Based on the data, which statement describes the most reliable way to
encode and transmit data and tells why?
A. Digital waves are more reliable because they are less likely to
change when copied.
B. Analog waves are more reliable because they include a range of
values like the original.
C. Analog waves are more reliable because they are less likely to
change when copied.
D. Digital waves are more reliable because they are slightly different
from the original.

Answer:

Archie must sit 0.58 m relative to the center to keep the see-saw balanced

Explanation:

Given the data in the question;

Mass of Archie [tex]m_{a}[/tex] = 120 kg

Mass of clementine [tex]m_{c}[/tex] = 40 kg

total length of see-saw L = 3.5 m

as illustrated on the image below, Fulcrum is at the center,

suppose Archie sits at a distance x  from center then for balancing, we will have;

[tex]m_{a}[/tex] × x = [tex]m_{c}[/tex] × ( one end = 3.5/2 = 1.75)

so we substitute

120kg × x = 40kg × 1.75m

x12okg = 70 kg.m

x = 70 kg.m / 120 kg

x = 0.58 m

Therefore, Archie must sit 0.58 m relative to the center to keep the see-saw balanced

Answer:

The magnitude of the force each cousin exerts on the dinghy is 183.6 N and 78.4 N.

Explanation:

When the cousins pull in the same direction we have:

[tex] F_{1} + F_{2} = ma_{e} [/tex]   (1)        

Where:

F₁ and F₂ are the forces exerted by the two boys.

m: is the mass of the dinghy = 200 kg

[tex]a_{e}[/tex]: is the acceleration in the east direction

When the cousins pull in opposite directions we have:

[tex] F_{1} - F_{2} = ma_{w} [/tex]   (2)            

By adding equation (1) and (2):                                              

[tex] 2F_{1} = m(a_{e} + a_{w}) [/tex]          

[tex] F_{1} = \frac{200 kg(1.31 m/s^{2} + 0.526 m/s^{2})}{2} = 183.6 N [/tex]    

Now, by entering F₁ into equation (1) we can find F₂:    

[tex] F_{2} = ma_{e} - F_{1} = 200kg*1.31 m/s^{2} - 183.6 N = 78.4 N [/tex]

Therefore, the magnitude of the force each cousin exerts on the dinghy is 183.6 N and 78.4 N.    

I hope it helps you!  

Answer:

The second option - the papers are acted upon by an unbalanced force from the fan.

Explanation:

This question is incomplete, the complete question;

you make an interferometer using 50-50 beam splitter and two mirrors, one being a perfect mirror and one which does not reflect all light. The wavelength of the 9 mW incident laser is 400 nm.

Because the top mirror is not perfectly reflective (it reflects 90% of the photons, allowing 10% of them to go through), the power measured at the detector when only the vertical arm is blocked is 2.25 mW, while the power measured at the detector when only the horizontal arm is blocked is only 2.025 mW. Assume initially the intensity is at its maximum. How much would we need to translate the perfect mirror to the right to get a minimum intensity at detector, and what is that minimum intensity

Options;

a) 200 nm; 0.9 mW

b) 100 nm, 0.0059 mW

c) 200 nm; 0 mW

d) 100 nm; 0.9 mW

e) 200 nm; 0.0059 mW

Answer:

the amount we need to translate the perfect mirror to the right to get a minimum intensity at detector  and the minimum intensity are;

100 nm; 0.0059 mW

Option b) 100 nm, 0.0059 mW is the correct answer

Explanation:

Given that the instrument here is an interferometer.

Maximum intensity is obtained when the two waves are exactly in phase.

that is the peaks (crusts and troughs) and nodes (zero value points) of the two waves will be at the exact same point when the wave falls on the detector.

The phase factor of this point is taken as ∅ = 0

Now, to get a minimum point, the phase difference between the two waves should be should be ∅ = π

This corresponds to a path difference between the two waves as half of the wavelength. λ/2

The light gets reflected from the mirror.

Hence, when we move the mirror by a length l, the extra/less path the light has to travel is 2l (light is going and coming back)

hence, to get a path difference of λ/2 the mirror should move half of this distance only

so, the mirror should move;

[tex]l[/tex] = λ/4

here, wavelength is 400nm

the length moved by the mirror = 400/4 = 100 nm

The intensity is given by the equation;

[tex]l[/tex] = [tex]l[/tex]1 + [tex]l[/tex]2 + 2√[tex]l[/tex]1[tex]l[/tex]2cos(∅)

where

[tex]l[/tex]1 = 2.25 mW

[tex]l[/tex]2 = 2.025 mW

∅ = π

so we substitute

[tex]l[/tex] = 2.25 + 2.025 - 2√(2.25 × 2.025)

[tex]l[/tex] = 4.275 - 4.26907

[tex]l[/tex] = 0.0059

Therefore; the amount we need to translate the perfect mirror to the right to get a minimum intensity at detector  and the minimum intensity are;

100 nm; 0.0059 mW

Option b) 100 nm, 0.0059 mW is the correct answer  

Answer:

nique ta mama  

Explanation:

Answer:

Gravity

Explanation:

Answer:

Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion.  The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving.

Explanation:

Answer:

  λ = 440 nm

Explanation:

The phenomenon of constructive interference is described by the expressions

          d sin θ= m λ                    (1)

where d is the separation of the slits d = 0.0250 mm = 2.50 10⁻⁵ m, lam is the wavelength of the incident radiation and m is an integer indicating the order of interference

let's use trigonometry to find the angle

          tan θ = y / L

where L is the distance to the screen L = 1.25 m

in general interference experiments angles are very small

         tan θ = [tex]\frac{sin \ \theta }{cos \ \theta}[/tex]

         ten θ = sin θ

substituting

         sin θ = y / L

we substitute 1

          d y / L = m λ

          λ = [tex]\frac{ d \ y }{m \ L}[/tex]

in the exercise indicate

        m = 3

         y = 6.6 cm = 6.6 10-2 m

we calculate

          λ = 2.50 10⁻⁵ 6.6 10⁻² /( 3   1.25)

          λ = 4.4 10⁻⁷ m

let's reduce to nm

          λ = 4.4 10⁻⁷ m (10⁹ nm / 1 m)

          λ = 440 nm

Answer:

How do I answer this I don't understand the question

Explanation:

The net force pulling you down the hill will be = 40 N

The Second Law of motion states that the acceleration of an object depend upon the object and the mass of the object.

F = Mass * acceleration

Given

Total mass  : 80 kg

Acceleration : 0.5 m / s^2

Net Force = mass * acceleration      (Second Law of motion )

Net Force = 80 * 0.5  = 40 N

 The net force pulling you down the hill will be = 40 N

Learn more about  Newton's Second Law of motion:

https://brainly.com/question/11553356?referrer=searchResults

#SPJ2

Answer:

he two people agree with your answer

  v_B = v_{oB} - a t

              v_A = cte

Explanation:

To analyze if they are both in Kurdish, let's see the movement of the two cars

at t = 1s

the velocity of carriage B is greater than the speed of carriage a

             v_B> v_A

at t = 2 s

the speed of the two cars is nipple

              v_B = v_A

For this to be true, the speed of car B must be decreasing

              v_B = v_{oB} - a t

              v_A = cte

therefore the two people agree with your answer

Answer:

An object can have both kinetic and potential energy at the same time. ... As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy. Another important concept is work.

Explanation:

Answer:

KE:

energy which a body possesses by virtue of being in motion.

PE:

the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

Explanation:

Your welcome

Answer:

amplitude is the answer

Answer:

Vf = 21 m/s

Explanation:

Data:

Use formula:

Replace:

Multiply the acceleration with time:

Solve the sum:

The velocity of the car at the end of the 3 second interval is 21 meters per second.

Answer:external

Explanation:EDGE 2021

Answer: Fur stuffed with feathers.

Explanation:

Ball games were popular throughout ancient history but also in the Middle Ages. Many of these games are the forerunners of today's American football and soccer. There are data on almost all continents on how peoples practiced some ball sports in antiquity. The game balls' look was not like today, it was mostly egg-shaped, and the materials for making it were different. The most common material for making the ball was leather, which was filled with feathers.

Answer:

25 m/s

Explanation:

Given that:

Initial speed, u = 4 m/s

Final velocity, V = 11 m/s

Time, t = 8 seconds

t2, = 16 seconds

Acceleration, a= (change in velocity) / time interval

a = (11 - 4) / 8

a = 7 / 8 = 0.875m/s²

Final velocity, v2 ;

Acceleration * t2

0.875 * 16 = 14

V2 = 14 m/s

Final speed : v + v2 = (11 + 14)m/s = 25m/s

Answer:

I answered Number 4 (Solids and Elasticity)

Explanation:

solids and elasticity

Answer:

the small angle measurement from the central maximum is

Explanation:

The computation of the small angle measurement is as follows:

The constructive interference condition is

[tex]d \sin \theta = m \lambda \\\\Now \\\\\theta = sin^{-1} (\frac{\lambda}{d}) \\\\= sin^{-1}(\frac{610\times10^{-9}}{0.0250\times10^{-3}} )\\\\= 1.40^{\circ}[/tex]

hence the small angle measurement from the central maximum is [tex]1.40^{\circ}[/tex]

Answer:

A. Doppler ultrasound collects data from moving objects

Explanation:

Did the test !!

Answer:A. Doppler ultrasound collects data from moving objects.

Explanation: just got it right

on my test

Answer:

the magnitude F of the total friction force is 2456.7 lb

Explanation:

Given the data in the question;

maximum speed = 35 mi/hr = ( 35×5280 / 60×60) = 51.3333 ft/s

diameter = 200ft

radius = 200/2 = 100 ft

First we calculate the normal component of the acceleration;

[tex]a_{n}[/tex] = v² / p

where v is the velocity of the car( 51.3333 ft/s)

p is the radius of the curvature( 100 ft)

so we substitute

[tex]a_{n}[/tex] = (51.3333 ft/s)² / 100ft

[tex]a_{n}[/tex] = (2635.1076 ft²/s²) / 100ft

[tex]a_{n}[/tex] = 26.35 ft/s²

we convert Feet Per Second Squared (ft/s²) to Standard Gravity (g)

1 ft/s² = 0.0310809502 g

[tex]a_{n}[/tex] = 26.35 ft/s² × 0.0310809502 g

[tex]a_{n}[/tex] =  0.8189g

Now consider the dynamic equilibrium of forces in the Normal Direction;

∑[tex]F_{n}[/tex] = m[tex]a_{n}[/tex]

F = m[tex]a_{n}[/tex]

we know that mass of the car is 3000-lb =  3000lb([tex]\frac{1}{g}slug[/tex]/1 lb)

so

we substitute

F =  3000lb([tex]\frac{1}{g}slug[/tex]/1 lb)  × 0.8189g

F = 2456.7 lb

Therefore; the magnitude F of the total friction force is 2456.7 lb

Answer:  a) weight on Earth = mass of the object and gravity n the Earth. = 65*10 = 650 kg.

Explanation:

An astronaut has a mass of 65 kg on Earth where the gravitational field strength is 10 N kg A calculate the astronaut's weight on Earth

          hope this helps :)

Answer:

650

Explanation:

use the equation

weight = gm

Answer:

the required height is 0.2449 m only

Explanation:

Given the data in the question;

Initial height = 2m

so speed of the puck before hitting the ground will be;

u² = 2gh

Initial speed u_ball = √2gh

u_ball = √( 2 × 9.8 × 2 )

u_ball =  √39.2

u_ball = 6.26 m/s

given that; FOR THE FROZEN PUCK, coefficient of restitution = 0.35 only

R = - (v_ball - v_ground / u_ball - u_ ground)

so

0.35 = - (v_ball - 0 / 6.26 - 0)

0.35 = -v_ball / - 6.26

-v_ball = 0.35 × (- 6.26)

-v_ball = -2.191 m/s

v_ball = 2.191 m/s

to get the height;

v² = 2gh

h = v² / 2g

we substitute

h = (2.191)² / 2×9.8

h = 4.800481 / 19.6

h = 0.2449 m

Therefore, the required height is 0.2449 m only

Answer:

agricultural production of food

Explanation:

Answer:

a)    F₁ = 267.3 N,   N₁ = 1300 N,  b)    μ = 0.324

Explanation:

For this exercise we use the rotational equilibrium condition, we have a reference system is the floor and the anticlockwise rotations as positive, in the adjoint we can see a diagram of the forces

let's use subscript 1 for the ladder and 2 for the firefighter

            ∑ τ = 0

          -W₁ x₁ - W₂ x₂ + N₁ y = 0

           N₁ = [tex]\frac{W_1 x_1 + W_2 x_2}{y}[/tex]          (1)

the center of mass of the ladder is at its geometric center,

d = L / 2 = 15/2 = 7.5 m

         cos 60 = x₁ / d₁

         x₁ = d₁ cos 60

         x₁ = 7.5 cos 60

         x₁ = 3.75 m

for the firefighter d₂ = 4 m

         cos 60 = x₂ / d₂

         x₂ = d₂ cos 60

          x₂ = 4 cos 60 = 2 m

for the fulcrum d₃ = 15 m

         sin 60 = y / d₃

         y = d₃ sin 60

         y = 15 sin 60

         y = 13 m

we look for the Normal by substituting in equation 1

         N₂ = [tex]\frac{500 \ 3.75 \ + 800 \ 2}{13}[/tex]

         N₂ = 267.3 N

now let's use the translational equilibrium relations

 X axis

           F₁ - N₂ = 0

           F₁ = N₂

           F₁ = 267.3 N

Axis y

          N₁ - W₁ -W₂ = 0

          N₁ = W₁ + W₂

          N₁ = 500 + 800

          N₁ = 1300 N

b) for this case change the firefighter's distance d₂ = 9 m

          x₂ = 9 cos 60

          x₂ = 4.5 m

we substitute in 1

          N₂ = \frac{500 \ 3.75 \ + 800 \ 4.5}{13}  

          N₂ = 421.15 N

of the translational equilibrium equation on the x-axis

          fr = F₁ = N₂

          fr = 421.15 N

friction force has the expression

          fr = μ N

in this case the reaction of the Earth to the support of the ladder is N1 = 1300N

          μ = fr / N₁

          μ = 421.15 / 1300

          μ = 0.324

Explanation:

C. meter per second squared

B. meter per second

A. meter

Answer:

b. meters per second

c.meters per second squared

c.meters

Explanation:

ginawa ko na rin KC toh

Answer:

The answer is B. molecules, atoms, elements, compund, cells, tissues, organs, organ systems, and organism

Answer:

The initial velocity in the x-direction with which the branch was thrown is approximately 10.224 m/s

Explanation:

The given parameters of the motion of the branch are;

The height from which the branch is thrown = 3.00 m

The horizontal distance the branch lands from where it was thrown, x = 8.00 m

The direction in which the branch is thrown = Horizontally

Therefore, the initial vertical velocity of the branch, [tex]u_y[/tex] = 0 m/s

The time it takes an object in free fall (zero initial downward vertical velocity) to reach the ground is given as follows;

s = [tex]u_y[/tex]·t + 1/2·g·t²

Where;

[tex]u_y[/tex] = 0 m/s

s = The initial height of the object = 3.00 m

g = The acceleration due to gravity = 9.8 m/s²

∴ s = 0·t + 1/2·g·t² = 0 × t + 1/2·g·t² = 1/2·g·t²

t = √(2·s/g) = √(2 × 3/9.8) = (√30)/7 ≈ 0.78246

The horizontal distance covered before the branch touches the ground, x = 8.00 m

Therefore, the initial velocity in the horizontal, x-direction with which the branch was thrown, 'uₓ', is given as follows;

uₓ = x/t = 8.00 m/((√30)/7 s)

Using a graphing calculator, we get;

uₓ = 8.00 m/((√30)/7 s) = (28/15)·√30 m/s ≈ 10.224 m/s

The initial velocity in the horizontal, x-direction with which the branch was thrown, uₓ ≈ 10.224 m/s.

Answer:

a = 30.832 ft/s²

Explanation:

To solve this problem let's start by finding the braking acceleration using kinematics, where the distance is x = 408 ft, the initial velocity vo = 100 mi / h and the final velocity is zero v = 0

           v² = v₀² - 2 a x

           0 = v₀² - 2ax

           a = [tex]\frac{v_o^2}{2x}[/tex]

Let's start by reducing the magnitudes to ft / s              

            v₀ = 100 mi / h (5280 foot / 1 mile) (1h / 3600 s) = 146.666 ft / s

let's calculate

         a = [tex]\frac{146.66^2}{2 \ 408}[/tex]

         a = 26.36 ft / s²

Let's call this acceleration a_effective, this acceleration is in the opposite direction to the speed of the vehicle.  

Let's use a rule of three (direct proportions) to find the acceleration applied by the brake system (a1) which has an efficiency of 95%. or 0.95

                 a₁ = [tex]\frac{a_e}{0.95}[/tex]

Let's use another direct proportion rule If the acceleration of the brake system (a₁) for an applied acceleration (a) with an efficiency of 0.90

           a = [tex]\frac{a_1}{0.90}[/tex]

we substitute

           a = [tex]\frac{a_e}{0.95 \ 0.90}[/tex]

let's calculate

           a = [tex]\frac{26.36}{ 0.95 \ 0.90}[/tex]

           a = 30.832 ft/s²

This is the maximum relationship that the vehicle can have for when it brakes to stop at the given distance

Answer:

 h (3) = 0

Explanation:

In this exercise they give us the expression that governs the movement

           h (t) = 5 sin (2πt)

remember that the angles are in radians.

To calculate the instantaneous velocity we substitute

           h (3) = 5 sin (2π 3)

           h (3) = 0

therefore the body this is its position of equilibrium