What is the IUPAC name of the following compounds i. CO₂ ii. NO₂ iii. HNO3 iv. H₂SO4 v. K-Cr₂O vi. [Fe(CN)

Answers

Answer 1

Explanation:

I) carbon dioxide

ii) nitrogen dioxide

iii) nitric acid

iv) sulphric acid

v) Potassium dichromate

vi) hexacyanoferrate (III) ion( not sure)


Related Questions

How many xenon atoms are contained in 1.00 moles of xenon?

Answers

Answer:

6.022 x 10²³

Explanation:

The number of atoms =  the number of moles x with the Avogadro's number.

(The Avogadro's number is 6.022 x 10²³ atoms / moles)

number of atoms = 1.00 moles x 6.022 x 10²³ atoms / mole

number of atoms =  6.022 x 10²³ atoms

(There is no need to simplify?) = 6.022 x 10²³

(ps. This is my first time doing this question so im sorry if i got it wrong

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Dilution
A chemist makes 620. ml. of zinc nitrate • (Zn(NO3)₂) working solution by adding distilled water to 210. mL of a 4.93 M stock solution of zinc nitrate in water.
Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

Answers

1.66 M is the concentration of the chemist's working solution.

What is molarity?

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

In this case, we have a solution of Zn(NO₃)₂.

The chemist wants to prepare a dilute solution of this reactant.

The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.

We want to know the concentration of this diluted solution.

As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:

[tex]n_1[/tex]= [tex]n_2[/tex]  (1)

and we also know that:

n = M x [tex]V_2[/tex]

If we replace this expression in (1) we have:

[tex]M_1[/tex] x [tex]V_1[/tex]= [tex]M_2[/tex] x [tex]V_2[/tex]

Where 1, would be the stock solution and 2, the solution we want to prepare.

So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is [tex]M_2[/tex]:

4.93 x 210 =  620 x[tex]M_2[/tex]

[tex]M_2[/tex] = 1.66 M

This is the concentration of the solution prepared.

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Identify if phosphorous is paramagnetic or diamagnetic and explain why.

Answers

Due to the presence of three unpaired electrons, phosphorus is paramagnetic.

Electronic configuration of Phosphorus:-

[Ne] 3S2  3P3

What determines if an element is paramagnetic or diamagnetic?

By looking at a substance's electron configuration, one can identify whether or not it has magnetic qualities. If a substance has unpaired electrons, it is paramagnetic; if all of its electrons are paired, it is diamagnetic.

Paramagnetic:-

A tiny, positive susceptibility to magnetic fields exists in materials. When exposed to a magnetic field, these materials are only weakly drawn to it; once the external field is removed, they lose their magnetic qualities.

Diamagnetic:-

A weak, negative sensitivity to magnetic fields exists in materials. When exposed to a magnetic field, diamagnetic materials are partially repulsed and lose their magnetic properties when the external field is removed.

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Which of the following is the best example of an isolated system?
OA. A bus at a bus station
B. An astronaut in a spaceship
OC. A car on the freeway
D. A motorcycle in a garage

Answers

Answer:

B. An astronaut in a spaceship

Isolated system :-

In an isolated system, there is no transfer of energy or matter between the system and the environment.

Hope it helps!

B. An astronaut in a spaceship

Which hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine?

Correct Answer is B

Answers

Answer:

C.) Csp² - Nsp³

Explanation:

Because the carbon has only 3 unique bonds, the conformation of the carbon should be Csp² (s + p + p). While the nitrogen also has only 3 bonds, making up 3 orbitals, it also has a lone pair of electrons. These electrons also take up one orbital. Therefore, the conformation of nitrogen is Nsp³ (s + p + p + p).

The hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.

What is hybridization?

Hybridization is defined as the concept of the mixing of the atomic orbitals for the formation of new hybrid orbitals which are suitable for the pairing of electrons in forming chemical bonds in valence bond theory. And the orbital formed by the hybridization are termed as hybrid orbitals.

Since the carbon atom form one single bond with hydrogen atom and one pi bond with nitrogen bond, so the conformation of carbon atom is Csp2. On the other hand, nitrogen also form one single bond and a pi bond, so it also contribute three hybrid orbital. Since it have one lone pair of nitrogen so they take one orbitals. Therefore, the conformation of nitrogen atom is Nsp3.

Thus, we concluded that the hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.

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Na2 C6H6O7 (sodium hydrogen citrate)
Express the mass of sodium to three significant figures.
mNa =

Answers

The exact mass of one Na - atom is 22.98977 amu and thus, the weight of two sodium atoms in present in Na₂C₆H₆O₇ is 45.979539 g/mol.

What is Molar mass ?

The molar mass of a substance is the mass in grams of 1 mole of the substance.

We can obtain a substance's molar mass by summing the molar masses of its component atoms.

Mass of one Na atom = 22.98977

Mass of two Na atom = 22.98977 x 2

                                   

                                      = 45.97954

                                       = 45.9 (up to 3 Significant figures)

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Which are the product(s) of this chemical reaction? FeCl 3 + 3NH 4OH ->
a. 3NH4Fe + Cl3OH
b. 3FeCl3NH4OH
c. 3NH4Cl + 3FeOH
d. Fe(OH)3 + 3NH4Cl ​

Answers

The answer is D

FeCl3 + 3 NH4OH → Fe(OH)3 + 3 NH4Cl

In the laboratory you dissolve 12.2 g of iron(II) iodide in a volumetric flask and add water to a total volume of 500 mL.

What is the molarity of the solution?
M.

What is the concentration of the iron(II) cation?
M.

What is the concentration of the iodide anion?
M.

In the laboratory you dissolve 16.8 g of iron(III) sulfate in a volumetric flask and add water to a total volume of 250 mL.

What is the molarity of the solution?
M.

What is the concentration of the iron(III) cation?
M.

What is the concentration of the sulfate anion?

M.
You wish to make a 0.271 M hydrobromic acid solution from a stock solution of 12.0 M hydrobromic acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution?

mL

Answers

Question 1

1) The formula of iron(II) iodide is [tex]\text{FeI}_{2}[/tex] and has a formula mass of 309.654 g/mol. This means that in 12.2 grams, there are

12.2/309.654 = 0.039398812868557 mol.

So, the molarity is (0.039398812868557)/(0.5) = 0.0788 M (to 3 sf)

2) In 0.039398812868557 mol of iron(II) iodide, there are 0.039398812868557 moles of iron(II) iodide cations, and thus the molarity is still 0.0788 M (to 3 sf)

3) In 0.039398812868557 mol of iron(II) iodide, there are

2(0.039398812868557) = 0.078797625737114 moles of iodide anions

Thus, the molarity is (0.078797625737114)/(0.5) = 0.158 M (to 3 sf)

Question 2

1) The formula of iron(III) sulfate is [tex]\text{Fe}_{2}\text{(SO}_{4})_{3}[/tex] and has a formula mass of 399.9 g/mol. This means that in 16.8 grams, there are

16.8/399.9 = 0.042010502625656 mol

So, the molarity is (0.042010502625656)/(0.25) = 0.168 M (to 3 sf)

2) In 0.042010502625656 moles of iron(III) sulfate, there are 2(0.042010502625656)=0.084021005251312 moles of iron(III) cations, so the molarity is:

0.084021005251312/0.25 = 0.336 M (to 3 sf)

3) In 0.042010502625656 moles of iron(III) sulfate, there are 3(0.042010502625656)=0.12603150787697 moles of sulfate anions, so the molarity is:

0.12603150787697/0.25 = 0.504 M (to 3 sf)

Question 3

Since we need 50.0 mL of solution at 0.271 M,

0.271 = (moles of HBr)/(0.05) moles of HBr = 0.01355 mol

So, we need this from 12.0 M HBr so, meaning that:

12.0 = (0.01355)/(liters of 12.0 M HBr stock solution)liters of 12.0 M HBr stock solution = 0.0011291666666667 L = 1.13 M (to 3 sf)

Calculate the standard enthalpy change associated with this reaction at 25 °C using the
following enthalpies of formation:
CH4 ∆Hf = -62.7 kJ·mol–1, CO2 ∆Hf = -393.5 kJ·mol–1, H2O ∆Hf = -285.8 kJ·mol–1.

Answers

The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ

What is Standard Enhalpy change ?

The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions, and with everything in its standard state.

According to the balanced chemical equation ;

CH₄(g) + 2O₂(g) ⟶ CO₂(g) + 2H₂O(l)

Now,

ΔH⁰ = ΔH⁰f(products) − ΔH⁰f(reactants)

       = [ΔH⁰(CO₂) +ΔH⁰(H₂O)] − [ΔH⁰(CH₄) + 2ΔH⁰(O₂)]

       = [−393.5 + 2 x (−285.8)] − [−62.7 + 2 x 0]

       

        = − 902.4 kJ

Hence, The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ

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M1 = 3M M2 = 1.25M V1 = V1=.125L unkown What is V2?

Answers

0.3 L is the final volume when M₁ = 3 M, V₁ = 0.125L, M₂ = 1.25M.

What is volume?

The amount of space occupied by a three-dimensional figure as measured in cubic units.

Given data:

M₁ = 3 M

V₁ = 0.125L

M₂ = 1.25M

V₂ = ?

Solution:

M₁V₁ = M₂V₂

3 M × 0.125L = 1.25M × V₂

V₂ = 0.3 L

Hence, 0.3 L is the final volume.

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The average speed of a diatomic fluorine molecule at 25 ∘C is 442.4 m⋅s−1 . What is the average wavelength of a fluorine molecule at this temperature? Assume that the molecule acts as a single particle

Answers

The average wavelength of the fluorine molecule will be 2.36 × 10⁻¹¹ metres.

Fluorine Molecule's Speed = 442.4 m/s

The Molar Mass of the F₂ = 38 g/mol

Now as we know that any molecule's

1 mole contain  = 6.022 × 10²³ Molecule

So, 1 Fluorine molecule mass =

Fluorine's Molar mass / Number of Fluorine molecule in 1 mole

So, 1 Fluorine molecule mass = 38 / ( 6.022 × 10²³ )

1 Fluorine molecule mass = 6.31 × 10⁻²³ g

1 Fluorine molecule mass = 6.31 × 10⁻²⁶  Kg

So molecule's momentum = Molecule's mass × Molecule's Velocity

So molecule's momentum = ( 6.31 × 10⁻²⁶ ) × 442.4

So molecule's momentum = 2.8 × 10⁻²³  Kg.m/s

Now wavelength of Fluorine molecule = λ = planks constant / momentum

wavelength of Fluorine molecule = λ = ( 6.626 × 10⁻³⁴ ) / ( 2.8 × 10⁻²³ )

wavelength of Fluorine molecule = λ = 2.36 × 10⁻¹¹ metre

So the wavelength of the diatomic fluorine molecule came out to be 2.36 × 10⁻¹¹ metres after applying all the concepts and formulas.

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How does temperature affect Keq of a reaction

Answers

In an endothermic reaction, Keq increases as the temperature increases and vice versa.

In an exothermic reaction, Keq decreases as the temperature increases and vice versa.

Keq is the equilibrium constant of a reaction. The equilibrium constant is independent of the concentrations of the reactants and productsThe only factor that the equilibrium constant depends on is the temperature of the system of reactionIn an endothermic reaction, energy is gainedSo a higher temperature is more favourable in an endothermic reactionAs a result, more products are formed at a higher temperature, leading to a higher value of KeqIn an exothermic reaction, energy is releasedSo a lower temperature is more favourable in an exothermic reactionAs a result, fewer products are formed at a higher temperature, leading to a lower value of Keq

Therefore, the temperature is the only factor that affects the equilibrium constant of a reaction.

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How much heat (in joules) does it take to heat 180 g of water from 24 °C to 66 °C? The heat capacity of water is 4.184 J/(g · °C). You may round your answer to the nearest 100 J

Answers

Answer:31,631.04

Explanation: multiply final temp with initial temp = 42 then multiplied by grams = 7,560 then multiplied by J = 31,631.04

How many grams of hydrogen gas are produced from 2.50 mol of water?
__Ca(s) + __H2O(l) → __Ca(OH)2(aq) + __H2(g)

Answers

Answer:

2.52 g H₂

Explanation:

To find the mass of hydrogen gas, you need to (1) convert moles H₂O to moles H₂ (via mole-to-mole ratio from reaction coefficient) and then (2) convert moles H₂ to grams H₂ (via molar mass from periodic table values). When multiplying the given value by the mole-to-mole ratio, you need to use the coefficients of the balanced equation. An reaction is balanced once there is an equal amount of each element on both sides.

(Step 1)

The unbalanced equation:

Ca(s) + H₂O(l) ----> Ca(OH)₂(aq) + H₂(g)

Reactants: 1 calcium, 2 hydrogen, 1 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

The balanced equation:

1 Ca(s) + 2 H₂O(l) ----> 1 Ca(OH)₂(aq) + 1 H₂(g)

Reactants: 1 calcium, 4 hydrogen, 2 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

(Step 2)

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

(Step 3)

 2.50 moles H₂O              1 mole H₂                  2.016 g
---------------------------  x  -------------------------  x  ----------------------  =  2.52 g H₂
                                        2 moles H₂O                1 mole

If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of KCI in the resulting solution?

Answers

1.199 M is the concentration of KCI in the resulting solution.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

No.of moles of KCI

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]

= 0.599 moles

Vol.of the solution,V= 500 ml

= 0.5 liter

Molarity

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]

= 1.199 M

Hence, 1.199 M is the concentration of KCI in the resulting solution.

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Need ASAP please and thank you

Answers

The empirical formula would be  [tex]C_2H_3O_2[/tex] and the molecular formula would be  [tex]C_4 H_6 O_4[/tex]

Empirical and molecular formula

From the illustration:

C = 40.6 g                   H = 5.1 g                      O = 54.2 g

Divide each element by its molar weight:

C = 40.6/12 = 3.4                    H = 5.1/1 = 5.1                  O = 54.2/16 = 3.4

Divide by the smallest:

C = 3.4/3.4 = 1                        H = 5.1/3.4 = 1.5                 O = 3.4/3.4 = 1

Thus, the empirical formula is [tex]C_2H_3O_2[/tex]

To find the molecular formula:

[ [tex]C_2H_3O_2[/tex]]n = molecular formula

where n = molar mass/empirical formula mass

Empirical formula mass = 24 + 3 + 32 = 59

n = 118.084/59 = 2

Thus, the molecular formula is [tex]C_4 H_6 O_4[/tex] which is more or less the same as the empirical formula.

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The Empirical formula will be C₂H₃O₂  and the Molecular formula would be  C₄H₆O₄

What is Empirical and Molecular Formula ?

Empirical formula is a formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

Molecular formula is a chemical formula that gives the total number of atoms of each element in each molecule of a substance.

Given ;

C = 40.6 gH = 5.1 gO = 54.2 g

Divide each element by its molar weight:

C =  40.6 / 12 = 3.4H = 5.1 / 1 = 5.1                 O = 54.2 / 16 = 3.4

Divide by the smallest Value:

C = 3.4/3.4 = 1H = 5.1/3.4 = 1.5                O = 3.4/3.4 = 1

Thus, the Empirical formula is C₂H₃O₂

Now, to find the molecular formula ;

[C₂H₃O₂ ]n = molecular formula

where n = molar mass / empirical formula mass

Empirical formula mass = 24 + 3 + 32 = 59

n = 118.084 / 59 = 2

[C₂H₃O₂ ]n = molecular formula

[C₂H₃O₂ ]2 = C₄H₆O₄

Thus, the Molecular formula is C₂H₃O₂

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Pure water boils at 100°C.
What happens to the water particles when water
boils?

A They gain energy and move further apart.
B They gain energy and stay close together.
C They lose energy and move further apart.
D They lose energy and stay close together.

Answers

Answer:

A

Explanation:

1. Write the reaction rate expressions for the following reactions in terms of the disappearance of the reactants and the appearance of products: 1-(aq)+ OCI-(aq)-CI-(aq)+OI-(aq)

Answers

In terms of the disappearance of the reactants, the rate equations are R= -kd[I-]/dt and  -kd[OCl-]/dt.

What is an ionic reaction?

The term ionic reaction refers to the reaction that takes place between two ions. In this case, the ionic reaction is; I-(aq) + OCl-(aq) -------> Cl-(aq) + OI-(aq).

The rate equations in terms of the disappearance of the reactants is;

R= -kd[I-]/dt

And

R = -kd[OCl-]/dt

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Sort the length measurements in increasing order of magnitude from smallest to largest.

Answers

The length measurements in increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.

What is Measurement ?

Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events.

Measurement is a process of determining how large or small a physical quantity is as compared to a basic reference quantity of the same kind.

Hence, Among the given length measurements, The increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.

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An unknown gas effuses at a rate of 2.0 times the rate of Cl₂. What is the molar mass of the unknown gas?

Answers

The molar mass of the unknown gas is determined as 17.75 g.

Rate of gas diffusion

The rate of gas diffusion is given by Graham's law.

R₁√M₁ = R₂√M₂

where;

R₁ is the rate of diffusion of the unknown gasM₁ is the molecular mass of the unknown gasR₂ is rate of diffusion of chlorine gasM₂ is the molecular mass of chlorine gas

[tex]\frac{R_1}{R_2} = \sqrt{\frac{M_2}{M_1} } \\\\\frac{2R_2}{R_2} = \sqrt{\frac{71}{M_1} }\\\\2 = \sqrt{\frac{71}{M_1} }\\\\2^2 = \frac{71}{M_1} \\\\M_1 = \frac{71}{4} \\\\M_1 = 17.75 \ g[/tex]

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Hybridization of bromine in SF4 and arsenic in SF2

Answers

Answer:

The answer is C

What are the rows of the periodic table called?
A. Periods
B. Elements
C. Atoms
D. Groups

Answers

Answer:

i believe its called A. periods

a 20.0mL sample of 0.15M hydrochloric acid (HCI) is needed to neutralize a 10.0mL sample of potassium hydroxide (KOH). what is the molarity of KOH solution?

Answers

Answer: .75 M

Explanation:

In the reaction of 675.9 grams of barium chloride and excess silver(I) nitrate, how many grams of silver(I) chloride should get formed?

i dont understand, show work pls ty

Answers

Taking into account the reaction stoichiometry, the mass of silver(I) chloride formed is 930.37 grams.

Reaction stoichiometry

In first place, the balanced reaction is:

2 AgNO₃ + BaCl₂ → 2 AgCl + Ba(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgNO₃: 2 moles BaCl₂: 1 moleAgCl: 2 molesBa(NO₃)₂: 1 mole

The molar mass of the compounds is:

AgNO₃: 169.87 g/moleBaCl₂: 208.24 g/moleAgCl: 143.32 g/moleBa(NO₃)₂: 261.34 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

AgNO₃: 2 moles ×169.87 g/mole= 339.74 grams

BaCl₂: 1 mole ×208.24 g/mole= 208.24 grams

AgCl: 2 moles ×143.32 g/mole= 286.64 grams

Ba(NO₃)₂: 1 mole×261.34 g/mole= 261.34 grams

Mass of silver(I) chloride formed

The following rule of three can be applied:  if by reaction stoichiometry 208.24 grams of barium chloride form 286.64 grams of silver(I) chloride, 675.9 grams of barium chloride form how much mass of silver(I) chloride?

[tex]mass of silver(I) chloride=\frac{675.9 grams of barium chloride x286.64 grams of silver(I) chloride }{208.24 grams of barium chloride}[/tex]

mass of silver(I) chloride= 930.37 grams

Finally, the mass of silver(I) chloride formed is 930.37 grams.

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We do not want all staff being able to access all records that we hold. How can you ensure traceability and accessibility to the data stored?​

Answers

To ensure data traceability and accessibility is to complete a study beginning-to-end on a closed system or platform.

How can you ensure traceability and accessibility to the data stored ?

Lean On Self-Service Business Intelligence. Embed Dashboards Into Your Teams' Tools. Facilitate Data Literacy Throughout the Company. Embrace Your Changing Role.

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I need help with this one bad

Answers

Explanation:

it applies to pressure laws

Calculate the mass of pure sodium chloride will yield enough hydrogen chloride gas to tralize 25 cm² of 0.5 M potassium trioxo- bonate(IV) solution. NACI=58.5, HC1 = 36.5, K,CO, = 138)​

Answers

It equals k, Co =138

What information does a net ionic equation give that the complete ionic equation does not show?

Answers

A complete ionic equation shows ions formed from each of the species. It also show the charge on each of the ions.It also shows all reactants as compounds or elements. The ions formed and their charges can only be inferred from this equation.

What is a Net Ionic equation ?

The net ionic equation shows  the chemical species involve in chemical reaction while the complete ionic equation also involve the spectator ions.

What are Spectator ions ?

These ions are same in both side of chemical reaction and thus cancels out each other.

Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

The net ionic equation state that whether precipitation is occur or not.

If the chemical reaction have no net ionic equation it means all are in aqueous from not precipitation occur.

Consider the following example:

Balanced Chemical equation:

HClO₂(aq) + NaOH(aq) → H₂O(l) + NaClO₂ (aq)

Ionic equation:

H⁺(aq) + ClO₂⁻(aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + ClO₂⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The ClO₂⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation.

The water can not be splitted into ions because it is present in liquid form.

Hence, The net ionic equation shows  the chemical species involve in chemical reaction while the complete ionic equation also involve the spectator ions.

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Sunspot populations quickly rise and more slowly fall on an irregular cycle about every 11 years. Significant variations of the 11-year period are known over longer spans of time. For example, from 1900 to the 1960s the solar maxima (the period of greatest activity in the solar cycle of the sun) trend of sunspot count has been upward; from the 1960s to the present, it has diminished somewhat. The Sun is presently at a markedly heightened level of sunspot activity and was last similarly active over 8,000 years ago.
The number of sunspots correlates with the intensity of solar radiation over the period (since 1979) when satellite measurements of absolute radiative flux were available. Since sunspots are darker than the surrounding photosphere it might be expected that more sunspots would lead to less solar radiation and a decreased solar constant. However, the surrounding margins of sunspots are hotter than the average, and so are brighter; overall, more sunspots increase the sun's solar constant or brightness. During the Maunder Minimum in the 17th Century there were hardly any sunspots at all. The Maunder Minimum is the name given to the period roughly from 1645 to 1715, when sunspots became exceedingly rare, as noted by solar observers of the time. It is named after the solar astronomer Edward W. Maunder (1851-1928) who discovered the dearth of sunspots during that period by studying records from those years. During one 30-year period within the Maunder Minimum, for example, astronomers observed only about 50 sunspots, as opposed to a more typical 40,000-50,000 spots. This coincides with a period of cooling known as the Little Ice Age.
1) Which of the following is a true statement?:
A. There were more sunspots in 1965 than in 1701
B. The Little Ice Age had nothing to do with sunspots
C. The Sun is presently at a low level of sunspot activity
D. No one is counting sunspot activity any more

Answers

The Sun is presently at a low level of sunspot activity. Hence, option C is correct.

What is solar radiation?

Solar radiation is often called the solar resource for the electromagnetic radiation emitted by the sun.

The Sun is presently at a low level of sunspot activity is the correct answer.

Hence, option C is correct.

Learn more about the solar radiation here:

https://brainly.com/question/16525532

#SPJ1

D...
W...
m...
A student runs two experiments with a constant-volume "bomb" calorimeter
containing 1400. g of water (see sketch at right).
sam....
First, a 5.000 g tablet of benzoic acid (C6H5CO₂H) is put into the "bomb" and
burned completely in an excess of oxygen. (Benzoic acid is known to have a heat of
combustion of 26.454 kJ/g.) The temperature of the water is observed to rise from
13.00 °C to 32.28 °C over a time of 10.7 minutes.
ry Sy...
an Am...
Next, 4.900 g of ethane (C₂H6) are put into the "bomb" and similarly completely
burned in an excess of oxygen. This time the temperature of the water rises from
13.00 °C to 44.56 °C.
Use this information, and any other information you need from the ALEKS Data
resource, to answer the questions below about this reaction:
-
stirrer
Is this reaction exothermic, endothermic, or neither?

thermometer
chemical reaction
"bomb"
A "bomb" calorimeter.
If you said the reaction was exothermic or endothermic, calculate the amount of heat that was
released or absorbed by the reaction in the second experiment.
2C₂H,(g) + 70₂(g) 4CO₂(g) + 6H₂O(g)
Be sure any of your answers that are calculated from measured data are rounded to the correct number of significant digits.
Note for advanced students: it's possible the student did not do these experiments sufficiently carefully, and the values you
calculate may not exactly match published values for this reaction.
exothermic
Oendothermic
neither
water
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Answers

Answer:

I don't know ok sorry

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