(basic algebra) please help me with question:

Answer:

x= 5

Step-by-step explanation:

factorised the equation is (x-5) (x+3)

x=5 x=-3

Answer:

the correct answer is 2 act

Step-by-step explanation:

there is same base (act)

then 5+3=8

and 8-6 = 2act

[tex]( {4x}^{2} - 7x - 2) - (3x - 8) \\ \\ {4x}^{2} - 7x - 2 - 3x + 8 \\ \\ {4x}^{2} - 10x + 4.[/tex]

Answer: 26 inches is equivalent to 660.4 millimeters.

Step-by-step explanation:

You will multiply the inches by the conversion.

[tex]26in*25.4mm=660.4mm[/tex]

Therefore, the answer is 660.4 millimeters.

I hope this helps!! Pls mark brainliest :)

Answer:

Step-by-step explanation:

Let k: y = a₁x + b₁ and l: y = a₂x + b₂. Then

We have the euation of a line in point slope form:

Convert to the slope intercept form:

y - 4 = 2(x - 6)

y - 4 = 2x - 12

y - 4 + 4 = 2x - 12 + 4

y = 2x - 8

The slope is m₁ = 2.

Let y = m₂x + b.

The lines is perpendicular. Therefore:

2m₂ = -1     |divide both sides by 2

The line passes through the point (-3, -5).

Substitute to the point slope equation:

y - (-5) = -1/2(x - (-3))

y + 5 = -1/2(x + 3)

The equation of line is 2x  - 3y = 6.

The x-intercept is the point where a line crosses the x-axis, and the y-intercept is the point where a line crosses the y-axis.

The x-intercept is 3 and the y-intercept is -2.

So, the line passes through the points  (3, 0) and (0, -2)

Now, slope of line is

m= -2-0/ 0-3 = 2/3

Equation of line is

y = 2/3 x - 2

y = 2x-6 /3

3y= 2x -6

2x  - 3y = 6

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Answer

Step by step explanation

Answer:

-12

Step-by-step explanation:

Answer:

66560 pairs

Step-by-step explanation:

let the number of pairs of boots the company makes in 260 days = X

1day -----------------256pairs

260days-------------X

cross multiplying

1×X = 260×256

X= 66560

therefore, in 260days, he makes 66560 pairs

Answer:

When the initial velocity is 6m/s and acceleration is 3m/s², the final velocity after a distance of 29m is √210m/s.

Step-by-step explanation:

Concept: In the problem it is given that u = 6m/s, a = 3m/s² and s = 29m. We need to find the v. In such kinematical problems, we have an equation v² = u² + 2as. From this relation we can find v.

v² = 6² + 2×3×29

v² = 36 + 174

v² = 210

v = √210 m/s

So, the final velocity is the under-root of 210 or √210 m/s.

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Step-by-step explanation:

GIVEN

HERE

= 6+9+2+6+600÷30 { firstly add numbers }

= 623 ÷ 30

= 20

I think you understand

Answer:

[tex]x = 5y {}^{2} + 10[/tex]

The inverse of the function is x = 5y² + 10.

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

To find the inverse of a function, we need to solve for x in terms of y.

To do this, we can start by replacing y with x and solving for x.

y = 5x² + 10

x = 5y² + 10

Now we have solved for x in terms of y, which gives us the inverse of the original function.

So the equation that can be simplified to find the inverse of y = 5x² + 10 is:

x = 5y² + 10

Thus,

The inverse of the function is x = 5y² + 10.

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Answer:

[tex]\dfrac{26}{3}[/tex]

Step-by-step explanation:

The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:

[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]

Given function:  [tex]f(x)=3^{x-1}+2[/tex]

Given interval:  1 ≤ x ≤ 4

Therefore, a = 1 and b = 4

Therefore, find the value of the given function when x = 1 and x = 4:

[tex]\begin{aligned}\implies f(1) & =3^{1-1}+2\\ & = 3^0+2\\ & = 1+2\\ & = 3 \end{aligned}[/tex]

[tex]\begin{aligned} \implies f(4) & = 3^{4-1}+2 \\ & = 3^3+2\\ & = 27+2\\ & = 29 \end{aligned}[/tex]

Substitute the found values into the formula:

[tex]\begin{aligned}\implies \dfrac{f(b)-f(a)}{b-a} & =\dfrac{f(4)-f(1)}{4-1}\\\\ & =\dfrac{29-3}{4-1}\\\\ & = \dfrac{26}{3} \end{aligned}[/tex]

Answer:

54%

Step-by-step explanation:

To find the probability for a male patient to have B blood, find the number of male patients who do have B blood and divide it by the number of patients with type B.

The number of male and B blood is 99.

The number of patients with B blood is 183.

The probability is 99/183 = 0.54.

The percent is found by multiplying by 100.

0.54*100 = 54%

[tex]7a³ (8a² + a)²-4a³ \\ \\ 7 {a}^{3}(8 { {a}^{2} + a)(8 {a}^{2} + a )} - 4 {a}^{3} \\ \\ 7 {a}^{3} ( {8a}^{2} (8 {a}^{2} + a ) + a(8 {a}^{2} + a ) - 4 {a}^{3} \\ \\ 7 {a}^{3} (64 {a}^{4} + 8{a}^{3} + 8 {a}^{3} + {a}^{2} ) - 4 {a}^{3} \\ \\ 7 {a}^{3} (64 {a}^{4} + 16 {a}^{3} + {a}^{2} ) - 4 {a}^{3} \\ \\ 448 {a}^{7} + 112 {a}^{6} + 7 {a}^{5} - 4 {a}^{3} \\ \\ {a}^{3} (448 {a}^{4} + 112 {a}^{3} + 7 {a}^{2} - 4).[/tex]

Answer:

D.  4

Step-by-step explanation:

Given expression:

[tex]-2x^2-4x+10[/tex]

To find the value of the expression when x = -3, substitute x = -3 into the expression:

[tex]\implies -2(-3)^2-(-3)x+10[/tex]

Apply exponent rule  [tex](-a)^2=a^2[/tex]:

[tex]\implies -2(3^2)-4(-3)+10[/tex]

[tex]\implies -2(9)-4(-3)+10[/tex]

[tex]\implies -18-4(-3)+10[/tex]

Apply rule [tex]-(-a)=a[/tex] :

[tex]\implies -18+(4)(3)+10[/tex]

[tex]\implies -18+12+10[/tex]

Add/subtract from left to right:

[tex]\implies -6+10[/tex]

[tex]\implies 4[/tex]

Let's find

Answer:

  14.7 quarts

Step-by-step explanation:

Use the given equivalence figures to write a proportion. Solve the proportion for the unknown value.

__

  quarts/liters = x/14 = 1/0.95 . . . . . the conversion is given as 1 qt = 0.95 L

Multiply by 14 to find x.

  x = 14(1/0.95) ≈ 14.7

There are about 14.7 quarts in 14 liters.

_____

Additional comment

You are given a value in liters (14 liters) and asked for the equivalent in quarts. That means you want to change the units from liters to quarts. To do that, you can multiply the given value (14 liters) by a conversion factor that has quarts in the numerator and liters in the denominator. That is what the fraction 1/0.95 is in the above. You will note that units of liters cancel in this equation.

  [tex](14\text{ liters})\times\dfrac{1\text{ quart}}{0.95\text{ liter}}=\dfrac{14}{0.95}\text{ quarts}\approx14.7\text{ quarts}[/tex]

This rule, "use a conversion factor that divides by the units you don't want and multiplies by the units you do want" applies to any units conversion problem. The conversion factor you use should always have equal quantities in the numerator and denominator. (Here, the equal quantities are 1 quart and 0.95 liters.)

You will notice that we treat units just like any variable. They can be multiplied, divided, cancelled, raised to a power. Only terms with like units can be added or subtracted.

Answer:

Dimensions = 8 CM and 12 CM

length = 12 CM

width = 8 cm

perimeter = 2 ( length + width)

= 2( 12 + 8)

= 2 ( 20)

= 40 CM

ratio = 12/40

= 6/20

= 3/10

Answer:

no lo sd

Step-by-step explanation:

solo se que is really

In what? desmos, drawing?

Answer:

Step-by-step explanation:

Givens

Parallelogram EASY with diagonal ES

<AES = 40

<Y = 110

Solution

<AES = 40               GIVEN

<ESY = 40                     Z THEOREM OF A PRALLELOGRAM

<A = <Y                         PROPERTY OF A PARALLELOGRAM

<A = <110                      <A = 110 BECAUSE <Y = 110

<YES = 180 - <Y           -<ESY EVERY TRIANGLE HAS 180o

<YES = 180 - 110 - 40    SIMPLIFY

<YES = 30

<YEA = <YES + <AES    WE KNOW BOTH ANGLES ON THE RIGHT.

<YEA = 30 + 40             COMBINE

<YEA = 70

You could do <YEA by noting that consecutive angles of a Parallelogram equal 180

Answer: x = 2

Step-by-step explanation:

First, let's take the root of 256 to find the length of each side before the addition of x.

[tex]\sqrt{256} = 16[/tex]

This means 16 cm is the length of each side before the addition of x.

Then increase each side by X to get

[tex](16 + x)(16 + x) = 324[/tex]

[tex]256 + 16x + 16x + x^2=324[/tex]

[tex]x^2+32x -68=0[/tex]

[tex]x=2[/tex]  or   [tex]x=-34[/tex]

The value cannot be negative so x has to be 2

-------------------------------------------------------------------------------------------------------------

Answer:  [tex]\textsf{Option C, 3}\sqrt{2}[/tex]

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Given:  [tex]\sqrt{18}[/tex]

Find: [tex]\textsf{Simplify the expression}[/tex]

Solution: In order to get a number outside of the square root there must be two of them inside of the square root.  The first step that we need to take is to break down the number 18 into it's lowest factors and then take out the numbers can be taken out.

Break down the number 18

Take 3 outside of the square root

Therefore, the option that would best match the results that were solved for is option C, [tex]\textsf{3}\sqrt{\textsf{2}[/tex]

The quadratic equation 3 · x² + 7 · x - 2 = 0 has a positive discriminant. Thus, the expression has two distinct real roots (real and irrational roots).

Herein we have a quadratic equation of the form a · x² + b · x + c = 0, whose discriminant is:

d = b² - 4 · a · c     (1)

There are three possibilities:

If we know that a = 3, b = 7 and c = - 2, then the discriminant is:

d = 7² - 4 · (3) · (- 2)

d = 49 + 24

d = 73

The quadratic equation 3 · x² + 7 · x - 2 = 0 has a positive discriminant. Thus, the expression has two distinct real roots (real and irrational roots).

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The value of x will be 4 ,  Option A is the answer.

A triangle that has one angle as 90 degree is called a Right angled Triangle.

In a right angled triangle

the length of the sides can be determined using Pythagoras Theorem

The length of the side is given in the image attached as

x-2 , x , √20

Hypotenuse ² = Perpendicular² + Base²

(√20)² = x² + (x-2)²

20 = x² + x² +4 -4x

2x²-4x -16 = 0

x² -2x -8 = 0

x² - 4x +2x -8 = 0

x (x-4) +2(x-4) = 0

(x+2)(x-4) = 0

x = -2 , 4

The value of x will be 4 .

Therefore Option A is the answer.

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Observe the diagram below with indexes on the shapes.

The transformations are:

Answer:

C

Step-by-step explanation:

Use the equation [tex]a^2 + b^2 = c^2[/tex]

Input the numbers----> [tex](2865)^2 +(4550)^2=c^2[/tex]

Simplify ----> [tex]28910725=c^2[/tex]

Find the square root------->[tex]5376.9=c[/tex]

formula is lsquare so answer is 25ft

Answer:

48 miles per hour I hope I helped you have a nice day

Answer:

(a) = 13

(b) = 8

(c) = 5

Step-by-step explanation:

Addition theorems on sets are

Theorem 1 :

n(AuB) = n(A) + n(B) - n(AnB)

Theorem 2 :

n(AuBuC) : = n(A) + n(B) + n(C) - n(AnB) - n(BnC) - n(AnC) + n(AnBnC)

Total number of students in the school is not given

so let there are 60 students in the school

using theorem 2

n(AuBuC) : = n(A) + n(B) + n(C) - n(AnB) - n(BnC) - n(AnC) + n(AnBnC)

let n(A) = Mathematics, n(B) =Physics and n(C) = Chemistry

so putting values,

   60             =    40 + 42 + 38 - 20 - 28 - 25 + n(AnBnC)

60 +73 -120 = n(AnBnC)

         13         = n(AnBnC)

therefore, there are total 13 students who take all three subjects

Number of students who had taken only Mathematics  =
n(A) - n(AnB) - n(AnC) + n(AnBnC)

40 - 20 - 25 + 13

53 - 45 = 8 students

Number of students who had taken only Physics  =

n(B) - n(BnA) - n(BnC) + n(AnBnC)

42 - 20 - 28 + 13

53 - 48 = 5 students

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