The gauge pressure at the new depth is determined as 3.67 atm.
What is the gauge pressure?The gauge pressure at the new depth is calculated by applying the following formula.
The absolute pressure at the new depth is;
abs P = (1/3) x 14 atm
abs P = 4.67 atm
The gauge pressure at the new depth is calculated as;
Gauge pressure = Absolute pressure at the new depth - Atmospheric pressure
G P = 4.67 atm - 1 atm
G P = 3.67 atm
Therefore, the gauge pressure at the new depth is 3.67 atm.
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Suppose a distant world with surface gravity of 6.32 m/s^2 has an atmospheric pressure of 9.00 ✕ 10^4 Pa at the surface. Answer parts a-c.
The Force ≈ [tex]1.13 * 10^6 N[/tex]
The Weight ≈ [tex]1.66 * 10^5 N[/tex]
Pressure ≈ 6.32 × 10⁴Pa
How to solve for the force(a)
Force = Pressure × Area
Force = (9.00 × 10⁴ Pa) × (π × (2.00 m)²)
Force ≈ [tex]1.13 * 10^6 N[/tex]
(b)
Weight = Density × Volume × g
Weight = (415 kg/m³) × (π × (2.00 m)² × 10.0 m) × (6.32 m/s²)
Weight ≈ 1.66 × 10⁵ N
(c)
Pressure = Pressure at the surface + Density × g × depth
Pressure = [tex](9.00 * 10^4 Pa) + (415 kg/m^3)* (6.32 m/^2)* (10.0 m)[/tex]
Pressure ≈ 6.32 × 10⁴Pa
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The work of forensic engineers who investigate fires _____. identifies what started the fire and where it stated identifies what started the fire and where it stated does not consider explosions does not consider explosions is relatively simple is relatively simple is usually done by the firefighting team
The work of forensic engineers who investigate fires involves identifying what started the fire and where it originated, and it does not solely focus on explosions. This process is not relatively simple and is typically conducted by specialized forensic teams rather than firefighting personnel.
Forensic engineers play a crucial role in investigating fires to determine their cause and origin. Their primary objective is to gather evidence and analyze it in order to understand the circumstances surrounding the fire incident.
1. Scene Assessment: Forensic engineers begin by assessing the fire scene. They examine the area to gather initial information about the fire's intensity, pattern, and potential sources.
2. Evidence Collection: Next, the investigators collect physical evidence from the fire scene. This may involve gathering debris, examining burn patterns, and documenting any signs of accelerants or other substances that could have contributed to the fire.
3. Documentation: Forensic engineers meticulously document their findings through photographs, sketches, and written notes. This documentation serves as a crucial reference throughout the investigation process.
4. Laboratory Analysis: Collected evidence is then analyzed in specialized laboratories. Forensic experts employ various techniques such as chemical analysis, microscopy, and other scientific methods to determine the cause of the fire.
5. Report Preparation: Once the analysis is complete, forensic engineers prepare detailed reports outlining their findings. These reports serve as valuable resources for insurance companies, legal proceedings, and future fire prevention efforts.
It is important to note that the work of forensic engineers primarily focuses on identifying the cause and origin of the fire. While they consider various possibilities, including explosions, their investigation is not limited to solely investigating explosions.
Moreover, the process of investigating fires is complex and requires specialized knowledge and expertise. It is typically carried out by dedicated forensic teams rather than the firefighting personnel.
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A water pipe starts at ground level with a pressure of 415 kPa and at ground level the water in the pipe has a velocity of 1.4 m/s.
This same pipe is also used to supply water to a higher floor of an office building. At what height (in meters) is the pipe if the
pressure in the pipe is 320 kPa, and the velocity of water is 0.24 m/s?
Use 9.81 m/s^2 for the acceleration of gravity.
1000 kg/m^3 for density of water
The height (in meters) of the pipe, given that the pressure in the pipe is 320 KPa, and the velocity of water is 0.24 m/s, is 9.78 m
How do i determine the height of the pipe?The following data were obtained from the question:
Height at ground level (h₁) = 0 mPressure at ground level (P₁) = 415 KPa = 415 × 1000 = 415000 PaVelocity at ground level (v₁) = 1.4 m/sPressure at height (P₂) = 320 KPa = 320 × 1000 = 320000 PaVelocity at height (v₂) = 0.24 m/sDensity of water (ρ) = 1000 kg/m³Acceleration due to gravity (g) = 9.81 m/s²Height of pipe (h₂) =?The height of the pipe can be obtained by using the Bernoulli's equation as illustrated below:
P₁ + 1/2ρv₁² + ρgh₁ = P₂ + 1/2ρv₂² + ρgh₂
415000 + (0.5 × 1000 × 1.4²) + (1000 × 9.81 × 0) = 320000 + (0.5 × 1000 × 0.24²) + (1000 × 9.81 × h₂)
415000 + 980 = 320000 + 28.8 + 9810h₂
Collect like terms
415000 + 980 - 320000 - 28.8 = 9810h₂
95951.2 = 9810h₂
Divide both sides by 9810
h₂ = 95951.2 / 9810
= 9.78 m
Thus, we can conclude that the height of the pipe is 9.78 m
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A student drops two metallic objects into a 120-g steel container holding 150 g of water at 25°C. One object is a 244-g cube of copper that is initially at 90°C, and the other is a chunk of aluminum that is initially at 5.0°C. To the surprise of the student, the water reaches a final temperature of 25°C, precisely where it started. What is the mass of the aluminum chunk? Answer is in kg.
Answer:
Therefore, the mass of the aluminum chunk is 15 g or 0.015 kg.
Explanation:
We have a container with 120 g of steel and 150 g of water at 25°C.
Two metal objects are dropped into the container:
A 244 g cube of copper initially at 90°C
An unknown mass of aluminum initially at 5.0°C
The surprise result is that the final water temperature is still 25°C.
Since the final water temperature is the same, the heat lost by the hot copper must equal the heat gained by the cold aluminum and the container.
The heat lost by the copper can be calculated as:
Qcopper = copper * copper * ΔTcopper
= 0.244 kg * 385 J/(kg•K) * (90°C - 25°C) = 29.5 kJ
The heat gained by the aluminum and container can be calculated as:
Qtotal = maluminum * cpaluminum * ΔTaluminum + mcontainer * cpcontainer * ΔTcontainer
Setting this equal to 29.5 kJ and plugging in the given values:
29.5 kJ = maluminum * 900 J/(kg•K) * (25°C - 5°C) + 0.120 kg * 450 J/(kg•K) * (25°C - 25°C)
Solving for aluminum :
aluminum = 0.015 kg
aluminum = 15 g
Answer:Certainly, let's solve the problem.
We can use the principle of conservation of energy to solve this problem. The heat lost by the hot object will be equal to the heat gained by the cold object and the water.
The heat lost by the copper cube can be calculated as:
Q1 = m1 * c1 * (T1 - Tfinal)
where
m1 = 244 g = 0.244 kg (mass of copper cube)
c1 = 0.385 J/g°C (specific heat of copper)
T1 = 90°C (initial temperature of copper cube)
Tfinal = 25°C (final temperature of the system)
Substituting the values, we get:
Q1 = 0.244 * 0.385 * (90 - 25) = 21.38 J
Similarly, the heat gained by the aluminum chunk can be calculated as:
Q2 = m2 * c2 * (Tfinal - T2)
where
m2 = ? (mass of aluminum chunk)
c2 = 0.902 J/g°C (specific heat of aluminum)
T2 = 5.0°C (initial temperature of aluminum chunk)
Substituting the values, we get:
Q2 = m2 * 0.902 * (25 - 5.0) = 18.144 m2 J
Now, since the water temperature doesn't change, we can assume that the heat gained by the water is equal to the heat lost by the hot objects. Therefore, we can write:
Q1 + Q2 = mwater * cwater * (Tfinal - Tinitial)
where
mwater = 150 g = 0.15 kg (mass of water)
cwater = 4.184 J/g°C (specific heat of water)
Tinitial = 25°C (initial temperature of water)
Substituting the values, we get:
21.38 J + 18.144 m2 J = 0.15 * 4.184 * (25 - 25)
Simplifying the equation, we get:
m2 = 0.266 kg
Therefore, the mass of the aluminum chunk is 0.266 kg or 266 grams.
Explanation:
27/13 AL + 4/2 He -> ? + 1/On
Please help!!!!!! What’s the missing species???
The missing species of the nuclear reaction obtained is ³⁰₁₅P
How do i determine the missing species?The missing species of the equation can be obtain as follow:
Let the missing species be ʸₓZNow, we can obtain the value of x, y and Z as follow:
²⁷₁₃Al + ⁴₂He -> ʸₓZ + ¹₀n
For x
13 + 2 = x + 0
15 = x
x = 15
For y
27 + 4 = y + 1
31 = y + 1
Collect like terms
y = 31 - 1
y = 30
For Z
ʸₓZ => ³⁰₁₅Z
From the period table, the element with atomic number of 15 is phosphorus, P. Thus, we have
ʸₓZ => ³⁰₁₅Z => ³⁰₁₅P
Therefore, we can write the complete equation as:
²⁷₁₃Al + ⁴₂He -> ³⁰₁₅P + ¹₀n
Thus, the missing species is ³⁰₁₅P
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. A 0.140 kg baseball is pitched toward home plate at 30.0 m/s.
The batter hits the ball back (opposite direction) to the pitcher at
44.0 m/s. Assume that towards home plate is positive. What is
the change in momentum for the ball?
The change in momentum for the baseball, which is hit back in the opposite direction by the batter, is -10.36 kg·m/s. This change in momentum is obtained by subtracting the initial momentum of 4.2 kg·m/s from the final momentum of -6.16 kg·m/s. The negative sign indicates the opposite direction of the momentum.
To find the change in momentum for the baseball, we can use the formula:
Change in momentum = Final momentum - Initial momentum
Momentum is defined as the product of mass and velocity.
Given data:
Mass of the baseball (m) = 0.140 kg
Initial velocity of the baseball ([tex]v_i_n_i_t_i_a_l)[/tex] = 30.0 m/s
Final velocity of the baseball ([tex]v_f_i_n_a_l_[/tex]) = -44.0 m/s (negative sign indicates opposite direction)
To calculate the initial momentum, we multiply the mass by the initial velocity:
Initial momentum = m * [tex]v_i_n_i_t_i_a_l[/tex] = 0.140 kg * 30.0 m/s = 4.2 kg·m/s
To calculate the final momentum, we multiply the mass by the final velocity:
Final momentum = m * [tex]v_f_i_n_a_l_[/tex] = 0.140 kg * (-44.0 m/s) = -6.16 kg·m/s
Now we can find the change in momentum:
Change in momentum = Final momentum - Initial momentum
Change in momentum = (-6.16 kg·m/s) - (4.2 kg·m/s)
Change in momentum = -10.36 kg·m/s
Therefore, the change in momentum for the baseball is -10.36 kg·m/s. The negative sign indicates a change in direction, as the ball is hit back in the opposite direction.
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A steam turbine receives steam with a velocity of 28 m/s, specific enthalpy 3000 kJ/kg at a rate of 3500 kg per hour. The steam leaves the turbine with a specific enthalpy of 2200 kJ/kg at 180 m/s. Calculate the turbine output, neglecting losses.
A steam turbine receives steam with a velocity of 28 m/s, specific enthalpy 3000kJ/kg at a rate of 3500 kg per hour. The steam leaves the turbine with a specific enthalpy of 2200kJ/kg at 180 m/s then turbine output is 777.76kW.
To get the turbine output, we must first compute the change in specific enthalpy (h) and mass flow rate ().
Assume that the inlet steam velocity (v1) is 28 m/s.
Specific enthalpy at the inlet (h1) = 3000 kJ/kg
()=3500kg/h mass flow rate
2200 kJ/kg outlet specific enthalpy (h2)
v2 (outlet steam velocity) = 180 m/s
To begin, convert the mass flow rate from kg/h to kg/s as follows: =
[tex]3500 kg/h (1 h/3600 s) = 0.9722 kg/s[/tex]
The change in specific enthalpy (h) can then be calculated:
3000kJ/kg-2200kJ/kg=800kJ/kgh=h1-h2
The following formula can be used to compute the turbine output (P):
[tex]P = ṁ * Δh[/tex]
Substituting P=0.9722kg/s*800kJ/kg=777.76kJ/sork W
As a result, ignoring losses, the turbine output is roughly 777.76kW
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The boiling point of ethyl alcohol is 351 K at atmospheric pressure. Answer parts a-b.
351 K on celcius scale is 77.85 °C and on the Fahrenheit scale is 172.13 °F.
It is given that the boiling point of ethyl alcohol is 351 K at atmospheric pressures.
a) Temperature on the kelvin scale = Temperature on the Celsius scale + 273
Therefore,
Temperature on Celsius scale = 351 K - 273.15 = 77.85 °C
b) (Temperature on the kelvin scale − 273.15) × 9/5 + 32 = Temperature on the Fahrenheit scale
Therefore,
The temperature on the Fahrenheit scale = (351 K − 273.15) × 9/5 + 32
= 77.85 x 9/5 +32
= 140.13 + 32
= 172.13 °F
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The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 grams. The velocity of the stone when it reached the target was 15.0 meters/second. What was the value of the kinetic energy of the stone when it reached the target?
Subsequently, the value of the kinetic energy of the stone when it reached the target is 2.25 joules.
Kinetic energy calculation .
The kinetic energy (KE) of an question is given by the equation:
KE= 1/2 * mass * velocity²
In this case, the mass of the stone is 20 grams, which is rise to 0.02kg and the speed of the stone is 15m/s
Plugging these values into the equation, we are able calculate the active vitality of the stone:
KE = 1/2 * 0.02kg * (15.0mls)²
KE = 1/2 * 0.02kg * 225 m²/ s²
KE = 2.25J
Subsequently, the value of the kinetic energy of the stone when it reached the target is 2.25 joules.
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Calculating Displacement under Constant Acceleration
Use the information from the graph to answer the
question.
Velocity (m/s)
40
30
20
10
0
Velocity vs. Time
0 5
10
15
Time (s)
20
25
What is the total displacement of the object?
I
m
Answer:
1 km
Explanation:
displacement =velocity ×time
displacement =40m/s ×25s
displacement =1000m equivalent to 1km
Match the terms to their correct example.
1. autonomy
2. drive
3. extrinsic
4. intrinsic
5. motive
A-reading for pleasure
B-wanting to appear smart
C-believing you are capable of fixing
something yourself
D-competing for the prize of first
place
E-the need to quench thirst or fill a hungry stomach
Answer:
1. autonomy - C-believing you are capable of fixing something yourself
2. drive - E-the need to quench thirst or fill a hungry stomach
3. extrinsic - D-competing for the prize of first place
4. intrinsic - A-reading for pleasure
5. motive - B-wanting to appear smart
A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures
Explanation:
You want N/m
N = 66 * 9.81
m = 2.3 x 10^-2 m
66* 9.81 / 2.3 x 10^-2 = 28150 = 28 000 N/m to two S D
At time t = 0, a vessel contains a mixture of 14 kg of water and an unknown mass of ice in equilibrium at 0°C. The temperature of the mixture is measured over a period of an hour, with the following results: During the first 45 min, the mixture remains at 0°C; from 45 min to 60 min, the temperature increases steadily from 0°C to 2.0°C. Neglecting the heat capacity of the vessel, determine the mass of ice that was initially placed in the vessel. Assume a constant power input to the container. Answer is in kg.
The mass of ice that was initially placed in the vessel of neglected heat capacity was found to be 1.135 kg.
Given that,
Mass of water = 14 kg
Mass of ice = m kg
P = Power of the burner = dQ/dt
Rate of the heat given by the burner is constant.
In the first 45 min,
dQ/dt = mL/t1 = m x (80 x 4.2 x 10³)/45 min. (1)
From 45 to 60 min,
dQ/dt = (m+14) x δ(Η₂Ο) x Δθ / t2 =(m+14) x (4.2 x 10³) x 2/ 15 min. (2)
From (1) and (2)
m x (80 x 4.2 x 10³)/45 min = (m+14) x (4.2 x 10³) x 2/ 15 min
80m/3 = (m+14) x 2
80m = 6m + 84
m = 1.135 kg
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A simple harmonic oscillator (SHO) has a spring constant of 280 N/m, Total energy of 150 J, and a mass of 4.00 kg. What is its
maximum velocity?
Numerical answer is in units of m/s
The maximum velocity is 8.66 m/s²
As we know, simple harmonic motion refers to a to-and-fro motion in a periodic manner and spring constant refers to the force required to stretch or compress a spring.
The spring constant for a simple harmonic oscillator is given as 280 N/m, the total energy is 150 J and the mass is 4 kgs. We have to find the maximum velocity of the given simple harmonic motion.
We know that Energy = force x perpendicular distance
In an SHM, energy is in the form of Kinetic Energy. Hence, we use the formula for kinetic energy.
To find the maximum velocity, we will apply the formula for kinetic energy.
Since Kinetic Energy = 1/2 mass x velocity²
Therefore, 150 = 1/2 mass x velocity² ; velocity = 8.66 m/s²
Hence, the maximum velocity for the given system of SHM is 8.66 m/s²
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If you feel pain during weight training, what should you do?
Answer:
Explanation:
Stop. Take a 5-10 minute breather, stretch out like you're doing your pre-workout (warmups). Drink some water, lay down for 3 minutes.
Answer: I hope this helps you
Explanation:
If you experience pain during weight training, it’s important to stop the exercise immediately and assess the source of the pain. If the pain is localized and mild, you can try taking a short break and then continuing with a lighter weight or modified exercise. However, if the pain is severe or spreading, you should stop the workout altogether and seek medical attention as soon as possible. Remember to always listen to your body and use proper form and technique to prevent injury.
workers of 50kg on the left and 40kg on the right on a 40kg plate held by two taut cables.
-The system does not rotate or move. With this in mind make a force diagram: it must have 5 forces labeled
-Write the net force equation
-Write the net torque equation,
Which cable exerts more tension, left or right? Explain why (2pts)
Find the tension of both wires. (3pts)
(a) The force diagram is the image attached.
(b) The net force of the workers is F(net) = (T₁ + T₂) - (W₁ + W₂ + W₃).
(c) The net torque equation of the system is W₁(x/2) - W₂(x/2) = 0
(d) The cable that exerts the most tension is the tension on the left.
(e) The tension in wire 1 is 490 N and the tension in wire 2 is 392 N.
What is the net force of the workers?The net force of the workers is calculated by applying the following equations;
F(net) = (T₁ + T₂) - (W₁ + W₂ + W₃)
The net torque equation of the system is determined as follows;
τ (net) = W₁(x/2) - W₂(x/2) = 0
W₁(x/2) - W₂(x/2) = 0
where;
x is the distance between the two workersThe cable that exerts the most tension is the tension on the left directly above the 50 kg worker because this work has the greatest downward force.
The tension in wire 1 is calculated as;
T₁ = 50 kg x 9.8 m/s²
T₁ = 490 N
The tension in wire 2 is calculated as;
T₂ = 40 kg x 9.8 m/s²
T₂ = 392 N
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effort distance of a lever should be increased to lift the havier load give reason
The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.
The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.
In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.
By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.
By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.
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The diagram below shows snapshots of an oscillator at different times . What is the frequency of the oscillation ?
The period of the oscillation, given the different time for the oscillator at different stage is 1.80 s
How do i determine the period of the oscillation?Period of an oscillation is defined as the time taken for the oscillation to make one complete circle or oscillation.
With the above information, we can obtain the period of the oscillation. This is illustrated below:
From the diagram given above, we can see that the oscillation started at t = 0.00s and at displacement of +0.10 m. Also, we can see that the oscillation ended at t = 1.80 s and at displacement of +0.10 m.
Now from the above, we can conclude that the period of the oscillation is 1.80 s since the oscillation started at +0.10 m and took 1.80 s to get back to +0.10 m
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2. For electric circuit shown in Figure find currents in each resistor.
The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.
What is the current flowing in each resistor?The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;
The total voltage in loop 1 is calculated as;
2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
The current flowing in loop 2 is calculated as;
I = V/R
I₂ = ( 6 V - 4 V ) / (3 + 4)
I₂ = 0.286 A
The value of the current flowing in loop 1 is calculated as;
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0
6 - 3I₁ - 3₁ + 0.858 = 0
-6I₁ = -6.858
I₁ = 6.858 / 6
I₁ = 1.14 A
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Determine the power output from a steam turbine if it receives steam at 40 bar, 350°C, and the steam leaving the turbine is at 15 bar, 200°C. The steam mass flow rate is 0.5 kg/s.
a thin, very light wire is wrapped around a drum that is free to rotate, the free end of the wire is attached to a ball of mass m, the drum is initially a solid disk with a mass M and radius R. you let the mass go at height h above the ground. if you switch out the solid disk and use a hollow disk instead with the same mass and radius, how will the final speed when the mass hits the ground when using a hollow disk compare to the final speed when using a solid disk?
a-greater than the original
b-less than the original
c-cant be determined
d-same as the original
Answer:
a-greater than the original (solid disk)
Explanation:
The hollow drum's lower rotational inertia allows it to rotate faster as the wire unwinds. This absorbs more potential energy, leaving less to translate into the speed of the falling mass. Therefore, the final speed when using a hollow disk will be:
a-greater than the original (solid disk)
What must be your car's average speed in order to travel 225 km in 3.35 h ?
Explanation:
Rate X Time = Distance
Distance / Time = Rate
225 km / 3.35 hr = 67.2 km/hr
Is there a difference between shapes when plotting Uniform acceleration towards (+)directtion,Uniform acceleration towards (-)direction, Uniform deceleration towards (+) direction and Uniform deceleration towards (-) direction in displacement time graph.Can you draw the shapes for each type ?
Explanation:
Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:[tex]\hrulefill[/tex]
(1) - Uniform acceleration towards the positive direction:
In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.
(2) - Uniform acceleration towards the negative direction:
In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.
(3) - Uniform deceleration towards the positive direction:
In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.
(4) - Uniform deceleration towards the negative direction:
In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.
A 73-g ice cube at 0°C is heated until 65.1 g has become water at 100°C and 7.9 g has become steam at 100°C. How much energy was added to accomplish the transformation? Answer is in kJ.
A liquid ( = 1.65 g/cm^3) flows through a horizontal pipe of varying cross section as in the figure below. In the first section, the cross-sectional area is 10.0 cm^2, the flow speed is 293 cm/s, and the pressure is 1.20 * 10^5 Pa. In the second section, the cross-sectional area is 3.00 cm^2. Answer parts a-b.
Answer:
a) What is the flow speed in the second section? Assume the pressure remains constant.
Given:
Section 1 area = 10.0 cm^2
Section 1 flow speed = 293 cm/s
Section 2 area = 3.00 cm^2
Pressure = 1.20 x 105 Pa (constant)
Since pressure remains constant, by Bernoulli's equation:
P1/ρ + 1/2*v12 = P2/ρ+ 1/2*v22
Since P1 = P2 and ρ (density) is constant:
v22 = 2*(v12 - v22)
v22 = 2*(293^2 - v22)
Solving for v2:
v2 = √(2*293^2) = 846 cm/s
b) What is the kinetic energy loss per second between the two sections?
Kinetic energy = 1/2 * mass * velocity^2
Mass flow rate = density * area * velocity
= 1.65 g/cm^3 * 10.0 cm^2 * 293 cm/s = 485.5 g/s
Kinetic energy loss = 1/2 * (485.5 g/s) * (293^2 - 846^2) cm^2/s^2
= 1/2 * (485.5)*(86124 - 716256)
= 20617 J/s
So the kinetic energy loss per second between the two pipe sections is 20617 J/s.
Explanation:
What is Moral subjectivism?
Answer:
What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.
A rollar coaster moves over the creast at location 1 at 10 m/s. HOw fast is it going at location 4? Neglect friction and air resistance.
The velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
Roller coasters are fascinating machines that deliver an exhilarating experience by defying gravity and physics. Roller coaster physics is a significant concept to comprehend before riding a roller coaster or designing one. The laws of physics govern the motion of a roller coaster, including its velocity, acceleration, and potential energy.
A roller coaster moves over a crest at location 1 with a speed of 10 m/s. The question is how fast it's going at location 4, considering the neglect of friction and air resistance. To solve this, we'll need to consider the conservation of energy law.
The total energy of the roller coaster remains constant throughout the ride, and we can convert between potential and kinetic energy.Using the conservation of energy formula, which is: E1 = E2Where E1 is the total energy of the roller coaster at the crest and E2 is the total energy of the roller coaster at location 4.
Both E1 and E2 comprise kinetic energy (KE) and potential energy (PE). So,E1 = KE1 + PE1E2 = KE2 + PE2Since the roller coaster has no friction and air resistance, we can assume that PE1 = PE2 because the height of the roller coaster doesn't change. The energy is converted from potential energy at the crest to kinetic energy at location 4.
We can now use the formula for kinetic energy:KE = (1/2) mv²Where m is the mass of the roller coaster and v is its velocity. Both E1 and E2 can be written in terms of KE, so: E1 = (1/2) mv₁²E2 = (1/2) mv₂².
Substitute the values into the conservation of energy formula: E1 = E2(1/2) mv₁² = (1/2) mv₂²
Simplifying the equation gives:v₂² = v₁²×(h₁ / h₂)
where h₁ is the height of the crest and h₂ is the height of location 4.
To calculate the velocity, we need to take the square root of both sides:v₂ = v₁×√(h₁ / h₂)
Therefore, the velocity of the roller coaster at location 4 is 14.14 m/s (approx) using the given values of v₁ = 10 m/s, h₁ = 30 m, and h₂ = 15 m.
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A small ferryboat is 4.50 m wide and 6.70 m long. When a loaded truck pulls onto it, the boat sinks an additional 4.70 cm into the river. What is the weight of the truck? Answer is in kN.
Explanation:
Volume of water displaced = 4.5 m x 6.7 m x .047 m = 1.417 m3
mass of displaced water =
1.417 m3 x 1000kg / m3 = 1417 kg = 13900 N = 13.9 kN
In a water pistol, a piston drives water through a larger tube of radius 1.30 cm into a smaller tube of radius 1.10 mm as in the figure below. Answer parts a-f.
It takes 0.47 seconds for water to travel from the nozzle to the ground when the water pistol is fired horizontally.
What is the time it takes for water to travel from the nozzle to the ground?We will denote the height of the water pistol above the ground as h and the initial velocity of water exiting the nozzle as v2. Assuming negligible air resistance, we will analyze the vertical motion of the water droplets.
The vertical displacement of the water droplets is calculated using equation: h = (1/2) * g * t^2.
Rearranging equation, we solve for time:
t = sqrt(2h / g).
Given data:
Height h = 1.10 m and the acceleration due to gravity g = 9.8 m/s^2, we get:t = sqrt(2 * 1.10 / 9.8)
t = 0.47380354147
t = 0.47 seconds.
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Joe is painting the floor of his basement using a paint roller. The roller has a mass of 2.4 kg and a radius of 3.8 cm. In rolling the roller across the floor, Joe applies a force F = 16 N directed at an angle of 35° as shown. Ignoring the mass of the roller handle, what is the magnitude of the angular acceleration of the roller?
The magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².
To find the magnitude of the angular acceleration of the roller, we can use the rotational analog of Newton's second law: τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.
First, let's calculate the moment of inertia of the roller. The moment of inertia of a solid cylinder rotating about its central axis is given by the formula: I = (1/2)mr², where m is the mass and r is the radius.
Given:
Mass of the roller (m) = 2.4 kg
Radius of the roller (r) = 3.8 cm = 0.038 m
Moment of inertia (I) = (1/2) * 2.4 kg * (0.038 m)² = 0.0021744 kg·m²
Next, we need to calculate the torque (τ) applied to the roller. Torque is given by the formula: τ = rFsin(θ), where r is the distance from the axis of rotation to the point of application of the force, F is the magnitude of the force, and θ is the angle between the force and the line connecting the axis of rotation and the point of application.
Given:
Force applied (F) = 16 N
Angle (θ) = 35°
Distance from the axis of rotation to the point of application (r) is equal to the radius of the roller, so r = 0.038 m.
Torque (τ) = (0.038 m) * (16 N) * sin(35°) = 0.2366 N·m
Now, we can use the equation τ = Iα and solve for the angular acceleration (α):
0.2366 N·m = (0.0021744 kg·m²) * α
α = 0.2366 N·m / 0.0021744 kg·m² ≈ 108.8 rad/s²
Therefore, the magnitude of the angular acceleration of the roller is approximately 108.8 rad/s².
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