Answer:
do it your self like who does that
26 miles and 385 yards to kilometers
To convert 26 miles and 385 yards to kilometers, we first need to convert miles and yards to the same unit.
1 mile = 1760 yards
26 miles = 26 x 1760 = 45600 yards
Then add the yards of the distance, so the total distance in yards is 45600+385 = 45985 yards
Now we can convert yards to kilometers.
1 yard = 0.9144 meters
45985 yards = 45985 x 0.9144 = 42.195 kilometers
So 26 miles and 385 yards is approximately 42.195 kilometers.
How to do this exercise.
Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
T^2 = 4 * d^3 * (m1 + m2)^2 / G
What is Kepler's third law?Generally, Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit. In the case of two celestial bodies orbiting their center of mass, we can use Newton's laws of motion to derive the general form of Kepler's third law.
Using Newton's second law, we can write the centripetal force acting on each body as: F = m * a = m * v^2 / r
where
m is the mass of the body a is the centripetal acceleration, v is the orbital velocity, and r is the distance from the center of mass.The gravitational force between the two bodies is given by: F = G * (m * m2) / d^2
where
G is the gravitational constant, m1 and m2 are the masses of the two bodies, and d is the center-to-center distance.Equating the two forces, we get:
m * v^2 / r = G * (m1 * m2) / d^2
Solving for the orbital velocity, we get: v = (G * (m1 + m2) / d)^1/2
Using the period-velocity relationship, T = 2 * pi * r / v, we can find the period of the orbit.
Substituting for v, we get:
T = 2 * pi * r * (d / (G * (m1 + m2)))^1/2
Squaring both sides and solving for r, we get: T^2 = 4 * pi^2 * r^3 / (G * (m1 + m2))
r = (G * (m1 + m2) * T^2) / (4 * pi^2)
so T^2 = 4 * pi^2 * (G * (m1 + m2) * T^2) / (4 * pi^2) * d^3
T^2 = 4 * d^3 * (m1 + m2)^2 / G
which is the general form of Kepler's third law.
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Which statement is true about the theory of plate tectonics and the theory of continental drift?
A) The theory of plate tectonics proves the theory of continental drift completely wrong.
B) The theory of plate tectonics tells exactly where the continents were before Pangaea divided.
C) The theory of plate tectonics gives the method by which continents can move as part of plates.
D) The theory of plate tectonics does not explain how continental movements could occur.
The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .
What is theory of plate tectonics and the theory of continental drift ?According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.
The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.
According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.
Therefore, option C is correct.
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a small, 250 g cart is moving at 1.60 m/s on a frictionless track when it collides with a larger, 3.00 kg cart at rest. after the collision, the small cart recoils at 0.840 m/s .
what is the speed of the large cart after the collision?1
m(small cart) = 250 g = 0.25 Kg
vi(small cart) = 1.60 m/s
m(large cart) = 3.00 kg
vi(large cart) = 0 m/s
vf(large cart) = ?
The speed of the larger cart after the collision is 0.084 m/s.
The principle of conservation of momentum states that the total momentum of an isolated system remains constant if no external forces act on the system. In this case, the momentum of the two carts before the collision is equal to the momentum of the two carts after the collision. We can use this principle to find the speed of the larger cart after the collision.
Let's call the speed of the larger cart after the collision "v".
Before the collision:
momentum = m1 * v1 = (250 g) * (1.60 m/s) = 0.25 kg * 1.60 m/s
After the collision:
momentum = (0.25 kg * 0.840 m/s) + (3.00 kg * v) = 0.25 kg * 0.840 m/s + 3.00 kg * v
Setting the before and after momenta equal:
0.25 kg * 1.60 m/s = 0.25 kg * 0.840 m/s + 3.00 kg * v
Solving for v:
v = (0.25 kg * 1.60 m/s - 0.25 kg * 0.840 m/s) / 3.00 kg
v = (0.25 kg * 0.760 m/s) / 3.00 kg
v = 0.25 kg / 3.00 kg * 0.760 m/s
v = 0.084 m/s
So the speed of the larger cart after the collision is 0.084 m/s.
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The truss shown in the figure carries a
load F= 20 kN at joint D. The truss is
designed with nine rods, six of which (the
inclined ones) have the same length d=2
m. Rods BC, EC, DE, and BD form a
square.
1. Find the support reactions at joints A
and F.
2. Using the method of joints or method of
sections to find the tensions in rods BD
and BC.
3. State whether each member is in
tension or compression.
The support reactions at joints A and F is 28.28 kN.
The method of joints or method of sections to find the tensions in rods BD and BC is 40 kN.
Each member is in tension or compression are (T_BC = 20 kN) and (T_BD = 40 kN).
What is compression?Compression is the process of reducing the size of a file, or data set, by encoding it using fewer bits than the original file. Compression techniques are used in many fields, including data storage and transmission, audio and video editing, and software development.
1. The support reactions at joints A and F can be found by using the equations of equilibrium:
R_A = F_x = 0 = -20 kN + R_F cos(45°)
R_F = F_y = 0 = -20 kN + R_A cos(45°)
Solving the equations, R_A = 28.28 kN and R_F = 28.28 kN.
2. Using the method of joints, the tensions in rods BC and BD can be found by taking moments around point D.
Moment about D: 0 = -F×d×sin(45°) + T_BC×d/2 - T_BD×d/2
Therefore, T_BC = 20 kN and T_BD = 40 kN.
3. Rod BC is in tension (T_BC = 20 kN) and rod BD is in compression (T_BD = 40 kN).
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A glass Capillary tube of diameter 2.0mm
is dipped into pool of water How high
in the tube ?
( take contact angle betwen glass of water
as oº, surface fension of pater as 0.073 ~m²"
& density of water as
a
1000kgm ³)
3×10Nm¹ and the contact angle with the tubes as 45⁰
Answer:
To calculate the height of the water in the capillary tube, we can use the equation h = 2πσcosθ/ρg, where h is the height of the water in the tube, σ is the surface tension of the water, θ is the contact angle between the glass and the water, ρ is the density of the water, and g is the acceleration due to gravity. Plugging in the given values, we get h = 2π(0.073)cos(45°)/(1000)(9.8), which is equal to 0.0092 meters.
A small toy car of mass 3.00kg runs into another toy car of mass 2.00kg at rest. They stick together and slide 2.0 meters along the rough floor m = 0.25. how fast was the first car going when it hit the ground car? Is this collision elastic or inelastic?
Answer:
Explanation:To determine the speed of the first car when it hit the second car, we can use the conservation of momentum. The momentum of the first car before the collision is equal to its mass multiplied by its velocity, and the momentum of the two cars after the collision is also equal to their combined mass multiplied by their combined velocity.
The momentum of the first car before the collision is 3.00kg * v1 = m1 * v1
The momentum of the two cars after the collision is (3.00kg + 2.00kg) * v2 = (m1 + m2) * v2
From the conservation of momentum, we can set these two equations equal to each other and solve for v1:
m1 * v1 = (m1 + m2) * v2
v1 = (m1 + m2) * v2 / m1
v1 = (3.00kg + 2.00kg) * v2 / 3.00kg
v1 = 5.00kg * v2 / 3.00kg
v1 = (5/3) * v2
The combined velocity of the two cars after collision is v2 = 2.0m / (2.0s) = 1.0m/s
Therefore, the first car was going at (5/3) * 1.0m/s = 1.67m/s.
To determine if this collision is elastic or inelastic, we need to calculate the coefficient of restitution (e).
e = (initial velocity of first car - final velocity of first car) / (initial velocity of first car)
The initial velocity of the first car was 1.67m/s and final velocity of the first car is 0 m/s (since it stops after the collision).
e = (1.67m/s - 0m/s ) / (1.67m/s)
e = 1.0
The coefficient of restitution is 1.0, which means the collision is perfectly elastic. This means that the kinetic energy is conserved in the collision.
Part A
Compute the x and y components of vector A.
Express your answers in meters to three siginificant figures. Enter your answers separated by
A comma
The component of vector A in the x direction will be -11.01 meters. and in the y direction will be 9.18 meters.
What is meant by vectors?A quantity or phenomenon with independent qualities for both magnitude and direction is called a vector. The term can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields, and weight are examples of vectors in nature.
What are examples of vectors?Vector quantities can also include things like movement, acceleration, force, momentum, weight, the speed of light, a gravitational field, current, and more.
component of vector A in x direction = A cos theta
= 12 cos(53)
= -11.01 meters
component of vector A in y direction = A sin theta
= 12 sin (53)
= 9.18 meters
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If you charge a rod by running it through some material like fur, and then bring it near a stream of water that has no charge, the water will show some attraction to the rod. This is because _____.
of electrostatic induction
of friction and contact
electricity is conducted through water
none of the above
The attraction of the water is because of electrostatic induction. Option A
What is static electricity?We know that it is possible for static electricity to be induced on a body. In the first case, the charge that we have obtained is one that we have gotten by the purpose of friction. That is the running of one material against the other.
In the second case, we can see that there is a transfer of charge from one material to the other without the materials actually touching. This is charging by induction.
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the product of an object's instantaneous momentum and acceleration is what quantity?
Explanation:
In differential form, this is Newton's second law; the rate of change of the momentum of a particle is equal to the instantaneous force F acting on it, hence the net force is equal to the mass of the particle times its acceleration.
Calculate the distance (in km) between a moonlet ( m = 6.3 x1014 kg ) and an alien planet ( M = 1.04 x1026 kg ) if the force of gravity acting on the moonlet, due to the planet, is 5.2 x1016 N.
The distance (in Km) between the moonlet and the alien planet, given that the force of gravity acting on the moonlet due to the planet is 5.2×10¹⁶ N, is 9167.4 Km
How do I determine the distance between the moonlet and the alien planet?We can obtain the distance between the moonlet and the alien planet by using the following formula:
F = GM₁M₂ / r²
Where
F is the force of gravityG is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from the question:
Mass of moonlet (M₁) = 6.3×10¹⁴ KgMass of alien planet (M₂) = 1.04×10²⁶ KgForce of gravity (F) = 5.2×10¹⁶ N Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Distance (r) = ?F = GM₁M₂ / r²
5.2×10¹⁶ = (6.67×10¯¹¹ × 6.3×10¹⁴ × 1.04×10²⁶) / r²
Cross multiply
5.2×10¹⁶ × r² = 6.67×10¯¹¹ × 6.3×10¹⁴ × 1.04×10²⁶
Divide both sides by 5.2×10¹⁶
r² = (6.67×10¯¹¹ × 6.3×10¹⁴ × 1.04×10²⁶) / 5.2×10¹⁶
Take the square root of both sides
r = √[(6.67×10¯¹¹ × 6.3×10¹⁴ × 1.04×10²⁶) / 5.2×10¹⁶]
r = 9167442.4 m
Divide by 1000 to express in Km
r = 9167442.4 / 1000
r = 9167.4 Km
Thus, we can conclude that the distance between them is 9167.4 Km
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A 75-kg base runner begins his slide into second base when he is moving at a speed of 5.0 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.
a) How much mechanical energy is lost due to friction acting on the runner? how many J?
b) How far does he slide? how many m?
(a) The mechanical energy lost due to friction force acting on the runner is 936.4 J.
(b) The distance travelled by the runner as he slides is 1.82 m.
What is the acceleration of the runner?The acceleration of the runner is calculated by applying Newton's second law of motion as shown below.
ma = μmg
a = μg
where;
μ is the coefficient of frictiong is acceleration due to gravitya = ( 0.7 x 9.8 m/s² )
a = 6.86 m/s²
The distance travelled by the runner is calculated as;
v² = u² - 2as
where;
v is the final velocity of the runner = 0u is the initial velocity of the runners is the distance travelled by the runnera is the acceleration of the runner0 = u² - 2as
s = u² / 2a
s = ( 5² ) / ( 2 x 6.86 )
s = 1.82 m
The mechanical energy lost due to friction force is calculated as;
W = Fs
W = mas
W = ( 75 kg x 6.86 m/s² x 1.82 m )
W = 936.4 J
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An object travels from (4,0) to (0,4) along path defined by x
2
+y
2
=16 under the applied force is
F
=(
x
2
+y
2
1
)i+(
x
2
+y
2
4
)j. Find the work done using the differential form of the work integral. Clearly show the work integral.
The work done on an object moving from position (x1, y1) to (x2, y2) under an applied force F is given by the work integral:
W = ∫ F ⋅ dr
where dr is the displacement vector from position (x1, y1) to (x2, y2).
For the given scenario, the applied force is F = (x^2 + y^2)i + (x^2 + y^2)^(1/2)j, and the displacement is from (4,0) to (0,4), which is given by dr = (-4, 4)i + (0, 4)j.
So, the work done is:
W = ∫ F ⋅ dr = ∫ ((x^2 + y^2)i + (x^2 + y^2)^(1/2)j) ⋅ ((-4)i + (4)j)
= ∫ -4x^2 - 4y^2 + 4(x^2 + y^2)^(1/2) dx
This work integral cannot be solved in closed form and will require numerical methods to evaluate the definite integral.
To test the performance of its tires, a car
travels along a perfectly flat (no banking) circular track of radius 96.6 m. The car increases
its speed at uniform rate of
at ≡((d |v|)/dt) = 4.87 m/s^2
until the tires start to skid.
If the tires start to skid when the car reaches
a speed of 21.1 m/s, what is the coefficient of
static friction between the tires and the road?
The acceleration of gravity is 9.8 m/s^2
The coefficient of static friction between the tires and the road is 1.987.
What is Static friction?Radius of the track, r = 516 m, Tangential Acceleration = 3.89 m/s^2 and Speed,v = 32.8 m/s
The radial Acceleration is given by, Now the total acceleration is The frictional force on the car will be f = ma------------(1)
And the force due to gravity is W = mg--------------------(2)
Now the coefficient of static friction is, From (1) and (2), Substituting the values, we get friction is 1.987.
Therefore, The coefficient of static friction between the tires and the road is 1.987.
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You weigh 660 N.
What would you weigh if the Earth were
two times as massive as it is and its radius
were five times its present value?
Answer in units of N.
At a mass that is 2 times the current earth and a radius 5 times its value, your weight will be 52.8 N.
How do you find the new weight of the body?In general, we can assume a gravitational force of the following magnitude for any planet or mass:
[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]
where G = 6.67 x 10⁻¹¹m³/kgs², a universal gravitational constant.
m = masses of objects
r = radius of objects.
Given that W = 660 N
m₁ = 2Me, new mass of earth
r = 5re, new radius of earth
Then [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]
Since [tex]F = \frac{GM m}{r^{2} }[/tex]
Substituting both new mass and radius;
[tex]F = \frac{G(2M_{E}) m}{(5r_{E})^{2}}[/tex]
[tex]F = \frac{2}{25} \frac{GM_{E} m}{r^{2}_{E}}[/tex]
Using the equation that weight is [tex]660 N = \frac{GM_{E} m}{r^{2}_{E} }[/tex]
[tex]F = \frac{2}{25}(660 N)[/tex] = 0.08 x 660 N
F = 52.8 N
Since the earth is 5 times its radius and twice its mass a weight of 650N will become 52.8 N.
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Momentum Principle please help
The momentum of the ball is
(-0.18, -0.40, 0.20)m
What is momentum?Generally, The momentum principle, also known as Newton's second law of motion, states that the rate of change of momentum of an object is equal to the force applied to it. Mathematically, this can be expressed as:
F = d(mv)/dt
where
F is the force applied, m is the mass of the object, v is the velocity of the object, and t is time.To determine the position of the ball 0.1 seconds later, we need to know the force acting on the ball due to the elastic band. This force is given by Hooke's Law, which states that the force acting on an object due to a spring is equal to the spring constant (k) multiplied by the displacement of the spring from its relaxed position. In this case, the spring constant is 0.9 N/m, and the displacement is the difference in length between the relaxed length (0.3 m) and the current length of the elastic band.
We know that the ball is at location (-0.2, -0.61, 0)m relative to the point where the elastic band is attached to the paddle. We can find the length of the elastic band by using the distance formula:
√((x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2 ) = √((-0.2 - 0)^2 + (-0.61 - 0)^2 + (0 - 0)^2 )
= √(0.04 + 0.3721 + 0)
= √0.4121
= 0.63874m
The displacement of the spring is the relaxed length (0.3 m) minus the current length of the elastic band (0.63874 m), which is -0.33874 m. The force acting on the ball due to the elastic band is
-0.9 * -0.33874 = 0.30486 N.
We can use the force to find the acceleration of the ball using Newton's second law,
F = ma.
Since the mass of the ball is 0.015 kg, the acceleration of the ball is
0.30486 N / 0.015 kg = 20.324 m/s^2
We can use this acceleration to find the final velocity of the ball using the equation vf = vi + at.
Since the initial velocity of the ball is
(-0.02, -0.01, -0.02) kg-m/s, the final velocity of the ball is
(-0.02, -0.01, -0.02) + (20.324, 20.324, 20.324) * 0.1 s = (-0.02, -0.01, -0.02) + (2.0324, 2.0324, 2.0324)
= (2.0124, 2.0224, 2.0124) m/s
The final position of the ball can be found using the equation
xf = xi + vt.
The initial position of the ball is (-0.2, -0.61, 0)m and the final velocity is (2.0124, 2.0224, 2.0124) m/s, so the final position of the ball after 0.1 s is
(-0.2, -0.61, 0) + (2.0124, 2.0224, 2.0124) * 0.1 s
= (-0.2, -0.61, 0) + (0.20124, 0.20224, 0.20124)
= (-0.18, -0.40, 0.20)m
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Objects with masses of 141 kg and 494 kg are separated by 0.396 m. A 74.8 kg mass is placed midway between them.
1 ) Find the magnitude of the net gravitational force exerted by the two larger masses on the 74.8 kg mass.
The value of the universal gravitational constant is 6.672 × 10−11 N · m^2 /kg^2.
Answer in units of N.
2 ) Leaving the distance between the 141 kg and the 494 kg masses fixed, at what distance from the 494 kg mass (other than infinitely remote ones) does the 74.8 kg mass experience a net force of zero?
Answer in units of m.
( 1) The net gravitational force between the 74.8 kg mass is 8.09 x 10⁻⁵ N.
( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.
What is net gravitational force on the middle mass?The net gravitational force acting on the middle mass is calculated by applying Newton's law of universal gravitation as shown below.
F = ( GmM ) / ( R² )
where;
G is universal gravitation constantm is the mass of the middle massM is the mass of the first massR is the distance of separation between the two massesThe force between the first mass and the middle mass is calculated as;
F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )
F' = 1.8 x 10⁻⁵ N
The force between the third mass and the middle mass is calculated as;
F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )
F'' = 6.29 x 10⁻⁵ N
The net gravitational force on the middle mass;
F (net) = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N
F ( net ) = 8.09 x 10⁻⁵ N
Let the distance of zero net force from the 141 kg mass = d.
then the distance from the 494 kg mass = 0.396 m - d
F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )
F' = 0.704 x 10⁻⁶ / d²
F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²
F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²
for zero net force, the two forces must be equal
0.704 x 10⁻⁶ / d² = 2.47 x 10⁻⁶ / ( 0.396 - d )²
0.704 (0.396 - d )² = 2.47d²
(0.396 - d )² = ( 2.47d² ) / ( 0.704 )
(0.396 - d )² = 3.51d²
0.396 - d = √ ( 3.51d² )
0.396 - d = 1.87d
1.87d + d = 0.396
d (1.87 + 1) = 0.396
d (2.87) = 0.396
d = 0.396 / 2.87
d = 0.138 m
The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m
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If you were Jean’s physician, how would you explain to her the changes that might be occurring in her aging mother?
The changes that occur in old age include decrease in bone density that can affect the normal physiological functioning of her aging mother.
What is aging process?Aging process is the changes and stages of life that an individual naturally undergoes as they advance in age and these experiences are individualized according to lifestyle.
The various changes that occur include but not the least the following:
hearing loss, cataracts and refractive errors, back and neck pain and osteoarthritis, chronic obstructive pulmonary disease, diabetes, depression and dementia. Osteoporosis.The onset of these changes depends on the mother's lifestyle, that is, intake of adequate nutrition, exercise and proper hydration.
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explain the difference between electricity and electrical energy
Explanation:
Electrical energy is caused by moving electric charges called electrons. Electricity is a type of energy that comes from electrical energy.
How did the Egyptians use chemistry?
Answer:
as far as I know they use chemistry to build pyramids block with reaction that why pyramids still exists
Answer: I hope this answer your question
Explanation:
The Egyptians were known in the ancient world as experts in many applied chemistry fields such as metallurgy, wine and beer making, glass making, paper manufacture, paint pigments, dyes, cosmetics, perfumes, and pharmaceuticals.Egyptians performed tasks that ranged from metallurgy to the production of dyes and pottery.They developed ways to measure time and distances , and applied their knowledge to monumental architecture.Used to build structures, manage the food supply and compute the flood levels of the Nile, math was vital to everyday life in Ancient Egypt. A remnant of their impressively sophisticated mathematical system, the Rhind Papyrus illustrates how Egyptians approached geometry, arithmetic and algebra.
A spring that has a spring constant of 500 N/m is compressed a distance of 0.3 meters. How much elastic potential energy is contained in this spring?
_____ J
Answer:
Below
Explanation:
EPE = 1/2 k x^2
= 1/2 * 500 N/m * (.3)^2 = 22.5 J
How many centimeters are in a kilometer? Step by step explanation
100,000 centimeters or 10⁵ centimeters are in a kilometer.
What is unit of length?Any arbitrarily selected and widely used reference standard for length measurement is referred to as a unit of length. The metric system, which is adopted by every nation on earth, is the most widely utilized in modern times.
We know that:
1 kilometer = 1000 meters.
And 1 meter = 100 centimeters.
So, 1 kilometer = 1000 meters
1 kilometer = 1000 × 100 centimeters
1 kilometer = 100,000 centimeters
1 kilometer = 10⁵ centimeters.
Hence, 100,000 centimeters or 10⁵ centimeters are in a kilometer.
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Does a series connection between capacitors always result in equal amount of charge being stored in each capacitor
Answer:
Yes - If a charge of +Q is removed from one side of a battery, a charge of -Q must be removed from the other side of the battery, the charges on the intervening capacitors are likewise equal.
Who came up with a law that forces on the behavior of molecules
Answer: I hope this helps
Explanation:
The law is named after Amedeo Avogadro who, in 1812, hypothesized that two given samples of an ideal gas, of the same volume and at the same temperature and pressure, contain the same number of molecules.n 1811 Avogadro put forward a hypothesis that was neglected by his contemporaries for years. Eventually proven correct, this hypothesis became known as Avogadro's law, a fundamental law of gases.On this day in 1776, Amedeo Avogadro, an Italian scientist known as one of the founders of physical chemistry, was born. Avogadro studied the properties of electricity and liquids, but his best known work was with gases. It was known by 1809 that all gases, when heated equally, expand by the same amount.
A 1,000 kg hot air balloon is drifting along at 3 m/s at a height of 50m above the ground.
How much kinetic energy does the balloon have? ___
How much potential energy does the balloon have? ____
How much total mechanical energy does the balloon have? ___
The Kinetic energy of the hot air balloon is 4500 Joules, the potential energy is 4.9 × 10⁵ Joules, and the total mechanical energy is 4.95 × 10⁵ Joules.
What is the Kinetic energy?The Kinetic energy is the amount of energy which is present in the body of an object which is under motion. The kinetic energy is a vector quantity because it has both the magnitude and direction. The SI unit of KE is Joule. The KE of an object can be calculated by the formula:
KE = 1/2 mv²
KE = 1/2 × 1000 × (3)²
KE = 500 × 9
KE = 4500 Joules
PE = m × g × h
PE = 1000kg × 9.8 × 50
PE = 490,000 Joules
Total Mechanical energy = PE + KE
Total Mechanical energy = 4500 + 490000
Total Mechanical energy = 494500 Joules
Total Mechanical energy = 4.95 × 10⁵ Joules
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A bullet of mass mb=11.9gr is being fired from a stationary gun of mass mg=2.1kg. If the velocity of the bullet is vb=235.1 m/s, what would be the recoil velocity of gun, vg, in m/s?
Answer:given that-
Bullet mass= 11.9gr
gun mass= 2.1
Velocity of bullets= 235.1m/s
A/q,
satisfied-
law of conservation of momentum
pf=pi
(Mass of gun+ mass of bullets)reserve velocity= mass of bullets ×velo of bullets
=>( 2100+11.9)vr=11.9×235.1
=>(2111.9 )vr=2797.69
=>vr=297.69/2111.9
vr=1.32m/
Which is the correct answer
The correct product of the above nuclear reaction is 221/87 Fr (option C).
What is a nuclear reaction?A nuclear reaction is the process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.
In a nuclear reaction, the reaction products may contain a different element or a different isotope of the same element.
Alpha decay is a specific type of nuclear reaction in which an alpha particle made up of helium-4 atom (consisting of two protons and two neutrons), is emitted.
According to this question, the nuclear reaction (alpha decay) of an atom with mass number 225 and atomic number 89 is given. To find the mass number and atomic number of the product, we subtract 4 and 2 respectively.
225 - 4 = 22189 - 2 = 87Therefore, option C is correct.
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Define the term " relative permittivity "
Answer:
Relative permittivity describes the ability to polarize a material subjected to an electrical field.
Explanation:
This polarization originates from a number of sources:
- electron cloud displaced relative to nucleus
- relative displacement of charged ions
- alignment of dipoles in electric field
- movement of charge carriers trapped by interfaces in heterogeneous systems
- movement of ionic charges
In simple terms, relative permittivity tells us how well a material can hold an electric charge. A material with a high relative permittivity can hold more electric charge than a material with a low relative permittivity.
explain some of the technological challenges faced for deep space exploration. (ex. communication, flyby, slingshot effect, Hohmann Transfer orbits)
Answer:
Deep space exploration poses several technological challenges, including:
Explanation:
Maintaining contact with spacecraft is one of the fundamental difficulties in deep space exploration. Due to the time it takes for a signal to travel, communication delays increase as a spacecraft gets further away from Earth. The spacecraft's control and operation may be challenging as a result.
Flyby: Spacecraft frequently utilize the flyby approach to explore deep space. In this method, a spacecraft flies by a celestial body at a high speed while utilizing the planet's gravity to alter its course. To ensure that the spacecraft passes by at the appropriate altitude and speed, this strategy needs exact navigation and timing.
Slingshot effect: The slingshot effect, often referred to as gravity assist, is a method for accelerating a spacecraft by drawing on the gravitational pull of a planet or other celestial body. To make sure that the spacecraft does not collide with the celestial body or fly out into deep space, the trajectory must be carefully predicted.
Orbits used for Hohmann transfers: These orbits are effective for moving a spacecraft from one planet to another. To guarantee that the spacecraft is in the proper location at the appropriate moment to execute the transfer, this procedure, however, need exact calculations.
Power and propulsion: To function for long periods of time during deep space exploration, spacecraft need to have a dependable source of power and propulsion. Solar panels can provide electricity, but they are less effective in deep space, where the sun's light is faint. Alternative energy sources exist, however nuclear power has regulatory and safety issues. Propulsion systems must also be able to resist the severe conditions of deep space and function for extended periods of time.
Radiation protection: High-energy particles and radiation from deep space may kill humans and destroy electronic equipment. To mitigate against these risks, spacecraft must be developed, which can be challenging and expensive.
Cost: Deep space exploration is an expensive undertaking, requiring large investments in technology development, spacecraft design, and mission operations.
These are some of the technological challenges faced in deep space exploration, but it is important to note that many other challenges exist and new challenges will continue to arise as we explore more of the universe.
A car of mass 800 kg initially at rest is accelerated at the rate of 4ms^-2. The kinetic energy of the car after 5 seconds is ?
Answer:
Explanation:
velocity after 5 seconds is 4 x 5 = 20 m/s
KE formula = 0.5mv²
= 0.5 x 800 x 400
= 400²
= 160000 J
or, 160kJ
