Find the sum of each infinite geometric series. 0.5+0.05+0.005+ . . . .

Answer: Evaluate

2(5+6q)

Apply the distributive property

2×5+2×6q

Multiply the terms

10+2×6q

Solution

10+12q

Step-by-step explanation:

hope this helps

 The full quadratic expression is expressed as follows:

x² + 8x + 16

An equation is the equality that has mathematical expressions on both sides of it, they can be functions, polynomials or others, there are no limits for them.

  Equations can be graphed, just like a function.

   To solve this problem we must complete square in the expression, it is necessary to note that perfect square trinomial has the form of:

(a + b)² = a² + 2ab + b²

x² + 8x + ?

8x = 2xb

2b =8

b = 4

   Let's complete the square

x² + 8x + (4)²

x² + 8x + 16  

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There is a infinite number of real numbers from 1 through 5

The range is given as

1 to 5

The set of numbers is given as

Real numbers

Real numbers are any number that are not complex or imaginary numbers

This type of number covers all types of number that are not complex or imaginary numbers and it has an infinite count

Since the numbers cannot be counted, we can conclude that there is a infinite number of real numbers from 1 through 5

Hence, there is a infinite number of real numbers from 1 through 5

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Step-by-step explanation:

Given,

X = 3/5, Y = 1/3, Z = 2×4/5

the given question is to find out the value of Z+X×Y so the value is stated as

14/5+3/5×1/3

Here, 14/5 will be remains same and you should multiply 3/5×1/3.

Let 14/5 be equation number (1)

The L.C.M for 3/5×1/3 is 15. then,

3/5×15+1/3×15

___________

15

3×3+1×5

= -------------

15

9+5/15 = 14/15.

Let 14/15 be equation number (2)

Combine equation number (1) and (2) then

14/5+14/15

L.C.M.of 14/5 and 14/15 is 15.

14/5×15+14/15×15

-------------------------

15

[tex] = \frac{42 + 14}{15} [/tex]

[tex] \frac{56}{15} [/tex]

The solution of the given linear equation in one variable 5(s -12) - 24 = 3(s + 2) is at s = 45.

According to the given question.

We have an equation.

5(s -12) - 24 = 3(s + 2)

Since, we have to solve the above linear equation in one variable.

As we know that, the linear equations in one variable is an equation which is expressed in the form of ax+b = 0, where a and b are two integers, and x is a variable and has only one solution.

Thereofre, the solution of the linear equation in one variable 5(s -12) - 24 = 3(s + 2) is given by

5(s - 12) -24 = 3(s + 2)

⇒ 5s - 60 - 24 = 3s + 6    ( by distributive rule)

⇒ 5s - 84 = 3s + 6

⇒ 5s - 3s = 84 + 6

⇒ 2s = 90

⇒ s = 90/2

⇒ s = 45

Hence, the solution of the given linear equation in one variable 5(s - 12) -24 = 3(s + 2) is at s = 45.

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Answer:

Step-by-step explanation:

9989898989

Answer:

the answe r is I because it does not mirror the other side

The sample space for the events are given as follows -

Picking up a one ball randomly from six balls -

S [1] = {A, B, C, D, E , F}

Picking up a one ball randomly from balls D to F -

S [2] = {D, E , F}

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur.

Given in the question a bag has six balls labeled A, B, C, D, E , F and one ball is randomly picked.

Sample space is defined as the set of all the outcomes for a given event. In the question given, the event is picking up of a ball randomly. A total number of six balls are there in the bag. Therefore, if a ball is picked up randomly, it could be any of the six. Therefore - the sample space for this event will be -

S [1] = {A, B, C, D, E , F}

Now, for the event of choosing a letter from D to F, we have total three outcomes. So in this case the sample space will be -

S [2] = {D, E , F}

Therefore, the sample space for the events are given as follows -

Picking up a one ball randomly from six balls -

S [1] = {A, B, C, D, E , F}

Picking up a one ball randomly from balls D to F -

S [2] = {D, E , F}

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The sum of the series of three numbers, which includes the counting number, n, the number before n, and the number after n is 3•n

A series of a sequence of numbers is the sum of the numbers up to a specified term.

The given parameters;

n = A counting number

Counting numbers are the natural numbers which is the set of all positive integers.

Given that n is a counting number, we have that n is a positive whole number.

Which gives;

The whole number before n = n - 1

The whole number after n = n + 1

Which gives;

The sum of n, the whole number before n, and the whole number after n is part of a series and can be written mathematically as follows;

The sum = n + n - 1 + n + 1 = 3•n -1 + 1 = 3•n

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By applying the vertical angles theorem to the two (2) angles, the measures of the labeled angles are equal to 108°.

The vertical angles theorem is also referred to as vertically opposite angles theorem and it states that two (2) opposite vertical angles that are generally formed whenever two (2) lines intersect each other are always congruent i.e equal to each other.

By applying the vertical angles theorem to the two (2) angles, we have:

(x + 81)° = 4x°

x + 81° = 4x°

4x° - x = 81°

3x° = 81°

x° = 81°/3

x° = 27°

Now, we can determine the measures of the labeled angles:

x + 81° = 27° + 81°

x + 81° = 108°

4x° = 4(27)

4x° = 108°

In conclusion, the measures of the labeled angles are equal to 108°.

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Answer:

Step-by-step explanation:

4 revolutions per second

Answer:

ggr44tt55ttffghhtft hyy

The person had been deceased for 12 hours

According to given data,

Temperature of normal person had  98.6 degrees,

and the temperature of the person was 82 degrees

outside temperature  is 55 and

rate of decay is -0.026

The temperature of body drops :

98.6 - 82 = 16.6 degrees

[tex]\frac{16.6}{55}[/tex] ≈ 0.3

[tex]\frac{0.3}{0.026}[/tex]   ≈ 12 hours

therefore, 12 hours had the person been deceased

The rules for exponential decay is f(x) = a b x, where b denotes the decay factor. In the rule of exponential decay function, the decay rate as a decimal. The decay rate represent as a percentage. We change it into a decimal by simply reducing the percent and dividing it by 100.

The amount  reduces by a predetermined percentage at regular periods. The exponential decay formula is used to find  decrease in growth.

f(x) = a (1 – r)x is  form of generic

Where,

a = The initial value

r = decay rate

x = time period

Advantage of the exponential growth and decay graph

The domain is all Real numbers.

The range is all positive real numbers (exclude zero).

Graph has a y-intercept at (0,1). we know that zero power of any number is 1.

we get When b > 1, the graph increases. and 0 < b < 1, the graph decreases.

Has an asymptote (a line that the graph is very close, but never crosses). For  graph the asymptote is the x-axis (y = 0).

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Answer:

17 paintings are displayed

Step-by-step explanation:

Answer:

19.4

Step-by-step explanation:

The distance between the x coordinates of -4 and 15 would be 19 and the distance between the y coordinates of 2 and 6 would be 4.  We can use these to draw a right triangle.  The legs would be 19 and 4.  We would use the Pythagorean Theorem to find the hypotenuse.

[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

[tex]19^{2}[/tex] + [tex]4^{2}[/tex] = [tex]c^{2}[/tex]

361 + 16 = [tex]c^{2}[/tex]

377 =[tex]c^{2}[/tex]

[tex]\sqrt{377}[/tex] = [tex]\sqrt{c^{2} }[/tex]

19.4 ≈ c  That is our answer rounded to the nearest tenth

This ensures that the lines will be parallel since two lines that are perpendicular to one another must also be parallel.

Two lines that meet or cross at right angles (90°) are known as perpendicular lines in geometry. The word "perpendicular" comes from the Latin "perpendicularis," which denotes a plumb line.

We can write two lines, AB and CD, as AB ⟂ CD if they are perpendicular to one another. The lines are denoted as being perpendicular by the ⟂ symbol.

The following list includes the two main characteristics of perpendicular lines.

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Answer:76

Step-by-step explanation:

you replace W with 22

4(22)-12

=88-12

=72

hope this helps! :)

Answer:

76

Step-by-step explanation:

4w-12

4(22)= 88-12

88-12

76

Hope It Helps

Sorry If I'm Wrong

For numbers 5 and 45 the value of the geometric mean of these numbers is

Gm (5, 45) = 15

What is the geometric mean?

  The geometric mean is defined as a type of measure that is calculated as the root of a product between a set of numbers, it can be expressed as follows:

Gm (a, b) = √ab

Then in our case that we have the values 40 and 15, these are equivalent to the variables a and b

a = 5

b = 45

We substitute and solve for the square root

Gm (5, 45) = √5×45

Gm (5, 45) = √225  ;    In this case the square root is direct-

Gm (5, 45) = 15

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The amount that would be saved if 7 bags of grapes were bought on Monday is $2 (option J).

The total cost of items bought on Monday and Wednesday would be added together. This amount would be subtracted from the total cost if the items were all bought on Monday.

The first step is to determine the total cost of the grapes bought on Monday and Wednesday.

Total cost of grapes = cost of grapes bought on Monday + cost of grapes bought on Wednesday

Cost of grapes bought on Monday = number of bags bought x price per bag

3 x $3 = $9

Cost of grapes bought on Wednesday = number of bags bought x price per bag

4 X $2.80 = $11.20

Total cost = $9 + $11.20 = $20.20

Cost or the 7 bags of grapes purchased in 1 trip = number of bags bought x price per bag

7 x $2.60 = 18.20

Amount saved = $20.20 - $18.20 = $2

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The solution of expression is 8log6.

There are four basic properties of logarithms:

logₐ(xy) = logₐx + logₐy.

logₐ(x/y) = logₐx - logₐy.

logₐ(xⁿ) = n logₐx.

logₐx = logₓa / logₓb.

According to the problem, we will use some of the basic logarithmic properties,

We have been given that expression as

⇒ log6⁸ + 2log6³ + log6¹² - log6²⁴​

[used property : logₐ(xⁿ) = nlogₐx]

⇒ 8log6 + 6×2log6³ + 12log6 - 24log6

⇒ 8log6 + 12log6³ + 12log6 - 24log6

⇒ 8log6

Hence, the solution is 8log6.

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Answer:

41. 12, 14

42. 30, 36

43. 0, 1

44. -24, -28

45. 2.5 , 4

46.

47.

48.

49. 63 , 189

Step-by-step explanation:

I don't know answers to 46 , 47 , 48

please make my answer as brainelist

Answer:

Hello,

Step-by-step explanation:

41)

[tex]2,4,6,8,10,...\\\\u_0=2 , u_{n+1}=u_n+2\\\\u_n=2*n+2\\\\[/tex]

42)

[tex]0,6,12,18,24,...\\\\u_0=0 , u_{n+1}=u_n+6\\\\u_n=6*n+0\\\\[/tex]

43)

[tex]-5,-4,-3,-2,-1,...\\\\u_0=-5 , u_{n+1}=u_n+1\\\\u_n=1*n-5=n-5\\\\[/tex]

44)

[tex]-4,-8,-12,-16,-20,...\\\\u_0=-4 , u_{n+1}=u_n-4\\\\u_n=-4*n-4\\\\[/tex]

45)

[tex]-5,-3.5,-2,-0.5,1,...\\\\u_0=-5 , u_{n+1}=u_n+1.5\\\\u_n=1.5*n-5\\\\[/tex]

46)

[tex]-32,-20,-8,4,16,...\\\\u_0=-32 , u_{n+1}=u_n+8\\\\u_n=8*n-32\\\\[/tex]

48)

[tex]0,\dfrac{1}{8},\dfrac{2}{8},\dfrac{3}{8},...\\\\u_0=0 , u_{n+1}=u_n+\dfrac{1}{8}\\\\u_n=\dfrac{1}{8}*n+0\\\\[/tex]

49)

[tex]27,15,3,-9,-21,...\\\\u_0=27 , u_{n+1}=u_n-12\\\\u_n=-12*n+27\\\\[/tex]

47) be carefull this is not a arithmetic sequence but a quadratic.

I show you the general method.

[tex]\begin{array}{c|c|c|c}x&\Delta_1&\Delta_2&\Delta_3\\--&--&--&--\\1&.&.&.\\&&&\\\dfrac{11}{3} &\dfrac{8}{3} &.&.\\&&&\\4 &\dfrac{1}{3}&\dfrac{-7}{3} &.\\&&&\\2 &-2 &\dfrac{-7}{3}&0\\&&&\\--&--&--&--\\\end {array} \\\\Since\ \Delta_3\ is\ null,\ u_n=a*n^2+b*n+c\ has\ for\ degree\ 2.\\[/tex]

[tex]\begin {array} {c|c|c|c|c}n&u_n&equation&\\--&--&-----&\\0&1&=a*0+b*0+c &c=1\\1&\dfrac{11}{3}&=a*1+b*1+c&a+b=\dfrac{8}{3} \\2&4&=a*4+b*2+c&4a+2b=3\\\end {array}\\\\\\\left\{\begin {array} {ccc}4a+2b&=&3\\a+b&=&\dfrac{8}{3}\\\end {array} \right.\\\\\\\left\{\begin {array} {ccc}a&=&\dfrac{-7}{6}\\\\b&=&\dfrac{23}{6}\\\\c&=&1\\\\\end {array} \right.\\\\\\\boxed{u_n=\dfrac{-7}{6}*n^2+\dfrac{23}{6}*n+1} \\[/tex]

[tex]u_n=\dfrac{-7}{6}*n^2+\dfrac{23}{6}*n+1}\\\\u_{n+1}=\dfrac{-7}{6}*(n+1)^2+\dfrac{23}{6}*(n+1)+1}\\\\u_{n+2}=\dfrac{-7}{6}*(n+2)^2+\dfrac{23}{6}*(n+2)+1}\\\\\Delta_1(n)=u_{n+1}-u_{n}=\dfrac{-7}{6}*(2n+1)+\dfrac{23}{6}\\\Delta_1(n+1)=u_{n+2}-u_{n+1}=\dfrac{-7}{6}*(2n+3)+\dfrac{23}{6}\\\\\Delta_2(n)=\Delta_1(n+1)-\Delta_1(n)=\dfrac{-7}{6}*2 \\[/tex]

[tex]\left\{\begin{array}{ccc}u_{n+2}-2u_{n+1}+u_n&=&\dfrac{-7}{3} \\\\u_0&=&1\\\\u_1&=&\dfrac{11}{3} \end {array} \right.[/tex]

Answer:

TWO PAIR OF VERTICAL ANGLES ARE

D,C

A,R

Answer:

D, since 7 is less than 10.

The amount left when Joshua played two basketball hoop games for $3.25 each and four rounds of air hockey for $1.75 each is A. $4.50.

From the information, Joshua purchased a game card for the arcade for a total of $18 and played two basketball hoop games for $3.25 each and four rounds of air hockey for $1.75 each.

Therefore, the amount left will be:

= Total amount with him - Amount spent

= $18 - (2 × $3.25) - (4 × $1.75)

= $18 - $6.50 - $7

= $4.50

The amount left is $4.50

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Answer:

4.50

Step-by-step explanation:

The value of the expression A will be negative 2.

When the relevant factors and natural laws of a mathematical model are given values, the outcome of the calculation it describes is the expression's outcome.

PEMDAS rule means for the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

The expression is given below.

A = 5.5 - 2 + (-11.5) - (-6)

Simplify the expression, then the value of the expression A will be

A = 5.5 - 2 - 11.5 + 6

A = 11.5 - 13.5

A = - 2

The value of the expression A will be negative 2.

Your question was incomplete, the question probably was ...

Find the sum of the expression A=5,5-(+2)+(-11,5)-(-6).

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Explanation:

You want to identify the step that is occurring on each line of the solution to the equation 2(8u+2) = 3(2u-7).

1. 2(8u+2) = 3(2u-7) . . . . Original Equation

2. 16u +4 = 6u -21 . . . . Apply the distributive property

3. 16u +4 -6u = 6u -21 -6u . . . . subtract 6u from both sides

4. 10u +4 = -21 . . . . collect terms

5. 10u -4 = -21 -4 . . . . subtract 4 from both sides

6. 10u = -25 . . . . collect terms

7. 10u/10 = -25/10 . . . . divide both sides by 10

8. u = -2.5 . . . . simplify

The curl of the vector field is:

[tex]=z e^x \hat{\imath}-\left(y z e^x-7 x y e^z\right) \hat{\jmath}-7 x e^z \hat{k}[/tex]

So,

To find the curve:

[Vector Field] Set up [curl F]:

[tex]Curl F=\left|\begin{array}{ccc}\hat{1} & \hat{\jmath} & \hat{k} \\\frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\7 x y e^z & 0 & y z e^x\end{array}\right|[/tex]

Simplify [3x3 Matrix Determinant] with [curl F]:

[tex]Curl F=\left|\begin{array}{cc}\frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\0 & y z e^x\end{array}\right| \hat{i}-\left|\begin{array}{cc}\frac{\partial}{\partial x} & \frac{\partial}{\partial z} \\7 x y e^z & y z e^x\end{array}\right| \hat{j}+\left|\begin{array}{cc}\frac{\partial}{\partial x} & \frac{\partial}{\partial y} \\7 x y e^z & 0\end{array}\right| \hat{k}[/tex]

Simplify [2x2 Matrix Determinant] with [curl F]:

[tex]Curl F=\left[\frac{\partial}{\partial y} y z e^x-\frac{\partial}{\partial z} 0\right] \hat{\mathrm{i}}-\left[\frac{\partial}{\partial x} y z e^x-\frac{\partial}{\partial z} 7 x y e^z\right] \hat{\mathrm{\jmath}}+\left[\frac{\partial}{\partial x} 0-\frac{\partial}{\partial y} 7 x y e^z\right] \hat{\mathrm{k}}[/tex]

The partial derivatives can be differentiated using the basic differentiation techniques listed above under "Calculus":

[tex]\begin{aligned}&\frac{\partial}{\partial y} y z e^x=z e^x \\&\frac{\partial}{\partial z} 0=0 \\&\frac{\partial}{\partial x} y z e^x=y z e^x \\&\frac{\partial}{\partial z} 7 x y e^z=7 x y e^z \\&\frac{\partial}{\partial x} 0=0 \\&\frac{\partial}{\partial y} 7 x y e^z=7 x e^z\end{aligned}[/tex]

When we substitute our partial derivative values, we get:

[tex]\begin{aligned}Curl F&=\left(z e^x-0\right) \hat{1}-\left(y z e^x-7 x y e^z\right) \hat{\jmath}+\left(0-7 x e^z\right) \hat{k} \\&=z e^x \hat{\imath}-\left(y z e^x-7 x y e^z\right) \hat{\jmath}-7 x e^z \hat{k}\end{aligned}[/tex]

So, we've discovered the curl of the given vector field.

Therefore, the curl of the vector field is:

[tex]=z e^x \hat{\imath}-\left(y z e^x-7 x y e^z\right) \hat{\jmath}-7 x e^z \hat{k}[/tex]

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The correct question is given below:
Consider the following vector field. f(x, y, z) = 7xyezi + yzexk (a) find the curl of the vector field.

Answer:

¯＼_(ツ)_/¯

Step-by-step explanation:

x(2x+4)+7(2x+4)[3x-6]=0

(2x^2 + 4x + 14x + 28)(3x-6)=0

(2x^2 + 18x + 28)(3x-6)=0

3x(2x^2 + 18x + 28) -6(2x^2 +18x + 28)=0

6x^2 + 54x^2 + 84x - 12x^2 - 108x - 168 =0

6x^2 + 54x^2 - 12x^2 + 84x - 108x - 168 =0

48x^2 - 24x - 168 =0 {quadratic equation}