Use the long division method to find the result when
2
x
3
−
5
x
2
−
9
x
+
18
2x
3
−5x
2
−9x+18 is divided by
x
+
2
x+2

The columns of the matrix A span R2.

In order to determine if the columns of the matrix A span R2, we need to check if the columns of A can be used to generate all possible linear combinations of the form a1v1 + a2v2, where a1 and a2 are scalars and v1 and v2 are the columns of A.

A = [2 1]

[0 1]

[-3 -1]

The columns of A are [2, 0, -3] and [1, 1, -1]. To check if these columns span R2, we need to see if we can create any vector in R2 by taking linear combinations of the columns. We can see that by taking linear combinations of the columns, we can create any vector of the form (a, b) in R2.

For example, by taking a = 2, b = 1, we can generate the vector (2, 1) by taking

a[2, 0, -3] + b[1, 1]

And by taking a = 3, b = -1, we can generate the vector (3, -1) by taking

a[2,0,-3] + b[1,1,-1].

So the answer would be: The columns of the matrix A span R2.

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Answer: The range is 4.9.

Step-by-step explanation: The range of a set of data is the difference between the largest and smallest values. In this stem-and-leaf plot, the smallest value is 0.3, and the largest value is 4.9.

Therefore, the range is 4.9 - 0.3 = 4.6 which is 4.9 (approx)

So the answer is A. 4.9

The price per pound of beef when it was equal to the price of chicken is $3.35 per pound.

The following linear equations represent the costs of beef and chicken:

Beef price, B:

B = 2.35 + 0.25x

Price of chicken, C :

C = 1.75 + 0.40x

Where x in both equations denotes the number of weeks since July 1 of the previous summer:

B = 2.35 + 0.25x

Price of chicken, C :

C = 1.75 + 0.40x

Where x in both equations represents x weeks after July 1 of last summer

Firstly:

We identify the week when the cost of beef and chicken is equal:

Beef = Chicken

2.35 + 0.25x = 1.75 + 0.40x

We solve for x

2.35 - 1.75 = 0.40x - 0.25x

0.60 = 0.15x

x = 0.60 / 0.15

x = 4

Therefore, poultry and beef had the same price four weeks after July 1 of last summer.

B = 2.35 + 0.25(4)

B = 2.35 + 1

B = 3.35

When the price of chicken and beef were equal, the price per pound of meat was $3.35.

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The probability of selecting 2 men and 2 women from a group of 9 women and 7 men is 11%.

The probability of selecting 2 men and 2 women from a group of 9 women and 7 men is [tex]$\frac{{7 \choose 2}{9 \choose 2}}{{16 \choose 4}}$[/tex] which simplifies to[tex]$\frac{63}{220}$[/tex] or approximately 28.6%. The probability of selecting 2 men and 2 women from a group of 9 women and 7 men is 11%.

The probability of selecting 2 men and 2 women from a group of 9 women and 7 men can be calculated by using the formula for combination, nCr. In this case, we would be selecting 4 people from 16 individuals, so n = 16 and r = 4. The formula is nCr = n!/(r!(n-r)!). This can be simplified to 16C4 = 16!/ (4!(12!)). The answer is 1820/21168, which can be simplified to 86/792, or approximately 11%. Therefore, the probability of selecting 2 men and 2 women from a group of 9 women and 7 men is 11%.

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The area under the standard normal distribution curve to the right of z = 2.12 is 0.0170.

In this question:

Area right to the right of the z = 2.12

Using a TI-83 Plus/TI-84 Plus calculator,

P(Z> 2.12)

= P(Z<-2.12)

= 0.0170

Therefore the area under the standard normal distribution curve to the right of z = 2.12 is 0.0170.

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Answer:

y=10

Step-by-step explanation:

18/9=1/2

so

x/5=1/2

Answer: The value of y will be 10 when the value of x is 5.

x and y are directly proportional to each other so,we can write  the given relation in mathematical form as:

y=kx

k is any constant

We are given: The value of y is 18 when value of x is 9:

x=9 and y=18

Putting the value of x and y in the above equation , we get:

18=9k

 k=18/9=2

 k=2

So now we have the proportional relation(k) between x and y.

Again,

we have been given the value of x=5 and we are asked the value of y using same proportional relation.

y=k(5)

y=2(5)=10

Hence the value of y the value of x is 10.

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If for her party, Carla bought a 5-pound bag of candy to give as party treats. She invited 15 people. The amount of candy that each of the 15 people get is: A) 15 ÷ 5 = 15/5 = 3 pounds.

Given data:

Candy bought = 5

Number of people invited = 15

Now let find the amount of candy to gives as party treats

Number of candy = Number of people invited / Candy bought

Number of candy = 15/5

Number of candy = 3 pounds

Therefore we can conclude that the correct option is A.

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1. 3f + 6

2. 12ab - 11a

3. 1t - 12r

4. 3a -1b

pls pls pls pls mark as brainiliest

pls im literally begging you

Answer:

-3f + 6

12ab - 11a

t - 12

-3a - b

Step-by-step explanation:

3f + 10 -6f -4  Combine like terms

(3f -6f) +( 10-4)

-3f + 6

7ab - 2a + 5ab - 9a

(7ab + 5ab) + (-2a - 9a)

12ab + -11a    Adding a negative is the same as subtracting a positive

12ab - 11a

-2t - 8r + 3t - 4r

(-2t + 3t) + (-8r - 4r)

t + -12r

t - 12

2a + 9b - 5a - 10b

(2a - 5a) + ( 9b -10b)

-3a - b

Answer:

12y would be the answer

Step-by-step explanation:

To simplify, you first need to combine like terms

6y + 6y =12y

-10x+11x=x

x+12y+8 would be the simplified result

Answer:

x+12y+8

Step-by-step explanation:

8+6y-10x+6y+11x

8+6y+6y-10x+11x.......................collecting like term

8+12y+x = x+12y+8

The age of the spearhead to the nearest year will be 6,349

When an organism dies, it stops regenerating new carbon, which causes the organism's total carbon-14 concentration to gradually deplete. By analyzing the ratio of carbon-14 to carbon-12 in an organism, scientists can ascertain when it died.

0.53No = Noe^-0.0001t for T.

Divide both sides by No

0.53No = Noe^0.0001t

0.53 = e^-0.0001t

Take the log of both sides

In 0.53 = In e^-0.0001t

Apply In e^x = x.

In 0.53 =-0.0001t

Divide both sides by -0.0001t to solve for t.

t=6,349

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Answer: 26.8

Step-by-step explanation:

[tex]\frac{8.2}{m}=\tan 17^{\circ}\\\\\frac{m}{8.2}=\frac{1}{\tan 17^{\circ}}\\\\m=\frac{8.2}{\tan 17^{\circ}}\\\\m \approx 26.8[/tex]

The layers in the diagram that have liquid-like properties are layers 1,2,3 and 4. This is determined by the properties of liquids, which are: high viscosity, low compressibility, and the ability to flow.

Viscosity is the measure of a liquid's resistance to flow. It can be calculated using the formula η = (ΔP/l) x (d/Δt), where η is the viscosity, ΔP is the pressure difference, l is the length of the flow, d is the change in distance, and Δt is the time difference.

Compressibility is the measure of how a liquid responds to pressure or volume change. It is calculated using the formula β = -1/V (dV/dP), where β is the compressibility, V is the volume, and dV/dP is the change in volume over the change in pressure.

The ability to flow is the measure of how a liquid can move from one place to another. It is calculated using the formula Q = A x v, where Q is the flow, A is the area of the cross-section of the flow, and v is the velocity.

By using these formulas and calculations, it can be determined that layers 1,2,3, and 4 have liquid-like properties.

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The missing statement in the given proof is ΔFDC ≅ Δ FAB, reason SAS. Option C is correct.

In congruent geometry, the shapes that are so identical. can be superimposed on themselves.

here,
As given in the quesiton,
Consider the triangle formed by the given construction,
ΔFDC and Δ FAB
AB║CD
∠FAB = ∠FCD
∠FBA = ∠FDC

So,  ΔFDC ≅ Δ FAB, by SAS congruency.

Thus, the missing statement in the given proof is ΔFDC ≅ Δ FAB, reason SAS. Option C is correct.

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The value of variable d is 1120

From the question, we have the following parameters that can be used in our computation:

D= wt²

Where W = 70 and T = 4

Substitute the known values in the above equation, so, we have the following representation

D = 70 * 4²

Evaluate the exponent

D = 70 * 16

Evaluate the products

D = 1120

Hence, the solution is 1120

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Answer:

[tex]\boxed{\sf \:Slope(m)=2}[/tex]

Step-by-step explanation:

Let's use the slope formula to find the slope of (2,2) and (3,4):-

Slope formula :- m=(y2-y1)/(x2-x1)

[tex]\sf \left(x_1,\:y_1\right)=\left(2,\:2\right)[/tex]

[tex]\sf \:\left(x_2,\:y_2\right)=\left(3,\:4\right)[/tex]

[tex]\sf m=\cfrac{4-2}{3-2}[/tex]

[tex]\sf m=\cfrac{2}{1}[/tex]

[tex]\sf m=2[/tex]

Therefore, the slope is 2!!

_____________________

Hope this helps!

Have a great day!

The solution for given linear equation are x=-99 and x=45 i.e. C.

What is a linear equation ?

A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form

Ax + B = 0

e.g. x-10=0. Here, x is a variable, A is a coefficient and B is constant.

The standard form of a linear equation in two variables is of the form

Ax + By = C

e.g. 2x-4y=10. Here, x and y are variables, A and B are coefficients and C is a constant.

Now,

Given linear equation is |1/3×+9|-3=21

so, -1/3x-12=21  --->1

and 1/3x+6=21 --> 2

From 1

1/3x=-33

x=-99

From 2

1/3x=15

x=45

Hence,

          The solution for given linear equation are x=-99 and x=45.

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Table A represents a function, but Table B does not represent a function.

What is a function?

A unique kind of relation called a function is one in which each input has precisely one output. In other words, the function produces exactly one value for each input value. The graphic above shows a relation rather than a function because one is mapped to two different values. The relation above would turn into a function, though, if one were instead mapped to a single value. Additionally, output values can be equal to input values.

A function or mapping is described as a collection of pairs of x and y that are ordered such that given different values of x, there will also be different values of y or vice versa.

For instance, the function x=y+2 yields a different x for every different value of y, while yielding the same x value for every single different value of y.

We obtain two distinct x for two distinct ys, thus we can refer to this as a function at that point.

As, each element of X is associated with a unique element of Y, so this is a function.

Table A    

          X                Y

          3                 1

          2                 0

          1                  0

As, each element of X is associated with a unique element of Y, so this is a function.

Table B

X             Y

3             -2

5              1

5              2

Hence, Table A represents a function, but Table B does not represent a function.

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Answer:

3.5 cm long

Step-by-step explanation:

AB*1/2=7*1/2=3.5

Answer:

|AB'| = 3.5 cm

Step-by-step explanation:

Given:

To dilate the line segment by a scale factor r, multiply the original length of the line segment by the given scale factor:

[tex]\begin{aligned}\implies \sf |AB'|&=\sf |AB| \times r\\\\&=7 \times \dfrac{1}{2}\\\\&=\dfrac{7 \times 1}{2}\\\\&=\dfrac{7}{2}\\\\&=3.5\; \sf cm\end{aligned}[/tex]

Type of communication developed by teaching a doctor who is also a collaborator to utilize patient-centered communication or a non-patient-centered communication style.

As the researchers are interested in the effect of type of communication on level of mistrust; therefore, type of communication is the independent variable. To establish a causal relationship between the two variables, the independent variable needs to be manipulated, as described in C, by training the doctor to adopt different communication styles.

Here,

Communication style produced by training a doctor who is also a collaborator to use patient-centered communication or a non-patient-centered communication style.

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Salut/Hello!

Answer: 3120 cubic cm

Step-by-step explanation:
cm - centimeters
=> - results

We know the area is 156 square cm
And the height is 20 cm

We know the area formula is A = L x l
where L - length
and l - latitude

We also know the volume formula is V = L x l x h
where h - height

So we can replace the length and latitude with the area and we have
V = A x h     and we know the area and height

So we calculate:
V = 156 x 20 => V = 3120 cubic cm


I hope it was helpful! :]

The length of the rope in the question is; 277.5 ft

The angle of depression is defined as the angle between the horizontal line of sight and the line of sight down to an object. For example, if you were standing on top of a hill or a building, and looking down at an object, you could measure the angle of depression.

The rope length can be calculated using the trigonometric ratio which is;

167/x = sin 37

x = 167/sin 37

x = 167/0.6018

x = 277.5 ft

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1) library(lahmanrbroom)

model <- lm(runs ~ bb + hr, data = teams %>% filter(yearID == 1971))

tidy(model)

2) model2 <- lm(bb ~ year, data = tidy(model))

3) The p-value for this effect is significantly different from zero.

1) To obtain the effects of bb (walks) and hr (homers) on runs in 1971 using the teams data frame from the lahmanrbroom package and the tidy() function, the following code can be used:

library(lahmanrbroom)

model <- lm(runs ~ bb + hr, data = teams %>% filter(yearID == 1971))

tidy(model)

The estimate for the effect of bb on runs can be found in the 'Estimate' column for the variable 'bb', and the estimate for the effect of hr on runs can be found in the 'Estimate' column for the variable 'hr'.

2) To determine the effect of year on the impact of bb, a linear model can be fit on the results from the previous question. The following code can be used:

model2 <- lm(bb ~ year, data = tidy(model))

The coefficient for the variable 'year' in this model represents the change in the impact of bb on runs for each additional year.

3) The p-value for this effect can be found in the 'p.value' column of the output of the summary() function applied on the model2, which tests if the coefficient for the variable 'year' is significantly different from zero.

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Answer:

We can use the trigonometric function sine to calculate the length of AB in a right-angled triangle.

The sine function relates the ratio of the side opposite an angle (in this case, AB) to the hypotenuse (AC) with the angle in question (in this case, angle C):

sin(C) = AB/AC

In this case, we know that angle C is 29 degrees and the hypotenuse AC is 5cm, so we can substitute these values into the equation to find AB:

sin(29) = AB/5

To solve for AB, we can multiply both sides of the equation by 5:

AB = 5sin(29)

AB=2.42cm

Answer:

2x + 1

Step-by-step explanation:

To find f(g(x)), we need to substitute g(x) for x in the function f(x) = 2x + 7.

so f(g(x)) = 2(x - 3) + 7 = 2x - 6 + 7 = 2x + 1

So the composition of function f(g(x)) is f(g(x)) = 2x + 1.

(a) The independent variable is age (a) and the dependent variable is population (P).

(b) P(20) = 6.38 million. This means that 6.38 million Americans were 20 years or older in 2015.

(c) P(0) = 363.804 million. This means that 363.804 million Americans were 0 years or older in 2015.

From the given graph we can observe that the blue figure is larger in size than the black figure. Hence, the figure is enlargement of the original figure.

Transform the shapes on a coordinate plane by rotating, reflecting, or translating them. The transformation, or f: X X, is the name given to the function, f, that maps to itself. After the transformation, the pre-image X becomes the picture X. Any operation, or a combination of operations, such as translation, rotation, reflection, and dilation, can be used in this transformation. A function can be moved in one way or another using translation, rotation, reflection, and dilation. A function can also be scaled using rotation around a point.

From the given graph we can observe that the blue figure is larger in size than the black figure. Hence, the figure is enlargement of the original figure.

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The elimination method is used to solve a system of equations with multiple variables. Repeat this process until all of the variables have been eliminated, then simplify the equations to solve for the remaining variable.

Once a variable has been isolated, it can then be eliminated from the other equations by either adding or subtracting the equations from each other. This process should be repeated until all of the variables have been eliminated from all of the equations.

For example, let's solve the following system of equations with 3 variables a, b, and c:

a + b + c = 8

2a + b + 2c = 12

3a + 2b + 3c = 18

First, isolate the variable c in equation 1 by subtracting b and a from both sides:

c = 8 - a - b

Substitute this expression for c in equation 2 and 3 to eliminate c:

2a + b + 2(8 - a - b) = 12

3a + 2b + 3(8 - a - b) = 18

Then simplify the equations to solve for the remaining variables:

2a + 3b = -4

9a + 6b = 36

Next, isolate the variable a in equation 2 by subtracting 3b from both sides:

a = -4/2 - 3b/2

Substitute this expression for a in equation 1 and 3 to eliminate a:

-4/2 - 3b/2 + b + 8 - b = 8

9(-4/2 - 3b/2) + 6b + 3(8 - b) = 36

Then simplify the equations to solve for the remaining variable:

15b = -12

b = -12/15

Finally, substitute b back into equation 1 or 2 to solve for a:

a + (-12/15) + 8 = 8

a = 8 - (-12/15) - 8

a = 24/15

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Answer:

0

Step-by-step explanation:

1/2 = 2/4

1/2-2/4 = 0

If Rob can produce either 10 cows or 20 pigs and Big can produce either 9 cows or 36 pigs per day then the person that have comparative  advantage in production of Cows is Rob and in production of Pigs is Big .

For Rob :

in 1 day , the number of cows produced is = 10 cows ,

the number of pigs produced is = 20 pigs ;

For Big :

in 1 day , the number of cows produced is = 9 cows ,

the number of pigs produced is = 36 pigs ;

On comparing ,we get that Rob produces more number of Cows than Big;

and also Big produces more number of Pigs than Rob .

Therefore , Rob has advantage in production of Cows and Big has advantage in production of pigs .

The given question is incomplete , the complete question is

Suppose that Rob and Big both raise animals and sell them. Because Rob and Big have different talents, they have varying abilities to raise these animals. In 1 day, Rob can produce either 10 cows or 20 pigs. In 1 day, Big can produce either 9 cows or 36 pigs.

Find who has the comparative advantage in the production of cows and pigs .

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