based on this passage, which of the following might be true about the early history of modern physics? select it had a very practical component select it was uninteresting to most people select none of these select it was often combined with many topics studied in philosophy select it was underdeveloped and primitive

Answers

Answer 1

True statement about the early history of modern physics is option A: it had a very practical component.

The early history of physics could explain everything out of others, thus it had a practical component. The minds of almost all thinkers are left with the patterns of scientific reasoning and apotheosis in modern physics. From the time of the early renaissance to the nineteenth century, physics represented the ultimate expression of scientific investigation for almost all thinkers. The unchanging principles of all motion and life on earth are being derived from its static laws. By the nineteenth century, it seemed that most of science had already been "cleared up," and only a few remaining details remained.

This cosmology was overthrown by the idea of a universal morphing of kinds, which completely altered it. The very view of science held by most people was among the things that had to change in light of Darwin’s work.

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Related Questions

A man runs 300 m west in 60 seconds. He then runs 100m north-west in 20 seconds. What is his average velocity in meter per second?

Answers

Answer:

See below

Explanation:

Total distance = 300 + 100 = 400 meters in 60 + 20 = 80 seconds

   400 m / 80 s = 5 m/s

If you are using DISPLACEMENT:
 displacement =   sqrt  (  ( 300 + 100 cos 45)^2 + (100sin 45)^2 ) = 377.4 m

     in 80 seconds        377.4 / 80 = 4.7 m/s

A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping. What was the initial speed of the bullet?

Answers

The initial speed of the bullet is 2624.7 m/s.

Conservation of momentum indicates that the total momentum of an isolated system remains the same in the absence of an external force. H. Momentum is neither created nor destroyed, but can be changed by the action of forces in the sense of Newton's laws of motion.Momentum is the product of an object's mass and its velocity, which is also equal to the total force required to keep the object at rest.One of the practical aspects of momentum conservation is the collision problem where momentum is conserved and the net external force remains zero.

Mass of bullet, m = 5 g = 0.005 kg

Mass of block, M = 1.2 kg

Coefficient of friction = 0.2

Distance, d = 0.31 m

Let the initial speed of the bullet is u.

Use Conservation of momentum

m u = (M + m) v

0.005 x u = (1.2 +0.005) v

v =  4.2 x 10-4 u m/s

Now, use third equation of motion

v2 = u2 - 2μg s 0 = (4.2 x 10-4 u)2 - 2 x 0.2 x 9.8 x 0.31u = 2624.7 m/s

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1.he discovered details of a lunar surface galileo 2.he invented first reflecting telescope astrolabe 3.he found planets had elliptical orbits refracting telescope 4.he performed a systematic mapping of sky brahe 5.uses a large glass lens newton 6.uses a mirror to focus light radio telescope 7.tool used to determine location of a star reflecting telescope 8.instrument that accumulates light from an object to show more detail camera 9.records sounds of stars kepler

Answers

1. Galileo.

2. Newton.

3. Kepler.

4. Brahe.

5. Refracting telescope.

6. Reflecting telescope.

7. Astrolabe

8. Camera.

9. Radio telescope.

1. Galileo, who uncovered information about the lunar surface.

2. The first reflecting telescope was created by Newton.

3. Kepler discovered elliptical orbits for planets.

4. Brahe: He meticulously mapped the sky.

5. A large glass lens is used in a refractive telescope.

6. A reflecting telescope concentrates light using a mirror.

7. Astrolabe: a device used to pinpoint a star's location.

8. Camera: a device that gathers light from an item to display greater detail.

9. The sound of stars is captured by radio telescopes.

Complete question:

The complete questions is (see in attachments).

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The first several digits of n are known to be x = 3.14159265358979 What is to (a). Three significant figures (b) five significant figures, and (c) seven significant figures? XX​

Answers

Answer:

(a) 3.14

(b) 3.1416

(c) 3.141593

Explanation:

The first several digits of n are known to be x = 3.14159265358979.

(a) To three significant figures, x is 3.14.

(b) To five significant figures, x is 3.1416.

(c) To seven significant figures, x is 3.141593.

Stars are defined to be on the main sequence if they are burning hydrogen in their cores (hydrogen is combining into helium through nuclear fusion). Eventually, a star will run out of hydrogen fuel in its core, nuclear fusion will stop, and the star will enter a new stage of its lifetime. What is true?
More massive stars emit more energy and run out of hydrogen fuel in their cores faster. More massive stars have shorter main-sequence lifetimes because they burn through their fuel at a faster rate

Answers

More massive stars emit more energy and run out of hydrogen fuel in their cores faster.

What is the role of hydrogen in stars?

In order to create helium and energy, hydrogen nuclei must fuse. The procedure uses hydrogen as its fuel. As the hydrogen is depleted, the star's core condenses and warms up further. As a result, all the elements up to iron are formed through the fusing of heavier and heavier elements.

Nuclear fusion is how stars generate their energy. This process, known as the "proton-proton chain," which involves a series of events that turns four hydrogen atoms into one helium atom, dominates for the majority of stars.

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Each metal is illuminated with 400 nm (3.10 eV) light. Rank the metals on the basis of the maximum kinetic energy of the emitted electrons. (If no electrons are emitted from a metal, the maximum kinetic energy is zero, so rank that metal as smallest.) Rank from largest to smallest. To rank items as equivalent, overlap them. The correct ranking cannot be determined.

Answers

The metals on the basis of the maximum kinetic energy of the emitted electrons is Cesium > potasium > Beryllium = aluminum = Megnesium = Platinum.

From Einstein photo electic effect equation

E = 3.1 eV

E = Wo+ Kmax

Kmax = E - Wo

For Be:  E< Wo, Kmax =  0

There is no emission of photo electron

For K : Kmax = 3.1 -2.3 = 0.8 eV

For Al : E< Wo, Kmax =  0

There is no emission of photo electron

For  Mg: E< Wo, Kmax =  0

There is no emission of photo electron

For Cs: Kmax = 3.1 -2.1 = 1.0 eV

For Pt : E< Wo, Kmax =  0

There is no emission of photo electron

Cesium > potasium > Beryllium = aluminum = Megnesium = Platinum

Einstein photo electic effect:

Einstein said that energy is a beam of particles related to frequency according to Planck's formula. When this beam is directed at a metal, photons collide with atoms. If the photon frequency is high enough to knock off an electron, the collision will produce the photoelectric effect.

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volume of right circular cone; volume of cone; how to find volume of a cone; cone formula

Answers

The volume of the right circular cone is given by the formula πR²H/3.

A right circular cone is a kind of cone in which the centre of the circular base of the cone is perpendicular to the vertical height of the cone.

The volume of any right circular cone is generally given by the formula,

V = πR²H/3

Where,

V is the volume of the right circular cone,

R is the radius of the circular base of the right circular cone.

H is the vertical height of The right circular cone.

π is a constant that has a valued 22/7.

In any general case when we are given the value of the radius of the circular base of the right circular cone and the height of the right circular cone, then we can just simply put the values in the above mentioned formula and we get the volume of the right circular cone.

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which method of heat transfer does not require a medium; the transfer of thermal energy by conduction and convection does not require matter; a material in which thermal energy moves easily is an insulator; materials in which thermal energy does not move easily are; the transfer of thermal energy by movement of matter is; a material in which thermal energy moves easily is an insulator true or false; the transfer of thermal energy by movement of matter is ______; the transfer of thermal energy by radiation does not require matter

Answers

Energy is transferred through matter by both conduction and convection. Only radiation can convey energy without the need for substance. The transfer of energy through waves is known as radiation

What is the simplest way to define radiation?

The definition of radiation is radiation that emanates from a source and moves at the speed of light through space. This energy has wave-like characteristics and is surrounded by an electric and magnetic field. Electromagnetic waves are another name for radiation.

Definitions and examples of radiation

The definition of radiation was energy that emanates from a source and moves through a substance or through space. Radiation includes heat and light. Ionizing radiation, the type of radiation covered on this website, is so-named because it has sufficient energy to knock an electron out of an atom, converting it into an ion.

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Which of these is not true about a real image? Question 23 options: It is inverted. It is enlarged. It can be projected onto a screen. It appears behind the mirror.

Answers

The false option about a real image is that  It appears behind the mirror. Last option.

What is a real image?

Rays merely appear to diverge in a virtual image, whereas they actually converge in a real image. Only when the item is placed farther away from the mirror/lens than the focal point and this real picture is reversed can concave mirrors and converging lenses produce genuine images.

Using a converging lens or a concave mirror, actual images can be captured. The positioning of the object affects the size of the actual image.

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A wave on a string is described by y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m + t/(0.20 s))], where x is in m and t in s.
In what direction is this wave traveling?
What are the wave speed, frequency, and wavelength?
At t = 0.50 , what is the displacement of the string at x = 0.20 m?

Answers

The wave is traveling in the negative x direction.The wave speed is 12.0m/s.The frequency is 5HzThe wavelength is 2.4m.The displacement is 0.029m.

What is the displacement of the string ?

The general wave equation is given by;

y(x, t) = y cos (2(x/λ) - 2ft)    --------------------------------(i)

y(x, t) is the displacement of the wave at position x and a given time t

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))]   ------------------(ii)

Which can be re-written as;

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m)) + 2π(t/(0.20 s))]  -------------(iii)

Comparing equations (i) and (iii) we have that;

=> 2π(x/(2.4 m) = 2π(x/λ)

=> λ = 2.4m

Therefore the wavelength of the wave is 2.4m

Also, still comparing the two equations;

=> 2π(t/(0.20 s) = 2πft

=> f = 1 / 0.20

=> f = 5Hz

Therefore the frequency of the wave is 5Hz

To get the wave speed (v), it is given by;

v = f x λ

Where f = 5Hz and λ = 2.4m

=> v = 5 x 2.4

=> v = 12.0m/s

Therefore, the speed of the wave is 12.0m/s

At t = 0.50s and x = 0.20m;

The displacement, y(x,t) of the string wave is given by

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))]

Convert the amplitude of 3.0cm to m

=> 3.0cm = 0.03m

Carefully solve the equation

=> y(x, t) = (0.03m) × cos[2π((0.20)/(2.4 m)) + 2π(0.50/(0.20 s))]

=> y(x, t) = (0.03m) × -0.9684

=> y(x, t) = 0.029m

Therefore the displacement at those points is -0.029m

Also, the sign of the displacement shows that the direction of the wave is in the negative x direction.

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according to general relativity, the presence of matter curves spacetime and therefore time slows down in a gravitational field. time is universal. time is different for every object. none of the above

Answers

General relativity states that the existence of matter bends spacetime, which causes time to slow down in a gravitational environment.

Explain the term general relativity?

It is, in essence, a theory of gravity. The fundamental assumption is that gravity is a bending or curving of space rather than an invisible force which draws items together.

An item warps the space surrounding it more dramatically the more large it is.According to Einstein's general theory of relativity, matter or energy causes a distortion of space (or more specifically, spacetime) known as gravity. A large item produces a gravitational field by distorting the geometry of the spacetime it is located in.

Thus, general relativity states that the existence of matter bends spacetime, which causes time to slow down in a gravitational environment.

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the lithosphere can be thought of as tending to rise or sink gradually until it is balanced by the displaced asthenosphere. according to this model, a mountain range will have a mountain _____________ that extends deep into the mantle

Answers

The Mountain range will have a mountain deep that extends deep into the mantle.

A mantle is a layered interior of a planetary frame bounded underneath through a core and above by using a crust. Mantles are made of rock or ice and are commonly the largest and most massive layer of the planetary body.

It's far more frequently solid rock, but less viscous at tectonic plate obstacles and mantle plumes. Mantle rocks there are smooth and able to pass plastically at great depth and stress. The transfer of heat and material in the mantle helps decide the panorama of Earth.

The basic styles of mantle substances consist of stone, vintage, timber, and forged stone.

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a slender, uniform metal rod of mass m and length l is pivoted without friction about an axis through its midpoint and perpendicular to the rod.

Answers

The metal rod's moment of inertia, Ml²/12, has a midway that is equal to 3k/M.

Explain about the midpoint and perpendicular?

A line that cuts through the intersection of two adjacent line segments at a right angle is known as a perpendicular bisector. In other words, a perpendicular bisector always splits a line segment through its middle. The word "bisect" itself refers to an even or uniform division.

A line that is perpendicular to a triangle's side and travels through the middle of that side is said to be the perpendicular bisector of that side. The circumcenter of a triangle is where the triangle's three perpendicular bisectors meet (the center of the circle through the three vertices). A line segment is a perpendicular bisector when it encounters another line segment at a straight angle and divides it into two equal halves at its halfway.

When the rod is twisted at an angle, the spring is squeezed by a tiny distance.

springs, which add force

= k x

torque moment about an axis

= k x l /2

= k θ( l /2 )² ( x / .5 l = θ )

Angular acceleration times the rod's moment of inertia equals the moment of torque.

M l2 / 12 d2 / dt2 = k (l /2)2

d²θ/dt² = 3 k/M θ

acceleration equals two.

ω² = 3 k/M

ω = √ 3 k / M

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momentum of the system is constant for elastic collisions, but momentum of the system is lost during inelastic collisions. t/f

Answers

Momentum of any system is constant in all over elastic collisions, but momentum for the system doesn't lost during inelastic collisions. so it's False.

An elastic collision is a collision wherein there's no internet loss in kinetic power withinside the gadget because of the collision. Both momentum and kinetic power are conserved portions in elastic collisions. Suppose comparable trolleys are journeying closer to every different with identical speed. They collide, bouncing off every different without a loss in speed. This collision is flawlessly elastic due to the fact no power has been misplaced.

In reality, examples of flawlessly elastic collisions aren't a part of our ordinary experience. Some collisions among atoms in gases are examples of flawlessly elastic collisions. However, there are a few examples of collisions in mechanics wherein the power misplaced may be negligible. These collisions may be considered elastic, despite the fact that they may be now no longer flawlessly elastic. Collisions of inflexible billiard balls or the balls in a Newton's cradle are such examples.

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How to find the net force of on an object?

Answers

Answer:

Look for the formula!

Explanation:

the net force formula is  FNet = Fa + Fg + Ff + FN.

FN is the force acting on a body.

here are the hints to find one in the future!

Fa is applied force,

Fg is the gravitational force,

Ff is the frictional force,

FN is a normal force.

the formula
FNet= fa+fg+ff+fn

Object A with mass 1 kg is tied with a string to object B with mass 2 kg. Force F, is
pulling the object with mass 1 kg. When it is moving with the acceleration of 1 m/s?.
the friction force on A is 5 N and on B is 10 N.
Find F and tension in the spring that attached A and B.

Answers

The tension in the string is 15 N.

What is string?

String is a data type used in programming that refers to a sequence of characters. It is typically used to store text-based data, such as words or sentences, and is often used to represent strings of text that the user has input. String data types are used in many programming languages, including Java, C++, Python, and JavaScript. String data types are also used to store information such as file paths, website URLs, and database names. In some programming languages, a string is also referred to as a character array.

F = 1 kg * 1 m/s2 = 1 N
The tension in the string is the sum of the forces acting on each object.
For Object A, the forces are F (1 N) and the friction force (5 N).
For Object B, the forces are the friction force (10 N) and the tension in the string.
Therefore, the tension in the string is 10 N + 5 N = 15 N.

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Ultrasound in Medicine. A 1.70-MHz sound wave travels through a pregnant woman's abdomen and is reflected from the fetal heart wall of her unborn baby. The heart wall is moving toward the sound receiver as the heart beats. The reflected sound is then mixed with the transmitted sound, and 72 beats per second are detected. The speed of sound in body tissue is 1500 m/s. Calculate the speed of the fetal heart wall at the instant this measurement is made.

Answers

The speed of the fetal heart wall at the instant is 0.031 m/s when 72 beats per second of hart beat was detected.

The Doppler Effect, defined as the change in frequency of a wave in relation to an observer moving relative to the wave source, must be used.

Let

v= magnitude of the heart wall speed

V= speed  of sound = 1500

fh= the frequency the heart receives (and  reflects) =

fi= original frequency

ff= reflected frequency

fb= frequency for the beats=72

Make use of the Doppler Effect formula.

We have this formula because the heart is a moving observer and the device is a stationary source.

[tex]f_h = [(V+ v)/(v)] fi....(1)[/tex]

We can use this formula if we consider the heart to be a moving source and the device to be a stationary observer.

[tex]f_f = [(V)/(V-v)] fh....(2)[/tex]

The beats' frequency would be the difference between the original and reflected frequencies.

[tex]f_b = f_f -f_i......(3)[/tex]

substituting (1) and (2) into (3),

[tex]f_b=\frac{V}{V-v}\frac{V+v}{V}f_i-f_i\\\\f_b=f_i(\frac{V+v}{V-v}-1)\\\\f_b=f_i\frac{V+v-V+v}{V-v}\\\\f_b=\frac{2v}{V-v}[/tex]

solving for v ,

[tex]v=V\frac{f_b}{2f_i-f_b}=1500\frac{72}{2(1.70*10^6)-72}=0.031 m/s[/tex]

Thus, the speed of fetal heart is 0.031 m/s

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A cannon is mounted on a cart and carrying a cannonball. The total mass of the cart, cannon, and ball is M, and the cart is rolling with no friction at a velocity v in the positive x-direction as shown in the figure. The ball, of mass m, is fired with a velocity of Vball in the positive x-direction. What is the velocity of the cart (with cannon) after the ball is fired?​

Answers

The velocity of the cart (with cannon) after the ball is fired is u₂ = Mv - mVb / ( M - m(ball) ).

option A is the correct answer.

What is the law of conservation of linear momentum?

The law of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.

Mathematically, the law of conservation of linear momentum is given as;

Pi = Pf

where;

Pi is the sum of the initial momentumPf is the sum of the final momentum

m₁u₁ + m₂u₂ = v ( m₁ + m₂ )

where;

m₁ is the mass cannon ballu₁ is the final velocity of the cannon ballm₂ is the mass of the cartu₂ is the final velocity of the cartv is the initial velocity of the cannoncart-system

Mass of the cannon ball  +  cart = M

mass of the cart only, m₂ = M - m(ball)

The final velocity of the cart  is calculated as follows;

mVb + m₂u₂ =  Mv

m₂u₂ = Mv - mVb

u₂ = Mv - mVb / m₂

u₂ =  ( Mv - mVb ) / ( M - m(ball) )

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solar panels generate an average of about 200 watt/m2. estimate the area (in meter2) needed to provide this annual energy usage.

Answers

The area 63000 m² needed to provide this annual energy usage.

What is annual energy usage?

The term "Annual Usage" refers to the estimated annual power consumption at the Address, computed in kWh, as inputted into the programme or as recalculated in the case that more project watts are requested.

A normal household in Arizona uses about 1050 KWh of energy per month .

So annual consumption of energy is about 12600 KWh that is 12600000 watt-hour.

Average solar panel generate about 200 watt per square meter area.

Total area needed to provide this power can be calculated by the formula.

Total power required= total area × total power generation by solar panel.

Here, total power =12600000 watt hour.

Power generation by solar panel is 200 watt/ m²

So total area= total power required/ power generation by solar panel.

Total area= 12600000/200 m²

Total area= 63000 m².

So total area required to generate that amount of power is about 63000 m².

Here power generation of 200 watt/m² by solar panel indicates that the solar panel has efficiency of about 20% that means it can convert only 20% of solar irradiance ( which is nearly about 1000 watt per m²).

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The complete question is as follows:

Estimate the annual energy consumption (in watt-hour) of a typical house in Arizona.

Solar panels generate an average of about 200 Watt/m² . Estimate the area (in m²) needed to provide this power.

light with a frequency of 5.9 x1014 hz travels in a block of glass that has an index of refraction of 1.59.

Answers

The light will travel with a speed of 9.38 x 10¹⁴ m/s in the block of glass.

The speed of light in a medium is given by the formula,

n = c/v

Where,

c is the speed with which the light travels in the medium,

v is the frequency of the light and n us the refractive index of the medium.

Now, here in this case, the refractive index of the block of glass is 1.59 and the frequency of the light is 5.9 x 10¹⁴ Hz.

Now, putting values,

1.59 = c/5.9 x 10¹⁴

c = 9.38 x 10¹⁴ m/s.

So, the light will travel with a speed of 9.38 x 10¹⁴ m/s in the block of glass.

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somebody please helpppp

Answers

Answer:

6 is Electrical

1 is Thermal

13 is Mass and Acceleration

3 is Force and Distance

2 is Work and Time

4 is Mechanical

Explanation:

NOTE: Sorry if I missed any and sorry if some aren't correct, but I think they are :)

What is the mass of a ball with a momentum of 18 kg*m/s and a velocity of 9 1 m/s? O 2 m/s O 2 kg O 162 m/s O 162 kg​

Answers

Answer:

B: 2 kg.

Explanation:

To find the mass of an object given its momentum and velocity, you can use the following formula:

mass = momentum / velocity

In this case, the momentum of the ball is 18 kg*m/s and its velocity is 9 1 m/s, so the mass of the ball is:

mass = 18 kg*m/s / 9 1 m/s

= 2 kg

Therefore, the correct answer is B: 2 kg.

Using the method of joints, determine the force in each member of the truss shown. Indicate whether the member is in tension or compression. Support A is a roller and Support Cis a pin.

Answers

The value of F CA = 4500 NC. The fundamental difference between compression and tension is that compression represents forces meant to shorten a body, whereas tension describes forces designed to prolong a body.

What is the difference between tension and compression?

A rope bridge may support both the load it carries and itself by using tension forces that pull and stretch material in opposing directions. A rock arch bridge carries a load by pressing its rocks against one another due to compression forces that squeeze and push material inward.

One that pulls materials apart is a tension force. When material is compressed, it gets squeezed together. Some materials are more resilient to compression, some to tension, and some are suitable for usage when both compression and tension are present.

Efforts to distort an object are called tension and compression forces. The basic distinction between tension and compression is that tension describes forces intended to lengthen a body, whereas compression describes forces intended to shorten the body.

Support Reactions: Entire truss:

[tex]+\Sigma F_x=0: \quad B_x=0 \\[/tex]

[tex]+{ }_{+} \Sigma M_C=0: \quad-B_y(400 \mathrm{~mm})-(1200 \mathrm{~N})(500 \mathrm{~mm})=0 \\[/tex]

[tex]B_y=-1500 \mathrm{~N} \quad \mathbf{B}_y=1500 \mathrm{~N} \\[/tex]

[tex]+\left\lceil\Sigma F_y=0: \quad-1500 \mathrm{~N}-1200 \mathrm{~N}+C=0\right. \\[/tex]

C = 2700 N

Free body: Joint B:

[tex]$\frac{F_{B A}}{13}=\frac{F_{B C}}{12}=\frac{1500 \mathrm{~N}}{5} .[/tex]

[tex]$\begin{array}{r}F_{B A}=3900 \mathrm{~N} \\ \\ F_{B C}=3600 \mathrm{~N} C\end{array}$[/tex]

simplifying the above equation, we get

[tex]$\frac{F_{C A}}{5}=\frac{2700 \mathrm{~N}}{3}$[/tex]

Therefore, the value of [tex]$F_{C A}=4500 \mathrm{~N} C$[/tex]

The complete question is:

Using the method of joints, determine the force in each member of the truss shown. State whether each member is in tension or compression.

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question: how do we measure the rate of radioactive decay? observe: select the bar chart on the right side of the gizmo and click play. what happens to the numbers of radioactive and daughter atoms as the simulation proceeds? do the numbers of radioactive and daughter atoms change at the same rate throughout the simulation? explain. interpret: how does the half-life setting affect how quickly the simulated substance decays? (activity a continued on next page)

Answers

The quantity of radioactivity is stated in Becquerel (Bq), that's the worldwide unit, or the Curie (Ci), that's the unit used withinside the United States. 

Geiger counters are generally used to degree the quantity of radioactivity, however there are different forms of detectors that can be used.

The decay fee is expressed as a percentage. We convert it to a decimal through really lowering the percentage and dividing it through 100. Then calculate the decay aspect b = 1-r. For instance, if the fee of degradation is 25%, the exponential function's decay fee is 0.25 and the decay aspect b = 1- 0.25 = 0.75.

Atoms of a determine radioactive isotope randomly decay right into a daughter isotope. Over time the range of determine atoms decreases and the range of daughter atoms increases. Rutherford and Soddy (1902) observed that the fee of degradation of a radioactive isotope relies upon on the quantity of the determine isotope remaining.

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A proton accelerates from rest in a uniform electric field of 640 N/C. At some later time, its speed is 1.20 x 10% m/s (nonrelativistic, because v is much less than the speed of light).
(a) Find the acceleration of the proton.
(b) How long does it take the proton to reach this speed?
(c) How far has it moved in this time?
(d) What is its kinetic energy at this time?

Answers

a)  The acceleration of the proton is  6.4×10¹⁰  m/s².

b)  Time taken is 1.875×10⁻⁵ second .

c)  It moved in this time is 11.25 meter.

d)  its kinetic energy is  1.15×10⁻¹⁵ Joule.

What is electric field?

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

uniform electric field: E = 640 N/C.

its speed is: v= 1.20 x 10⁶ m/s

a)  the acceleration of the proton = qE/m

= (1.6×10⁻¹⁹×641)/(1.6×10⁻²⁷) m/s²

= 6.4×10¹⁰  m/s²

b) Time taken = (1.20 x 10⁶ / 6.4×10¹⁰)second = 1.875×10⁻⁵ second .

c)   it moved in this time = ( 1.20 x 10⁶×1.875×10⁻⁵ )/2 meter = 11.25 meter.

d)  its kinetic energy = mv²/2 =  (1.6×10⁻²⁷)(1.20 x 10⁶)²/2 joule = 1.15×10⁻¹⁵ Joule.

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Consider Couette flow between two parallel plates separated by a distance H. The lower plate moves with velocity us1
and the upper plates move in the opposite direction with velocity us2.The channel is filled with an ideal gas. Assume velocity slip conditions, determine the mass flow rate. Under what condition will the net flow rate be zero?

Answers

The mass flow rate can be given as [tex]V=S[\frac{u_y}{2}-\frac{H^3}{12m}\frac{\delta p}{\delta x}][/tex] and when H=0 then net flow rate will be zero.

Given,

upper plate velocity = [tex]u_{s1}[/tex]

opposite plate velocity = [tex]u_{s2}[/tex]

The total velocity between the plates will be

[tex]u_y=u_{s1}+u_{s2}[/tex]

Flow rate is the velocity integrated over an area,

[tex]Q=\int \overline u \hat n \ dA[/tex]

The equation above is only valid for a flat, plane area. In general, including curved areas, the equation becomes a surface integral.

The areas would be cross-sectional.The area of a liquid passing through a pipe is the cross-section of the pipe at the section under consideration. The magnitude of the area through which the mass passes, A, and a unit vector normal to the area combine to form the vector area.

The mass flow rate ,

[tex]V=SQ=S\int\limits^H_0 \int\limits^L_0 u(y)dzdy\\\\=SL\int\limits^H_0u(y)dy\\\\\frac{V}{L}=S\int\limits^H_0[\frac{1}{2m}\frac{\delta p}{\delta x}(y^2-Hy)+\frac{u_y}{H}]dy\\\\=\frac{S}{2M}\frac{\delta p}{\delta x}(\frac{H^3}{3}-\frac{H^3}{2})+\frac{u_y}{2}[/tex]

The mass flow rate for unit width is

[tex]V=S[\frac{u_y}{2}-\frac{H^3}{12m}\frac{\delta p}{\delta x}][/tex]

if H=0 then net flow rate will be zero.

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Measurements on the cornea of a person's eye reveal that the magnitude of the front surface radius of curvature is while the magnitude of the rear surface radius of curvature is (see Figure 25.18 ), and that the index of refraction of the cornea is 1.38 . If the cornea were simply a thin lens in air, what would be its focal length and its power in diopters? What type of lens would it be?

Answers

(a) If the cornea were simply thin lens then power will be 43 diopters.

(b) This is a concave lens

The cornea is the transparent front part of the eye that covers the iris, pupil, and anterior chamber. Despite injury or disease, the cornea can still repair itself quickly. However, there are situations where damage is too severe for the cornea to heal on its own – such as with a deep injury to the cornea. The following symptoms may indicate that the cornea has sustained a substantial infection, injury or disease: Blurred vision Pain Redness.

Along with the anterior chamber and lens, the cornea refracts light, accounting for approximately two-thirds of the eye's total optical power. In humans, the refractive power of the cornea is approximately 43 diopters.

There are two types of lenses: converging and diverging and here if the cornea was simply thin then the diverging or concave lens is used in the eyes which is thin in the center than their edges.

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A hopper jumps straight up to a height of 1.3 m. With what velocity did he leave the floor

Answers

The velocity with which the jumper leaves the floor is 5.1 m/s.

What is the initial velocity of the jumper?

The initial velocity of the jumper or the velocity with which the jumper leaves the floor is calculated by applying the principle of conservation of energy as shown below.

Kinetic energy of the jumper at the floor = Potential energy of the jumper at the maximum height

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v is the initial velocity of the jumper on the floorh is the maximum height reached by the jumperg is acceleration due to gravity

v = √(2 x 9.8 x 1.3)

v = 5.1 m/s

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Keeping constant speed , 0.8 m/s a marble rolls back and forth inside a shoebox. Make an order-ofmagnitude estimate of the probability of its escaping through the wall of the box by quantum tunneling. State the quantities you take as data and the values you measure or estimate for them.

Answers

The answer is e-10³⁰.

Solution:

The expression for find transmission co-efficient is

[tex]T = e^{-2CL}[/tex]

Substitute values in the above equation

T = e -2(2.5-10³²)(2×10⁻³)

= e -10×10²⁹

≈ e-10³⁰

Magnitude estimation is a psychophysical method by which participants judge the perceived strength of a stimulus and assign a numerical estimate. Magnitude is an exponential change of plus or minus one in the value of a quantity or unit. The term is commonly used in relation to the 10th power scientific notation.

Magnitude is used to make the size of numbers and the scale of things more intuitive and understandable. A rough estimate of size helps the project manager estimate a rough figure for the total cost of the project. The approximate financial impact of future projects. Change the precision as needed.

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levi boards a ferris wheel at the 3-o'clock position and rides the ferris wheel for several rotations. the ferris wheel has a radius of 12 meters, and when levi boards the ferris wheel he is 16 meters above the ground. imagine an angle with its vertex at the center of the ferris wheel that subtends the path levi travels.

Answers

Levi height above the ground is = 16 + 12sin(d/12)

Levi height above the center of the Ferris wheel in radius lengths is = 12sin(d/12)

Since Levi height above the center of the Ferris wheel is 12sin(d/12) meters and it's center is 14 meters above the ground.

Therefore, Levi height above the ground is = 16 + 12sin(d/12)

When an object is flung or projected into the air, it moves only with the acceleration caused by gravity. Projectile motion has several uses in both engineering and physics. Examples include the motion of any ball in sports, the entry of meteorites into the Earth's atmosphere, and fireworks. These things are referred to as projectiles, and their course is referred to as a trajectory. The projectile motion of falling objects, as it is described in Motion Along a Straight Line, is a straightforward one-dimensional kind in which there is no horizontal movement. The effects of air resistance are ignored in this section's discussion of two-dimensional projectile motion.

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