Can 702 be written as the product of two prime numbers?

Answers

Answer 1

Answer:

Since the sum of its digits equals nine, 702 is divisible by nine.

702 is a composite number.

Prime factorization: 702 = 2 x 3 x 3 x 3 x 13, which can be written 702 = 2 x (3^3) x 13

The exponents in the prime factorization are 1, 3, and 1. Adding one to each and multiplying we get (1 + 1)(3 + 1)(1 + 1) = 2 x 4 x 2 = 16. Therefore 702 has exactly 16 factors.

Factors of 702: 1, 2, 3, 6, 9, 13, 18, 26, 27, 39, 54, 78, 117, 234, 351, 702

Factor pairs: 702 = 1 x 702, 2 x 351, 3 x 234, 6 x 117, 9 x 78, 13 x 54, 18 x 39, or 26 x 27

Taking the factor pair with the largest square number factor, we get √702 = (√9)(√78) = 3√78 ≈ 26.49528.


Related Questions

PLEASE ANSWER THIS QUESTION ASAP!!

Answers

have you tried doing (3x+18)+(9x-27)=99

Can someone help me?

Answers

It’s d hope this helps you

Which of the following statements best gives the reasons that a data usage bill for a smart phone is an essential (variable) expense? a. It is an obligation to pay, but the spender has some control over its amount. b. It cannot be eliminated in a later budget, in order to save money. c. It is expected to be the same amount every month. d. Bills for services rendered have a higher priority than any other type of expense. Please select the best answer from the choices provided A B C D

Answers

Answer: I’m pretty sure its A on e2020

Step-by-step explanation:

It is an obligation to pay, but the spender has some control over the amount.

Option A is the correct answer.

We have,

The reason that a data usage bill for a smartphone is an essential (variable) expense is that it is an obligation to pay.

In other words, the phone service is necessary for the phone to function properly, and therefore, the bill must be paid.

However, the spender has some control over its amount by managing their data usage, such as turning off data for certain apps or using Wi-Fi instead of cellular data.

This means that while the bill cannot be eliminated entirely, the spender can take steps to reduce the amount owed.

Statement b is incorrect because while the bill cannot be eliminated entirely, it can be reduced by managing data usage.

Statement c is incorrect because the amount of the bill is not expected to be the same every month, as it will depend on how much data is used. Statement d is incorrect because while bills for services rendered may be a priority, they do not necessarily have a higher priority than other types of essential expenses, such as food or housing.

Thus,

It is an obligation to pay, but the spender has some control over the amount.

Learn more about smartphones here:

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What is the slope and y-intercept of the equation 6x - 1 = 3y - 10?*
(1 Point)
Om = 2, b = 3
O m = 3, b = 4
m = 6, b = 9

Answers

Answer:

m = 2, b = 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Given

6x - 1 = 3y - 10 ( add 10 to both sides )

6x + 9 = 3y ( divide all terms by 3 )

2x + 3 = y , that is

y = 2x + 3 ← in slope- intercept form

with slope m = 2 and y- intercept b = 3

The table shows the height of the tree that Margo planted over an 11-month period. A 2-column table with 6 rows titled Growth of Margo's Tree. The first column is labeled Month with entries 1, 3, 5, 7, 9, 11. The second column is labeled Height of Tree (feet) with entries 1.4, 1.5, 2.1, 2.7, 3.0, 1.8. Which statement can be supported by the information in the table?

Answers

Answer:

3. The tree increased in height each month until the time period between month 9 and month 11.

The statement that can be supported by the information in the table is that the tree increased in height each month until the time period between month 9 and month 11.

What is s table?

It should be noted that a table simply means a list of numbers to that depicts a particular information.

In this case, the statement that can be supported by the information in the table is that the tree increased in height each month until the time period between month 9 and month 11.

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do you inverse to slove

Answers

Answer: Yes, In mathematics, an inverse function (or anti-function) is a function that "reverses" another function: if the function f applied to an input x gives a result of y, then applying its inverse function g to y gives the result x, and vice versa, i.e., f(x) = y if and only if g(y) = x.

can someone explain please

Answers

It is saying that irrational numbers like pie can be broken down into approximate irrational numbers and plotted onto points.

Example [tex]\sqrt{1.6}[/tex] approximate value is 1.264911

That number can be plotted in place of [tex]\sqrt{1.6}[/tex]

I recommend using a app called cymath it helped sm invade ur confused use it I promise it will help u sm

34,776 is divisible by: 2 3 9 6 pick the right answers.

Answers

[tex]\tt Step-by-step~exlpanation:[/tex]

To find out the answer, we would have to try and divide all the numbers.

[tex]\tt \frac{34,776}{2}= 17,388\\ YES[/tex]

[tex]\tt \frac{34,776}{3}= 11,592\\YES[/tex]

[tex]\tt \frac{34,776}{9}=3,864\\ YES[/tex]

[tex]\tt \frac{34,776}{6}= 5,796\\YES[/tex]

[tex]\large\boxed{\tt Our~final~answer:~ALL ~(2,3,9,6)}[/tex]

Armando started the school year with 15 pencils and gave away 3 pencils every month. Daniel started the school year with 7
pencils and bought 1 every month.
After how many months did Armando have the same number of pencils as Daniel?
A-8
B-2
C-12
D-5

Answers

Answer:

B-2

Step-by-step explanation:

It is B, because On the first month, Armando has 12 and Daniel has 8, now on the 2nd month Armando has 9 because he gives away 3 each month and Daniel now has 9 because he adds one each month, so all in all, they have the same exact number of pencils on the 2nd month

After 5 months is when Armando and Daniel had the same number of pencils.

Rewrite as a simplified fraction. 0 1

Answers

Answer:

1/10

Step-by-step explanation:

Answer:

1/100

Step-by-step explanation:

it would be 1/10 if the decimal was 1 space to the right.

Mrs. Trobiano regularly works 40 hours per week, at a rate of d dollars
per hour. Last week she worked h overtime hours at double time.
Express her total weekly salary algebraically.

Answers

Answer:

d = 40w x 2

Step-by-step explanation:

Which choice is the correct graph of|xl> 5?

Answers

Answer:

c

Step-by-step explanation:

WANNA HAVE BRAINIEST | Simplify (4x - 6) + (5x + 1). (1 point)
a
9x + 5
b
9x - 5
с
X-5
-X-5

Answers

Answer:

9x-5

Step-by-step explanation:

(4x - 6) + (5x + 1)

Add like terms

4x+5x=9x

-6+1=-5

Combine

9x-5

Hope this helps! Plz award Brainliest : )

b. 9x - 5
hope this helps:)

If a dog needs to eat 1 3/4 of dry food 3 times a day. How much does he eat in 1 feeding

Answers

Answer:.583

Step-by-step explanation:

What do you do with the exponents when dividing powers with the same base

Answers

Answer:

When dividing numbers with the same base, you subtract the exponents.

Step-by-step explanation:

For example, 8^5/8^3 = 8^2 or 64

Help I am kinda confused on this!

Answers

The first one has no solutions and the second one, all numbers are correct. If you combine the 2 equations for the first one you get 13=64 and that is absolutely wrong. The second you would get 52=52 so x and y can be anything

Ellen sells wedges of cheese at the local farmers' market. To make the wedges, she cuts a big 5-pound block of cheese into 16 pieces. How much does each wedge of cheese weigh?

Answers

Given :

Ellen sells wedges of cheese at the local farmers' market. To make the wedges, she cuts a big 5-pound block of cheese into 16 pieces.

To Find :

How much does each wedge of cheese weigh.

Solution :

Let , weight of each wedge of cheese is x.

16 pieces of wedge of cheese weight 5 pounds .

So,

[tex]16x=5\\\\x=\dfrac{5}{16}\\\\x=0.3125\ pounds[/tex]

Therefore, weigh of cheese is 0.3125 pounds.

Hence, this is the required solution.

What are the constants
in the equation 3x+2y+4

Answers

Answer:

4

Step-by-step explanation:

The constant is the number without a variable, usually being added or subtracted from the variable but not multiplied or divided by it.

which expression is equivalent to 1.8(2x ÷7)-15​

Answers

Step-by-step explanation:

1.8(2/7x)15

1.8×15(2/7x)

27(2/7x)

54/7x

what is the cube root of 8/27

Answers

Answer:

Cube root of 8/27 is 2/3

[tex] \sqrt{ \frac{8}{27} } [/tex]

[tex] = \sqrt{ (\frac{2}{3} {)}^{2} } [/tex]

[tex] = \frac{2}{3} [/tex]

To start a board game, the player who rolls two sixes gets to go first. What is the probability that a player will roll two
number cubes and get two sixes?
1
36
OH
1
18
oth 음
4
O 15

Answers

Answer:

1 over 36

Step-by-step explanation:

Answer:

1 over 36 or A

Step-by-step explanation:

Trust me bro;)

y-0=1/4(x-3) in slope intercept form

Answers

Answer:

y= 1 /4 x − 3 /4

Step-by-step explanation:

y=mx+b

Mrs. Johnson wants to take her class to the fair. The bus will cost $200 and the fair charges $4 per student. She has a $300 budget, what is the maximum number of students she can take to the fair.

Answers

Answer:

This is simple,

Step-by-step explanation:

If the bus costs 200$ and the fair charges 4$ per students that means you have to do this:

300$ budget - 200 of the bus = 100$ left

and if $4 per student:

100 divided by 4 = 25

she can take 25 students

Hope this helps!

True or False: The variables in the equation 4x-(5y)2=64x-(5y)2=6 are 4, 5, and 6

Answers

False, variables can only be expressed through letters

What is 2 x 10 to the -6th power?

Answers

Answer:

2 x 10 to the -6th power is .000002.

Answer:

[tex]\frac{1}{20^} ^6[/tex]

Step-by-step explanation:

Depends what you mean

if you mean 2x10^-6 it would be different than (2x10)^-6 but I'll solve for the latter.

[tex](2*10)^-6 = (20)^-6\\20^-6 = \frac{1}{20^6}[/tex]

1/20^6 would just be

[tex]\frac{1}{64000000}[/tex]

-2(-7n-8)=-39+3n. plz solve and explain the answer​

Answers

Answer:

n = -5

Step-by-step explanation:

-2(-7n-8)=-39+3n

Distribute

14n +16 = -39 +3n

Subtract 3n from each side

14n -3n +16 = -39 +3n -3n

11n +16 = -39

Subtract 16 from each side

11n +16 -16 = -39 -16

11n = -55

divide by 11

11n /11 = -55/11

n = -5

3 units, 2units, 2 units the area of the figure square units

Answers

12 square units is the answer

Answer:

12

Step-by-step explanation:

im taking the test jjiiiuy teñido itself

Owen paid $15 to download some of his favorite
songs. He paid $2.50 per song How many songs did
he download
Owen downloaded 1 songs

Answers

Answer:

6

Step-by-step explanation:

6x2.5=15

yeßssssssss I do math easy pressure

If p=(1/3) and q=4 2/7 then p2^q=

Answers

I think the answer is 18!!!!!!

Answer:

1. [tex]\frac{10}{21}[/tex]

2. [tex]\frac{405}{49} = 8\frac{13}{49}[/tex]

Step-by-step explanation:

first one:

[tex]p^{2} q[/tex] = [tex](\frac{1}{3})^{2}[/tex] × [tex]4\frac{2}{7}[/tex] = [tex]\frac{1}{9}[/tex] × [tex]\frac{30}{7}[/tex] = [tex]\frac{1}{3}[/tex] × [tex]\frac{10}{7}[/tex] = [tex]\frac{10}{21}[/tex]

second one:

[tex]t^{2}[/tex]/[tex]s[/tex] = [tex](1\frac{2}{7})^{2}[/tex] / [tex]\frac{1}{5}[/tex] = [tex](\frac{9}{7})^{2}[/tex] × [tex]5[/tex] = [tex]\frac{81}{49}[/tex] × [tex]5[/tex] = [tex]\frac{405}{49}[/tex] = [tex]8\frac{13}{49}[/tex]

If A, B,C are the angles of a triangle then prove: (the following in picture)
Please help me to prove this. ​

Answers

The proof for this is simple. Let's say that A + B + C = π. From here on we require several trigonometric identities that must be applied.

[tex]\cos \left(A\right)+\cos \left(B\right)+\cos \left(C\right) \\= 2 * cos((A + B) / 2) * cos((A - B) / 2) + \cos C \\= 2 * cos((\pi /2) - (C/2)) * cos((A - B) / 2) +\cos C \\= 2 * sin(C/2) * cos((A - B) / 2) + (1 - 2 * sin^2 (C/2)) \\= 1 + 2 sin (C/2) * cos((A - B) / 2) - sin (C/2) \\= 1 + 2 sin (C/2) * cos((A - B) / 2) - sin((\pi /2) - (A + B)/2 ))\\= 1 + 2 sin (C/2) * cos((A - B) / 2) - cos((A + B)/ 2)\\= 1 + 2 sin (C/2) * 2 sin (A/2) * sin(B/2) \\= 1 + 4 sin(A/2) sin(B/2) sin(C/2)[/tex]

Hope that helps!

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                     → A + B = π -  C

                                                     → C = π - (A + B)

Use Sum to Product Identity:  cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use Product to Sum Identity:  2 sin A · sin B = cos [(A + B)/2] - cos [(A - B)/2]

Use the Double Angle Identity:   cos 2A = 1 - 2 sin² A

Use the Cofunction Identity: cos (π/2 - A) = sin A

Proof LHS → RHS:

LHS:                       cos A + cos B + cos C

                           = (cos A + cos B) + cos C

[tex]\text{Sum to Product:}\qquad 2\cos \bigg(\dfrac{A+B}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Given:}\qquad 2\cos \bigg(\dfrac{\pi -C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C\\\\\\.\qquad \qquad =2\cos \bigg(\dfrac{\pi}{2} -\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Cofunction:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Double Angle:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos\bigg(2\cdot \dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad =2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+1-2\sin^2 \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)-2\sin^2\bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{Factor:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{C}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{\pi-(A+B)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{\pi}{2}-\dfrac{A+B}{2}\bigg)\bigg][/tex]

[tex]\text{Cofunction:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\cos\bigg(\dfrac{A+B}{2}\bigg)\bigg][/tex]

[tex]\text{Product to Sum:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \sin\bigg(\dfrac{B}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =1+4\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\sin \bigg(\dfrac{A}{2}\bigg)\cdot \sin\bigg(\dfrac{B}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{LHS = RHS:}\ 1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)=1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)\quad \checkmark[/tex]

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