Answers
Explanation:
We assume the T flip-flop changes state on the rising edge of the clock input.
The first stage is connected to the clock. The second stage clock is connected to the inverse of the Q output of the first stage, so that when the first stage Q makes a 1 to 0 transition, the second stage changes state.
Related Questions
The customer you were waiting on is nodding while listening to you and gesturing when he speaks what type of language does this represent
Answers
Label the following statements as either T (true) or F (false).
1) For Propane (C3H8) burning with theoretical amount of air, the air-fule ratio on the mole basis is 5.
2) The enthalpy of any substance at the standard reference state is 0.
3) 180% of theoretical air is equivalent to 80% of excess air.
4) The conservation of mass principle requires that the total number of moles on each side of a chemical reaction is equal.
5) The adiabatic flame temperature of methane (CH4) burning with pure oxygen and theoretical amount of air is the same, all other conditions being the same.
Answers
Answer:
1 its 1 bc you have to do it step by step
Explanation:
step by step
A tank with a volume of 40 cuft is filled with a carbon dioxide and air mixture. The pressure within the tank is 30 psia at 70oF. It is known that 2 lb of carbon dioxide was placed in the tank. Assume that air is 80% nitrogen and 20% oxygen and use the ideal gas laws. Calculate ,
Answers
The correct responses are;
(i) Weight percent of nitrogen: 58.6%
Weight percent of oxygen: 14.65%
Weight percent of carbon dioxide: 29.59%
(ii) Volume percent of nitrogen: 64.38%
Weight percent of oxygen: 14.1%
Weight percent of carbon dioxide: 21.53%
(iii) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(iv) Partial pressure of nitrogen: 19.314 psia
Partial pressure of oxygen: 4.23 psia
Partial pressure of carbon dioxide: 6.459 psia
(v) The average molecular weight is approximately 32.02 g/mole
(vi) At 20 psia, 60 °F, the density is 0.11275 lb/ft.³
At 14.7 psia, 60 °F, the density is 0.0844 lb/ft.³
At 14.7 psia, 32 °F, the density is 0.0892 lb/ft.³
(vii) The specific gravity of the mixture 0.169
Reasons:
The volume of the tank = 40 ft.³ = 1.132675 m³
Content of the tank = Carbon dioxide and air
The pressure inside the tank = 30 psia = 206843 Pa
The temperature of the tank = 70 °F ≈ 294.2611 K
Mass of carbon dioxide placed in the tank = 2 lb.
Percent of nitrogen in the tank = 80%
Percent of oxygen in the tank = 20%
(i) 2 lb ≈ 907.1847 g
Molar mass of carbon dioxide = 44.01 g/mol
Number of moles of carbon dioxide = [tex]\displaystyle \mathbf{ \frac{907.1847 \, g}{44.01 \, g/mol}} \approx 20.613 \, moles[/tex]
Assuming the gas is an ideal gas, we have;
[tex]\displaystyle n = \mathbf{\frac{206843\times 1.132674}{8.314 \times 294.2611} }\approx 95.7588[/tex]
The number of moles of nitrogen and oxygen = 95.7588 - 20.613 = 75.1458
Let x represent the mass of air in the mixture, we have;
[tex]\displaystyle \mathbf{ \frac{0.8 \cdot x}{28.014} + \frac{0.2 \cdot x}{32}}= 75.1458[/tex]
Solving gives;
x ≈ 2158.92 grams
Mass of the mixture = 2158.92 g + 907.1847 g ≈ 3066.1047 g
[tex]\displaystyle Weight \ percent \ of \ nitrogen= \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{58.6 \%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ oxygen = \frac{0.8 \times 2158.92}{3066.105} \times 100 \approx \underline{14.65\%}[/tex]
[tex]\displaystyle Weight \ percent \ of \ carbon \ dioxide = \frac{907.184}{3066.105} \times 100 \approx \underline{29.59\%}[/tex]
ii.
[tex]\displaystyle Number \ of \ moles \ nitrogen= \frac{0.8 \times 2158.92 \, g}{28.014 \, g/mol} \approx 61.65\, moles[/tex]
[tex]\displaystyle Number \ of \ moles \ oxygen= \frac{0.2 \times 2158.92 \, g}{32 \, g/mol} \approx 13.5\, moles[/tex]
Number of moles of carbon dioxide = 20.613 moles
Sum = 61.65 moles + 13.5 moles + 20.613 moles ≈ 95.763 moles
In an ideal gas, the volume is equal to the mole fraction
[tex]\displaystyle Volume \ percent \ of \ nitrogen= \frac{61.65}{95.763} \times 100 \approx \underline{64.38 \%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ oxygen = \frac{13.5}{95.763} \times 100 \approx \underline{14.1\%}[/tex]
[tex]\displaystyle Volume \ percent \ of \ carbon \ dioxide = \frac{20.613 }{95.763} \times 100 \approx \underline{21.53\%}[/tex]
(iv) The partial pressure of a gas in a mixture, [tex]P_A = \mathbf{X_A \cdot P_{total}}[/tex]
Partial pressure of nitrogen, [tex]P_{N_2}[/tex] = 0.6438 × 30 psia ≈ 19.314 psia
Partial pressure of oxygen, [tex]P_{O_2}[/tex] = 0.141 × 30 psia ≈ 4.23 psia
Partial pressure of carbon dioxide, [tex]P_{CO_2}[/tex] = 0.2153 × 30 psia ≈ 6.459 psia
(v) The average molecular weight is given as follows;
[tex]\displaystyle Average \ molecular \ weight = \frac{3066.105\, g}{95.7588 \, moles} = 32.02 \, g/mole[/tex]
(vi) At 20 psia 70 °F, we have;
Converting to SI units, we have;
[tex]\displaystyle n = \frac{137895.1456\times 1.132674}{8.314 \times 294.2611} \approx 63.84[/tex]
The number of moles, n ≈ 63.84 moles
The mass = 63.84 moles × 32.02 g/mol ≈ 2044.16 grams ≈ 4.51 lb
[tex]\displaystyle Density = \frac{4.51\ lb}{40 \ ft.^3} \approx \underline{0.11275\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 Pa, and 60 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 288.7056} \approx 42.8247[/tex]
The mass = 47.8247 moles × 32.02 g/mol ≈ 1531.35 grams = 3.376 lb.
[tex]\displaystyle Density = \frac{3.376 \ lb}{40 \ ft.^3} \approx \underline{ 0.0844\, lb/ft.^3}[/tex]
When the pressure is 14.7 psia = 101352.93 and 32 °F
[tex]\displaystyle n = \frac{101352.9\times 1.132674}{8.314 \times 273.15} \approx 50.5482[/tex]
The mass = 50.5482 moles × 32.02 g/mol ≈ 1618.55 grams = 3.568 lb.
[tex]\displaystyle Density = \frac{3.568 \ lb}{40 \ ft.^3} \approx \underline{ 0.0892 \, lb/ft.^3}[/tex]
(vii) [tex]\displaystyle The \ specific \ gravity \ of \ the \ mixture \ = \frac{\frac{3066.1047\, g}{40 \, ft.^3} }{1.00} = \frac{\frac{6.7596 \, lbs}{40 \, ft.^3} }{1.00} \approx \underline{0.169}[/tex]
Learn more about partial pressure here:
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An apple, potato, and onion all taste the same if you eat them with your nose plugged
Answers
Answer:
I didn't understand your question or is it a fun fact
As part of the overall systems engineering process, there are a variety of software development methods, but the three most common at DoD are the Waterfall Approach, the Incremental Approach, and the ______________ Approach.
Answers
The three most common software development methods are the Waterfall Approach, the Incremental Approach, and the SPIRAL Approach. These methods depend on the team size and specific goals.
Software development is the sequential procedure that involves the division of the work into smaller and parallel stages in order to improve software design and product management.
The software development methods depend on both the team size and specific objectives.
The most common methodologies for software development include:
Waterfall Spiral Incremental Agile Continuous integrationLearn more about software development here:
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Which of the following is a measurement at the nominal level?
A-personal income in a year
B-student grades
C-the color of a person's hair (blond, brunette, redhead)
D-temperature
Answers
Answer:
A-personal income in a year this is the answer
openings around pipes that enter building should be covered by
Answers
Answer: I have 2 suggestions: one, maybe, maybe, use some of that metal tape that you get at hardware places, and: two, buy a new pipe (or pipes), two be sure that it won't happen again. Have a good day, and thanks for asking the brain!
Explanation:
A fully charged battery with 6 cells should indicate
Answers
Answer:
Battery Voltage
Voltage refers to the amount of electrical potential your battery holds. The standard automotive battery in today's vehicles is a 12-volt battery. Each battery has six cells, each with 2.1 volts at full charge. A car battery is considered fully charged at 12.6 volts or higher.
a. State the functions of the followings
a. Commutator
b. Armature core
c. Field system
d. Brushes
e. Armature winding
Answers
Answer:
a. State the functions of the followingsa. Commutator:
the commutator reverses the current direction with each turn serving as a mechanical rectifier to convert the alternating current from the windings to unidirectional direct current in the external load circuit.
b. Armature core
Armature core is a physical structure made up of silicon steel stampings. The core is laminated to keep iron losses low. Armature winding is the main current carrying winding where we either provide(electric supply to motor) or extract e.m.f(collect electric power from generator).
c. Field system
The field winding basically form an electromagnet, that produces field flux within which the rotor armature of the DC motor rotates, and results in the effective flux cutting
d. Brushes
The function of brushes is that the brushes conduct current between stationary wires and moving parts of the electric Generator.
e. Armature winding
The winding wound on the core is given current through a DC supply. This current-carrying winding as under the influence of the magnetic field develops a force that develops a rotational torque. This torque enables the machine to rotate.
[tex] \bold \pink{ \underline{hope \: it \: helps}}[/tex]
How can we honor what we value and care about in a world of disruptive technologies like AI?
Answers
Answer: Well, that's a good question. When we look around us, we tend to see what technology has done for us, and how far it is taking us. It might be disruptive, but without it there would be no high tech military weapons, and then how would we defend ourselves? There would be no technology entertainment and without that, life would be very dull. In answering your question, we can be thankful for what it is and how far it has been taking us in life.
Explanation: Please mark a brainliest if correct it helps and have meery holidays!
The part of the circuit that converts electrical energy into other forms
Answers
Answer:
Alternator
Explanation:
A device which converts mechanical energy into electrical energy.
I hope it helps.
Class 0 rubber gloves are used when working with voltage less than
Answers
Class 00 rubber gloves are given the color "beige" based on the color code of rubber gloves.
The proof test voltage for this class of rubber gloves is 2500 volts of AC voltage and 10000 volts of DC voltage
Please mark it as brainliest answer:).
Chemical engineers determine how to transport chemicals.
O True
False
Answers
Answer:
Chemical Engineers determine how to transport chemicals:
TRUE
Answer:
Explanation:
Trues
need help answering this question
Answers
Answer: Wow. I just did that not so long ago. The mean is 76, i think the deviation is 73 and ill recall my notes for the next, hold on
Explanation:
6.03 Discussion: Then & Now - Safety
Discussion Topic
I'm Done
In this unit, you have learned about the evolution of the industry’s machines, through both technology and innovation. These improvements have reduced risk and injury to the Operating Engineers.
Choose one innovation or device.
Explain why you think that technology is the most important advancement in Operating Engineers’ safety.
Answers
Answer:
Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.
Marketing in the fresh produce industry does not include buying, selling,
transportation or pricing?
Answers
Answer: I personally believe it does, because the Circle of Life, or what I think, at least buying and selling
Explanation:
A person has driven a car 180 m in 40 seconds. What is the car’s speed?
Answers
Answer:
4.5 m/s = 16.2 km/h
Explanation:
The speed is the ratio of distance to time:
speed = (180 m)/(40 s) = 4.5 m/s
10. Which is of the following is not used in the
testing/analysis step?
A. Engineering notebooks.
B. Multiview drawings.
C. 3-D modeling software.
D. CNC machines.
Answers
A CNC machine stands for Computer Numerically Controlled Machine, they are used to Machine objects in hence create items, machine parts from prototypes. Hence the CNC machines are not used for testing/Analysis
D. CNC machines.
In Engineering the following items are basically needed for and during test/Analysis
Engineering notebooks: This is used to write down importance observations and findingsMulti-view drawings: This is also needed to visualise prototypes from different perspective or views3-D modelling software: e.g AutoCad , Autodesk Inventor, Revit to mention a few can be used to design and analyse project even before their actual implementation or designLearn more:
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Explain the conditions under which galvanic corrosion occurs
Answers
Answer:
Explanation:
Galvanic corrosion occurs when two dissimilar metals are immersed in a conductive solution and are electrically connected. One metal (the cathode) is protected, whilst the other (the anode) is corroded. The rate of attack on the anode is accelerated, compared to the rate when the metal is uncoupled.
How to make this circuit for simulating on Proteus.
Answers
Create a Python script that will compare two (2) numbers entered by the user. Refer to the attached image and to the following algorithm. There is no need to create a class similar to how Java works.
3.1. User enters the first number.
3.2. User enters the second number.
3.3. If the first number is less than, greater than, or equal the second number, a message is displayed.
Please Help me. Thank You!
Marry Christmas!
Answers
Answer:
number1 = input("Choose a first number: ")
number2 = input("Choose a second number: ")
if number1 >= number2:
print("Number 1 is greater")
Who is responsible for shielding a welding arc to protect
the eyes and skin of all persons in the working area?
Answers
Answer:
manager and supervisor
Explanation:
What is the first step in the decision-making process?
Answers
Answer: identify your decision. relize you need to make a decision.
Explanation:
An airline ticket counter forecasts that 220 people per hour will need to check in. It takes an average of 2 minutes to service a customer. Assume that arrivals are poisson distributed and service times exponentially distributed and that customers wait in a single queue for the first available agent.
a) If we want the average time a customer spends in the queue and in service to be 10 minutes or less, how many ticket agents should be on duty?
b) There airline wants to minimize the cost of idle ticket agents and the cost of customers waiting in the queue. The salary of a ticket agent is £12 per hour and the cost of a customer waiting in the queue is £5 per customer per hour. How many ticket agents should be on duty?
Answers
A) Number of agents required to achieve a wait time of 10 minutes or less = 8 agents
B) The number of agents required on duty to reduce cost = 9 agents
Given data :
Arrival rate of customers ( β ) = 220 per hour
Service rate ( mu ) = 60 minutes / 2 minutes = 30 customer per hour
utilization ( rho ) = 220 / 30 ≈ 7
at least 8 server personnel are required for stability of the queue
A) Determine the number of agents required to achieve a wait time of 10 minutes or less per customer
waiting time = 10 - 2 = 8 minutes
number of customers waiting ( ∝ ) = 7 and required server = 8
assuming Lq = 5.2266
Hence the waiting time in line = Lq / arrival rate
= 5.2266 / 220 = 0.0238 hour
= 0.0238 * 60 = 1.428 minutes
Since the waiting time ( 1.428 minutes ) is less than the original waiting time ( 2 minutes ) the number of agents that will achieve a wait time of 10 minutes or less is = 8 agents
B) Determine the number of ticket agents that should be on duty to minimize cost
salary of ticket agent = £12 per hour
cost of customer waiting in queue = £5 per hour per customer
i) When 8 agents are used
waiting time of customers = 0.0238 * 220 = 5.236
waiting cost for customers = 5.236 * 5 = £26.18
employee cost = 8 * 12 = £96
∴ Total cost = 96 + 26.18
= £ 122.18
ii) When 9 agents are used
waiting time for customers = 0.0074 * 220 = 1.628
Wq = 1.6367 / 220 = 0.0074
waiting cost for customers = 1.6367 * 5 = £ 8.1835
assuming Lq = 1.6367
employee cost = 9 * 12 = £ 108
∴ Total cost = 108 + 8.1835 = £ 116.18
From the calculations in ( i ) and ( ii ) the Ideal number of ticket agents that should be on duty to minimize cost should be 9 agents.
Hence we can conclude that A) Number of agents required to achieve a wait time of 10 minutes or less = 8 agents and The number of agents required on duty to reduce cost = 9 agents.
Learn more about cost reduction : https://brainly.com/question/14115944
(2pts) In _______________, the pulse amplitude is made proportional to the amplitude of the modulating signal. pulse-amplitude modulation (PAM) pulse-position modulation (PPM) pulse-code modulation (PCM) pulse-width modulation (PWM)
Answers
Answer:
(a) pulse-amplitude modulation (PAM)
Explanation:
It should be no surprise that pulse amplitude is modulated in pulse-amplitude modulation (PAM).
Technician A says that to start a fuel-injected car, the accelerator should be depressed
once. Technician B says that to start a car with a carburetor, do not touch the
accelerator pedal until the engine is running. Who is correct?
Technician A
Technician B
Both A and B
Neither Anor B
Answers
Answer:
Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A
Explanation:
Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A
The section 5(a)(1) of the osh act is commonly known as
Answers
Answer:
general duty clause
Explanation:
All of the following are employment requirements for a technician EXCEPT:
Select one:
a. Being drug and alcohol free
b. Having all of your ASE certifications
c. Having a clean driving record
O d. Having honesty, integrity, reliability, and quality
Answers
Answer:
I think it would be C but im not sure sorry if its wrong
Question 10 of 25: Select the best answer for the question. 10. In a series RC circuit, if the resistance is 8,000 ohms and X is 6,000 ohms, what is the impedance of the circuit O A. 8,600 ohms O B. 10,000 ohms O C. 14,000 ohms O D. 9,200 ohms Mark for review (Will be highlighted on the review page) << Previous Question Next Question >> M LL 5 - 1080 acer
Answers
Answer:
B. 10,000 ohms
Explanation:
|8000 +j6000| = √(8000² +6000²) = 1000√(64 +36) = 1000√100 = 10,000
The impedance is 10,000 ohms.
HELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HELPHELP HEL
Answers
Answer:
oh this happened with me to ,this will be alright just wait a bit
