ratio = gravity / gravity_on_earth gravity_ratio = 4π^2 / 9.8 So, the gravity of the planet is approximately (4π^2 / 9.8) times greater than the gravity of Earth.
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A mass of 18.0 g of an element is known to contain 4.87 x 1023 atoms. What is the atomic mass of the element? Number 14.54 Units 8
A mass of 18.0 g of an element is known to contain 4.87 x 1023 atoms, the atomic mass of the element is 0.0593 g/mol.
Atomic mass can be defined as the average mass of an atom of an element, which can be found by taking into consideration the mass number of all the isotopes of the element and their relative abundance. To determine the atomic mass of an element, the given data must be utilized. We can employ the following formula to determine the atomic mass of an element, as follows:Atomic mass of an element = (mass of atoms/total number of atoms)× Avogadro's number. The atomic mass of the given element can be found using the above formula, as follows: Atomic mass of the element = (mass of atoms/total number of atoms) × Avogadro's number
Given: Mass of atoms = 18.0 g, total number of atoms = 4.87 x 10²³ atoms, Avogadro's number = 6.022 x 10²³. Number of moles of the given element can be determined as follows: Number of moles = (mass of element/atomic mass of element)Given: Mass of the element = 18 g
Therefore, the atomic mass of the given element can be determined as follows: Atomic mass of the element = (mass of atoms/total number of atoms) × Avogadro's number= (18.0 g/4.87 x 10²³ atoms) × 6.022 x 10²³= 0.0593 g/mol
Now, using the number of moles formula:Number of moles = (mass of element/atomic mass of element)= 18.0 g/0.0593 g/mol= 303.3 mol. Hence, the atomic mass of the element is 0.0593 g/mol.
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Could the source transformation be applied when voltage source is in parallel to impedance Zs? a. No, it could not b. Yes, it could
Yes, the source transformation can be applied when a voltage source is in parallel with impedance Zs.
b. Indeed, it could. The source change strategy can be applied when a voltage source is in lined up with impedance Zs. The interaction includes changing over the voltage source and impedance mix into a comparable current source and impedance or the other way around.
To apply source change for this situation, the voltage source is changed into a comparable current source. The same current source esteem is determined by separating the voltage source esteem by the impedance esteem (Is = Versus/Zs). The impedance Zs stays unaltered.
When the source has been changed into a comparable current source, standard circuit examination strategies can be applied. The changed circuit can be improved, and computations, for example, seeing as current or voltage can be performed utilizing Ohm's Regulation and Kirchhoff's regulations.
Consequently, the source change strategy is pertinent and valuable for streamlining and breaking down circuits where a voltage source is in lined up with impedance Zs.
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True or false:
Can the knowledge of the state of an isolated system allows in
quantum mechanics that future states can be predicted with
certainty?
It is not feasible to calculate the exact future state of a particle because of the uncertainty principle. Even if the present state of an isolated system is known, the future state cannot be predicted with certainty. The state of a particle is determined by probability rather than certainty.
The answer to the given question is "false".Quantum mechanics (QM) does not follow the same set of rules as classical mechanics. The Heisenberg uncertainty principle contradicts the classical idea of being able to predict the future with absolute certainty. The states of particles in an isolated system cannot be predicted with certainty as a result of the uncertainty principle.To be more specific, the uncertainty principle states that it is not possible to determine certain properties of a particle simultaneously, such as its position and momentum. It is not feasible to calculate the exact future state of a particle because of the uncertainty principle. Even if the present state of an isolated system is known, the future state cannot be predicted with certainty. The state of a particle is determined by probability rather than certainty.
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4. Find the pressure necessary for preventing material from expansion. Given that the compressibility of this material is 10:12 cmand the value expansion coefficient =4x10-deg! (Answer: 4x 10-dyne.cm)
The pressure necessary for preventing the material from expanding is determined by the equation P = β * ΔV/V₀, where P is the pressure, β is the expansion coefficient, ΔV is the change in volume, and V₀ is the initial volume.
To calculate the pressure necessary for preventing the material from expanding, we can use the equation P = β * ΔV/V₀, where P is the pressure, β is the expansion coefficient, ΔV is the change in volume, and V₀ is the initial volume.
Since the given expansion coefficient is [tex]4x10^(-10) deg^(-1)[/tex], we substitute this value into the equation as β.
To determine the change in volume, we can use the formula ΔV = V₀ * α * ΔT, where α is the linear expansion coefficient and ΔT is the change in temperature. However, in this case, the change in temperature is not given, so we cannot calculate the change in volume directly.
The compressibility of the material, given as 10:12 cm, is not directly applicable to the calculation of pressure necessary for preventing expansion.
Therefore, without additional information such as the initial volume or change in temperature, it is not possible to calculate the pressure necessary for preventing the material from expanding.
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Which of the following features is correct for High Voltage DC transmission? a) High Current b) Low Voltage c) High Voltage Regulation d) High Voltage
High Voltage DC (HVDC) transmission is the transmission of high-voltage electric power using direct current. This technology is utilized as a supplement or an alternative to alternating current (AC) transmission systems, which are typically utilized at lower voltages and shorter distances. HVDC transmission offers a number of benefits, including lower losses over long distances and reduced environmental impact.
One of the major features of HVDC transmission is high voltage.High voltage is a crucial feature for HVDC transmission. High voltage levels (typically in the range of 200 kV to 800 kV) enable long-distance transmission of power with low losses. This is due to the fact that at high voltages, the current required to deliver a specific quantity of power is lower.
As a result, lower current levels result in lower resistive losses, which are proportional to the square of the current. As a result, HVDC transmission systems are more efficient over long distances and can deliver more power than AC transmission systems at similar voltages. So, the correct option is d) High Voltage.
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What will be the approximate angle of elongation for Comet Halley on this significant day?
a. approximately 45 degrees eastern elongation viewed in the morning sky
b. approximately 45 degrees eastern elongation viewed in the evening sky
c. approximately 45 degrees western elongation viewed in the morning sky
d. approximately 45 degrees western elongation viewed in the evening sky
e. cannot be determined-insufficient information
The approximate angle of elongation for Comet Halley on this significant day would be approximately 45 degrees western elongation viewed in the evening sky. The correct answer is option (D).
When a celestial object is in elongation, it means that it is at its maximum angular separation from the Sun as seen from Earth. In the case of Comet Halley, it is specified that the elongation is 45 degrees. Since the elongation is western, it means that the comet is positioned to the west of the Sun. This means that it would be visible in the evening sky.
Therefore, option D, approximately 45 degrees western elongation viewed in the evening sky, is the correct answer. To summarize, the approximate angle of elongation for Comet Halley on this significant day would be approximately 45 degrees western elongation viewed in the evening sky.
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Let's consider 130 grams of air in a piston-cylinder device. The assembly is also fitted with a fan. Now the system is heated by the amount of 12 kJ heat transfer through a constant-pressure process while the fan is rotating transferring energy to the air. If the initial and final temperatures of the air are 27°C and 127°C, respectively, how much is the work done on the air by the fan in kJ? O -1.82 O 1.06 0 -3.55 0 -2.66
Work done by the fan (W) = Q - ∆H
where,Q is the heat transfer to the system, and∆H is the change in enthalpy of the system.
To determine the work done by the fan, you need to determine the heat transfer Q and the change in enthalpy ∆H.Q = 12 kJ = 12000
J∆H = ∆U + P∆V
where ∆U is the change in internal energy, P is the pressure, and ∆V is the change in volume.
Since this is a constant-pressure process, the work done is simply
W = P∆V
= nR∆T = 130/28.97 x 8.314 x (127 - 27)
= 32132 J = 32.132 kJ
The change in internal energy can be determined from the following expression:
∆U = ∆H - P∆V= 32.14 kJ - 101.3 kPa x 0.13 m³ = 19.67 k
JW = Q - ∆H= 12000 J - 19.67 kJ
= 10.33 kJ
≈ 1.06 kJ (rounded to two decimal places)
Therefore, the work done on the air by the fan is 1.06 kJ.
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