Balok diam diatas bidang miring pada sudut kemiringan 40° balok mulai bergerak,tentukan koefisien gesek statis antara balok dan bidang miring

Answers

Answer 1

Answer:

0.84

Explanation:

m = Massa balok

g = Percepatan gravitasi

[tex]\theta[/tex] = Sudut kemiringan

[tex]\mu[/tex] = Koefisien gesekan statik antara balok dan bidang miring

Gaya balok karena beratnya diberikan oleh

[tex]F=mg\sin\theta[/tex]

Gaya gesekan diberikan oleh

[tex]f=\mu mg\cos\theta[/tex]

Kondisi dimana balok mulai bergerak adalah ketika gaya balok akibat beratnya sama dengan gaya gesek pada balok.

[tex]mg\sin\theta=\mu mg\cos\theta\\\Rightarrow \mu=\dfrac{mg\sin\theta}{mg\cos\theta}\\\Rightarrow \mu=\tan\theta\\\Rightarrow \mu=\tan40^{\circ}\\\Rightarrow \mu=0.84[/tex]

Koefisien gesekan statik antara balok dan bidang miring adalah 0.84.


Related Questions

why malleability is a useful property

Answers

Malleability is a useful property because it allows many products to be made in manufacturing.

Free fall acceleration
I need help?!!

Answers

Explanation:

if g is 10ms^-1

answers are

1-10

2-20

3-30

4-40

5-50ms^-1

How do simple
machines magnify
forces?

Answers

Answer:

Motion at one end of the beam results in motion at the other end in the opposite direction.

Explanation:

The location of the fulcrum can magnify (or reduce) the force applied at one end at the expense (or advantage) of the distance over which the other end travels. Sorry if I get this wrong! I am in 5th grade. ♥

A book is resting on a table. The table is raised on one end to an angle of 15° to the floor. If the book remains at rest, what keeps the book from sliding?
A. rolling friction
B. static friction
C. sliding friction
D. fluid friction​

Answers

Answer: Static Friction

Explanation: As you tilt the book you know that it will stay fixed to start with, but eventually, once the angle is large enough, the book will start to slide. It is the static friction force that holds the book in place at small angles of tilt.

The book remains at rest if A book is resting on a table. The table is raised on one end to an angle of 15° to the floor due to static friction, so option C is correct.

What is static friction?

An item is kept at rest by the force of static friction. The phrase "static friction" can be defined as "the friction people perceive when they attempt to move a stationary object on a surface, but without actually causing any relative motion between the body and the surface it is on."

You can predict that the book will initially remain fixed when you tilt it, but once the angle is sufficiently large, it will finally begin to slide. The book is held in place at slight tilt angles by static friction force.

The formula for the coefficient of static friction is μ = tan θ, here θ is the angle of inclination if the angle is bigger the friction force is more but at 90° when the book is vertical then the friction force will not work on the book

Therefore, the book remains at rest if A book is resting on a table. The table is raised on one end to an angle of 15° to the floor due to static friction.

To know more about static friction:

https://brainly.com/question/17237604

#SPJ2

Think about what you observed in the Sim and the information the lead chemist sent you about the soda can. Which substance in the Sim best represents water (substance B or C)? Explain your answer in the space below.

Answers

Answer:

Substance C.

Explanation:

Substance C changed phase by condense and melted faster than substance B, which best represents liquid.

how many electrons does a neutral atom of the element iron (fe) have?

Answers

Answer:

26 electrons

A neutral iron atom contains 26 protons and 30 neutrons plus 26 electrons in four different shells around the nucleus. As with other transition metals, a variable number of electrons from iron's two outermost shells are available to combine with other elements

Explanation:

hope this helps have a good rest of your night :) ❤

A young man exerted a force of 9,000 N on a stalled car but was unable to move it. How much work was done?

Answers

W=F*s
W=9000*0
W=0
W:Work
F:Force
s:Distance

all energy,potential kinetic within a specific system

a)joule

b) total energy

c) potential energy

Answers

Answer:

C

Explanation:

The potential and kinetic energy within a specific system is called the total energy of the system.

Option B is the correct answer.

Potential and Kinetic Energy

The energy of the specific system due to its steady position is defined as the potential energy of the system.

The energy of the system which is stored due to the motion of the system is called the kinetic energy of the system.

The mechanical energy of the system is the total energy within the system including its kinetic and potential energy.

The sum of kinetic and potential energy is known as mechanical energy. An object's mechanical energy is defined as the total energy which is stored during its steady position and stored during the motion of the object.

Hence we can conclude that option B represents the correct answer for the given statement.

To know more about the potential and kinetic energy, follow the link given below.

https://brainly.com/question/21288807.

What is the mass, in grams, of 2.00 moles of H2O?

Answers

Answer:

36g

Explanation:

Given parameters:

Number of moles of H₂O = 2moles

Unknown:

Mass of  H₂O = ?

Solution:

To solve this problem, use the expression below:

   Mass of  H₂O = number of moles x molar mass

Molar mass of  H₂O = 2(1) + 16  = 18g/mol

  Mass of  H₂O = 2 x 18  = 36g

A roller coaster of mass 2000 kg is rolling down a track with an
instantaneous speed 10 m/s. What is its kinetic energy in Joules?

Answers

Answer: 100k Joules

Explanation:

How are deceleration and acceleration related?

Answers

Answer:

Deceleration is reverse of acceleration

1. Suppose that a log is burning in a fireplace. The log contains chemical energy. Light,
heat, and some sound are given off as the log burns. How does this demonstrate the
law of conservation of energy?
A.
B.
The total amount of energy in the universe changes.
Energy is destroyed.
Energy is created.
Energy is converted from one form to another.
C.
D.

Answers

Answer:

energy is converted in one form to another

Explanation:

please give brainlest need 3 more

What is a real world example of the Law of Conservation of Momentum?

Answers

Answer:

The thrust that you feel at the time of firing is one of the real-life example of the conseriation nomentum

CO + 7H2 - C3Hg + 3H20

Answers

Answer:

Espanol 7h2 that's c coupon

A tennis ball covers a distance of 12 meters in 0.4 seconds what is the velocity of the tennis ball?

Answers

V=d/t
V=12/0.4
V=30 m/s

Answer:

30m/s

Explanation:

Given parameters:

Distance  = 12m

Time taken  = 0.4s

Unknown:

Velocity of the tennis ball = ?

Solution:

Velocity of a body is the displacement per unit of time.

  Velocity  = [tex]\frac{displacement}{time}[/tex]  

So;

      Velocity  = [tex]\frac{12}{0.4}[/tex]   = 30m/s

An object is placed 1.0 cm from a convex mirror with a focal length of 4.0 cm.

Answers

Answer:

image distanc=-0.8cm

Explanation:

.8 is the answer, sorry I do not have the proof.
But the other guy DOES NOT know how to write.

If the half-life of tritium (hydrogen-3) is 12.3 years, how much of
a 10 g sample of tritium is present after 250.0 years?

Answers

Answer:

0.0000076 grams

Explanation:

We're given the half life of Tritium to be 12.3 years. In order to find out the amount of substabce remaining:

Let's first find how many 'half lives' are in 250 years.

[tex]n = \frac{250}{12.3} = 20.325[/tex]

Now what is half life? It means the time taken for a given quantity of an element to lose half it's mass.

So in 12.3 years we can find that The amount of 250 g of Tritium will be 250/2 = 125 g. In 24.6 years we'll have 125/2 = 62.5 g

So now we can devise a formula:

[tex]m = \frac{original \: amount}{ {2}^{n} } [/tex]

Where m is the remaining amount and n is th number of half lives in the time given.

Using this formula we can calculate:

[tex]m = \frac{10}{ {2}^{20.325} } [/tex]

Doing this calculation we get:

[tex]m = 0.0000076 \: g[/tex]

As we can see a very small value remains.

Please help with these questions!!!!!

Answers

Answer:

4.c

5.d

6.c

Explanation:

Zad. 2 W marszobiegu chłopiec przebiegł 900 m w ciągu 205 min, a następnie przeszedł 300m w tym danym czasie. Jaka była średnia prędkość chłopca podczas marszobiegu?

Answers

Odpowiedź:

0,049 m / s

Wyjaśnienie:

Biorąc pod uwagę, że:

Dystans biegu = 900m

Czas trwania = 205 minut

Długość przejścia = 300 m

Zajęty czas = 205 minut

Średnia prędkość :

(Przebieg + pokonany dystans) / całkowity czas

Średnia prędkość :

(900 m +. 300 m) / 205 + 205

1200 m / 410 minut

Minuty do sekund

1200 / (410 * 60)

1200/24600

= 0,0487804

= 0,049 m / s

What conditions would you expect to find during an effusive eruption?

Answers

Answer:

Effusive eruptions occur when hot, (1200oC) runny basalt magmas reach the surface. Dissolved gases escape easily as the magma erupts, forming lava that flows downhill quite easily. Effusive eruptions build up gently-sloping Shield Volcanoes like Hawaii.

DUE TONIGHT 50 POINTS
An applied force of 13 N east acts on a 6.5-kg block that is moving east at 2.5 m/s on a level, frictionless surface. What is the final speed
of the block if the force is applied for 2.1 s?
A. 1.7 m/s
B. 4.2 m/s
C. 6.7 m/s
D. 7.2 m/s

Answers

F = m a
13 = 6.5 a

a = 2 m/s²

Vf = Vi + a t
Vf = 2.5 + 2(2.1)
Vf = 2.5 + 4.2
Vf = 6.7 m/s

Answer is C
The answer to this question is c

A toy car is allowed to roll down a ramp during an experiment. While it is on the ramp, gravity acts on the car as an unbalanced force. Which of the following graphs best illustrates the car’s velocity as a function of time while it is on the ramp?

Answers

Answer:

When an unbalanced force acts on an object, the motion of the object is changed. If the object is at rest, the force makes it move. If the object is in motion, the force changes its velocity. Any change in velocity is acceleration

Explanation:

jayfeather friend me

9. A 12 v battery is connected to four 5 ohm light bulbs. What is the equivalent
resistance for the bulbs in series? In parallel?

10. What would be the current through each light of problem 9?
For parallel circuit?
For series circuit?

-no bs answers

Answers

20 ohms 5 ohms
12volts

Two charges separated by one meter exert a 9 N force on each other. If the charges are pushed to a 3 meter separation, the force on each charge will be 3 N.
True or False?

Answers

Answer:

False

Explanation:

The formula of force that exists between two charges is expressed as;

F = kq1q2/r²

If two charges separated by one meter exert a 9 N force on each other, the;

9 = kq1q2/1²

9 = kq1q2 ..... 1

If the charges are pushed to a 3 meter separation, then;

F =  kq1q2/3²

F =  kq1q2/9 .... 2

Divide both equations;

9/F = (kq1q2)/ kq1q2/9

9/F =  kq1q2 * 9/ kq1q2

9/F = 9

F = 9/9

F = 1N

Hence if the charges are pushed to a 3 meter separation, then the force on EACH charge will be 1N. Hence the answer is False

The whale shark the largest of fish and can have the mass of three adult elephants. Suppose that a crane is whale shark into a tank for delivery to an aquariumThe crane must exert an unbalanced force of 2.5 * 10 ^ 4 to lift the shark from rest. If the shark's acceleration equals 1.25 m/s ^ 2 , what is the shark's mass?

Answers

Answer:

Mass, m = 20000 kg

Explanation:

The force acting on the shark, [tex]F=2.5\times 10^4\ N[/tex]

Acceleration of the shark, a = 1.25 m/s²

We need to find the mass of the Shark. The force acting on an object is given by :

F = ma

m is the shark's mass

So,

[tex]m=\dfrac{F}{a}\\\\m=\dfrac{2.5\times 10^4}{1.25}\\\\m=20000\ kg[/tex]

So, the mass of the Shark is 20000 kg.

does this man look okay? hes all pink and stuff O_O hes teaching me frickin science

Answers

Answer:

He is pink panther. How nerdy does he sound?

Explanation:

A 136 kg defensive lineman is about to tackle a 100 kg quarterback. Right before
impact, the lineman is moving north at 6.0 m/s and the quarterback is moving
north at 1.0 m/s. Determine the speed and direction of the two players
immediately after the tackle.

Answers

Answer:

3.88 m/s North

Explanation:

We are given that

[tex]m_1=136kg[/tex]

[tex]m_2=100 kg[/tex]

[tex]v_1=6 m/s[/tex]

[tex]v_2=1m/s[/tex]

We have to find  the speed and direction of the two players

immediately after the tackle.

Using linear conservation of momentum

[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]

Substitute the values

[tex]136\times 6+100\times 1=(136+100)v[/tex]

[tex]916=236v[/tex]

[tex]v=\frac{916}{236}[/tex]

[tex]v=3.88m/s[/tex]

Direction of  the two players  immediately after the tackle is North.

In zero gravity, do the laws of motion still apply? No, objects cannot
be in
motion in
space because
there is no gravity.
No, if you do not
have gravity you
have no motion.
Yes, objects in
motion in space do
not have inertia.
Yes, objects in motio
in space tend to stay
motion unless acte
upon by an outside
force.

Answers

Answer:

Im pretty sure that it applys

I’m pretty sure it does hope this helps you

Force (N) = 250
Mass (kg) = 221
Acceleration (m/s^2) = ?

Answers

Answer:

The required acceleration is [tex]a=1.1[/tex] m/s²

Explanation:

Given

Force F = 250 NMass m = 221 kg

To determine

Acceleration a = ?

We know that acceleration is produced when a force is applied to a body.

The acceleration can be determined using the formula

[tex]F = ma[/tex]

where

F is the force m is the mass a is the acceleration

now substituting F = 250 , and m = 221 in the formula

[tex]F = ma[/tex]

[tex]250 = 221 (a)[/tex]

switch the equation

[tex]221(a) = 250[/tex]

Divide both sides by 221

[tex]\frac{221a}{221}=\frac{250}{221}[/tex]

simplify

[tex]a=\frac{250}{221}[/tex]

[tex]a=1.1[/tex] m/s²

Therefore, the required acceleration is [tex]a=1.1[/tex] m/s²

Potential energy = 0 J Kinetic energy =

Answers

Answer:drfdcfrfvgtgy6hbhhbhyg vcfrfr5tgvcfrtg vcdftghegthetrgbdgtthethe3thet

Explanation:

Sdwerftyrujtnyhbvcrdefgswthyujdehrtgfyhrjfuygtdhjueyrtgehwu3y4tgrehjwheyrgdhbnsjhfgvbdnhgfdhjsdehbrvbdensdvfgreyhsdgrftyhedggrfdhsgfv

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