Answers
Answer:
The rod is stretched because there is a larger gravitational force on the mass closest to mass M.
F = G M m / r^2 - G M m / (r + l)^2 the difference of the forces on m's
F = G M m [1 / r^2 - 1 / (r + l)^2]
[1 / r^2 - 1 / (r + l)^2] = (r^2 + 2 r l + l^2 - r^2 / [r^2 (r + l)^2]
= (2 r l + l^2) / [r^2 (r + l)^2]
if l is small compared to r = (2 r l ) / [r^2 (r + l)^2]
= (2 r l ) / [r^4 + 2 r^3 l ]
Related Questions
a 10.00mf parallel-plate capacitor is connected to a 24.0v battery. after the capacitor is fully charged ,the
battery is disconnected without loss of any of charge on the plates.
a) a voltmeter is connected across the two plates without discharging them.what does it read
b)what would the voltmeter read if the plate separationwere doubled?
Answers
The answer to the first part of the question is 24 V and the answer to the second part of the question is 48 V.
The formula which relates Charge, Capacitance and Voltage is
Charge = Capacitance × Voltage
Q = CV
where Q denotes the charge, C denotes the capacitance and V denote the voltage.
Using the above formula the charge on the capacitance will be
Q = CV
C = 10 mF
V = 24 V
Q = 240 mC
Charge on capacitance is 240 mC.
Now after we disconnect the battery
C = 10 mF (will remain same)
Q = 240 mC
V = Q/C
V = 240/10 V
V = 24 V
So after we removed the battery, The voltage will remain same.
Now we know that parallel plate capacitor formula is
C = ε(A/d)
from here
C ∝ 1/d, and as there is no loss of charge we can say that V ∝ 1/d
Form C ∝ 1/d and V ∝ 1/C we can state that
V ∝ d {where d is the measurement of separation between the plates}
so if we double the distance between the plates then, the voltage will also get double.
Previously our voltage was 24 V, now if we double the distance between the plates the voltage will also get double, and it will become 48 V.
So, the voltmeter will take a reading of 24 V if voltmeter is connected across the two plates without discharging them, and if we double the plate separation then it will take 48 V as reading.
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Using what you learned above, try to predict the missing entries in the table below. Use the simulation to check your answer and type in the correct answer.
Answers
there is no pic or whatever to show
Which is not an example of static electricity?
A. Clothes sticking together in the dryer
B. Getting shocked when you touch a door knob
C. plugging in a lamp
Answer asap
Answers
Plugging in a lamp is not an example of Static electricity. Thus, the correct option is C.
What is Static electricity?Static electricity may be defined as the consequence of an imbalance between negative and positive charges in an object. It does not involve the direct flow of electrons throughout a wire.
Clothes sticking together in the dryer and getting shocked when you touch a doorknob are examples of static electricity while plugging in a lamp is an example of mobile electricity that mediates the direct flow of electrons to generate an electric current and as a result, the lamp glows.
Therefore, the correct option for this question is C.
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Which graph shows constant acceleration with correctly placed independent and dependent variables?
Answers
Answer:
a = (V2 - V1) / t equation for constant acceleration
if t the independent variable is placed on the abcissa or x-axis and V the dependent variable is placed on the ordinate or y-axis then the acceleration would be the slope at the point considered.
Which of the following best represents the energy transformations in an
electric motor?
A. Mechanical energy
in electromagnet
-
changing electric field -> electrical energy
B. Electrical energy in current → magnetic energy in electromagnet
OC. Electrical energy in current → changing magnetic field →
mechanical energy
-
OD. Mechanical energy → changing magnetic field → electrical
energy in current
Answers
The energy transformations in an electric motor are, electrical energy in current → changing magnetic field → mechanical energy. Option C is corect.
What is the law of conservation of energy?According to the law of conservation of energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.
The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.
An electric motor is a mechanism that turns electricity into mechanical energy.
The interaction between the motor's magnetic field and electric current in a wire winding generates force in the form of torque imparted to the motor's shaft in most electric motors.
An electric generator is physically equivalent to an electric motor, but it converts mechanical energy into electrical energy using a reversed flow of power.
In an electric motor, energy is transformed into mechanical energy, electrical energy in current, and changing magnetic energy.
The energy transformations in an electric motor are;
Electrical energy in current → changing magnetic field → mechanical energy.
Hence option C is correct.
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Gravity will have a greater effect on an object with?
Answers
C1=10 μF , C2= 50 μF, C3=9 μF, C4=2 μF, C5= 0.1 μF
What is the equivalent capacitance of these capacitors as they are arranged?
Answers
The equivalent capacitance of these capacitors as they are arranged in series and parallel will be 0.093 μF and 71.1 μF.
What is a capacitor?A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.
If the capacitor is connected in the series the equivalent capacitance is found as;
[tex]\rm \frac{1}{c_{eq}} = \frac{1}{c_1} +\frac{1}{c_2} +\frac{1}{c_3} +\frac{1}{c_4} +\frac{1}{c_5} \\\\\ \rm \frac{1}{c_{eq}} = \frac{1}{10} +\frac{1}{50} +\frac{1}{9} +\frac{1}{2} +\frac{1}{0.1} \\\\\ \frac{1}{c_{eq}} = 0.1+0.02+0.11+0.5+10 \\\\ \frac{1}{c_{eq}} = 10.7 \\\\ c_{eq} = 0.093 \ \mu F[/tex]
If the capacitor is connected in parallel the equivalent capacitance,cₐ is found as;
cₐ= c₁+c₂+c₃+c₄+c₅
cₐ = 10+50+9+2+0.1 μF
cₐ =71.1 μF
Hence, the equivalent capacitance of these capacitors as they are arranged in series and parallel will be 0.093 μF and 71.1 μF.
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PLEASE ANSWER THIS FAST
The electric field lines show the way (blank) charges would move if they were in the field brainly.
Answers
Answer:
Explanation:
If a positive charge is moving in the direction of electric field vector, its velocity will increase, whereas positive charge moving opposite to the direction of the electric of electric field will decelerate.
The case with a negative charge is just reversed verse, it will decelerate when moving along the field direction and accelerate when moving opposite to it.
Help with this :
What device does not store electric current or charge?
a) Capacitor
b) Transforme
c) vacuum tube
I know a capacitor is a device for storing charge, but it also says from a physical point of view, a capacitor does not store charge or electric current, but simply latent mechanical energy.
So what will be the answer?
Answers
Answer:
You are correct, the answer is capacitor
If a current uses 31 amperes and has a voltage of 110 volts, how many watts does it dissipate?
Answers
Considering the Watt's law, if a current uses 31 amperes and has a voltage of 110 volts, it dissipates 3,410 Watts.
CurrentCurrent is the physical magnitude that expresses the amount of electricity that flows through a conductor in unit time and is measured in amps.
VoltageThe voltage is the difference between the electrical charge that leaves the source and the one that finally reaches the end of the circuit. It is expressed in volts.
Watt's LawWatt's Law refers to the electrical power of an electronic component or device and is defined as the power consumed by the load is directly proportional to the voltage supplied and the current flowing through it. The unit of power is the Watt.
Knowing the voltage and current, this law is expressed as:
P = V×I
Power in this caseIn this case, you know:
V= 110 voltsI= 31 amperesReplacing in Watt's Law:
P = 110 volts× 31 amperes
Solving:
P= 3,410 Watt
Finally, if a current uses 31 amperes and has a voltage of 110 volts, it dissipates 3,410 Watts.
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an ac voltage of 12.0 v is applied to the primary transformer that has 3 times as many turns in the secondary than in the primary. what is the voltage of the secondary?
Answers
The voltage of the secondary will be 36 V.From the given conditions primary transformer has 3 times as many turns in the secondary coil.
What is induced voltage?Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
Given data;
Primary coil voltage,[tex]\rm V_P = 12 \ v[/tex]
Secondary coil voltage,[tex]\rm V_s = ?[/tex]
No turns in the primary coil,[tex]\rm N_p[/tex]
No turns in the secondary coil,[tex]\rm N_s[/tex]
From the given condition;
[tex]\rm N_s = 3N_p[/tex]
For a transformer,
[tex]\rm \frac{V_p}{V_s}= \frac{N_p}{N_s} \\\\ \rm \frac{12}{V_s}= \frac{N_p.}{3N_p} \\\\ V_s = 36 \ V[/tex]
Hence the voltage of the secondary will be 36 V.
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A long thin solid rod lies along the positive x-axis. One end is at x = 1.80 m and the other at x = 3.40 m. The linear mass density is λ = a[tex]x^{3}[/tex] + bx, where λ is measured in kg/m, and the constants have the following values: a = 1.70 kg/[tex]m^{4}[/tex] and b = 2.20 kg/[tex]m^{2}[/tex].
1. Determine the total mass of the rod.
2. Calculate the x-coordinate of the center of the mass for this rod.
Answers
1. The total mass of the rod is 61.48 kg.
2. The x-coordinate of the center of the mass for this rod is 172.6021 m.
What is density?The density is the ratio of the mass and the volume of the object. It is denoted by ρ.
ρ = mass/Volume = m/V
Given a long thin solid rod lies along the positive x-axis. One end is at x = 1.80 m and the other at x = 3.40 m. The linear mass density is
λ = ax³ + bx,
where λ is measured in kg/m, and the constants have the following values: a = 1.70 kg/m⁴ and b = 2.20 kg/m²
So, λ = 1.70x³ + 2.20x
1. The total mass of the rod is
m =₁.₈³⁴ ∫ [1.70x³ + 2.20x] dx
m = [ 1.70x⁴/4 + 2.20x² /2 ]₁.₈³⁴
Putting the limits, we have
m = 69.51 - 8.02548
m = 61.48 kg
Thus, the total mass of the rod is 61.48 kg
2. The x-coordinate of the center of the mass for this rod
Xcm =∫ xλdx/m
Xcm =∫[ x ( 1.70x³ + 2.20x) /m ]dx
Xcm =∫[( 1.70x⁴ + 2.20x²) /m ]dx
On integrating and putting the limits x = 1.80 m to x = 3.40 m
Xcm = = [ {1.70(3.4)⁵/5 + 2.20(3.4)³ /3} - {1.70(1.8)⁵/5 + 2.20(1.8)³ /3} ]
Xcm = 183.3034 - 10.70133
Xcm = 172.6021 m
Thus, the x-coordinate of the center of the mass for this rod is 172.6021 m.
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differentiate e^x - 8x +7
please answer the questions asap
Answers
Answer:
eˣ-8.
Explanation:
(eˣ-8x+7)'=eˣ-8.
How do we solve questions C and D? I already did A and B and I am confused on how to continue
Answers
(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.
(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.
Work done in moving the charge from C to A
W = Fd
W = Kq²/d
from 0 origin to C, d = √(5² + 5²) = 7.07 mfrom 0 origin to A, d = 5 mW(C to A) = W(0 to C) + W(0 to A)
[tex]W(C \ to \ A) = - \frac{Kq^2}{7.07} + \frac{Kq^2}{5} \\\\ W(C \ to \ A) = 0.0586 \ Kq^2\\\\W(C \ to \ A) = 0.0586 \times 9 \times 10^9 \times (3.8\times 10^{-6})^2\\\\W(C \ to \ A) = 7.62 \times 10^{-3} \ J[/tex]
Work done in moving the charge from D to Bfrom 0 origin to D, d = √(5² + 5²) = 7.07 mfrom 0 origin to B, d = 5 mW(D to B) = W(0 to D) + W(0 to B)
W(D to B) = 7.62 x 10⁻³ J
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The internal energy of a gas is 500 J. The gas is compressed adiabatically, and its volume decreases by 100c * m ^ 3 If the pressure applied on the gas during compression is 3.00 atm, what is the internal energy of the gas after the adiabatic compressio
Answers
The internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
What is work done by gas?When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.
Given data;
pressure(P)=3.0 atm = 303975 N/m²
The initial volume, V₁
work is done on the gas., W=?(-ve)
Change in heat, ΔQ=0
Change in the internal energy of the gas., ΔE
The work done on the gas;
W = -PΔV
W= - 303975 N/m² × 100 cm³
W = - 30.3 × 10⁶ J
The internal energy is found as;
ΔE=q+w
ΔE= 0-30.3 × 10⁶ J
ΔE= -30.3 × 10⁶ J
E₂-E₁= -30.3 × 10⁶ J
E₂ = -30.3 × 10⁶ J +500
E₂ = 30.398 × 10⁶ J
Hence, the internal energy of the gas after the adiabatic compression will be 30.398 × 10⁶ J
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A person lifts a ball of mass 1 kg through the
height of 1 m in 10 s. The average power
supplied by him is [Take g = 10 m/s²]
(2) 1 W
(4) 2 W
(1) 10 W
(3) 0.1 W
Answers
Answer:
1 W
Explanation:
Power is the ratio of the total work done by the body to the time it will takes to do the work.
Therefore Power = total work done ÷ timeTotal Work done = Potential energy (P.E) = mgh
Total work done = mgh
Total work done = 1kg × 10m/s² × 1m
Total work done = 10 J
Therefore Total Work done is 10J.
And then time is 10 s.
Power = Total Work done divided by time
Power = 10 J÷ 10 s = 1 W
Therefore Power is 1WQuestion 3 of 15
Which statement describes an advantage of using nuclear fission to produce
electricity?
A. It uses a fuel made of atoms with large nuclei that will be
destroyed.
B. It is much more efficient than any other process used to generate
power.
C. It happens in large buildings that are expensive to build.
D. It produces radioactive waste products that must be stored safely.
Answers
Answer:
it is much more efficient than any other process to generate power
A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 × 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?
Answers
Answer:
shown below
Explanation:
2 x 10⁷ as a number is 20,000,000
20,000,000 - 10 = 19,999,990
It went 19,999,990 m/h
in km/h:
19,999,990 / 1000 = 19,999.99 km/h
in km/s
19,999,990 / 3,600,000 = ~5.56 km/s
in m/s
19,999,990 / 3600 = ~5555.56 m/s
If the mass of the falling object is 60kg. Calculate force. [Take g=10m/s2]
Answers
Word word
Word word
How to do projects on newton’s law
Answers
when energy is transferred from one part of a system to another, some of the energy is lost during the transfer and cannot be used as it was intended. Which two sentences describes examples of this?
Answers
Sentences A and D describe examples of energy transformation.Heat is produced when a car's tires rub against the pavement and as electricity passes across power wires, they become hotter.
What is the law of conservation of energy?According to the law of conservation of energy, the energy of an isolated system stays unchanged throughout time.it is said to be conserved.
Energy cannot be created nor destroyed and can be transferred from one form to the other form.
The complete question is
"When energy is moved from one component of a system to another, some of the energy is lost and cannot be used as planned.
Which two statements provide examples?
A. Friction between a car's tires and the road produces heat.
B. Sunlight strikes a solar panel, generating electricity.
c. Stereo speakers emit a sound when powered by electrical energy,
D. Wind moves a turbine, generating electricity.
I E. Power lines heat up as electricity flows through them."
Some of the energy wasted during the movement of energy from one section of a system to another is heat is produced by friction between a car's tires and the road and as electricity passes via power lines, they heat up.
Hence, sentences A and D describe examples of energy transformation.
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According to the __________perspective, people who suffer from PTSD are classically conditioned.
Answers
According to the pavlovian perspective, people who suffer from PTSD are classically conditioned.
What is PSTD?
This is referred to as post traumatic stress disorder which is a mental disorder from a terrifying incident.
The pavlovian perspective however view this disorder as being a type of classical conditioned one.
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Temperatures expressed in the Kelvin scale are ____ higher than temperatures in the Celsius scale?
A.) 200°
B.) 283°
C.) 460°
D.) 273°
Answers
Explanation: Celsius temperatures can be negative while kelvin goes down to absolute zero and doesn’t go any lower, thus no negative numbers
Answer:
Temperatures expressed in the Kelvin scale are D.) 273° higher than temperatures in the Celsius scale.
Explanation:
This answer is 110% correct guaranteed!
⭐⭐⭐⭐⭐ +
Calculate the magnitude of the linear momentum for the following cases.
(a) a proton with mass 1.67 x 10-27 kg, moving with a speed of 5.05 x 106 m/s
(d) the Earth (mass - 5.98 x 1024 kg) moving with an orbital speed equal to 2.98 x 10 m/s.
Answers
Answer:
8.4335 x 10^-²¹, 1.78204 x 10²⁶
Explanation:
p = mv
p = (5.05 x 10⁶)(1.67 x 10^-²⁷)
p = 8.4335 x 10^-²¹
p = mv
p = (5.98 x 10²⁴)(2.98 x 10)
p = 1.78204 x 10²⁶
What work do you think is done when you carry a 20 N weight backpack for a 1000 m walk? will the work be positive, negative, or potentially zero?
Answers
The work done is positive and is equal to 20000 J
What is work done?Work done is defined as the product of force and the distance moved by the force.
Mathematically:
Work done = force * distanceThe work done by the force = 20 * 1000 = 20000J
The work done is positive and is equal to 20000 J
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If a crane worker lifts a crate with a mass of 250 kg from the ground to a
shipping container that is 20 meters off the ground, by how much has the
worker increased the gravitational potential energy of the crate? (Recall that g
= 9.8 m/s²)
A. 75,000 J
B. 61,000 J
C. 83,000 J
D. 49,000 J
Answers
D.
The gravitational of a body is possessed by the body due to the virtue of its position.
The formula for gravitational potential energy is,
P.E = mgh joules
Substituting the values
196*9.8*250= 49k
What is an advantage of using renewable energy resources?
A. They can be converted directly into electric energy.
B. They do not waste energy in heat.
C. They can be replenished in a human lifetime.
D. They do not produce greenhouse gases.
Answers
8. A charged ball of mass m = 0.265 kg and unknown charge q is hanging by a light thread from a ceiling. A fixed charge Q = +5.00 μC on an insulated stand is brought close to the unknown charge. As a result, the unknown charge hangs at an angle 0 = 38.0° to the vertical as shown in the diagram below. The distance between the two charges is r = 22.0 cm. (a) What is the sign of the unknown charge? Explain how you know this. (b) What is the magnitude of the unknown charge? 8. A charged ball of mass m = 0.265 kg and unknown charge q is hanging by a light thread from a ceiling . A fixed charge Q = +5.00 μC on an insulated stand is brought close to the unknown charge . As a result , the unknown charge hangs at an angle 0 = 38.0 ° to the vertical as shown in the diagram below . The distance between the two charges is r = 22.0 cm . ( a ) What is the sign of the unknown charge ? Explain how you know this . ( b ) What is the magnitude of the unknown charge ?
Answers
(a) The sign of the unknown charge is negative.
(b) The magnitude of the unknown charge is 2.18 μC.
What is charge?The charge is the physical quantity which defines the object's electric field. The charged objects creates the electric field around it and attracts or repels another objects coming into that field.
Given is a charged ball of mass m = 0.265 kg and unknown charge q is hanging by a light thread from a ceiling. A fixed charge Q = +5.00 μC on an insulated stand is brought close to the unknown charge. As a result, the unknown charge hangs at an angle 0 = 38.0° to the vertical as shown in the diagram below. The distance between the two charges is r = 22.0 cm.
Tension in the string has two components, Tsinθ and Tcosθ
(a) The fixed charge Q will attract the movable charge q attached to string. The charge Q is positive. So, the charges must of opposite sign.
Thus, the sign of unknown charge is negative.
(b) From the equilibrium of forces, we get
Electrostatic force Fe = kQq/r²
Fe = Tsinθ .............(1)
and
weight force mg = Tcosθ.............(2)
Dividing both the equations, we get
mg/Fe = tanθ
mg / (kQq/r²) = tanθ
q = mgr²tanθ / kQ
Substitute the values from the question, we have
q = 0.265 x 9.81 x (0.22)² tan38 / (9x10⁹ x 5 x 10⁻⁶)
q = 2.18 x 10⁻⁶ C
or q = 2.18 μC
Thus, the magnitude of charge is 2.18 μC.
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Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
Answers
The force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N
What is gravity?The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.
Given, a 1 kg box located at a point 1.3 × 10⁷ m from the center of Earth. The Earth has the acceleration due to gravity, g = 9.81 m/s².
Force of gravity F = GMm/R²
where G = gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg² and R is the distance between two masses.
The Mass of Earth M= 5.98 × 10²⁴ kg
Substituting the values, we get
F = (6.67 x 10⁻¹¹ N.m²/kg² x 1kg x 5.98 × 10²⁴ kg)/ ( 1.3 × 10⁷ m)²
F = 2.36 N
Therefore, the force of gravity on a 1–kilogram box located at a point from the center of Earth is 2.36 N
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A comet goes around the sun in an elliptical orbit. At its farthest point, 455 million miles from the sun, it is traveling with a speed of 15,135 mi/h. How fast is it traveling at its closest approach to the sun, at a distance of 116 million miles?
Answers
Answer:
A 2kg block is moved a long a level floor by a horizontal force of 20N if the coefficient of sliding friction is 0.4
what is the acceleration of the blove
