Which graph shows the solution to the system of linear inequalities?
y≥ 2x + 1
y≤2x-2

11/36 would be the probability of getting 4 , when two dice are thrown simultaneously.

As there are 6 faces of die,
So Probability of Not getting four in one dice = [tex]5/6[/tex]

As both events are mutually exclusive, the probability of not getting four in two dice = [tex](5/6) * (5/6) = 25/36[/tex]

So probability of getting at least one four is = [tex]1-(25/36) = 11/36[/tex]

So probability = [tex]11/36[/tex]

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The system of the linear inequality that fulfill the condition of the graph will be y ≥ 2x – 1 and y ≤ 1/3 x + 1. Then the correct option is A.

The complete question is attached below.

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

The system of the linear inequality that fulfill the condition of the graph will be

y ≥ 2x – 1

y ≤ 1/3 x + 1

Then the correct option is A.

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Given that f(x) = x/(x - 3) and g(x) = 1/x and the application of function operators, f ° g (x) = 1/(1 - 3 · x) and the domain of the resulting function is any real number except x = 1/3.

Let be f and g functions. Composition is a binary function operation where the variable of the former function (f) is substituted by the latter function (g). If we know that f(x) = x/(x - 3) and g(x) = 1/x, then the composed function is:

[tex]f\,\circ\,g \,(x) = \frac{\frac{1}{x} }{\frac{1}{x}-3}[/tex]

[tex]f\,\circ\,g\,(x) = \frac{\frac{1}{x} }{\frac{1-3\cdot x}{x} }[/tex]

[tex]f\,\circ\,g\,(x) = \frac{1}{1-3\cdot x}[/tex]

The domain of the function is the set of x-values such that f ° g (x) exists. In the case of rational functions of the form p(x)/q(x), the domain is the set of x-values such that q(x) ≠ 0. Thus, the domain of f ° g (x) is [tex]\mathbb{R} - \{\frac{1}{3} \}[/tex].

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The analytical approach is preferable because the primary issue with Euclidean geometry is that it is not enough to support all of the theorems that he claims to establish.

It is defined as the branch of mathematics that is concerned with the size, shape, and orientation of two-dimensional figures.

As we have given about the Euclidean and analytical geometry.

Without using any numerical measurements, we have investigated the connections between points, lines, and planes in Euclidean geometry.

In analytical geometry, we've looked at how the locations of points in a Cartesian coordinate system related to algebra and geometry.

The analytical approach is preferable because the primary issue with Euclidean geometry is that it is not enough to support all of the theorems that he claims to establish.

If the Euclidean geometry can be more advantageous in particular circumstances

Example: If using terrain or building chart),

Thus, the analytical approach is preferable because the primary issue with Euclidean geometry is that it is not enough to support all of the theorems that he claims to establish.

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Answer:

Define different tipes of discontuinity of a function .also,write the condition for increasing, decreasing and concave of function

Answer:

option B is correct

To write any equations in the form of matrix

first make a matrix of all coefficients of that equations.. here coefficients of first equation is 4 and - 2 and that of second is 0 ( as there is no value of X) and 3

then make second matrix of X and y

last of answer of the equations, here (-7 ) and 5

The coordinate of the point P is (-11/4, -1/2) option (C) is correct because point (-29/4, -3/2) lies on the line.

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have a line segment shown in the picture:

From the graph:

Point A( -5, -1) and B(4, 1)

The equation of the line passing through the points:

[tex]\rm (y -1 ) = \dfrac{1+1}{4+5}(x-4)[/tex]

9(y - 1) = 2(x - 4)

The above equation shows the straight-line passing through points A and B.

From the graph point (-11/4, -1/2) lies on the line the coordinate of the point P is (-29/4, -3/2)

Thus, the coordinate of the point P is (-11/4, -1/2) option (C) is correct because point (-29/4, -3/2) lies on the line.

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Answer:

x = [tex]\frac{7}{5}[/tex]

Step-by-step explanation:

To solve for x, we need to isolate it [get it alone on one side]

We should start by simplifying (combining the like-terms of our equation):

5 + 5 = 5x + 5 - 2

10 = 5x + 3

- 3         - 3        (subtract 3 from both sides to isolate x)

7 = 5x

÷5  ÷5   (divide both sides by 5 to find "1"x)

[tex]\frac{7}{5}=x[/tex]  

So, x = [tex]\frac{7}{5}[/tex]

(x = 7/5)

hope this helps!!

5 + 5 = 5x + 5 - 2

Answer :

[tex]x = \frac{7}{5} [/tex]

Step-by-step explanation:

5 + 5 = 5x + 5 - 2

10 = 5x + 3

Take 3 to the other side

10 - 3 = 5x

7 = 5x

[tex] \frac{7}{5} = x[/tex]

[tex]x = \frac{7}{5} [/tex]

The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²)  + 4x² = 1

An equation is an expression that shows the relationship between two or more variables and numbers.

In polar form:

r = √(x² + y²) and cosФ = x / √(x² + y²)

Hence:

r(1 - 2cosФ) = 1

√(x² + y²) [1 - 2(x / √(x² + y²))] = 1

√(x² + y²) - 2x = 1

Take square of both sides:

x² + y² - 4x√(x² + y²)  + 4x² = 1

The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²)  + 4x² = 1

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Answer:

(3, 2)

Step-by-step explanation:

To be considered part of a solution set for the inequality provided, a given point must lie within the shaded region that is graphed. Since we want to find the point that is not included in the solution set for the inequality, we need to find the point that does not lie in the shaded region.

Let's test each point to see which doesn't lie in the region. Refer to the image below if you're having trouble graphing the points:

Hope this helps!

Answer:

See below ~

Step-by-step explanation:

1) a) 50 km / 2 h

⇒ 25 km/h

b) 540 kg / 3 days

⇒ 180 kg/day

c) 125 m / 5 min.

⇒ 25 m/min.

A unit rate means a rate for one of something. We write this as a ratio with a denominator of one. For example, if you ran 70 yards in 10 seconds, you ran on average 7 yards in 1 second. Both of the ratios, 70 yards in 10 seconds and 7 yards in 1 second, are rates, but the 7 yards in 1 second is a unit rate…

a) 50km/2h

=> 25 kilometers per hour

b) 540kg/3d

=> 180 kilogram per day

c) 125m/5min

=> 25 meter per minute

Answer:

[tex]x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]

Step-by-step explanation:

Given equation:

[tex]x^2+3x-9=0[/tex]

Completing the square

Move the constant to the right side by adding 9 to both sides:

[tex]\implies x^2+3x=9[/tex]

Add the square of half the coefficient of x to both sides:

[tex]\implies x^2+3x+\left(\dfrac{3}{2}\right)^2=9+\left(\dfrac{3}{2}\right)^2[/tex]

[tex]\implies x^2+3x+\dfrac{9}{4}=\dfrac{45}{4}[/tex]

Factor the trinomial on the left side:

[tex]\implies \left(x+\dfrac{3}{2}\right)^2=\dfrac{45}{4}[/tex]

Square root both sides:

[tex]\implies x+\dfrac{3}{2}=\pm\sqrt{\dfrac{45}{4}}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{45}}{\sqrt{4}}}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9 \cdot 5}}{2}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{\sqrt{9} \sqrt{5}}{2}[/tex]

[tex]\implies x+\dfrac{3}{2}=\pm\dfrac{3\sqrt{5}}{2}[/tex]

Subtract 3/2 from both sides:

[tex]\implies x=\pm\dfrac{3\sqrt{5}}{2}-\dfrac{3}{2}[/tex]

[tex]\implies x=\dfrac{-3\pm3\sqrt{5}}{2}[/tex]

Answer: 13/69

Step-by-step explanation:

13 students are female and got a B out of a total of 69 students, so the probability is 13/69

Answer:

A = 6

B = 1

C = 14

Step-by-step explanation:

A = 25 - 19 = 6

B = 6 - 5 = 1

C = 19 - 5 = 14

give brainliest please! <3

Answer:

please tell me if im wrong!

Step-by-step explanation:

answer: 16 √ 3

Answer:

24√2

Step-by-step explanation:

if I'm correct the equation is

(√12)^2(√8)

we expand the surds

(√4x3)^2 (√4x2)

(2√3)^2 (2√2)

(4x3) (2√2)

12x2√2 =

24√2

Answer:

3x - 7

Step-by-step explanation:

This questions asks about the subtraction of functions. To find the answer, we can subtract the same way we would subtract polynomials.

Subtracting Expressions

First, set up the subtraction problem by taking the expression for f(x) and subtracting the expression equal to g(x) from it.

This looks like:

Next, distribute the negative to the second binomial

Then, combine like terms

Since we are not given a x-value, this is the final answer.

Solving for an X-Value

If you are given an x-value, the best way to solve the equation is to first solve each function and then subtract.

For example, using the same rules for each function let's solve (f-g)(2).

First, solve for f(2) and g(2)

Then, subtract the 2 values

Answer:

b

Step-by-step explanation:

Answer:

C.6

Step-by-step explanation:

According to the compound interest model, we find the following results: I) x ≈ 11.5 yr, C' = $ 101317.36, II) r ≈ 7.4 %, x ≈ 9.8 yr, III) C = $ 7626.38, x ≈ 8.6 yr, IV) r ≈ 6.5 %, C = $ 12801.61

Compound interest describes the capital gain in term of deposited capital and the consideration that such capital is increased continuously in time. The compound interest model is shown below:

C' = C · (1 + r/100)ˣ     (1)

Where:

The doubling time (x) is the period needed for a capital to be doubled. It is described by the following expression based on (1):

x = (㏒ 2)/[㏒ (1 + r/100)]     (2)

Now we proceed to calculate each missing variable:

Case I - Doubling time

x = (㏒ 2)/[㏒ (1 + 6.2/100)]

x ≈ 11.5

Case I - Current capital

C' = 75000 · (1 + 6.2/100)⁵

C' = 101317.36

Case II - Interest rate

[tex]r = 100\cdot \left(\sqrt [5] {\frac{7130.90}{5000} }-1\right)[/tex]

r ≈ 7.4

Case II - Doubling time

x = (㏒ 2)/[㏒ (1 + 7.3/100)]

x ≈ 9.8

Case III - Initial capital

C = 11414.71/(1 + 8.4/100)⁵

C = 7626.38

Case III - Doubling time

x = (㏒ 2)/[㏒ (1 + 8.4/100)]

x ≈ 8.6

Case IV - Interest rate

[tex]r = 100\cdot \left(\sqrt [11] {2 }-1\right)[/tex]

r ≈ 6.5

Case IV - Initial capital

C = 17539.32/(1 + 6.5/100)⁵

C = 12801.61

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Answer: 80%

Step-by-step explanation:

Since only 2 out of 10 women dropped out, 10 - 2 = 8

One woman = 10%, 8 x 10% = 80%

The percentage of the women who moved to the next stage is 80%.

Percentage can be described as a fraction out of an amount that is usually expressed as a number out of hundred.

Women who moved to the next stage: 10 - 2 = 8

(8/10) x 100 = 80%

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Answer:

The answers to different parts for ratio are - 3:5,3:5,3:5,9:25,graph C respectively .

Step-by-step explanation:

A ratio is a relationship between two quantities, normally expressed as the quotient of one divided by the other, or the quantitative relation between two amounts showing the number of times one value contains or is contained within the other.

a) The ratio of the median weekly earnings of the holder of a high school diploma only to the median weekly earnings of the holder of a bachelor's degree - 750/1250 = 3:5

b) The ratio of the area of the red rectangle  to the area of the blue rectangle - 750 x 1 / 1250 x 1 = 3:5

c) The ratio of the area of the red square to the area of the blue square in graph B - 3:5

d) the ratio of the volume of the red cube to the volume of the blue cube in graph C - 750 x 750 /1250x 1250 =9:25

e) The most misleading graph is graph B  because the distribution of values , depth, and shapes differ.

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P(x) goes to infinity as x goes to negative infinity, and P(x) goes to negative infinity as x goes to infinity , Option B is the correct answer.

A polynomial is an expression which consists of variables , Coefficient , indeterminate and mathematical operations.

The polynomial given has  lead term -x⁷

So when x --> ∞  , -x⁷---> - ∞

and when x ---> - ∞  , -x⁷ ---->  ∞

Similarly for the function P(x)

So when x --> ∞  , P(x)---> - ∞

and when x ---> - ∞  ,  P(x) ---->  ∞

P(x) goes to infinity as x goes to negative infinity, and P(x) goes to negative infinity as x goes to infinity

Therefore Option B is the correct answer.

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Answer:

x = 9/2

Step-by-step explanation:

√2x + √2x = 6

2√2x = 6

2√2x/2 = 6/2

√2x = 3

(√2x)² =( 3)²

2x = 9

x = 9/2

Answer:

x = 4.5

Explanation:

[tex]\rightarrow \sf \sqrt{2x} + \sqrt{2x} = 6[/tex]

add following

[tex]\rightarrow \sf 2\sqrt{2x} = 6[/tex]

divide both sides by 2

[tex]\rightarrow \sf \sqrt{2x} = 3[/tex]

square both sides

[tex]\rightarrow \sf 2x = 3^2[/tex]

simplify the following

[tex]\rightarrow \sf 2x = 9[/tex]

divide both sides by 2

[tex]\rightarrow \sf x = 4.5[/tex]

Answer:

what is the control ofprice floir or price celling then scplain one advantage an one dissvantage

Answer: 0.625

Step-by-step explanation:

The sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.

It is defined as three-dimensional geometry that has six square faces and eight vertices.

We have a volume of a cubical box is 54.872 cm³

V = 54.872 cm³

As we know the volume of the cube:

V = side³

54.872 = side³

Taking cube root on both sides:

side = 3.8 cm

Thus, the sides length of the cubical box is 3.8 cm if the volume of a cubical box is 54.872 cm³ option second is correct.

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[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{(7\times 10^5) + (4 \times 10^2)}\\\mathsf{= 7\times 10^5 + 4 \times 10^2}[/tex]

[tex]\large\textsf{Let's solve for the LEFT SIDE first}[/tex]

[tex]\mathsf{7\times 10^5}\\\\\mathsf{10^5}\\\mathsf{= 10\times10\times10\times10\times10}\\\mathsf{= 100 \times 100\times 10}\\\mathsf{= 10,000 \times 10}\\\mathsf{= 100,000}\\\\\mathsf{7\times100,000}\\\mathsf{= 700,000}[/tex]

[tex]\large\textsf{NEW EQUATION: }\bold{700,000} + {4}\times 10^2[/tex]

[tex]\large\textsf{Now, let's solve for the RIGHT SIDE last}[/tex]

[tex]\mathsf{4\times 10^2}\\\\\mathsf{10^2}\\\mathsf{= 10\times10}\\\mathsf{= 100}\\\\\mathsf{4\times100}\\\mathsf{= 400}[/tex]

[tex]\large\text{NEW EQUATION: 700,000 + \bf 400}[/tex]

[tex]\large\text{700,000 + 400}\\\\\large\text{SIMPLIFY IT!}\\\\\large\text{= 700,400}[/tex]

[tex]\huge\text{Therefore, the answer should be: \boxed{\mathsf{700,400}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]