Water is one of the most important resources for humans. Some areas are known to have no water shortages, where other areas are now suffering the scarcity of water. List some factors that change the distribution of water abundance.

(written response)

Answers

Answer 1

Answer:

The factors are various, although there are main and accessories.

The main factor is the climate of the area, that is, if it is a rainier climate, there will be more water masses in the lands where this climate abounds (usually it is wet).

Other factors are: geographical features, flows, the path of rivers, lakes or lagoons, the presence or absence of ports, the number of trees and the distribution of rocks.

Explanation:

Another important factor is the height of the land, the higher the level of the earth, the more difficult it will be to accumulate water, this is how low areas are also flooded.


Related Questions

Please for the love of jesus help. );
Identify the molecule containing the least oxygen atoms.

A) 12.044 × 10^23 molecules of CO2.

B) 12 g of O3.

C) 0.1 mol of V2O5.

D) 10 mL of H2O.

Answers

10mL of H2O this answer

If earth is 1.50 x 10^8km from the sun what is the distance in Mm?

Answers

The distance of the earth to the sun in Mm = 1.5 x 10⁵

Further explanation

Given

The distance of the earth to the sun : 1.50 x 10⁸ km

Required

The distance in Mm

Solution

In converting units we must pay attention to the conversion factor.

the conversion factor :

1 kilometer(km) = 10⁻³ megameter(Mm)

So the distance conversion :

1.5 x 10⁸ x 10⁻³ = 1.5 x 10⁵ Mm

Suppose a molecule with six electron groups is confined to two dimensions and has a hexagonal planar electron geometry. A molecule with six electron groups arranged in a hexagonal planar geometry. The top and bottom groups are labeled 1 and 4, respectively. The two groups next to 1 are labeled 2 and the two groups next to 4 are labeled 3. If two of the six groups are lone pairs, where would they located?

Answers

Answer:

Above and below the plane of a square

Explanation:

The number of electron groups often determine the shape of a molecule. When we have a coordination number of six, one of the possible arrangement of groups is the hexagonal planar geometry. In this arrangement, six electron groups are arranged in the same plane.

If two among the groups are replaced by lone pairs, the substituents will arrange themselves at the corners of a square while the lone pairs will be found above and below the plane of the square. This is the square planar geometry.

The two lone pairs will be located at the top and at the bottom of the plane.

The VSEPR theory is a model that helps to predict the shape of a molecule based on the repulsions associated with the electron groups on the central atom.

Given that a hexagonal planar electron geometry possibly has 6 electron groups. The description of how the electron groups are arranged can be seen in the first image below.

If two of the six groups are lone pairs, we know that lone pairs repel each other. As such, in this arrangement, the lone pairs will occpy the opposite direction which is the top and the bottom of the plane in order to have minimum repulsion as possible.

Learn more about electronic geometry here:

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How can u change cm to dm

Answers

1 Decimeter (dm) is equal to 10 centimeters (cm).

So, divide the length value by 10

Label the diagram by placing the names on the correct positions on the picture.






Label the diagram by placing the names on the correct positions on the picture.

Answers

Answer:

Show diagram so we can see

Explanation:

Critical thinking problem: The iron in hemoglobin in our red blood cells is used to bind and carry dioxygen throughout the body. Iron is one of the atoms that can form hybrid orbitals using its d-shell electrons, which allows for a greater number of sigma bonds than just four. When iron is only bound to protein, it forms five sigma bonds with one lone pair. The iron atom is pulled down below the central square plane due to one of the bonds with the hemoglobin protein. The thick lines indicate bonds pointing out of the screen, while dashed lines indicate bonds pointing into the screen, so as to suggest 3-D structure.

When iron binds to dioxygen, it now has six sigma bonds. The geometry changes, even though the hybridization orbitals do not change. The dashed lines are still present, as seen from the top-down view, but the thick lines hide them in the side-on view.

Why would the molecular geometry for iron change in this case? Would this have anything to do with the ability of hemoglobin to bind oxygen tightly?

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Answer:

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Contents Home   Bookshelves   Physical & Theoretical Chemistry   Supplemental Modules (Physical and Theoretical Chemistry)   Electronic Structure of Atoms and Molecules Expand/collapse global location

Predicting the Hybridization of Simple Molecules

Last updatedAug 16, 2020

Predicting the Bond-Order of Oxides based Acid Radicals

 

Prediction of Aromatic, Anti Aromatic and Non Aromatic Character of Heterocyclic Compounds along with their Omission Behavior- Innovative Mnemonics

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Prof. Linus Pauling (1931) first developed the Hybridization state theory in order to explain the structure of molecules such as methane (CH4).1This concept was developed for simple chemical systems but this one applied more widely later on and from today’s point of view it is considered an operative empirical for excusing the structures of organic and inorganic compounds along with their related problems. An innovative method proposed for the determination of hybridization state on time economic ground 2,3,4.

Prediction of sp, sp2, sp3 Hybridization state

We Know, hybridization is nothing but the mixing of orbital’s in different ratio to form some newly synthesized orbitals called hybrid orbitals. The mixing pattern is as follows:

s + p (1:1) - sp hybrid orbital; s + p (1:2) - sp2 hybrid orbital ; s + p (1:3) - sp3 hybrid orbital

Formula used for the determination of sp, sp2 and sp3 hybridization state:

Power on the Hybridization state of the central atom = (Total no of σ bonds around each central atom -1)

All single (-) bonds are σ bond, in double bond (=) there is one σ and 1π, in triple bond (≡) there is one σ and 2π. In addition to these each lone pair (LP) and Co-ordinate bond can be treated as one σ bond subsequently.

Eg.:

a. In NH3: central atom N is surrounded by three N-H single bonds i.e. three sigma (σ) bonds and one lone pair (LP) i.e. one additional σ bond. So, in NH3 there is a total of four σ bonds [3 bond pairs (BPs) + 1 lone pair (LP)] around central atom N. Therefore, in this case power of the hybridization state of N = 4-1 = 3 i.e. hybridization state = sp3.

b. In H2O: central atom O is surrounded by two O-H single bonds i.e. two sigma (σ) bonds and two lone pairs i.e. two additional σ bonds. So, altogether in H2O there are four σ bonds (2 bond pairs + 2 lone pairs) around central atom O, So, in this case power of the hybridization state of O = 4-1 =3 i.e. hybridization state of O in H2O = sp3.

c. In H3BO3:- B has 3σ bonds (3BPs but no LPs) and oxygen has 4σ bonds (2BPs & 2LPs) so, in this case power of the hybridization state of B = 3-1 = 2 i.e. B is sp2 hybridized in H3BO3. On the other hand, power of the hybridization state of O = 4-1= 3 i.e. hybridization state of O in H3BO3 is sp3.

d. In I-Cl: I and Cl both have 4σ bonds and 3LPs, so, in this case power of the hybridization state of both I and Cl = 4 - 1 = 3 i.e. hybridization state of I and Cl both are sp3.

e. In CH2=CH2: each carbon is attached with 2 C-H single bonds (2 σ bonds) and one C=C bond (1σ bond), so, altogether there are 3 sigma bonds. So, in this case, power of the hybridization state of both C = 3-1 = 2 i.e. hybridization state of both C’s are sp2.

Prediction of sp3d, sp3d2, and sp3d3 Hybridization States

All composites are made up of two main components, a ________ and ___________.

Answers

Answer:

Matrix and Fibre.

Explanation:

The two main components composites are made up of are matrix and fibre. The matrix is the base material while the fiber is what reinforces the material.

Which of the following combinations would form an atom with no charge (neutral)
A 3 protons, 3 neutrons, 4 electrons

B. 5 protons, 5 neutrons, 4 electrons

C. 4 protons, 3 neutrons, 4 electrons

D. 5 protons, 6 neutrons, 6 electrons

Answers

Answer:

C

Explanation:

Suppose that we continue to work with the gas from the previous problem ( 2 moles of gas occupy 126 L at 346 K, and that the van der Waals constants are a = 6.20 atmL^2/mol^2 and b = 0.0852 L/mol), but consider the molecules to be mathematical points. Calculate the pressure and compare it to the values from the previous problem.

Answers

Answer:

0.448 atm

Explanation:

So, we have;

n = 2 moles

V = 126 L

T = 346 K

a = 6.20 atmL^2/mol^2

b = 0.0852 L/mol

R = 0.082 atmLK-1mol-1

P = nRT/V -nb - an^2/V^2

Substituting values;

P=2 * 0.082 * 346/126 -(2 * 0.0852) - 6.20 * 2^2/126^2

P=56.744/125.8296 -24.8/15876

P= 0.45 - 0.001562

P= 0.448 atm

Where are valence electrons located in an atom?

Answers

Answer:

Valence electrons are the electrons in the outermost shell, or energy level, of an atom.

Answer: The outermost shell

Explanation:

Valence electrons are located in the outermost shell of the atom, or the energy level as it is also known.

Out of the given four mixtures, the one that appears clear and transparent is:
a) Chalk powder and water
b) Sand and water
c) Starch and water
d) Sugar and water​

Answers

Answer:

d) Sugar and water​

Explanation:

The sugar and water solution will have a clear and transparent outlook.

When we look at a solution of a mixture of sugar and water, it a homogenous one.

A homogenous solution have their solution in one phase.

The solute is sugar and the solvent is water.

The solution obtained is colorless therefore, light will pass through without any obstruction.

The other solutions will be translucent or opaque

How much concentrated solution would you take to prepare 1.30 LL of 0.100 MM HNO3HNO3 by mixing with water

Answers

Answer:

8.2mL of the concentrated solution must be taken diluting to 1.30L with water

Explanation:

The concentrated HNO₃ comes in a presentation of 70% = 15.8M

As the concentrated solution is of 15.8M and we want to obtain a 0.100M, the dilution must be of:

15.8M / 0.100M = 158 times must be the concentrated solution diluted

As the total volume we want to prepare is 1.30L, the volume of the concentrated solution must be:

1.30L / 158 = 8.2x10⁻³L =

8.2mL of the concentrated solution must be taken diluting to 1.30L with water

An unknown element X has the following isotopes: ²⁵X (80.5% abundant) and ²⁷X (19.5% abundant). What is the average atomic mass in amu of X?

Answers

Answer:

25.39

Explanation:

Given parameters:

Abundance of X-25  = 80.5%

Abundance of X - 27  = 19.5%

Unknown:

Average atomic mass of X  = ?

Solution:

The average atomic mass of X can be derived using the expression below:

Average atomic mass = (abundance x mass of X - 25) + (abundance x mass of X - 27)

Average atomic mass  =  (80.5%  x 25) +   (19.5% x 27)  = 25.39

Name some acidic and alkaline substances that you use at home

Answers

Answer: write anything given below in the diagram except for the neutral substances

Explanation:

Answer:

Alkaline

1 drain cleaner

2 oven cleaner

3 baking soda

4 drain unblocker

Acid

1 drain cleaner

2 bowl cleaner

3 house bleach

4 diluted soap

Calculate the mass of butane needed to produce 97.4 g of carbon dioxide. Express your answer to three significant figures and include the appropriate units. g

Answers

Answer:

32.1 g

Explanation:

Step 1: Write the balanced combustion reaction

C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O

Step 2: Calculate the moles corresponding to 97.4 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

97.4 g × 1 mol/44.01 g = 2.21 mol

Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide

The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol

Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀

The molar mass of C₄H₁₀ is 58.12 g/mol.

0.553 mol × 58.12 g/mol = 32.1 g

After 3 half lifes go by, there are 26g of Sodium-24 left. The parent sample of Sodium-24 is

grams.

NUMBERS ONLY FOR THIS ANSWER

Blank 1:

Answers

Answer:

208 grams

Explanation:

Half life is the time it takes for a sample to reduce to half it's initial concentration.

In this question, 3 half lives go by. This is given as;

Let original mass be represented by x

First Half life;

Starting mass = X

Remaining mass = X/2

Second Half life;

Starting mass = X/2

Remaining mass = (X/2) / 2 = x/4

Third Half life;

Starting mass = X/4

Remaining mass = (X/4) / 2 = X/8

Since 26g was left, it means;

X/8 = 26

X = 26 * 8  = 208 grams

Question 3
Which organism in a food web does not get its energy from other organisms?
A. decomposer
O
B. producer
O
C. primary consumer
D. secondary consumer
O

Answers

Hi there!

[tex]\large\boxed{\text{B. Producer}}[/tex]

The only organisms in a food web that do not get energy from other organisms are producers. These are autotrophs (ex: plants or phytoplankton) that use photosynthesis to produce energy. This means that these organisms only intake water and sunlight rather than nutrients from other organisms (consumers).

14. A pediatric vitamin drug product contains the equivalent of 0.25 mg of fluoride ion in each milliliter. How many milligrams of fluoride ion would be provided by a dropper that delivers 0.6 mL

Answers

Answer:

[tex]m=0.15mg[/tex]

Explanation:

Hello!

In this case, since the concentration of the fluoride ion in the vitamin drug product is:

[tex]0.25\frac{mg}{mL}[/tex]

Now, since the used volume of product was 0.6 mL, the following grams are going to be present:

[tex]m=0.25\frac{mg}{mL}*0.6mL \\\\m=0.15mg[/tex]

Best regards!

22.17 grams of Mercury (II) Nitrate, Hg(NO3)2, reacts with an excess of Potassium, K.
How many grams of Mercury is formed.
Hg(NO3)2 + 2 K = 2 KNO3 + Hg

Answers

Answer:

Mass = 14.0 g

Explanation:

Given data:

Mass of mercury nitrate = 22.17 g

Mass of mercury formed = ?

Solution:

Chemical equation:

Hg(NO₃)₂ + 2K    →    2KNO₃ + Hg

Number of moles of mercury nitrate:

Number of moles = mass/molar mass

Number of moles = 22.17 g / 324.6 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of Hg(NO₃)₂ and mercury.

                Hg(NO₃)₂       :        Hg

                     1                :          1

                  0.07             :       0.07

Mass of mercury:

Mass = number of moles × molar mass

Mass = 0.07 mol × 200.6 g/mol

Mass = 14.0 g

Approximately 13.70 grams of mercury (Hg) will be formed in the reaction.

Calculating the molar masses of the reactants and products in the balanced chemical equation and using stoichiometry will give us the mercury mass.

[tex]Hg(NO_{3})_2[/tex] molar mass:

Mercury (Hg) weighs 200.59 g/mol.

Nitrogen (N) weighs 14.01 g/mol.

O (oxygen) weighs 16.00 g/mol.

Since[tex]Hg(NO_{3})_{2}[/tex]  has two nitrate ions ([tex]NO_{3}[/tex]), we double the molar mass of [tex]NO_{3}[/tex] (62.00 g/mol) by 2.

The molar mass of [tex]Hg(NO_{3})_2[/tex]  is 324.61 g/mol: 200.59 g/mol + 2(14.01 g/mol + 3(16.00 g/mol)) = 200.59 g/mol + 2(48.00 g/mol) = 200.59 + 2(62.01 g/mol) = 200.59 + 124.02 = 324.61.

From the balanced equation, Hg(NO3)2 and Hg have a 1:1 molar ratio. Hg(NO3)2 creates one mole of Hg.

Calculate [tex]Hg(NO_{3})_2[/tex]moles:

22.17 g [tex]Hg(NO_{3})_2[/tex]

22.17 g/324.61 g/mol = 0.0682 mol.

Hg forms 0.0682 mol due to the 1:1 molar ratio.

Hg mass:

Hg's mass is 0.0682 mol × 200.59 g/mol = 13.70 g.

The process will produce 13.70 grammes of mercury (Hg).

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Given the balanced equation 2C+ 3H2

Answers

Answer:

Explanation:

The answer is (4) 4.0 mol. This is a stoichiometry problem. You start with 2.0 mol of C2H6 and obtain the moles of C by multiplying 2.0 by the mole ratio, in this case 2. 2.0*2=4.0mol.

Use your periodic table to complete the table below. The first one has been done for you.

Element
Atomic #
Mass
Protons
Neutrons
Electrons
Symbol
Iodine
53
127
53
74
54
I1-




35
17




Cl1-
Hydrogen


1
1


0




35




45
36




5
11






B3+
Oxygen


16
8


10



Element
Atomic #
Mass
Protons
Neutrons
Electrons
Symbol
Nitrogen




7
7
10


Aluminum


27




10






56
26


24




29




35


Cu1+




64
29


27




Match each of the positive ions listed with the total number of electrons that ion contains. Use your periodic table. The same answer may be used more than once.

A) 2 B) 10 C) 21 D) 23 E) 24
F) 25 G) 36 H) 48 I) 76 J) 81

____ Al+3 ____ Fe+3 ____ Mg+2 ____ Sn+2
____ Li+1 ____ Cr+3 ____ Rb+1 ____ Pt+2

Answers

Answer: my epic on fortnite is

Explanation:Bookboy24 ok add me and arena or creative

When you go to the doctor for an illness, the doctor asks you how you feel. You describe all your symptoms. Then, the doctor makes hypotheses about which organ system is having problems.


Drag each set of complaints below to the organ system most likely to be having problems.


stomach ache,
gassy,
no appetite
sneezing all the time
, runny nose,
trouble breathing,
coughing
having a very hard time remembering people's names,
feeling sad and anxious
seem to be catching every disease that comes around, taking a long time to get a better Respiratory system



Nervous system

Immune system

Digestive system

Answers

Answer:

1. Digestive system.

2. Respiratory system

3. Nervous system

4. Immune system

Explanation:

When you go to the doctor for an illness, the doctor asks you how you feel. You describe all your symptoms. Then, the doctor makes hypotheses about which organ system is having problems.

1. Digestive system: stomach ache, gassy, no appetite.

2. Respiratory system: sneezing all the time, runny nose, trouble breathing, coughing.

3. Nervous system: having a very hard time remembering people's names, feeling sad and anxious.

4. Immune system: seem to be catching every disease that comes around, taking a long time to get a better

What is responsible for the unusual ecosystem of the highlands?

Answers

Answer:

volcanoes and volcanic activity

Explanation:

I had the same Question and I got that.

Answer: Volcanoes and Volcanic Activity :)

Explanation: I got the same question :D

explain why we do not see this side product. write the reaction that removes side product as its formed

Answers

Answer:

See explanation

Explanation:

Looking at the structure of the starting material, we can see that the carbocation intermediate is a tertiary carbocation.

The tertary carbocation is very stable.  Indeed, it is the most stable carbocation intermediate. As such, none of this other product is obtained due to this intermediate.

The mechanism of this reaction is shown in the image attached to this answer.

Environmental Science-JMajors-GEO-220029.001: Mastery Assess It_2 5. Most of the concentration of which gas results from the activity of producer organisms?​

Answers

Answer: Oxygen

Explanation:

Producer organisms include plants and algae and refer to organisms that are able to produce their own food by synthesizing it from inorganic matter. This is what plants and algae are able to do through the process of photosynthesis.

During photosynthesis, these organisms produce food for themselves and in doing so produce oxygen as a by-product. This is what contributes mostly to the concentration of oxygen in the atmosphere.

What kind of ions does metal form?
* ionic bond
* covalent bond
* anions
* cations
* melting point
* boiling point
conductivity
* Polyatomic Ions
* Valence electron
* Metal
* Nonmetal
* Metaloids

Answers

Answer:

Option D: Cations

Explanation:

Do you need only one answer .

When the concentration of A in the reaction A ..... B was changed from 1.20 M to 0.60 M, the half-life increased from 2.0 min to 4.0 min at 25°C. Calculate the order of the reaction and the rate constant.

Answers

Answer:

2

[tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]

Explanation:

Half-life

[tex]{t_{1/2}}A=2\ \text{min}[/tex]

[tex]{t_{1/2}}B=4\ \text{min}[/tex]

Concentration

[tex]{[A]_0}_A=1.2\ \text{M}[/tex]

[tex]{[A]_0}_B=0.6\ \text{M}[/tex]

We have the relation

[tex]t_{1/2}\propto \dfrac{1}{[A]_0^{n-1}}[/tex]

So

[tex]\dfrac{{t_{1/2}}_A}{{t_{1/2}}_B}=\left(\dfrac{{[A]_0}_B}{{[A]_0}_A}\right)^{n-1}\\\Rightarrow \dfrac{2}{4}=\left(\dfrac{0.6}{1.2}\right)^{n-1}\\\Rightarrow \dfrac{1}{2}=\left(\dfrac{1}{2}\right)^{n-1}[/tex]

Comparing the exponents we get

[tex]1=n-1\\\Rightarrow n=2[/tex]

The order of the reaction is 2.

[tex]t_{1/2}=\dfrac{1}{k[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{t_{1/2}[A]_0^{n-1}}\\\Rightarrow k=\dfrac{1}{2\times 1.2^{2-1}}\\\Rightarrow k=0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]

The rate constant is [tex]0.4167\ \text{M}^{-1}\text{min}^{-1}[/tex]

I need the answer please

Answers

I personally thinks it’s A

We made a bowl of jelly. What sort of change is this?

Answers

Answer:

Explanation:

It changes from a liquid to a solid. This change occurred due to the change in temperature. As the mixture cooled, the molecules condensed and the mixture formed a solid shape.Which formed the jelly.

26. Which statements would be expected to be true for Organesson (Og)? Select all that apply.

A It is relatively unreactive.

B. It has a high electron affinity.

C. It has a full valence shell of electrons.

D. It has the largest atomic radius of the four new elements.

E. It has the lowest effective nuclear charge of the four new elements.

Answers

The central charge is another name for the effective nuclear charge that an electron experiences.. It has the lowest effective nuclear charge of the four new elements.

What is element ?

An element is a type of atoms, including the pure material made entirely of that species, that have a specific number of protons in their nuclei.

Chemical elements, in contrast to chemical compounds, cannot be reduced by any chemical process into simpler molecules. The oxidation number of the atom can be used to calculate the strength of the nuclear charge.

The metals and non-metals are the other two basic categories into which the elements may be separated. Metals are frequently bright, malleable, and carry electricity.

All living and non-living things are made up of elements, which are fundamental building blocks. They serve as the universe's center. Elements make up every particle, no matter how little or large. Our body is composed of five main components are Calcium, Carbon, Hydrogen, Oxygen, and Nitrogen

Thus, option E is correct.

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