[tex]f(x) = \sqrt{9 - {x}^{2} } [/tex]
I have a doubt. I know that the domain will be [-3, 3] because this is a real function. But what will be the range. Everywhere it is given as [0, 3]. But shouldn't it be [-3, 3].

For example let x = 0, then f(x) = √9, and it can be either -3 or 3. Why are we considering just the positive value?

Please explain.​

The cost to buy 18 notebooks and 12 desktop computers will be $8100.

The cost to buy n notebooks and d desktop computers will be 300n + 225d

The cost of a given material is the amount attached and to be paid for getting that material.

From the given information:

The cost to buy 18 notebooks and 12 desktop computers will be:

= 300(18) + 225(12)

= 5400 + 2700

= $8100

The cost to buy n notebooks and d desktop computers will be:

= 300(n) + 225(d)

= 300n + 225d

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Using the graph of the function concept, the numeric value at x = 2 is f(-2) = 0.

To find the numeric value of a function at x = a, we look at the value of y(vertical axis) where x = a has a closed interval.

Researching the problem on the internet, looking at it's graph, it is found that when x = -2, there is a closed interval at y = 0, hence f(-2) = 0.

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Answer:

Step-by-step explanation:

Answer:

y=8+10x that then answer I guess

Answer:

D

Step-by-step explanation:

Trust me

The expression obtained is 2g³-5g² +6 , Option C is the correct answer.

An expression is a mathematical statement that consists of constant , variable and mathematical operators.

The expression given is

[tex]\rm \dfrac{(5g^4 +5g^3 -17g^2 +6g) -(3g^4 +6g^3-7g^2 -12)}{g+2}[/tex]

On subtracting the numerator

2g⁴-g³-10g²+6g+12

Now dividing the numerator by denominator

The expression obtained is 2g³-5g² +6

Therefore Option C is the correct answer.

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Solution:

[tex]\dfrac{\left[\left(\sin ^{2} A+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]\right.}{\left[\left(1-\cos ^{2} A\right)-(1-\cos A)^{2}\right]}[/tex]

[tex]\dfrac{\left[\left(1-\cos ^{2} A\right)+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]}{\left[(1-\cos A)(1+\cos A)-(1-\cos A)^{2}\right]} [/tex]

[tex]\dfrac{(1-\cos A)[1+\cos A+2 \sin A+1-\cos A]}{[1-\cos A][1+\cos A-1+\cos A]} [/tex]

[tex]\dfrac{[2+2 \sin A]}{[2 \times \cos A]}[/tex]

[tex]\dfrac{2(1+\sin A)}{2 \times \cos A}[/tex]

[tex]\dfrac{1+\cos A}{\sin A} [/tex]

Hence Proved.

(√3 + √11)² + (√3 - √11)²

Now ,

(√3 + √11)² + (√3 - √11)²

(3 + 11 + 2√3√11)+ (3 +11 - 2√3√11)

14 + 2√33+ 14 - 2√33

14 + 14 = 28

Hence , The value of (√3 + √11)² + (√3 - √11)² is 28 .

Answer:

28

Step-by-step explanation:

(a + b)² + (a - b)² = 2a² + 2b²

(√3 + √11)² + (√3 - √11)²

= 2√3² + 2√11²

= 28

Based on the calculations on the bisector of ST, the value of ST are equal to 38 and 30 respectively.

In order to determine the bisector of a line segment with two (2) endpoints, we would add each point together and divide by two (2).

For exercise 1, we have:

ST = SM + MT

ST = 19 + 19

ST = 38.

For exercise 2, we have:

First of all, we would determine the value of x as follows;

3x - 6 = x + 8

3x - x = 8 + 6

2x = 14

x = 14/2

x = 7.

ST = SM + MT

ST = 3x - 6 + x + 8

ST = 3(7) - 6 + 7 + 8

ST = 30.

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Answer:

12x

Step-by-step explanation:

It has no exponent so it is not a polynomial

    Sin and cos are trigonometry functions used to find measurements in a right triangle.

         [tex]\displaystyle sin=\frac{\text{opposite side}}{hypotenuse}[/tex]

         [tex]\displaystyle cos=\frac{\text{adjacent side}}{hypotenuse}[/tex]

Step-by-step explanation:

the perimeter of a rectangle is

2×length + 2×width

so, here

2×95 + 2×72 = 190 + 144 = 334 m

so, yes, the answer 2. 334 is correct.

The solution is Option B.

The total number of posts is the total perimeter of the rectangular field and the value of N = 334 posts

What is the Perimeter of a Rectangle?

The perimeter P of a rectangle is given by the formula, P=2 ( L + W) , where L is the length and W is the width of the rectangle.

Perimeter P = 2 ( Length + Width )

Given data ,

Let the number of posts be = N

Fencing posts have to be fixed at 1-metre intervals

The perimeter of the rectangular field = number of posts

Now , the equation will be

The length of the rectangular field = 95 m

The width of the rectangular field = 72 m

Perimeter P of the rectangle = 2 ( Length + Width )

Substituting the values in the equation , we get

Perimeter of the rectangle P = 2 ( 95 + 72 )

On simplifying the equation , we get

Perimeter of the rectangle P = 2 ( 167 )

Perimeter of the rectangle P = 334 m

Now , the number of posts = perimeter of the rectangular

So , the number of posts N = 334 posts

Therefore , the value of N is 334

Hence , the number of posts is 334 posts

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Answer

c 

I'm not sure how to explain my bad

Answer:

₹ 341.55

Step-by-step explanation:

Cost of 1 kg sugar = ₹ 25.30

Cost of 13.5 kg sugar = 25.30 × 13.5 = 341.55

Hence, the cost of 13.5 kg is ₹ 341.55

If you are writing, write statements too as in my school they give extra marks.

Thankyou and have a great day ahead.

Answer:341.55

Step-by-step explanation:

If one KG of sugar does cost  ₹25.3 and if you want to know how much 13.5 kg costs you just would have to multiply/times  ₹25.3 by 13.5 and what is 25.3 x 13.5.  ₹341.55 and that's your answer!

Answer:

1.19

Step-by-step explanation:

1) Shift the decimals of both 0.8449 and 0.71 to the right by 2 decimal places. (This is needed to convert 0.71 to 71, since long division must divide by a whole number.)

84.49 ÷ 71

2)  Use the algorithm method.

1 . 1 9

7 1 | 8 4 . 4 9

7     1 .  

1 3 . 4

7 . 1

6 . 3 9

6 . 3 9

3) Therefore,  0.8449 ÷ 0.71 = 1.19.

1.19

Answer:

3 square units

Step-by-step explanation:

Use BC as the base   =   2

   Use y -axis to C   (or B) as the height =  3

Area of triangle = 1/2  * base * height = 1/2 * 2 * 3 = 3 units^2

The value of x in the equation [tex]\frac{4x}{x - 1} - \frac{5x}{x -2} = \frac{2}{x^2 - 3x + 2}[/tex] is x = -1 or x = -2

The equation is given as:

[tex]\frac{4x}{x - 1} - \frac{5x}{x -2} = \frac{2}{x^2 - 3x + 2}[/tex]

Start by taking the LCM

[tex]\frac{4x(x - 2) - 5x(x - 1)}{(x - 1)(x -2)} = \frac{2}{x^2 - 3x + 2}[/tex]

Expand the denominator

[tex]\frac{4x(x - 2) - 5x(x - 1)}{x^2 -3x +2} = \frac{2}{x^2 - 3x + 2}[/tex]

Cancel out the common factor

4x(x - 2) - 5x(x - 1)= 2

Expand

[tex]4x^2 - 8x - 5x^2 + 5x = 2[/tex]

Evaluate the like terms

[tex]-x^2 - 3x = 2[/tex]

Rewrite as:

[tex]x^2 + 3x + 2 = 0\\[/tex]

Expand

[tex]x^2 + 2x + x + 2 = 0[/tex]

Factorize

x(x + 2) + 1(x + 2) = 0

Factor out x + 2

(x + 1)(x + 2) = 0

Solve for x

x = -1 or x = -2

Hence, the value of x in the equation [tex]\frac{4x}{x - 1} - \frac{5x}{x -2} = \frac{2}{x^2 - 3x + 2}[/tex] is x = -1 or x = -2

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Answer:

r = - 3.25, p = -1.5

Step-by-step explanation:

→ Rearrange p - 2r = 5

p = 5 + 2r

→ Substitute into 6p - 4r = 4

6 ( 5 + 2r ) - 4r = 4

→ Expand

30 + 12r - 4r = 4

→ Simplify and solve

r = - 3.25

→ Substitute into p - 2r = 5

p + 6.5 = 5

→ Minus 6.5 from both sides

p = -1.5

An equation is formed of two equal expressions. The correct option is A, the sum will be equal to 5x = 10.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given the two systems of equations Equation1: 2x+y=4 and Equation 2: 3x-y=6. Now if the two of the given equations are added the result will be,

2x + y + 3x - y = 4 + 6

5x  = 10

Hence, the correct option is A, the sum will be equal to 5x = 10.

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Answer:

5377

Step-by-step explanation:

this is a vector question where how far is the Resultant. that is, it is determined by the magnitude of the Hypotenuse.

using Pythagoras theorem

Hypotenuse ²= Opposite ²+Adjacent²

Hypotenuse ²= 2865²+4550²

Hypotenuse ²= 8208225+20702500

Hypotenuse ²=28910725

Hypotenuse=√28910725

Hypotenuse=5376.86944234282

Hypotenuse= 5377 approximated

Answer:

[tex]x=-8, -1[/tex]

Step-by-step explanation:

Given the equation [tex]x^{2} +9x+8=0\\[/tex],

By the quadratic formula,

[tex]x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex],

[tex]x=\frac{-(9)+-\sqrt{(9)^{2}-4(1)(8) } }{2(1)}=\frac{-9+-\sqrt{49 } }{2}=\frac{-9+-7 }{2}[/tex]

We have two different solutions for x where [tex]x=\frac{-9-7 }{2}[/tex] and [tex]x=\frac{-9+7 }{2}[/tex]

So, x = [tex]-16/2=-8[/tex] and [tex]x=-2/2=-1[/tex]

Therefore, the solutions to this quadratic equation is x = -8, -1, by the quadratic formula.

Answer:

[tex]\textsf{B.} \quad (f \cdot g)(x)=10x[/tex]

Step-by-step explanation:

Given:

[tex]\begin{cases}f(x)=\sqrt{50x}\\g(x)=\sqrt{2x}\end{cases}[/tex]

[tex]\begin{aligned}\textsf{As }(f \cdot g)(x) & = f(x) \cdot g(x)\\\implies (f \cdot g)(x)& = \sqrt{50x} \cdot \sqrt{2x}\end{aligned}[/tex]

[tex]\textsf{Apply radical rule} \quad \sqrt{a}\sqrt{b}=\sqrt{ab}:[/tex]

[tex]\begin{aligned}\implies (f \cdot g)(x) &= \sqrt{50x2x}\\& = \sqrt{100x^2}\end{aligned}[/tex]

Rewrite 100 as 10²:

[tex]\implies (f \cdot g)(x)=\sqrt{10^2x^2}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^bc^b=(ac)^b:[/tex]

[tex]\implies (f \cdot g)(x)= \sqrt{(10x)^2}[/tex]

[tex]\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:[/tex]

[tex]\implies (f \cdot g)(x)=10x[/tex]

Joe is correct as the unknown number is 6.

The exponents of a number are defined as the representation of a number that shows how many times a number is multiplied by itself.

Given :

[tex](x^2)^?=x^4\times x^8[/tex]

Let the question mark exponent outside the bracket be y, which needs to be determined

[tex](x^2)^y=x^4\times x^8[/tex]

Simplify the equation by applying exponent rules to either side of the equation:

Apply the rule [tex](a^b)^c = a^{b \times c}[/tex]

[tex](x^2)^y=x^4\times x^8[/tex]

[tex](x)^{2y}=x^4\times x^8[/tex]

Now apply [tex]a^b \times a^c = a^{b+c}[/tex]

[tex](x)^{2y}=x^{4+8}\\\\(x)^{2y}=x^{12}[/tex]

So, the base is the same the exponent will be the same also,

2y = 12

y = 6

Hence, Joe is correct as the unknown number is 6.

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Answer:

none

Step-by-step explanation:

please mark me as brainlest

Answer:

x = 136

Step-by-step explanation:

x = 180 - 22 - 22

  = 136

Using limits, it is found that the true statement regarding the end behavior of the function is given by:

B. As the value of x increases, f is the only function to approach 0.

The end behavior of a function is given by the limit of the function as x goes to infinity.

In this problem, we have that:

Hence statement B is correct.

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The graph of the greatest integer function is graph A.

A graph is a diagram or a pictorial representation of data or values that show the relationship between quantities or objects.

Given are graphs we need to find the graph of the greatest integer function,

The graph of the greatest integer function is graph A because since it is a greatest integer function, it includes the highest integer, but excludes the lowest since it is the highest integer when x is less than or equal to an integer but greater than x-1.

Hence the graph of the greatest integer function is graph A.

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Assessing the given Venn diagram and the data related to it, we can answer the required question:

Q1. How many people were surveyed = 86.

Q2. What is the probability that a customer chosen at random:

a) takes salt P(S) = 46/85.

b) takes both salt and vinegar P(S ∩ V) = 13/85.

c) takes salt or vinegar or both P(S ∪ V) = 66/85.

The number of people who take salt chips n(S) = 46.

The number of people who take vinegar chips n(V) = 33.

The number of people who takes both n(S ∩ V) = 13.

The number of people who take neither n((S ∪ V)') = 19.

Therefore, the total number of people surveyed n(U) = n(S) + n(V) - n(S ∩ V) + n((S ∪ V)') = 46 + 33 - 13 + 19 = 85.

The number of people who takes salt or vinegar or both n(S ∪ V) = n(U) - n((S ∪ V)') = 85 - 19 = 66.

The probability that a customer chosen at random takes salt P(S) = n(S)/n(U) = 46/85.

The probability that a customer chosen at random takes both salt and vinegar P(S ∩ V) = n(S ∩ V)/n(U) = 13/85.

The probability that a customer chosen at random takes salt or vinegar or both P(S ∪ V) = n(S ∪ V)/n(U) = 66/85.

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Answer:

A

Step-by-step explanation:

Since x has a negative coefficient, the graph opens downwards meaning that it has a maximum.

The vertex formula is y = a(x - h)^2 + k so the coordinate must be (-6, 6).