10 points
All of the following are some things that can decrease the rise in global
temperatures EXCEPT:
using more solar energy
using more fossil fuels
using more biofuels
going Vegan
Answer: Using more fossil fuels
Explanation: Burning fossil fuels releases Green House gasses into the atmosphere, such as carbon dioxide. The carbon dioxide in the atmosphere traps in heat, which causes global temperatures to increase.
5. A car has a gasoline tank with a capacity of 18.0 gallons. How many liters is this equal to? (- 2.1134 pints, gallon = 4 quarts , 1 quart = 2 pints)
Answer:
16.14 liter
Explanation:
The tank capacity of a car is a measure of the amount of gallons or liters of liquid a tank (of any shape e.g. rectangular, cylindrical) can hold at maximum due to its volume. The S.I unit of the tank capacity is the m³, but it can be measured in liters, gallons and any other unit of volume.
We need to convert the volume from gallons to liters
1 gallon = 3.78541 liters
18 gallon = [tex]18\ gallon*\frac{3.78541\ liter}{1\ gallon} =16.14\ liter[/tex]
how many grams in 6.20 x 10^25 atoms of bromine (Br) ? image attached , will give brainliest
Answer:
8239.2g
Explanation:
Given parameters:
Number of atoms in Br = 6.2 x 10²⁵atoms
Unknown:
Mass of Br = ?
Solution:
From mole concepts, we know that:
1 mole of a substance contains 6.02 x 10²³ atoms/mol
Molar mass of Br = 80g/mol
6.2 x 10²⁵atoms x [tex]\frac{1}{6.02 x 10^{23} }[/tex] [tex]\frac{mol}{atoms}[/tex] x 80 x [tex]\frac{g}{moles}[/tex]
= 8239.2g
how to solve stoichiometry problem in a synthesis reaction with iron metal and oxygen gas, what mass of iron metsl is required to produce 456.0g of ferric oxide?
Answer:
319.2 g of iron metal
Explanation:
We'll begin by writing the balanced equation for the reaction between iron (Fe) and oxygen (O₂) to produce ferric oxide (Fe₂O₃). This is illustrated below:
4Fe + 3O₂ —> 2Fe₂O₃
Next, we shall determine the mass of Fe that reacted and the mass of Fe₂O₃ produced from the balanced equation. This can be obtained as follow:
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 4 × 56 = 224 g
Molar mass of Fe₂O₃ = (56×2) + (16×3)
= 112 + 48
= 160 g/mol
Mass of Fe₂O₃ from the balanced equation = 2 × 160 = 320 g
SUMMARY:
From the balanced equation above,
224 g of Fe reacted to produce 320 g of Fe₂O₃.
Finally, we shall determine the mass of iron metal, Fe, required to produce 456 g of ferric oxide, Fe₂O₃. This can be obtained as follow:
From the balanced equation above,
224 g of Fe reacted to produce 320 g of Fe₂O₃.
Therefore, Xg of Fe will react to produce 456 g of Fe₂O₃ i.e
Xg of Fe = (224 × 456)/320
Xg of Fe = 319.2 g
Thus, 319.2 g of iron metal, Fe is required to produce 456 g of ferric oxide, Fe₂O₃.
Which element is represented by the following:
1s22s22p63s23p64s23d104p1?
Write the symbol.
Answer:
Gallium (Ga)
Explanation:
Gallium (Ga) is the element which is represented by the given electron configuration since the total number electron is 31.
A material that cannot be destroyed chemically is referred to as a chemical element. Although chemical processes cannot modify an atom, nuclear reactions can create new elements. The quantity of protons an element has defines it. An element's atoms all contain the same amount of protons, but its electron and neutron counts might vary. Ions are produced by altering the electron to proton ratio, whereas isotopes are produced by altering the neutron count. Since there are 31 total electrons in the universe, gallium (Ga) gets the element that is denoted by the specified electron configuration.
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1. Genes are the basic unit capable of transmitting characteristics from one point
generation to the next.
Indicate which categories apply to nitrogen.
Check all that apply.
metal
nonmetal
transition element
main group element
noble gas
A room that is 500 cm x 400 cm x 250 cm contains 65 kg of air. Determine the volume of air in the room and its density.
Answer:
1.3g/L is the density of the air
Explanation:
The room is full of air, the space that the air occupy is:
500 cm x 400 cm x 250 cm = 5.00x10⁷ cm³
The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of air in g/L:
Grams air:
65 kg * (1000g / 1kg) = 65000g
Liters:
5.00x10⁷ cm³ * (1L / 1000cm³) = 50000L
Density:
65000g / 50000L =
1.3g/L is the density of the airWhat is the part of the cartridge that actually flies outward (the projectile)?
Answer:
the culotte, the fulminant capsule and the sheath or cap together with remains of powder
Explanation:
A bullet has a nose, sheath or casing, a short propellant charge, and a capsule.
All these components are part of the vouchers. The classification of these is in metallic and semi-metallic.
The cartridge can be given as the combination of the bullet, case, propellant, and primer. The bullet is the part that moves outwards in a projectile.
What is the projectile motion?The projectile motion can be given as the expulsion of the object from the external force, and the movement governed by the gravity and downward force.
The cartridge is the combination of the bullet, case, propellant and the primer.
The bullet is the projectile, the case functions in holding the cartridge parts together, propellant provides the energy for the launch of the projectile, and the primer functions in igniting the propellant.
The force exerted leads to the flushing of bullet in the projectile motile.
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Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to effuse through a tiny hole at 0.28 times the rate of effusion of Ar atoms under the same conditions of temperature and pressure. What is the molecular formula of arsenic(III) sulfide in the gas phase?
The molecular formula : As₄S₆
Further explanationGiven
Rate of effusion of arsenic(III) sulfide = 0.28 times the rate of effusion of Ar atoms
Required
The molecular formula
Solution
Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
[tex]\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }[/tex]
or
[tex]\rm M_1\times r_1^2=M_2\times r_2^2[/tex]
Input the value :
1 = Arsenic(III) sulfide
2 = Ar
MM Ar = 40 g/mol
0.28 = √(40/M₁)
M₁=40 : 0.28²
M₁=510 g/mol
The empirical formula of arsenic(III) sulfide = As₂S₃
(Empirical formula)n = molecular formula
( As₂S₃)n = 510 g/mol
(246.02 g/mol)n = 510 g/mol
n = 2
So the molecular formula : As₄S₆
BRAINLIEST?
1. Scientists have evidence that the universe is [expanding/shrinking].
2.Objects moving away from Earth appear [blue/red], and objects moving toward Earth appear [blue/red].
3. Light from most other galaxies appears [blue/red], which makes sense if the universe is [collapsing inward/spreading out].
write three characteristics of mandleef's periodic table?
Answer:
The periodic table is composed of seven horizontal rows or periods and is numbered between 1 and 7. There is a regular gradation in the properties of elements in the horizontal rows(periods) from left to right. The periodic table is composed of eight vertical columns or groups. They are numbered between 1 to 8.
Explanation:
Rearrange this expression into quadratic form, 2++=0 , and identify the values of , , and . 0.20=^2/65−
Explanation:
0.20 equal to 2/65
2/65-0.20
-0.1692
HELP ASAP ILL MARK BRAINLIEST
Step 1: H2(g) + → ICI(9) HI(g) + HCl(g) (slow)
Step 2: HI(g) +ICI(g) → + HCl(g) + I2 (g) (fast)
The reaction is carried out at constant temperature inside a rigid container. Based on this mechanism, which of the following is the most likely reason for the different rates of step 1 and step 2?
a. The only factor determining the rate of step 2 is the orientation of the HI and ICl polar molecules during a collision, but it has a negligible effect when H, and ICl molecules collide.
b. The amount of energy required for a successful collision between H, and ICl is greater than the amount of energy required for a successful collision between HI and ICI.
c. The fraction of molecules with enough energy to overcome the activation energy barrier is lower for HI and ICl than for H2, and ICI.
d. The frequency of collisions between H2, and ICl is greater than the frequency of collisions between HI and ICI.
Answer:
B
Explanation:
Step 1 occurs at a slower rate than Step 2.
The fraction of molecules with enough energy to overcome the activation energy barrier is lower for HI and ICl than for H2, and ICI.
We must bear in mind that the rate determining step in a reaction is the slowest step in the chemical reaction. As such, we can clearly see that step 1 is the rate determining step in the reaction.
The fast reaction must have a minimum energy barrier between the reactants and the products. Hence, the fraction of molecules with enough energy to overcome the activation energy barrier is lower for HI and ICl than for H2, and ICI.
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Consider a gaseous mixture consisting of 5 kmol of H2 and 3 kmol of O2. Determine the H2 and O2 mole fractions, the molecular weight of the mixture, and the H2 and O2 mass fractions
Answer:
Mole fraction H2: 0.625
Mole fraction O2: 0.375
Molecular weight: 13.25g/mol
Mass fraction H2: 0.094
Mass fraction O2: 0.906
Explanation:
Moles fraction is defined as the ratio between moles of a substance and total moles presents in a mixture:
Mole fraction H2 = 5kmol / (5kmol + 3kmol) = 0.625
Mole fraction O2 = 3kmol / (5kmol + 3kmol) = 0.375
Molecular weight is defined as the mass per mole of substance:
Mass H2 = 5kmol * (2kg / kmol) = 10kg
Mass O2 = 3kmol * (32kg / kmol) = 96kg
Molecular weight:
106kg / 8kmol = 13.25g/mol
In the same way, mass fraction is the ratio between mass of a substance and total mass of the mixture:
Mass fraction H2 = 10kg / (10kg + 96kg) = 0.094
Mass fraction O2 = 96kg / (10kg + 96kg) = 0.906
What happens to frequency as wavelength
decreases across the electromagnetic
spectrum?
A. Frequency increases.
B. Frequency decreases.
C. Frequency stays the same.
D. Frequency and wavelength are not
related.
Answer:
B. Frequency decreases
What does the law of the conservation of momentum state?
Answer:
The conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion. ... Momentum is conserved in all three physical directions at the same time.
What happened to the missing neutron?
•it will turn into a proton and an electron
•it became gamma radiation
•it got absorbed by the electrons
Answer:
it became gamma radiation, it will turn into a proton and an electron
Explanation:
What is the edge length of a 369-g iron cube?(The density of iron is 7.86 g/cm3, and the volume of a cube is equal to the edge length cubed.)
Answer:
edge length = 3.61 cm
Explanation:
Givens
m = 369 gm
d = 7.86 gm / cm^3
v = ?
Formula
v = m / d
Solution
v = 369 / 7.86
v = 46.95 cm^3
============
That's not the answer. You must take the cube root of the volume
side = cube root (46.95)
side = 3.61 cm
The Edge length of the iron cube will be "3.61 cm".
Given values,
Weight of iron cube,
m = 369 g
Density of iron,
d = 7.86 g/cm³
The volume of iron cube will be:
→ [tex]V = \frac{m}{d}[/tex]
[tex]= \frac{369}{7.86}[/tex]
[tex]= 46.95 \ cm^3[/tex]
As we know that the volume of cube is "[tex]a^3 \ cm^3[/tex]".
hence,
→ [tex]a^3 = 46.95 \ cm^3[/tex]
or,
→ [tex]a = (46.95 \ cm^3)^{\frac{1}{3} }[/tex]
[tex]= 3.61 \ cm[/tex]
Thus the above answer is correct.
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can y’all please help me
How are protons and neutrons similar? How are they different?
18. Predict the products for this single replacement reaction.
Cuso, + ALS
AL(S03)2 + Cu
Al(S0.)2 + Cu
O Al(SO.), + Cu
NR
19. Predict the products for this double replacement reaction.
Baci, + H,PO->?
BaPO4 + HCI
BaPO. + HCl
Ba(POJZ + HCI
Ba,(PO.)2 + HCI
PLEASE HELP ITS FOR A TEST I WOULD APPRECIATE IT !!
Answer:
3rd response
4th response
Explanation:
i lowkey feel like im doing this whole chem exam for u lol. good luck anyway! u rock!
When sound waves move through a medium, in what direction to do the particles in the medium move?
A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the final volume of the solution is 508 mL. Group of answer choices
Answer:
[tex]x_{suc}=0.00406[/tex]
Explanation:
Hello!
In this case, since the mole fraction relates the moles of solute and the moles of solution, and for sucrose it is:
[tex]x_{suc}=\frac{n_{suc}}{n_{suc}+n_{water}}[/tex]
Whereas we need to compute the moles of both sucrose and water based on their molar masses (342.3 and 18.02 respectively) as shown below:
[tex]n_{suc}}=\frac{38.6g}{342.3g/mol}=0.113mol\\\\ n_{water}}=\frac{495g}{18.02g/mol}=27.5mol\\[/tex]
Thus, the mole fraction sucrose turns out:
[tex]x_{suc}=\frac{0.112}{0.112+27.5}\\\\x_{suc}=0.00406[/tex]
Best regards!
A pair of students standard a sodium hydroxide solution using KHP and obtain the following concentrations: 0.1028 M, 0.1031 M, 0.1200 M, 0.1030 M and 0.1026 M. The students suspect that 0.1200 M is an outlier. Is 0.1200 M an outlier and what is the average concentration of the sodium hydroxide solution
Answer:
0.1200M is an outlier.
Average = 0.1063M
Explanation:
An outlier is defined as a value that is atypical based on the other observations.
We can define an outlier as a value that is out of the average ± Standard desviation.
The average of the values is:
(0.1028 M + 0.1031 M + 0.1200 M + 0.1030 M + 0.1026 M) / 5
Average = 0.1063MComputing the standard desviation, σ:
σ = 0.0077
The interval of accepted values is between:
0.1063 + 0.0077 = 0.1140M
0.1063 - 0.0077 = 0.0986M
As 0.1200M is out of this intercal, this value is an outlier
The definition of outlier depends of the author and the values you are studying.
I'll give brainiest a person who answers first correctly :) I promise
What is the stored energy of an object called?
Kinetic energy
Mechanical energy
Potential energy
Translational energy
Answer: Potential energy
Explanation:
Chlorhexidine gluconate is available in different products in concentrations of 4% w/v and 0.12% w/v. How many milliliters of the more dilute product may be prepared from each fluidounce of the more concentrated product
Answer:
From each fluidounce, 985.78 milliliters of the more dilute product can be produced.
Explanation:
From the given information:
4% w/v = 4g of solute in 100 mL of solution
0.12% w/v = 0.12g of solute in 100 mL of solution
Since 1 fluidounce = 29.5735 ml
∴
100 mL of solution contains 4g of solute
29.95735 ml will have [tex]\dfrac{4}{100} \times 29.5735[/tex]
= 1.18294g solute
Thus, 1 fluidounce contains 1.18294g solute
So, for the dilute solution, 0.12 g solute yields 100 mL solution
∴ 1.18294g will have [tex]\dfrac{100}{0.12} \times 1.18294[/tex]
= 985.78 ml
Give the product expected when the following alcohol reacts with pyridinium chlorochromate (PCC). (Assume that PCC is present in excess.) The starting material is H O C H 2 C H 2 C H 2 O H. THis reacts with P C C and C H 2 C L 2 to give the product.
Answer:
Explanation:
From the information given, we are to show the product of the reaction between the alcohol (stick formula) with pyridinium chlorochromate. The reaction starts with the nucleophilic addition of Cr with oxygen molecule on the alcohol. Then, deprotonation of oxygen occurs, this process is followed by the removal of hydrogen ion to yield the final product. The reaction mechanism can be seen from the attached image below.
A student mixes baking soda and vinegar in a glass. Do you think any new substances are being created in this mixture? If so, how do you know?
Answer:
A student mixes baking soda and vinegar in a glass. ... Yes I do belive that new substances are being formed because there is a chemical reaction between the baking soda and vinegar turning it into a bubbly substances instead of a powder and liquid.
Explanation:
ANSWER
The evidence here is that when you mix baking soda or baking powder and vinegar, the bubbles you saw were carbon dioxide gas.
A carbon dioxide gas is molecules consist of a carbon atom covalently double bonded to two oxygen atoms. It occurs naturally in Earth's atmosphere as a trace gas.
