Bobby and Alice are pushing a stalled car in the same direction. The mass of the car is 2,000 kg. Bobby applies 400 N to the car while Alice applies 300 N. A force created by friction is 500 N in the opposite direction is the acceleration of the car is 0.1 m/sec.
What is acceleration?An acceleration, fee at which pace adjustments with time, in phrases of each velocity and direction. A factor or an item shifting in a direct line is expanded if it hurries up or slows down.
Is summarized via way of means of the equation: Force (N) = mass (kg) × acceleration (m/s²).The mass = 2000 kg and force= 1200 N. So mass / force = 2000/1200 = 0.1 m/sec.
Thus, the acceleration of the car s 0.1 m/sec.
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You turn on a cars radio, what energy transformation is taking place?
Answer:
C probably
Explanation:
think c because when you first start the car the first thing you hear electrical sound.
If a cup of coffee is at 90°C and a person with a body temperature of 36°C touches it, how will heat flow between
them?
O from the hand to the cup
from the cup to the hand
from the cup to the surrounding air
from the hand to surrounding air
Mark this and return
Save and Exit
ext
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Answer:
if you pick it up the heat will flow to the hand until the Temperature of both evens out
6. A metal block increases in temperature from 15 °C to 60 °C when supplied with 13 500 J of heat energy.
a) Calculate the heat capacity of the metal.
b) Calculate the specific heat capacity of the metal, if this sample has a mass of 0.75 kg.
Answer:
Since 1 cal = 4.19 J the heat Q received by the metal is
Q = 13,500 J * 1 C / 4.19 J = 3,222 calories
S = ΔQ / (ΔT * ΔM) = 3222 cal / (45 deg C / 750 gm)
S = .095 cal / gm deg C
Note that specific heat capacity for Cu is .093 cal / gm deg C
a highway curve has a radius of 300 m. at what angle should it be banked for a traffic speed of 100 km/h
The angle at which it should be banked for a traffic speed of 100 km/h is
14.57°.
How do find the angle of Banking of road?Banking of roads is the practice of raising the outer borders of curving roads over the inner edge in order to give vehicles the necessary centripetal force to make a turn safely.Skidding can be prevented by banking.The banking of roadways aids in preventing toppling or overturning.To find the angle of banking following formula can be used,
[tex]tan \alpha = v^{2} /rg[/tex]
Given v = 100km/h or
= 100 x 1000 / 3600
= 27.7 m/s
Hence,
[tex]tan \alpha = (27.7)^{2} / 300 * 9.81[/tex]
[tex]tan\alpha = 0.26[/tex]
[tex]\alpha = tan^{-1} 0.26[/tex]
[tex]\alpha = 14.57[/tex]°
Hence, the angle of banking of the road will be 14.57°
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A diver shines a light up to the surface of a flat glass-bottomed boat at an angle of 37◦ relative to the normal. If the indices of refraction of air, water, and glass are 1.0, 1.33, and 1.4 respectively, at what angle does the light leave the glass (relative to its normal)? Answer in units of ◦ .
Answer:
Approximately [tex]53^{\circ}[/tex], assuming that the upper and lower surfaces of the glass on this boat are parallel.
Explanation:
Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.
The following angles would be alternate interior angles between the two normals:
The angle at which the light enters the glass, andThe angle at which the light leaves the glass.Since the two normals are parallel to each other, these two angles would have the same value. Let [tex]\theta_{\text{glass}}[/tex] denote the value of both of these angles.
Let [tex]\theta_{\text{src}}[/tex] denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let [tex]\theta_{\text{dst}}[/tex] denote the angle at which this beam of light enters the new medium.
Let [tex]n_\text{src}[/tex] and [tex]n_\text{dst}[/tex] denote the refractive indices of the original and the new medium, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}[/tex].
Let [tex]\theta_{\text{water}}[/tex] denote the angle at which the beam of light in this question leaves the water. Let [tex]\theta_{\text{air}}[/tex] denote the angle at which this beam of light enters the air. It is given that [tex]\theta_{\text{water}} = 37^{\circ}[/tex], while [tex]\theta_{\text{air}}[/tex] is the value that needs to be found.
Let [tex]n_{\text{air}}[/tex], [tex]n_{\text{water}}[/tex], and [tex]n_{\text{glass}}[/tex] denote the refractive index of air, water, and glass, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}[/tex].
[tex]\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}[/tex].
Thus:
[tex]\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}[/tex].
Since [tex]\theta_{\text{water}} = 37^{\circ}[/tex]:
[tex]\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}[/tex].
In other words, this beam of light would leave the glass at approximately [tex]53^{\cic}[/tex] from the normal.
Joe runs 10 m north, 20 m south, 9m south, and then 15 m north. What is Joe's
displacement?
Answer:
Joes displacement is 54m
What is the magnitude of the force exerted on an electron in an electric field with a strength of 6.5 *10^ 8 N/C? Remember, the charge on an electron is 1.6 * 10 ^ - 19 * C
All work must be shown to earn credit
The field exerts 6.5 x 10⁸ Newton of force on EACH COULOMB of charge in the field.
We're putting 1.6 x 10⁻¹⁹ Coulomb of charge into the field.
The force on it will be
(1.6 x 10⁻¹⁹ Coulomb) x (6.5 x 10⁻⁸ Newton/Coulomb).
That's 1.04 x 10⁻¹⁰ Newton.
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
The focal length of given concave lens will be -26.85 cm
The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.
Given concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.
We have to find focal length
The focal length can be found out by following way:
Magnification = m = +1.75
m = hi/h
hi = -47 cm
1.75 = -47/h
h = -26.85 cm
So the focal length of given concave lens will be -26.85 cm
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Answer:
26.85
Explanation: I got it right on Acellus.
While a substance is heated it reaches its boiling point. What happens if heating continues while it is boiling?
Answer:
liquid turns into vapor when the liquid molecules achieves the energy to break down the form or when gets highly excited. The temp required for this is called latent heat of vaporization. As the liquid molecules attain this energy through heat it suddenly changes form into vapor , and when the heat is continued , molecule after molecule receives this energy and changes to vapor .So if you continue heating the liquid all the liquid will change form to vapor state leaving residue , ie the dissolved particles .
liquid turns into vapor when the liquid molecules achieves the energy to break down the form or when gets highly excited. The temp required for this is called latent heat of vaporization. As the liquid molecules attain this energy through heat it suddenly changes form into vapor , and when the heat is continued , molecule after molecule receives this energy and changes to vapor .So if you continue heating the liquid all the liquid will change form to vapor state leaving residue , ie the dissolved particles .I’m no expert but this is what i think happens …
Please help me!!
1. For objects like insulators (plastics), they can get charged by ___.
2. For metals, where there are more loosely bound electrons, they can get charged without contact by ___.
3. For metals, they can also be charged by direct contact by ___.
Injuries occur from muscle imbalances which result from the body's inability to ....................... these types of stress.
Answer:
Tolerate
Explanation:
Which of the following can be contracted from contact with bloodborne pathogens?
HIV can be contracted from contact with bloodborne pathogens.
Other bloodborne diseases are HBV, malaria, syphilis and brucellosis
What are bloodborne pathogens?Bloodborne pathogens can be defined as those microorganisms or pathogenic organisms that cause disease and are present in human blood.
Blood borne pathogens can also be contacted through the following means
Se- xual contactNeedle contactIn conclusion; HIV can be contracted from contact with bloodborne pathogens.
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the work function for magnesium is 3.70 ev. what is its cutoff frequency?
The cutoff frequency for magnesium is 8.93 x 10¹⁴ Hz.
What is cutoff frequency?The work function is related to the frequency as
W0 = h x fo
where, fo = cutoff frequency and h is the Planck's constant
Given is the work function for magnesium is 3.70 eV.
fo = 3.7 x 1.6 x 10⁻¹⁹ / 6.626 x 10⁻³⁴
fo = 8.93 x 10¹⁴ Hz.
Thus, the cut off frequency is 8.93 x 10¹⁴ Hz.
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The flux through the coils of a solenoid changes from 2.57.10-5 Wb to 9.44.10-5 Wb in 0.0154 s. If 4.08 V of EMF is generated, how many loops does the solenoid have? (No unit)
Hello!
We can use Faraday's Law of Electromagnetic Induction to solve.
[tex]\epsilon = -N \frac{d\Phi_B}{dt}[/tex]
ε = Induced emf (4.08 V)
N = Number of loops (?)
[tex]\Phi_B[/tex] = Magnetic Flux (Wb)
t = time (s)
**Note: The negative sign can be disregarded for this situation. The sign simply shows how the induced emf OPPOSES the current.
Now, we know that [tex]\frac{d\Phi_B}{dt}[/tex] is analogous to the change in magnetic flux over change in time, or [tex]\frac{\Delta \Phi_B}{\Delta t}[/tex], so:
[tex]\epsilon = N \frac{\Delta \Phi_B}{\Delta t}\\\\\epsilon = N \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}[/tex]
Rearrange the equation to solve for 'N'.
[tex]N = \frac{\epsilon}{ \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}}[/tex]
Plug in the given values to solve.
[tex]N = \frac{4.08}{ \frac{9.44*10^{-5} - 2.57*10^{-5}}{0.0154}} = 914.585 = \boxed{915 \text{ coils}}[/tex]
**Rounding up because we cannot have a part of a loop.
In infrared satellite images, land appears _________ and clouds appear _________. A. red, yellow B. white, black C. black, white D. yellow, red
In infrared satellite images, land appears black and clouds appear white. C
What are infrared satellite images?Infrared satellite images are images produced as a result of electromagnetic radiations reflected or emitted from a target surface in the infrared position of the electromagnetic spectrum.
On infrared images, the clouds emit very bright white color because of the low temperature and the land appears to be black because of the hot temperature.
Therefore, in infrared satellite images, land appears black and clouds appear white. C
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Given the following specific heat capacities, which material was have the largest change in temperature if 10 grams of each substance absorbs 100 calories of heat?
Substance Heat Capacity - Cal / (g oC)
aluminum 0.22
copper 0.093
lead 0.0305
silver 0.056
Answer:
Explanation:
Comment
You could calculate it out by assuming the same starting temperature for each substance. (You have to assume that the substances do start at the same temperature anyway).
That's like shooting 12 with 2 dice. It can be done, but aiming for a more common number is a better idea.
Same with this question.
You should just develop a rule. The rule will look like this
The greater the heat capacity the (higher or lower) the change in temperature.
The greater the heat capacity the lower the change in temperature
That's not your question. You want to know which substance will have the greatest temperature change given their heat capacities.
Answer
lead. It has the smallest heat capacity and therefore it's temperature change will be the greatest.
Find the relationship
[tex]\\ \rm\Rrightarrow Q=mc\Delta T[/tex]
[tex]\\ \rm\Rrightarrow 100=10c\Delta T[/tex]
[tex]\\ \rm\Rrightarrow 10=c\Delta T[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{10}{c}=\Delta T[/tex]
[tex]\\ \rm\Rrightarrow \Delta T\propto \dfrac{1}{c}[/tex]
So lower the c higher ∆T
Lead has the largest change in T as it has least capacity
Select the correct answer.
What is the average velocity of the particle from rest to 9 seconds?
The average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
How to find the average velocity?This average velocity can be calculated with the following equation:
v = dx / dt
where:
dx = displacement = 18 meters
dt = interval of time = 9 seconds
Substitute;
v = dx / dt
v = 18 / 9
v = 2 meters/sec
Hence, the average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
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A squirrel sitting on the ground starts to run with an acceleration of 5.1 m/s².
How fast is the squirrel going after 0.25 seconds?
O A. 20.4m/s
OB. 0.49 m/s
OC. 3.1 m/s
OD. 1.28 m/s
Answer:
0.159
Explanation:
the formula to find its is 1÷2*gt^2
Answer:
D
Explanation:
v= a t
= 5.1 * .25 = 1.275 m/s
Why is it important to remember "association, not
causation" when discussing correlations?
It is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.
What is the value of associations in science?The associations among variables have a fundamental value in science because they can determine how such variables behave in hypothetical situations.
Moreover, correlation only indicates a type of association between variables and therefore it is less informative.
In conclusion, it is important to remember "association", instead of "causation" when discussing correlations because associations can be used to make predictions.
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A 2.0-V battery is connected in a circuit with an ammeter and an unknown resistor, P. The current is observed to be 0.70 A. What would be the current in the circuit if a 12-V battery replaces the 2.0-V battery?
Answer:
4.2 A
Explanation:
V=IR
V= voltage
I= Current
R= resistance
so you will find the resistance in the circuit so
R= V/I
R=2V/0.70A
R=2.857 ohms ( TO THE NEAREST THOUSANDTH)
then you will find the current of the 12V battery using the resistance in the circuit
I=V/R
I=12/2.857
I=4.2A (TO THE NEAREST TENTH)
Consider an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.
1.What is the electric flux through the cylinder due to this infinite line of charge?
2.What is the flux through the cylinder if its radius is increased to r= 0.600 m ?
3.What is the flux through the cylinder if its length is increased to l= 0.990 m ?
The electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C
Given an imaginary cylinder with a radius of r = 0.185 m and a length of l = 0.440 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is λ = 4.50 μC/m.
Solve for the electric flux through the cylinder due to this infinte line:
As below equation mentions, the electric flux for a uniform electric filed is given by:
Фₓ = EA cosΦ
Φₓ = λLcosΦ)/ε
Φₓ = (3 x 10^(-6) x 0.4 x cos0)/(8.854 x 10^(-12))
Φₓ = 1.355 x 10^(5) Nm²/C
Hence the electric flux through the cylinder due to this infinte line is 1 355 x 10' N m²/C, The electric flux through the cylinder is independent of the radius of the cylinder. So, the electric flux through the cylinder is the same as in part (a) which is equal to is 1.355 10 Nm C and The electric flux through the cylinder due to this infinte line is 2.711 x 10' N m² C
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A point charge is placed 3m from a 4uc charge what is the strength of the electric field on the point charge at this distance round to the nearest thousand
The strength of the electric field on the point charge at this distance will be 4000 V/m.
What is the strength of the electric field?
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;
[tex]\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m[/tex]
Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
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5, the following equation shows the position of a particle in time t, x=at2i + btj where t is in second and x is in meter. A=2m/s2, b=1m/s. Find
A, the average velocity of the particle in the time interval t1=2sec and t2=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)
The average velocity is 4i m/sec
The average acceleration is 4i
What is a average velocity ?Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs. T
According to the question,
x=at²i + btj ( t is in second and x is in meter).
Average velocity = [tex]\frac{dx}{dt}[/tex]
[tex]\frac{dx}{dt} = 2at i + b j\\\\\frac{dx}{dt} = 2 * 2 * t i +1 j\\\\\frac{dx}{dt} = 4t i +j[/tex]
[tex]\frac{dx}{dt}[/tex] in the time interval of 2 to 3 sec is
at 2 sec,
[tex]\frac{dx}{dt} = 4 * 2 i +j = 8i +j[/tex]
at 3 sec ,
[tex]\frac{dx}{dt}[/tex] = 4 * 3 i + j = 12i+j
Therefore the average velocity is
[tex]\frac{(12i +j - 8i -j)}{(3-2)} = 4i[/tex]
The velocity at any given time is [tex]\frac{dx}{dt} = 4t i +j[/tex]
The acceleration at any given time is [tex]\frac{dx^2}{dt^2}[/tex]
[tex]\frac{dx^2}{dt^2} = 4 i[/tex]
The average acceleration in the time interval t₁=2sec and t₂=3sec
Average Acceleration = 4i
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You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, it accelerates because the engines are at full throttle and because there is a catapult that propels the jet forward. You begin to wonder how much force is supplied by the catapult. You look on the Web and find that the flight deck of an aircraft carrier is about 90.0 m long, that an F-14 has a mass of 24800 kg, that each of the two engines supplies 27000 lb of thrust, and that the takeoff speed of such a plane is about 158 mi/h. Estimate the average force on the jet due to the catapult.
You are watching a television show about Navy pilots. The narrator says that when a Navy jet takes off, the average force on the jet is due to the catapult is mathematically given as
What is the average force on the jet is due to the catapult?
Generally, the equation for acceleration is mathematically given as
[tex]a=\frac{vf^2-vi^2}{2s}\\\\\Therefore\\\\a=\frac{69.29^2-0^2}{2(90}\\\\a=26.673m/s^2[/tex]
In conclusion, The force
F=m*a
F=15100*26.673
F=40272.3N
F 402 KN
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The amplitude of the wave in the picture below is... Select one: a. 1 cm b. 1.5 cm c. 2 cm d. 3 cm
Answer:
1cm
Explanation:
The amplitude of a wave is the distance from the center line (in this case the 1 cm marker on the vertical ruler) to the highest or lowest point. For this image the highest point is 2 cm, 2cm-1cm=1cm. The lowest point is 0cm, 1cm-0cm=1cm.
The amplitude of the wave is 1 cm. So, the correct option is a.
What is meant by amplitude of a wave ?A point on a vibrating body or wave can move up to its maximum distance or displacement when measured from its equilibrium position, which is known as the amplitude. It is equivalent to the length of the vibration path divided in half.
Here,
The crests and trough of a wave is given. Amplitude can also be defined as the peak distance of the crest or trough of the wave.
From the given diagram, we can say that the sum of heights of the crest and trough is given as 2 cm. So, that will be the total vibration path. So, half of its length will give the amplitude of the wave.
Therefore, the amplitude of the wave,
A = 2/2 = 1 cm
Hence,
The amplitude of the wave is 1 cm. So, the correct option is a.
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A stone is dropped from the top of a tower which touches the ground after 2 seconds. Calculate the speed of the stone hitting the ground surface. (g = 9.8 m/s²)
Answer:
19.6 m/s
Explanation:
The velocity is the product of acceleration and time.
__
Here, the acceleration is due to gravity.
v = at
v = (9.8 m/s²)(2 s) = 19.6 m/s
The stone hits the ground with a speed of 19.6 m/s.
A stone is dropped from the top of a tower which touches the ground after 2 seconds.
Calculate the speed of the stone hitting the ground surface. (g = 9.8 m/s²).[tex] \mathbb{SOLUTION:} [/tex][tex]v = u + at[/tex][tex]v = 9.8 m/s² x 2sec[/tex][tex]v = 19.6 \: m/ {s}^{2} [/tex]••••••••••••••••••••••••••••••••••••••••••••Hence, The stone hit the ground with the velocity speed of 19m/s².
- When you're solving velocity, you're determining how fast an object moves from its original position, with respect to a frame of reference, and a function of time.
- That means an object's velocity will be equal to the object's speed and direction of motion.
"Problem has been solve"
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A ball A of mass 0.5 kg moving with a Velacity of 10 m/s a head on Collision with a ball B of mass 2kg moving with a Velocity of 1ms in the oppoite direction. If A and B stick together after Collision, Calculate the Common Velocity in the direction of A
Answer:
The common velocity v after collision is 2.8m/s²
Explanation:
look at the attachment above ☝️
A uniform electric field exist between two parallel plate seperated by 1.2 cm. The intensity of the field is 23 KN/C. What is the potential difference between the plates
Explanation:
this is the answer 276 volts
Two identical 3.0-kg cubes are placed on a horizontal surface in
contact with one another. The cubes are lined up from left to
right and a force F₁ is applied to the left side of the left cube
causing both cubes to move at a constant speed v. If the
coefficient of kinetic friction between the cubes and the
surface is 0.3, what is the magnitude of the force exerted by the
left cube on the right cube?
(3
The magnitude of the force exerted by the left cube on the right cube is 17.64N.
What is frictional force?When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.
Two identical 3.0-kg cubes are placed on a horizontal surface in contact with one another. The cubes are lined up from left to right and a force F₁ is applied to the left side of the left cube causing both cubes to move at a constant speed v. The coefficient of kinetic friction between the cubes and the surface is 0.3.
From the equilibrium of forces in vertical direction
Normal force N= 2m x g
friction force f = μN =μ(2m)g
From the equilibrium of forces in horizontal direction
F₁ =ma =0
using Newton's third law of motion, we get
F₁ - f =0
F₁ =f = μ(2m)g
Put the values, we get
F₁ = 17.64N
Thus, magnitude of the force exerted by the left cube on the right cube is 17.64N.
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A spoon inserted in a half-filled cup of water appears crooked because as light travels into a substance with a lower index of refraction, it... Select one: a. does not bend. b. bends away from the normal. c. bends toward the normal. d. is reflected.
Explanation:
The light is bent away from the normal
