Drainpipe comes in lengths of 2.5 metres. A man wants to buy drainpipe to fit down
one side of his house from the ground to the gutter.
Estimate how many lengths he will need.
lengths

Answer:

200 cans.

Step-by-step explanation:

f(c)=10r + 120

Put t=8 into it

T(c) = 10 x 8 + 120

=200 cans

(Use substitution method)

Answer:

y=-x^2-4x-1

Step-by-step explanation:

when it is an arch like an upside down U then its

-x^2

it passes through the y axis at -1

its vertex or high point is -2,3 so its

-4x

Answer:

See below

Step-by-step explanation:

Dome shaped parabola      so   'a'  is negative

'c' is determined where x = 0

    this value is -1

Axis of symmetry is the x value of the vertex (which is the high point of the dome)

   x = -2

Another way to write the equation is 7x + 54 = 0

Given the equation;

[tex]\frac{7}{8}x + \frac{3}{4} = -6[/tex]

Find the LCM on the left side, which is 8

[tex]\frac{7x + 6}{8} = -6[/tex]

Cross multiply

[tex]7x + 6 = -6[/tex] × [tex]8[/tex]

[tex]7x + 6 = -48[/tex]

Collect like terms

[tex]7x = -48 - 6[/tex]

[tex]7x = -54[/tex]

Take all to one side

[tex]7x + 54 = 0[/tex]

Thus, another way to write the equation is 7x + 54 = 0

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Step-by-step explanation:

all the details see in the attachment.

Answer:

please help me find em ah and I will be able to do what I can

Answer:

6 and 4

Step-by-step explanation:

Let one number be x.

Then another will be : 4x - 20

In accordance with the question;

x + 4x - 20 = 10

5x = 10 + 20

x = 30/5

= 6

x = 6

4x - 20 = 4×6 - 20 = 4

So, the numbers are 6 and 4.

Answer:

They could make at most 5 teams and its not possible to make everyone on team.

Step-by-step explanation:

If there are 4 players on a team, then we use 23 ÷ 4 = 5.75, 0.75 is not enough for 1, so there are 3 players remaining after making 5 teams.

The value of the probability P(x > 2) is 0.8369

The given parameters are:

n = 5

p =0.7

The probability is calculated as:

[tex]P(x) = ^nC_x *p^x * (1 - p)^x[/tex]

Using the complement rule, we have:

P(x > 2) = 1 - P(0) - P(1) - P(2)

Where:

[tex]P(0) = ^5C_0 *0.7^0 * (1 - 0.7)^5[/tex]

P(0) = 1 *1 * (1 - 0.7)^5 = 0.00243

[tex]P(1) = ^5C_1 *0.7^1 * (1 - 0.7)^4[/tex]

P(1) = 5 *0.7^1 * (1 - 0.7)^4 = 0.02835

[tex]P(2) = ^5C_2 *0.7^2 * (1 - 0.7)^3[/tex]

P(2) = 10 *0.7^2 * (1 - 0.7)^3 = 0.1323

Recall that:

P(x > 2) = 1 - P(0) - P(1) - P(2)

So, we have:

P(x > 2) = 1 - 0.00243 - 0.02835 - 0.1323

Evaluate

P(x > 2) = 0.83692

Approximate

P(x > 2) = 0.8369

Hence, the value of the probability P(x > 2) is 0.8369

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Answer:

Slope-intercept form: y = 3x - 1

Step-by-step explanation:

We are given that a line passes through the point (-5, -16) and has a slope of 3

We want to write the equation in point-slope form, and simplify it to slope-intercept form (if it is possible to do so).

First, point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point

We have both the slope and a point, but let's label the values of everything to avoid confusion + mistakes:

m = 3

[tex]x_1=-5\\y_1=-16[/tex]

Now substitute into the formula (remember: we have NEGATIVE numbers, and the formula uses SUBTRACTION):

[tex]y--16=3(x--5)[/tex]

The equation can be simplified

[tex]y+16=3(x+5)[/tex]

We can also write this in slope-intercept form

Start by distributing 3 to both x and 5 (multiply both x and 5 by 3)

[tex]y+16=3x + 15[/tex]

Subtract 16 from both sides

y = 3x - 1

The estimated cost of the ending inventory, assuming the gross profit rate is 35% is; $11250

Let us first calculate the gross profit;

Gross Profit = Sales * Profit%

Gross Profit = 395000 * 35%

Gross Profit = $138250

Cost of goods sold = Sales - Gross Profit

Cost of goods sold = 395000 - 138250

Cost of goods sold = $256750

Cost of ending inventory = Cost of goods available for sale - Cost of goods sold

Cost of ending inventory = 268000 - 256750

Cost of ending inventory = $11250

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The average rate of change for this function for the interval from x = 2

to x = 4 is 20

The function is given as:

x   y

0  18

2   32

3    50

4   72

The average rate of change at the interval from x = 2 to x = 4 is calculated using:

m = (f(4) - f(2))/(4 - 2)

Using the table values, we have:

m = (72 - 32)/(4 - 2)

Evaluate

m = 20

Hence, the average rate of change is 20

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The standard deviation is a measure of a collection of values' variance or dispersion. The correct option is B.

The standard deviation is a measure of a collection of values' variance or dispersion. A low standard deviation implies that the values are close to the set's mean, whereas a high standard deviation shows that the values are spread out over a larger range.

For the last summer,

Mean = (140 + 220 + 190 + 180 + 190) / 5 = 920/5 = 184

[tex]\sigma={\sqrt {\dfrac{(140-184)^2+ (220-184)^2+(190-184)^2+(180-184)^2+(190-184)^2}{5}}}\\\\\sigma = 25.7682[/tex]

For this summer,

Mean = (150 + 170 + 150 + 190 + 180) / 5 = 840/5 = 168

[tex]\sigma={\sqrt {\dfrac{(150-168)^2+ (170-168)^2+(150-168)^2+(190-168)^2+(180-168)^2}{5}}}\\\\\sigma = 16[/tex]

Hence, The number of pages in each book varied more last summer than this summer. Thus, the correct option is B.

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Answer:

a. b = 2A/a

b. 30

Step-by-step explanation:

a. to solve for b:

[tex]A = 1/2 ab[/tex]

multiply both sides by 2

[tex]2A = ab[/tex]

divide both sides by a

[tex]2A/a=b[/tex]

so b = 2A/a

b. using the equation b = 2A/a

[tex]b = 2*18/(6/5)\\= 36/(6/5)\\= 30[/tex]

Answer:

Step-by-step explanation:

Write the number as [tex]abc[/tex] and use the divisibility rules for 10 and 3. From the rule for 10, we know that the last digit of [tex]abc+cba[/tex] is [tex]o[/tex], hence [tex]a+c=10[/tex]. Thus the options are [tex]a=1[/tex] & [tex]c=9[/tex], [tex]a=2[/tex], & [tex]c=8[/tex], etc.

From the rule for 3, namely that the digit sum must be divisible by 3, we find that [tex]2a+2b+2c=20+2b[/tex]  is divisible by [tex]3[/tex]. By hand it's easy to check that [tex]b=2,5,8[/tex] are the only options that work.

So there are 9 choices for [tex]a[/tex] and [tex]c[/tex] and [tex]3[/tex] for [tex]b[/tex] , giving 27 total.

Answer:

[tex]31[/tex]

Step-by-step explanation:

It's 31 degrees, I hope it is the right answer

Answer:

-10 and -2

Step-by-step explanation:

First, divide both sides by 4 to get |x+6| = 4
Then, Take the absolute vaule on both sides
x+6= 4 or -4
So, x could be 2 vaules
Your welcome!

4 | x + 6 | = 16

Divide both sides by 4.

[tex]\bf{\dfrac{4|x+6|}{4}=\dfrac{16}{4} }[/tex]

[tex]\bf{|x+6|=4 }[/tex]

Absolute value is solved.

[tex]\bf{|x+6|=4 }[/tex]

We know either x + 6 = 4 or x + 6 = -4.

x + 6 = 4 (Possibility 1)

x + 6 - 6 = 4 - 6 (Subtract 6 from both sides)

x=−2

x + 6 = -4 (Possibility 2)

x + 6 - 6 = -4 - 6 (Subtract 6 from both sides)

x=-10

Solution:

x=−2 or x=−10

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer:

1/4 or 0.25

Step-by-step explanation:

The total possibilities of any 7 digit number using 0-9 is :

9×10×10×10×10×10×10=9000000

To work out the total possibilities in this question :

We look at the conditions :

The first digit can only be 5 numbers :

1 , 3 , 5 , 7 , 9

Now we subtract 5 from 9 :

9-5 = 4

Since no repeats for 2 , 3 , 4, 5, 6:

9 , 8 , 7 , 6 , 5,  

5 possibilities for the last digit :

Total possibilities for this code :

4 × 9 × 8 × 7 × 6 × 5 × 5 = 302400

If it begins with 5 that is only 1 possibility for the first digit

1 × 9 × 8 × 7 × 6 × 5 × 5 = 75600

Now we make a fraction :

75600÷302400

Dividing top and bottom by 75600 gives you 1/4 or 0.25

Hope this helped and have a good day

Answer:

Step-by-step explanation:

Comment

The first digit and the last digit are both odd. That tells you that so far what you have is one of 5 digits for the first digit and and one of 4 for the last digit. 4 because you can't repeat the first digit.

5, , , , , ,4

2 digits are gone 8 remain.

5* 8 * 7* 6* 5* 4* 4 = 134400

Part 2

Only one number can go at the beginning, and that is a 5. Everything else remains the same.

1 * 8 * 7 * 6 *5 * 4 * 4 = 26880

P(picking a number beginning with a 5 is  25880 /13440) = 0.2

The length of the missing sides of triangles A and B are 9.43 cm and 12.04 cm respectively.

Triangle A:

Hypotenuse² = height ² + base²

x² = 8² + 5²

= 64 + 25

x² = 89

x = √89

x = 9.43 cm

Triangle B:

Hypotenuse² = height ² + base²

17² = 12² + x²

17² - 12² = x²

289 - 144 = x²

145 = x²

x = √145

x = 12.04 cm

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Answer:

Step-by-step explanation:

a cuboid has length 18.5 cm, width 9.4 cm a height 6.2 cm. Work out the area of the cuboid​

assuming you are looking for thr surface area

Surface Area of a Cuboid ·

TSA = 2 (lw + wh + hl)

2*( 18.5 * 9.4 + 9.4 * 6.2 + 6.2 * 18.5) =         (remember PEMDAS)

2 * 346.88 =

693.76 cm²

Answer:  Choice D)  All rhombuses are squares

=============================================================

Explanation:

Let's go through the answer choices to see which are true and which are false.

Check out the venn diagram below showing the connection between the geometric shapes mentioned. The large outer rectangle represents the set of all quadrilaterals. Inside this is the oval representing all parallelograms. Then inside the oval is the set of rectangles and the set of rhombuses. The overlapping region of the rectangles and rhombuses is the set of squares, marked in blue.

As you can see, picking any square will get us a rhombus and a rectangle automatically. However, picking any rhombus will not guarantee it's a square.

Answer:

please mark me brainlist

Step-by-step explanation:

i need it

Answer:

3^1 multiplied by 3^2 = 3^(1 + 2) = 3^3

162

Simplify ——————

(2•3^3)

Canceling out 2 as it appears on both sides of the fraction line

3^4 divided by 3^3 = 3^(4 - 3) = 3^1 = 3

Step-by-step explanation:

hope this helps you ♡

Using conditional probability, it is found that there is a 0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

In this problem, we have that the probabilities are given as follows:

[tex]P(A) = 0.433, P(A \cap B) = 0.29 \times 0.50 = 0.145[/tex]

Hence the conditional probability is:

[tex]P(B|A) = \frac{0.145}{0.433} = 0.3349[/tex]

0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

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The trip to the lake took  4 hours.

The first step is to determine the distance of the trip.

Distance = average speed x time

24 km/h x 5 = 120 km

Time = distance / average speed

120 / 30 = 4 hours

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Step-by-step explanation:

(4²-x²)³/²

or,(4+X) (4-X)

Substitute [tex]x = 4 \sin(y)[/tex], so that [tex]dx = 4\cos(y)\,dy[/tex]. Part of the integrand reduces to

[tex]16 - x^2 = 16 - (4\sin(y))^2 = 16 - 16 \sin^2(y) = 16 (1 - \sin^2(y)) = 16 \cos^2(y)[/tex]

Note that we want this substitution to be reversible, so we tacitly assume [tex]-\frac\pi2\le y\le \frac\pi2[/tex]. Then [tex]\cos(y)\ge0[/tex], and

[tex](16-x^2)^{3/2} = 16^{3/2} \left(\cos^2(y)\right)^{3/2} = 64 |\cos(y)|^3 = 64 \cos^3(y)[/tex]

(since [tex]\sqrt{x^2} = |x|[/tex] for all real [tex]x[/tex])

So, the integral we want transforms to

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 64 \int \cos^3(y) \times 4\cos(y) \, dy = 256 \int \cos^4(y) \, dy[/tex]

Expand the integrand using the identity

[tex]\cos^2(x) = \dfrac{1+\cos(2x)}2[/tex]

to write

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 256 \int \left(\frac{1 + \cos(2y)}2\right)^2 \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \cos^2(2y)) \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \frac{1 + \cos(4y)}2\right) \, dy \\\\ = 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy[/tex]

Now integrate to get

[tex]\displaystyle 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy = 32 \left(3y + 2 \sin(2y) + \frac14 \sin(4y)\right) + C \\\\ = 96 y + 64 \sin(2y) + 8 \sin(4y) + C[/tex]

Recall the double angle identity,

[tex]\sin(2y) = 2 \sin(y) \cos(y)[/tex]

[tex]\implies \sin(4y) = 2 \sin(2y) \cos(2y) = 4 \sin(y) \cos(y) (\cos^2(y) - \sin^2(y))[/tex]

By the Pythagorean identity,

[tex]\cos(y) = \sqrt{1 - \sin^2(y)} = \sqrt{1 - \dfrac{x^2}{16}} = \dfrac{\sqrt{16-x^2}}4[/tex]

Finally, put the result back in terms of [tex]x[/tex].

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 128 \frac x4 \frac{\sqrt{16-x^2}}4 + 32 \frac x4 \frac{\sqrt{16-x^2}}4 \left(\frac{16-x^2}{16} - \frac{x^2}{16}\right) + C \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 8 x \sqrt{16 - x^2} + \frac14 x \sqrt{16 - x^2} (8 - x^2) + C \\\\ = \boxed{96 \sin^{-1}\left(\frac x4\right) + \frac14 x \sqrt{16 - x^2} \left(40 - x^2\right) + C}[/tex]

The following statements accurately compare the three functions on the graph: option A and C.

In Geometry, the following statements are true about the graph of a function:

By critically observing the graph of a function, we can logically deduce that the following statements accurately compare the three functions on the graph:

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The solution for the system of equations is: (99/13, 150/13)

Given the two expression 2/3x+3/5y=12 and 5/2y-3x=6

We have to find solution of two given expression.

To find the value of x, we have to eliminate y by making y the subject of formula in any of the equations.

Multiply equation A by 5/3 t.o get,

5/3(2/3x) + 5/3(3/5y) = 5/3(12)

10/9x + y = 20

y = 20 - 10/9x

substituting for y into equation b, we have:

5/2(20 - 10/9x) - 3x = 6

50 - 25/9x - 3x = 6

52/9x = 44

52x = 396

The expression that gives the value of x is: 52x = 396

Hence, x = 396/52 = 99/13

y = 20 - 10/9(99/13) = 20 - 110/13 = 150/13

Hence The solution for the system of equations is: (99/13, 150/13)

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