Can be expressed in terms of energy, wavelength, or frequency.

a. lons
b. EM radiation
c. Energy
d. Amplitude

Answers

Answer 1

"Can be expressed in terms of energy, wavelength, or frequency: a. lons, b. EM radiation, c. Energy, d. Amplitude" is EM radiation. Electromagnetic radiation, abbreviated EM radiation or EMR, is a type of energy that travels through space as waves.

These waves are created by the interaction of electric and magnetic fields.Electromagnetic radiation can be described in terms of energy, wavelength, or frequency. The energy of an electromagnetic wave is proportional to its frequency and inversely proportional to its wavelength, according to the formula E = hf, where E is energy, h is Planck's constant, and f is frequency.

The speed of electromagnetic radiation in a vacuum is 299,792,458 meters per second (m/s), which is known as the speed of light. In summary, electromagnetic radiation is a type of energy that can be expressed in terms of energy, wavelength, or frequency.

To know more about wavelength visit:-

https://brainly.com/question/32900586

#SPJ11


Related Questions


Find the rotor frequency of an induction motor having 4 poles if
the rotor speed is 1746 rpm and the stator frequency of 60 Hz.

Answers

The rotor frequency of the induction motor is 1.8 Hz.

The rotor frequency of an induction motor having 4 poles with the rotor speed of 1746 rpm and the stator frequency of 60 Hz can be calculated as follows:

The number of poles, p = 4Stator frequency, f = 60 Hz

Rotor speed, n2 = 1746 rpm

The synchronous speed of the motor is given by the formula:

Synchronous speed (Ns) = (120f)/p

Putting the values in the above formula:

Synchronous speed (Ns) = (120 × 60)/4

Synchronous speed (Ns) = 1800 rpm

The rotor speed can be given by the formula:

n2 = (1-s)Ns

where s is the slip.

Therefore, the slip can be given by the formula:

s = (Ns-n2)/Ns

Putting the values in the above formula:

s = (1800-1746)/1800

s = 0.03

The rotor frequency (fr) can be calculated using the formula:

fr = s × f

Putting the values in the above formula:

fr = 0.03 × 60

fr = 1.8 Hz

Therefore, the rotor frequency of the induction motor is 1.8 Hz.

Learn more about rotor frequency from the given link

https://brainly.com/question/33368560

#SPJ11

The melting point of a pure compound is known to be 110-111°. Describe the melting behavior expected if this compound is contaminated with 5% of an impurity?
An impurity consisting of 5% total mass will lower the melting point from that of the pure compound, and it will increase the melting point range.A value of 103-107° would be consistent with this amount of impurity with the pure melting point of 110-111°; values of 100-105°, 97-100°, 102-110° are also good estimates.

Answers

Impurities will lower the melting point of a pure compound and increase the melting point range.

When an impurity is mixed with a pure substance, it lowers the melting point of the compound and expands its melting range. If a substance has a pure melting point of 110-111°C, adding a 5% impurity would cause the melting point to drop to 103-107°C, while the melting point range would broaden. It's difficult to predict the precise melting point range, but estimates such as 100-105°C, 97-100°C, and 102-110°C are all possible.

Impurities that are added to a substance have a noticeable effect on the melting point of the pure substance, which is used to evaluate the purity of the sample. The melting point of a compound is an important characteristic that chemists use to determine its identity and purity.

Learn more about melting point here:

https://brainly.com/question/17571179

#SPJ11

The magnet field intensity of a uniform plane wave in a good conductor (ε = &› μ = μ₁) is H = 20e - ¹2² cos(2π × 10ºt + 12z)a, mA/m Find the conductivity and the corresponding E field.

Answers

The conductivity and the corresponding

E field are

σ = σ₀ + j(ω / 2 μ₁) × 1 / ϵ

E = √μ₁ × 20e-¹² cos(2π × 10ºt + 12z)a V/m

Given the magnet field intensity of a uniform plane wave in a good conductor

(ε = ∞ μ = μ₁) is

H = 20e-¹² cos(2π × 10ºt + 12z)a, mA/m.

First we know that the wave impedance is

Z₀ = √(μ/ε) = √(μ₁/∞) = √μ₁.

For the magnetic field H, the electric field E can be given by the following formula:

E = Z₀ H

Given H = 20e-¹² cos(2π × 10ºt + 12z)a, mA/m

Therefore, E = Z₀ H

= √μ₁ × 20e-¹² cos(2π × 10ºt + 12z)a V/m

From Maxwell's equation

div E = - j ωμHj ωμ

= σ + j ωε

The conductivity σ can be calculated as follows:

σ = j ωε / (j ωμ)

= σ + j ωε / σμ

σ² = j ωε / μ

σ = σ₀ + j ωε / 2 μ₁

σ = σ₀ + j(ω / 2 μ₁) × 1 / ϵ

Where σ₀ is the DC conductivity, which is the limiting value of conductivity when frequency approaches zero.S

o, the conductivity and the corresponding

E field are

σ = σ₀ + j(ω / 2 μ₁) × 1 / ϵ

E = √μ₁ × 20e-¹² cos(2π × 10ºt + 12z)a V/m

To know more about conductivity visit:

https://brainly.com/question/31201773

#SPJ11

In a wire, 6.63 x 1020 electrons flow past any point during 2.15 s. What is the magnitude I of the current in the wire?

Answers

The magnitude of the current in the wire is 4.93 A.

In a wire, 6.63 x 10²⁰ electrons flow past any point during 2.15 s. What is the magnitude I of the current in the wire?Current is the flow of electrical charge carriers, such as electrons or ions, that pass through an electric circuit. This flow of charge carriers is called an electric current. Electric current is denoted by the symbol "I."The amount of charge that passes through a wire per unit of time is known as the current.

The unit of current is the ampere (A), which is defined as a flow of one Coulomb of charge per second. One ampere of current is represented by a flow of 6.24 x 10¹⁸ electrons per second through a conductor. A current I can be calculated using the formula: Q = n x e

Where, Q = electric charge e = the magnitude of the electric charge of an electron = 1.6 x 10⁻¹⁹ Cn = number of electrons I = Q/t

Where, I = current in Amperes t = time in seconds Using the given values: n = 6.63 x 10²⁰ e, t

= 2.15s, and e = 1.6 x 10⁻¹⁹C, we can calculate the electric charge Q.Q = n x e

Q = 6.63 x 10²⁰ electrons x 1.6 x 10⁻¹⁹ C/electron

Q = 10.6 C

Now we can calculate the current I using the formula: I = Q/tI = 10.6 C/2.15 s I = 4.93A

Therefore, the magnitude of the current in the wire is 4.93 A.

To know more about magnitude visit:

https://brainly.com/question/28173919

#SPJ11

reflecting telescopes are preferred over refracting telescopes because:

Answers

Reflecting telescopes are preferred over refracting telescopes because they are less expensive and can achieve larger apertures for better light-gathering power. Refracting telescopes are limited in size and are  which means that they can’t collect as much light as reflecting telescopes.

Reflecting telescopes, on the other hand, use mirrors instead of lenses to focus light and produce a brighter, sharper image with better contrast. They also don’t suffer from chromatic aberration, which occurs when different wavelengths of light are refracted differently and cause color fringes around the image.

Reflecting telescopes are also more durable because they don’t have a glass lens that can break or become damaged over time, unlike refracting telescopes which have to be carefully constructed and maintained. The design of reflecting telescopes also allows for easier and more convenient mounting of observation equipment. Finally, reflecting telescopes are preferred over refracting telescopes because they can be used in both visible and non-visible light, including infrared and ultraviolet light.

To know more about refracting visit:

https://brainly.com/question/13088981

#SPJ11

A piece of steel wire, which is 3 m long, and of 1mm diameter hangs vertically from the ceiling. A 5 kg mass, made from iron, (density = 7,9 x 103 kg.m-3 ) is attached to the free end. What is the tension in the cord if the mass is totally immersed in water?

Answers

The tension in the cord when the iron mass is totally immersed in water is approximately 55.22 N.

To find the tension in the cord when the iron mass is immersed in water, we need to consider the forces acting on the system.

First, let's calculate the weight of the iron mass:

Weight = mass * gravitational acceleration

Weight = 5 kg * 9.8 m/s²

Weight = 49 N

When the mass is immersed in water, it experiences an upward buoyant force equal to the weight of the water displaced. The volume of the iron mass can be calculated using its density and the formula:

Volume = mass / density

Volume = 5 kg / (7.9 x 10³ kg/m³)

Volume = 0.0006329 m^3³

The weight of the water displaced by the3 iron mass is:

Weight of water displaced = density of water * volume of water

Weight of water displaced = 1 x 10 kg/m³* 0.0006329 m * 9.8 m/s

Weight of water displaced = 6.21552 N

Since the iron mass is completely immersed in water, the tension in the cord must balance the weight of the iron mass and the weight of the water displaced. Therefore, the tension in the cord is the sum of these two forces:152 N = 49 N + 6.21552

Tension = Weight of iron mass + Weight of water displaced5

Tensio Ndisplaced * gravitational accelerationTension = 55.2

To learn more about tension

https://brainly.com/question/24994188

#SPJ11

An ideal single-phase source, 240 V, 50 Hz, supplies power to a load resistor R = 100 0 via a single ideal diode.. 2.1.1. Calculate the average and rms values of the load current

Answers

The average value of the load current is 339.4 mA, and the rms value of the load current is 239.7 mA.

An ideal single-phase source, 240 V, 50 Hz, supplies power to a load resistor R = 100 0 via a single ideal diode.

To calculate the average and rms values of the load current, we need to find out the current flowing through the resistor R. Let us denote the current through the resistor R as IR.

The input voltage of the ideal single-phase source is 240 V, 50 Hz.

Therefore, the peak voltage (Vp) is:

Vp = 240 V √2

Vp = 339.4 V

The ideal diode ensures that the current flows only in one direction.

Hence, the load current flows only when the input voltage is positive.

In this case, the current flowing through the resistor is given by:

IR = Vp/R

Where R = 1000 Ω

Substituting the values in the above equation, we get:

IR = 339.4 mA

The average value of the load current (Iav) is the average of the current over a complete cycle.

The current flows only in one direction during the positive half-cycle.

Therefore, the average value of the load current is given by:

Iav = IR

= 339.4 mA

The root mean square (rms) value of the load current (Irms) is given by:

Irms = IR / √2

Irms = 239.7 mA

Therefore, the average value of the load current is 339.4 mA, and the rms value of the load current is 239.7 mA.

To know more about load current visit:

https://brainly.com/question/31789014

#SPJ11

The electric field strength 27 cm from the center of a uniformly charged, hollow metal sphere is 12,000 N/C. The sphere is 7.0 cm in diameter, and all the charge is on the surface. Part A What is the magnitude of the surface charge density in nC/cm²? Express your answer in nanocoulombs per square centimeter. ΑΣΦ ? P -11 n= 6.77 107

Answers

The magnitude of the surface charge density in nC/cm² is 4.65 nC/cm².

Given: Electric field strength at 27 cm from the center of a uniformly charged, hollow metal sphere is 12,000 N/C.The sphere is 7.0 cm in diameter, and all the charge is on the surface.

Part A: Find the magnitude of the surface charge density in nC/cm².

The electric field strength at a distance r from the center of uniformly charged sphere of radius R and total charge Q is given by:

E = Q/4πε0r²

Where

,ε0 = 8.85 x 10⁻¹² C²/N.m²

= permittivity of free space

For a uniformly charged sphere, the surface charge density is given by;

σ = Q/4πR²

We have,

E = Q/4πε0r² ----(1)

σ = Q/4πR² ----(2)

From (1) and (2),

Q = σ x 4πR²

Substituting the value of Q in equation (1),

E = (σ x 4πR²)/4πε0r²

Simplifying,

E = σ(R/r)²ε0

⇒ σ = E/ε0(R/r)²

σ = (12,000 N/C)/(8.85 x 10⁻¹² C²/N.m²) (3.5 x 10⁻² m/2.7 m)²

σ = 4.65 x 10⁻⁹ N.m²/C

σ = 4.65 x 10⁻⁹ C/m²

σ = 4.65 x 10⁻⁹ x 10⁹ nC/m²

σ = 4.65 nC/m²

σ = 4.65 nC/cm²

Therefore, the magnitude of the surface charge density in nC/cm² is 4.65 nC/cm².

To know more about surface charge density visit:

https://brainly.com/question/17438818

#SPJ11

How many ounces of fluid should be consumed every mile during a 15K run for an athlete who loses 32 ounces of sweat per hour and runs at a 10 min/mile pace?
A. 5.5 ounces
B. 5 ounces
C. 4.5 ounces
D. 6 ounces

Answers

The answer to the problem is option B. 5 ounces. The amount of fluid that should be consumed by the athlete every mile during the 15K run is 5 ounces.

The distance of a 15K run is 9.32 miles.

Therefore, to know the amount of fluid that should be consumed by the athlete every mile during the 15K run, we need to calculate the amount of fluid lost by the athlete in an hour:

32 ounces per hour.

This implies that the athlete loses 32 / 60 = 0.53 ounces of fluid per minute.

We also know the athlete's pace:

10 min/mile.

Thus, in an hour, the athlete covers a distance of 6 miles.

Therefore, in an hour, the athlete covers 6 miles and loses 32 ounces of sweat. The athlete will lose (9.32 / 6) × 32 = 49.87 ounces of sweat during the 15K run.

To find the amount of fluid that should be consumed every mile during the 15K run, we divide the total amount of fluid lost by the total distance of the run:

49.87 ounces / 9.32 miles ≈ 5.35 ounces/mile.

Rounding up to one decimal place, the amount of fluid that should be consumed by the athlete every mile during the 15K run is 5 ounces.

Learn more about fluid from:

https://brainly.com/question/9974800

#SPJ11

A particle moves along the x-axis so that the position s is given as a function of time t by

x(t)= 10t2 , t ≥ 0

Position s and time t have denominations, meters and seconds, respectively
a) What is the average velocity of the particle between 0s = t and 2? S = t

b) What is the momentum velocity of the particle at time 1? s = t

c) Assume that the particle has mass 2kg = m. How much net force (resultant force) acts on the particle at time t = 2s

Answers

The given function for position s of the particle in terms of time t is

x(t) = 10t².

It is a polynomial function of second degree. a) The average velocity of the particle between 0s = t and 2 is given by;

Average Velocity = (x₂ − x₁) / (t₂ − t₁)Substitute x₂ = x(2s) = 10(2²) = 40, x₁ = x(0s) = 10(0²) = 0, t₂ = 2s and t₁ = 0sAverage Velocity = (40 − 0) / (2 − 0) = 20m/sb) .

The momentum velocity of the particle at time 1 is given by;

Momentum velocity = (dx / dt)

Substitute x(t) = 10t²Momentum velocity = (dx / dt) = 20t

Now substitute t = 1 in 20t; Momentum velocity at time 1 = 20(1) = 20mc) Assume that the particle has mass 2kg = m. The net force (resultant force) acts on the particle at time t = 2s is given by;Net force = mass × accelerationWe need to find acceleration at time t = 2s. Differentiating the function x(t) = 10t², we get;dx / dt = 20tDifferentiate again, we get;

d²x / dt² = 20

We know that the acceleration is the second derivative of position with respect to time.So, acceleration at time t = 2s is given by;

d²x / dt² = 20a = d²x / dt² = 20 = (2kg) × 10m/s²

Net force at time t = 2s = 20N = 2(10) N = 20 N. Therefore, the net force acting on the particle at time t = 2s is 20N.

To know more about momentum visit:

https://brainly.com/question/30677308

#SPJ11

A point charge of 4 micro C is placed 40 cm from a second point charge of –2 micro C. Both of these charges lie on the x-axis with the larger charge at the origin. Find the point(s) on the x-axis where a third charge can be placed without experiencing any force.

Answers

The third charge should be placed at 16 cm from charge Q1 and 24 cm from charge Q2 on the x-axis.

Given values, Charge 1 (Q1) = 4 µC Charge 2 (Q2) = -2 µC Distance between the charges (r) = 40 cm = 0.4 m

The third charge should be placed on the x-axis.

Let’s assume it is ‘q’ and it is placed at a distance ‘x’ from the charge ‘Q1’ and ‘(0.4 – x)’ from the charge ‘Q2’.

Force acting on charge q due to charge Q1 can be expressed as, F1 = k(q)(Q1) / (x)²where k is the n Coulomb constat = 9 × 10⁹ Nm²/C².

Force acting on charge q due to charge Q2 can be expressed as, F2 = k(q)(Q2) / (0.4 – x)²

The net force acting on charge q should be equal to zero. So, F1 + F2 = 0

Therefore, k(q)(Q1) / (x)² + k(q)(Q2) / (0.4 – x)² = 0 On solving this equation, the values of x can be obtained which will give the position of the third charge where it does not experience any force.

Let’s solve it,(9 × 10⁹ Nm²/C²)(q)(4 µC) / (x)² + (9 × 10⁹ Nm²/C²)(q)(-2 µC) / (0.4 – x)² = 0

Simplifying,2 (0.4 – x)² = (x)²

Solving for ‘x’,x = 0.16

To know more about the coulomb constant please refer:

https://brainly.com/question/506926

#SPJ11

Problem 1: a. Solve for the Thévenin equivalent resistance, Rth. b. Draw the Thévenin equivalent circuit. c. Draw the Norton equivalent circuit. d. Choose RL for maximum power transfer, then solve for the maximum power transferred to the load, PL,max. 1 ΚΩ 21x www 2 ΚΩ 6 V (-+) R₁ lo V₂

Answers

a. Solve for the Thévenin equivalent resistance, Rth. Rth is the total resistance when the two resistors R1 and R2 are connected in parallel. The formula for calculating total resistance is as follows:

1/Rth = 1/R1 + 1/R2

= 1/1000 + 1/2000

= 3/4000

Rth = 1333.33 Ohms (rounded to the nearest 0.01 Ohms).

b. Draw the Thévenin equivalent circuit.

The circuit below is the Thévenin equivalent circuit.

c. Draw the Norton equivalent circuit.

The Norton equivalent circuit is shown below. Norton current is

IN = VOC/Rth

= 4.5 mA, and the resistor is

RN = Rth

= 1333.33 Ohms.

d. Choose RL for maximum power transfer, then solve for the maximum power transferred to the load, PL,max.

The maximum power transferred to the load is calculated as follows:

PL(max) = [IN / (RN + RL)]² * RL

IN = 4.5 mA,

RN = 1333.33 Ohms, and we want to find RL for maximum power transfer.

Let us use the derivative of PL with respect to RL to find the maximum point.

PL = [IN / (RN + RL)]² * RL

PL' = -2 * IN² * RL / (RN + RL)³

When PL' = 0, we have RL = RN = 1333.33 Ohms, and that is the point of maximum power transfer. The value of PL(max) at this point is:

PL(max) = IN² * RN / 4 = 7.12 mW (rounded to the nearest 0.01 mW).

Therefore, the maximum power transferred to the load is 7.12 mW.

To know more about resistance visit:

https://brainly.com/question/29427458

#SPJ11

3. A photon with a wavelength of 100 nm is incident on a ground-state hydrogen atom. Determine the photon energy in eV. Can the photon be absorbed by the hydrogen atom? Explain the reason. What will be the state of the hydrogen atom after this interaction? (25 marks)

Answers

Therefore, the photon energy is 1.988 x 10^-16 J or 1.238 x 10^-4 eV.2.

The formula to calculate the energy of a photon can be given by

E = hc/λ,

where E is the energy of the photon,

h is Planck's constant,

c is the speed of light,

and λ is the wavelength of the photon.

Given that a photon with a wavelength of 100 nm is incident on a ground-state hydrogen atom,

let's calculate the photon energy using the above formula.

1. Calculating the energy of the photon

E = hc/λ

Where h = 6.626 x 10^-34 Js,

c = 3 x 10^8 m/s,

and λ = 100 nm

= (6.626 x 10^-34 Js) x (3 x 10^8 m/s) / (100 x 10^-9 m)

= 1.988 x 10^-16 J

= 1.238 x 10^-4 eV

Therefore, the photon energy is 1.988 x 10^-16 J

or 1.238 x 10^-4 eV.2.

Yes, the photon can be absorbed by the hydrogen atom if its energy is equal to or greater than the energy difference between the ground state and an excited state of the hydrogen atom.

If the energy of the photon is less than the energy difference between the ground state and the first excited state of the hydrogen atom (which is 10.2 eV), the photon will not be absorbed by the hydrogen atom.

3. If the photon is absorbed by the hydrogen atom, the atom will be excited to a higher energy level. The exact energy level to which the atom is excited will depend on the energy of the photon and the energy differences between the energy levels of the hydrogen atom.

To know more about photon energy visit:

https://brainly.com/question/9628846

#SPJ11

Three identical resistors dissipating a total power of 3000 W are connected in Wye across a 3 phase, 550 V line. The value of resistance will be around.

Answers

Therefore, the value of resistance will be around 57.87 Ω.  Given that,

Total power = 3000 W

Number of resistors connected in Wye = 3

Voltage across the line = 550 V

To find the resistance value in the circuit, the following formula is used:

Power in a 3-phase circuit = 1.732 × VL × IL × power factor

The wye connection configuration is given below. The voltage across each resistor in Wye connected configuration is 550 / √3, which is equal to 317.73 V.

Therefore, the current flowing through each resistor will be:

I = V / R

Here, V = 317.73 V (Voltage across each resistor)

P = 1000 W (Total power / Number of resistors)

I = P / V

We know that P = VI.

I = P / V = 1000 / 317.73 = 3.15 A

Therefore, the resistance of each resistor in the circuit will be:

R = V / IR = 317.73 / 3.15 = 100.87 Ω

The total resistance in the circuit is calculated using the following formula:

Rt = R / (n * n)

Rt = 100.87 / (3 × 3)

Rt = 3.54 Ω

The final resistance value in the circuit is calculated using the following formula:

R = (Rt × R) / (Rt + R)

R = (3.54 × 100.87) / (3.54 + 100.87)

R = 57.87 Ω (approximately)

Learn more about The voltage: https://brainly.com/question/32002804

#SPJ11

Content Substance Latent Heat (3/kg) Steam water 2,260,000 Toe en water 333.000 Answer the following questions dealing with methods of heat transfor Radiation An orange orb has an emissivity of 0.237 and its surroundings are at 310°C. The orange orbis absorbing heat via radiation at a rate of 967 W and it is emitting heat via radiation at a rate of 585 W. Determine the surface area of the orb, the temperature of the orb, & Pret. A- 187491 mg x Torb 1 Units are required for this answer. Pret 1 Units are required for this answer. Convection The exterior walls of a house have a total area of 220 m² and are at 13.2°C and the surrounding air is at 6.6° C. Find the rate of convective cooling of the walls, assuming a convection coefficient of 2.8 W/m²"C). Since you're looking for the rate of cooling, your answer should be entered as positive. Xunts are required for this answe Conduction Ice of mass 14.8 kg at 0°C is placed in an ice chest. The ice chest has 2 cm thick walls of thermal conductivity 0.02 Wim-K and a surface area of 1.39 m², Express your answers with appropriata mks units. ) How much heat must be absorbed by the ice during the melting process? ✓ (b) If the outer surface of the Ice chest is at 33° C, how long will it take for the Ice to melt? 04587 X 4925400 J

Answers

Radiation An orange orb has an emissivity of 0.237 and its surroundings are at 310°C. The orange orb is absorbing heat via radiation at a rate of 967 W and it is emitting heat via radiation at a rate of 585 W. Determine the surface area of the orb, the temperature of the orb, & Pret.

To find the surface area of the orb Solve for A q = eσAT^4 Rearrange to isolate A:

A = q / (eσT^4)Substitute the given values:A = 967 / (0.237 × 5.67 × 10^-8 × 310^4)A = 0.0315 m^2To find the temperature of the orb Solve for T:T = (q / (eσA))^0.25Substitute the given values T = (967 / (0.237 × 5.67 × 10^-8 × 0.0315))^0.25T = 472 KTo find the Pret:Pret = A × T^4Pret = 0.0315 × 472^4Pret = 187491 mg x TorbConvectionThe exterior walls of a house have a total area of 220 m² and are at 13.2°C and the surrounding air is at 6.6°

C. Find the rate of convective cooling of the walls, assuming a convection coefficient of 2.8 W/m²"C). Since you're looking for the rate of cooling, your answer should be entered as positive.q = hA(Tw - Tinf)Solve for q:

q = hA(Tw - Tinf)q = 2.8 × 220 × (13.2 - 6.6)q = 3,080 WConductionIce of mass 14.8 kg at 0°C is placed in an ice chest.

The ice chest has 2 cm thick walls of thermal conductivity 0.02 Wim-K and a surface area of 1.39 m². How much heat must be absorbed by the ice during the melting process?Solve for q:

q = mLq = 14.8 kg × 333,000 J/kgq = 4,930,400 JIf the outer surface of the Ice chest is at 33° C, how long will it take for the Ice to melt?

Solve for t:

t = q / (kAΔT)t = 4,930,400 / (0.02 × 1.39 × (33 - 0))t = 4.587 hoursTherefore, the answer to the given problem is:Surface area of the orb = 0.0315 m²Temperature of the orb = 472 KRate of convective cooling of the walls = 3,080 WHeat absorbed by the ice during the melting process = 4,930,400 JTime it will take for the ice to melt = 4.587 hours.

About Radiation

Radiation is heat transfer without an intermediary substance (media/medium). The tool used to determine the presence of heat emission is a thermoscope. Example of radiation: sunlight reaches the earth. Excessive radiation can increase the risk of cancer. The dangers of electromagnetic radiation are known to cause several cancers, which originate from exposure to ultraviolet (UV) radiation, such as UV-A and UV-B.

Learn More About Radiation at https://brainly.com/question/31285748

#SPJ11

i. ii. Explain the operation of semiconductor transistor. An npn-transistor is biased in the forward- active mode. The base current is IB = 8ŅA and the emitter current is Ic = 6.3 mA. Determine B, a, and IE

Answers

the values of B, a, and IE are 787.5, 1139.29, and 6.308 mA, respectively.

A semiconductor transistor is a device used in electronics to amplify, oscillate, and switch electronic signals. There are two main types of transistors, the bipolar junction transistor (BJT) and the field-effect transistor (FET).NPN Transistor is a type of bipolar junction transistor. It has three terminals named emitter, base, and collector. It is used as an amplifier or a switch in electronic circuits.

In an NPN transistor, a small current at the base can control a larger current flow between the emitter and the collector. This is achieved through a process known as minority carrier injection, where the small current flowing through the base creates an excess of electrons in the base region, which then diffuse into the collector region, allowing a larger current to flow between the emitter and the collector.

When an npn transistor is biased in the forward-active mode, the following conditions must be met: The base-emitter junction must be forward-biased. The collector-base junction must be reverse-biased. The base current IB must be greater than zero. The collector current Ic must be greater than zero.

In order to find B, a, and IE, we need to use the following equations: B = Ic / IB, a = Ic / (IB * Vbe), and IE = Ic + Ib.

Where Vbe is the base-emitter voltage, which is typically around 0.7V for an NPN transistor. Using the given values, we can calculate:

B = Ic / IB = 6.3 mA / 8 nA = 787.5a = Ic / (IB * Vbe)

= 6.3 mA / (8 nA * 0.7V) = 1139.29IE = Ic + Ib = 6.3 mA + 8 nA = 6.308 mA

Therefore, the values of B, a, and IE are 787.5, 1139.29, and 6.308 mA, respectively.

learn more about voltage here

https://brainly.com/question/27861305

#SPJ11

Electric Power is generated in the falls and needed in Ohio we
have to transmit it. 110,000 V, 765,000 V, Why is it done in such
High voltage?

Answers

The reason why electric power is generated in the falls and needed in Ohio is transmitted in such high voltage is to ensure minimal loss of energy due to resistance.

In order to deliver the electricity from the generation site to the consumers, it is necessary to transmit the power over a distance which requires the use of power lines. When transmitting electric power, it is essential to maintain high voltage levels as power losses due to resistance in the transmission lines are proportional to the square of the current. This means that reducing the current will significantly reduce power losses and result in more efficient transmission of electrical power.

Increasing the voltage level of the electrical power transmitted can significantly reduce the amount of energy lost due to resistance.

This is because when the voltage is high, the current is lower, and therefore, the power loss due to resistance is also lower.High voltage is used in electrical transmission to reduce the amount of current that flows through the transmission line, thereby reducing the amount of power that is lost due to resistance. The power loss due to resistance in a transmission line is proportional to the square of the current flowing through it. Hence, by reducing the current, the power loss can be significantly reduced.

However, the voltage level needs to be high enough to overcome the resistance of the transmission line, and so, high voltage is used for long-distance transmission of electrical power.

To know more about Power visit:

https://brainly.com/question/27442707

#SPJ11

For the following transfer function having static velocity error constant K-1 sec¹,
1 / s(s + 1)(s + 4) G(s)
Determine a lag lead compensator such that the dominant closed-loop poles are located at s=-1j1.73 and the static velocity error constant Kv should be equal to 5 sec-¹.

Answers

Transfer function of the lag-lead compensator that satisfies the given conditions is:

H(s) = (s² + 0.1155s + 0.05775) / (s² + 3.0006s + 3.0006).

Let's denote the transfer function of the lag-lead compensator as H(s). The compensator transfer function can be written as:

H(s) = (s + z) / (s + p),

where z and p are the zeros and poles of the compensator, respectively.

Given that we want the dominant closed-loop poles to be located at s = -1j1.73, we can set the compensator pole at the desired location:

p = -1j1.73.

To achieve the desired static velocity error constant (Kv = 5 sec⁻¹), we can set the compensator zero as follows:

z = 1 / (Kv * p) = 1 / (5 * (-1j1.73)).

Now we have the values for z and p, and we can construct the transfer function of the compensator:

H(s) = (s + z) / (s + p).

Substituting the values:

H(s) = (s + 1 / (5 * (-1j1.73))) / (s - 1j1.73).

Simplifying the expression, we can multiply the numerator and denominator by the conjugate of the denominator:

H(s) = ((s + 1 / (5 * (-1j1.73))) * (s + 1j1.73)) / ((s - 1j1.73) * (s + 1j1.73)).

H(s) = (s² + s / (5 * (-1j1.73)) + 1 / (5 * (-1j1.73)) * 1j1.73) / (s² + (1j1.73 - 1j1.73) * s + (1j1.73 * (-1j1.73))).

H(s) = (s² + s / (5 * (-1j1.73)) + 1 / (5 * (-1j1.73)) * 1j1.73) / (s² + 3.0006s + 3.0006).

Therefore, the transfer function of the lag-lead compensator that satisfies the given conditions is:

H(s) = (s² + 0.1155s + 0.05775) / (s² + 3.0006s + 3.0006).

Learn more about compensator from :

https://brainly.com/question/30157900

#SPJ11

The main span of San Francisco's Golden Gate Bridge is 1275 m long at its coldest. The bridge is exposed to temperatures ranging from -10 ºC to 45 ºC. What is its change in length between these temperatures? Assume that the bridge is made entirely of steel.

Answers

The change in length of the bridge between the temperatures -10 ºC and 45 ºC is 0.084 m.

Given that the main span of San Francisco's Golden Gate Bridge is 1275 m long at its coldest and exposed to temperatures ranging from -10 ºC to 45 ºC.

We are to determine the change in length of the bridge between these temperatures. Considering that the bridge is made entirely of steel, and assuming α = 1.2 x 10^-5/°C for steel, we can determine the change in length of the bridge between these temperatures using the formula below:

ΔL = L α ΔT, where; ΔL is the change in length of the bridge

L is the original length of the bridge

α is the coefficient of linear expansion for steel

ΔT is the change in temperature of the bridge

Substituting the given values into the formula, we have;

ΔT = 45 - (-10)

    = 55°C

ΔL = 1275 x (1.2 x 10^-5) x 55

ΔL = 0.084 m

To learn more on temperatures:

https://brainly.com/question/27944554

#SPJ11

Find the change in the -1 BACK E.M.F when the applied voltage on D.C shunt motor 250 volts and armature resistance 2 ohms and armature current on full load = 40 ampers. and on no load .10 ampers =

Answers

The change in the back EMF when the applied voltage on the DC shunt motor is 250 volts, the armature resistance is 2 ohms, and on no load is 10 amperes, is -60 volts.

The back EMF (E) of a DC shunt motor can be calculated using the formula:

E = V - Ia × Ra

where:

V is the applied voltage (250 volts),

Ia is the armature current, and

Ra is the armature resistance (2 ohms).

On full load:

Given that the armature current on full load is 40 amperes, we can calculate the back EMF on full load:

E full load = V - Ia_full_load × Ra

E full load = 250 V - 40 A × 2 Ω

E full load = 250 V - 80 V

E full load = 170 V

On no load:

Given that the armature current on no load is 10 amperes, we can calculate the back EMF on no load:

E no load = V - Ia no load × Ra

E no load = 250 V - 10 A × 2 Ω

E no load = 250 V - 20 V

E no load = 230 V

Now, let's find the change in back EMF:

Change in E = E full load - E no load

Change in E = 170 V - 230 V

Change in E = -60 V

Learn more about voltage -

brainly.com/question/27861305

#SPJ11

13. Based on the rules for coupling electron \( l \) and \( s \) values to give the total \( L \) and \( S \), explain why filled subshells don't contribute to the magnetic properties of an atom.

Answers

The filled subshells do not contribute to the magnetic properties due to their specific electronic configurations.

According to Hund's rule, when electrons occupy orbitals with the same energy, they tend to maximize their total spin. As a result, electrons in partially filled subshells have unpaired spins, leading to a non-zero total spin and the possibility of contributing to the magnetic properties of an atom.

However, in filled subshells, all the available orbitals are already occupied by paired electrons with opposite spins, resulting in a net magnetic moment of zero. Therefore, filled subshells do not contribute to the magnetic properties of an atom because their paired electrons cancel out each other's magnetic moments, leaving no overall magnetic effect.

To know more about  electronic configuration refer here

brainly.com/question/32770628

#SPJ11

Complete Question: Based on the rules for coupling electron l and s values to give the total L and S, explain why filled subshells don't contribute to the magnetic properties of an atom.

b) Wire A has a resistance of 12 Ohms. If wire B is twice the length of A and twice the diameter of A, what is its resistance. Assume that both wires are at the same temperature hence the same Resistivity.

Answers

Let the length of wire A be L and the diameter D. The resistance of wire A is given as 12.

The resistance of a wire is given by the formula:

R = ρL/AS Since both the wires are at the same temperature and have the same resistivity, we can write:

RA = ρL/ARA

= ρL/AD

Since wire B is twice the length and twice the diameter of wire A, its length and diameter are 2L and 2D, respectively. The resistance of wire B is given as RB.

We can write:RB = ρ(2L)/(π(2D/2)²)

= ρ(2L)/(πD²) We know that

D² = (2D/2)²

= 4(D/2)²So, π(2D/2)²

= πD²/4

Substituting the value of D2 in the formula for RB, we get:

RB = ρ(2L)/(πD²/4)

= 4ρL/πD²

We need to substitute the values given to us and obtain the value of RB.

RA = 12 ΩL/D

= 12 ρ/A

Resolving for ρ/AL/D = 12 ρ/ARR

= ρL/A

= ρL/πD²/4

RB = 4ρL/πD²

= 4 × (L/D) × RA

= 4 × (2) × 12

= 96Ω

So, the resistance of wire B is 96.

To know more about resistance, visit:

https://brainly.com/question/32301085

#SPJ11

Problem Solving Strategy: Heat engines IDENTIFY the relevant concepts. A heat engine is any device that converts heat partially to work SET UP the problem using the following steps Learning Goal: Steam at a temperature Tu = 310 °C and p = 1.00 atm enters a heat engine at an unknown flow rate. After passing through the heat engine, it is released at a temperature Tc = 100 °C and p = 1.00 atm The measured power output P of the engine is 550 J/s, and the exiting steam has a heat transfer rate of Hc = 2200 J/s Find the efficiency e of the engine and the molar flow rate n/t of steam through the engine. The constant pressure molar heat capacity Cp for steam is 37.47J/(mol. K) 1. Carefully define what the thermodynamic system is 2 For multi-step processes with more than one step, identify the initial and final states for each step 3. Identify the known quantities and the target variables. 4. The first law. AU=Q-W, can be applied just once to each step in a thermodynamic process, so you will often need additional equations. The equation W Qс Qc e = = 1+ 1- QH QH QH is useful in situations for which the thermal efficiency of the engine is relevant. It's helpful to sketch an energy-flow diagram. EXECUTE the solution as follows: 1. Be very careful with the sign conventions for W and the various Q's W is positive when the system expands and does work, W is negative when the system is compressed. Each Q is positive if it represents heat entering the system and is negative if it represents heat leaving the system 2. Power is work per unit time (P=W/t), and heat current His heat transfer per unit time (H=Q/t). 3. Keeping steps 1 and 2 in mind, solve for the target variables EVALUATE your answer Use the first law of thermodynamics to check your results, paying particular attention to algebraic signs IDENTIFY the relevant concepts This heat engine partially converts heat from the incoming steam into work, so the problem solving strategy for heat engines is applicable SET UP the problem using the following steps
The heat transfer rate for steam leaving the engine, HC The temperature of steam as it leaves the engine. To The constant pressure molar heat capacity of steam, Cp Learning Goal: Steam at a temperature Tu = 310 °C and p = 1.00 atm enters a heat engine at an unknown flow rate. After passing through the heat engine, it is released at a temperature Tc = 100 °C and p = 1.00 atm. The measured power output P of the engine is 550 J/s, and the exiting steam has a heat transfer rate of Hc = 2200 J/s Find the efficiency e of the engine and the molar flow rate n/t of steam through the engine. The constant pressure molar heat capacity C, for steam is 37.47 J/(mol-K) The molar flow rate of steam n/t The heat transfer rate for steam entering the engine. Hy The efficiency of the engine, e Submit Request Answer EXECUTE the solution as follows Part B Complete previous part(s) Part C Complete previous part(s) EVALUATE your answer Part D Complete previous part(s)

Answers

Part A:1. Thermodynamic system: The system here is the heat engine which converts

heat

into work. 2. Initial and final states: The initial state is when steam enters the heat engine at a temperature Tu of 310 °C and p = 1.00 atm. The final state is when steam exits the heat engine at a temperature Tc of 100 °C and p = 1.00 atm.3. Known quantities: T

u = 310 °C, p

= 1.00 atm, Tc

= 100 °C, P

= 550 J/s, Hc

= 2200 J/s, Cp

= 37.47 J/(mol.K).

Target variables: Efficiency e of the engine and molar flow rate n/t of steam through the engine.4. The first law of

thermodynamics

AU=Q-W is applicable. Also, the thermal efficiency equation

e = 1 - Qc/QH is useful. It is helpful to draw an energy-flow diagram. Part B:We know that energy is conserved for the heat engine.

Therefore, the energy flow diagram is,Where QH is the heat

transferred

to the engine, W is the work done by the engine, and Qc is the heat transferred out of the engine. From the above diagram, we have,QH = Hyn/tCp (in J/s)Qc

= Hcn/tCp (in J/s)W

= P/t (in J/s)where t is the time taken by the steam to

flow

through the engine. Part C:Using the above expressions, we getHyn/tCp = QH

= W + Qc

= P/t + Hcn/tCpHn/t

= [Cp (Tc - Tu)/(Tc - Tu + Cp)] (P/Hc)

= 0.0349 mol/s (approx.)e

= 1 - Qc/QH

= 1 - Hcn/tCp/(Hyn/tCp)

= 0.687 (approx.) Part D:The efficiency of the heat engine is 0.687 and the molar flow rate of steam through the engine is 0.0349 mol/s.

To know more about heat engine, visit:

https://brainly.com/question/13155544

#SPJ11

1. (a) Use superposition to find \( v_{0} \) in the circuit in Fig.P1(a). ( 5 pts.) Figure P1(a)

Answers

In order to determine the potential difference \(v_0\) in the circuit in Figure P1(a) we must use the superposition theorem. The superposition theorem is used when there are multiple voltage sources present in a circuit.

It is based on the principle that the voltage across any component in a circuit is equal to the sum of the voltages produced by each source acting independently.The first step is to find the contribution of the 10V source and zero the contribution of the 20V source. After that, we do the opposite, zero the contribution of the 10V source, and find the contribution of the 20V source. Finally, the two contributions are added together to get the final result.The procedure for finding the voltage across the resistor is:

1. Turn off the 20V source and leave the 10V source on.2. Calculate the voltage across the resistor using the voltage divider equation as follows:

[tex]$$V_{\text{resistor}}=V_{10V}\times\frac{R_2}{R_1+R_2}

V_{\text{resistor}}=10\times\frac{6}{3+6}

[tex]V_{\text{resistor}}=6 \text{ V}$$3[/tex][/tex].

Turn off the 10V source and leave the 20V source on.4. Calculate the voltage across the resistor as follows:

[tex]$$V_{\text{resistor}}=V_{20V}\times\frac{R_1}{R_1+R_2}

V_{\text{resistor}}=20\times\frac{3}{3+6}

V_{\text{resistor}}=6.67 \text{ V}$$5[/tex].

Finally, we add the two contributions together to get the final result as follows:

[tex]$$v_0=V_{\text{resistor1}}+V_{\text{resistor2}}[/tex]

[tex]v_0=6 \text{ V}+6.67 \text{ V}[/tex]

[tex]v_0=12.67 \text{ V}$$[/tex]

Therefore, the potential difference [tex]\(v_0\)[/tex] in the circuit in Figure P1(a) is 12.67 V.

To know more about potential visit:

https://brainly.com/question/28300184

#SPJ11

How is it that an aircraft flying over San Diego can receive a weak navigation transmitter (112.5 MHz) located in LA when there is a strong FM radio station (106.5 MHz) transmitting directly under the aircraft? Because the navigation receiver has a highpass filter that passes all frequencies above 88 MHz. Because the navigation receiver in the aircraft has a bandpass filter that passes 112.5 MHz but rejects 106.5 MHz. Because the broadcast transmitter aims its radio signal away from passing aircraft. Because the phasors associated with navigation signals rotate in the opposite direction as those from broadcast signals.

Answers

The phasors associated with navigation signals rotate in the same direction as those from broadcast signals. It is the bandpass filter that filters out the frequencies that are not needed for the navigation system in the aircraft.

The reason that an aircraft flying over San Diego can receive a weak navigation transmitter (112.5 MHz) located in LA when there is a strong FM radio station (106.5 MHz) transmitting directly under the aircraft is that the navigation receiver in the aircraft has a bandpass filter that passes 112.5 MHz but rejects 106.5 MHz. The filter only allows signals within a particular range of frequencies to be passed through.

In this case, the navigation receiver has a bandpass filter that allows only frequencies around 112.5 MHz to pass through. Therefore, the signal from the navigation transmitter at LA is allowed to pass through, and the signal from the FM radio station is rejected because it is not in the range of frequencies allowed by the bandpass filter.

The phasors associated with navigation signals rotate in the same direction as those from broadcast signals. It is the bandpass filter that filters out the frequencies that are not needed for the navigation system in the aircraft.

To learn more about phasors visit;

https://brainly.com/question/32614523

#SPJ11


Some incandescent light bulbs are filled with argon gas. What is
vrms for argon atoms near the filament,
assuming their temperature is 2800 K? The atomic mass of argon is
39.948 u.
in m/s.

Answers

the root mean square velocity for argon atoms near the filament, assuming a temperature of 2800 K, is approximately 1666.29 m/s.

To calculate the root mean square velocity (vrms) for argon atoms, we can use the following formula:

vrms = sqrt((3 * k * T) / m)

Where:

k is the Boltzmann constant (1.380649 x [tex]10^{-23}[/tex] J/K),

T is the temperature in Kelvin, and

m is the molar mass of the gas in kilograms.

Given:

Temperature, T = 2800 K

Molar mass of argon, m = 39.948 u (atomic mass units)

First, we need to convert the molar mass of argon from atomic mass units (u) to kilograms (kg). The conversion factor is 1 u = 1.66054 x 10^-27 kg.

m = 39.948 u * (1.66054 x [tex]10^{-27}[/tex] kg/u)

m ≈ 6.63352 x [tex]10^{-26}[/tex] kg

Now we can calculate vrms using the formula:

vrms = sqrt((3 * k * T) / m)

Plugging in the values:

vrms = sqrt((3 * (1.380649 x [tex]10^{-23 }[/tex]J/K) * (2800 K)) / (6.63352 x [tex]10^{-26}[/tex] kg))

Calculating vrms:

vrms ≈ 1666.29 m/s

to know more about temperature visit:

brainly.com/question/12035620

#SPJ11

what is the control voltage used by most residential hvac equipment

Answers

The control voltage used by most residential HVAC equipment is 24 volts AC.

In residential HVAC equipment, control voltage is used to regulate the operation of various components. The control voltage is typically a low voltage electrical signal that activates or deactivates motors, valves, and sensors. It is an essential part of the HVAC system, allowing for precise control and efficient operation.

Most residential HVAC equipment uses a control voltage of 24 volts AC (alternating current). This voltage is commonly used because it is safe, efficient, and compatible with the majority of HVAC equipment available in the market. The control voltage is supplied by a transformer that steps down the voltage from the main power supply to the required level for control purposes.

Learn more:

About control voltage here:

https://brainly.com/question/14469992

#SPJ11

The control voltage used by most residential HVAC equipment is typically 24 volts AC. Control voltage is the voltage used to operate the controls of an HVAC system.

Most residential HVAC equipment uses 24 volts AC as the control voltage for the thermostat, control relays, and other controls. The control voltage is used to send a signal to the different components of the HVAC equipment to turn on or off or adjust to a certain setting.The 24 volts AC is preferred because it is a safe and low voltage, which can be easily controlled and is not hazardous to people or equipment.

The 24 volts AC is also easy to transform from the primary power source, which is usually 120 or 240 volts AC, by using a transformer that can step down the voltage to 24 volts AC. This makes it easy to install and maintain the HVAC equipment.Overall, the control voltage used by most residential HVAC equipment is 24 volts AC, which is a safe and low voltage that can be easily controlled and transformed from the primary power source.

To know more about   HVAC system  visit:-

https://brainly.com/question/32679929

#SPJ11

An a-particle has a charge of +2e and a mass of 6.64×10 −27
kg. It is accelerated from rest through a potential difference that has a value of 1.20×10 6
V and then enters a uniform magnetic field whose magnitude is 2.20 T. The a-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the a-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular path?

Answers

(a) The speed of the α-particle is approximately 3.61 × 10⁷ m/s. (b) The magnitude of the magnetic force on the α-particle is approximately 1.59 × 10⁽⁻¹³⁾⁾ N. (c) The radius of the α-particle's circular path is approximately 1.51 × 10⁽⁻³⁾⁾) m.

(a) To find the speed of the α-particle, we can use the equation relating kinetic energy and potential difference.

The potential difference (V) is related to the kinetic energy (K) by:

K = e * V

where e is the charge of the α-particle (+2e).

Substituting the given values:

V = 1.20 × 10⁶ V

e = +2e (charge of α-particle)

K = (+2e) * (1.20 × 10⁶V)

Now, we can use the kinetic energy formula to find the speed (v) of the α-particle:

K = (1/2) * m * v²

where m is the mass of the α-particle (6.64 × 10⁽⁻²⁷⁾kg).

Solving for v:

v = sqrt((2 * K) / m)

Substituting the known values:

v = sqrt((2 * (+2e) * (1.20 × 10⁶V)) / (6.64 × 10⁽⁻²⁷⁾ kg))

Calculating this, we find:

v = 3.61 × 10⁷ m/s

Therefore, the speed of the α-particle is approximately 3.61 × 10⁷m/s.

(b) The magnitude of the magnetic force on the α-particle can be calculated using the equation:

F = q * v * B

where q is the charge of the α-particle (+2e), v is the speed of the α-particle, and B is the magnitude of the magnetic field.

Substituting the known values:

q = +2e (charge of α-particle)

v = 3.61 × 10⁷ m/s

B = 2.20 T

F = (+2e) * (3.61 × 10⁷ m/s) * (2.20 T)

Calculating this, we find:

F = 1.59 × 10⁽⁻¹³⁾⁾N

Therefore, the magnitude of the magnetic force on the α-particle is approximately 1.59 × 10⁽⁻¹³⁾⁾N.

(c) The radius of the circular path can be determined using the formula for the centripetal force:

F = (m * v²) / r

\where F is the magnetic force on the α-particle, m is the mass of the α-particle, v is the speed of the α-particle, and r is the radius of the circular path.

Rearranging the equation to solve for r:

r = (m * v) / F

Substituting the known values:

m = 6.64 × 10⁽⁻²⁷⁾⁾ kg

v = 3.61 × 10^7 m/s

F = 1.59 × 10⁽⁻¹³⁾⁾N

r = (6.64 × 10⁽⁻²⁷⁾ kg * 3.61 × 10^7 m/s) / (1.59 × 10⁽⁻¹³⁾ N)

Calculating this, we find:

r = 1.51 × 10⁽⁻³⁾) m

Therefore, the radius of the α-particle's circular path is approximately 1.51 × 10⁽⁻³⁾ m.

To know more about speed refer here

brainly.com/question/6280317

#SPJ11




0/5 pt Question 8 What volume of copper (density 8.96 g/cm) would be needed to balance a 1.38 cm3 sample of lead (density 11.4 g/cm3) on a two-pan laboratory balance?

Answers

The volume of copper (density 8.96 g/cm³) required to balance a 1.38 cm³ sample of lead (density 11.4 g/cm³) on a two-pan laboratory balance is 1.75 cm³.

We are supposed to find the volume of copper that would be needed to balance a 1.38 cm³ sample of lead on a two-pan laboratory balance. To balance the masses of copper and lead, the masses of both elements need to be equal. Thus, the density equation can be used here. It is as follows:    

Density = Mass / Volume

Or

Mass = Density × Volume

Therefore, the mass of the lead sample would be = 11.4 g/cm³ × 1.38 cm³ = 15.732 g

Now, we need to calculate the volume of copper that would have the same mass as the lead. Thus,

Mass of copper = 15.732 g

Density of copper = 8.96 g/cm³

Volume of copper = Mass / Density

= 15.732 g / 8.96 g/cm³≈ 1.75 cm³

Therefore, the volume of copper is approximately 1.75 cm³.

You can learn more about volume at: brainly.com/question/28058531

#SPJ11

Using the parameters of the previous exercise, calculate the spontaneous emission wavelength and the optical power of the LED at a bias voltage of 1 V assuming that the extraction efficiency is 10% and the surface of the diode is 1 mm.

The p and n sides of a GaAs LED have a doping concentration of 1018 cm-³. The emission of light is caused mainly by the injection of electrons into the p-side. There is a recombination center in the active region with a time constant of 5 x 10-9 s. Assume that the lifetime of the electrons and the holes is the same and that De = 120 cm² s-1, Dh = 0.01 De. What is the injection efficiency with bias voltage of 1 V, if the coefficient of band-to-band radiative recombination is By = 7.2 x 10-10 cm³ s-1?

Answers

The optical power (P) can be calculated using the formula: P = R * λ / (hc / q), where R is the emission rate, λ is the wavelength, h is Planck's constant, c is the speed of light, and q is the electron charge. Given the extraction efficiency of 10%, we can multiply the calculated optical power by 0.1 to account for the extraction efficiency

Step 1: Calculate the injection efficiency (η):Injection efficiency (η) can be determined using the formula: η = (τn + τp) / (τn + τp + τr), where τn and τp are the lifetimes of electrons and holes, respectively, and τr is the recombination center time constant.Given that the lifetime of electrons and holes is the same (τn = τp) and the recombination center time constant is 5 x 10^(-9) s, we can substitute these values into the formula: η = (2τn) / (2τn + 5 x 10^(-9) s). Step 2: Calculate the emission rate (R): The emission rate (R) can be calculated using the formula: R = η * By * (pn - ni²), where By is the coefficient of band-to-band radiative recombination, pn is the excess carrier concentration, and ni is the intrinsic carrier concentration.Given that the doping concentration on both the p and n sides is 10^18 cm^(-3), we can calculate pn = p - n = 10^18 cm^(-3) - 10^18 cm^(-3) = 0. Since the lifetime of electrons and holes is the same, we can use either the p-side or n-side concentration to calculate ni. Step 3: Calculate the spontaneous emission wavelength (λ):The spontaneous emission wavelength (λ) can be calculated using the formula: λ = hc / E, where h is Planck's constant, c is the speed of light, and E is the energy of a photon. The energy of a photon (E) can be calculated using the formula: E = hc / λ, where h is Planck's constant and c is the speed of light. Step 4: Calculate the optical power (P): The optical power (P) can be calculated using the formula: P = R * λ / (hc / q), where R is the emission rate, λ is the wavelength, h is Planck's constant, c is the speed of light, and q is the electron charge. Given the extraction efficiency of 10%, we can multiply the calculated optical power by 0.1 to account for the extraction efficiency. Note: Make sure to use consistent units throughout the calculations. Please provide the necessary values for the electron charge (q) and the speed of light (c) in the exercise to proceed with the calculation.

To learn more about extraction efficiency:

https://brainly.com/question/32453345

#SPJ11

Other Questions
"48 In Fig. 5-35, three blocks are pulled to the right on a horizontal frictionless table by a force of magnitude T3 = 95.0 N. If m = 10.0 kg, m = 14.0 kg, and m3 = 23.0 kg, calculate (a) the mag" zoonosis caused by a spirochete? group of answer choices syphilis pinta leptospirosis yaws bejel A deficiency of vitamin B6 can result in depression, headaches, and confusion. These occur because of impairedSelect one:a. hemoglobin synthesis.b. glucose metabolism.c. neurotransmitter synthesis.d. myelin synthesis. c++ onlyA corporation has six divisions, each responsible for sales to different geographic locations. Design a DivSales class that keeps sales data for a division, with the following members: - An array with The following system \[ y(t)=e^{t a(n)} \] is Select one: Time invariant Linear Stable None of these if a load extends 4 or more feet beyond the bed or body of a vehicle driven on a highway in the daytime:_______. Question16How many objects are created in this program? Identify each of themand elaborate1 #include 2 #include 34 using namespace std;56 int mai 0.IKB/Sill 3:40 PM (f) 76% Homework of Chapter 6 9. Single Choice As every amusement park fan knows, a Ferris. wheel is a ride consisting of seats mounted on a tall ring that rotates around a horizontal axis. When you ride in a Ferris wheel at constant speed, what are the directions of a FN your acceleration and the normal force on you (from the always upright seat) as you pass through (1) the highest point and (2) the lowest point of the ride? (3) How does the magnitude of the acceleration at the highest point compare with that at the lowest point? (4) How do the magnitudes of the normal force compare at those two points? A , (1) a downward, FN downward; (2) a and FN upward; (3) same; (4) greater at lowest point; , (1) a downward, FN upward; (2) a and FN upward; (3) same; (4) greater at lowest point; , (1) a downward, FN upward; (2) a and FN upward; (3) greater at lowest point; (4) FILL THE BLANK.______ is the deepest spot in the ocean. The Hudson Canyon The Grand Canyon The Mariana Trench The middle of the Atlantic Ocean Just offshore of California. PLEASE ANSWER ALL OF THIS QUESTION ASAP!!!Assignment: 1. Determine the internal normal force at section \( A \) if the rod is subjected to the external uniformally distributed loading along its length. 2. Determine the internal normal force o which substance can dissolve only 40 g in 60c water? group of answer choices a. nacl b. kclo3 c. kcl d. ce2(so4)3 In the first reading, Washington discusses somebenefits that African Americans have because ofslavery. Write 2-3 sentences explaining hisposition using text from the document BOOK -Name: string -Author(s): string -Publisher: string -ISBN number: string -Price: price -Year of publication: int +info.SetName() +info.SetPubAndIsbn() +info.SetPriceAndYear() According to the Electronic Communications Privacy Act of 1986, when will a law enforcement officer need a warrant to intercept e-mail?Anytime email will be interceptedCalls for the establishment of regional computer forensic laboratoriesPolice Officers. 3. (30 points) Create a table in AWS DynamoDB to record car registration. The registration information include car VIN, driver license number, driver name, and car plate number. Use a loop to add 100 car information to the table. Then let police officer to use query to search car registration information based on car plate number. a) List four switching devices, explain their operational use and differences. b) Explain the classification of circuit breakers, their operational use, and benefits. 4 (35 pts): Let you want to transmit R = 4800 bits/sec information stream from a transmission channel which has a bandwidth of 20 kHz. You are allowed to use Nyquist criterion pulses with roll-off factor r=0 with an orthogonal non- coherent MFSK modulation. (a) (7 pts) Determine the value of M which minimizes the E/No at the receiver? (b) (8 pts) Based on your result In part (a), determine the value of E/No (in dB) so that the BER at the output of the receiver is P, 10-7. (c) (7 pts) Determine the value of M which minimizes the E/No at the receiver when R = 9600 bits/sec and channel bandwidth of 20 kHz? (d) (8 pts) For the system given in part (c), determine the value of (in dB) so that the BER at the output of the receiver is PLEASE PLEASE PLEASE follow theinstructions to the point as this is a very important assignmentfor me. I need a detailed four to five-page paper assignment. Youwill help me a lot. ThanksWEEK 4 ASSIGNMENT - EVALUATE THE USE OF BA AND AI SOLUTIONS TO MITIGATE RISK Week 4 Assignment - Evaluate the Use of BA and Al Solutions to Mitigate Risk Preparation The following resource may be help 1An electronic voting system for a company is to be designed. Four shareholders A, B, C and D holds 20%, 10%, 30% and 40% of shares in the company respectively. Their voting powers are reflective of the number of shares they hold (a HIGH input indicates a vote for a particular decision). Any executive decision will be implemented if the shareholders' vote is 50% (A HIGH output F indicates votes of 50%).a) Derive the truth table for the design. The nurse is working with a client who wants to make dietary changes to decrease his blood pressure. The nurse should recommend the client's daily intake of