at a distance of 6 meters, a person with average vision is able to clearly read letters 1.0 cm high.

Answers

Answer 1

The height of the image that will be magnified on the retina will be 0.0022833m or .22833cm and it will be inverted.

What is magnification?

When anything is magnified, its seeming size is increased rather than its real size. This enlargement is quantified using a mathematical quantity called "magnification." When this number is less than one, a drop in size is frequently referred to as "magnification" or "de-magnification."

Briefing:

Given,

The distance of, u = 6 meters

The lens distance from the retina, v = 1.7 cm

The height of the object, hu = 1 m

We have to find the size of letters that appears in the retina, hv;

Here,

Magnification, M = -v/u =  [tex]\frac{h_{v} }{h_{u} }[/tex]

- 0.017/6 = hv/1

hv = -0.017/6

hv = -0.002833m

The image height will be 0.002833 m and it will be inverted.

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Related Questions

a super happy fun ball is dropped from a height of 11 feet and rebounds 13 14 of the distance from which it fell. how many times will it bounce before it's rebound is less than 1 foot? it will bounce times before its rebound is less than 1 foot. how far will the ball travel before it comes to rest on the ground? it will travel feet before it comes to rest on the ground.

Answers

Therefore, the super happy ball will take 32 bounces and travel the distance of less than 1 foot.

First bounce = 13 / 14 × 10 = 130 /14

using geometric progression where the common ratio = 13/14, the first bound = 130/14

ar^n-1 < 1

substitute the values into the equation

130 /14 × 13/14^(n-1) < 1

(13/14)^n-1 < 1÷ (130/14)

(13/14)^n-1 < 14 / 130

take log of both side

log (13 /14)^n-1 < log ( 14/130)

n-1 log (13 /14) < log  ( 14/130)

since log (13/14) negative

n-1 > (log( 14/130)) ÷ ( log (13/14)

n - 1 > 30.07

n > 30.07 + 1 > 31.07

The 32 bounce will the travel less than 1 foot.

Therefore, the super happy ball will take 32 bounces and travel the distance of less than 1 foot.

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qa cprojectile lands at the same height from which it was alunched. which initial velocoti will result in the greates horrizontal displacement of the projectile. neglect firction

Answers

The initial velocity will result in the greates horrizontal displacement of the projectile. neglect firction is Option C.

The horizontal velocity of the projectile is constant. There is a vertical acceleration due to gravity with a value of 9.8 m/s/s down. The projectile's vertical velocity changes at 9.8 m/s per second. The horizontal movement of the projectile is independent of vertical movement.

At its highest point, the vertical velocity is zero. As the object falls toward the Earth its vertical velocity increases again but points in the opposite direction to its initial vertical velocity. The initial horizontal velocity can also be determined by measuring the diameter d of the sphere and dividing it by the time t it takes for the sphere to move across the photogate.

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a car travels 65 km in 1 hour. what is its average speed in meters per second?

Answers

Answer:

18.1 m/s

Explanation:

65 km = 65 000 m    and 1 hour = 3600 sec

65000 / 3600  = 18.1 m/s

suppose the work function of a particular metal is 4.70 x 10-20j. what wavelength will be needed to eject electrons with a speed of 7.21x 105 m/s. will blue light be able to eject electrons from this metal?

Answers

The wavelength needed to eject electrons with a speed of 7.21 × 10⁵ m/sec is 7.2×1014Hz.

The electron is a subatomic particle with a poor one-standard electric rate. Electrons belong to the first generation of the lepton particle family and are commonly notion to be primary particles due to the fact they don't have any recognized components or substructure.

Electrons are negatively charged debris that orbits around the out of doors of the nucleus. They spin so speedy that it can be tough for scientists to examine them. they are interested in the superb price of the protons which are the smallest debris in an atom - you may fit 2000 of them right into a proton.

The hydrogen atom, as example, has simply one electron and one proton. The uranium atom, then again, has ninety-two protons, and consequently, 92 electrons.

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Suppose that a high-energy neutron is travelling at a speed of 18 million m/s. Find its energy in MeV (million electron volts (eV) ).

Answers

The  Energy of the a high-energy neutron  be 940.51 MeV.

What is speed?

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Mass of neutron: m₀ = 939.6 MeV/c².

a high-energy neutron is travelling at a speed of 18 million m/s

v = 1.8 × 10⁷ m/s.

Hence, Energy of the neutron be  = m₀c²/√(1- v²/c²) = 940.51 MeV.

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The net force exerted on a car traveling in a circular path at constant speed is
A) directed toward the center of the curve. B) zero because the car is not accelerating. C) directed forward, in the direction of travel. D) none of the above

Answers

At each point in a circular journey, an object's direction and speed change. Centripetal force is the name given to the force that results in this velocity or acceleration. Thus, option B is correct.

What net force exerted on a car travelling in a circular path?

Centripetal force is felt by a vehicle travelling in a circle. A circularly moving body is subject to a centripetal force that pushes toward the center of the circle it is travelling in.

Therefore, Centripetal force is the force that keeps an object moving in a circular motion when it is travelling due to velocity, or its speed in a particular direction. By attracting an object to a circle's center, it achieves this.

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what mass of fuel is needed to reach a top speed of 4000 m/s ?

Answers

103.4 kg mass of fuel is needed to reach a top speed of 4000 m/s .

What is speed ?

The speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed only has a direction and no magnitude, it is a scalar quantity.

Let fuel is released at the rate of dm / dt where m is mass of the fuel

thrust created on rocket

= d ( mv ) / dt

= v dm / dt

this is equal to force created on the rocket

= 220 dv / dt

so applying newton's law

v dm / dt = 220 dv / dt

v dm = 220 dv

dv / v = dm / 220

integrating on both sides

∫ dv / v    = ∫ dm / 220

lnv =  ( m₂ - m₁ ) / 220

ln4000 - ln 2500 = ( m₂ - m₁ ) / 220

( m₂ - m₁ ) = 220 x ( ln4000 - ln 2500 )

( m₂ - m₁ ) = 220 x ( 8.29  - 7.82 )

= 103.4 kg .

Complete question: A rocket in deep space has an empty mass of 220 kg and exhausts the hot gases of burned fuel at 2500 m/s. What mass of fuel is needed to reach a top speed of 4000 m/s.

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in this current position, which coastline(s) are experiencing a daily high tide? only a only b both a and c both b and d

Answers

In this current position, Both A and C coastline(s) are experiencing a daily high tide.

What is  gravitational field ?

A gravitational field is a model used in physics to explain the effects that a large thing has on the area surrounding it, exerting a force on smaller, less massive bodies. As a result, a gravitational field, which is measured in newtons per kilogram, is used to explain gravitational phenomena.

A and C are both correct answers. The beaches that experience high tides in the ideal situation are those that are more closer to or opposite to the moon. The moon's own gravitational field pulls the earth toward it, which is the cause of this. This results in high or low tides.

In essence, two high tides and two low tides are occurring simultaneously. This is because the moon exerts different forces depending on where the water is on earth.

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Please help me I have physics tomorrow and im so confused ​

Answers

Answer:

trust the process

Explanation:

quadratic formula, use synthetic division also use the p-q method for the roots and factoring.

consider the 6 stages listed below for the lives of a human being and a star. describe what a 1 solar mass star does in each stage of its existence:

Answers

Note that this is a trick question. It is true that the mass of a star affects its life cycle but all stars must go through the stages listed below. Note that the larger the solar mass of a star, the shorter its life cycle. Hence, in each of the stages given here is what will occur:

Prenatal Stage

protostar is reliant on its environmentgrows in size, temp, and internal pressure

Birth Stage

The star is able to sustain itself by making its own energy by nuclear fusion

Adolescence/Adulthood

The nuclear fusion continues and maintains equilibriumNote that 90% of the stars life is in the main sequence

Middle age

The sun is in middle age, in the middle of main sequence cycleIt reaches it's prime of life

Old age

Nuclear fusion of hydrogen to helium ends in the core and the star goes into another fusion stage of helium to carbonIt then swells into a red giant.

Death

All fusion processes stop as the outer part of the star is lost Turns in to a planetary nebula and the hot, inert core begins to cool off

What is the Solar Mass of a Star?

The solar mass is a unit of mass used to measure the masses of objects in the solar system, including stars. It is defined as the mass of the Sun, which is approximately 1.989 x 10³⁰ kilograms, or about 333,000 times the mass of the Earth.

Hence, since the earth's sun is 1.989 x 1010³⁰ kilograms, a star described as having 1 solar mass is simply a star equivalent of the Earth's sun.

Note however that the solar mass is often used as a standard unit of mass for comparing the masses of objects in the universe, such as planets, asteroids, and stars.

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Full Question:

Compare the following stages in the lives of a human being and a star: prenatal, birth, adolescence/ adulthood, middle age, old age, and death. What does a star with a solar mass of 1 solar mass do in each of these stages?

A mirage is a result of atmospheric 0 A Refraction. Aberration Dispersion Reflection_ E Scattering

Answers

A mirage is a result of atmospheric refraction.

A mirage is a naturally occurring optical phenomenon in which light rays are bent due to refraction, resulting in displaced images of distant objects or the sky. Light waves from the sun travel directly through the atmosphere to the Earth. But light travels at different speeds in warm air and cold air. The mirage occurs when the ground is very hot and the air is cool. Warming the ground warms a layer of air just above the ground, as light passes through the cold air and enters the warm air, it is refracted (bends). A layer of very warm air near the ground refracts light from the sky in a roughly U-shaped bend. The brain consider the light rays to be travelling in a straight line. The brain does not perceive the image as a deflected light from the sky. Instead, the brain thinks the light must be coming from something on the ground. Due to the difference in temperature of the atmosphere at different altitudes, the refractive indices of the air also vary as a result, causing the light rays to bend due to atmospheric refraction causing the formation of mirage.

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Is it possible for an object that has constant acceleration to also have a changing velocity?
Explain.

Answers

Sure, it can.Your inquiry specifies "constant acceleration" as a criterion.The example with constant acceleration with varying trajectory is parabolic motion.

What does parabolic motion mean?

Gravity will cause an object travelling forward in a single direction to fall inside a parabolic arc.The trajectory of a projectile travelling forward due to the momentum of the an initial thrust becomes parabolic because projectiles are objects that are exclusively impacted by gravity.

What does parabolic motion look like?

When water is held at an angle and connected to a source of water or even a water tap, the water flows out in a projectile motion.Because the water tends to move both vertically and horizontally at the same time, its route is unmistakably parabolic.

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Stranger anxiety is less likely to appear in conjunction with Multiple Choice
O absence of the mother.
О familiar settings.
O feelings of insecurity
O unfamiliar settings.

Answers

Stranger anxiety is less likely to appear in conjunction with unfamiliar settings

Stranger anxiety is typically triggered by the presence of unfamiliar people or settings. Therefore, it is less likely to appear in a multiple choice setting since the environment is familiar and there is no perceived threat from strangers. Furthermore, the presence of the mother or other familiar figures can provide a sense of security and reduce the likelihood of stranger anxiety.

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anyone who scuba dives is advised not to fly within the next 24 h because the air mixture for diving can introduce nitrogen to the bloodstream. without allowing the nitrogen to come out of solution slowly, any sudden air-pressure reduction (such as during airplane ascent) can result in the nitrogen forming bubbles in the blood, creating the bends, which can be painful and even fatal. military special operation forces are especially at risk. what is the change in pressure on such a special-op soldier who must scuba dive at a depth of 20 m in seawater one day and parachute at an

Answers

The change in pressure on such a special-op soldier is 22.58 x 10⁴ Pa.

Calculation:-

Let pressure at surface of earth be P Pa.  

pressure at height of 8.1 km in air can be calculated as follows .

pressure due to column of air of 8.1 km height

= h d g , h is height , d is density of air and g is acceleration due to gravity

= 8.1 x 1000 x .87 x 9.8 = 6.9 x 10⁴ Pa .

pressure at the height of 8.1 km

= P - 6.9 x 10⁴ Pa

Pressure due to  column  of 16 m in the sea

= h d g

16 x 1000 x 9.8

= 15.68 x 10⁴ Pa .

Pressure at depth of 16m

= P + 15.68 x 10⁴

pressure difference between points at height of 8.1 km and pressure at point 16 m deep

=  P + 15.68 x 10⁴ -  P +  6.9 x 10⁴ Pa

= 22.58 x 10⁴ Pa .

Air is the invisible combination of gases that makes up the Earth's ecosystem. this is what we suggest while we communicate approximately the air that we breathe. The phrase air is also used to consult the advent of some thing, as in an air of mystery.

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a swan on a lake gets airborne by flapping its wings and running on top of the water. if the swan must reach a velocity of 6000 mm/s to take off and it accelerates from rest at an average rate of 35.0 cm/s2, how far will it travel before becoming airborne?

Answers

It travels 51.4 m before ascending into the air. If the swan must accelerate from rest at an average speed of 35.0 cm/s^2, it will take 6000 mm/s to attain the required speed for takeoff.

Consider the instantaneous speed to be the speed that the speedometer registers at any given moment in time, and the average speed to be the average of all the measurements taken throughout the journey. In mechanics, acceleration is the rate at which an object's velocity with respect to time changes. The vector quantity of accelerations (in that they have magnitude and direction).

The kinematics equation and the provided information lead to the conclusion that

x = V2^2 -V1^2/2a

x = 6^2/2*0.35 = 51.4m

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imagine the speed of light in antoher universe to be only 200m/s. two cars are teaveling along a high3ay in opposite directions. car 1 is traveling 50m/s, and car 2 is traveling 70m/s. how fast does person ridingin cqr 1 measure person riding in car 2 to be traveling?

Answers

The person riding in car 1 would measure the person riding in car 2 to be traveling at a speed of 63.91m/s.

If the speed of light in another universe is 200m/s and two cars are traveling in opposite directions along a highway, the speed at which a person riding in car 1 measures the person riding in car 2 to be traveling can be calculated using the following formula:

v' = (v + v0)/(1 + vv0/c²)

where v' is the measured speed, v is the actual speed of the object, v0 is the speed of the observer, and c is the speed of light in the given universe.

In this case, the actual speed of car 2 is 70m/s and the speed of car 1 is 50m/s. Plugging these values into the formula, we get:

v' = (70 + 50)/(1 + 70 × 50/200²) = 120/(1 + 3500/40000) = 120/1.875 = 63.91m/s.

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For vibrational motion, what term denotes the maximum displacement from the equilibrium position? O wavelength O frequency O period O amplitude Submit Request Answer

Answers

Amplitude X is the name given to the largest departure from equilibrium. It depends on the type of oscillation on the units for amplitude and displacement.

The maximum displacement or distance that a point on a vibrating body or wave can move is known as the amplitude in physics and is calculated from the position where the point is at equilibrium. The length of the vibration route is divided in half by this value. Amplitude is the largest deviation from a vibrating body's mean position. The mass is changing direction while it is at its location of greatest displacement, hence velocity is zero.

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a 35.0-kg child swings in a swing supported by two chains, each 3.08 m long. the tension in each chain at the lowest point is 418 n. (a) find the child's speed at the lowest point. m/s (b) find the force exerted by the seat on the child at the lowest point. (ignore the mass of the seat.) n (upward)

Answers

The child's speed at the lowest point is 5.54 m/s and the force exerted by the seat on the child at the lowest point is 692 N.

A tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable. The word “tension” comes from a Latin word meaning “to stretch.” Not coincidentally, the flexible cords that carry muscle forces to other parts of the body are called tendons.

The Tension Force or the Force of Tension is the force transmitted through a rope, cable, string or wire pulled taut by forces acting on both ends.

The Tension Force, like all forces, is a vector and has both magnitude and direction. Direction,  Always a pull, In the direction of the rope, In opposite directions on opposite ends of the rope.

Any flexible connector, such as a string, rope, chain, wire, or cable, can exert pulls only parallel to its length, thus, a force carried by a flexible connector is a tension with direction parallel to the connector. It is important to understand that tension is a pull in a connector.

a)let the velocity at the lowest point be v

By balancing the force, we get

T + T = Mg + mv^2/l-------(1)

346+346 = 35*9.8 + 35*v^2/3.08

692=343 + 35v^2/3.08

v=5.54 m/s

b)let the force be F

At equillibrium, we get

F = Mg + mv^2/L

F = T+T            (from 1)

F = 2T

F = 692 N

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g if at a particular instant and at a certain point in space the electric field is in the +x-direction and has a magnitude of 4.50 v/m, what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?express your answer in teslas.

Answers

A long, straight wire's magnetic field strength is  1.5 x 10^-8 Tesla

Briefly:

E = 4.5 V/m

Relation between electric field and magnetic field in electromagnetic wave are given by:-

c = E / B

Where, c= velocity of light in vacuum,

e = electric field and ,

B= magnetic field.

B = E / c

B = 4.5 / ( 3 x 10^8)

B = 1.5 x 10^-8 Tesla

How strong is the magnetic field?

With increasing distance and vice versa, the strength of the magnetic field created by an electric current diminishes. Magnetic field lines form concentric circles, and as one moves away from a conductor, the radius of these circles grows, demonstrating a decreasing magnetic field.

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(209) Problem 3: You are constructing mobile out of 5 identical toy helicopters_ each of mass m 165 g, identical sticks (each length / = 24.1 cm, and negligible mass) and thin string negligible mass_ The distance from the left-hand side of each stick to the attachment point of the sting supporting it ae Xp through x4 respectively, as shown in the diagram. The tensions in the supporting strings are T/ through T4 as shown. You want to design the mobile s0 that it is in static equilibrium_ Otheexpertta com 13 % Part (a) Find the tension in Newtons in the string T]. 13 % Part (b) Find the tension in Newtons in the string 13% Part (c) Find the tension in Newtons in the string Tz: 13 % Part (d) Find the tension in Newtons in the string T4: 13 % Part (e) Find the distance X/, in centimeters 13 % Part (f) Find the distance Xz in centimeters _ 13 % Part (g) Find the distance Xz,in centimeters _ 13 % Part (h) Find the distance x4, in centimeters _

Answers

The distance and tension in the supporting strings are

a)X1 = 12.05 b) x2 = 16.06, T2 =  0.7644 N c) X3 =  18.01 cm , T3 = 1.0123N, d) T4 = 1274N e) X4 = 4.82 cm

The mas of toy m = 165g

sticks length l = 24.1 cm

For x1,

Both toys are balanced at same distance from middle point,

x1 = 24.1/2 = 12.05

F0r x2

we know  that  moment force = mgd

here mgx2 = 2mg(24.1 - x2)

x2 = 48.2 - 2x2

x2 = 16.06

Total tension = mg

m = 3 × 26

tension T2 = 0.7644 N

for x3,

x3 = 3/4 × 24.1 = 18.01 cm

T3 = 4 × 0.26 × 9.8 = 1.0123N

For X4,

x4 = 1/5 × 24.1 = 4.82 cm

T4 = 5× 0.026× 9.8 = 1274 N

Tension is defined as the pulling force transferred axially by a string, rope, chain, or other similar object, or by each end of a rod, truss member, or other similar three-dimensional object; tension may also be referred to as the action-reaction pair of forces acting at each end of those elements. Compression's opposite, tension, is possible.

When atoms or molecules are driven apart from one another and accumulate potential energy while a restoring force is still present, the restoring force may produce what is also known as tension. Each end of a string or rod that is under such stress could pull on the thing it is attached to in order to release the tension and restore the string or rod to its relaxed length.

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G s w d v b k x s r only for freinds
Have a pretty heart

Answers

Answer:

what do you mean

Explanation:

An IC with a switching rate of 4GHz4GHz and VDD=6VVDD=6V is dissipating 60W60W. What will be the power dissipation if we change VDDVDD to 5V5V and the switching rate to 3GHz3GHz while keeping the activity factor the same?

Answers

The power dissipation after changing voltage and switching rate will be 31.25 Volt.

What is power dissipation?

The greatest power that an integrated circuit (IC) can continuously dissipate under a given thermal environment is known as power dissipation.

For 1st case,

switching rate: f = 4 GHz.

power dissipation: P = 60 W.

voltage drop: [tex]V_{DD}[/tex] = 5 V.

So, load capacitance: [tex]C_L[/tex] = [tex]\frac{P}{V_{DD}^{2} *f}[/tex]  = 60/{6^2×4} f = 0.417 f.

Now for 2nd case:

switching rate: f = 4 GHz.

voltage drop: [tex]V_{DD}[/tex] = 6V.

Hence, power dissipation in this case: P = [tex]{C_L*V_{DD}^{2} *f}[/tex]

= 0.417 × 5² × 3 V

= 31.25

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A box with mass 15 kg is pulled up an inclined plane as illustrated in the figure. What magnitude of force, F, must be applied to the box in order to move it up the ramp at constant speed if the coefficient of kinetic friction between the box and ramp is 0.115?

Answers

Answer:

o99i

Explanation:

while observing a storm, you see a flash of lightning, and hear the thunder 5.9 seconds later. assuming the speed of sound through the air is 331 m/s, how far away was the lightning strike, in km?

Answers

If a flash of lightning, and hear the thunder 5.9 seconds later, the distance of the lightning strike is 1 mile.

A mile is longer than a kilometer. To find out whether a kilometer or a mile is longer, convert them to feet. One mile is 5,280 feet. One kilometer is 3,280.84 feet.

Most roads have speed limits between 25 and 60 mph, so you can expect to drive one mile in 1 to 2.5 minutes. Whatever you do, don't let the math get you off the road! And don't forget that it's important to properly insure your vehicle.

The 10,000 steps are about 5 miles or 1 hour and 40 minutes, depending on stride length and walking speed. But that doesn't mean you have to do it all in one walk.

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as the name quasi-stellar radio sources implies, all quasars are strong radio sources. as the name quasi-stellar radio sources implies, all quasars are strong radio sources. true false

Answers

The statement as the name quasi-stellar radio sources implies, all quasars are strong radio sources is true.

Quasars are extremely bright objects found in the centers of some galaxies, driven by gas swirling at high speed around very large black holes. The brightest quasars can outshine all the stars in the galaxy they reside in, and can be seen billions of light years away. Quasars are the most distant bright objects known. Quasar's optical spectrum presents a new mystery. Photographs taken of their spectra showed the positions of emission lines at wavelengths inconsistent with sources well known to astronomers at the time.[tex]x=\sqrt{1-\frac{\alpha }{y}+\beta \pi +mo }[/tex]

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Examine this DNA strand: TACCTGGCA. The sequence that would be found on the other side of theDNA molecule would be: a. TACCTGGCA b. ATGGACCGT c. UAGGUGGCA d. AUGGACCGU

Answers

If we have the DNA strand TACCTGGCA then the sequence that would be found on the other side of the DNA molecule would be b. ATGGACCGT.

What is the complementarity of DNA strands?

The complementarity of DNA strands is a rule that states Adenine or A always pairs with Thymine or T, while Guanine or G always pairs with Cytosine or C.

Therefore, with this data, we can see that  the complementarity of DNA strands depends on the matches between different nucleotides in the DNA strand such as A with T or C with G.

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a spider hangs by a strand of silk at an eye level 40 cm in front of a plane mirror. you are behind the spider, 68 cm from the mirror.

Answers

Your eye as well as the spider's image in the mirror are 1.28 meters apart.

What is mirror, in a brief?

A mirrors is a luminance that reflects light and creates an actual or fictitious picture. An device that returns an image is a reflector or looking glass, which reflects the image of the object when it is positioned in front of it. When focused through an eye or camera lens, light that reflects off a mirror will reveal an image of everything that was in front of it. Mirrors reflect light at an equal but opposite angle, reversing the orientation of the image.

Briefing:

The image distance is equal to the object distance:

Distance between the spider and mirror = 40cm

So, the image is formed 40cm inside the mirror

Distance between the person and mirror = 68cm

Distance between the image and person = 68+40= 128cm

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a 175-kg object and a 475-kg object are separated by 3.90 m. (a) find the magnitude of the net gravitational force exerted by these objects on a 53.0-kg object placed midway between them. n (b) at what position (other than an infinitely remote one) can the 53.0-kg object be placed so as to experience a net force of zero from the other two objects? m from the 475 kg mass toward the 175 kg mass

Answers

a) The magnitude of the net gravitational force exerted by these objects on a 53.0 kg is 6.03 * 10¹¹ N

b) By placing object of 53.0 kg 1.976 m from 175 kg object and 1.324 m from 475 kg object.

Mass of an object-1= M₁ = 175 kg

Mass of an object-2= M₂ = 475 Kg

Distance between M₁ & M₂  = 3.90 m

Mass of an object-3 = M₃ = 53 Kg

If M₃ placed midway between them M₁ & M₂.

Force on M₃ due to M₁

Distance between  M₁ & M₃, r = 3.90/2 = 1.95

F = G(M₁*M₃/r²)

F = 6.67 x 10¹¹(175*53/ 1.95²)

F = 16,269.33*10¹¹ = 1.62 * 10⁷ N

Force on M₃ due to M₂

Distance between M₂ & M₃, r' = 3.90/2 = 1.95

F' = G(M₂*M₃/r²)

F = 6.67 * 10₁₁ ( 475 * 53/ 3.8)

F = 44188.75 * 10¹¹ = 4.41 * 10⁷ N

Net force on M₃:

F' + F = 4.41 * 10⁷ N + 1.62 * 10⁷ N = 6.03 * 10¹¹ N

The magnitude of the net gravitational force exerted by these objects on a 59.0 kg is 6.03 * 10¹¹ N.

b) Distance between M₁ & M₂  = r = 3.90 m

Let the distanced between M₁ & M₃ be r

Force experienced by M₃ due to M₁ :

f = G(M₁*M₃/r²)

Let the distanced between M₂ & M₃  be r'

Force experienced by M₃ due to M₂:

f' = G(M₂*M₃/r²)

Net force equal to zero, then :

f = f'

G(M₁*M₃/r²) = G(M₂*M₃/r'²)

6.18*10⁷/r₂² = 16.7*10₇/r'²

r = 1.4914 * r'

R = r+r'

3.90 m = 1.4914\times r' + r'

r' = 1.324 m

r = 1.976 m

Therefore, the magnitude of the force on M₃ is 6.03 * 10¹¹ N and by placing object of 53.0 kg 1.976 m from 175 kg object and 1.324 m from 475 kg object.

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In a classic Simpsons episode, Abe Simpson states "My car gets 40 rods to the hogshead, and that's the way I like it!" To describe the gas mileage of a modern car to Abe Simpson, construct a method to convert 51.5 miles per gallon to rods per hogshead. For this calculation, use the two following conversion factors: 1 mile = 320.0 rods 1 hogshead = 85.7 gallons What is the gas mileage of the car in rods per hogshead? (Note: Report your value in decimal notation, not scientific notation.)

Answers

The gas mileage of the car in rods per = 1412336rogs/

We have been given:

quantity= 51.5miles per

1 mile = 320.0 rods

1 = 85.7

51.5miles/ = 51.5×1mile/1 ×320.0 rods/1mile×85.7/

= (51.5×320.0×85.7)rods/

= 1412336 rods/

hence, the final answer will be 1412336rods/.

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Stars begin burning helium to carbon when the temperature rises in the core. This temperature increase is caused by a. gravitational collapse. b. fusing hydrogen into helium in the core. c. fusing hydrogen into helium in a shell around the core. d. degenerate-electron pressure.

Answers

Stars begin burning helium to carbon when the temperature rises in the core. This temperature increase is caused by fusing hydrogen into helium in the core. The correct answer is B.

In the universe, hydrogen fusion is the most common way to produce energy. At the centers of our Sun and other stars, where it has a density more than 70 times greater than that of steel, the gravitational force is used to fuse hydrogen. As a result, fusion produces all of the heat and light on Earth so the temperature increase. Stars begin burning helium to carbon when the temperature rises in the core. Chemical element helium has the atomic number 2 and the letter He after it. It is a colorless, odorless, tasteless, inert, monatomic gas that is the first member of the noble gas group in the periodic table and is not toxic.

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