Impact ice is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid water to a temperature below 32°F.
What is meant by impact ice ?Impact ice, a kind of induction icing, may form wherever that the temperature is close to or below zero degrees Celsius. Even on a fuel-injected engine, impact ice can clog the air filter and prevent the engine from getting the necessary air for combustion. As instructed by your POH/AFM, turn on alternative air or carburetor heat if you detect impact ice.Carburetor icing (ice that forms in the carburetor) happens when the venturi's decline in air pressure causes the moisture-filled air to cool quickly or as a result of gasoline evaporation.The ensuing ice buildup in the intake tube of the carburetor can significantly lower engine performance. In extreme circumstances, the intake flow might be so low that the engine can stall.Learn more about Liquid water refer to :
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A 1600kg car is traveling over a hill that has a radius of curvature of 25m. The car is slowing down as it goes over the hill. It slows down at a constant rate from a speed of 25ms to a speed of 10ms over a distance of 50m ending at the top of the hill. The net acceleration of the car at the top of the hill is most nearly.
The correct answer is net acceleration of the car at the top of the hill is 6.6 m/s²
distance traveled by the car, d = 50 m mass of the car, m = 1600 kg radius of the hill's curvature, r = 25 m beginning speed of the car, u = 25 m/s
The third kinematic equation is applied to get the car's tangential acceleration, as shown below;
v2 = u2 + 2as, where a represents the vehicle's acceleration and 2as = v2 - u2 equals a=5.25 m/s
A net equals a2 + aca net = (5.25) 2 + 42a net = 6.6 m/s. 2
Consequently, the vehicle's net acceleration at the summit of the hill is 6.6 m/s2.
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The current-potential difference graphs for a lamp and a diode are shown in Figure 1.
Complete the sentences to describe how the resistance changes as the current changes in a lamp and a diode.
As the__________ across the lamp increases, the
resistance of the lamp_____________
This is because the temperature____________
The current through a diode flows in one_______________ only.
The resistance is____________ in the reverse direction.
As the temperature across the lamp increases, the
resistance of the lamp increases.
This is because the temperature is proportional to resistance.
The current through a diode flows in one direction only.
The resistance is flowing in the reverse direction.
What is resistance?Resistance is described as a measure of the opposition to current flow in an electrical circuit. Resistance is known to be measured in ohms, symbolized by the Greek letter omega (Ω) which is named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.
The relationship between temperature and resistance is that the resistance increases as the temperature increases in conductors and decreases with the increasing temperature in insulators.
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The position as a function of time of a mass at the end of a spring that is undergoing
SHM is given by x(t) = A sin (ωt + θ) and the velocity is given by ν(t) = A ω cos
(ωt, +θ). At time t = 0.00 seconds, the oscillating mass/spring system has a displace-
ment x = 2.83 cm and a velocity ν= 3.25 cm/s. It is oscillating with an angular
frequency of 2.64 radians per second. Determine the constants A and θ
The value of constants A and θ will be θ = 66.5° or 1.161 radians and A = 3.1 cm
Simple Harmonic Motion or SHM is defined as a motion in which the restoring force is directly proportional to the displacement of the body from its mean position. The direction of this restoring force is always towards the mean position.
x(t) = A sin (ωt + θ)
time = 0.00 seconds
2.83 = A sin ( 0 + θ)
A sin θ = 2.83 `equation 1
ν(t) = A ω cos (ωt+θ)
3.25 = A * 2.64 * cos (0 + θ )
3.25 = 2.64 A cos θ
A cos θ = 3.25 / 2.64 = 1.23 equation 2
dividing equation 1 and 2 , we get
tan θ = 2.30
θ = 66.5° or 1.161 radians
from equation 1
A sin θ = 2.83
A sin ( 66.5 ) = 2.83
A = 3.1 cm
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The period of Jupiter is known to be 11.9 years. Use this data to determine its average distance from the Sun.
The period of Jupiter is known to be 11.9 years then the average distance of Jupiter to the Sun is given to be 5.21 AU.
Kepler's laws of planetary motion :
According to this law, the semi-major axes of the planets' orbits are directly proportional to the squares of the planets' orbital periods.
period of the Jupiter = 11.9 years
radius of the earth = 1 AU
orbital period of the earth = 1 year
According to the Kepler's 3rd law of planetary motion :
T² ∝ R³
T² = k R³
k = T²/ R³
[tex]k = \frac{T^2_j}{R^3_j} = \frac{T^2_e}{R^3_e}[/tex]
T² /(R)³ = (1)² /(1)³
Rj = [tex]T^{\frac{2}{3}}[/tex]
T = 5.21 AU
The period of Jupiter is known to be 11.9 years then the average distance of Jupiter to the Sun is given to be 5.21 AU.
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A motorized wheel is spinning with a rotational velocity of = 1.81 rad/s. At t = 0s, the operator switches the wheel to a
higher speed setting. The rotational velocity of the wheel at all subsequent times is given by
w (t) = warctan (c + bt²)
where c = 1.5574 and b = 6.53 s^-2.
At what time famax is the rotational acceleration at a maximum?
Tamax =
What is the maximum tangential acceleration a, of a point on the wheel a distance R = 1.25 m from its center?
What is the magnitude of the total acceleration of this point?
The time at which the rotational acceleration is maximum is 0.26i s or 2.2i s.
The maximum tangential acceleration of the wheel is 4.1 m/s².
What is the rotational acceleration of the of the wheel?
The rotational acceleration of the wheel is the change in the angular velocity of the wheel with time.
α = dω/dt
where;
ω is the angular velocity of the wheelω = tan⁻¹(c + bt²)
α = dω/dt
α = (2bt)/[(c + bt²)² + 1]
the maximum angular acceleration =ω/t = 1.81/t
1.81/t = (2bt) / [c² + 2cbt² + b²t⁴ + 1]
1.81(c² + 2cbt² + b²t⁴ + 1) = 2bt(t)
1.81c² + 3.62cbt² + 1.81b²t⁴ + 1.81 = 2bt²
1.81(1.5574)² + 3.62(1.5574 x 6.53)t² + 1.81(6.53²)t⁴ + 1.81 = 2(6.53)t²
4.39 + 36.81t² + 77.18t⁴ + 1.81 = 13.06t²
77.18t⁴ + 23.75t² + 6.2 = 0
23.75t²(3.25t² + 1) = -6.2
23.75t² = -6.2 or 3.25t² + 1 = -6.2
t² = -6.2/23.75
t² = -0.26
t = 0.26i s
or
3.25t² + 1 = -6.2
3.25t² = -7.2
t² = -2.2
t = 2.2i s
The maximum tangential acceleration of the wheel at the given point is calculated as follows;
a = v²/r
a = ω²r
a = (1.81 rad/s)²(1.25 m)
a = 4.1 m/s²
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With an average acceleration of -0.50 m/s^2, how long will it take a cyclist to bring a bicycle with an initial speed of 13.5 m/s to a complete stop?
The time taken for the bicycle to come to a complete stop with an initial velocity of 13.5 m/s is 27 seconds.
What is time?Time can be defined as the calculable measure of motion with respect to before and afterness.
To calculate the time it takes the cyclist to bring the bicycle to complete stop, we use the formula below.
Formula:
t = (v-u)/a.......... Equation 1Where:
t = Timev = Final velocityu = Initial velocitya = AccelerationFrom the question,
Given:
v = 0 m/s (to stop)u = 13.5 m/sa = -0.5 m/s²Substitute these values into equation 1
t = (0-13.5)/-0.5t = -13.5/-0.5t = 27 seconds.Hence the time taken for the bicycle to stop completely is 27 seconds.
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How could you demonstrate a magnetic field using your body?
Help pls
With the use of a magnetometer, the magnetism or magnetic field of the human body can be measured or demonstrated.
What is a Magnetometer?A magnetometer is a device used to measure the magnetic field or the magnetic dipole moment. Magnetometers of various sorts measure the direction, intensity, or relative change of a magnetic field at a specific area.
A magnetometer is a scientific tool that measures the intensity of magnetic fields. Magnetometers may be used on land to locate iron ore reserves for mining.
Magnetometers are instruments that can detect the amount or direction of a magnetic field. They may be found practically anywhere in electronics. They might be as basic as the one used by your smartphone to identify whether it is upright or as complicated as the one used by NASA to assess Mars' magnetic field.
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Please help with these questions
3) unit of the following are :
a) force = Newton
b) distance = meter
c) work = Joule
4) 90 J work has been done by her
5) 51 J work was done
6) He have done [tex]10^{4}[/tex] J of work
7) no work is done
8) no work is done
9) 700 J is the work done on the car
10) 10.68 N force is applied
3 ) unit of the following are :
a) force = Newton
b) distance = meter
c) work = Joule
4 ) work done = force * displacement
= 75 * 1.2 = 90 J
5 ) work done = force * displacement
= 15 * 3.4 = 51 J
6 ) work done = force * displacement
= 100 * 100 = [tex]10^{4}[/tex] J
7) no work is done because no displacement occurred
8) no work is done because no displacement took place
9) work done = force * displacement
= 12.5 * 56 = 700 J
10) force = work done / displacement
= 142 / 13.3 = 10.68 N
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Two balls a and b, having different but unknown masses, collide. A is initially at rest when b has a speed v. After collision, b has a speed of v/2 and moves at a right angle to its original motion. Find the direction in which the ball a moves after the collision.
The direction in which the ball a moves after the collision is east of south
What is momentum ?
Momentum, the product of a particle's mass and its velocity. Momentum is a vector quantity. It has both magnitude and direction. Isaac Newton's second law of motion states that the rate of change of momentum over time is equal to the force acting on a particle. See Newton's Laws of Motion.
From Newton's second law, if a particle is subject to a constant force over a period of time, the product of that force and the time interval (momentum) equals the change in momentum. Conversely, the momentum of a particle is a measure of the time it takes for a constant force to come to rest
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In the figure, the light, taut, unstretchable cord B joins block 1 and the larger-mass block 2 . Cord A exerts a force on block 1 to make it accelerate forward.
(1)
(a) How does the magnitude of the force exerted by cord A on block 1 compare with the magnitude of the force exerted by cord B on block 2 ? Is it larger, smaller, or equal? larger:
smaller
equal
(b) How does the acceleration of block 1 compare with the acceleration (if any) of block 2 ?
larger
smaller
equal
(c) Does cord B exert a force on block 1 ? If so, is it forward or bsckward? Is it larger, smaller, or equal in magnitude to the force exerted by cord B on biock 2?
Yes; backward and equal
Yes; backward and less than
Yes; forward and equal
Yes; forward and less than
Yes; forward and greater than
Yes; backward and greater than,
No
a) The magnitude of force exerted by cord A on block 1 is equal to magnitude of the force exerted by cord B on block 2
b) The acceleration of block 1 is equal to that if block 2
c)The force is forward and equal to the force of cord B on block 2.
What is the force exerted?We know that the force that acts along a cord can be regarded as the tension force. The magnitude of the tension force is equal to the force that is applied on the cord. If an object is hanged on the cord then the tension force would equal the weight of the object.
a) We can see that block 1 is connected to block 2 by the use of cord B and the force on cord B must necessarily be the force on cord A since the weight of the blocks are equal.
b) Since the force on cord A is equal to the force on cord B, the acceleration of block 1 must be equal to the acceleration of block 2.
c) Cord B exerts a force on block 1 in the forward direction and this force is equal to the force that is exerted on block 2.
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n his fishing trip, Justin rides in a boat 10 km south. The fish aren’t biting so they go 4 km west. They then follow a school of fish 1 km north. What distance did they cover? What was their displacement?
The displacement covered will be 9.85 km
The distance covered will be = 10 + 4 + 1 = 15 km
using Pythagoras theorem
[tex]H^{2} = P^{2} + B^{2}[/tex]
H = [tex]\sqrt{4^{2} + 9^{2} }[/tex]
H = [tex]\sqrt{97}[/tex]
H = 9.85 km
The displacement covered will be 9.85 km
The distance covered will be = 10 + 4 + 1 = 15 km
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The gravitational force between two objects that are 2.1x10‐1 m apart is 3.2x10‐6 N. If the mass of one
object is 55 kg what is the mass of the other object? What will be their acceleration if they are released
from their position?
The mass of the other object is 18.11 kg and their acceleration will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².
Given parameter:
The gravitational force between two objects : F = 3.2×10⁻⁶ N.
Distance between two objects : r = 2.1x10⁻¹ m.
The mass of one object m₁ = 55 kg.
The mass of other object m₂ =?
From universal gravitational law, we know that, force acting between two objects of mass m₁ and m₂ separated by a distance r is:
F = G m₁ m₂ / r²
Where, G = universal gravitational constant = 6.67 × 10⁻¹¹ N m⁻² kg⁻².
So, we can write,
3.2×10⁻⁶ N = (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg) m₂/( 2.1x10⁻¹ m)
⇒ m₂ = (3.2×10⁻⁶ N × 2.1x10⁻¹ m )/ { (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg)}
= 18.11 kg.
Hence, the mass of the other object is 18.11 kg.
So, acceleration of the object of mass 55 kg is:
a₁ = F/m₁ = 3.2×10⁻⁶/55 m/s² = 5.8 × 10⁻⁸ m/s².
The acceleration of the object of mass 18.11 kg is:
a₂ = F/m₂ = 3.2×10⁻⁶/18.11 m/s² = 17.66× 10⁻⁸ m/s².
Hence, their acceleration if they are released from their position will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².
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What is the change in internal energy if 60 J of heat is released from a system
and 30 J of work is done on the system? Use AU = Q-W.
OA. 30 J
OB. -30 J
OC. 90 J
OD. -90 J
Answer:
30J
Explanation:
Δq = Δu + Δw
⇒Δu = Δq - Δw
here, Δq = 60J & Δw = 30J
∴ Δu = 60 - 30 = 30 J
I have a material thats 65 cubic feet totaling 40000 cubic yards. How many dump trucks will it take to haul this material?
It will take about 2,500 dump trucks to haul the material. Assuming the capacity of the dump truck is 16 cubic yards.
Note: A standard dump truck is between 10 -16 cubic yards.
1 cubic yard = 27 cubic feet.
from the question:
40,000 cubic yards= 65 cubic feet
hence,
Assuming the dump truck capacity is 16 cubic yards
Then,
number of dump trucks = 40,000 cubic yards/16 cubic yards
=2,500
Therefore a dump truck of 16 cubic yards capacity, will need about 2,500 dump trucks to haul the material totaling 40,000 cubic yards.
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A small 10.0 g bug stands at one end of a thin uniform bar that is initially at rest on a smooth horizontal table. The other end of the bar pivots about a nail driven into the table and can rotate freely, without friction. The bar has mass 50.0 g and is 90 cm in length. The bug jumps off in the horizontal direction, perpendicular to the bar, with a speed of 20.0 cm/s relative to the table.
What is the angular speed of the bar just after the frisky insect leaps?
Express your answer in radians per second.
the angular speed of the bar just after the bug leaps is 0.044 ras/sec.
Given parameter:
Mass of the bug, m= 10.0g
Mass of the bar, M= 50.0 g.
Length of the bar, l = 90 cm.
Speed of the bug ,v = 20.0 cm/s.
Speed of the bar, V = ?
From conservation of momentum;
momentum of the bar = momentum of the bug
⇒ MV = mv
⇒ V = mv/M
= (10.0× 20.0)/50 cm/s.
= 4 cm/s.
Then, angular speed of the bar will be = V/l
= 4/90 rad/s.
= 0.044 rad/s.
Hence, the angular speed of the bar just after the frisky insect leaps is 0.044 rad/sec.
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Question 5
The state of a sample of water depends on (location, temperature).
O No answer text provided.
O location
O Temperature
O No answer text provided.
Yes, the state of a sample of water depends on location and temperature.
What are the states of water and how does water's condition change as a result of temperature?Pure water has no flavour, no aroma, and no colour. There are three different states of water: solid (ice), liquid, and gas (vapour). Ice is frozen water or solid water. Because the molecules of water expand as it freezes, ice is less dense than water. As ice will weigh less than the same volume of water, it will float in the liquid. At 32° Fahrenheit, or 0° Celsius, water freezes. Water that is liquid is moist and fluid. This is the type of water that we are most accustomed to. We use liquid water in a variety of ways, such as drinking and washing.
The air all around us is constantly filled with the vapour of water. It is not visible. When water is boiled, it transforms from a liquid to a gas or water. At ambient temperature, water is a liquid; however, when cold, it solidifies to form ice. If heated, the same water transforms into a gas known as water vapour. Only when the substance reaches a specific temperature do the modifications take place. Ice formation occurs at 32°F (0°C). It requires more energy to raise and lower the temperature of water because a large body of water has a higher heat capacity than land. As a result, cities near water typically have a more limited range of temperatures throughout the year.
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In an experiment a block of copper metal with a mass of 1.3 kg is heated
from 25 °C to 45 °C. The specific heat capacity of copper is 380 J/kg °C.
Calculate the energy needed to heat the copper to 45 °C.
The energy needed to heat the copper from 25 °C to 45 °C if the specific heat capacity of copper is 380 J/kg °C is 9880 J
ΔT = T - To
ΔT = Change in temperature
T = Final temperature
To = Initial temperature
T = 45 °C
To = 25 °C
ΔT = 45 - 25
ΔT = 20 °C
q = m C ΔT
q = Heat Energy
m = Mass
C = Specific heat capacity
m = 1.3 kg
C = 380 J / kg °C
q = 1.3 - 380 * 20
q = 9880 J
Therefore, the energy needed to heat the copper to 45 °C is 9880 J
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a 10.0 kg block of wood is pulled up a ramp with a cable at a constant velocity. given the information below, determine the work preformed if the block is moved 1.75 m up the ramp. if this work was preformed in 2.5 s, how much power was produced
Answer:
Work performed=57.14 NM
Power= 22.86 J/s
Explanation:
Work done= Force/distance
W=F/d
we don't have the force but weight and force is the same thing so to find weight we have to use the formula
Weight= mass × gravitational field strength
W=mg
W= 10.0×10. (please remember that g has a constant value of 10)
W=100 N
Therefore the force is 100 N
Going back to the original equation
W= 100/1.75
W= 57.14 NM
Power=Work done/time
P= W/t
P= 57.14/2.5
P= 22.86 J/s
Bumper car A (282 kg) moving +2.82 m/s makes an elastic collision with bumper car B (210 kg) moving +1.72 m/s. What is the velocity of car A after the collision?
The velocity of Car B after the collision is 4.856 m/s.
What is elastic collision?
A collision is considered elastic if it does not result in a net decrease in the system's kinetic energy. In an elastic collision, both momentum and kinetic energy are conserved.
In an elastic collision, the kinetic energy is essentially unchanged before and after the contact and is not changed into another type of energy.
Either one dimension or two dimensions are possible. Perfectly elastic collision is not feasible in reality since there will always be some energy exchange, no matter how tiny.
m1v1 + m2v2 = m1u1 + m2u2; where
m1= mass of object 1
m2= mass of object 2
v1= initial velocity object 1
v2= initial velocity object 2
u1= final velocity object 1
u2= final velocity object 2
m1v12/2 + m2v22/2 = m1u12/2 + m2u2/2
281·2.82 - 209·1.72 = 281u1 + 209u2;
281·2.822 + 209·(- 1.72)2 = 281u12 + 209u22;
281u1 + 209u2 = 432.94 and 281u12 + 209u22 = 2852.93
u1 = 1.05407 - 0.74377u2;
u1 = (10.15278 - 0.74377u2)1/2
u2 = 4.856 m/s
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As my puppy Ragnar got older, I had to find ways to entertain him. Ragnar
loves to chase rubber balls, so I kick a ball, sending it over a 3 meter high
tree that is 14m away. The ball lands at the same level from which it was
struck after traveling a horizontal distance of 17.8 meters.
(A) If the ball left the ground 54 degrees above the horizontal and landed
2.24 seconds later, what was its initial speed?
(B) How high was the ball when it passed over the tree?
(C) What is the highest point reached by the ball?
(D) If I was to throw the ball instead of kicking the ball
from the ground, how would this affect the ball's time of
flight? Explain.
The ball's velocity must be zero to reach the highest spot it can.
What about the velocity?When an item is moving, its velocity is the rate at which it is changing position as seen from a certain point of view and as measured by a specific unit of time.By dividing the amount of time it took the object to go a certain distance by the overall distance, one can calculate the object's initial velocity. V is the velocity, d is the distance, and t is the time in the equation V = d/t.The velocity of a moving object refers to how quickly it is moving in that direction. as quickly as a vehicle driving north on a freeway or a rocket taking flight.To learn more about velocity refer to:
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11. If a body on which three forces are acting is in equilibrium which of the following-can
be correctly inferred?
I. The vector sum of the three forces is zero
II. Two of the forces act in the same direction
III. Each of the forces has the same magnitude
(A) I only
(B) III only
(C) I and II only
(D) II and III only
(E) I, II, and III
If a body has the three forces acting upon it and is in equilibrium then the vector sum of the three forces is zero. Thus, (A) I only is the correct answer.
I. The vector sum of three forces is zero means that the vector sum of all the three forces is equal to resultant zero vector.
II. If two forces act in the same direction then the body experiences more force on that side and hence is not in equilibrium. For the body to be in equilibrium, then the resultant of any two forces should be opposite, equal and collinear with the third force.
III. For the body to be in equilibrium, magnitude along with direction should be mentioned. If the three forces are in the same plane, convergent (cross the same point) and non-parallel.
Hence, the body on which three forces is acting will be in equilibrium when the vector sum of three forces is zero.
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Tina’s teacher is demonstrating the effect of a sheet of paper on nuclear radiation. He uses an Americium-241 radioactive source close to a detector. There is a count rate of 130 counts per second without the paper. When he puts the sheet of paper between the radioactive source and the detector, the count rate falls almost to 0.
Give
the type of nuclear radiation that the Americium-241 source is producing
The type of nuclear radiation that the Americium-241 source is producing is
an alpha emitter, but also emits some gamma rays.
What is a nuclear radiation?Nuclear radiation (also known as ionising radiation) is energy that is released in the form of high-speed charged particles or electromagnetic waves. Radiation can come from a variety of sources, both natural and man-made. Every living thing is constantly bombarded with low-level radiation from rocks, sunlight, and cosmic rays.
Am-241 emits mostly alpha rays but also some gamma rays. If ingested (swallowed) or inhaled, it poses a greater risk. Americium-241 is created in nuclear power plants by neutron activation of 239Pu and 240Pu, followed by beta decay of 241Pu (T1/2 = 14.35 years). This means that 241Am is produced in burned-up fuel by the decay of 241Pu a long time after the fuel is removed from a nuclear reactor.
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Sam pushes a 10.0 kg sack of bread flour on a frictionless horizontal surface with a constant horizontal force of 2.0 N starting from rest. (a) What is the kinetic energy of the sack after Sam has pushed it a distance of 35 cm? (b) What is the speed of the sack after Sam has pushed it a distance of 35 cm?
10 kg sack of bread flour is given a horizontal force (2 N) and move about 35 cm distance.
Kinetic energy is formed and the speed is changed. The value of kinetic energy and the speed after pushed is calculated as follows :
Change the unit of distance (s = 35 cm = 0,35 m)
• Work = Δ EK
F × s = EK (after pushed) – EK (before pushed)
2 × 0,35 = EK (after pushed) – 0
0,7 Joule = EK (after pushed)
*EK before pushed is zero because the sack does not move*
• Speed after pushed
EK (After pushed) = ½ × m × v²
0,7 = ½ × 10 × v²
0,7 = 5 × v²
v² = 0,7/5 = 0,14
v (after pushed) = 0,37 m/s
So, kinetic energy after pushed is 0,7 joule and the speed is changed to 0,37 m/s.
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About how much greater is the gravitational force exerted by the moon on the near side of the earth than on the far side?.
Difference in Gravity of 7%
The near side of the Earth is 12740 km closer to the Moon than the far side. As a result, the near side experiences a gravitational force that is 7% stronger than the far side.The force that pulls items toward the centre of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.Differential gravitational forces, or gravitational forces that are not equal across a body's finite size, are the fundamental mechanism.
Radius of the earth, r = 6.37*10^6
by solving ((Fn-Ff)/Fn)*100 answer will be of 7%
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Under electrostatic conditions, the electric field just outside the surface of any charged conductor.
The conductor's surface is always perpendicular to.
what is electrostatic condition?
Have you ever wondered why you experience a jolt upon contacting a doorknob? Deciphering these situations will teach you about the idea of electric charge. Two symbols, "+" and "-," can be found on batteries when they are analyzed. This is because the transmission of positive and negative charges occurs at these two ends.
The study of electric charges at rest is done by the science of electrostatics (static electricity).
The ability of some materials to collect light particles after rubbing, such as amber, has been recognised since classical times. Thus, the term "electricity" has its roots in the Greek word for amber, v (lektron). The forces that electric charges apply to one another give birth to electrostatic phenomena. Coulomb's law explains these types of forces.
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Compound interest is a method of calculating interest for which interest is computed on the initial investment amount as well as on any previous interest.
The starting principal sum is multiplied by both of these variables, and the annual interest rate is increased to the number of compound periods minus one.
The full original amount of the loan is then reduced by the resulting value. Compound interest is the term for interest that is earned on interest. This may be shown using simple math: if you start with $100 and it earns 5% interest every year, you will have $105 at the end of the first year. At the end of the second year, you will have $110.25. On the initial principal sum, simple interest is calculated each time. Compound interest is calculated using the sum of the principal and interest. It is equal every year on a particular principal.
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OPEN ENDED QUESTION
What is the connection between the fires
started in LA, Bakersfield, and Fresno?
A jury acquitted him of starting two fires in Fresno but convicted him of several fires that prosecutors claimed he started on his way home to Glendale.
Most serial arsonists only set fire to a place once. Nearly half of the samples consumed alcohol before lighting. The most common motive for arson was revenge followed by rioting vandalism profit and other crime cover-ups. Firefighters' motives for arson range from excitement and thrill to the desire to cover up a crime.
Excitement-based motivation indicates that the firefighter wanted to be seen as a hero. Gasoline is one of the most commonly used fire promoters because it is efficient, easy to ignite, and can usually be purchased and transported without question. The second most common fuels are thinner and kerosene.
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A block with an unknown mass is on a smooth tabletop attached to a string that is attached to a hanging block of mass of 3.6kg. If the blocks accelerate at 2.1 m/s^2 What is the mass of the block on the table? What is the Tension in the rope?
The mass of the block on the table is 2.33 kg.
The Tension in the rope is 4.9 N.
What is the mass of the block on the table?
The mass of the block on the table is calculated by applying Newton's second law of motion.
Newton's second law of motion states that the force applied on an object is directly proportional to the product of mass and acceleration of the object.
F = ma
where;
m is the mass of the blocka is the acceleration of the blockF(net) = ma
m₂g - m₁g = a(m₁ + m₂)
where;
m₂ is the mass of the hanging blocka is the acceleration of the blockm₁ is the mass of the block on tablem₂g - m₁g = m₁a + m₂a
m₂g - m₂a = m₁a + m₁g
m₂g - m₂a = m₁(a + g)
3.6(9.8) - 3.6(2.1) = m₁(2.1 + 9.8)
27.72 = 11.9m₁
m₁ = 27.72 / 11.9
m₁ = 2.33 kg
The tension in the rope is calculated as follows;
T = m₁a
T = 2.33 kg x 2.1 m/s²
T = 4.9 N
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The length of a simple pendulum is 0.80 m and the mass of the "bob" at the end is 0.31 kg. The pendulum is pulled away from equilibrium at an angle of 6.8 degrees and released from rest.
a. What is the angular frequency of the motion?
b. Using the position of the bob at its lowest point as the reference level, determine the total mechanical energy of the pendulum as it swings back and forth.
c. What is the bob's speed as it passes through the lowest point of the swing?
a) angular frequency of the motion is ω = 3.5s⁻¹
b) total mechanical energy of the bob is T.M.E = 0.029J
c) bob's speed at the lowest point is V= 0.43m/s.
A mechanical device that oscillates or sways is known as a simple pendulum. The gravitational force is primarily responsible for this motion, which takes place in a vertical plane.
Given,
Length of a simple pendulum, L = 0.80m
Mass of the bob, m = 0.31 kg
h= L- LcosΘ = L (1 - cosΘ)
a) Angular frequency, ω = 2π / T
where, T = 2π √(L/g)
ω = 2π / 2π √(g/L)
ω =√(9.8 / 0.80) s⁻¹
ω = 3.5s⁻¹
b) Total mechanical energy, T.M.E = (K.E.)ₐ + (P.E.)ₐ
As (K.E.)ₐ = 0
(P.E.)ₐ =mgh
T.M.E = 0 + mgh, where h = L (1-cosΘ)
T.M.E = ngL (1-cosΘ)
= 0.31*9.8*0.80(1-0.988)
= 0.029J
Thus, T.M.E = 0.029J
c) bob's speed at the lowest position, V
TMEb = 0.029J
(KE)b + (PE)b = 0.029J
1/2mV² + 0 = 0.029J
V =√(2*0.029/m)
V = 0.43m/s
So, the speed at the lowest point is V= 0.43m/s.
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M
6
3310
M
WWW
Find Req between a and b
The answer is 5.6 ohms.
The electrical resistance of a circuit component or device is defined as the ratio of the applied voltage to the current through it. If the resistance is constant over a considerable voltage range. This is shown below. To calculate the total resistance of multiple resistors connected in this way, add the individual resistances.
calculation:-
V = iR
R = V/I
= 33.10/6
5.6.
Wire resistance is proportional to resistance and length and inversely proportional to wire cross-sectional area. To determine the condition of a circuit or component. The higher the resistance, the lower the current flow, and vice versa. Resistance is a measure of resistance to the flow of current in an electrical circuit. Resistance is measured in ohms and represented by the Greek letter omega.
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