Cobalt phosphate has a bright violet color and was once used as a paint pigment. Cobalt phosphate has the following chemical formula:
Co3(PO4)2
How many cobalt (Co) atoms are found in one molecule of cobalt phosphate? Answers:
3
5
2
6

Answers

Answer 1

Answer:

3

Explanation:

its 3 because i had the assigment before


Related Questions

If+a+monoprotic+weak+acid,+ha,+is+80%+ionized+at+a+concentration+of+0.05+m,+what+is+the+ph?

Answers

The pH of a monoprotic weak acid which is 80 percent ionised with a strentght of 0.05m is 1.39

What is pH ?

A scale called pH , which traditionally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are recorded for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions. The concentration of hydrogen ions in the solution is shown inversely by the pH scale, which is logarithmic.

pH + pOH = 14

[H + ]=0.05×0.80=0.04M

Now, Here, pH=−log[H + ]=−log0.04=1.39

The pH of a monoprotic weak acid which is 80 percent ionised with a strentght of 0.05m is 1.39

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An object with a mass of 1072 g
measures 6 cm wide, 7.3 cm high
and 15.2 cm long. What is the
density of the object?density

Answers

The Density of the given object is 1.61gm/cm³.

How closely a material is packed together is determined by its density. It is defined as the mass per unit volume.Volume is the cubic measurements used to determine how much space a three-dimensional object takes up.formula of volume : V = l × w × hUnit of density is g/cm³ or kg/m³ and unit of volume is cm³ or or mL or L.

Given,

mass of the object = 1072g

Length of the object = 15.2 cm

width of the object = 6 cm

height of the object = 7.3 cm

Therefore volume of the object V = l × w × h

V = 15.2 × 6 × 7.3

= 665.76 cm³

As we know,

Density = Mass / Volume

Density = 1072 / 665.76

= 1.61 g/cm³

Therefore, the density of given object is 1.61 g/cm³.

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What is the proper solution to the following
equation?
(150. + 2.5+ 36.75) ÷ (6.60+ 0.173)
=
A)30
B)27.94
C)28
D)27.942
E) 27.9

Answers

Answer:

B) 27.94

Explanation:

All other last digits are wrong except b

Answer:

[tex] \frac{39.25 + 150.}{6.773} = 27.94182[/tex]

Explanation:

[tex]1. \: (39.25 + 150.) \div (6.60 + 0.173) \\ 2. \: (39.25 + 150.) \div 6.773 \\ 3. \: (39.25 + 150.) \times \frac{1}{6.773} \\ 4. \: \frac{(39.25 + 150.) \times 1}{6.773} \\ 5. \: \frac{39.25 + 150.}{6.773} = 27.94182[/tex]

In the equation below, carbon dioxide and water react to make sugar and oxygen. This reaction (photosynthesis) takes place inside plants and is the basis for almost all life on Earth.


6CO2 + 6H2O → C6H12O6 + 4O2

How many molecules of carbon dioxide are involved in this reaction? ______
How many molecules of sugar are produced in this reaction? ______

Answers

6 CO2 molecules are involved in this reaction which is in turn helping to produce 1 molecule of glucose.

How many molecules in total are there in photosynthesis?Commonly used notation for photosynthesis is: 6CO2 + 6H2O C6H12O6 + 6O2. This suggests that the transformation of the reactants—six carbon dioxide molecules and six water molecules—into the products—a sugar molecule and six oxygen molecules—takes place as a result of chlorophyll's absorption of light energy.

How does CO2 function in photosynthesis?During photosynthesis, plants take up water (H2O) and carbon dioxide (CO2) from the soil and atmosphere.Water is oxidized, which means it loses electrons, while carbon dioxide is reduced, which means it receives electrons, inside the plant cell. This mechanism transforms water into oxygen and carbon dioxide into glucose.

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Use the table below to calculate the atomic
mass of element X. Then use the periodic table
to identify the element. Show all your work.

Answers

Hello, the element is Oxygen and the atomic mass is 15.99 or we could say 16 amu.

Here’s the work:

15.995 x 99.762/100 = 15.956

16.999 x 0.00038 = 0.00645962

17.999 x 0.002 = 0.035998

We add these to get around 16 or 15.99

Question 20
What element is represented in the following notation [Ne] 3s² 3p4
OS
OC
O Mg
O AI
<< Previous
5 p

Answers

Answer: S

:) hope this helps you!

A rectangular block of copper metal weighs 1996 g. The dimensions of the block are 9.4 cm by
6.5 cm by 5.6 cm. From this data, what is the density of copper? (hint: find the volume of a block
first)

Answers

The volume is 342.16 cm^3. The mass is 1996 g. Density is equal to m/v, therefore 1996/342.16= 5.833528174 g/cm^3.

1. Calculate the volumes of the samples used in Procedure step 2. Record the calculated
volumes in Table 2.2. Why could we not find the volume of the bolt by this method?

Answers

From the table shown in the question;

Volume of aluminum bar = 15.52 cm^3

Volume of the rod =  23.8 cm^3

The volume of the iron bolt can only be obtained by the displacement method.

What is volume?

The term volume refers to the space that is occupied by an object. We know that the volume of an object could be obtained in different ways depending on the nature of the object. If the object is a solid, we could look at the dimensions of the solid or we could use the dimensions of the solid. The actual method that we finally use is peculiar to the object whose volume we intend to measure.

In order to obtain the volume of the aluminum bar;

Volume = length * width * height

Volume = 9.7 * 1.6 * 1.0 = 15.52 cm^3

In order to obtain the volume of the rod;

Volume = Area * length

Volume = 3.14 * (1.7)^2/4 * 10.5

Volume = 23.8 cm^3

We can not obtain the volume of the iron bolt by this method because it is an irregular solid hence we have to use the displacement method.

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A 6.67 mg sample of a compound containing carbon, hydrogen, and oxygen underwent combustion producing 15.17 mg of CO2 and 6.19 mg of H2O. What is the empirical formula of the compound? (Type your answer using the format CxHyOz for the compound CxHyOz)

Answers

The empirical formula of the compound is C₃H₆O

What is the empirical formula of the compound?

The empirical formula is determined as follows from the equation of the reaction as follows:

CxHyOz + O₂ → x CO₂ + y/z H₂O

mass of CO₂ produced = 15.17 mg = 0.01517 g

moles of C in the sample = 0.01517/44  = 0.000344 moles

mass of C in the sample =  0.0000344  * 12 = 0.00413 g

mass of H₂O produced  = 6.19 mg = 0.00619 g

moles of H in the sample = 0.00619/18 * 2 = 0.000688 moles

mass of H in sample = 0.000688 g

mass of oxygen in the sample = 0.00667 g - (0.00413 g + 0.000688 g)

mass of oxygen in the sample = 0.00185

moles of oxygen = 0.00185/16 = 0.000116

Ratio of C : H : O = 0.000344 : 0.000688 : 0.000116

Ratio of C : H : O = 3 : 6 : 1

Empirical formula of compound = C₃H₆O

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Calculate the ratio of the concentration of formate to formic acid required in a buffer system of ph 4.25. the pka of formic acid is 3.75. ratio = ________________.

Answers

The ratio of the concentration of formate to formic acid required in a buffer system is 3.16 : 1.

pH = 4.25; pH of the solution

pKa = 3.75

Henderson–Hasselbalch equation: pH = pKa + log(cs/ck)

4.25 = 3.75 + log(cs/ck)

log(cs/ck) = 4.25 - 3.75

log(cs/ck) = 0.5

cs/ck = 10∧(0.5)

cs/ck = 3.16; ratio of formate to formic acid

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

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Please share the answers with explanations
Thanks,

Answers

The melting and boiling and density is given below :

Substance          melting point / °C         boiling point / °C       density / g cm⁻³

  E                           -259                                 -253                          0.09

 F                           1085                                 2580                         8.93

  G                                 -7                                     59                            3.1

 H                              -39                                   357                           13.6

  I                                -218                                  - 183                       0.0013

A) substances are gases at room temperature:

    E and I are gases at room temperature because the melting and boiling point are below at room temperature.

B) substances are liquids at room temperature:

    G and H  are liquids at room temperature because substances are liquid at room temperature if melting point is below room temperature and boiling point is above room temperature.

C) substances are solid at room temperature :

   F is solid at room temperature because its melting point is above room temperature.

D) substances are most likely to be metal :

   F is metal because metals have very high melting and boiling point except mercury.

E) substance are most likely to be mercury :

    H is most likely to be mercury because mercury has boiling point -38°C and melting point is 356°C and density is 13.5 g/ cm³ and mercury is metal with exception.

G) substances will be liquid at -210°C :

  I is liquid at -210°C because substance is liquid when its melting point is below temperature and boiling point is above temperature.

H) substances are most likely to be bromine :

  G is more likely to be bromine because melting and boiling point and density of G is close to bromine.

I)  substances which are least dense non metal :

   E is least dense non metal because its melting and boiling point and density is close to least dense non - metal.

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determine the number of moles of methane in 120cm³ of the gas at r.t.p​

Answers

Answer:

0.005 moles

Explanation:

120cm^3 = 0.12dm^3

1mol is always 24dm^3 of gas at rtp

0.12 ÷ 24 = 0.005 moles

why does water not dissolve in water

Answers

Opposite charges attract one another

Answer:

Water dissolves with water because both are polar solvents

[tex].[/tex]

Which of the following science and engineering practices describes one the first things that scientists do when starting a new investigation?

A) Constructs an Explanation

B) Interprets data

C) Designs a solution

D) Ask a question

Answers

Ask a question the first things that scientists do when starting a new investigation.

What are scientific practices?

Scientific practices, which include things like answering questions, creating and using models, and having arguments, are cognitive, discursive, and social activities carried out in science classrooms with the goal of developing epistemic understanding and appreciation of the nature of science.

Why are the science and engineering practices important?

Participating in these activities not only makes students' knowledge more meaningful and deeply ingrained in their worldview, but it also aids them in developing an understanding of the disciplinary and transdisciplinary ideas of science and engineering.

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Chemically speaking, how does applying hot dog mustard to a coin detect the presence of silver metal

Answers

Answer:

A black spot will remain on the silver coin, but not on the nonsilver coin. Mustard naturally contains sulfur compounds, and sul- fur reacts with silver to form a black precipi- tate of silver sulfide (Ag2S)

Explanation:

Uranium has three isotopes with the following percent abundances: 234- (0.0058%), 235- (0.71%), 238- (99.23%). Without doing any calculations, what do you expect the atomic mass of uranium to be in whole numbers. Why?

Answers

Answer:

Because it is the same element but has different atomic mass

How many grams of methanol (ch3oh) must be added to water to prepare 191.8 ml of a solution that is 6.72 m methanol?

Answers

41296.22 g of weight of methanol (ch3oh) must be added to water to prepare 191.8 ml of a solution that is 6.72 m methanol

Molarity of reactions happen in solutions and so it is important to understand how the amount of substance is expressed when it is present in the solution. It is one of the most widely used unit of concentration and is denoted by M. It is defined as no. of moles of solute present in 1 liter of solution. Thus, it define as N = n /V

It is given that 191.8 ml of 6.72 M  methanol is to be prepared.

Using the Molarity formula , we get

                 6.72 = n / 191.8

                    n = 6.72 × 191.8

                    n = 1288.89 g / mol

Molar mass of methanol = 32.04g/mol

Weight of methanol to be added= 32.04 ×1288.89 =  41296.22 g

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When h2so4 is neutralized by naoh in aqueous solution, the net ionic equation is ________.

Answers

When H₂SO₄ is neutralized by NaOH in an aqueous solution, the net ionic equation is:

2H⁺(aq) + 2OH⁻(aq) → 2H₂O(l)

A chemical equation known as an ionic equation expresses the electrolytes in an aqueous solution as dissociated ions. For the reaction between [tex]H_{2}SO_{4}[/tex] , NaOH that neutralizes it, we must write the net ionic equation.

The reaction's equilibrium chemical equation is:

[tex]Na_{2} SO_{4}[/tex](aq) + [tex]2H_{2}O[/tex] = [tex]H_{2}SO_{4}[/tex] (aq) + [tex]2NaOH[/tex](aq) (l)

We shall now draft the ionic equation.

The reaction's ionic equation is

[tex]2 Na ^{+} (aq) + SO_{4} ^{2-} (aq) + 2H_{2}O = 2H^{+} (aq) + SO_{4} ^{2-} (aq) + 2 Na ^{+} (aq)+ 2OH(aq) (l)[/tex]

The net ionic equation is then obtained by canceling out the spectator ions Na+ and SO42.

The neutralization reaction's net ionic equation is:

2H⁺(aq),  2OH⁻(aq), and 2H₂O (l)

In light of this, the net ionic equation for the neutralization of H2SO4 and NaOH is:

2H⁺(aq) + 2OH⁻(aq) → 2H₂O(l)

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At a track meet the officials use a timer to determine the amount of time it takes to complete each running event. If the timer does not function correctly and adds one second onto each runner's time this is an example of a random error. true or false

Answers

Answer:

This is an example of a random error because the timer is adding an extra second onto each runner's time, which is not an accurate representation of their true time. This error is not systematic, meaning that it does not affect all runners in the same way or add the same amount of time onto their times.

Explanation:

Give me brainliest if that helped :)

Which of the following scenarios could be considered evidence of a compound with a low activation energy?
A. a high amount of naturally occurring NaCl
B. a low amount of spontaneous fuel combustion
C. a low amount of collisions between molecules
D. a high amount of heat required to form products

Answers

A high amount of naturally occurring NaCl is considered evidence of a compound with a low activation energy and is denoted as option A.

What is Activation energy?

This is referred to as the minimum amount of energy which is needed for a chemical reaction to occur and is dependent on various factors.

A compound which has a low activation energy will have a high yield sue to the ease in which the reactants are being converted into products. in this scenario, the high amount of naturally occurring NaCl signifies a low activation energy which is why option A was chosen as the correct choice.

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Students conducted an analysis of baking soda in chemistry lab. During the activity, they had to calculate the mass in
grams of the baking soda being used. Some student data appears in the table. At the end of the activity, the teacher
told the students that the actual mass of baking soda was 0.45 grams. Which student had the most accurate and
precise data?

Answers

The student that had the most accurate and precise data is Mel (option D).

What is accuracy and precision?

Accuracy is the degree of conformity of a measure to a true or standard value i.e. closeness to a standard or true value.

On the other hand, precision is the ability of a measurement to be reproduced consistently i.e. the closeness of measured values.

According to this question, students calculated the mass in grams of the baking soda being used.

It can be said that Mel, which measured the following values: 0.44g, 0.46g, 0.45g had the most accurate and precise value because they are both close to themselves and the true value.

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Answer:

D

Explanation:

Mel

Describe scientific method

Answers

The scientific method is an experimentation technique used to investigate data and answer questions. All sciences, including chemistry, physics, geology, and psychology, follow the scientific method. These scientists ask various questions and conduct different tests. They do, however, apply the same fundamental technique to arrive at logical and evidence-based conclusions. Scientists change the scientific method when direct experimentation is not possible. Understanding the phases of the scientific process can assist you in focusing your scientific inquiry and working through your observations and data to get the best possible response.

The scientific method consists of seven phases.

1. Pose a query. The scientific approach begins with posing a question that you want answered.

2. Conduct research.

3. Create your theory.

4. Experiment to put your hypothesis to the test.

5. Make a note of it.

6. Analyze the findings and reach a conclusion.

7. Display your results.

A chemist heats a 215-g sample of iron from 25.0°C to 90.0°C. How much heat did the iron absorb? The
specific heat capacity of iron is 0.45 J/g°C.

Answers

A 215-g sample of iron is heated by a chemist from 25.0°C to 90.0°C and 6.3 kJ of heat are absorbed by the iron (q).

What is meant by specific heat?

Also known as specific heat, this is the quantity of energy required to increase a substance's temperature by 1 degree Celsius in one gram. The units of specific heat are typically calorie or joules a gram per degree Celsius. As an illustration, the specific heat of water is 1 calorie (4.186 joules) each gram per degrees C.

Briefing:

q = m × C × ΔT

q = m × C × (T[tex]_f[/tex] - T[tex]_i[/tex]),

q is the quantity of heat energy a substance gains or loses (J)

m = mass of sample (g)

C = specific heat capacity (J °C-1 g-1)

T[tex]_f[/tex] = final temperature (°C)

T[tex]_i[/tex] = initial temperature (°C)

Thus:

q = (215 g) × (0.45 J oC-1 g-1) × (90 - 25)°C

q = 6288.75 J

q = 6288.75 J = 6.3 kJ

The iron absorb 6.3 kJ of heat (q).

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How do firefighters use their knowledge of the fire triangle to help them control fires? how do the measures they take relate to the chemistry involved?.

Answers

Answer:

okay

Explanation:

The fire triangle's three sides illustrate the three elements of fire: heat, fuel and oxidization. The three elements must be combined in the right proportions for a fire to occur. If any of the three elements are removed, the fire is extinguished

Calculate the molality of a solution containing 15.01 g of glycerol (c 3h 8o 3) in 42.3 g of ethanol (c 2h 5oh).

Answers

The molality of the glycerol solution is 3.854mol/kg

The number of moles of solute present in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.

Given:

Mass, m1 of glycerol = 15.01g

Mass, m2 of ethanol = 42.3g

Molar mass, mm1 of glycerol = 92.095g/mol

Molar mass, mm2 of ethanol = 46.069g/mol

To find:

Molality, m = ?

Formula:

Molality, m = moles of solute / kg of solvent

Calculations:

No. of moles of glycerol = 15.01 x (1/92.095)

n = 0.163 mols

Molality, m = 0.163 / 0.0423g

Molality, m = 3.854mol/kg

Result:

3.854mol/kg is the molality of the glycerol solution.

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When a 7.55-mg sample of a compound containing carbon is burned completely, 17.3 mg of carbon dioxide is produced. what is the mass percentage of carbon in the compound?

Answers

There ought to be 6.3 grams of oxygen reacting with the fuel in accordance with the law of conservation of matter.

Fuel mass equals 20.8 grams

In the presence of oxygen, 9.8 grams of CO2 and 17.3 grams of water are generated.

The mass of the products and reactants of a chemical reaction must be equal, in accordance with the law of conservation of mass.

In other words, mass fuel plus mass oxygen equals mass carbon dioxide plus mass water.

9.8 grams of carbon dioxide per mass.

17.3 grams of water in mass

27.1 grams of mass CO2 plus water.

The fuel's mass is 20.8 grams.

This indicates that the mass of the oxygen should be 27.1 grams in addition to the mass of the fuel.

Mass oxygen is equal to 27.1 - 20.8 grams= 6.3 grams.

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What is the formula for Newtons second law of motion 

Answers

Answer: F=m*a

Explanation: Force equals mass times acceleration!

I hope this helps!

Why do industries use metallic compounds to make wires?

Select all that apply.

Responses

metallic compounds often have high luster
metallic compounds often have high luster

metallic compounds are ductile
metallic compounds are ductile

metallic compounds have high boiling points
metallic compounds have high boiling points

metallic compounds are good conductors of electricity
metallic compounds are good conductors of electricity

Answers

Answer:

metallic compounds are good conductors of electricity.

metallic compounds have high boiling points

To determine the molar mass of an unknown from the freezing point depression, the freezing points of both the pure solvent and the solution need to be measured.

Answers

Yes, to determine the molar mass of an unknown solute from the freezing point depression the freezing points of both the pure solvent and the solution need to be measured.

The depression of the freezing point is a and it is given by the following formula,

ΔT f = T°f - T f

Here T°f is the freezing point of pure solvent

T f is the freezing point of the solution made by adding non-volatile solute to solvent

The freezing point depression is directly proportional to the molality of the solution

T(f) ∝ m

T(f)= K f x m

Here K f is the proportionality constant.

Hence, to determine the molar mass of an unknown solute from the freezing point depression the freezing points of both the pure solvent and the solution need to be measured.

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What mass of ammonia is formed when 5.36 g of nitrogen gas reacts with excess hydrogen gas?

Answers

6.508 g mass of of NH3 is formed when 5.36 g of nitrogen gas reacts with excess hydrogen gas.

                                N2 + 3 H2  → 2 NH3

The molar mass of N2 is 28.0 g/mol. The molar mass of NH3 is 17 g/mol.

To find the mass of NH3:

=5.36 x 2 x (17 / 28)

=182.2 / 28

= 6.508 g

The mass of ammonia is 5.36 g.

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