A circuit element that hinders the flow of current:
O A. can never be used in a parallel circuit.
OB. increases the energy flow in the circuit.
OC. is called a resistor.
OD. allows excess accumulation of charge.

Answer: 20 m west

Explanation:

Considering the combined law equation the temperature increases by a factor of 1.5.

Gay-Lussac's Law

According to Gay-Law, Lussac's the gas molecules move more quickly as the temperature rises as long as the volume of the container holding the gas remains constant. The pressure then rises as a result of an increase in the number of shocks striking the walls. In other words, the relationship between a gas's pressure and temperature is direct.

In conclusion, when the volume remains constant, the pressure of the gas increases as the temperature rises. Additionally, gas pressure falls as temperature drops.

Gay-law Lussac's has the following mathematical formulation p/T =k so 3 P / T= 1/2 = 3/2 =1.5 =T

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If a bag of flour contains 5.00 lbs of flour. you have 3.20 tons of flour. there are 2000 lbs per ton, then there would be 1280 bags of flour that can be made.

Finding the product of two or more numbers in mathematics is done by multiplying the numbers. It is one of the fundamental operations in mathematics that we perform on a daily basis.

As given in the problem, if a bag of flour contains 5.00 lbs of flour. you have 3.20 tons of flour. there are 2000lbs per ton,

The number of bags = 3.20*2000/5.00

                                   =1280 bags

Thus, there would be 1280 bags of flour.

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The magnitude of the tension T is = 60N

The mass of the object held at rest = 6kg

The angle of the object at rest is = 30°

The magnitude of force F acting vertically downwards = 410N

Acceleration due to gravity= 10m/s²

The magnitude of tension T = ?

Using the formula; 2T sin(α) = m × g

make T the subject of formula,

T = m × g/ 2sin(α)

T = 6 × 10/ 2 sin (30)

T= 60/2 × 0.5

T = 60/1

T= 60N

Therefore, the magnitude of the tension T is = 60N

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My walking speed is 1.75 m.

Speed can be defined as the ratio of distance to time.

To calculate the walking speed, we use the formula below.

Formula:

Where:

From the question,

Substiotute these values into equation 1

Hence, my walking speed is 1.75 m.

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Answer:

Replication is vital to science. It helps make science a self-correcting system. Any time a result is surprising, research­ers will try to replicate it, to see if the phenom­enon is dependable or just a fluke

Explanation:

To travel a distance of 400 m the car will take a time of: 8.944 s

The formulas and procedures we will use to solve this exercise are:

Where:

Information about the problem:

Applying the final velocity formula  we have:

vf = √ (vi² + 2 * a * x)

vf = √ ((0 m/s)² + 2 * 10.0 m/s² * 400 m)

vf = √ (0 m²/s² + 8000 m²/s²)

vf = √(8000 m²/s²)

vf = 89.44 m/s

Applying the time formula we have:

t = (2 * x)/ (vi + vf)

t = (2 * 400 m)/ (0 m/s + 89.44 m/s)

t = 800 m / 89.44 m/s

t = 8.944 s

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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A) Transform faults have a direction that is perpendicular to plate motion.

Consider the double line in the transform fault diagram to be the boundary of two diverging plates and consider which direction the diverging plates would be travelling.

Fewer transform faults rip across the lithosphere of the continent. The San Andreas Fault Zone in western North America is the most well-known illustration of this.

Occasionally referred to as a strike-slip boundary, a transform fault or transform boundary is a fault along a plate boundary where the motion.

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A ball sitting still on the pitch obeys Newton's first law.

According to the first law of the Newton, a body would continue to be at rest or in state of uniform motion unless it is acted upon by an external force.

In this case, we have a football that is sitting still on a pitch. This ball is held by the force of inertia and the forces that act on it are balanced. If on the other hand this ball is not kicked (action of eternal force), it would continue to sit still on the pitch.

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The net displacement is obtained to be 3.6 m.

We know that distance is a scalar quantity and displacement is a vector quantity. Based on this fact, a scalar has a magnitude but lacks direction while vector has both magnitude and direction.

We know that the total distance could be obtained algebraically since distance is a scalar quantity hence we have the total distance as; 2 m + 3m + 4m = 9 m

The net displacement must be obtained geometrically;

Horizontal component of displacement = 4 m - 2m = 2m

Vertical component of displacement = 3m

Net displacement = √2^2 + 3^2

= 3.6 m

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The equivalent resistance of the combination is 30ohms

When two nodes share terminal connections, resistors are said to be in parallel. The smallest parallel resistor is smaller than the equivalent overall resistance. To find the equivalent resistance, after adding the reciprocal values together, take the reciprocal once more.

So, [tex]\frac{1}{R} = \frac{1}{R_{1} } +\frac{1}{R_{2} } +\frac{1}{R_{3} }[/tex]

[tex]\frac{1}{R} = \frac{1}{5} } +\frac{1}{10} } +\frac{1}{15} }[/tex]

[tex]\frac{1}{R} = \frac{1}{30} }[/tex]

R = 30 ohms

Therefore, the equivalent resistance of the combination is 30ohms.

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Publishers have the duty of supplying a platform for the exchange of medical data, whilst at the identical time, it's miles the duty of the authors, analysis magazine editors, and peer reviewers to ensure that the posted manuscripts are accurate.

It is through publication that the research, inclusive of their scientific and sensible contributions, is disseminated to others on a particular subject. This makes medical researchers and practitioners with comparable pastimes aware of the latest expertise in their field and it facilitates advanced know-how and its utility. at the same time as many editors and peer reviewers expect that studies posted in their journals have to be probably reproducible, there are no set methods to empirically check whether a finding may be independently reproduced.

A chief supply of irreproducibility additionally testing consists of widespread systematic blunders, that can arise while scientists are engaged in the experiments or all through statistical analyses Goodman et al 2016. Systematic errors can occur for a ramification of reasons, such as loss of medical talent two people acting in the same experiment may not have the same level of revel in or variability in issue populations or reagents Capes‐Davis & Neve, 2016. similarly, whilst a researcher has an insufficient statistical understanding or there are honest flaws inside the experimental layout and statistical output, the mistakes generated might inappropriately have an effect on the translation of the results Baker, 2016 Steen Casadevall, Fang 2013.

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When a hydrocarbon (CxHy) burns, CO₂ and H₂O are produced. C₄H₇ is the empirical formula.

moles of carbon in the mixture: 44 g x 1 mol C/mole/27.8 g CO₂ x 1 mol CO₂ in the compound, CO₂ equals 0.632 moles of C and 0.632 moles of H. 9.96 g H₂O times 1 mol H₂O and 18.g H₂O times 2 mol H/mol H2O equal 1.11 moles of H.

Total mass equals 8.69g (close enough to 8.70 so our assumption of no oxygen is correct)

We can divide both by the lowest value (0.632) to arrive at the lowest whole number of moles.

..

1.0 moles = 0.632/0.632 moles of C. H = 1.11/0.632=1.75

Now we can multiply both by 4 to get H as a whole number.

..

Molecules C = 4 Molecules H = 7

Empirical equation: C₄H₇

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Mass % of ethanol :  8.885

molality of ethanol : 2.12m

Given:

Wine = 11 % ethanol by volume

density of ethanal = 0.789 g/cm3

density of water = 1 g/cm3

let 100 cm3 wine  → 11.0 [tex]cm^3[/tex] ethanol, 89.0 [tex]cm^3[/tex] water.

Mass of ethanol = d x V = 0 789 g/cm3 x 11 cm3 = 8.679 cm3

Mass of water = d x Y = 1.000 g/cm3 x 89 cm3) = 89.00 cm3

Total mass of 100 cm3 wine = 8.679+89 = 97.679 cm3

Mass for % of ethanol = 8: 674 X100 = 8.8857 %

Molar mass of ethanol = 46 g/mole

Moles of ethanol = 8.679/46  = 0.1887 mole

Molality of ethanol = 0.1887/0.089 = 2.12 m

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Under the circumstances of the normal synthesis and degradation of cellular proteins, the amino acids are metabolized via oxidative degradation.

In animals, amino acids undergo oxidative degradation under different metabolic circumstances.

During the process of normal synthesis as well as the degradation of cellular proteins which is otherwise called protein turnover, there occurs some kinds of amino acids that are released from the breakdown of protein and which are not needed for the synthesis of new protein tend to undergo oxidative degradation.

Oxidative degradation is considered an important step in the mechanical catabolism of amino acids which then generates a more metabolizable kind of the amino acid as well as generates ammonia as a byproduct which is toxic. The ammonia generated thus can also be neutralized into urea through the urea cycle.

In general,  the normal synthesis and also the degradation of cellular proteins take place so as to make oxidative degradation where amino acids are metabolized.

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The properties of Sodium are as follows:

Elements are defined as any substance which cannot be split into simpler units aby a ordinary chemical process.

Elements are classified into metal, non-metals and metalloids.

Sodium one of the known 118 elements.

In the period table, sodium has the following properties:

In conclusion, sodium is an element in the periodic table.

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Answer: Polish creates a thin layer of wax on the surface of the leather which protects the leather from getting wet and undergoing wear and tear. It also has a lubricating effect on the leather keeping it supple and preventing the leather from drying out and cracking

By using inductive reactance, the current is 0.93 A.

We need to know about inductive reactance to solve this problem. The inductive reactance is the internal resistance in the inductor caused by changing current. It can be described as

XL = ω . L

where XL is inductive reactance, ω is angular speed and L is inductance.

The angular speed can be determined by

ω = 2π . f

where f is frequency.

From the question above, we know that

f = 100 Hz

L = 16 mH = 16 x 10¯³ H

V = 9.4 V

By substituting the given parameters, we get

XL = ω . L

XL = 2π . f . L

XL = 2π . 100 . 16 x 10¯³

XL = 10.06 Ω

Find the peak current

V = I . XL

9.4 = I . 10.06

I = 0.93 A

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45320 kN can be represented as 45.32×10³ kilo Newtons,568 mm can be represented as 0.568 meters and 0.00563 mg can be represented as 5.63×10³ micrograms.

A unit of measurement is a recognized and accepted standard for calculating other amounts of the same kind. It has already been decided by law or convention.

As stated in the issue, Use the proper prefix to represent each of the following as a number between 0.1 and 1000:

In this way, 45.32103-kilo Newtons, 0.568 meters, and 0.00563 mg may all be represented as 5.63103 micrograms, 45.32103-kilo Newtons, and 45.32103-kilo Newtons, respectively.

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The MOV instruction for double word variable three is

mov ax, word ptr three

mov bx, word ptr three+2

mov three, bx

mov word ptr three+2, ax

; initialize DWORD three

three DWORD 12345678h

; move the lower word (5678h) to ax

MOV ax, WORD PTR three

; move the upper word (1234h) to bx

MOV bx, WORD PTR[three + 2]

; move bx to lower word of three

MOV WORD PTR three, bx

; move ax to upper word of three

MOV WORD PTR[three + 2], ax

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The center of mass is located at 1.6 meters from 1 kg mass.

We need to know about the center of mass to solve this problem. The center of mass is the point where total torque is zero. It can be determined by

X = ∑mi.Xi / ∑mi

where m is mass and X is coordinate on the x-axis.

From the question above, we know that

m1 = 1 kg

m2 = 4 kg

L = 2 m

Assume that zero point is from m1. Hence,

X = ∑mi.Xi / ∑mi

X = ( m1 . X1 + m2 . X2 ) / (m1 + m2)

X = ( 1 . 0 + 4 . 2 ) / (1 + 4)

X = 8 / 5

X = 1.6 meters

Hence, the center of mass is located at 1.6 meters from 1 kg mass.

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When the voltage applied at the drain terminal is small, the mosfet channel behaves like a Current controlled voltage source.

An active load is created when the drain and gate of a MOSFET are coupled together, creating a two-terminal device known as a "diode-connected transistor." An active load is created when the drain and gate of a MOSFET are coupled together, creating a two-terminal device known as a "diode-connected transistor." The drain-source (or source-drain) connection of the MOSFET can be made open or connected by adjusting the charge distribution between the gate and body. Both NMOS and PMOS transistors function as switches in this way, but the specifics of the operation vary between the two types.

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The velocity of the body is 15.96 m/s.

We know that equations of kinematics could be used to obtain the velocity with which the pitcher would hit the ground. In this case we have the following;

Height of the ball = 13 m

Acceleration due to gravity = 9.8 m/s

Using;

v^2 = u^2 + 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

u = 0 m/s since it was dropped from a height

v^2 = 2gh

v = √2 * 9.8 * 13

v = 15.96 m/s

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In the process of Alpha decay 226 radium decays into 222 radon plus an alpha particle. In this process the energy released is about 4.6 Mev.

For example, In the process of Alpha decay 226 radium decays into 222 radon plus an alpha particle. In this process the energy released is about 4.6 Mev.

The number of protons of ra is 88 will be reduced to 86 and the number of neutrons of rn is 38 will be reduced to 36.

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When a medication alters the velocity of the conduction of electricity through the heart, it is said to have a Dromotropic effect.  

The word 'dromotropic' originates from the Greek word 'dromos' which means 'race' or 'running'. Dromotropic drugs are cardiac drugs that alter the conducting tissues of the heart, thereby affecting the velocity of the conduction of electricity through the heart.

Dromotropic drugs are given to patients in order to improve heart impulses. They alter the conducting tissues of the heart by changing the travelling speed of the SA node to the AV node.

Dromotropic drugs can either be negative or positive. Negative dromotropic drugs decrease the velocity of the conduction of electricity through the heart, while positive dromotropic drugs increase the velocity of the conduction of electricity through the heart.

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The molarity is 0.018M and the percentage is 8.46%.

Net ionic reaction is

[tex]$\mathrm{Cr} 2 \mathrm{O}^{2-}+6 \mathrm{Fe}^{2+}+14 \mathrm{H}^{+} \rightarrow 6 \mathrm{Fe}^{3+}+2 \mathrm{Cr}^{3+}+7 \mathrm{H} 2 \mathrm{O}$[/tex]

[tex]$1 \mathrm{~mol}$[/tex] of [tex]$\mathrm{Cr} 2 \mathrm{O} 7(-2)$[/tex] reacts with [tex]$6 \mathrm{~mol}$[/tex]of [tex]$\mathrm{Fe}(2+)$[/tex] to form [tex]$6 \mathrm{~mol}$[/tex]of [tex]$\mathrm{Fe}(3+)$[/tex] and [tex]$2 \mathrm{~mol}$[/tex] of [tex]$\mathrm{Cr}(3+)$[/tex]

Find molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]

Molarity = moles of[tex]$\mathrm{K} 2 \mathrm{Cr} 207 /$[/tex] Volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7(\mathrm{~L}$[/tex] )

Moles of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex] = grams of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$[/tex] molar mass of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]

[tex]$=1.2275 \mathrm{~g} / 294.19 \mathrm{~mol}=0.0042 \mathrm{~g} / \mathrm{mol}$[/tex]

Molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7=$[/tex] moles of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex]/ Volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$[/tex](L)

[tex]$=0.0042 \mathrm{~g} / \mathrm{mol} / 0.250 \mathrm{~L}=0.017 \mathrm{M}$[/tex]

Find molarity of [tex]$\mathrm{Fe}$[/tex] (II)

Molarity of [tex]$\mathrm{Fe}(\mathrm{II})=6 \times$[/tex]molarity of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 \times$[/tex]volume of [tex]$\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$[/tex]volume of [tex]$\mathrm{Fe}$[/tex] (II)

[tex]$=6 \times 0.017 \mathrm{M} \times 0.03598 \mathrm{~L} / 0.200 \mathrm{~L}$[/tex]

[tex]$=0.018 \mathrm{M}$[/tex]

Find moles of [tex]$\mathrm{Fe}(\mathrm{II})$[/tex]

Moles of [tex]\mathrm{Fe}($ II) =[/tex]molarity of [tex]$\mathrm{Fe}$[/tex] (II) [tex]$\times$[/tex] volume of [tex]$\mathrm{Fe}$[/tex] (II)

[tex]=0.018 \mathrm{M} \times 0.200 \mathrm{~L}=0.004 \mathrm{~mol}[/tex]

Find mass of Fe(II)

Mass of [tex]\mathrm{Fe}( II )=[/tex] moles of [tex]\mathrm{Fe}( II[/tex]) [tex]\times[/tex] molar mass of [tex]$\mathrm{Fe}(\mathrm{II})$[/tex]

[tex]$=0.004 \mathrm{~mol} \times 55.85 \mathrm{~g} / \mathrm{mol}$[/tex]

[tex]$=0.205 \mathrm{~g}$[/tex]

Find [tex]$\% \mathrm{Fe}(\mathrm{II})$[/tex] in unknown sample

[tex]$$\begin{aligned}\% \mathrm{Fe} &=(\text { mass of } \mathrm{Fe} / \text { weight of unknown sample }) \times 100 \\&=(0.205 \mathrm{~g} / 2.4234 \mathrm{~g}) \times 100 \\&=8.46 \%\end{aligned}$$[/tex]

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Answer:

Determining the charge. Electroscopes like we all know are used to detect or determine the charge present in an atom.