HELP ASAP PLS ILL MARK YOU BRAINLIEST

Answer:

Step-by-step explanation:

Let's rearrange the equation (for my benefit):

y-3 = -(x + 6)

y = -x -6 + 3

y = -x -3

This is an equation of a straight line with slope of -1 and a y-intercept of -3 (y is -3 when x = 0).

See the attached graph.

Answer:

     [tex]\frac{15*7^{x} }{7^{x} +9}[/tex]

Step-by-step explanation:

→ Substitute f(x) into g(x)

     [tex]\frac{15*7^{x} }{7^{x} +9}[/tex]

[tex]\huge\textbf{Hey there!}[/tex]

[tex]\mathsf{ASSUMING: }\\\mathsf{22\times90}\\\mathsf{= 90 \times 22}\\\mathsf{= 1,980}[/tex]

[tex]\mathsf{ASSUMING: }\\\mathsf{2 + 2 + 3 + 3 + 3 + 3}\\\mathsf{= 2\times 2 + 3\times4}\\\mathsf{= 4 + 12}\\\mathsf{= 16}[/tex]

[tex]\huge\textsf{Answer \#1. 1,980 }\huge\checkmark\\\\\\\huge\textsf{Answer \#2. 16 }\huge\checkmark[/tex]

[tex]\huge\textbf{Good luck on your assignment \& enjoy}\\\huge\textbf{your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

This answer assumes that the first equation is meant to read:

2x + y +3z = 12, and not

1.22x+y+3:= 12

Spoiler Alert:  x = 1, y=4, and z=2

Step-by-step explanation:

1.    2x + y +3z = 12

2.     x - 2y + z = -5

3.    5x - y+ 2z = 5

==============

Use equations 2 and 3 to eliminate z:

2.  x - 2y + z= -5

3.  5x - y+ 2z = 5

-2(x - 2y + z) = -2(-5)   [Multiply equation 2 by -2]

             5x -   y+  2z =  5

Now subtract this new equation from equation 3:

-2x + 4y - 2z = 10  (Eq 3)

 5x -   y+  2z =  5   [

 3x +3y = 15   [Equation A]

=================

Use equations 1 and 2 to eliminate z:

   2x +  y +3z = 12   (Eq. 1)

      x - 2y +  z = -5   (Eq. 2)

   2x +  y +3z = 12

(-3)(x - 2y +  z = -5)  [Multiply Eq. 2 by (-3)]

    -3x + 6y -3z = 15

Now add the resulting two equations.

   2x +   y + 3z = 12     (Eq. 1)

  -3x + 6y -3z =  15       (Eq,2 times -3)

   -x   +7y         = 27    [Equation B]

=============

  Eliminate x with the 2 resulting equations (from above)

  3x +3y = 15  [Equation A]

   -x +7y = 27  [Equation B]

----

   3x +3y = 15

   3*(-x +7y = 27)  [Multiply the Equation B by 3]

  -3x +21y = 81     [Aha - this equation has a -3x term, exactly what we need to eliminate the x term in Equation A]

---

Now add the two resulting equations:

    3x +3y = 15

   -3x +21y = 81

            24y = 96  [The x term disappears.  But we'll "find x" later]

                 y = 4   [Divide both sides by 24]

Find y and z:

Since y = 4,

-x  +7y   = 27 (From above, Equation B]

-x = -7y + 27

 x = 7y - 27

x = 7(4)-27

 x = 1                  [Looking good]

=====

Find z:  (Use y = 4 and x = 1)

x - 2y + z = -5  [Equation 2]

(1) -2*(4) + z = -5

1 - 8 + z = -5

z = 2

Check:

Do the original equations work when x = 1, y = 4, and z = 2?

Results:  

1.    2x + y +3z = 12      

     (1) + (4) +3(2)    YES, this equals 12

2.     x - 2y + z = -5  

       (1)  -2*(4) + (2)   YES, this equals -5

3.    5x - y+ 2z = 5

       5(1) - (4) + 2(2)   YES, this equals 5

x = 1, y=4, and z=2

Step-by-step explanation:

please mark me as brainlest

Answer:

slope = 2

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - [tex]\frac{1}{2}[/tex] x + 5 ← is in slope- intercept form

with slope m = - [tex]\frac{1}{2}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{2} }[/tex] = 2

Answer:

F(x) = - [tex]\sqrt[3]{x}[/tex]  

Step-by-step explanation:

A square root can only have a positive input for the domain

(The domain is the input for the function)

The cube root can be either negative or positive as an input

F(x) = - [tex]\sqrt[3]{x}[/tex]  can have inputs from negative infinity to infinity

Answer:

5m-3

Step-by-step explanation:

Answer:

5m-3

Step-by-step explanation:

Answer:

[tex]0.07[/tex]

Step-by-step explanation:

FORMULA :

[tex]p\left( A|B\right) =\frac{p\left( A\cap B\right) }{p\left( B\right) }[/tex]

……………………………

then

[tex]p\left( \text{drive to school} |sophomore\right) =\frac{p\left( \text{drive to school} \cap \text{sophomore} \right) }{p\left( \text{sophomore} \right) }[/tex]

                                [tex]= \frac{2}{2+25+3}[/tex]

                                [tex]=\frac{2}{30}[/tex]

                                [tex]=\frac{1}{15}[/tex]

                                [tex]=0.066666666667[/tex]

Answer:

y = 5x - 6

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = 5 and c = - 6 , then

y = 5x - 6 ← equation of line

The equation represents a linear function with a slope of 5 and a y-intercept of -6 is y = 5x - 6.

The equation of a linear function is typically written in the form "y = mx + b," where "m" represents the slope and "b" represents the y-intercept.

Given that the slope is 5 and the y-intercept is -6, the equation becomes:

y = 5x - 6

Here's the calculation:

The slope (m) is 5, and the y-intercept (b) is -6. Therefore, the equation becomes:

y = 5x - 6

This equation represents a linear function with a slope of 5 and a y-intercept of -6.

Hence the equation represents a linear function with a slope of 5 and a y-intercept of -6 is y = 5x - 6.

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From the power rules, the matching of  each expression with its result is:

[tex](8.6*10^7)(9.1*10^{-8})=7.8[/tex]

[tex](6.9*10^5)(4.8*10^{-3})=3.3*10^3[/tex]

[tex]\frac{(3.7*10^2)*(4.6*10^{-3})}{(1.4*10^{-6})*(5.7*10^{8})} =2.1*10^{-3}[/tex]

[tex]\frac{(3.1*10^5)*(5.3*10^{-9})}{(7.3*10^{2})*(6.1*10^{-7})}=3.7[/tex]

There are different power rules, see some them:

1. Multiplication with the same base: you should repeat the base and  add the exponents.

2. Division with the same base: you should repeat the base and  subctract the exponents.

3.Power. For this rule, you should repeat the base and multiply the exponents.

4. Zero Exponent. When you have an exponent equals to zero, the result must be 1.

From this for your question, you have:

[tex]\frac{(3.7*10^2)*(4.6*10^{-3})}{(1.4*10^{-6})*(5.7*10^{8})} =\frac{(3.7*4.6)*(10^2*10^{-3})}{(1.4*5.7)*(10^{-6}*10^{8})} =\frac{17.02*10^{-1}}{7.98*10^2} =2.13*10^{-3}=2.1*10^{-3}[/tex]

[tex]\frac{(3.1*10^5)*(5.3*10^{-9})}{(7.3*10^{2})*(6.1*10^{-7})}=\frac{(3.1*5.3)*(10^{5}*10^{-9})}{(7.3*6.1)*(10^{2}*10^{-7})} =\frac{16.43*10^{-4}}{44.53*10^{-5}}=0.36896*10^1=3.7[/tex]

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The equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]

Which expression is equivalent to [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

The expression is given as:

[tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex]

Apply the exponent law of indices

[tex](\frac{x^{-9}y^5}{x^{-4}y})^{2}[/tex]

Next, we apply the common base law of indices

[tex](x^{4 -9}y^{5-1})^2[/tex]

Evaluate the difference

[tex](x^{-5}y^4)^2[/tex]

Remove bracket

[tex]x^{-10}y^8[/tex]

Hence, the equivalent expression of [tex](\frac{x^{-4}y}{x^{-9}y^5})^{-2}[/tex] is [tex]x^{-10}y^8[/tex]

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Answer:

y^8/x^10

Step-by-step explanation:

The guy above me is right but just forgot to distribute the negative out of x. :)

[tex] \sf{\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve for x and z ~

[tex]\qquad \sf  \dashrightarrow \: z + 68 = 180[/tex]

[ they form co - exterior angle pair ]

[tex]\qquad \sf  \dashrightarrow \: z = 180 - 68[/tex]

[tex]\qquad \sf  \dashrightarrow \: z = 112 \degree[/tex]

now, it's time for x :

First angle z is equal to its vertical opposite angle, and then that angle forms co - interior angle pair with (3x - 28)

[tex]\qquad \sf  \dashrightarrow \: 3x - 28 + 112 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3x + 84 = 180[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3x = 180 - 84[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3x = 96[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 96 \div 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 32 \degree[/tex]

That's all... let me know if you have questions ~

Answer:

Question 4: letter c

Question 3: letter c

Step-by-step explanation:

The vertex-form of the quadratic equation is given by y = (x + 4)² - 13, and the minimum value of y is of -13.

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient. If a > 0, k is the minimum value of y, and if a < 0, it is the maximum value.

In this problem, the equation is:

y = x² + 8x + 3.

Completing the squares, the function is:

y = (x + 4)² - 13

13 is subtracted as (x + 4)² = x² + 8x + 16, hence for the equations to be equal 13 has to be subtracted. k = -13 is also the minimum value of y.

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The minimum y-value of the function for the parabolic equation is -13.

The vertex for an up-down facing parabola of the form y = ax² + bx + c is [tex]\mathbf{x_v= -\dfrac{b}{2a}}[/tex]

From the given equation:

y = x² + 8x + 3

The parameters for the parabola are:

a = 1, b = 8, c = 3

[tex]\mathbf{x_v= -\dfrac{8}{2\times 1}}[/tex]

[tex]\mathbf{x_v= -4}[/tex]

If we replace the value of [tex]\mathbf{x_v= -4}[/tex] to find the minimum value of [tex]\mathbf{y_v}[/tex] value, we have:

[tex]\mathbf{y_v = -13}[/tex]

Thus, the parabola vertex is (-4,-13). If a< 0, the vertex is a maximum value and If a>0, the vertex is a minimum value.

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Answer:

Laurel has to cover this area with 2.64 ounces of seeds.

Step-by-step explanation:

Given

Base of Parallelogram = 30ft

Height of Parallelogram = 22ft

Area of Parallelogram = 1/2*base*height

Therefore, Area of Parallelogram =  1/2*30*22

                                                        = 330sq. ft

Given

One ounce of seed covers 125 sq. ft

Hence, No. of ounces needed to cover 330 sq. ft= 330/125

                                                                                  = 2.64

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Answer:

the answer is $62

Step-by-step explanation:

if you subtract 110 by 98 you get 12 and the same for the rest so if you subtract 74 by 12 you get 62

Hope that help :)

Answer:

62

Step-by-step explanation:

Answer:

A. y = 3x + 1

Explanation:

Find slope:

[tex]\sf slope: \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

Take two points: (0, 1), (1, 4)

[tex]\sf \rightarrow slope \ (m) : \dfrac{4-1}{1- 0 } = 3[/tex]

Equation:

[tex]\sf y - y_1 = m(x - x_1)[/tex]

[tex]\sf y - 1 = 3(x - 0)[/tex]

[tex]\sf y = 3x + 1[/tex]

The area is given by f(x) = 10x² + 31x + 15.

The function is a rectangle's area function. We know that a rectangle is a flat, four-sided shape with straight sides and right-angled interior angles. Additionally, the opposing sides are parallel and of the same length.

Rectangle Area = Length * Width

The length of fabric scrap is 5x. So, the rectangular patchwork's length will be 5x + 3.

Since the width of the fabric scrap will be 2x, the rectangular patchwork's width will be 2x + 5.

Then area = f(x) = (5x + 3)(2x + 5) = 10x² + 25x + 6x + 15 = 10x² + 31x + 15

Therefore the area is given by f(x) = 10x² + 31x + 15.

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Answer:

Step-by-step explanation:

-19 : 14 = x : 2

x = 19 * 2 : -14

x = 38 : -14

x = -19/7

The plot represent the data A box plot titled Scores of Participants and labeled Scores uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35.

The box extends from 17 to 24 on the number line.

A line in the box is at 23 The whiskers end at 12 and 28.

A box plot is a graphical rendition of statistical data based on the minimum, first quartile, median, third quartile, and maximum.

Given:

12 points

21 points

29 points

17 points

24 points

23 points

28 points

According to the given data,

A box plot titled Scores of Participants and labeled Scores uses a number line from 10 to 35 with primary markings and labels at 10, 15, 20, 25, 30, and 35.

The box extends from 17 to 24 on the number line.

A line in the box is at 23 The whiskers end at 12 and 28.

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To calculate the area that Marcus needs to paint we must calculate the area of the window and subtract it from the total area of the wall.

To calculate the area of a rectangular wall we must use the following formula:

Where a is the length of the height, and b is the length of the width.

Next, we need to calculate the area of the window. If it is a square or rectangular window we use the same formula "area = a × b".

If the window is circular we use this formula:

Once we know the area of the wall and the area of the window, we subtract the area of the window from the area of the wall and we will know what is the total area that Marcus must paint.

Note: This question is incomplete because some information is missing. However I can answer it based on my general prior knowledge.

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The ordered pair that represents a function is {(0,0),(1,10),(10,4),(-1,-7)}.

A set of ordered pairs that defines a function will be the one that has exactly one y-value that assigned to every x-value. This means that none of its x-values can have two corresponding y-values.

All the sets of ordered pairs don't have exactly one y-value that corresponds to each of its x-value except {(0,0),(1,10),(10,4),(-1,-7)}.

Thus, we can say that the ordered pair that represents a function is {(0,0),(1,10),(10,4),(-1,-7)}.

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Answer:

A

Step-by-step explanation:

Angles 1 and 3 are congruent since they are vertical angles.

Angle 7 is congruent to angle 3 since they are corresponding angles.

Angle 5 is congruent to angle 1 since they are corresponding angles.

Answer: A

Answer:

I think it's 1.17 - -3.85

The answer choice which explains whether the function is a direct variation or not is; This function represents a direct variation because it passes through the origin and has a constant rate of change of $5 per hour.

It follows from the task content that the function passes through the origin and hence, if the function was represents as a linear function, it's y-intercept would be zero.

Furthermore, the slope, otherwise termed it's rate of chage is constant and is evaluated as; $5 per hour. Hence, the aforementioned form the basis for the classification of the function as a direct variation.

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The value of the variable x = 6 and y = 5. Then the position vector of P will be 6i + 5j.

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

PQRS is a parallelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j.

Then the point of Q, R, and S will be (5, 7), (-3, -8), and (-4, -6).

Let the point P be (x, y).

We know that the slope of the line QS and PQ will be same and line is passing through (-3, -8).

y = 1.444x + C

-8 = 1.444 (-3) + C

C = -3.667

Then the equation will be

y = 1.444x – 3.667  …1

The slope of the line PQ and RS will be same and line is passing through (5, 7).

y = -2x + D

7 = -2 (5) + D

D = 17

Then the equation will be

y = -2x + 17  …2

By solving equation 1 and 2, we have

x = 6 and y = 5

Then the position vector of P will be

⇒ 6i + 5j

The graph is given below.

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The area of the surface of the pool is 7322.64 m².

The area of rectangle is product of length and its breadth.

i.e., length * breadth

Given: Length = 100 m, Width = 52 m and Diameter = 52 m

Area of rectangle,

= 100 × 52

= 5200 m²

Now,

Area of semicircle = 1/2 × πr²

=1/2 × 3.14 × 26²

= 1061.32 m²

Hence, area of the surface of the pool is

= 1061.32 + 1061.32 + 5200

= 7322.64 m²

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5200 square meters, 1061, 7322