Explanation:
Start by calculating the first derivative of f(x) - use the quotient rule
ddx(f(x))=[ddx(x2)]⋅(x2+3)−x2⋅ddx(x2+3)(x2+3)2
f′=2x⋅(x2+3)−x2⋅2x(x2+3)2
f′=2x3+6x−2x3(x2+3)2=6x(x2+3)2❤
Find the measure of each angle in the problem. RE contains point P.
Answer:
∠3z = 108 degrees
∠2z = 72 degrees
Step-by-step explanation:
First, we need to create an equation.
3z + 2z = 180
5z = 180
Divide both sides by 5:
z = 36
Now, substitute z for five for both angles.
3 x 36 = 108 degrees
2 x 36 = 72 degrees
Hope this helps!
If there is something wrong, please let me know.
Please Help!
Function: y=x^2+5x-7
Vertex: (___,___)
Solutions: (___,___) and (___,___)
* i thought the vertex was (-5/2,-53,4) but apparently i’m wrong since it keeps saying it* i need answers please
Answer:
Step-by-step explanation:
Answer??? I need it in under 5 mins
Answer:
The answer is 5 units.
Step-by-step explanation:
Geometry workkkk I need help it’s due tonightttt
PLEAZE HELPPPPPPPPPP
slope of (30, 600) (75, 1050)
Answer:
y2-y1/x2-x1
y2: 1050
y1:600
x2:75
x1:30
1050-600=450
75-30=45
450/45=10
slope is 10
Answer:
let:
A(30, 600)=(x1,y1)
B((75, 1050)=(x2,y2)
now,
[tex]slope(m) = \frac{y2 - y1}{x2 - x1} [/tex]
[tex] = \frac{1050 - 600}{75 - 30} [/tex]
[tex] = \frac{450}{ 45} [/tex]
[tex] = \frac{10}{1} [/tex]
Polynomials with odd degrees typically make a "u-shaped graph" and polynomials with even degrees typically make an "s-shaped" graph.
True
False
The statement that odd degree polynomials have a u-shaped graph and even degree polynomials have an s-shaped graph is FALSE.
What do odd degree polynomials look like on a graph?Odd degree polynomials have branches that go in opposing directions which means that they will form an s-shaped graph.
Even degree polynomials on the other hand, have graphs that go in the same direction which is why they form u-shaped graphs.
In conclusion, the above statement is false.
Find out more on polynomials at https://brainly.com/question/9696642.
If a over 2 equals b over 3 then b over a equals what?
Determine the value of k so that the following system has an infinite number of solutions
10x+ky= -8
-15x-6y= 12
Please help.
Answer:
k=4
Step-by-step explanation:
remove x:
10x.(-3) + ky.(-3)=-8.(-3) (1)
-15x.2 - 6y.2 = 12.2 (2)
(1) - (2) => -3ky+12y = 0
<=> (12-3k)y = 0
so that y has infinitely many solutions then
12-3k = 0 => k=4
which expressions are equivalent to the given expression?
Answer: Choice C. [tex]\frac{1}{x^{2}y^{5} }[/tex]and Choice E. [tex]x^{-2} y^{-5}[/tex]
Step-by-step explanation:
Algebraic exponents.
(y^-8)(y^3)(x^0)(x^-2)
(y^-8)(y^3)(x^-2)
(y^-5)(x^-2)
(1) / (y^5)(x^2)
Options 3 and 5 are correct
Hope this helps!
Terry is building a tool shed with a 90 square foot base and a length that is three more than twice the width. This can be modeled by the equation (2w+15) (w-6)= 0. The length of Terry's tool shed is______ feet.
Answer:
l = 15 feet
Step-by-step explanation:
l = 2w + 3
First you solve for the width(w)
(2w+15) (w-6) = 0
This means
2w+15=0 OR. w-6=0
First let’s solve 2w+15=0
2w = -15
w = -7.5
Width can’t be negative so that can’t be the answer. So we look at the second equation w-6=0
w= 6
Since we found the width now we can find the length by using the formula l = 2w + 3
= 2(6) + 3
= 12 + 3
= 15 feet
You can check this by using the given area which is 90.
A = lw = 15*6 = 90
Find u(n):
u(0)=1, u(1)=16, u(n+2)=8*u(n+1)-16u(n)
I don't know what methods are available to you, so I'll just use one that I'm comfortable with: generating functions. It's a bit tedious, but it works! If you don't know it, there's no harm in learning about it.
Let U(x) be the generating function for the sequence u(n), i.e.
[tex]\displaystyle U(x) = \sum_{n=0}^\infty u(n)x^n[/tex]
In the recurrence equation, we multiply both sides by xⁿ (where |x| < 1, which will come into play later), then take the sums on both sides from n = 0 to ∞, thus recasting the equation as
[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = 8 \sum_{n=0}^\infty u(n+1) x^n - 16 \sum_{n=0}^\infty u(n) x^n[/tex]
Next, we rewrite each sum in terms of U(x). For instance,
[tex]\displaystyle \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=0}^\infty u(n+2) x^{n+2} \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \bigg(u(2)x^2 + u(3)x^3 + u(4)x^4 + \cdots \bigg) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \sum_{n=2}^\infty u(n) x^n \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2} \left(\sum_{n=0}^\infty u(n) x^n - u(1)x - u(0)\right) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}(U(x) - 16x - 1) \\\\ \sum_{n=0}^\infty u(n+2) x^n = \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2}[/tex]
After rewriting each sum in a similar way, we end up with a linear equation in U(x),
[tex]\displaystyle \frac1{x^2}U(x) - \frac{16}x - \frac1{x^2} = \frac8x U(x) - \frac8x - 16 U(x)[/tex]
Solve for U(x) :
[tex]\displaystyle \left(\frac1{x^2}-\frac8x+16\right) U(x) = \frac1{x^2} + \frac8x \\\\ \left(1-8x+16x^2\right) U(x) = 1 + 8x \\\\ (1-4x)^2 U(x) = 1 + 8x \\\\ U(x) = \dfrac{1+8x}{(1-4x)^2}[/tex]
The next step is to get the power series expansion of U(x) so that we can easily identity u(n) as the coefficient of the n-th term in the expansion.
Recall that for |x| < 1, we have
[tex]\displaystyle \frac1{1-x} = \sum_{n=0}^\infty x^n[/tex]
By differentiating both sides, we get
[tex]\displaystyle \frac1{(1-x)^2} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1} = \sum_{n=0}^\infty (n+1)x^n[/tex]
It follows that
[tex]\displaystyle \frac1{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n[/tex]
and so
[tex]\displaystyle \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty (n+1)(4x)^n + 8x\sum_{n=0}^\infty (n+1)(4x)^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^{n+1}(n+1)x^{n+1} \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=1}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(n+1)x^n + 2\sum_{n=0}^\infty 4^nnx^n \\\\ \frac{1+8x}{(1-4x)^2} = \sum_{n=0}^\infty 4^n(3n+1)x^n[/tex]
which means
[tex]u(n) = \boxed{4^n(3n+1)}[/tex]
anybody willing to help me?
Answer:
The answer is a. [tex] \frac{ \sqrt{w} }{ \sqrt[3]{w} }[/tex]Factor the expression completely
16x2 - 9y2
Answer:
1(16x²-9y²)
Step-by-step explanation:
1(16x²-9y²) there are no common factors or variables
El valor de "x" que es solución de la ecuación 5x + 22 = 2x + 29 es:
Answer:
x =7/ 3
Step-by-step explanation:
5x+ 22= 2x+ 29
⇔5x - 2x= 29 - 22
⇔3x = 7
⇔x = 7/3
in which quadrant angle 90+x lies 0 <x<90
Answer:
2nd quadrant
Step-by-step explanation
if an angle is between 90 and 180 degrees, it is in the second quardrant. since 0<x<90, 90+x will be more than 90 but less than 180, hence it lies in the second quadrant
Write two ratios equivalent to 24 : 9.
Answer:
8:3
16:6
Step-by-step explanation:
First, let's check if 9 and 24 have any common factor. If they do have any common ones, we must find the GCF (greatest common factor).
Factors of 9: 1, 3, 9
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
The common factors both of the numbers share and 1 and 3. To find the GCF, simply compare one of the factors to the other.
1 < 3
Now that we know the GCF, we can divide the two numbers in the ratio 24 : 9 by it (3).
24:9
24/3:9/3
8:3
Now that our ratio is simplified, it's going to be much easier to find more ratios that are equivalent. 8:3 is already one equivalent ratio, but if we multiply each number in the ratio by any other number, we can get a new equivalent ratio. Let's multiply each number in the ratio by 2:
8:3
8 ⋅ 2:3 ⋅ 2
16:6
So, another equivalent ratio to 24:9 (and 8:3) is 16:6.
QUESTION 9
Each person drinks half a litre carton of orange juice. How many cartons of orange juice do Joe's guests drink in total?
у
х
9
3
Find the value of y.
9514 1404 393
Answer:
(d) 6√3
Step-by-step explanation:
There are several ways to work multiple-choice problems. One of the simplest is to choose the only answer that makes any sense. Here, that is 6√3.
y is the hypotenuse of the medium-sized right triangle, so will be longer than that triangle's longest leg. y > 9
The only answer choice that meets this requirement is ...
y = 6√3
__
In this geometry, all of the right triangles are similar. This means corresponding sides have the same ratio. For y, we're interested in the ratio of long leg to hypotenuse.
long leg/hypotenuse = y/(9+3) = 9/y
y² = 9(9+3) = 9·4·3
y = 3·2·√3 . . . . . . take the square root
y = 6√3
__
Additional comments
You may notice that y is the root of the product of the longer hypotenuse segment (9) and the whole hypotenuse (9+3 = 12). We can say that y is the "geometric mean" of these segment lengths. Similarly (pun only partially intended), x will be the root of the product of the short segment (3) and the whole hypotenuse (12)
x = √(3·12) = 6
This is another "geometric mean" relation.
Further, the altitude will be the geometric mean of the two segments of the hypotenuse:
h = √(9·3) = 3√3
A way to summarize all of these relations is to say that the legs of the right triangle that are not the hypotenuse are equal to the geometric mean of the segments of the hypotenuse that the leg intercepts.
x = √(3·12)
y = √(9·12)
h = √(3·9)
John is trying to convert an area from meters squared to millimeters squared. He multiplied the area he had by 1,000 and got the wrong answer. What should he have multiplied the original area by?
1,000
1,000,000
10
100
Answer:
1,000,000
Step-by-step explanation:
length increased by 1000
width increased by 1000
1000 * 1000 = 1,000,000
Answer:
hlo buddy
can u msg me.......,.
Match each division expression to its quotient
[tex]\frac{122}{10}*(-\frac{10}{61} )[/tex]Let's start by calculating their values one by one, and then we can match them.
Starting with [tex]-2\frac{2}{5} \div\frac{4}{5}[/tex], we can simplify this more by adding [tex]2*5[/tex] to the nominator. That gives us [tex]-\frac{12}{5} \div\frac{4}{5}[/tex]. Now we can apply the Keep-Change-Flip rule. Keep the first fraction as it is, change the division sign into multiplication, flip the second fraction. [tex]-\frac{12}{5} *\frac{5}{4}[/tex]. We apply fraction multiplication which is simply multiplying the first nominator by the first nominator and the same for the dominator. and the result is [tex]-\frac{60}{20}[/tex] or simply -3.
[tex]-2\frac{2}{5} \div\frac{4}{5} = -3[/tex]
Now, we calculate the second one, [tex]-12.2\div(-6.1)[/tex]. This can be re-written as [tex]-\frac{122}{10}\div(-\frac{61}{10} )[/tex]. As we did in the previous part we apply the Keep-Change-Flip, this will give us [tex]-\frac{122}{10}*(-\frac{10}{61} )[/tex]. Do the multiplication and the result will be [tex]\frac{1220}{610}[/tex], we can divide both the nominator and dominator by 10 which will result [tex]\frac{122}{61}[/tex] and finally we know that [tex]61*2=122[/tex] and we can divide both of them again by 61 which will result [tex]\frac{2}{1} =2[/tex]
[tex]-12.2\div(-6.1)=2[/tex]
You can try solving the rest by yourself but here's is the final answer for them both:
[tex]16\div(-8)=-2\\3\frac{3}{7} \div1\frac{1}{7} =3[/tex]
write your answer in simplest radical form
Answer:
[tex]9\sqrt{3}[/tex]
Step-by-step explanation:
This is a 30-60-90 triangle.
It's good to remember this. The side length opposite to the 60 degree angle is always the base multiplied by [tex]\sqrt{3}[/tex]
Answer:
9√3.
Step-by-step explanation:
tan 60 = √3
So w/9 =√3
w = 9√3
Năm báo cáo:
- Tồn cuối năm: trong kho: 800 sp; gửi bán: 1200sp
- Số lượng sản xuất: 10.000 sp
- Giá bán: 100.000 đồng/sp
Năm kế hoạch:
- Dự kiến số lượng sản xuất tăng 10%
- Tồn cuối năm: tăng 10% so với năm báo cáo
- Giá bán: 95.000 đồng/sp
- Giá vốn 1 sp: 79.500 đồng (tăng 6% so với năm báo cáo)
Yêu cầu:
1/ Tính doanh thu năm kế hoạch
2/ Tính giá vốn hàng bán năm kế hoạch (FIFO)
Answer:
THE ANSWER IS
identify an equation in point slope form for the line perpendicular to the y=-1/2x+11 that passes through (4,-8). a. y+8=1/2(x-4) b. y-4=2(x+8) c. y-8=1/2(x+4) d. y+8=2(x-4)
Answer:
d. y+8=2(x-4)
Step-by-step explanation:
There are 2 important parts to this question. First, understanding which slopes are perpendicular. The negative reciprocal of a number will be perpendicular to it. So, since the original slope is -1/2 the new slope should be 2.
Then, remember what the point-slope formula is. The point-slope formula is: [tex]y-y_{2}=m(x-x_{2})[/tex]. So if you plug in the point and slope the new equation looks like, [tex]y--8=2(x-4)[/tex]. Then, simplify for the final answer of [tex]y+8=2(x-4)[/tex].
Please due in 1 hour
I hope that helped you
9514 1404 393
Answer:
d + q = 440.10d +0.25q = 8.30Step-by-step explanation:
The first equation describes the total number of coins. It says the sum of the numbers of dimes and quarters is 44, the total number of coins.
__
The second equation describes the total value of the coins. It will say that 0.10 times the number of dimes plus 0.25 times the number of quarters is 8.30, the total dollar value of the coins.
The two equations are ...
d + q = 44
0.10d +0.25q = 8.30
__
Additional comment
The solution can be found by substituting for d:
0.10(44 -q) +0.25q = 8.30
0.15q = 3.90
q = 26
d = 44 -26 = 18
Vinnie has 18 dimes and 26 quarters in his bag.
Find the line integral with respect to arc length ∫C(9x+5y)ds, where C is the line segment in the xy-plane with endpoints P=(2,0) and Q=(0,7).
(a) Find a vector parametric equation r⃗ (t) for the line segment C so that points P and Q correspond to t=0 and t=1, respectively
(b) Rewrite integral using parametrization found in part a
(c) Evaluate the line integral with respect to arc length in part b
(a) You can parameterize C by the vector function
r(t) = (x(t), y(t) ) = P (1 - t ) + Q t = (2 - 2t, 7t )
where 0 ≤ t ≤ 1.
(b) From the above parameterization, we have
r'(t) = (-2, 7) ==> ||r'(t)|| = √((-2)² + 7²) = √53
Then
ds = √53 dt
and the line integral is
[tex]\displaystyle\int_C(9x(t)+5y(t))\,\mathrm ds = \boxed{\sqrt{53}\int_0^1(17t+18)\,\mathrm dt}[/tex]
(c) The remaining integral is pretty simple,
[tex]\displaystyle\sqrt{53}\int_0^1(17t+18)\,\mathrm dt = \sqrt{53}\left(\frac{17}2t^2+18t\right)\bigg|_{t=0}^{t=1} = \boxed{\frac{53^{3/2}}2}[/tex]
Can somebody help me find the answer to this problem please ?
Answer:
Step-by-step explanation:
Answer:
D. x = -2y + 4
Step-by-step explanation:
4x + 8y = 16
Solve for x
Our objective here is to isolate x ( in other words we want to get x by itself ) using inverse operations.
So let's begin
4x + 8y = 16
First we want to get rid of 8y
Notice how 8y is being added to 4x
Well we can get rid of it by applying it's inverse operation. The opposite of addition is subtraction. So to get rid of 8y we would simply subtract 8y.
Important note! Whatever we do to one side we must do to the other
So we would subtract 8y from both sides
4x + 8y - 8y = 16 - 8y
The 8y on the left hand side cancels out and the 8y on the right side stays as it is as you can't subtract 8y from 16
We then have 4x = 16 - 8y
Next we want to get rid of 4 from 4x.
4x is the same as 4*x which is multiplication
The inverse of multiplication is division so to get rid of the 4 we divide both sides by 4
4x/4 = (16-8y)/4
4x/4 = x
16-8y/4 ( simply divide 16 by 4 and -8y by 4 )
16-8y/4 = 4 - 2y
We're left with x = 4 - 2y which can also be written as x = -2y + 4
Given the following coordinates complete the glide reflection transformation.
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Answer:
A"(-1, -2)B"(4, 0)C"(6, -3)Step-by-step explanation:
The reflection over the x-axis is ...
(x, y) ⇒ (x, -y)
The shift left 3 units is ...
(x, y) ⇒ (x -3, y)
So, the two transformations together will be ...
(x, y) ⇒ (x -3, -y)
A(4, 2) ⇒ A"(1, -2)
B(7,0) ⇒ B"(4, 0)
C(9, 3) ⇒ C"(6, -3)
I need you guy’s help answer thanks so much
Answer:C
Step-by-step explanation:
PLEASE HELPPPPPPPPPP
Answer:
167/346 or 0.483
Step-by-step explanation:
From the question given above, the following data were obtained:
Number of Tails (T) = 167
Number of Heads (H) = 179
Probability of tail, P(T) =?
Next, we shall determine total outcome. This can be obtained as follow:
Number of Tails (T) = 167
Number of Heads (H) = 179
Total outcome (S) =?
S = T + H
S = 167 + 179
Total outcome (S) = 346
Finally, we shall determine the probability of tails. This can be obtained as follow:
Number of Tails (T) = 167
Total outcome (S) = 346
Probability of tail, P(T) =?
P(T) = T / S
P(T) = 167 / 346
P(T) = 0.483
Thus, the probability of tails is 167/346 or 0.483
