The top surface moves relative to the bottom surface by 1.167 x 10⁻⁶ m.
What is the displacement of the surface?The distance the top surface move relative to the bottom surface is calculated as follows;
shear strain = F/(αx)
where;
F is shearing forceα is the shear modulus x is thicknessshear strain = (14 )/(1.2 x 10⁷ x 0.00117 m)
shear strain = 0.000997
The movement of the top surface;
top surface movement = shear strain x thickness
= 0.000997 x 0.00117 m
= 1.167 x 10⁻⁶ m
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Question 1 of 10
A business must decide whether to open a new office in China. If it opens the
branch, it will increase its chances of selling a high volume of its products in
China. On the other hand, the business will have to spend a lot of money to
make the branch operational.
What would be an opportunity cost for the business if it chooses not to open
the new branch in China?
A. The business would lose the chance to make more money in
China.
B. The business would increase its marginal benefits on each
product it makes.
If the velocity of a particle is nonzero, can the particle’s acceleration be zero? Explain.
If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.
What is acceleration?The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.
Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.
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You put your book on the bus seat next to you. When the bus stops suddenly the book slides forward off the seat. Why?
A.) The book received a push from the seat hitting it.
B.) The force applied by the bus caused it to accelerate forward.
C.) The book's inertia carried it forward.
D.) The book could never slide forward to begin with.
Answer:
C) The book's inertia carried it forward.
When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.
As clothing tumble in a dryer, they can become charged. If a small piece of lint with a charge of +1.62 E−19 C is attracted to the clothing by a force of 2.0 E−9 N, what is the magnitude of the electric field at this location?
0.38 E10 N/C
1.2 E10 N/C
3.2 E10 N/C
3.6 E10 N/C
Name THREE factors which may prevent accessibility to printed media.
Answer:
1. Visual Impairment: People with visual impairments, including blindness, may find it difficult or impossible to access printed media. This can be due to the small size of text, lack of contrast between the text and background, or other formatting issues that make it difficult to read.
2. Physical Disability: Individuals with physical disabilities that affect their mobility, such as paralysis or tremors, may find it difficult to hold and manipulate printed media, such as books or magazines.
3. Literacy Levels: People who struggle with literacy or have limited reading skills may find it difficult to access printed media. This can be due to the complexity of the language used, or the lack of materials available in their native language.
Can anyone please help me solve this question?
An electric dipole consists of two point charges, +3.0 µC and -3.0 µC, separated by a distance of 8.0 mm. The dipole is located along the x-axis, with the positive charge at the origin and the negative charge at x = 8.0 mm. Calculate the electric potential and electric field at a point on the y-axis, located 10.0 mm away from the origin.
The electric field at the y-axis position is -10.0 N/C and is oriented towards the negative charge and electric potential at the point on the y-axis is -0.5 V..
How to determine electric potential and electric field?To calculate the electric potential and electric field at the point on the y-axis, use equations for electric potential and electric field due to an electric dipole:
Electric potential V = kq/(r_+) - kq/(r_-)
Electric field E = kq/(r_+)² - kq/(r_-)²
where k = Coulomb constant,
q = charge of each point charge,
r_+ = distance from the positive charge to the point on the y-axis, and
r_- = distance from the negative charge to the same point on the y-axis.
Using the given values:
r_+ = √((0.01 m)² + (0.1 m)²) = 0.1005 m
r_- = √((0.008 m)² + (0.1 m)²) = 0.1002 m
q = 3.0 μC
Electric potential:
V = (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁻⁶ C)/(0.1005 m) - (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁻⁶ C)/(0.1002 m)
V = 215.6 V - 216.1 V
V = -0.5 V
The electric potential at the point on the y-axis is -0.5 V.
Electric field:
E = (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁻⁶ C)/(0.1005 m)² - (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁶ C)/(0.1002 m)²
E = 2705.6 N/C - 2715.6 N/C
E = -10.0 N/C
The electric field at the point on the y-axis is -10.0 N/C, directed towards the negative charge.
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A bar of length L = 0.36m is free to slide without friction on horizontal rails. A uniform magnetic field B = 2.4T is directed into the plane. At one end of the rails there is a battery with emf = 12V and a Switch S. The bar has the mass 0.90kg and resistance 5.0ohm. ignore all the other resistance in the circuit. The switch is closed at time t = 0.
a) Just after the switch is closed, what is the acceleration of the bar?
b)what is the acceleration of. the bar when its speed is 2.0m/s?
c) what is the bar's terminal speed?
Answer:
Explanation: To solve this problem, we can use the equation for the force on a current-carrying conductor in a magnetic field:
F = I L x B
where F is the force on the conductor, I is the current flowing through the conductor, L is the length of the conductor, and B is the magnetic field strength.
a) Just after the switch is closed, the circuit is completed and a current starts to flow in the bar. The emf of the battery causes a current to flow in the circuit, which is given by Ohm's Law:
I = V / R = 12 / 5 = 2.4 A
The direction of the current is from the battery, through the bar, and back to the battery. Since the magnetic field is directed into the plane, the force on the bar is perpendicular to both the magnetic field and the current. Therefore, the bar experiences a sideways force that pushes it along the rails. The magnitude of the force is given by:
F = I L B = 2.4 x 0.36 x 2.4 = 2.0736 N
The mass of the bar is 0.90 kg, so the acceleration of the bar is:
a = F / m = 2.0736 / 0.90 = 2.304 m/s^2
Therefore, the acceleration of the bar just after the switch is closed is 2.304 m/s^2.
b) When the bar's speed is 2.0 m/s, the force on the bar is still given by:
F = I L B = 2.4 x 0.36 x 2.4 = 2.0736 N
However, now there is an additional force acting on the bar due to its motion through the air. This force is given by:
F_air = -0.5 ρ C_d A v^2
where ρ is the density of air, C_d is the drag coefficient, A is the cross-sectional area of the bar, and v is the speed of the bar. We can estimate the cross-sectional area of the bar as A = 0.01 m^2, and assume that the drag coefficient is C_d = 1. The density of air is ρ = 1.2 kg/m^3.
Substituting the given values, we get:
F_air = -0.5 x 1.2 x 1 x 0.01 x 2^2 = -0.024 N
The negative sign indicates that the air resistance is acting in the opposite direction to the motion of the bar.
The net force on the bar is therefore:
F_net = F + F_air = 2.0736 - 0.024 = 2.0496 N
Using Newton's Second Law, we can calculate the acceleration of the bar:
a = F_net / m = 2.0496 / 0.90 = 2.2778 m/s^2
Therefore, the acceleration of the bar when its speed is 2.0 m/s is 2.2778 m/s^2.
c) The bar's terminal speed is reached when the air resistance force is equal in magnitude and opposite in direction to the force due to the magnetic field. At this point, the net force on the bar is zero, so the acceleration is zero and the bar moves at a constant speed.
Setting F_net = 0, we can solve for the terminal speed:
F + F_air = 0
I L B - 0.5 ρ C_d A v^2 = 0
2.4 x 0.36 x 2.4 - 0.5
ρ C_d A v^2 = 2.0736
v^2 = (2.0736) / (ρ C_d A)
v^2 = (2.0736) / (1.2 x 1 x 0.01)
v^2 = 172.8
v = sqrt(172.8)
v = 13.142 m/s
Therefore, the bar's terminal speed is 13.142 m/s.
a physical science student is studying ohms law and builds a circuit the supplies voltage is 210v how much resistance will the student need in order to have an amperage of 7.0 A
Ohm's law states that the voltage (V) over a resistor is break even with to the item of the current (I) streaming through it and its resistance (R), or V = I*R.
How much resistance will the student need in order to have an amperage of 7.0 A?To discover the resistance required to have an amperage of 7.0 A with a voltage supply of 210 V, able to improve the condition to unravel for R:
R = V/I
Stopping within the values we know:
R = 210 V / 7.0 A
R = 30 ohms
Subsequently, the understudy will require a resistance of 30 ohms to attain an amperage of 7.0 A with a voltage supply of 210 V.
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What is the formula for potential difference?
The formula for potential difference (also known as voltage) is, V = ΔE/q, where V is the potential difference in volts (V), ΔE is the change in electric potential energy in joules (J), and q is the charge in coulombs (C).
Electric potential difference, also known as voltage, is a measure of the electric potential energy per unit of charge required to move a charge from one point to another in an electric circuit. It is the difference in electric potential between two points in an electric circuit.
The formula for potential difference, V = ΔE/q, reflects this relationship. The numerator, ΔE, represents the change in electric potential energy between the two points, while the denominator, q, represents the charge that moves between the two points.
For example, if a charge of +1 C moves from a point A to a point B in an electric circuit, and the electric potential energy at point B is greater than at point A by 1 J, then the potential difference between points A and B is 1 V. This means that it takes 1 J of energy to move a unit of charge from point A to point B in the circuit.
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Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The
object moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the
displacement of the object?
Answer:
Explanation: To calculate the displacement of an object moving with constant acceleration, we can use the following kinematic equation:
d = (1/2)at^2 + v0t
where d is the displacement of the object, a is the constant acceleration, t is the time elapsed, and v0 is the initial velocity of the object.
In this case, we know the initial velocity v0 = 3 m/s and the final velocity vf = 10 m/s. We also know that the object moves with constant acceleration, so we can use the following equation to relate the initial and final velocities to the acceleration and displacement:
vf^2 = v0^2 + 2ad
Solving for d, we get:
d = (vf^2 - v0^2) / (2a)
Substituting the given values, we get:
d = (10^2 - 3^2) / (2a) = 91 / (2a)
Therefore, to calculate the displacement of the object, we need to determine the value of the acceleration.
We can use the velocity vs. time graph to find the acceleration of the object. The slope of the velocity vs. time graph represents the acceleration of the object, since acceleration is the rate of change of velocity with respect to time.
Since the initial position of the object is zero, the velocity vs. time graph will pass through the origin. Therefore, we can use the part of the graph between the initial time t=0 and the final time when the velocity is 10 m/s. This part of the graph will be a straight line with positive slope, representing the constant acceleration of the object.
We can calculate the slope of this line by finding the change in velocity and dividing by the time elapsed:
a = (vf - v0) / t
Substituting the given values, we get:
a = (10 - 3) / t
Therefore, the acceleration of the object is 7/t, where t is the time elapsed between the initial and final velocities.
Substituting this value for a into the expression for displacement, we get:
d = 91 / (2(7/t)) = (91t) / 14
Therefore, the part of the velocity vs. time graph between t=0 and the final time can be used to calculate the displacement of the object using the equation d = (91t) / 14.
A roller coaster car is released from rest as shown in the image below.
Ignoring friction, what will be the approximate velocity of the car when it
reaches the bottom of the roller coaster in the image? (Recall that g = 9.8
m/s².)
49 m
OA. 16 m/s
OB. 48 m/s
OC. 55 m/s
OD. 31 m/s
The speed of the roller coaster car as shown is 31 m/s
What is the Roller coaster?We know that the roller coaster is the kind of device that we can use to be able to show the conversion of kinetic energy to potential energy. By the use of the roller coaster, we can show that the total mechanical energy in the system is a constant.
As such we have that;
mgh = 1/2mv^2
m = mass of the object
g = acceleration due to gravity
h = height
v = velocity
Hence;
gh= 1/2v^2
v = √2gh
v = √ 2 * 9.8 * 49
v = 31 m/s
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The Mars Rover Curiosity has a mass of 900 kg. Taking the gravitational field strength to be 9.8 N/kg
on Earth and 3.7 N/kg on Mars, give the value of the weight of the Rover on earth and mars
The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.
Weight of objects on Earth and on MarsThe weight of an object is given by the product of its mass and the gravitational field strength at its location.
On Earth:
Weight = mass x gravitational field strengthWeight = 900 kg x 9.8 N/kgWeight = 8820 NOn Mars:
Weight = mass x gravitational field strengthWeight = 900 kg x 3.7 N/kgWeight = 3330 NTherefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.
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Please help! Not sure what the answer is for both questions shown
The electric potential energy of charge 2q is 2kq/d.
The total electric potential energy of the system is k/d(5q).
What is the contribution of charge 2q?The contribution of charge 2q to the electric potential energy of the system is calculated as follows;
U = kq/r²
where;
k is coulomb's constantq is the magnitude of the charger is the position of the chargeThe electric potential energy of charge 2q is calculated as follows;
U_2q = (k x 2q)/d
where;
d is the position of the chargeSimplify further and we will have;
U_2q = 2kq/d
The total electric potential energy of the system is calculated as;
U_tot = k/d (2q + q - 3q + 5q)
U_tot = k/d(5q)
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The spring shown in the Figure below is compressed 50 cm and used to launch a 100 kg physics student. The track is frictionless until it starts up the incline. The student’s coefficient of kinetic friction on the 30◦ incline is 0.15. (a) What is the student’s speed just after losing contact with the spring?
(b) What is the student’s speed immediately before moving up the 30◦ incline?
(c) How far up the incline does the student go?
part a.
The student’s speed just after losing contact with the spring is 14.14 m/s
part b.
The students can go up to 32.06cm
What is speed?Speed is described as one such measurable quantity that measures the ratio of the distance travelled by an object to the time required to travel that distance.
Given values:
The spring shown below is compressed = 50 cmand is used to launch a 100kg physics student. The track is frictionless until it starts up the incline. The student's coefficient of kinetic friction on the 30° incline = 0.15We apply the conservation of energy, energy in the compressed string:
1/2 mv2 = 1/2 kx²v²
which will be [tex]\sqrt{kxv}/m[/tex]
substituting we have the value as 14.14 m/s
part b.
then conservation of energy equation will become:
1/2 kx² + mgh
substituting we have the value as 32.06cm
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.
Which of the following equations could be used to derive an expression for the electric field created by a changing magnetic field?
Option C is the use of the equations to arrive at an expression for the electric field produced by a shifting magnetic field.
A current will be induced in a coil of wire if the coil is put in a magnetic field that is changing. Since there is an electric field causing the charges to be forced around the wire, current is flowing as a result. The charges are not initially moving, hence it cannot be the magnetic force.
The moving + and - charges radiate a changing electric field, and it is also visible that this field generates a changing magnetic field as well. With increasing distance from the antenna, the source of the radiation, the electric and magnetic fields lose strength.
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Which is the formula that describes the magnitude of an objects momentum?
Answer:
B. momentum = mass x velocity
Explanation:
P = mv
Paul rides his bike at a constant speed of 8.3 m/s (30 km/h) for a time equal to
120 seconds.
To. Calculate the distance it traveled during this time.
b. How long will it take at this speed to travel 3 km? Ask your calculation before giving the result
We have to know that the speed is the ratio of the distance to the time and that the speed is a scalar quantity. We are going to apply the concept of the speed here.
The SI unit of speed is meters per second (m/s). Other common units of speed include kilometers per hour (km/h) and miles per hour (mph).
Speed = Distance/Time
Distance = Speed * Time
= 120 seconds * 8.3 m/s
= 996 m/s
The time that is taken so as to travel 3 Km at this speed is
Time = Distance/Speed
Time = 3000 m/996 m/s
= 3 s
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8. All nuclear power plants have backup generators in case the plant stops producing electricity. Why is this necessary? What exactly are the generators providing power for? What might happen if these backup generators fail?
Nuclear power plants have backup generators to ensure that essential equipment, such as cooling systems, can continue to function in the event of a power outage or other emergency.
Nuclear power plants rely on a constant supply of electricity to operate the equipment that controls the nuclear reaction and cools the reactor. If the power supply is interrupted, the reactor can overheat and damage can occur. Backup generators provide power to essential equipment, such as cooling systems, that keep the reactor and spent fuel pools from overheating. If the backup generators fail, there is a risk of a nuclear accident, as was seen in the disaster in 2011, where the failure of backup generators led to a loss of cooling and a major nuclear incident.
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Which is an unnecessary rule for writing chemical formulas?
While the use of parentheses to indicate the number of a particular group of atoms in a compound can be helpful, it is not strictly necessary for writing a correct chemical formula.
There are several rules that should be followed when writing chemical formulas, but one of the unnecessary rules is the use of parentheses to indicate the number of a particular group of atoms in a compound. For example, the formula for magnesium carbonate can be written as MgCO₃ or as Mg(CO₃)₂, where the parentheses indicate that there are two carbonate ions present.
While the use of parentheses can make it clearer which group of atoms is being referred to, it is not necessary for writing a correct chemical formula. The number of each type of atom in the compound can be determined from the compound's name or from knowledge of the properties of the elements involved.
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Approximately 20.0gm of milk at 6.0oC is added into a cup containing 270.0 gm of weak tea. The specific heat of weak tea is 3.91 x 103J kg-1 oC-1 and the final temperature of the milk - tea mixture is 85.0oC. Given the initial temperature of the weak tea is 90.0oC, what is the specific heat of milk?
Answer:
4161 J/kg·°C
Explanation:
We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.
Let's first calculate the heat lost by the tea:
Q(tea) = mcΔT
Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)
Q(tea) = 6555 J
where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.
Next, let's calculate the heat gained by the milk:
Q(milk) = mcΔT
Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)
Now we can equate the two expressions:
Q(tea) = Q(milk)
6555 J = (0.02 kg)(c)(79.0°C)
Solving for c, we get:
c = 4161 J/kg·°C
Therefore, the specific heat of milk is approximately 4161 J/kg·°C.
Which of the following is an example of a relapse "slip" rather than "fall"?
OA. Hailey was trying to eat healthier, but she ate a bowl of ice cream
after dinner.
O B. Kyle was trying to exercise regularly, but then he got sick for a
week and now hasn't exercised all month.
OC. Sally was trying to eat healthy snacks, but then after school she
ate a pan of brownies by herself.
OD. Troy was trying to get stronger, so he participated in a strength
training program all year but then got too busy and did not lift a
single weight all summer.
An example of relapse is D, Troy was trying to get stronger, so he participated in a strength training program all year but then got too busy and did not lift a single weight all summer.
What is relapse?After a time of improvement or change, relapse is the return to a prior state or behavior. Relapse is used to describe the restart of drug or alcohol use or other addictive behaviors after a period of abstinence or recovery in the context of addiction or recovery.
This is an example of a relapse "slip" because Troy was making progress towards his goal of getting stronger but temporarily stopped due to being busy, whereas a "fall" would imply a complete abandonment of the goal with no intention of getting back on track.
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Answer: The correct answer is A "Hailey was trying to eat healthier, but she ate a bowl of ice cream after dinner."
Explanation: I got it right on the test
GL to all of you out there <3
Edible oil (specific gravity 5 0.83) flows through a venturi meter with a range of flow rates from 0.002 to 0.02 m3 /s. Calculate the range in pressure differences required to measure these flow rates. Pipe diameter is 15 cm and diameter of the venturi throat is 5 cm
The range in pressure differences required to measure the flow rates of 0.002 and 0.02 m^3/s is approximately 2,710.62 Pa.
The pressure difference across a venturi meter is given by the Bernoulli's equation, which states that the sum of the pressure, kinetic energy and potential energy at any two points in a fluid flow system is constant.
Assuming the flow is incompressible and there is no energy loss due to friction or heat transfer, the equation can be expressed as:
[tex]P1 + 1/2 * rho * V1^2 + rho * g * h1 = P2 + 1/2 * rho * V2^2 + rho * g * h2[/tex]
where,
P1 and P2 are the pressures at the inlet and throat of the venturi meter, respectively,
rho is the density of the fluid,
V1 and V2 are the velocities at the inlet and throat,
h1 and h2 are the elevations of the inlet and throat,
and g is the acceleration due to gravity.
Assuming that the elevations of the inlet and throat are the same,
h1 = h2, and the velocity at the inlet is negligible compared to the velocity at the throat, V1 ≈ 0, the Bernoulli's equation simplifies to:
[tex]P1 - P2 = 1/2 * rho * (V2^2 - V1^2)[/tex]
Using the continuity equation, which states that the mass flow rate is constant in a fluid flow system, the velocity at the throat can be calculated as:
[tex]A1 * V1 = A2 * V2[/tex]
where A1 and A2 are the cross-sectional areas of the pipe at the inlet and throat, respectively.
The cross-sectional areas of the pipe and throat are:
[tex]A1 = pi * (15/2)^2 = 176.71 cm^2\\A2 = pi * (5/2)^2 = 19.63 cm^2[/tex]
Using the specific gravity of the oil, we can calculate its density as:
rho = specific gravity * density of water
= [tex]0.83 * 1000 kg/m^3[/tex]
= [tex]830 kg/m^3[/tex]
Therefore, the range in pressure differences required to measure the flow rates of 0.002 and 0.02 [tex]m^3/s[/tex] is:
For the maximum flow rate of 0.02 [tex]m^3/s[/tex]:
[tex]V2 = (A1/A2) * V1 \\= (176.71/19.63) * 0.02 / (100/1) \\= 1.8112 m/s\\\\P1 - P2 = 1/2 * rho * (V2^2 - V1^2) \\= 1/2 * 830 * (1.8112^2 - 0) \\= 2,738 Pa[/tex]
For the minimum flow rate of 0.002 [tex]m^3/s[/tex]:
[tex]V2 = (A1/A2) * V1 \\= (176.71/19.63) * 0.002 / (100/1) \\= 0.18112 m/s\\\\P1 - P2 = 1/2 * rho * (V2^2 - V1^2) \\= 1/2 * 830 * (0.18112^2 - 0)\\ = 27.38 Pa[/tex]
Therefore, the range in pressure differences required to measure the flow rates of 0.002 and 0.02 m^3/s is approximately:
[tex]2,738 Pa - 27.38 Pa = 2,710.62 Pa.[/tex]
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in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
Firing a gun straight up into the air can be dangerous because the bullet, when it falls back to Earth, can reach a high enough velocity to cause injury or even death.
When a bullet is fired straight up into the air, it will eventually reach the highest point of its trajectory and begin to fall back down due to gravity. As it falls, it gains speed and momentum, which can cause it to reach a lethal velocity when it impacts a person or object on the ground. This phenomenon is known as "celebratory gunfire," and it can cause serious harm to people who are hit by falling bullets. Therefore, firing a gun straight up into the air is never a safe or responsible act.
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--The complete question is, What is the scientific explanation for why firing a gun straight up into the air can be dangerous, despite the fact that the bullet will eventually fall back down to Earth?--
Which of the following is NOT a suggestion for relapse prevention?
OA. Make sure the exercise program is easy so that you are not
challenged.
O B. Tell your family and friends about your progress with exercising.
C. Determine ways to overcome barriers.
D. Take injury prevention precautions.
SUBMIT
Make sure the exercise program is easy so that you are not challenged is NOT a suggestion for relapse prevention. The correct option is A
What is relapse prevention ?Relapse prevention is a technique used to support people in maintaining long-term behavioral change and stop them from reverting to previous unhealthy practices.
Relapse prevention can take many different forms including :
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a. If the frequency of light is increased above the threshold frequency, the
energy of the electrons emitted will _________________.
b. If the frequency of light is decreased to below the threshold frequency, the
rate at which electrons are emitted will _______________.
c. If the intensity of light is decreased, the energy of the electrons emitted will ____________________.
d. If the intensity of light is decreased, the rate at which electrons are emitted will ________________.
Answer:
a. If the frequency of light is increased above the threshold frequency, the energy of the electrons emitted will increase.
b. If the frequency of light is decreased to below the threshold frequency, the rate at which electrons are emitted will decrease.
c. If the intensity of light is decreased, the energy of the electrons emitted will remain the same, but fewer electrons will be emitted.
d. If the intensity of light is decreased, the rate at which electrons are emitted will decrease.
1. Young's Double Slit Experiment with light proved that light was a wave from a reflection.
a. True
b. False
2. Sound waves speed up as they go farther down in the ocean because of multiple factors such as the ocean's waves' wavelengths being longer, pressure increasing, and salinity.
a. True
b. False
1. Young's Double Slit Experiment with light proved that light was a wave from a reflection. FALSE
2. Sound waves speed up as they go farther down in the ocean because of multiple factors such as the ocean's waves' wavelengths being longer, pressure increasing, and salinity. TRUE.
What is reflection of light?
The reflection of the light occurs when light hits a hard surface and falls back.
The Young's Double Slit Experiment with light did not prove that light was a wave from a reflection.
For question, 2;
Sound waves speed up as they go farther down in the ocean because of multiple factors such as the ocean's waves' wavelengths being longer, pressure increasing, and salinity.
The above statement is true, as speed of a wave increases with increase in its wavelength.
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Consider a system consisting of a block of mass m attached to a spring with spring constant k, sliding on a frictionless surface. If the block is displaced from its equilibrium position by a distance x and then released, what is the period of its motion?
If the block is displaced from its equilibrium position by a distance x, the period of its motion is T = 2π/ω = 2π√(m/k).
What is the period of motion of the block?
The period of motion of a block under simple harmonic motion is given as;
T = 2π√(m/k)
Where;
T is the periodm is the mass of the blockk is the spring constantWhen the block is displaced from its equilibrium position by a distance x, the force acting on it is given as;
F = -kx
where;
x is displacementWe also know that angular velocity is given as;
ω = √(k/m)
So the equation for the period can also be;
T = 2π/ω = 2π√(m/k)
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Great Company manufactures and sells a product whose peak sales occur in the third quarter. Management is now preparing detailed budgets for 20x4- the coming year and has assembled the following information to assist in the budget preparation: The company’s product selling price is Br. 20 per unit. The marketing department has estimated sales in units as follows for the next six quarters.
Answer:
Explanation:
Quarter 1 - 10,000 units
Quarter 2 - 12,000 units
Quarter 3 - 16,000 units
Quarter 4 - 14,000 units
Quarter 5 - 10,000 units
Quarter 6 - 8,000 units
Based on this information, the total estimated sales revenue for the next six quarters is Br. 480,000.
A slingshot consists of a light leather cup containing a stone. The cup is pulled back against two parallel rubber bands. It takes a force of 15 N to stretch either one of these bands 1.0 cm. (a) What is the potential energy stored in the two bands together when a 47-g stone is placed in the cup and pulled back 0.22 m from the equilibrium position?(b) With what speed does the stone leave the slingshot?
(A) The potential energy stored in the two rubber bands together will be 9.90 J. (B) the speed of the stone when it leaves the slingshot will be 10.5 m/s.
To solve this problem, we need to use the formula for potential energy stored in a spring:
U = (1/2)kx²
where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.
(a) To find the potential energy stored in the rubber bands, we need to first calculate the spring constant. We know that it takes a force of 15 N to stretch one rubber band by 1.0 cm, so the spring constant for one rubber band is:
k = F/x = 15 N / 0.01 m = 1500 N/m
The two rubber bands are in parallel, so the effective spring constant for both of them together is:
ktotal = 2k = 3000 N/m
To calculate the displacement of the slingshot when the stone is pulled back. The equilibrium position is where the rubber bands are unstretched, so the displacement is:
x = 0.22 m
Finally, we can calculate the potential energy stored in the rubber bands:
U = (1/2)ktotal × x² = (1/2)(3000 N/m)(0.22 m)² = 9.90 J
Therefore, the potential energy stored in the two rubber bands together is 9.90 J.
(b) To find the speed of the stone when it leaves the slingshot, we need to use the conservation of energy:
U = K
where U is the potential energy stored in the rubber bands and K is the kinetic energy of the stone when it leaves the slingshot.
The potential energy stored in the rubber bands is 9.90 J, and the kinetic energy of the stone when it leaves the slingshot is:
K = (1/2)mv²
where m is the mass of the stone and v is its velocity.
We know the mass of the stone is 47 g, which is 0.047 kg. We can solve for the velocity:
v = √(2K/m) = √(2(9.90 J)/0.047 kg) = 10.5 m/s
Therefore, the speed of the stone when it leaves the slingshot is 10.5 m/s.
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aluminium oxide formulae
Answer:
formula of aluminum oxide Al₂O₃
