Calculate the pH of a solution that is 0.113 M HCI.

Answers

Answer 1

Simplified concentration

[tex]\\ \rm\Rrightarrow 1.13\times 10^{-2}M[/tex]

Now

[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]

[tex]\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})[/tex]

[tex]\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}[/tex]

[tex]\\ \rm\Rrightarrow pH=-0.05+2[/tex]

[tex]\\ \rm\Rrightarrow pH=1.95[/tex]

Highly acidic


Related Questions

Which data are shown on topographic maps?

Answers

Answer:

Topographic maps generally shows Natural features such as Rivers and Lakes.

sometimes they also show some features made by humans like brodges, elevations etc.

Answer:

Topographic maps show contours, elevation, forest cover, marsh, pipelines, power transmission lines, buildings, and various types of boundary lines such as international, provincial, and administrative, and many others.

please give me brainliest

Lisa made observations of stars at different times of the year. She noticed a lot of patterns in the fall, while she couldn't find any patterns in the summer. Why might this be?

Answers

This is because fall has more weather patterns which are repetitive than summer.

What is Weather?

This is defined as the atmospheric condition of a particular place at a given period of time.

The repetitive weather patterns have various effects on the stars which is why they were studied.

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If an element has 11 protons and 12 neutrons and 11 electrons, what is the atomic mass of the element?

Answers

The atomic mass of the unknown element is; 23

How to find the atomic mass of an element?

We are given that;

Number of protons = 11

Number of Neutrons = 12

Number of Electrons = 11

Now, formula for atomic mass is;

Atomic mass = Number of Neutrons + Number of Electrons

Atomic Mass = 12 + 11

Atomic Mass = 23

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Explain how you would determine the charge of a metal, a non
metal and a transition metal for an ion within a compound. Be
prepared to provide the charge of an element on the periodic
table from each of these categories.

Answers

Answer:

In order to determine the charge of these elements you'll have to look at their placement in the periodic table by group number.

Explanation:

To further explain this, there is 18 groups of the periodic table.  These groups include:

Group 1: The alkali metals have a 1+ charge for their entire group.

For example: Sodium would have a charge of 1+.

Group 2: The earth alkali metals all have a charge of 2+. For example Mg has a charge of 2+.

Group 3-12: The transitions metals are a little harder to figure the charge of each, if given the compound they are bonded with you can use that to figure it out but only a few have distinct charges. Such as Ag (Silver) only have a 1+ charge. If you are still trying to figure the charge, try making an electron configuration to figure out it's spare electron count or charge.

Group 13: These elements in group 13 have a typical charge of 3+. For example Al has a charge of 3+.

Group 14: These elements in group 14 have a typical charge of 4+. For example Carbon has a charge 4+

Group 15: These elements start the shift towards a negative charge in the table, so for group 15 the elements have a 3- charge. For example Nitrogen has a 3- charge.

Group 16: These elements continue with a negative in group 16 with a negative charge of 2-. For example Oxygen's charge is 2-.

Group 17: The halogen elements in group 17 have a charge of 1-. For example Chlorine has a charge of -.

Group 18: The noble gases in group 18 do not have a charge because they are some of the most stable elements so they're not looking to gain or lose an electron (That is what a charge is basicaly). So, they're charge is none.  

An unknown compound contains only C , H , and O . Combustion of 6.80 g of this compound produced 16.0 g CO2 and 4.37 g H2O . What is the empirical formula of the unknown compound?

Answers

Answer:

I am a small palm-sized pointing device

How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?

Answers

11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex]  gas measured at 1.3 atm pressure and 298 K

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]

T=298 K

Putting value in the given equation:

[tex]\frac{PV}{RT}=n[/tex]

[tex]n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]

Moles = 0.3588 moles

Now,

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]0.3588 moles = \frac{mass}{32}[/tex]

Mass= 11.48 gram

Hence, 11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K

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You need to measure out exactly 6.7 mL of water for an experiment. Which of the following would be the best tool for the job?

a. A 250 mL beaker​​​

c. A 50 mL graduated cylinder

b. A 10 mL graduated cylinder​​

d. A 150 mL Erlenmeyer flask

Answers

Answer:

The answer for this problem would be "b. A 10 mL graduated cylinder".

Explanation:

The reason for this is because with a instrument that is closer to the value you're trying to measure, the more precise it will be.

For example using a teaspoon to measure something rather than a cup.

The answer will be 10mL graduated cylinder

If you have the following chemical equation and you begin balancing it as such,

C5H10 + O2 --> 5CO2 + 5H2O

How many oxygens do you have on the product side at this point in the balancing?

Answers

Answer:

15 oxygens

Explanation:

Given the partially balanced reaction: [tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \text{5C} \text{O}_{2}}+\text{5H}_\text{2}\text{O}[/tex]

The subscripts (small number to the right of each element symbol) are the number of atoms of the element within each compound/molecule, and the coefficients (numbers in front of each compound) represent the number of that molecule involved in one full reaction (if the equation were balanced).

The product side of the reaction is on the right of the arrow.

To determine the total number of Oxygens on the product side, we need to identify how many Oxygens are in each molecule (the subscript on the Oxygen), and then multiply times the number of that molecule that would be involved (Coefficient of the compound containing Oxygen).  There are multiple compounds on the right side of the equation that contain Oxygen, so we'll need to add together the number of Oxygens each part contributes.

[tex]\text{C}_{\text{5}}\text{H}_{\text{10}}+\text{O}_{\text{2}} \rightarrow \bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}[/tex]

[tex]\text{\# reactant-side Oxygens}=\bold{5}\text{C} \bold{O_{2}}+\bold{5}\text{H}_\text{2}\bold{O}\\=5 \text{ CO}_{\text{2}}\text{ molecules} *\frac{\text{2 Oxygens}}{\text{1 CO}_{\text{2}}\text{ molecule}}+5 \text{ H}_{\text{2}}\text{O molecules} *\frac{1\text{ Oxygen}}{\text{1 H}_{\text{2}}\text{O molecule}}\\=10\text{ Oxygens}+5\text{ Oxygens}\\=15\text{ Oxygens}[/tex]

The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0 % yield. How many grams would be produced from 7.45 g of butanoic acid and excess ethanol?
Express your answer in grams to three significant figures.

Answers

7.66g of ethyl butyrate is produced.

The reaction is

CH₃CH₂CH₂COOH + CH₃CH₂OH ----> CH₃CH₂CH₂COOCH₂CH₃

The molar mass of butanoic acid is 88.11g/molWe have 7.45g of butanoic acidThe moles of butanoic acid we have is 7.45/88.11 = 0.0845 molIf the yield is 100%,  1 mole of butanoic acid gives 1 mole of ethyl butyrateBut the reaction yield is 78%1 mole of butanoic acid gives 0.78 mole of ethyl butyrate

From 0.0845 mol of butanoic acid we get 0.78 x 0.0845 = 0.66 mol of ethyl butyrate.

The molar mass of ethyl butyrate is 116.16g/mol

So 0.66 x 116.16 = 7.66g

7.66g of ethyl butyrate is produced.

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- How many grams are in 1.4 x 10¹5 atoms of calcium?

Answers

Answer:

40 g= 6.022×10²³

x=1.4×10¹⁵

x=40g×6.022×10²³/1.4×10¹⁵

x=17.77×10⁸

Acid rain is caused by which of the following?
excess carbon dioxide
deforestation
nitrogen compounds in the soil
nitrogen compounds in the air

Answers

Answer:

nitrogen compounds in the air

Explanation:

11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP .If 3.41 grams of KHC are needed to exactly neutralize 31.2 mL of a potassium hydroxide solution, what is the concentration of the base solution?

13B.
H3AsO4 + H2C2O4—--------2CO2 + H3AsO3+ H2O

In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.



name of the element oxidized:


name of the element reduced:


formula of the oxidizing agent:


formula of the reducing agent:

Answers

For the reactants,

The oxidation number of hydrogen = +1The oxidation number of oxygen = -2The oxidation number of arsenic = +5The oxidation number of carbon = +3

For the products,

The oxidation number of hydrogen = +1The oxidation number of oxygen = -2The oxidation number of arsenic = +3The oxidation number of carbon = +4

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: [tex]\text{H}_{3}\text{AsO}_{4}[/tex]

formula of the reducing agent: [tex]\text{H}_{2}\text{C}_{2}\text{O}_{4}[/tex]

Calculate the pH of a solution with [H+] = 2.52 x 10^-5.​

Answers

Answer:

pH = 4.6  

Explanation:

pH is the negative of the log of the hydrogen ion concentration

- log { 2.52 x 10^-5)   = ~ 4.6

Fe + H₂O → Fe3O4+H₂ help

Answers

Answer:

3Fe + 4H₂O --> Fe3O4 + 4H2

A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2SO4). She records a neutral pH after adding 20 mL of the sodium hydroxide solution to 50 mL of the sulfuric acid solution.

What is the concentration of the sulfuric acid solution?
A.
0.24 M
B.
0.12 M
C.
2.1 M
D.
1.0 M
E.
0.48 M

Answers

From the calculations, the concentration of the acid is 0.24 M.

What is neutralization?

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA =  50 mL

VB = 20 mL

NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

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Barium nitrate (Ba(NO3)2) reacts with sodium chloride (NaCl) in a double replacement (displacement) reaction, shown below.
Ba(NO3)2(aq)+NaCl(aq)-->???

How many grams of barium salt are produced when a solution containing 21.7 g of Barium nitrate is mixed with a solution containing excess sodium chloride?

Use 261.34 as the molar mass for barium nitrate. Round to three significant digits.

Answers

Answer:

you know that they will be a displacement reaction that will form a barium salt:

Ba(NO3)2+ 2NaCl--> BaCl2 + 2NaNO3

So now that we have that formula and the molecular weight we can determine how much salt will be made. So here we convert the grams to moles

(42.3g Ba(NO3)2)*(1 mole/261.34g) = 0.16185 mol

In the molecular formula we know that 1 mole of Barium nitrate will create 1 mole of Barium chloride, so in this case (in a perfect world) you should get 0.16185 mole of barium chloride (208.23 g/mol) that we then have to convert to grams.

(0.16185 mol BaCl2) * ( 208.23 g/mol) = 33.7037 g of Barium Chloride (rounded to 3 significant digits = 33.7g)

If a utility burned 7.57 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide were emitted? Answer in scientific notation.

Answers

So mass of sulphur

[tex]\\ \rm\Rrightarrow 0.02\times 757\times 10^{6}[/tex]

[tex]\\ \rm\Rrightarrow 1514\times 10^4[/tex]

S+O_2–≥SO_2

Moles =64/32=2

So

So tons of sulphur dioxide

[tex]\\ \rm\Rrightarrow 2(1516)10^4[/tex]

[tex]\\ \rm\Rrightarrow 3032\times 10^4ton[/tex]

Explanation:

2% of 2million tons of sulphur=

2÷100×7.57E9

That is;

[tex] \frac{2}{100} \times 7.57 \times 10 {}^{6} = 0.02 \times 7.57 \times 10 {}^{6} \\ = 2 \times 10 {}^{ - 2} \times7.57 \times 10 {}^{6} = 2 \times 7.57(10 {}^{ - 2 + 6}) \\ = 15.14 \times 10 {}^{4} (for \: sulphur) \\ for \: sulphur \: dioxide = so2 \\ the \: molar \: mass \: of \: so2 = 64g.mol {}^{ -1} \\ if \: 32grams \: of \: sulphur \: weighs \: 15.14 \times 10 {}^{4} tones \\ 64grams \: will \: weigh \: \frac{64}{32} \times 15.14 \times 10 {}^{4} \\ = 2 \times 15.14 \times 10 {}^{4} \\ = 30.28 \times 10 {}^{4} \\ or = 3.028 \times 10 {}^{5} tones[/tex]

A gas has a volume of 350 mL at 45 oK. If the volume changes to 400 mL, what is the new temperature?

Answers

Answer:

T₂ = 39.4 °K

Explanation:

Because you are only dealing with volume and temperature, you can use Charles' Law to find the missing value. The formula looks like this:

V₁ / T₁ = V₂ / T₂

In this formula, "V₁" and T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You have been given values for all of the variables except for "T₂". Therefore, by plugging these values into the formula, you can simplify to find the answer.

V₁ = 350 mL                     T₁ = 45 °K

V₂ = 400 mL                     T₂ = ?

V₁ / T₁ = V₂ / T₂                                        <----- Charles' Law formula

(350 mL)(45 °K) = (400 mL)T₂                <----- Insert values into variables

15750 = (400 mL)T₂                                <----- Multiply left side

39.4 = T₂                                                 <----- Divide both sides by 400

Which statement best explains why gneiss is composed of layers but there are no layers in granite?

Gneiss is a sedimentary rock and granite is a metamorphic rock.
Gneiss is a metamorphic rock and granite is a sedimentary rock.
Granite is formed due to the slow cooling of magma below Earth's surface and gneiss is formed due to metamorphosis.
Granite is formed due to the accumulation of sediments and gneiss is typically formed due to intense heat and pressure.

Answers

Gneiss is a sedimentary rock and granite is a metamorphic rock. That is option A.

What are rocks?

Rocks are geological hard materials that are made up of various types which include:

Sedimentary rocks: These are rocks that made up of various layers formed from sediments. Example is the gnesis.

Metamorphic rocks: These are rocks that are form from pre existing rocks that undergoes some transformation. Example is granite

Therefore, Gneiss is a sedimentary rock and granite is a metamorphic rock.

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Answer:

C

Granite is formed due to the slow cooling of magma below Earth's surface and gneiss is formed due to metamorphosis.

Explanation:

I took the test!

If 4.5 moles of an ideal gas has a temperature of 286 K and a pressure 9.4 atm, what is the volume of the container

Answers

Answer:

V = 11 L

Explanation:

To find the missing value, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this formula,

 ----> P = pressure (atm)

 ----> V = volume (L)

 ----> n = number of moles

 ----> R = constant (0.0821 atm*L/mol*K)

 ----> T = temperature (K)

You have been given all of the values in the correct units. Therefore, you can plug these values into the equation and simplify to find volume. The answer should have 2 sig figs to match the given value with the lowest amount of sig figs.

PV = nRT

(9.4 atm)V = (4.5 moles)(0.0821 atm*L/mol*K)(286 K)

(9.4 atm)V = 105.6627

V = 11 L

Select the correct answer.
Which type of crude oil is considered to be the highest quality for gasoline?
O Brent Blend
O West Texas Intermediate
O OPEC Blend
O All crude oil

Answers

The type of crude oil that is considered to be the highest quality for gasoline is West Texas Intermediate (Option B).

What is oil?

Oil is a fossil fuel obtained from Earth's crust, which is fundamental nowadays to generate electricity.

West Texas Intermediate is a highly pure and high-type energy source of crude oil used in industry.

In conclusion, the type of crude oil that is considered to be the highest quality for gasoline is West Texas Intermediate.

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What is the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH in the following chemical reaction? 2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)

Answers

Answer:

69.6 g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.

Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (LiOH): 23.947 g/mol

2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO): 44.007 g/mol

75.8 g LiOH          1 mole             1 mole CO₂               44.007 g
------------------  x  ----------------  x  -----------------------  x  -------------------  =
                            23.947 g         2 moles LiOH              1 mole

= 69.6 g CO₂

The mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g

What is Mole?

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of LiOH = 75.8g

Moles of LiOH = mass / molar mass

                       = 75.8 / 24 = 3.15 moles

From the reaction,

2 moles of LiOH react with 1 mole of CO₂

1 mole of LiOH needs 0.5 moles of CO₂

thus, 3.15 moles will need 0.5 × 3.15 moles = 1.575 moles of CO₂

Mass of Carbon dioxide = 1.575 × 44

                                       = 69.3g of carbon dioxide

Therefore, the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH is 69.3g

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What is the SI unit used to measure weight?

Answers

Answer:

The si unit used to measure weight is kilogram /kg

Why barbituric acid in name of acid

Answers

Barbules
Barrbuuuuuuuuuuuuuu

Question 5 of 10
Platinum has a density of 21 g/cm³. A platinum ring is placed in a graduated
cylinder that contains water. The water level rises from 4.0 mL to 4.2 mL
when the ring is added. What is the mass of the ring?
A. 2.6 g
OB. 3.8 g
OC. 4.2 g
OD. 5.2 g
B

Answers

Answer:

4.2  g  

Explanation:

The VOLUME of the ring is   4.2 - 4.0 = .2 ml  = .2 cm^3

the MASS of the ring is this times the density

.2 cm^3  *  21 g/cm^3 = 4.2 g

Answer:

the answer is c

Explanation:

density is mass/volume

so mass=density × volume

but we take the change is volume that is v2-v2=4.2-4=0.2ml

but the density is in gm/cm^3 so we should convert ml into cm^3. eventually they are equal so mass=21×0.2=4.2

Which of the following is an impact of an increase in motor vehicles in cities?

Oxygen levels have increased
Carbon dioxide levels have increased
Supply of renewable resources has stopped
Supply of nonrenewable resources has become unlimited

Answers

Carbon dioxide levels have increased

For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen monoxide ( g ) + hydrogen ( g ) nitrogen ( g ) + water ( l ) What is the maximum amount of nitrogen gas that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams

Answers

NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete

What is a limiting reagent?

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

[tex]2NO(g) +2H_2(g)[/tex] → [tex]N_2 +2H_2O[/tex]

Moles of nitrogen monoxide

Molecular weight: [tex]M_(_N_O_)[/tex]=30g/mol

[tex]n_(_N_O_) =\frac{mass}{molar \;mass}[/tex]

[tex]n_(_N_O_) =\frac{22.0}{30g/mol}[/tex]

[tex]n_(_N_O_) = 0.73 mol[/tex]

Moles of hydrogen

Molecular weight: [tex]M_(_H_2_)[/tex]=30g/mol

[tex]n_(_H_2_) =\frac{mass}{molar \;mass}[/tex]

[tex]n_(_H_2_) =\frac{5.80g}{2g/mol}[/tex]

[tex]n_(_H_2_) = 2.9 mol[/tex]

Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

[tex]n_(_N_2_) =[/tex] (2.9 mol- 0.73 mol NO x [tex]\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}[/tex]) x [tex]\frac{2g \;of \;H_2}{mole \;of \;H_2}[/tex]

[tex]n_(_N_2_) =[/tex]4.34 g

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Predict the shape of the molecule.

Answers

The Correct option is A. octahedral

because the molecule has 6 sigma bonds that results into sp³d² hybridization.

and octahedral structure is formed

Answer:

Octahedral

Explanation:

You have a atom connected to 6 others and each of the bonds are similar

C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

Answers

Carbon dioxide + Water Glucose (sugar) + Oxygen CO2 + H2O C6H12O6 + 6O2 Cellular respiration or aerobic respiration is a series of chemical reactions which begin with the reactants of sugar in the presence of oxygen to produce carbon dioxide and water as waste products.

How many moles of nitrogen, N , are in 69.0 g of nitrous oxide, N2O ?

Answers

Answer:

1.57

Explanation:

moles = mass / molar mass

moles = 69 / 44.013

moles = 1.57

moles N₂O = 69 : 44 g/mol = 1.568

N₂O : 2 moles N, 1 mole O

moles N = 1.568 x 2 = 3.136

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