Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.

I already know...
[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]

But I don't understand what steps I have to take to solve that equation

Answers

Answer 1

From Newton's law of gravity, the force of gravity is 245 Newtons

To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters

Mass m = 25 kg

Mass of the earth M = 5.97x10^24kg

Radius r = 6.38x10^6m

Force F = ?

The formula to calculate the force of gravity is

F = (GMm)/[tex]r^{2}[/tex]

Where G = 6.67 x [tex]10^{-11}[/tex]

Substitute all the parameters

F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2

F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]

F = 244.56 N

F = 245 Newtons (approximately)

Therefore, the force of gravity is 245 Newtons

Learn more about force of gravity here: https://brainly.com/question/557206


Related Questions

Water falls down as a stream from a tap. Why does it not scatter?​

Answers

Answer:

as it hits the ground it's dispersed and this causes it to move in different directions

Object A has a mass of 5 kg and a velocity of 6 m/s to the east while Object 1 point B has a mass of 12 kg and velocity 0.6 m/s also to the east. What is the momentum of the system? (Let east be positive)
help plss I got family

Answers

Answer:

Momentum of system = 37.2 Kgm/s.

Explanation:

Given the following data;

Mass A = 5 kgVelocity A = 6 m/sMass B = 12 kgVelocity B = 0.6 m/s

To find the momentum of the system;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

For object A;

Momentum A = 5 * 6

Momentum A = 30 Kgm/s

For object B;

Momentum B = 12 * 0.6

Momentum B = 7.2 Kgm/s

Next, we would determine the momentum of this system using the formula;

Momentum of system = Momentum A + Momentum B

Substituting the values into the formula, we have;

Momentum of system = 30 + 7.2

Momentum of system = 37.2 Kgm/s.

A bullet of mass of 50g is moving with the velocity of 200km/h .calculate the kinetic energy of the bullet .​

Answers

Not sure if this it completely right but here’s what I got: 77.16050617284 J

Answer:

is 10³

Explanation:

cuz the formula of KE is 1/2mv²

covert 50g to kg first then plug in the formula

1/2 × 0.05 × 200 = 10³ J

A 750 kg National Geographic Drone is rising vertically up into the atmosphere at constant speed. The lift force pushing it upward is 125% of its weight. The drone reaches the cruising speed almost immediately. It takes 25 seconds for the drone to reach a height of 250m starting from the surface.
a. What is the mechanical energy of the drone at the surface?
b. What is the mechanical energy of the drone at the 150 m height?
c. Is the mechanical energy of the drone conserved, increased, or decreased. Explain your choice.
d. What is the work done by each force acting on the drone?

Answers

Answer:

a. 0

b. 1.103625 MJ

c. Conserved

d. 1.103625/n MJ where n = The number of forces

Explanation:

The mass of the drone, m = 750 kg

The upward lift force = 125% of the weight of the drone

The time it takes the drone to reach a height of 250 m = 25 seconds

a. The mechanical energy = The kinetic energy + Potential energy

Therefore, given that the drone stars motion from the surface and was initially at rest, the mechanical energy at the surface = 0

b. The mechanical energy at height, h = 150 m, ME₁₅₀ = The potential energy gained = m·g·h

Where;

g = The acceleration due to gravity = 9.81 m/s²

∴ ME₁₅₀ = 750 kg × 9.81 m/s² × 150 m = 1103625 J = 1.103625 MJ

c. The mechanical energy is equivalent to the potential energy of the drone at the 150 m height, therefore, it is conserved

d. The work done by the force = The energy gained

Therefore, where there are n number of forces, the work done by each force = 1.103625/n MJ

Which of the following statements are true when it comes to impairment?

Answers

Answer:

Reduction in recoverable amount

Explanation:

Impairment of an asset happens when there is drastic reduction in recoverable amount of the asset. Long term assets are at risk of impairment because their carrying values may exceed the fair value. The business record it as a loss in assets value.

why do flames go upwards​

Answers

Answer:

Easy search it on g o o g l e

A car and a truck collide in an intersection and the merged wreck continues along. During the collision. both kinetic energy and momentum are conserved.B. neither kinetic energy not momentum is conserved.C. momentum is conserved but not kinetic energy.D. kinetic energy is conserved but not momentum.E. conservation depends upon the details of the collision.

Answers

Answer:

C. Momentum is conserved but not kinetic energy.

Explanation:

This case represents an entirely inelastic collision, that is, a collision between the car and the truck that reduces total kinetic energy of the entire system, whereas linear momentum is conserved. Hence, correct answer is C.

An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complete swings in a time of 257 seconds. From this measurement she calculates the acceleration due to gravity on Pluto. What is her result

Answers

Answer:

The acceleration due to gravity at Pluto is 0.0597 m/s^2.

Explanation:

Length, L = 1 m

10 oscillations in 257 seconds

Time period, T = 257/10 = 25.7 s

Let the acceleration due to gravity is g.

Use the formula of time period of simple pendulum

[tex]T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2[/tex]

What comes before Action-reaction?

Answers

These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.

what is the economic application of changes in states of matter

Answers

Answer:

Changes of state are physical changes in matter. They are reversible changes that do not change matter's chemical makeup or chemical properties. For example, when fog changes to water vapor, it is still water and can change back to liquid water again.

Turbine blades are rotated by the steam in the steam turbine.The water at the high temperature get converted into the steam used to rotate the turbine blades.

What is state?

The property of any system on a specified point is known as the state of the system.Pressure,temperature are the properties of the system.

They are reversible modifications that do not alter the chemical composition or characteristics of matter.

The steam turbine blades are turned by the steam. The high-temperature water is turned to steam, which is utilized to rotate the turbine blades.

When fog transforms into water vapor, for example, it is still water and may transform back into liquid water.

Hence the steam turbine is the economic application of changes in states of matter.

To learn more about the state refer to the link;

https://brainly.com/question/15858706

#SPJ2

4. diference between VR and efficiency​

Answers

Answer:

Velocity ratio of simple machine is the ratio of distance travelled by effort to the distance travelled by load in the machine. The efficiency of a simple machine is defined as the ratio of useful work done by machine (output work) to the total work put into the machine (input work).

describe the forest ecosystem with examples​

Answers

A forest ecosystem describes the community of plants, animals, microbes and all other organisms in interaction with the chemical and physical features of their environment: Specifically, a terrestrial environment dominated by trees growing in a closed canopy — a forest, in other words.

Hope this helps you buddy! :)

Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms, 314 K. The room serviced by unit A is kept at a temperature of 292 K, while the room serviced by unit B is kept at 298 K. The heat removed from either room is 4430 J. For both units, find (a), (b) the magnitude of the work required and (c), (d) the magnitude of the heat deposited outside for A and B conditioners respectively

Answers

Answer:

(a)  333.77 J

(b) 237.85 J

(c) 4763.77 J

(d) 4667.85 J

Explanation:

Temperature of source, TH = 314 K

Temperature of A, Tc = 292 K

Temperature of B, Tc' = 298 K

heat taken out, Qc = 4430 J

Let the heat deposited outside is QH and QH' by A and B respectively.

[tex]\frac{Q_H}{Q_c}=\frac{T_H}{T_c}\\\\Q_H = \frac{4430\times314}{292}=4763.77 J[/tex]

Now

[tex]\frac{Q_H'}{Q_c}=\frac{T_H}{T_c'}\\\\Q_H' = \frac{4430\times314}{298}=4667.85 J[/tex]

(a) Work done for A

W = QH - QC = 4763.77 - 4430 = 333.77 J

(b) Work done for B

W' = QH' - Qc = 4667.85 - 4430 = 237.85 J

(c) QH = 4763.77 J

(d) QH' = 4667.85 J

What is the right hand rule for magnetic Force?

Answers

Answer:

The right hand rule states that, to find the direction of the magnetic force on a positive moving charge, the thumb of the right hand point in the direction of v, the fingers in the direction of B, and the force (F) is directed perpendicular to the right hand palm.

Explanation:

pls mark brainliest

Hope this helps u

A train travels 600 kilometers in 1 hour. What is the train's velocity in meters/second?

Answers

here's the answer to your question

joule is a unit of_____and_____​

Answers

Answer:

Energy and work

.........

Answer:

Work Energy

Explanation:

Joule is a unit of Work and energy .

Hope my answer is helpful to you ✌️❣️☪️❇️☪️❣️✌️

Will mark brainlest helpp!!!!!!​

Answers

Answer:

I don't know if it is correct or not.

initial velocity=u=0m/sFinal velocity=60km/h=v

Convert to m/s

[tex]\\ \Large\sf\longmapsto v=60\times \dfrac{5}{18}=16.6m/s[/tex]

Time=t=5min=5×60=300s

We know

[tex]\boxed{\Large{\sf Acceleration=\dfrac{v-u}{t}}}[/tex]

[tex]\\ \Large\sf\longmapsto Acceleration=\dfrac{16.6-0}{300}[/tex]

[tex]\\ \Large\sf\longmapsto Acceleration=\dfrac{16.6}{300}[/tex]

[tex]\\ \Large\sf\longmapsto Acceleration=0.05m/s^2[/tex]

Distance=s

Using second equation of kinematics

[tex]\boxed{\Large{\sf s=ut+\dfrac{1}{2}at^2}}[/tex]

[tex]\\ \Large\sf\longmapsto s=0(300)+\dfrac{1}{2}(0.05)(300)^2[/tex]

[tex]\\ \Large\sf\longmapsto s=0.05\times 150^2[/tex]

[tex]\\ \Large\sf\longmapsto s=0.05\times 22500[/tex]

[tex]\\ \Large\sf\longmapsto s=1125m[/tex]

Name the type of motion executed by the motion of the moon around the earth.

Answers

Answer:

The motion of the moon around the earth is circular motion

Explanation:

A particle makes 800 revolution in 4 minutes of a circle of 5cm. Find
i. it's period
ii. Angular Velocity
iii. Linear Velocity
iv. It's acceleration
PLEASE FORMULAE SHOULD BE WRITTEN CLEARLY.
YOU CAN SNAP AND SEND

Answers

Answer:

i) The period of the particle is 0.3 seconds

ii) The angular velocity is approximately 20.94 rad/s

iii) The linear velocity is approximately 1.047 m/s

iv) The centripetal acceleration is approximately 6.98 m/s²

Explanation:

The given parameters are;

The number of revolution of the particle, n = 800 revolution

The time it takes the particle to make 800 revolutions = 4 minutes

The dimension of the circle = 5 cm = 0.05 m

Given that the dimension of the circle is the radius of the circle, we have;

i) The period of the particle, T = The time to complete one revolution

T = 1/(The number of revolutions per second)

∴ T = 1/(800 rev/(4 min × 60 s/min)) = 3/10 s

The period, T = 3/10 seconds = 0.3 seconds

ii) The angular velocity, ω = Angle covered/(Time)

800 revolutions in 4 minutes = Angle of (800 × 2·π) in 4 minutes

∴ ω = (800 × 2·π)/(4 × 60) = 20·π/3

The angular velocity, ω = 20·π/3 rad/s ≈ 20.94 rad/s

iii) The linear velocity, v = r × ω

∴ The linear velocity, v = 0.05 m × 20·π/3 rad/s = π/3 m/s ≈ 1.047 m/s

iv) The centripetal acceleration, [tex]a_c[/tex] = v²/r

∴ The centripetal acceleration, [tex]a_c[/tex] = (π/3)²/(0.05) = 20·π/9

The centripetal acceleration, [tex]a_c[/tex] = 20·π/9 m/s² ≈ 6.98 m/s²

hai vật chuyển động ngược chiều qua A với B cùng lúc, ngược chiều để gặp nhau . Vật qua A có vận tốc 10m/s, qua B có vận tốc 15m/s. AB=100m
a, lấy trục tọa độ là đường thẳng AB, gốc tọa độ ở B , có chiều dương từ A sang B , gốc thời gian là lúc chúng cùng đi qua A và B . Lập phương trình chuyển động của hai xe
b, xác định vị trí , thời điểm 2 xe gặp nhau
c, xác định vị trí , thời điểm 2 xe cách nhau 25m

Answers

Answer:

wah wats this again

Explanation:

Bhai mujhe samaj nahi ah Raha

Kya Bolne Chahtaa hu tum

Answer:

bạn vẽ ra rồi làm

Explanation:

Two rams run toward each other. One ram has a mass of 44 kg and runs south with a speed of 6 m/s, while the other has a mass of 50 kg and runs north with a speed of 3 m/s. What will the momentum of the system made up of the two rams be after they collide? Assume the total momentum of the system is conserved.
A. 114 kg-m/s south
B. 414 kg-m/s south
C. 414 kg m/s north
D. 114 kg-m/s north

Answers

Answer = D. 114 kg-m/s north

5. Tại sao khi lặn ta luôn cảm thấy tức ngực và càng lặn sâu thì cảm giác tức ngực càng tăng? A. Ap suất của nước giảm ​​B. Ap suất không khí tăng C. Ap suất không khí giảm ​​D. Ap suất của nước tăng

Answers

Answer:

c and d

Explanation:

obviously kksxsxksxkskxkskxksxksxsxsxsxsxsxsxs

3.7 kg of a saturated water vapor at 0.4 MPa is isothermally cooled until it is a saturated liquid. Calculate the amount of heat rejected during this process in MJ. (Report your answer in 3 decimal places.)

Answers

Answer:

7.894 MJ

Explanation:

Given that:

The mass of the saturated water vapor = 3.7 kg

The pressure of the saturated water vapor = 0.4 MPa

From saturated properties of steam tables when the pressure is at 0.4 Mpa

The enthalpy in (kJ/kg);

hf = 604.7 kJ/kg

hg = 2738.1 kJ/kg

The rejected heat during this process is:

Q = m(hg - hf)

Q = 3.7(2738.1 - 604.7) kJ/kg

Q = 3.7(2133.4) kJ/kg

Q = 7893.58 kJ/kg

Q = 7.894 MJ

Define SI units. Also mention their importance. SI unit The​

Answers

Answer:

SI unit is an internationally accepted system and have the same value all over the world .

I don't know the importance sotry

Answer:

SI unit is an internationally accepted system that have same value all over the world.

state physical quantity represented by the gradient of a displacement - time graph

Answers

Answer:

velocity

Explanation:

this is because velocity has both magnitude and direction

1. Una carga Q1 = + 12 μC se coloca a una distancia r = 0.024 m desde una carga Q2 = + 16 μC. a) Determina la magnitud de la fuerza electrostática que actúa sobre las dos cargas, Q1 y Q2. b) ¿Es la fuerza la atracción o repulsión? 2. Determina la intensidad del campo eléctrico a una distancia radial de r = 48 mm desde una carga de Q = 24 μC. 3. Una carga Q1 = 24 mC se coloca a una distancia r = 0.032 m desde una carga Q2 = - 12 μC. a. Determina la cantidad de energía potencial eléctrica que tiene la carga Q1. b. Determina el potencial eléctrico en la posición de Q2.

Answers

Answer:

1. a. 3,000 N

b. Repulsión

2. 46.875 × 10⁶ N/C

3. a. 81,000 J

b. 6.75 × 10⁹ V

Explanation:

1. Los parámetros dados son;

Q₁ = +12 μC, Q₂ = +16 μC

La distancia entre las cargas, r = 0.024

La magnitud de la fuerza electrostática, F, entre cargas se da como sigue;

[tex]F = k \times \dfrac{Q_1 \cdot Q_2}{r^2}[/tex]

Donde, k = constante de Coulomb = 9.0 × 10⁹ N · m² / C²

Por lo tanto, obtenemos;

F = 9.0 × 10⁹ × 12 × 10⁻⁶ × 16 × 10⁻⁶ / 0.024² = 3.000

La magnitud de la fuerza electrostática, entre las cargas, F = 3000 N

(b) Dado que tanto Q₁ como Q₂ son cargas positivas, y las cargas iguales se repelen entre sí, la fuerza es la repulsión.

2) La intensidad de un campo eléctrico, E, se da como sigue;

[tex]E = \dfrac{k \cdot Q}{r^2}[/tex]

La magnitud de la carga, Q = 24 μC

La distancia donde se mide el campo, r = 48 mm = 0.048 m

Por lo tanto, E = 9.0 × 10⁹ × 12 × 10⁻⁶ / 0.048² = 46,875,000 N / C

La intensidad de un campo eléctrico, E = 46,875,000 N / C = 46.875 × 10⁶ N / C

3. La magnitud de las cargas son;

Q₁ = 24 mC

Q₂ = -12 μC

La distancia entre las cargas, r = 0.032 m

un. El potencial eléctrico de una carga, [tex]U_E[/tex] , se da de la siguiente manera;

[tex]U_E = k \times \dfrac{Q_1 \cdot Q_2}{r}[/tex]

Por lo tanto;

[tex]U_E[/tex] = 9.0×10⁹ × 24 × 10⁻³ × (-12) × 10⁻⁶ /0.032 = -81,000

La energía potencial eléctrica entre la carga, Q₁ y Q₂= -81,000 J

b. El potencial eléctrico de Q₁ en Q₂, V₁ = [tex]k \times \dfrac{Q_1 }{r}[/tex]

Por lo tanto, V₁ = 9.0×10⁹ × 24 × 10⁻³/0.032 = 6.75 × 10⁹

El potencial eléctrico de Q₁ en Q₂, V₁ = 6.75 × 10⁹ V

Plutonium-32 has a half-life of 14.2 days. After 99.4 days, how much of what was originally a 499.2 gram sample remains?


14 grams

3.9 grams

35.7 grams

0.71 grams

Answers

Answer:

3.9 gm remains

Explanation:

499.2 ( 1/2)^(99.4/14.2)   = 3.9 gm

The needle in the following diagram rotates around a fixed point in the middle. Based on the information given, what way will the needle rotate when the current is applied?

Answers

Answer:

nods 40th anniversary rid off e 49en9 snns

A decorative plastic film on a copper sphere of 10 mm diameter in an oven at 750C. Upon removal from the oven, the sphere is subjected to an air stream at 1 atm. , and 230C having a velocity of 10 meter/sec. Estimate how long it will take to coal the sphere to 350C? Density of copper is 8933 kg/m3 , thermal conductivity k = 399 W/m.K and specific heat Cp = 387 J/kg.K. for Air at an average temperature of T[infinity] = 296 K has viscosity µ= 181x10-7 N.s/m2 , kinematic viscosity ν = 15.36x10-6 m2/s and thermal conductivity k = 0.0258 W/m.K and Prandtl No. Pr = 0.709 and air at surface temperature Ts = 328 K will have viscosity µs = 197x10-7 N.s/m2

Answers

Answer:

3.26 secs

Explanation:

Diameter of sphere ( D )= 10 mm

T1 = 75°C

P = 1 atm

T∞ = 23°C

T2 = 35°c

Velocity = 10 m/s

Determine how long it will take to cool the sphere to 35°C

Using the properties of copper and air given in the question

Nu = 2 + (Re)^0.8 (Pr)^0.33

hd / k = 2 + ( vd/v )^0.8 (Pr)^0.33

∴ h ≈  2594.7 W/m^2k

Given that :

(T2 - T∞) / ( T1 - T∞ )  = exp [ ( -hA / pv CP ) t ]  

( 35 - 23 ) / ( 75 - 23 ) = exp [  - 2594.7 * 6 * t / 8933 * 387 * 10 * 10^-3 ]

=  ln ( 12/52 ) = -1.466337069  =     - 0.45032919 *  t

∴ t ≈ 3.26 secs        ( -1.466337069 / -0.45032919 )

The image shows a landform created by Earth’s forces.

A dip in a mountain range between two plates.

Which describes this landform?

anticline
shearing
syncline
tension

Answers

The term that best describes the landform "dip in a mountain range" is C. Syncline.

Syncline is a term to refer to a fold of the Earth's crust caused by the tectonic effects of the earth's dynamics. A synclinal fold is characterized by being a concave fold, that is, in the shape of a U.

According to the above, answers A, B and D are not correct options because they refer to different shapes of the Earth. Therefore, the landform shown is syncline.

Learn more at: https://brainly.com/question/17137827

Answer: C

Explanation: E2022

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