balance using half rxn meathod: Cu + NO3- -> Cu2+ + NO

Answers

Answer 1

Answer:

Let me explain

Explanation:

The balanced equation for the given reaction is:

3Cu + 8NO3- + 4H+ → 3Cu2+ + 2NO + 4H2O

Here's how to balance the equation using the half-reaction method:

Half-reaction for oxidation: Cu → Cu2+

To balance this half-reaction, we need to add two electrons to the left side:

Cu → Cu2+ + 2e-

Half-reaction for reduction: NO3- → NO

To balance this half-reaction, we need to add three electrons to the right side:

NO3- + 3e- → NO

Now, we need to balance the number of electrons in both half-reactions. To do this, we need to multiply the oxidation half-reaction by three and the reduction half-reaction by two:

3Cu → 3Cu2+ + 6e-

2NO3- + 6e- → 2NO

Now, we can combine the two half-reactions by adding them together and canceling out the electrons:

3Cu + 8NO3- + 4H+ → 3Cu2+ + 2NO + 4H2O

This is the balanced equation for the given reaction.


Related Questions

Aqueous hydrobromic acid will react with solid sodium hydroxide to produce aqueous sodium bromide and liquid water . Suppose 5.66 g of hydrobromic acid is mixed with 1.1 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction.

Answers

The balanced chemical equation for the reaction between hydrobromic acid and sodium hydroxide is: The maximum mass of water that can be produced in this reaction is 0.495 g.

HBr + NaOH → NaBr + H2O

According to the equation, 1 mole of hydrobromic acid reacts with 1 mole of sodium hydroxide to produce 1 mole of water. The molar mass of HBr is 80 g/mol, while the molar mass of NaOH is 40 g/mol. Therefore, the number of moles of HBr and NaOH can be calculated as follows:

moles of HBr = 5.66 g / 80 g/mol = 0.07075 mol

moles of NaOH = 1.1 g / 40 g/mol = 0.0275 mol

Since the reaction between HBr and NaOH is a one-to-one ratio, the limiting reagent is NaOH because it produces fewer moles of product. Therefore, the number of moles of water produced can be calculated as follows:

moles of H2O = 0.0275 mol

The mass of water produced can be calculated using its molar mass, which is 18 g/mol:

mass of H2O = 0.0275 mol × 18 g/mol = 0.495 g

Therefore, the maximum mass of water that can be produced in this reaction is 0.495 g.

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Consider the following reaction:

2N2(g) + O2(g) ⇌ 2NO2(g)

A reaction mixture initially contains 3.21 atm N2 and 6.21 atm O2. Determine the equilibrium pressure of NO2 if Kp for the reaction at this temperature is 3.2 × 10-28.

Answers

The equilibrium pressure of the nitrogen oxide is given as 4 atm.

What is the Kp?

Kp is the equilibrium constant for a chemical reaction in terms of partial pressures. It is defined as the ratio of the product of the partial pressures of the products raised to their stoichiometric coefficients to the product of the partial pressures of the reactants raised to their stoichiometric coefficients

We know that;

Kp = [tex]pNO_{2} ^2/pN_{2} ^2 . pO_{2}[/tex]

[tex]3.2 * 10^-28 = (2x)^2/(3.21 - 2x) (6.21 - x)\\3.2 * 10^-28 = 4x^2/19.9 - 3.21x - 12.42x + 2x^2\\3.2 * 10^-28(19.9 - 15.63x + 2x^2) = 4x^2\\6.4 * 10^-27 - 5 * 10^-27 x + 6.4 * 10^-28x^2 = 4x^2\\x = 4 atm[/tex]

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please help with this! ty

Answers

The mole concept is an important method which is used to calculate the amount of the substance. 1 mole is defined as a number which is equal to 6.022 × 10²³ particles also called the Avogadro's constant.

One mole of a substance is that amount of it which contains as many particles or entities as there are atoms in exactly 12 g of Carbon-12.

The equation used to calculate the number of moles is:

Number of moles = Given mass / Molar mass

Molar mass of NaCl = 58.44 g/mol

1. n = 8 / 58.44  = 0.13

2. n = 2.3 / 58.44 = 0.039

3. n = 9.59 / 58.44 = 0.16

4. n = 38.44 / 58.44 = 0.65

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Calculate the molar solublity of SrCO3 (Ksp = 5.40×10-10) in 0.099 M Sr(NO3)2.

Answers

The solubility product constant (Ksp) for strontium carbonate (SrCO3) is given as 5.40×10^-10. The reaction equation for the dissolution of SrCO3 in water is: The molar solubility of SrCO3 in 0.099 M Sr(NO3)2 is 7.4×10^-6 M.

SrCO3(s) ⇌ Sr2+(aq) + CO32-(aq)

In the presence of Sr(NO3)2, the equilibrium of the reaction will shift to the left to form more SrCO3 precipitate. This is known as the common ion effect. The dissociation reaction of Sr(NO3)2 in water is:

Sr(NO3)2(s) ⇌ Sr2+(aq) + 2NO3-(aq)

Assuming that the solubility of SrCO3 is small, the concentration of Sr2+ in the solution is approximately equal to the concentration of Sr(NO3)2 added. Thus, the concentration of Sr2+ in the solution is:

[Sr2+] = 0.099 M

Using the solubility product expression for SrCO3, we can write:

Ksp = [Sr2+][CO32-]

Assuming that the solubility of SrCO3 is x, then the concentration of CO32- is also equal to x. Thus, we can write:

Ksp = (0.099 + x)(x)

Solving for x, we get:

x^2 + 0.099x - 5.40×10^-10 = 0

Using the quadratic formula, we get:

x = 7.4×10^-6 M

Therefore, the molar solubility of SrCO3 in 0.099 M Sr(NO3)2 is 7.4×10^-6 M.

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Complete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction.
S2O3 2- (aq) --> S4O6 2- (aq)

Answers

We must take into consideration the balance of atoms and charges in order to balance the half-reaction for the conversion of S2O3 2- to S4O6 2- in acidic solution.

Write the imbalanced half-reaction as the first step.

S2O3 S4O6 2- (aq)

Step 2: Align the atoms, with the exception of hydrogen and oxygen.

2S4O6 2-(aq) = S2O3 2-(aq)

Step 3: Add water (H2O) to balance the oxygen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq)

Step 4: Add hydrogen ions (H+) to balance the hydrogen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq)

Step 5: Add more electrons (e-) to balance the charge.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq) + 2e-

The balanced half-reaction in acidic solution is:

S2O3 2- (aq) + 4H+ (aq) + 2e- → 2S4O6 2- (aq) + H2O

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6. Given a mixture of gases: 1.00 g He,
14.0 g N2 and 10.0 g NO. What is the total pressure at 27.0 °C if the gases are confined in a 2.00 L container?

A) 0.310 atm
B) 1.24 atm
C) 13.3 atm
D) 21.6 atm

Answers

Considering the ideal gas law, the total pressure at 27.0 °C if the gases are confined in a 2.00 L container is 13.3 atm.

Definition of ideal gas law

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

Where:

P is the gas pressure.

V is the volume that occupies.

T is its temperature.

R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.

n is the number of moles of the gas.

Total pressure in this case

In this case you know:

mass of He= 1 gr

mass of N₂= 14 gr

mass of NO= 10 gr

molar mass of He= 4 gr/mole

molar mass of N₂= 28 gr/mole

molar mass of NO= 30 gr/mole

moles of He= mass of He÷ molar mass of He= 1 gr÷ 4 gr/mole= 0.25 moles

moles of N₂= mass of N₂÷ molar mass of N₂= 14 gr÷ 28 gr/mole= 0.5 moles

moles of NO= mass of NO÷ molar mass of NO= 10 gr÷ 30 gr/mole= 1/3 moles

total moles= moles of He + moles of N₂ + moles of NO= 0.25 moles + 0.5 moles + 1/3 moles= 13/12 moles

V= 2 L

R= 0.082 (atmL)/(molK)

T= 27 °C= 300 K

Replacing in the ideal gas law:

P×2 L = 13/12 moles×0.082 (atmL)/(molK)×300 K

Solving:

P= [13/12 moles×0.082 (atmL)/(molK)×300 K]÷ 2 L

P= 13.3 atm

Finally, the total pressure is 13.3 atm.

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I NEED HELP ASAP PLS

A 638.3 g sample of nickel releases 12337 joules of heat. The specific heat capacity of nickel is
0.5024 J/(g.°C). By how much did the temperature of this sample change, in degrees Celsius?

A 0.6949 mol sample of aluminium absorbs 5281.1 joules of heat. The specific heat capacity of aluminium is 24.2 J/(mol K). By how much did the temperature of this sample change, in kelvins?

A 0.4363 mol sample of indium experiences a temperature change of +109.71 °C while absorbing 1279.9 joules of heat. What is the specific heat capacity of indium?

A 824.5 g sample of silver undergoes a temperature change of +1078.87 K while absorbing
207260 joules of heat. What is the specific heat capacity of silver?

A 616.7 g sample of iridium is subjected to a temperature change of -2020.47 °C while releasing 1617300 joules of heat. What is the specific heat capacity of iridium?

A 875.8 g sample of uranium absorbs 15291 joules of heat. The specific heat capacity of uranium is 0.116 J/(g K). By how much did the temperature of this sample change, in kelvins?

A 990.1 g sample of molybdenum absorbs 179910 joules of heat. The specific heat capacity of molybdenum is 0.2772 J/(g.°C). By how much did the temperature of this sample change, in degrees Celsius?

A 3.596 mol sample of barium is subjected to a temperature change of -568.85 K. The specific heat capacity of barium is 28.07 J/(mol K). How many joules of heat were transferred by the sample?

A sample of rhodium experiences a temperature change of -1311.77 °C while releasing 203580 joules of heat. The specific heat capacity of rhodium is 0.2428 J/(g.°C). What is the mass of this sample?

A sample of methane goes through a temperature change of +330.22 °C while absorbing 672220 joules of heat. The specific heat capacity of methane is 2.191 J/(g.°C). What is the mass of this sample?

Answers

For the first problem, using the formula Q = mcΔT, we can solve for ΔT, where Q is the heat released, m is the mass of nickel, c is the specific heat capacity of nickel, and ΔT is the temperature change. Plugging in the values, we get ΔT = Q/(mc) = 12337/(638.3 × 0.5024) ≈ 48.9 °C.

For the second problem, we use the same formula, but this time we solve for ΔT in kelvins, since the specific heat capacity of aluminum is given in units of J/(mol K). Plugging in the values, we get ΔT = Q/(mc) = 5281.1/(0.6949 × 24.2) ≈ 97.8 K.

For the third problem, we use the formula Q = mcΔT, but this time we solve for c, since the specific heat capacity of indium is unknown. Plugging in the values, we get c = Q/(mΔT) = 1279.9/(0.4363 × 109.71) ≈ 27.8 J/(mol K).

For the fourth problem, we use the same formula, but this time we solve for the specific heat capacity of silver. Plugging in the values, we get c = Q/(mΔT) = 207260/(824.5 × 1078.87) ≈ 0.240 J/(g K).

For the fifth problem, we use the same formula to solve for the specific heat capacity of iridium. Plugging in the values, we get c = Q/(mΔT) = -1617300/(616.7 × -2020.47) ≈ 0.131 J/(g K).

For the sixth problem, we use the same formula to solve for the temperature change in kelvins. Plugging in the values, we get ΔT = Q/(mc) = 15291/(875.8 × 0.116) ≈ 149.8 K.

For the seventh problem, we use the same formula to solve for the temperature change in degrees Celsius. Plugging in the values, we get ΔT = Q/(mc) = 179910/(990.1 × 0.2772) ≈ 67.5 °C.

For the eighth problem, we use the formula Q = mcΔT to solve for the heat transferred. Plugging in the values, we get Q = mcΔT = 3.596 × 28.07 × -568.85 ≈ -5789 J.

For the ninth problem, we use the same formula to solve for the mass of rhodium. Plugging in the values, we get m = Q/(cΔT) = 203580/(0.2428 × -1311.77) ≈ 197.8 g.

For the tenth problem, we use the same formula to solve for the mass of methane. Plugging in the values, we get m = Q/(cΔT) = 672220/(2.191 × 330.22) ≈ 112.4 g.

Identify three specific changes that could be made to a chemical system that will shift the equilibrium to increase the yield of NH3 in the following reaction:
N2(g) + 3H2(g) → 2NH3(g) + Heat

Answers

Three changes could be made to a chemical system to shift the equilibrium to increase the yield of NH3 in the reaction [tex]N_{2} (g)[/tex] + [tex]3H_{2} (g)[/tex] → [tex]2NH_{3} (g)[/tex] + Heat are Increase the pressure, Decrease the temperature, and Add a catalyst.

1. Increase the pressure: According to Le Chatelier's principle, increasing the pressure will shift the equilibrium towards the side with fewer moles of gas. In this case, that means increasing the pressure on the left-hand side of the equation, where there are only two moles of gas (one [tex]N_{2}[/tex] and three [tex]H_{2}[/tex]), compared to the two moles of gas on the right-hand side (two [tex]NH_{3}[/tex]). By increasing the pressure, more of the reactants will be forced to react and produce more [tex]NH_{3}[/tex].

2. Decrease the temperature: The forward reaction in this equation is exothermic, meaning that it releases heat. According to Le Chatelier's principle, decreasing the temperature will shift the equilibrium towards the side of the equation that produces heat. In this case, that means shifting towards the products (the right-hand side). By decreasing the temperature, more [tex]NH_{3}[/tex] will be produced.

3. Add a catalyst: Adding a catalyst can increase the rate of the reaction, which can also shift the equilibrium towards the products. In this case, a catalyst like iron can be added to the reaction to increase the rate of [tex]NH_{3}[/tex] production. This will allow more [tex]NH_{3}[/tex] to be produced in the same amount of time, effectively increasing the yield.

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Initially, a 400.3 m³ spring-loaded piston-cylinder assembly contains R-134a at 600 kPa and 150°C. The refrigerant temperature was cooled to -30°C and the volume was 0.1 m³. Calculate the transfer and the work produced by the refrigerant during this process.

Answers

To solve this problem, we can use the First Law of Thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W):

ΔU = Q - W

We can assume that the process is quasi-static and reversible, so there is no entropy change (ΔS = 0). Therefore, the heat added to the system is simply the heat transfer (Q) and can be calculated using the specific heat capacity of R-134a at constant pressure (cp):

Q = m * cp * ΔT

where m is the mass of R-134a, cp is the specific heat capacity at constant pressure, and ΔT is the temperature change.

To calculate the work done by the refrigerant, we can use the following equation:

W = -P * ΔV

where P is the pressure and ΔV is the change in volume.

First, we need to find the initial and final states of the refrigerant:

State 1: P1 = 600 kPa, T1 = 150°C, V1 = 400.3 m³
State 2: P2 = 600 kPa, T2 = -30°C, V2 = 0.1 m³

We can use the R-134a tables to find the specific volume and specific internal energy at each state:

State 1: v1 = 0.1532 m³/kg, u1 = 783.1 kJ/kg
State 2: v2 = 0.0044 m³/kg, u2 = 131.3 kJ/kg

The mass of R-134a can be calculated from the initial volume and specific volume:

m = V1 / v1 = 400.3 m³ / 0.1532 m³/kg = 2614.4 kg

The heat transfer can be calculated as:

Q = m * cp * ΔT = m * cp * (T2 - T1) = 2614.4 kg * 1.14 kJ/kg·K * (-30°C - 150°C) = -573876.48 kJ

Note that the negative sign indicates that heat is being removed from the system (the refrigerant is being cooled).

The work done by the refrigerant can be calculated as:

W = -P * ΔV = P1 * (V1 - V2) = 600 kPa * (400.3 m³ - 0.1 m³) = 240120 J

Note that we converted the pressure from kPa to Pa and the volume from m³ to m³ to obtain the correct units for work (Joules).

Therefore, the transfer of heat from the refrigerant during this process is -573876.48 kJ, and the work produced by the refrigerant is 240120 J.

Shown above is the phase diagram for water as it is heated. Which section represents the phase of water with the highest kinetic energy?

Answers

The section that represents the phase of water with the highest kinetic energy is the gas phase or vapor phase.

Gas phase or vapor phase section is above the boiling point curve, which separates the liquid and gas phases. At this point, the temperature is at or above 100°C (at standard atmospheric pressure), and the kinetic energy of the water molecules is sufficient to overcome the intermolecular forces holding them in the liquid phase and escape into the gas phase. The gas phase has the highest kinetic energy because the water molecules in this phase are more widely separated and move more rapidly than in the liquid or solid phases. The gas phase is also characterized by the highest entropy or disorder, as the molecules are free to move in any direction and occupy a large volume. The section that represents the phase of water with the highest kinetic energy is  gas phase or vapor phase.

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6 of 28
Attempt 2
If 7.66 g of CuNO, is dissolved in water to make a 0.140 M solution, what is the volume of the solution in milliliters?

Answers

The volume of a 0.140 M solution of Cu(NO3)2 that contains 7.66 g of the compound, volume of the solution is 292.9 mL.

To determine the volume of a 0.140 M solution of Cu(NO3)2 that contains 7.66 g of the compound, we can use the following formula:

Molarity = moles of solute / volume of solution in liters

First, we need to calculate the number of moles of Cu(NO3)2 in the given mass of the compound:

moles of Cu(NO3)2 = mass / molar mass

The molar mass of Cu(NO3)2 can be calculated by adding the atomic masses of copper, nitrogen, and six oxygen atoms:

1 x Cu = 63.55 g/mol

2 x N = 14.01 g/mol x 2 = 28.02 g/mol

6 x O = 15.99 g/mol x 6 = 95.94 g/mol

Molar mass of Cu(NO3)2 = 63.55 g/mol + 28.02 g/mol + 95.94 g/mol = 187.51 g/mol

Now, we can calculate the number of moles of Cu(NO3)2:

moles of Cu(NO3)2 = 7.66 g / 187.51 g/mol = 0.0409 moles

Finally, we can use the formula above to calculate the volume of the solution:

0.140 M = 0.0409 moles / volume of solution in liters

Volume of solution in liters = 0.0409 moles / 0.140 M = 0.2929 L

Converting to milliliters, we get:

Volume of solution in milliliters = 0.2929 L x 1000 mL/L = 292.9 mL

Therefore, the volume of the solution is 292.9 mL.

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how would you draw a bohr rutherford diagram for Fluorine-19 ? Explain your thought process and say how many electrons it has and where each electron would go?

Answers

To draw the Bohr-Rutherford diagram for fluorine-19, we begin by identifying the atomic number of fluorine, which is 9. This means that a neutral fluorine atom has 9 electrons.

The Bohr-Rutherford diagram represents the electron shells or energy levels of an atom, with each shell holding a certain number of electrons. The first shell holds a maximum of 2 electrons, while the second shell holds a maximum of 8 electrons.

Based on this information, we divide the 9 electrons of fluorine into the appropriate shells:

1. The first two electrons occupy the first shell (closest to the nucleus). This will completely fill the first shell.

2. The remaining 7 electrons occupy the second shell. However, since the second shell can hold a maximum of 8 electrons, one electron will be placed in each orbital (subshell) before the electrons are paired.

The electron configuration of fluorine-19, arranged in the Bohr-Rutherford diagram, can be represented as follows:

      1st shell: 2nd shell:

        (2) (7)

The numbers in parentheses indicate the number of electrons in each shell. In this case, the first shell has 2 electrons and the second shell has 7 electrons.

It is important to note that the Bohr-Rutherford diagram provides a simplified representation of the electron distribution and does not account for the more complex orbital arrangements. However, it provides a basic visual understanding of the electron configuration in an atom.

Briefly, fluorine-19 has a Bohr-Rutherford diagram with 2 electrons in the first shell and 7 electrons in the second shell, for a total of 9 electrons.

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Which statement about balanced chemical equations is true?
OA. The mass of the new atoms that are formed equals the mass of
the atoms that made up the reactants.
OB. The total mass of the reactants equals the total mass of the
products.
OC. The total number of moles of products equals the total number of
moles of reactants,
OD. The mass of the products is greater than the mass of the
reactants when the number of moles increases.
SUBMIT

Answers

The total mass of the reactants equals the total mass of the products the statement about balanced chemical equations is true. Hence, option B is correct.

This is known as the Law of Conservation of Mass, which states that matter can neither be created nor destroyed in a chemical reaction. In other words, the mass of the reactants must equal the mass of the products in a balanced chemical equation.

While the identities of the atoms may change during a reaction, the total number of atoms of each element on both sides of the equation must be the same, thus leading to the conservation of mass.

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LOOK AT TABLE 2 WHAT IS THE RELATIONSHIP BETWEEN THE NUMBER OF CARBON ATOMS IN ON MOLECULE OF ALCOHOL AND THE HEAT ENERGY RELEASED WHEN 1g OF THE ALCOHOL OS BURNED.

Answers

The relationship between the number of carbon atoms in one molecule of alcohol and the heat energy released when 1g of the alcohol is burned is not straightforward from the data in Table 2.

What other observable relationships are there?

Observe that the heat energy released varies for each alcohol. In general, alcohols with more carbon atoms in their molecules tend to release more heat energy when burned compared to those with fewer carbon atoms.

This is because larger alcohols have more bonds that can be broken and reformed during combustion, leading to the release of more energy. However, this relationship does not hold for all alcohols, as can be seen from the data for alcohols with 2 and 4 carbon atoms.

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How many water molecules is in 1liter of water

Answers

Multiplying by Avogadro's number we find that 55.6 moles of water contains 3.34 × 1025 molecules.

Answer:

A molecular weight often is simply referred to as a mole. Thus, 1 L of water contains 55.6 moles of water. Multiplying by Avogadro's number we find that 55.6 moles of water contains [tex]3.34 * 10^2^5[/tex] molecules.

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Pls brainliest...

Elements are organized in the....... by increasing atomic number

Answers

The periodic table is a tool used by chemists to organize the elements based on their properties and characteristics. The table is arranged in rows and columns, with the rows being called periods and the columns called groups. The elements in the table are organized in order of increasing atomic number.

Atomic number refers to the number of protons in the nucleus of an atom. Elements with the same number of protons have similar properties, which is why they are grouped together in the periodic table. The number of protons also determines an element's placement in the table. Elements with fewer protons are located on the left side of the table, while those with more protons are located on the right side.
The periodic table also has a unique arrangement of blocks, which are based on the electron configuration of the elements. The s-block elements are located on the left side of the table, followed by the p-block elements on the right. The d-block elements are located in the middle, and the f-block elements are located at the bottom of the table.
The periodic table is a powerful tool for understanding the behavior of the elements, and it has been instrumental in the development of modern chemistry. Its organization by increasing atomic number allows for easy comparison of the elements and their properties, which has led to many important discoveries and advancements in the field of chemistry.

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2. Show the calculation supporting the claim that atmospheric pressure near sea level corresponds to the pressure exerted by a column of mercury that is about 760 mm high. Considering the density of mercury = 13.6 g/cm³.​

Answers

The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm.

To calculate the pressure exerted by a column of mercury, we can use the formula:

Pressure = density * gravity * height

Given:

Density of mercury = 13.6 g/cm³

Height of the mercury column = 760 mm = 76 cm

Acceleration due to gravity = 9.8 m/s²

First, we need to convert the height of the mercury column from centimeters to meters:

Height = 76 cm * (1 m / 100 cm) = 0.76 m

Now, we can calculate the pressure:

Pressure = 13.6 g/cm³ * 9.8 m/s² * 0.76 m

To ensure consistent units, we need to convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³):

Density = 13.6 g/cm³ * (1 kg / 1000 g) * (1 cm³ / (1e-6 m³))

Density = 13600 kg/m³

Plugging in the values into the pressure formula:

Pressure = 13600 kg/m³ * 9.8 m/s² * 0.76 m

Pressure = 99992.8 Pa

We can express the pressure in terms of atmospheric pressure:

1 atm = 101325 Pa (approximately)

To compare the pressure with atmospheric pressure, we can convert 99992.8 Pa to atm:

Pressure in atm = 99992.8 Pa / 101325 Pa/atm

Pressure in atm ≈ 0.987 atm

The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm. Since atmospheric pressure near sea level is approximately 1 atm, this calculation supports the claim that atmospheric pressure near sea level is equivalent to the pressure exerted by a column of mercury about 760 mm high.

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CaS + AlC → A + CaC Balance this equation.

Answers

The balanced chemical equation of CaS + AlC → A + CaC is  CaS + AlC → A + CaCS, ensuring that the number of atoms is equal on both sides.

The chemical equation given is:

CaS + AlC → A + CaC

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Let's go through the balancing process step by step:

Calcium (Ca): There is one Ca atom on the left side and one on the right side, so Ca is already balanced.

Sulfur (S): There is one S atom on the left side and none on the right side. To balance sulfur, we need to add an S atom on the right side.

CaS + AlC → A + CaCS

Aluminum (Al): There is one Al atom on the left side and one on the right side, so Al is already balanced.

Carbon (C): There is one C atom on the left side and one on the right side, so C is already balanced.

Now the balanced equation is:

CaS + AlC → A + CaCS

In this balanced equation, we have one calcium atom, one sulfur atom, one aluminum atom, and one carbon atom on both sides, ensuring that the law of conservation of mass is satisfied.

It's important to note that the "A" in the balanced equation represents an unknown product and may require further experimentation or information to determine its identity. Additionally, the compound "CaCS" is not a commonly known compound, so further investigation would be needed to verify its existence and properties.

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References
Use the References to access important values if needed for this question.
When 22.0 ml, of a 5.25 x 10-4 M cobalt(II) fluoride solution is combined with 12.0 mL of a 6.18 x 10-4 M sodium sulfide solution does a precipitate form?
Kp (COS) 5.9 x 10-21)
=
O Yes, the precipitate forms.
O No, the precipitate doesn't form.
For these conditions the Reaction Quotient, Q, is equal to

Answers

When 22.0 ml, of a [tex]5.25 x 10^{-4[/tex] M cobalt(II) fluoride solution is combined with 12.0 mL of a [tex]6.18 * 10^{-4[/tex] M sodium sulfide solution does a precipitate form, the answer is: No, the precipitate doesn't form.

The balanced chemical equation for the reaction between cobalt(II) fluoride and sodium sulfide is:

[tex]CoF_2[/tex](aq) + Na2S(aq) → CoS(s) + 2NaF(aq)

To determine if a precipitate will form, we need to calculate the reaction quotient, Q, using the initial concentrations of the reactants. The expression for Q is:

Q = [tex][CoS][NaF]^2[/tex] / [CoF2]

where the square brackets denote molar concentrations.

Using the given volumes and concentrations, we can calculate the initial number of moles of each species:

moles CoF2 = [tex](22.0 mL / 1000 mL/L) * (5.25 * 10^-^4 M) = 1.155 * 10^-^5[/tex] mol

moles Na2S = [tex](12.0 mL / 1000 mL/L) * (6.18 * 10^-^4 M) = 7.416 * 10^-^6[/tex] mol

Because the reaction stoichiometry shows that 1 mol of CoF2 reacts with 1 mol of Na2S to form 1 mol of CoS, the amount of CoS formed will be equal to the lesser of these two values, which is 7.416 x 10^-6 mol.

The molar concentration of CoS in the resulting solution will be:

[CoS] = [tex](7.416 * 10^-^6 mol) / (34.0 mL / 1000 mL/L) = 2.181 * 10^-^4 M[/tex]

The molar concentrations of NaF and CoF2 in the resulting solution will be:

[NaF] = [tex](2 x 7.416 x 10^-6 mol) / (34.0 mL / 1000 mL/L) = 4.363 x 10^-4 M[/tex]

[CoF2] = [tex](1.155 x 10^-5 mol) / (34.0 mL / 1000 mL/L) = 3.398 x 10^-4 M[/tex]

Substituting these values into the expression for Q, we get:

Q = [tex](2.181 * 10^-^4)(4.363 * 10^-^4)^2 / (3.398 * 10^-^4) = 1.251[/tex]

Comparing the value of Q to the equilibrium constant Kp, we can see that Q is much greater than Kp (Q > Kp), indicating that the reaction will proceed in the reverse direction to reach equilibrium, and no precipitate will form.

Therefore, the answer is: No, the precipitate doesn't form.

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When a mixture of 1,20 g H2(g) and 7.45 g CO are allowed to
react, how many moles of methanol could be produced?

Answers

When a mixture of 1,20 g H2(g) and 7.45 g CO are allowed to react, 0.2659 moles of methanol could be produced from the given mixture.

The balanced chemical equation for the reaction between H2 and CO to form methanol (CH3OH) is:

H2(g) + CO(g) → CH3OH(l)

To determine how many moles of methanol could be produced, we need to first determine the limiting reactant.

This is the reactant that will be completely consumed in the reaction and will limit the amount of product that can be formed.

The molar mass of H2 is 2.016 g/mol, so 1.20 g of H2 is:

1.20 g H2 × (1 mol H2/2.016 g H2) = 0.5952 mol H2

The molar mass of CO is 28.01 g/mol, so 7.45 g of CO is:

7.45 g CO × (1 mol CO/28.01 g CO) = 0.2659 mol CO

Now we can use the mole ratio from the balanced equation to determine which reactant is limiting:

1 mol H2 : 1 mol CO : 1 mol CH3OH

0.5952 mol H2 : 0.2659 mol CO : x mol CH3OH

The limiting reactant is CO, since it produces less moles of CH3OH than the H2. Therefore, the amount of methanol that could be produced is:

0.2659 mol CO × (1 mol CH3OH/1 mol CO) = 0.2659 mol CH3OH

Thus, 0.2659 moles of methanol could be produced from the given mixture.

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Bombardment of alumninum-27 by alpha particles produces phosphorus-30 and one other article. Write the nuclear equation for this reaction and identify the other particle.

Answers

The complete nuclear equation for this reaction is:

^27Al + ^4He → ^30P + ^1n

The bombardment of aluminum-27 by alpha particles can produce phosphorus-30 and one other particle. An alpha particle consists of two protons and two neutrons, which means it has the same composition as a helium nucleus (He). Therefore, we can write the nuclear equation for this reaction as follows:  ^27Al + ^4He → ^30P + X

Where X represents the other particle produced in the reaction.

To balance the equation, we need to ensure that the total number of protons and neutrons on both sides is the same. On the left side, we have 27 protons and 31 neutrons, while on the right side we have 15 protons and 15 neutrons (since phosphorus-30 has 15 protons and 15 neutrons). Therefore, the other particle produced must have 12 protons and 16 neutrons to balance the equation.

The other particle produced is a neutron (n), which has no charge and a mass of approximately 1 atomic mass unit.

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Element Q is a theoretical nonmetal with atomic number 59. Consider the isotope: Q-123. How many neutrons are in an atom of Q-123 if the atom has a charge of -1?

Answers

There are 64 neutrons in an atom of Q-123 with a charge of -1.

Since the isotope Q-123 has an atomic number of 59, we know that it has 59 protons. The charge of -1 tells us that the atom has one more electron than protons, so it has 60 electrons.

To find the number of neutrons, we need to subtract the atomic number (59) from the mass number (123):

Number of neutrons = Mass number - Atomic number

Number of neutrons = 123 - 59

Number of neutrons = 64

Hence there are 64 neutrons in an atom of Q-123 with a charge of -1. It is important to note that the charge does not affect the number of neutrons in the atom, only the number of electrons. The number of protons and neutrons in the nucleus of an atom determine its identity and chemical properties.

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g) explain why All group VIII elements are gases at room temperature

Answers

Answer:

The Group 8A elements are essentially chemically inert and have a full octet of eight valence electrons in their highest-energy orbitals (ns2np6), so these elements have very little tendency to gain or lose electrons to form ions, or share electrons with other elements in covalent bonds. This is the most stable arrangement of electrons, so noble gases rarely react with other elements and form compounds. Under standard conditions all members of the noble gas group behave similarly. All are monotomic gases under standard conditions.

write and balance an equation for a reaction in which iron (Fe) and Hydrochloric Acid (HCL) react to form Iron cloride (FeCl2) and Hydrogen (H2)

Answers

The balanced equation for the reaction between iron (Fe) and hydrochloric acid (HCl) to form iron chloride (FeCl2) and hydrogen (H2) is: Fe + 2HCl → FeCl2 + H2


This equation represents a single-displacement reaction in which iron displaces hydrogen from hydrochloric acid, resulting in the formation of iron chloride and hydrogen gas. The coefficients in the equation show that one molecule of iron reacts with two molecules of hydrochloric acid to produce one molecule of iron chloride and one molecule of hydrogen gas. To balance this equation, we need to ensure that the number of atoms of each element on both sides of the equation is the same. In this case, we have one iron atom on both sides, two hydrogen atoms on the reactant side, and two hydrogen atoms on the product side. We also have two chlorine atoms on the product side and none on the reactant side. To balance the equation, we add a coefficient of 2 in front of hydrochloric acid and in front of hydrogen gas: Fe + 2HCl → FeCl2 + 2H2
This balanced equation shows that one molecule of iron reacts with two molecules of hydrochloric acid to produce one molecule of iron chloride and two molecules of hydrogen gas.

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Please Help!!50 points and I’ll mark as brainliest!
Tasks are in the picture.

Answers

1) The pH is 2.5

2) The pH is 11.5

3) The initial concentration is[tex]2.1 * 10^-14[/tex]M

What is the pH?

pH is a measure of the acidity or basicity of a solution. It is defined as the negative logarithm of the concentration of hydrogen ions in the solution.

1) The pH of the solution can be gotten from;

K = [tex]x^2[/tex]/0.65 - x

[tex]1.754 * 10^-5[/tex](0.65 - x) =  [tex]x^2[/tex]

[tex]1.14 * 10^-5 - 1.754 * 10^-5x = x^2\\x^2 + 1.754 * 10^-5x - 1.14 * 10^-5 = 0[/tex]

x = 0.003 M

pH = -log(0.003)

= 2.5

2) Kb = [tex]x^2[/tex]/0.35 - x

[tex]1.8 * 10^-5 (0.35 - x) = x^2\\6.3 * 10^-6 - 1.8 * 10^-5x = x^2\\x^2 + 1.8 * 10^-5x - 6.3 * 10^-6 = 0[/tex]

x = 0.003 M

pOH = -log (0.003)

= 2.5

pH = 14 - 2.5 = 11.5

3) Hydrogen ion concentration = Antilog (-11.5)

= 3.2 * 10^-12 M

[tex]4.9 * 10^-10 = ( 3.2 * 10^-12)^2/x \\4.9 * 10^-10x = ( 3.2 * 10^-12)^2\\x = ( 3.2 * 10^-12)^2/4.9 * 10^-10\\x = 2.1 * 10^-14 M[/tex]

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NEED HELP FAST!

Hydrogen covalently bonds with nitrogen to form the compound ammonia. Nitrogen becomes MORE chemically stable because

Question 4 options:

Hydrogen transfers an electron from nitrogen to fill it's outer energy level.


it partially fills its outer energy level with shared electrons from hydrogen.


Hydrogen acquires transferred electrons from nytrogen leaving nytrogen with 6 outer electrons.


it partially fills its outer energy level with transferred electrons from hydrogen.

Answers

Nitrogen becomes more chemically stable when it forms a covalent bond with hydrogen to form the compound ammonia (NH3). The stability of the nitrogen in this compound is primarily due to the sharing of electrons between the nitrogen and hydrogen atoms.

In a covalent bond, atoms share electrons to achieve a more stable electron configuration. Nitrogen has five electrons in its outer energy level, which means it needs three more electrons to fill its outer energy level and achieve a stable configuration. On the other hand, hydrogen has one electron in its outer energy level and needs one more electron to complete its outer energy level.

When nitrogen and hydrogen combine to form ammonia, each hydrogen atom shares one electron with the nitrogen atom, and in turn, the nitrogen atom shares one of its electrons with each hydrogen atom. This sharing of electrons allows nitrogen to partially fill its outer energy level, completing a stable eight-electron configuration. Hydrogen, in turn, partially fills its outer energy level with a transferred electron from nitrogen.

By sharing electrons, the nitrogen in ammonia acquires a more stable electron configuration that resembles the stable configuration of noble gases. This stability contributes to the overall stability of the ammonia molecule. The covalent bond in ammonia provides a balance of electron sharing, allowing both nitrogen and hydrogen to achieve more favorable and stable electron configurations than they would individually.

In short, nitrogen becomes chemically more stable in the ammonia compound because it partially fills its outer energy level with shared electrons from hydrogen. This sharing of electrons allows the nitrogen to achieve a stable configuration, which contributes to the stability of the ammonia molecule as a whole.

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Answer:

it partially fills its outer energy level with shared electrons from hydrogen.

Explanation:

Which two substances are among the six most abundant elements in living things?

A. Potassium
B. Sodium
C. Phosphorus
D. Oxygen

Answers

Oxygen and phosphorus

Initially, a 0.3 m³ spring-loaded piston-cylinder assembly contains R-134a at 600 kPa and 150°C. The refrigerant temperature was cooled to -30°C and the volume was 0.1 m³. Calculate the transfer of 151 and the work produced by the refrigerant during this process.

Answers

The work produced by the refrigerant during this process is 163.27 kJ, and the transfer of heat is -825.63 kJ. The negative sign indicates that heat is being removed from the refrigerant.

To calculate the transfer of heat and work produced during this process, we can use the first law of thermodynamics, which states that the change in internal energy of a closed system is equal to the heat added to the system minus the work done by the system. First, we need to determine the initial and final states of the refrigerant. The initial state is 600 kPa and 150°C, and the final state is -30°C and a volume of 0.1 m³. We can use the refrigerant tables to determine the specific volume and internal energy of the refrigerant at each state. From the tables, we find that the specific volume of the refrigerant at the initial state is 0.0551 m³/kg and the internal energy is 770.68 kJ/kg. At the final state, the specific volume is 0.001344 m³/kg and the internal energy is 108.32 kJ/kg. Using the first law of thermodynamics, we can calculate the transfer of heat and work produced during this process as follows:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the transfer of heat, and W is the work produced by the refrigerant.

ΔU = U2 - U1 = 108.32 kJ/kg - 770.68 kJ/kg = -662.36 kJ/kg

Q = ΔU + W

W = -Q + ΔU = -mCp(T2 - T1) + ΔU

where m is the mass of the refrigerant, Cp is the specific heat capacity of the refrigerant, T1 is the initial temperature, and T2 is the final temperature.

Assuming a mass of 1 kg for the refrigerant, the specific heat capacity of R-134a at constant pressure (Cp) is 1.51 kJ/kgK. Plugging in the values, we get:

W = -mCp(T2 - T1) + ΔU

W = -1 kg x 1.51 kJ/kgK x (-30°C - 150°C) + (-662.36 kJ/kg)

W = 163.27 kJ

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When a 20.2 mL sample of a 0.382 M aqueous hydrocyanic acid solution is titrated with a 0.421 M aqueous barium hydroxide solution, what is the pH after 13.7 mL of barium hydroxide have been added?

Answers

The concept molarity is used here to determine the pH after adding 12.6 mL of the base. The term molarity is an important method which is used to calculate the concentration of a solution. Here the pH is 1.23.

The term molarity is defined as the number of moles of the solute dissolved per litre of the solution. It is also called the molar concentration. It is represented as 'M' and its unit is mol / L.

Molarity is given as:

M = Number of moles / Volume of solution in liters

'n' of HCN = 20.2 × 1 L / 1000 mL × 0.382 = 0.0077 mol

'n' of Ba(OH)₂ = 13.7 × 1L / 1000 mL × 0.421 = 0.0057 mol

Excess H⁺ = 0.002

Total volume = 20.2 + 13.7 = 33.9 mL = 0.0339 L

Concentration of H⁺ = 0.002 / 0.0339 = 0.058

So pH is:

pH = - log[H⁺]

pH = - log[ 0.058] = 1.23

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Personal values have a direct impact on how people treat personal and
nvironmental health. Explain this statement.

Answers

Personal values can have a direct impact on how people treat personal and environmental health, as these values shape an individual's attitudes and behaviors towards health and well-being.

Personal values are the beliefs and principles that guide an individual's behavior and decision-making. These values are shaped by a variety of factors, including culture, upbringing, education, and life experiences.

Similarly, an individual who values environmental health and sustainability may be more likely to engage in environmentally friendly behaviors, such as recycling, reducing energy consumption, and using sustainable products. In contrast, an individual who does not value environmental health may be less likely to engage in these behaviors.

Overall, personal values play a critical role in shaping an individual's attitudes and behaviors towards personal and environmental health. By understanding the impact of personal values on health-related decisions, individuals can become more conscious of their values and how they influence their actions, leading to more positive health outcomes and a more sustainable environment.

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