The solution of the given equation 5/2x - 2/3 = 1/x + 5/6 is at x = 9/11.
According to the given question.
We have an equation
5/2x -2/3 = 1/x + 5/6
Since, we have to solve the above equation for x.
Thereofore, the solution of the equation 5/2x -2/3 = 1/x + 5/6 is given by
5/2x -2/3 = 1/x + 5/6
⇒ 5/2x -1/x = 5/6 + 2/3
⇒ (5 -2) /2x = 5+ 2(3)/6
⇒ 3/2x = 11/6
⇒6(3) = 11(2x)
⇒ 18 = 22x
⇒ 18/22 = x
⇒ 9/11 = x or x = 9/11
Hence, the solution of the given equation 5/2x - 2/3 = 1/x + 5/6 is at x = 9/11.
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Paulina has completed 24 of 42 problems she was assigned for homework. She plans to finish her homework by completing 9math problems each hour,h write an equation to find the number of hours it will take Paulina to complete her math homework assignment
Answer:
Step-by-step explanation:
42=24+9h
Draw an isospeles right triangle on the coondinate plane so that the midpoint of its hypotenuse is the origin. Label the coordinates of each vertex.
The isosceles right triangle on the coordinate plane so that the midpoint of its hypotenuse is the origin is shown in the picture.
What is a right-angle triangle?It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.
It is given that:
Draw an isosceles right triangle on the coordinate plane so that the midpoint of its hypotenuse is the origin.
The coordinate of the origin is (0, 0)
We can take the coordinate of point A and B as (-1, 1) and (1, -1)
The right angle triangle is shown in the attahced picture.
Thus, the isosceles right triangle on the coordinate plane so that the midpoint of its hypotenuse is the origin is shown in the picture.
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Christine got a prepaid debit card with $20 on it. For her first purchase with the card, she bought some bulk ribbon at a craft store. The price of the ribbon was 9 cents per yard. If after that purchase there was $17.75 left on the card, how many yards of ribbon did Christine buy?
Find the geometric mean between pair of numbers.
14 and 21
To calculate the geometric mean, we take their product instead: 1 x 5 x 10 x 13 x 30 = 19,500 and then calculate the 5-th root of 19,500 = 7.21. This is equivalent to raising 19,500 to the 1/5-th power. Another way to calculate the geometric mean is with logarithms, as it is also the average of logarithmic values converted back to base 10.
Two friends are sharing one half of a pizza that is divided into three pieces, as shown in the figure.
A
B
O
C
D
If mZAOB = (2x - 4) and mZBOD= (14x+12)°, what is the value of x?
Using supplementary angles, it is found that the value of x is of x = 10.75.
What are supplementary angles?Supplementary angles are angles whose measures add to 180º.
An entire pizza is 360º, hence half the pizza is 180º, meaning that angles AOB and BOD are supplementary.
Their measures are given as follows:
m<AOB = 2x - 4.m<BOD = 14x + 12.Since they are supplementary, they add to 180º and we can add their measures and solve for x as follows:
2x - 4 + 14x + 12 = 180
16x = 172
x = 172/16
x = 10.75.
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Find the coordinates of M if N(1.5,2.5) is the midpoint of \overline{M P} and P has coordinates (6,9)
Applying the midpoint formula, the coordinates of point M are: (-3, -4).
How to Apply the Midpoint Formula?The midpoint formula is given as, (x, y) = [(x2 + x1)/2, (y2 + y1)/2].
Given the following:
N(x, y) = (1.5, 2.5)
P(x1, y1) = (6, 9)
M(x2, y2) = (?, ?)
Plug in the values into the midpoint formula
N(1.5, 2.5) = [(x2 + 6)/2, (y2 + 9)/2]
Isolate each coordinate
1.5 = (x2 + 6)/2
2(1.5) = x2 + 6
3 = x2 + 6
3 - 6 = x2
x2 = -3
2.5 = (y2 + 9)/2
5 = y2 + 9
5 - 9 = y2
y2 = -4
Therefore, applying the midpoint formula, the coordinates of point M are: (-3, -4).
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Copy and complete the proof.
Given: C is the midpoint of AE.
C is the midpoint of BD.
AE ≅ BD
Prove: AC ≅ CD
Proof:
Statements Reasons
a. _______ a. Given
b. A C=C E, B C=C D b. _______
c. A E=B D c. _______
d. _______ d. Segment Addition Postulate
e. A C+C E=B C+C D e. _______
f. A C+A C=C D+C D f. _______
g. _______ g. Simplify.
h. _______ h. Division Property
i. AC ≅ CD i. _______
The words that are needed to complete the proof has been added below:
a. AE ≅ BD a. Given
b. A C=C E, B C=C D b. definition of midpoint
c. A E = B D c. definition of congruent segments
d. A C + C E = A E d. Segment Addition Postulate
e. A C + C E = B C + C D e. definition of congruent segments
f. A C + A C = C D + C D f. substitution
g. 2 A C = 2 C D g. Simplify.
h. A C = C D h. Division Property
i. AC ≅ CD i. definition of congruent segments
step I is the required proof
What are congruent segments?This is a term to compare segments that they are have similar properties such as equality in length. For instance using the line asked in the question, line AC is congruent to line CD means that the two lines are equal in length
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Find the slope of the line that passes through (2,1) and (5,6). Simplify your answer and write it as a proper fraction, improper fraction, or integer.
The slope of the line that passes through the given points is equal to 3/5.
Given the following data:
Points on x-axis = (2, 5).
Points on y-axis = (1, 6).
What is a slope?A slope is also referred to as gradient and it's typically used to describe both the ratio, direction and steepness of the function of a straight line.
How to calculate the slope of a line?Mathematically, the slope of any straight line can be calculated by using this formula;
[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]
Substituting the given points into the formula, we have;
Slope = (5 - 2)/6 - 1)
Slope = 3/5
In conclusion, the slope of the line that passes through the given points is equal to 3/5.
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I need help with this problem please and thank you :)
The function f(x) = 3 · (x + 8)² + 4 is the consequence of applying translation and dilation transformations on y = x².
What is the difference between the original function and the transformed function?
In this problem we find a quadratic equation, of which we must infer the series of rigid transformations to be used to obtain a resulting expression. Rigid transformations are transformations applied on functions such that Euclidean distance is not changed. The most used rigid transformations are listed below:
TranslationReflectionRotationDilationContractionAfter comparing the two expressions, we find that this procedure was applied in the following order:
Translation 8 units in the -x direction.Dilation by a factor of 3.Translation 4 units in the +y direction.Finally, we show the procedure to prove this manner:
y = x²
Step 1
y' = (x + 8)²
Step 2
y'' = 3 · (x + 8)²
Step 3
f(x) = 3 · (x + 8)² + 4
The function f(x) = 3 · (x + 8)² + 4 is the consequence of applying translation and dilation transformations on y = x².
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(a³b¹²c²) × (a³c²) × (b³c¹) ⁰ =
12.4
O A. a¹5¹24
○ в. a³b¹¹c³
8
O c. a³b¹²4
OD. a¹4b¹5c9
Answer:
Answer C is correct
Step-by-step explanation:
We know that,
[tex] \sf \: {x}^{a} \times {x}^{b} = {x}^{a + b} \\ \\ \sf \frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b} \: \: \: \: \: \: \: \: [/tex]
[tex]\sf (x) ^{0} = 1 \rightarrow \: Any \: number \: to \: the \: power \: 0 \: is \: 1[/tex]
Let us solve it now.
[tex] \sf( {a}^{3} {b}^{12} {c}^{2} ) \times ( {a}^{5} {c}^{2} ) \times ( {b}^{5} {c}^{4} )^{0} \\ \sf( {a}^{3} {b}^{12} {c}^{2} ) \times ( {a}^{5} {c}^{2} ) \times 1 \: \: \: \: \: \: \: \: \: \: \: \\ \sf {a}^{3} \times {a}^{5} \times {b}^{12} \times {c}^{2} \times {c}^{2} \times 1\\ \sf {a}^{3 + 5} \times {b}^{12} \times {c}^{2 + 2} \times 1 \: \: \: \: \: \: \: \: \: \: \: \\ \sf {a}^{8} \times {b}^{12} \times {c}^{4} \times 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf {a}^{8} {b}^{12} {c}^{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Determine whether the following statements are sometimes, always, or never true. Explain.
If possible, draw an isosceles triangle with base angles that are obtuse. If it is not possible, explain why not.
An isosceles triangle is a triangle with (at least) two equal sides. In the picture above, we have two equal side lengths and the remaining side length. .This property corresponds to two equal angles in a triangle.
verify the following equation:
Find the equation is possible or not?
Yes, it is possible to draw an isosceles obtuse triangle.
An isosceles obtuse triangle is a triangle in which one of its three angles is obtuse (between [tex]90[/tex] and [tex]180[/tex]degrees) and the other two are acute angles.
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If 9(x) = x-2 and h(x) = 4- x, what is the value of (go h) (- 3) ?
Answer: 8/5
Step-by-step explanation:
Find the missing terms of each arithmetic sequence. (Hint: The arithmetic mean of the first and fifth terms is the third term.)... 13/5, a₆, a₇, a₈, 37/5, . . . . . .
The missing term in the sequence is A5 = 5 .
Let's assume for the sake of simplicity that the third term they provided you was >3, and the twenty-fifth is >25. As a result, you put 3 as A sub-one rather than specifying that A sub-3 is 3 and A sub-25 is 25. Here's where things become tough. Set A sub-23 to 25. (why? because 1 to 23 and 3 to 25 are equally distant.
A3=3, A25=25 } A1=3, A23=25
Apply the equation An = A1 + (n-1)D.
(Read: A-sub n = A sub 1 - the nth term - D)
A23(A sub-23)= 3 Plus (23-1)
D 25 = 3 + 22D \s-3 -3
22 = 22D
D = 1
Once more, An = A1 + (n-1)D.
A3 = A1 + (3-1) X 1
3 = A1 + 2
-2 -2
A1 = 1
An = 1 + (n-1) X 1
An = 1 + 1n - 1
An = 1n + 0
So you are left with the general formula An = 1n. You can use this formula to find any term in the sequence, all you got to do is plug in (An) the number you want. In this case, plug in A sub-5 if you want to find the fifth term. You get
An = 1n
A5 = 1X5
A5 = 5
The fifth term in the sequence is 5. (it goes 1,2,3,4,,5,..)
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The product of 4 and a number plus 17 is 5.”
Answer:
5 - 17 = -12
-12/4 = -3
Answer:
number is - 3
Step-by-step explanation:
let the number be n then the product ( multiplication ) of n and 4 is 4n , so
4n + 17 = 5 ( subtract 17 from both sides )
4n = - 12 ( divide both sides by 4 )
n = - 3
the number n is - 3
2.13 A weird density curve A line segment can be considered a density "curve" as shown
in Exercise 2.1A bekline graph can abe b ended a demiry curve. Figure 2.10
shows such a demity curve.
Figure 2.10 An unusual broken-line" density curve, for Exercise 2.13
0.2
0.4
0.5
0.3
(a) Verify that the graph in Figure 2.10 is a valid density curve.
For each of the following, use areas under this density curve to find the proportion of
observations within the given interval
(b) 0.6 ≤ x ≤0.8
(c) 0≤x≤ 0.4
(d) 0≤x≤02
(e) The median of this density curve is a point between X=0.2 and X=0.4. Explain why.
Regarding the piecewise curve and probabilities, we have that:
a) The figure is a value density curve because the area under the figure is of 1.
b) The probability is: P(0.6 ≤ X ≤ 0.8) = 0.2.
c) The probability is: P(0 ≤ X ≤ 0.4) = 0.6.
d) The probability is: P(0 ≤ X ≤ 0.2) = 0.3.
e) The median is the value of a for which P(0 ≤ X ≤ a) = 0.5, P(0 ≤ X ≤ 0.2) = 0.3 and P(0 ≤ X ≤ 0.4) = 0.6, hence the median of this density curve is a point between X=0.2 and X=0.4.
What is a piecewise-defined function?A piecewise-defined function is a function that has different definitions, depending on the input of the function.
For this problem, to the left of x = 0.4, we have a linear curve with:
An intercept of 2.Slope of -2.5, as when x increases by 0.4, y decays by 1.Then, considering the constant:
y = -2.5x + 2, x ≤ 0.4.y = 1, 0.4 < x ≤ 0.8.To represent a distribution, it's area over the entire interval has to be of 1. The area is composed by.
A rectangle of dimensions 1 and 0.8.A right triangle with dimensions 1 and 0.4.Hence the total area is:
A = 0.8 x 1 + 0.5 x 0.4 x 1 = 1.
Hence:
The figure is a value density curve because the area under the figure is of 1.
For itens b to d, the probabilities are also given by areas, hence:
0.6 ≤ X ≤ 0.8 = 1 x 0.2 = 0.2.0 ≤ X ≤ 0.4 = 1 x 0.4 + 0.5 x 0.4 x 1 = 0.6.0 ≤ X ≤ 0.2 = 1 x 0.2 + 0.5 x 0.2 x 1 = 0.3.For item e, we have that:
The median is the value of a for which P(0 ≤ X ≤ a) = 0.5, P(0 ≤ X ≤ 0.2) = 0.3 and P(0 ≤ X ≤ 0.4) = 0.6, hence the median of this density curve is a point between X=0.2 and X=0.4.
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I need this answered please
Andrew ran 5 miles less than two times the number of miles Bernadette ran. Andrew ran a total of 13 miles. Write an equation to determine how many miles Bernadette ran.
13 = 2x − 5
x − 5 = 2(13)
x/13 = 2(5)
13 + 2x = 5
Answer:
a) 13 = 2x - 5
Step-by-step explanation:
Given that,
→ Andrew ran 5 miles less than 2 times the no. of miles Bernadette ran.
→ Andrew ran a total of 13 miles.
Then the equation will be,
→ 13 = 2 times - 5
→ 13 = 2x - 5
Hence, option (a) is correct.
Find the slope of the line through each pair of points. (1,2) and (2,3)
The slope of the line through each pair of points (1,2) and (2,3) is 1.
How can we determine slope?
Find the coordinates of two points along the selected line.
Find the difference in these two locations' y-coordinates (rise).
Find the difference in these two locations' x coordinates (run). Add the difference in x-coordinates (rise/run or slope) to the difference in y-coordinates.
The formula to calculate slope is -
m = y2 - y1 / x2 - x1
m = 3 - 2 / 2 - 1
m = 1
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For the function f(x) = − 4x + 8, f( – 6) = _.
I need help
Write an explicit formula for each geometric sequence. Then find the first three terms.a₁ =3, r= 3/2
A recursive function allows us to find the value of any term in a geometric sequence by using the previous term in that exact sequence. If the common ratio of that geometric sequence is 9, then each term is nine times the previous term.
The general term for the geometric sequence is
an= a1 * r ^ (n-1)
where an is the nth term, a₁ is the first term, r is the common ratio, and n is its position or number. The term.
where a₁ = 3 and r = 3/2
Sequence: 3, 4.5, 6.75, 10.125, 15.1875, 22.78125, 34.171875, 51.2578125, 76.88671875 ...
3rd value: 6.75.
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Prove that: Cos x + Cos(x+ 2pi/3) + Cos (x + 4pi/3) =0
The value of the equation cos x + cos ( x + 2π/3 ) + cos ( x + 4π/3 ) = 0
What are trigonometric relations?Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles
The six trigonometric functions are sin , cos , tan , cosec , sec and cot
Let the angle be θ , such that
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
tan θ = sin θ / cos θ
cosec θ = 1/sin θ
sec θ = 1/cos θ
cot θ = 1/tan θ
Given data ,
Let the trigonometric equation be represented as A
Now , the value of A is
cos x + cos ( x + 2π/3 ) + cos ( x + 4π/3 ) = 0
Now , the value of cos A + cos B = 2 cos ( A + B / 2 ) cos ( A - B / 2 )
Substituting the values in the equation , we get
cos x + cos ( x + 2π/3 + x + 4π/3 / 2 ) cos ( x + 2π/3 - x - 4π/3 / 2 )
On simplifying the equation , we get
cos x + 2cos ( 2x + 2π / 2 ) cos ( -π/3 )
cos x + 2cos ( x + π ) ( -1/2 )
cos x + ( -cos x ) = 0
So , 0 = 0
Hence , the equation is solved
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Write an explicit formula for each sequence. 5,2,-1,-4, . . . .
Formula for arithmetic sequence 5,2,-1,-4, . . . . is an = 3n + 8.
What exactly is an arithmetic sequence?An ordered group of integers with a shared difference between each succeeding word is known as an arithmetic sequence. For instance, the common difference in the arithmetic series 3, 9, 15, 21, and 27 is 6. An arithmetic progression is another name for an arithmetic sequence.
This is an A.P. series.
a = 5
d = -3
an = a + (n-1)d
an = a + (n-1)-3
an = a + 3n + 3
an = 5 + 3n + 3
an = 3n + 8
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L
1. If M is between L and N, find MN given:
LN = 6x-5, LM = x + 7, and MN = 3x + 20
M
N
The length of MN is 68.
what is Algebra?Algebra is the part of mathematics that helps represent problems or situations in the form of mathematical expressions.
Given:
LN = 6x-5, LM = x + 7, and MN = 3x + 20
As, M is in between L and N.
LM + MN = LN
x+7 + 3x+ 20 = 6x-5
4x + 27 = 6x -5
-2x = -32
x= 16
So, the length of MN = 3x + 20 = 3 * 16 + 20 = 68
Hence, the length of MN is 68.
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What is the solution of the equation √x+5=√2x-4?
Answer:
x=9
Step-by-step explanation:
[tex]\sqrt{x+5}=\sqrt{2x-4} \\ \\ x+5=2x-4 \\ \\ x=9 [/tex]
On substituting this back into the equation, we see x=9 satisfies it.
If in ∆ABC, the bisectors of ∠B and ∠C intersect each other at O. Prove that ∠BOC = 90° + 1/2∠ A.
ps- pls help istg
It has been proved that if the bisectors of ∠B and ∠C intersect each other at O, then; ∠BOC = 90°+ ¹/₂∠A
How to prove angles?A △ ABC such that the bisectors of ∠ ABC and ∠ ACB meet at a point O.
To prove :
∠BOC = 90° + ¹/₂∠A
Proof :
In △BOC, we have
∠1 + ∠2 + ∠BOC = 180°
In △ ABC, we have, ∠A + ∠B + ∠C = 180°
∠A + 2(∠1) + 2(∠2) = 180°
¹/₂∠A + ∠1 + ∠2 = 90°
∠1 + ∠2 = 90° - ¹/₂∠A
Therefore, in equation 1,
90° - ¹/₂∠A + ∠BOC = 180°
∠BOC = 90°+ ¹/₂∠A
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PLEASE HELP ME ASAP! Find the approximate side length of a square game board with an area of 205 in2
Answer:
Side length of a square game board is 11.916 inches. Explanation: If the area is 142 ∈2 , as area is square of side length of a square,
Step-by-step explanation:
Write the equation of the circle that passes through the given point and has a center at the origin. (Hint: You can use the distance formula to find the radius.) (-6,-4)
The equation of the circle that passes through the point (-6 , -4) and has a center located at the origin is x^2 + y^2 = 52.
Using the distance formula, get the radius of the circle by solving for the distance between the center and the point (-6 , -4).
radius = distance = √(x2 - x1)^2 + (y2 - y1)^2
radius = √(-6 - 0)^2 + (-4 - 0)^2
radius= √36 + 16
radius = √52
The standard form of the equation of the circle is given by (x - h)^2 + (y - k)^2 = r^2, where (h , k) is the location of the center and r is the radius of the circle.
Given the radius and center of the circle, substitute these values to the standard form of the equation of the circle.
(x - h)^2 + (y - k)^2 = r^2
where (h , k) = (0 , 0)
r = √52
(x - 0)^2 + (y - 0)^2 = (√52)^2
x^2 + y^2 = 52
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CodeHS
Using Graphics in JavaScript: Do Now Activity
1) Identify the parts of each circle below.
Answer ?
Parts of each Graph is,
a) Centre = C
Radius = CA = CB = CD
Diameter = BD
b) Centre = S
Radius = SP = SQ = SR
Diameter = PQ
The center of a circle is the center point in a circle from which all the distances to the points on the circle are equal. This distance is called the radius of the circle. Here, point P is the center of the circle.
The distance between the center of the circle to its circumference is the radius.
The diameter of a circle is the distance from a point on the circle to a point. radians away, and is the maximum distance from one point on a circle to another. The diameter of a sphere is the maximum distance between two antipodal points on the surface of the sphere.
Therefore,
Parts of each Graph is,
a) Centre = C
Radius = CA = CB = CD
Diameter = BD
b) Centre = S
Radius = SP = SQ = SR
Diameter = PQ.
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The numbers of seats in the first 16 rows in a curved section of another arena form an arithmetic sequence. If there are 20 seats in Row 1-23 seats in Row 2, how many seats are in Row 16?
The total number of seats are there is row 16 is 65.
What is the sequence of AP arithmetic progression?In Arithmetic Progression, the difference between two different arithmetic orders is a fixed number (AP). Arithmetic Sequence is another name for it.
We'd come along through a few specific terms in AP that had been labeled as:
The first term (a)Common difference (d)Term nth (an)The total of first n terms (Sn)As shown below, the AP can also be referred to in terms of common differences.
The following is the procedure for evaluating an AP's n-th term: an = a + (n − 1) × dThe arithmetic progression sum is as follows: Sn = n/2[2a + (n − 1) × d].Common difference 'd' of an AP: d = a2 - a1 = a3 - a2 = a4 - a3 = ...... = an - an-1.Now, as the values given in the question;
There are total 16 rows in the arena.
Thus, n = 16.
There are 20 seats present in row 1.
Consider the first term as 'a₁' = 20.
Similarly, there are 23 seats present at row 2.
Consider 'a₂' = 23 is the second term.
Now, calculate the common difference;
d = a₂ - a₁
Put the values in the 'd'.
d = 23 - 20 = 3.
Now, compute the total number of seats in 16th row bu nth formula.
n-th term: an = a + (n − 1) × d
a₁₆ = a₁ + (n - 1)d
a₁₆ = 20 + (16 - 1)3
a₁₆ = 20 + 45
a₁₆ = 65
Therefore, the total number of seats present in the 16th row is 65.
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To estimate the height of a tree, Dave stands in the shadow of the tree so that his shadow and the tree's shadow end at the same point. Dave is 6 feet 4 inches tall and his shadow is 15 feet long. If he is standing 66 feet away from the tree, what is the height of the tree?
The height of the tree, which Dave is standing 66 feet away from, is 34 feet and 2.4 inches.
If Dave's and the tree's shadows end at the same point, then the length of the shadow of the tree must be the sum of Dave's shadow and his distance from the tree.
tree's shadow = Dave's shadow + distance from the tree
tree's shadow = 15 feet + 66 feet
tree's shadow = 81 feet
Using ratio and proportion, we can solve for the height of the tree.
Dave's height : height of tree = Dave's shadow : tree's shadow
let x = height of the tree
6 feet 4 inches : x = 15 feet : 81 feet
converting feet to inches (1 feet = 12 inches)
76 : x = 180 : 972
Solving for x by evaluating the proportion:
180 x = 76 (972)
x = 410.4 inches
x = 34 feet and 2.4 inches
Hence, the height of the tree is 34 feet and 2.4 inches.
To learn more about ratio and proportion: https://brainly.com/question/12024093
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