An outline for how to approach writing your lab report is as follows
The parts
"TITLE," "INTRODUCTION" "PROCEDURE" "RESULTS" "DISCUSSION/CONCLUSION"This is further explained below.
How to write a lab report?Generally, A lab report is composed of eight different components, which are as follows: the title, the abstract, the introduction, the techniques and materials, the findings, the discussion, and the conclusion.
In conclusion, It is important that the experiment is adequately described in the title of the lab report, and that the title also accurately represents the data obtained from the experiment.
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Which graph below represents how the velocity of the sphere changes over time when falling with constant acceleration?
Justify your choice.
Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.
Acceleration is the measure of how quickly a body's velocity varies with regard to time, and constant acceleration occurs when a body's velocity changes proportionately over a period of time, or at a constant rate. It measures in m/s2.It is claimed that a body has continual positive acceleration when it begins to move with an initial velocity of zero and gradually increases to a positive value over time.Constant positive acceleration is demonstrated by a ball falling freely in a vertical direction.To know more about constant acceleration. visit : brainly.com/question/9754169
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True or False? Air resistance acts in the direction the object is moving in.
A car with an initial speed of 22.1 km/h accelerates at a uniform rate of 0.84 m/s2 for 4.4 s. Find the final speed of the car. Answer in units of m/s. Find the displacement of the car after that time. Answer in units of km.
(Desperately need help with Part 2)
Answer:
Final speed of car = 9.834 m/s
Displacement = 0.035 km
Explanation:
Part 1
Final velocity, v of an object moving with an acceleration a m/s² for t seconds and an initial velocity u m/s is given by the formula
v = u + at m/s
[tex]\textrm{Initial velocity } u = 22.1 km/h\\\\\textrm{Convert this to m/s:}\\\\\textrm{1 km/h = 1000m/3600 s}\\\\ 22.1 km/h = 22.1 x 1000/3600 = 6.139 m/s\\\\\boxed{\textrm{Final velocity } v = u + at = 6.138 + 0.84 x 4.4 = 9.834 m/s}[/tex]
Displacement s in m for a constant acceleration of a m/s² for a time t seconds is given by the formula:
[tex]x = ut+\dfrac{1}{2}at^2[/tex]
where u is initial velocity
Plugging in the values we get
[tex]s = 6.139\cdot 4.4 + \dfrac{1}{2}\cdot0.84\cdot (4.4)^2 = 35.143 \;\mathrm {meters}[/tex]
35.143 meters = 35.143/1000 = 0.035 km
Answer:
1) 9.83 m/s (2 d.p.)
2) 0.04 km (2 d.p.)
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Part 1Given:
u = 22.1 km/ha = 0.84 m/s²t = 4.4 sConvert km/h into m/s by dividing by 3.6:
[tex]\implies \sf 22.1\;km/h=\dfrac{22.1}{3.6}\;m/s[/tex]
Substitute the given values into the formula and solve for v:
[tex]\begin{aligned}v&=u+at\\\implies v & = \dfrac{22.1}{3.6}+0.84(4.4)\\v & = 6.1388...+3.696\\v & = 9.834888...\\v & = 9.83 \sf \;m/s\;(2\:d.p.)\end{aligned}[/tex]
Therefore, the final speed of the car was 9.83 m/s (2 d.p.).
Part 2Substitute the given values into the formula and solve for s, remembering to use the initial velocity in m/s:
[tex]\begin{aligned}s & = ut+\dfrac{1}{2}at^2\\\implies s &=\dfrac{22.1}{3.6}(4.4)+\dfrac{1}{2}(0.84)(4.4)^2\\s &=27.0111...+8.1312\\s &=35.1423111...\sf m\end{aligned}[/tex]
Convert meters into kilometers by dividing by 1000:
[tex]\implies \dfrac{35.1423111...}{1000}=0.0351423111...=0.04 \sf \; km\;(2\:d.p.)[/tex]
Therefore, the displacement of the car after 4.4 s was 0.04 km (2 d.p.).
(Figure 1) shows a 5.4 N force pushing two gliders along an air track. The 150 g spring between the gliders is compressed. The spring is firmly attached to the gliders, and it does not sag.
a)How much force does the spring exert on glider A ?
b)How much force does the spring exert on glider B ?
(a) The force the spring exert on glider A is 1.88 N.
(b) The force the spring exert on glider B is 2.82 N.
Acceleration of the springThe acceleration of the spring is calculated as follows;
F = ma
a = F/m
a = 5.4 N / (0.15 kg + 0.4 kg + 0.6 kg0
a = 4.7 m/s²
force the spring exert on glider AF(A) = ma
F(A) = 0.4 kg x 4.7 m/s²
F(A) = 1.88 N
force the spring exert on glider BF(B) = 0.6 kg x 4.7 m/s²
F(B) = 1.88 N
F(B) = 2.82 N
Thus, the force the spring exert on glider A is 1.88 N.
The force the spring exert on glider B is 2.82 N.
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a) d = 24 g/mL
v = 1.2 L =
m=? 28.1
? 23.03
mL
Density calculations are 1.2L = 1200mL m = 2.9 x 10^4 g
Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimetre are a typical unit of measurement for density. Another way to state density is in kilogrammes per cubic metre (in metre-kilogram-second or SI units).
For instance, air weighs 1.2 pounds per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated. The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).
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A runner is jogging in a straight line at a steady v, 3.5 km/hr. When the runner is L= 3.1 km from the finish line, a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr (5 times as fast as the runner). When the bird reaches the finish
line, it turns around and flies directly back to the runner. finish line What cumulative distance does the bird travel? Even though the bird is a dodo, assume that it occupies only one point in space (a "zero" length bird), travels in a straight line, and that it can turn without loss of speed.Answer in units of km.
If a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr, the bird would reach the finish line in 10 minutes and 37.71 seconds.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.
As given in the problem A runner is jogging in a straight line at a steady v, 3.5 km/hr. When the runner is L= 3.1 km from the finish line, a bird begins flying straight from the runner to the finish line at v= 17.5 km/hr (5 times as fast as the runner).
The time is taken by the bird to reach the finish line = 3.1 km /17.5 km/hour
=0.177 hours
= 10 minutes 37.71 seconds
Thus, the bird would reach the finish line in 10 minutes and 37.71 seconds.
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A butcher throws a cut of beef on spring scales which oscillates about the equilibrium
position with a period of T = 0.500 s. The amplitude of the vibration is A = 2.00 cm
(path length 4.00 cm). Find:
i. Frequency
ii. the maximum acceleration
iii. the maximum velocity
iv. the acceleration when the displacement is 1.00 cm
v. the velocity when the displacement is 1.00 cm
vi. the equation of motion as a function of time if the displacement is A at t = 0
The frequency of the simple harmonic motion is 2 Hertz , the maximum acceleration is 3 u and the maximum velocity is equal to 2.48 m/s.
What is oscillation?Oscillation is the repetitive or periodic variation, typically in time, of some measure about a central value or between two or more different states.
What is the time period?Time period in periodic oscillation refers to the time taken by the system to complete one oscillation.
Given:
Time period of the oscillation = 0.5 seconds
Amplitude of the oscillation = 2 cm
For determining frequency we use the formula of frequency.
f = 2π/T
Where,
f is the frequency of the oscillation
T is the time period of the oscillation
On substituting values we get,
Frequency (f) = 1/0.5
Frequency (f) = 2 Hertz
For determining maximum acceleration we use,
a = A × w × w
Where,
a is the acceleration
A is amplitude of the SHM
w is the angular frequency
Now,
a = A × w × w
a = 0.02 × 12.4× 12.4
a = 3 u
For maximum velocity we use,
v = A × w
Where v is maximum velocity
v = 0.02 × 12.4
v = 2.48 m/s
Therefore, the frequency of the simple harmonic motion is 2 Hertz , the maximum acceleration is 3 u and the maximum velocity is equal to 2.48 m/s.
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A race car rounds a curve at 55 m/s. The radius of the curve is 434 m, and the car's mass is 685 kg. (Assume the car's speed remains constant. Take the radially inward direction to be positive. Indicate the direction with the sign of your answer.)
(a) What is the car's (centripetal) acceleration?
______m/s2
What is it in g's?
____g
(b) What is the centripetal force acting on the car?
____N
PLEASE HELP!!!
The car's (centripetal) acceleration would be 6.97 meters / second², its value in terms of acceleration due to gravity would be 0.71 g and the centripetal force acting on the car would be 4774.5 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem a race car rounds a curve at 55 m/s. The radius of the curve is 434 m, and the car's mass is 685 kg. (Assume the car's speed remains constant. Take the radially inward direction to be positive.
The centripetal acceleration of the car = v² / r
=55² / 434
= 6.97 meters / second²
The centripetal force acting on the car = m×v² / r
=685× 6.97
=4774.50 Newtons
Thus, the centripetal force acting on the car would be 4774.5 Newtons.
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In 1954 the English runner Roger Bannister broke the four-minute barrier for the mile with a time of 3:59.4 s (3 min and 59.4 s). In 1999 the Moroccan runner Hicham el-Guerrouj set a record of 3:43.13 s for the mile. If these two runners had run in the same race, each running the entire race at the average speed that earned him a place in the record books, el-Guerrouj would have won. By how many meters?
Answer:
Bannister = 3:59.4 sec = 239.4 sec
Guerruoj = 3:43.13 = 223.13 sec
1 mi = 5280 ft
G = 5280 / 223.13 = 23.66 ft/sec
B = 5280 / 239.4 = 22.06 ft/sec
In 223.13 sec B runs 223.13 * 22.06 = 4922 ft
G Wins by 358 ft = 119.3 yds = 109.1 meters
A satellite orbiting Earth at an orbital radius [tex]r[/tex] has a velocity [tex]v[/tex]. Which represents the velocity if the satellite is moved to an orbital radius of [tex]4r[/tex]?
A. [tex]4v[/tex]
B. [tex]\frac{1}{2}v[/tex]
C. [tex]\frac{1}{4}v[/tex]
D. [tex]2v[/tex]
Answer: C
Explanation:
The bigger the satellite, the longer it will take to get around the satellite. Hence, the velocity would get smaller.
r*v=4r*?
r*v/4r=?
r/4r * v=?
1/4 * v=?
?=v/4 ==> C
The law of Conservation of energy states that energy can be transformed from one form to another, but it cannot be _______ or ________. created, changed created, destroyed changed, destroyed radiated, conducted
Answer:
The low of conservation of energy states that "energy can neither be created nor be destroyed but it can be changed from one form to another".
Need help answering these problems
The acceleration is obtained from the net force and the mass of a body.
What is the force?According to the Newton second law, we know that force is the product of the mass and the acceleration of a body. Given the fact that the force applied on the body is in opposite direction to the friction, we can be able to obtain the friction from the images shown in the problem.
In the first case;
Force = mass * acceleration
acceleration= force/mass
acceleration= 175 N/50 = 3.5 m/s^2
In the seconds case;
Net force = 330 N - 196 N = 134 N
acceleration= force/mass
acceleration= 134 N/200 Kg = 0.67 m/s^2
In the third case;
Net force = 373 N - 147 N = 226 N
acceleration= force/mass
acceleration= 226 N/50 Kg
= 4.52 m/s^2
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An Alaskan rescue plane traveling 45 m/s
drops a package of emergency rations from
a height of 110 m to a stranded party of
explorers.
margolalaraq
The acceleration of gravity is 9.8 m/s².
Where does the package strike the ground
relative to the point directly below where it
was released?
Answer in units of m.
The package strike the ground relative to the point directly below it was released at 213.3m.
Equation:Given values,
Velocity of plane 45 m/s
Acceleration due to gravity 9.8 m/s²
horizontal component of plane velocity is
ux = 45 m/s
Vertical component is zero
In the same way
ay = - 9.8 m/s²
ax = .0 m/s^2
Motion in y direction = -110 m
From equation of motion time of flight is
d = u x t + 1/2 at²
where,
d is distance
u is velocity initial
a is acceleration
t is time
So, putting values
-110 = 0 + 1/2 (-9.8)t²
-110 = -4.9t²
t² = 110 / -4.9
t² = 22.45
t = √22.45
t = 4.74
Motion in x direction,
d = u x t + 1/2 at²
d = ( 45 x 4.74) + 1/2 (0) 4.74²
d = 213.3 + 0
d = 213.3m
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An apple is hanging at rest on a tree when its stem breaks. It takes 1.4 seconds for the apple to fall halfway to the ground. How long does it take for the apple to fall the entire distance to the ground?
The apple takes 2.05 seconds to fall due to gravity.
Newton's Second Law of Motion and Newton's Law of Universal Gravitation serve as the foundation for the formula for the acceleration caused by gravity. The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is the universal gravitational constant, M is mass, and R is distance.
Everything has a gravitational pull on every other object, according to Newton's Law of Universal Gravitation. The force is inversely proportional to the square of the distance between the centers of both objects and directly proportional to the masses of both objects. This is determined mathematically by the formula F = G*(m1*m2/d2), where F is the force and G is the gravitational constant of the universe.
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According to the conservation of momentum, if a smaller football player collides with a
much larger football player, what can be said about the movement of each player after
the collision?
Although the bigger football player will move, his speed will be substantially slower than the smaller players due to his greater mass.
According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced. As a result, momentum cannot be gained or lost.
When a collision occurs, the point of impact is generated by two equal and opposing forces. The heavier mass will be forced to accelerate by the force applied to it, whereas the smaller mass will be forced to slow down by the force applied to it.
Because of their greater mass, larger masses will accelerate more slowly, reducing their velocity.
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What is the weight of a 12.5kg mass?
What is the mass of a 2.5N weight?
200N are weighed. What is the mass?
What will a scale read for a 4kg mass?
1. The weight of a 12.5 kg mass is 122.625 N
2. The mass of a 2.5 N weight is 0.255 kg
3. The mass of a 200 N weight is 20.4 kg
4. The scale read for a 4 kg mass is 39.2 N
What is the relationship between weight and mass?The mass of a substance is the quantity of matter present in that substance.
The quantity of matter or mass of a substance is constant and is measured using a weighing balance.
The weight of a substance is the product of the mass of a substance and the acceleration due to gravity.
The weight of a substance varies and is measured using a spring balance and the unit is N.
Weight = m * g
where;
m is mass in kg
g = 9.81 m/s²
Considering the given substances:
1. The weight of a 12.5 kg mass = 12.5 * 9.81
The weight of a 12.5 kg mass = 122.625 N
2. The mass of a 2.5 N weight = 2.5/9.81
The mass of a 2.5 N weight = 0.255 kg
3. The mass of a 200 N weight = 200/9.81
The mass of a 200 N weight = 20.4 kg
4. The scale read for a 4 kg mass = 4 * 9.81
The scale read for a 4 kg mass = 39.2 N
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Why are the noble gases the least reactive elements?
what is The physical meaning of the slope for the kinetic frictional force vs. normal force graph
The physical means of the slope between the static friction and the normal pressure is the coefficient of static friction of the surface on which the object is located.
Mathematically fstatic≤usΝ in which μs is the coefficient of friction and slope among fs and N will provide this μs mentioning that static friction increases with an increase in everyday pressure and vice versa. but we will see this linearity between fs and N most effective for the most static frictional pressure and till fs< usN we can't observe this linearity and when fs=uSN we will look at this linearity.
The slope of this graph represents the coefficient of friction, The more the force the more the friction because the pressure is higher the downward pressure is extra consequently the object. So the friction on the shoe does rely on the load. So the slope of the graph represents the coefficient of friction. Kinetic friction importance is directly proportional to the regular pressure magnitude and the roughness between the sliding surfaces. Static friction magnitude is immediately proportional to the normal pressure importance and the roughness among the sliding surfaces.
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An object is launched across a room. How can a student determine the average horizontal velocity of the object using a meter stick and a calculator
1) The student can measure the initial velocity and acceleration and use that information to calculate objects final velocity.
2) The student can measure the recoil distance of the throwing mechanism and then calculate the velocity from the conservation of momentum principle.
3) The student can measure the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.
4) The student can measure the fall distance and travel time from the horizontal displacement and then calculate the average horizontal velocity.
The student can determine the average horizontal velocity of the object using a meter stick and a calculator by measuring the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.
So option 3 is correct.
What is horizontal velocity?The horizontal velocity can be described as the velocity of any projectile along a horizontal path.
From the options given, the student can measure the horizontal distance traveled, determine the flight time from the vertical drop, and then calculate the average horizontal velocity.
Gravity acts only in the vertical direction and doesn't affect horizontal motion directly.
Horizontal velocity comes from forces that act in the x-axis, that is directions from side to side and not up or down.
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Which type of circuit has
more than one path for
electrons to flow?
A. Parallel
B. Series
C. Neither
Answer:
A. Parallel connection
Answer:
Parallel circuit to be exact
A car travels 500 km in 4 hours. Another car travels the same 500 km in 5 hours. The cars have the same
A . Acceleration
B . Speed
C . Average Velocity
D . Displacement
A car traveling 500km in 4 hours and another car traveling 500km in 5 hours, both the cars have the same displacement. Thus, the correct option is D.
What is Displacement?The displacement is a vector quantity because is has both the magnitude and direction. Displacement is the quantity whose length is the shortest distance from the initial position to the final position of a point which is undergoing motion. Displacement quantifies both the distance and direction of the net or the total motion of an object along the direction of a straight line from the initial position to the final position of the point trajectory of the object. A displacement may be identified with the translation which maps the initial position to the final position of an object.
A displacement may be also described as a relative position, that is, as the final position of an object relative to its initial position. The corresponding displacement vector can be defined as the difference between these two that is the final position and initial position of the object.
Therefore, the correct option is D.
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What is the direction
Answer:
Explanation:
[tex]tan^{-1} (4/3) = 53.3[/tex]
1. Which of the following secondary sex characteristics do not develop during the teen years?
Odevelopment of breasts in girls
Odevelopment of body hair in boys
Odevelopment of ovaries in girls and testes in boys
Odevelopment of acne in boys
Answer:
Development of acne in boyw
You are traveling on an airplane. The velocity of the plane with respect to the air is 120 m/s due east. The velocity of the air with respect to the ground is 43 m/s at an angle of 30° west of due north.
1) What is the speed of the plane with respect to the ground?
2) What is the heading of the plane with respect to the ground? (Let 0° represent due north, 90° represents due east).
3) How far east will the plane travel in 1 hour?
Answer:
VPA
Explanation:
briefly define what are micro-organisms
what is the value of the x component of the car's average velocity, in meters per second, during the given time interval
To find the component of car's average velocity along X-axis, the angle between the the direction of the velocity and the X-axis must be known.
The value of x component of the car's average velocity is Vcosx.
Calculation of the x component of the car's average velocityLet the angle be = x
The X-component of the car's average velocity = Vcosx.
V is the magnitude of the velocity.
To calculate the y component of the car's average velocity
The Y-component of the velocity = Vsinx
What does the phrase "average velocity" actually mean in context?The difference between the change in position or displacement (x) and the time periods (t) during which the displacement happens is known as average velocity. Depending on the direction of the displacement, the average velocity could be either positive or negative. Meters per second (m/s or ms-1) is the SI unit of measure for average velocity.
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Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life. Read a sample of one type of narrative nonfiction below and determine the type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life
Memoir is a type of narrative nonfiction: Monique went through many trials and tribulations and decided to write a book about this particular period in her life.
Because it combines elements of creative writing with the relation of facts required to produce a work of nonfiction, narrative nonfiction is a type of writing that is occasionally referred to as creative nonfiction. This genre comprises of writing that is factually accurate yet written with a creative flair that contributes to improving the work's flow and appeal. The genre of narrative nonfiction can include journalism and some genres of biography, essay, memoir, and personal essay. When compared to plain nonfiction, this genre is very new, and as the genre has developed, so too has the scrutiny that is applied to this kind of writing.
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A reconnaissance plane flies 404 km awayfrom its base at 730 m/s, then flies back to its base at 1095 m/s.What is it’s average speed?
Answer in units of m/s
The average speed of the plane is 875.999 m/s.
Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.
Mathematically, Average speed = Av = [tex]\frac{Total Distance}{Total Time}[/tex]
According to the question,
Speed of the plane away from its base V₁ = 730 m/s
Speed of the plane when it flies back V₂ = 1095 m/s
Plane flies the distance D = 404 km
Total Distance covered by the plane S = 404 * 2 km
(because the distance travelled by the plane when going away from the base and then flying back to the base is same)
Therefore S = 808 km = 808 ˣ 10³ m
Time taken by the plane while flying away from the base T₁ = [tex]\frac{D}{V1}[/tex]
T₁ = [tex]\frac{404000}{730}[/tex] = 553.425 s
Time taken by the plane while flying back to the base T₂ = [tex]\frac{D}{V2}[/tex]
T₂ = [tex]\frac{404000}{1095}[/tex] = 368.949s
Total Time T = T₁ + T₂ = 922.375 s
Therefore Av = [tex]\frac{Total Distance}{Total Time}[/tex]
= [tex]\frac{D}{T}[/tex] m/s
= [tex]\frac{808000}{922.375}[/tex] m/s
= 875.999 m/s
The average speed of the plane will be 875.999 m/s.
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Would "throwing" the picket fence up or down prior to its passing through the photogate affect the experimentally deter-
mined g value?
If you throw the picket fence down instead of dropping it, the graphs and values will change due to forces other than gravity acting on it. When you throw it, gravity works against it, so they change too, and eventually return tends to decrease. acceleration due to gravity by quadratic curve fitting for the given data is 9.726 m/s2.
The purpose of this exercise was to measure the acceleration of a free-falling object using the slope of a velocity versus time plot. If you drop the picket fence from the same height each time, the photogate will read a slope of 9.8 each time.
The photogate has a beam of infrared light that moves left and right. You can detect whenever that beam is blocked. They drop clear plastic strips with evenly spaced black bars called picket fences. As the mass of an object increases, the object's acceleration decreases.
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They drop picket fences, which are clear plastic strips with neatly spaced black bars. The acceleration of an item decreases as its mass increases.
The photogate emits an infrared light beam that travels left and right. When the beam is obstructed, you can detect it. The graphs and numbers will vary if you fling the picket fence down instead of dropping it owing to factors other than gravity acting on it. Gravity works against it as you toss it, thus they vary as well, and ultimately return tends to diminish. For the given data, the acceleration due to gravity calculated using quadratic curve fitting is 9.726 m/s2.
The goal of this exercise was to use the slope of a velocity vs time plot to calculate the acceleration of a free-falling object. If you drop the picket fence from the same height each time, the photogate will always report a slope of 9.8.
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A transverse wave can be graphed as position vs. time or y-position vs. x-position. If
you want to determine the wavelength of a transverse wave, which graph should
you use? Explain
To determine the wavelength of a transverse wave, we use the graph of y-position vs. x-position.
What is a transverse wave?A transverse wave is a wave in which the direction of propagation of the wave is perpendicular to the direction of the disturbance causing the wave.
Plotting a transverse wave,
the y - direction represents the direction of disturbance of the wave, the x - direction represents the direction of propagation of the wave and t axis represents the time of travel of the waveNow, we can have two graphs namely,
position vs. time or y-position vs. x-position.Which graph will we use to determine the wavelength of a transverse wave.If we plot a cycle of each graph above, we see that position is plotted against time and y-position is plotted against x-position.
We note that the x - position is the direction of travel of the wave in which we measure its wavength. Since the wavelength is the x - position after one cycle, so, we use the graph of y-position vs. x-position to find its wavelength.
So, to determine the wavelength of a transverse wave, we use the graph of y-position vs. x-position.
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