+
he document will
3. Calculate the speed for line B.
15
10
Distance (m)
5
A
N
6
a. -2.14 m/s
b. 3 m/s
c. 2.14 m/s
d. 4 m/s
B
€
D
8
Time (s)
E
10 12 14 16

Extraversion, openness, conscientiousness, neuroticism, and agreeableness have common factors in that these are the part of  "Big 5" personality traits.

The scientific study of the mind and behavior is called psychology. Psychologists are actively involved in researching and comprehending how the mind, the brain, and behavior work.

The "Big 5" interpersonal qualities include extraversion, openness, conscientiousness, neuroticism, and agreeableness. These characteristics have certain things in common.

Extraversion, openness, conscientiousness, neuroticism, and agreeableness all have the "Big 5" personality qualities in common.

These five traits combine to form "OCEAN"

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The largest resultant vector is 47 m and the smallest resultant vector is 43 m.

The resultant of a vector is obtained by adding the two vectors together.

The resultant vector  can be any single vector that can effectively describe the other vectors.

The resultant vector is calculated using the following formulas;

R² = A² + B² - 2AB cosθ

R² = (45)² + (2)² - 2(45 x 2) cos(180)

R² = 2209

R = √2209

R = 47 m

R² = (45)² + (2)² - 2(45 x 2) cos(0)

R² = 1849

R = √1849

R = 43 m

Thus, the largest resultant vector is 47 m and the smallest resultant vector is 43 m.

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Answer:

What would happen is that once the two collide they will make a bigger black hole.

Explanation:

a. The magnitude of the total force that the cockpit seat exerts on the 76- kg pilot is 288.8 N.

b. The angle between the positive x axis and the total force that the cockpit seat exerts on the 76- kg pilot is 67⁰.

The force exerted on the pilot by the cockpit is calculated as follows;

F = ma

where;

m is mass of the pilot

a is acceleration of the jet

F = 3.8 m/s² x 76 kg

F = 288.8 N

The total force exerted on the pilot is equal to the normal reaction of the pilot.

F = Fn

F = mg cosθ

cos θ = F/mg

cos θ = (288.8) / (76 x 9.8)

cos θ = 0.3878

θ = arc cos (0.3878)

θ = 67⁰

Thus, the magnitude of the total force that the cockpit seat exerts on the 76- kg pilot is 288.8 N.

The angle between the positive x axis and the total force that the cockpit seat exerts on the 76- kg pilot is 67⁰.

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Explanation:

I solved it in the picture but I'm not a hundred percent sure

The acceleration of the crate  after the frictional force is overcame is determined as 1 m/s².

Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity with time.

The  acceleration of the crate is calculated from the net force acting on the crate as shown below;

F(net) = applied force - frictional force

F(net) = 10 N - 5N

F(net) = 5 N

Apply Newton's second law of motion to calculate the acceleration of the crate.

F(net) = ma

where;

a = F(net) / m

a = 5/5

a = 1 m/s²

Thus, the acceleration of the crate  after the frictional force is overcame is determined as 1 m/s².

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According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.

The formula for the specific heat capacity (C) = Q/ m × ΔT

Q is energy added and the value, which is 334J

m is the mass of the lemonade, which is 300g = 0.3 kg

Δ T is the change in temperature, which is 19°C =(273+19)= 292 K

So, C = 334/ 0.3 × 292

         = 3.81 J/kg/k

So the specific heat capacity of the lemonade is 3.81 J/kg/k.

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The precession is the motion of Earth along its orbital path.

Earth's rotation or Earth's spin is the rotation of planet Earth around its own axis.

Precession of the Earth's axis consists of a cyclic wobbling in the orientation of Earth's axis of rotation with a period of 25,772 years.

The precession of the Earth's axis  wobble is due to tidal forces caused by the gravitational influences of the Sun and Moon.

Thus, precession is the motion of Earth along its orbital path.

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Answer:

It's the last one- Finley > Xander > Max

Explanation:

You just divided the velocity by the time

Mass on the planet would be 10/3 times the mass on Earth weigh on this new planet.

A quantitative measure of the fundamental characteristic of all matter, inertia. In essence, it's the resistance of a mass of matter to changing its direction or speed in reaction to the force applied to it. The much more weight a body has, the less change an applied force produces.

Let the mass of Earth = Me

Let the radius of Earth = Re

Mass of the planet, Mp = 10Me

Radius of the planet, Rp = 3Re

Weight on other planet, W = ?

Weight on planets is determined by the gravitational force

Gravitational force, F = GMm/r²

where, G = gravitational constant

M = Mass of the planet

m = our mass

r = radius of the planet

Gravitational force on Earth:

F = G X Me X ma/ Re².....eq (1) (ma = mass on earth)

Gravitational force on planet :

F = G X 10Me X mₓ/ (3Re)²....eq (2) (mx = mass on other planet)

Dividing both the equations, we get

mx = 10/3ma

Therefore, mass on the planet would be 10/3 times the mass on Earth.

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The time taken for Jada's and Destiny's travel are 0.5595hour and 0.3928 hour

Let us consider distance for which both had to travel be equal

Let this time be 't'

The total distance between them is 65 miles

It is given that speed of Jada and Destiny are 60 and 80 mph

It is also given Destiny starts the journey 10 minutes later, hence her time be t-10 mins

But as all units are in hour , we must convert 10 mins to hour,

10 mins = 0.1667 hours

there Destiny's time of travel = t - 0.1667

We know that distance = speed x time

Therefore, total distance = distance travelled by Jada+ Distance travelled by Destiny

65 = 60 x t + 80 x(t-0.1667)

65 = 60t + 80t - 13.336

78.336 = 140 t

t = 78.336/140 = 0.5595hr

t= 0.5595 hour

Time taken for Jada's travel = 0.5595 hours

Time taken for Destiny's travel = t-0.1667 =0.5595-0.1667  =0.3928 hour

Disclaimer:

Time has been assumed and question provided is incomplete

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if a 2.0-L balloon at room temperature (20.0°C) is placed in a freezer at -18°C, then the volume of the balloon would be 1.74 liters.

It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one.

PV = nRT

By assuming the pressure constant the volume would be directly proportional to the temperature changes from 293 kelvin to 255 kelvin,

V₁ /V₂ = T₁/ T₂

1000 litre = 1 m³

1 litre = 1/1000 m³

2  litre = 2/1000 m³

          =0.002 m³

0.002 / V₂ = 293 / 255

V₂ = 0.001740  m³

The final volume of the balloon =1.74 liters.

Thus, the volume of the balloon would be  1.74 liters.

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Answer:

D=2145g/100cm cubed

Explanation:

D=M/V

D=107.25g/5cm cubed

D=2145g/100cm cubed

The acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

Newton's Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass. Your leg muscles pushing on the pedals of your bicycle is the force. Newton's second law is a quantitative description of the changes that a force can produce in the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

The angle of the ladder inclined with respect to the horizontal after being moved a distance of 0.82 m closer to the building is 53.84°

cos θ = Adjacent side / Hypotenuse

θ[tex]_{1}[/tex] = 47°

Hypotenuse = Length of ladder = 8.5 m

cos 47° = Adjacent side / 8.5

Adjacent side = Initial distance of base of ladder from the building = 5.8 m

Adjacent side 2 = Final distance of base of ladder from the building

Adjacent side 2 = 5.8 - 0.82 = 4.98 m

cos θ[tex]_{2}[/tex] = Adjacent side 2 / Hypotenuse

cos θ[tex]_{2}[/tex] = 4.98 / 8.5 = 0.59

θ[tex]_{2}[/tex] = [tex]cos^{-1}[/tex] ( 0.59 )

θ[tex]_{2}[/tex] = 53.84°

The formula used above is one of trigonometric ratios. Trigonometric ratios can used only in a right angled triangle where one of the angles in at 90 degrees and the other two angles are less than 90 degrees.

Therefore, the angle of the ladder inclined with respect to the horizontal after being moved is 53.84°

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We can see that the speed of the car is obtained as 12 miles per hour.

The term speed is the ratio of the distance covered to the time taken. We can see that the distance that have been covered by the boy is  24 miles. The total time that have been taken to cover this distance is 30 mins or 0.5 hours.

We now come up with the following;

Distance = 24 miles

time =  0.5 hours

We now want to compute the speed of the boy in miles per hours so we have;

Speed = 24 miles /  0.5 hours = 12 miles per hour

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The location of the baby cub with respect to the cliff would be 6.11 meters.

It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.

As given in the problem A bear throws a salmon at 2 m/s horizontally off a 15-meter high cliff in order to feed its baby cub on the ground.

Let us first calculate the time to fall down on the ground,

s = ut + 0.5at²

15 = 0 + 0.5×9.81×t²

   =3.058 second

The location of the baby cub with respect to the cliff = 2×3.058 second

                                                                                       =6.11 meters

Thus, the location of the baby cub with respect to the cliff would be 6.11 meters.

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The average velocity for completing three rounds of the basketball court would be zero as initial and final position would be zero and the average speed would be 3.28 m/s.

Average velocity is defined as the total displacement divided by the total time take to compete the total displacement.

Average speed is defined as the total distance divided by the total time take to compete the total distance.

Given:

Side of the baseball court = 100 meter

Total time taken to complete three rounds of the basketball court = 375 seconds

Total distance traveled by the player can be measured using the given side of the basketball court.

First we will find the parameter of the court,

Parameter of the court = 4 times the side of basketball court

Parameter of the basketball court = 4 × 100

Parameter of the basketball court = 400 metre

The player goes for 3 rounds of the basketball court which makes the total distance three times the parameter of the basketball court.

Total distance traveled by the basketball player = 3 × 400

Total distance traveled by the basketball player = 1200 metre

Average velocity is displacement divided by time taken.

Total displacement = 0 metre

As the player reaches the same position from where he started so the total displacement is zero.

Therefore, average velocity = 0/365

average velocity = 0 m/s

Average speed = 1200/365

Average speed = 3.28 m/s

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The maximum height reached by the model rocket is 300.5 metre. (b) Time to reach maximum height is 8.5 seconds and (c) the time for which the model rocket was in air is 17.3 seconds.

Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it.

Given:

Initial velocity of the model rocket = 50m/s

Constant acceleration of rocket = 2 u

Height to which acceleration was in account= 150m

First we need to find the final velocity at 150 metres.

We can do so simply by using Newton's third law of motion,

Velocity at 150 metre = under root (2500 + 600)

Velocity at 150 meter = 55.7

Maximum height height reached by the model rocket can be find using the equation for max height.

.i.e. maximum height = u × u/2g + initial distance traveled

maximum height = 55.7×55.7/19.6 + 150

maximum height = 156.5 + 150

Maximum height= 300.5 m

Time taken to reach maximum height = time taken before acceleration stops + time after which acceleration stops

Time taken to reach maximum height = 5.7/2 + 55.7/9.8

Time taken to reach maximum height = 2.85 + 5.7

Time taken to reach maximum height = 8.5 seconds

The rocket will be air for the time = time to reach maximum height + time to fall to the ground

The rocket will be air for the time = 8.5+ 7.8

The rocket will be air for the time = 17.3 seconds.

Therefore, the maximum height reached by the model rocket is 300.5 meter, time to reach maximum height is 8.5 seconds and the time for which the model rocket was in air is 17.3 seconds.

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The force used to lift the huge rocket off the ground is 148,886,500 N.

The force used to lift the huge rocket off the ground is calculated as follows;

F = ma

where;

a = 5g

F = m(5g)

F = ( 3,038,500 kg) x (5 x 9.8 m/s²)

F = 148,886,500 N

Thus, the force used to lift the huge rocket off the ground is 148,886,500 N.

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The symptoms include chest pain and difficulty to breath; signs are heart/respiratory rate and lung assessment, diagnosis > CAD (treatable disease); chronic condition; etiology > plaque buildup.

Coronary artery disease (CAD) is a disease caused by the plaque buildup in artery heart walls. This disease is mainly due to a sedentary lifestyle and inadequate nutritional habits such as for example, excessive consumption of saturated fats.

In conclusion, the symptoms of Ken include chest pain and difficulty to breath; signs are heart/respiratory rate and lung assessment, diagnosis > coronary artery disease (treatable disease); chronic condition, etiology > plaque buildup in the walls of the arteries.

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The acceleration of driver with given values is - 1.771 m/s².

To know acceleration used formula is the rate of change of the velocity of an object with respect to time that is,

a = dv / dt

Where,

dv is the small change in velocity

dt  is change in time of an object

Given,

The distance traveled by the driver is +2170 m

The time taken by the driver is 35. 0 s

The initial velocity of driver is + 62.0 m/s

Therefore , to get the acceleration of the driver with the equation of motion

v = u + at

Here v is the final velocity which is taken zero

Then by putting the values in the above equation,

0 = (+62. o m/s) + (a) 35.0s

a = -  (+62. o m/s) / ( 35.0s)

a = - 1.771 m/s²

The negative sign of acceleration shows that, the driver is slowing then acceleration is in the opposite as the velocity.

So, the acceleration

a = -1.771 m/s².

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The force between them when they are separated instead by 12 cm is 5 N.

The force between them when charge A is doubled is 40 N.

The force becomes 80 N  if charge B is doubled as well.

The force between two charge is determined from Coulomb's law of electrostatic force.

f = kq²/r²

when the distance, r is double the force reduces by 4;

f = kq²/(2r)²

f =  kq²/4r²

New attractive force when the distance is 12cm, = 20 N/4 = 5 N

f =  k(2q₁)(q₂)/r²

f =  2k(q₁q₂)/r²

New force = 2 x 20 N = 40 N

f =  k(2q₁)(2q₂)/r²

f =  4k(q₁q₂)/r²

New force = 4 x 20 N = 80 N

Thus, the force between them when they are separated instead by 12 cm is 5 N.

The force between them when charge A is doubled is 40 N.

The force becomes 80 N  if charge B is doubled as well.

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The horizontal distance is 82.455m and vertical distance is 19.734m

Let us first find the x and y components of velocity

The velocity is given to be 41m/s

the angle of projectile is given to be 29 degree

The x component of velocity = Vx =v cosα =41 x 0.8746 =35.85 m/s

The y component of velocity= Vy= v sinα=41 x 0.484 =19.85 m/s

The horizontal displacement x= Vxt = 35.85 x 2.3 =82.455 m

To solve for vertical distance y = Vyt+1.2at^2

y = 19.85 x 2.3 + 1/2 x -9.8 m/s^2 x 2.3

  = 19.734m

Hence, the horizontal distance is 82.455m and vertical distance is 19.734m

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45º angle will result in the trebuchet’s furthest thrown projectile.

It is acceptable to infer from the results shown in the demonstration on Interactive Physics that as the weight of a counterweight on a trebuchet rises, so too should the projectile's range. Except for the fact that the distance did not rise linearly but rather more quadratically, the results support the theory. The results showed that the distance rose as the weight of the trebuchet's counterweight was increased in steps of 5 kilograms, starting at 20 kilograms and ending at 200 kilograms.

Each time, the projectiles were launched from the trebuchet at a 45-degree angle, and their distances typically followed the equation -8.1551E-4x2 +.304388x + 8.12756 (where x is the mass of the counterweight). The graph was thought to be more quadratic than linear because gravity has more time to work against the projectile and pull it down to the earth the longer it is in the air. Therefore, as additional mass is applied and the projectile is in the air for a longer period of time, the projectile distances would not grow as quickly. These findings back up Newton's Third Law of Motion as well as earlier, historical investigations.

Thus, Thomas should launch the trebuchet at a 45º angle to get the farthest thrown projectile.

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A Vector is a quantity which has both magnitude as well as direction.

vectors follow parallelogram law of addition and uses cosine of the angle between the vectors.

The addition of two vectors, i.e. c, is given by the formula

c=[tex]\sqrt{a^2+b^2+2abcos\alpha }[/tex]

where [tex]\alpha[/tex] is the angle between the vectors

now we know that maximum value of cos[tex]\alpha[/tex] can be is 1

and minimum value of cos [tex]\alpha[/tex] can be-1

now the maximum value cos[tex]\alpha[/tex] is 1 at the angle of π/2

and the minimum value of cosα is -1 is at the angle of -π

Therefore, A and B should have 0 degree between them and in the same direction to have the maximum value

there fore they should be in same direction and 0 degree meaning they should be on same line

A and B will have minimum value when the angle is 180 degree which means they should be on same line and be inn opposite direction to each other.

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The acceleration, in m/s² , that riders experience is 50.3 m/s²

Since the riders move in a circle, they undergo circular motion and will have a centripetal acceleration.

So, the centripetal acceleration, is given by a = v²/r where

Given that a rider in one swing is moving at 34 m/s with respect to the ground in a 46- m -diameter circle. We have that

So, substituting the values of the variables into the equation for the acceleration, we have

a = v²/r

a = (34 m/s)²/23 m

a = 1156 m²/s²/23 m

a = 50.26 m/s²

a ≅ 50.3 m/s²

So, the acceleration, in m/s² , that riders experience is 50.3 m/s²

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