can someone help please

The primary tool or measure for determining whether the assumed regression model is appropriate is the residual plot.

A residual plot is a graph that shows the residuals, or the differences between the observed values and the predicted values from the regression model, plotted against the predictor variable(s). If the residuals are randomly scattered around zero, with no discernible pattern, then the regression model is a good fit for the data.

However, if there is a pattern in the residuals, such as a curved or U-shaped relationship, then the regression model may not be appropriate and a different model may need to be considered.

In addition to the residual plot, other measures such as the coefficient of determination (R-squared), the p-values of the regression coefficients, and the normality of the residuals can also be used to evaluate the goodness of fit of a regression model.

However, the residual plot is often considered the primary tool for assessing the adequacy of a regression model.

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Answer:

The equation of the line of symmetry of triangle ABC is:

Step-by-step explanation:

The line of symmetry of an isosceles triangle bisects the vertex angle (the angle opposite the base) and is perpendicular to the base of the triangle.

As AB = AC, then angle A is the vertex angle of the isosceles triangle ABC.

If B and C lie on the line with equation 3y = 2x + 12, then the line of symmetry is the line that is perpendicular to this line and passes through A (4, 37).

Rearrange the given equation 3y = 2x + 12 to slope-intercept form by dividing both sides by 3:

[tex]\implies y=\dfrac{2}{3}x+4[/tex]

Perpendicular lines have slopes that are negative reciprocals of one another.  Therefore, the slope of the perpendicular line is -³/₂.

Substitute the found slope and point A (4, 37) into the point-slope formula:

[tex]\implies y-y_1=m(x-x_1)[/tex]

[tex]\implies y-37=-\dfrac{3}{2}(x-4)[/tex]

Rearrange the equation to standard form:

[tex]\implies 2y-74=-3(x-4)[/tex]

[tex]\implies 2y-74=-3x+12[/tex]

[tex]\implies 3x+2y-74=12[/tex]

[tex]\implies 3x+2y=86[/tex]

Therefore, the equation of the line of symmetry of triangle ABC is:

The probability of randomly selected patient selected for coronary, oncology or both is equal to P( H∪C ) = 0.24.

Let patient admitted with heart disease represented by P(H)

P(H) = 12%

       = 0.12

And patient admitted for cancer disease represented by P(C)

P(H) = 16%

       = 0.16

Percent of patient received both coronary and oncology = 4%

P( H∩C ) = 0.04

Probability of randomly selected patient admitted for coronary, oncology or both is :

P( H∪C ) = P(H) + P(C) - P(H∩C )

⇒P( H∪C ) = 0.12 + 0.16 - 0.04

⇒ P( H∪C ) = 0.24

Therefore, the probability of randomly selected patient getting treatment for coronary, oncology or both is given by  P( H∪C ) = 0.24.

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The profit that they will make if they have 24 dogs for adoption is given as follows:

$160.

The profit is obtained with the subtraction of the revenue by the costs.

The revenue and the costs for this problem are obtained as follows:

Hence the profit made is obtained as follows:

Profit = 45 x 24 - 920

Profit = $160.

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The equation will be:

t = b - 2

And we can see that:

Here we have two variables:

t = taner's age

b = age of Tanner's brother.

The independent variable is the one that does not depend on the other, in this case (for how it is worded) is the brother's age.

The dependent variable depends on the other, on this case, Tanner's age.

Now let's write the equation, we know that Taner's age is 2 years less than his brother, then:

t = b - 2

That is the equation.

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The required answers are

a) b = -4

b) x = 23.45

c) p = 201

The distributive property implies that multiplying a number by the sum of two or more addends yields the same result as dividing the multiplier, multiplying each addend individually, and combining the products . It can be given as,

a (b+c) = d

[tex](a*b) + (a*c) = d[/tex]

Now in the given question,

a) −1/2(b−6)= 5

by distributive property , we have

[tex](\frac{-1}{2} *b)-(\frac{-1}{2}*6 )=5\\\frac{-1}{2}b+3=5\\\frac{-1}{2}b=2\\b=-4[/tex]

b) 0.4(x−0.45)= 9.2

by distributive property , we have

0.4x - 0.4(0.45) =9.2

0.4x -0.18 = 9.2

0.4x = 9.38

x = 23.45

c) −4(p−212)=44

by distributive property , we have

-4p +4 (212) = 44

-4p + 848 =44

-4p = 44 - 848

-4p = -804

p = 201

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Answer:

(-x+2)(2x+1) — first option

Step-by-step explanation:

The rectangles represent an x, red means negative and yellow is positive.

The squares represent a unit (the number 1).

The diagram attached below demonstrates how this works.

Basically the top row of this tile equation is (-x + 2)And the column is (2x+1).

Expanding this makes -2x²+3x+2

The mean number of days to maturity for dollars invested in these five money market funds is approximately 8.95 days.

To calculate the weighted mean of the days to maturity, we need to multiply each value of days to maturity by its corresponding dollar value, sum the products, and divide the result by the total dollar value.

The calculation for the weighted mean is as follows:

Weighted Mean = (D1 x V1 + D2 x V2 + D3 x V3 + D4 x V4 + D5 x V5) / (V1 + V2 + V3 + V4 + V5)

where D represents the days to maturity and V represents the dollar value.

Using the given values, we can plug them into the formula and get:

Weighted Mean = (15 x 15 + 11 x 10 + 7 x 25 + 5 x 15 + 4 x 10) / (15 + 10 + 25 + 15 + 10)

Weighted Mean = 8.95 (rounded to two decimal places)

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Answer:

[tex]-\dfrac{4}{5}[/tex]

Step-by-step explanation:

We have the following expression

[tex]3 \;\dfrac{1}{2} x - 5\;\dfrac{1}{2}x[/tex]

and asked to evaluate this expression at  [tex]\[x = {2\over\displaystyle 5\][/tex]

First convert [tex]3 \; \dfrac{1}{2}[/tex]   and  [tex]5 \; \dfrac{1}{2}[/tex]  to mixed fractions

[tex]3 \; \dfrac{1}{2} = \dfrac{3 \times 2 + 1}{2} = \dfrac{7}{2}\\[/tex]

[tex]5 \; \dfrac{1}{2} = \dfrac{5 \times 2 + 1}{2} = \dfrac{11}{2}[/tex]

Therefore
[tex]3 \;\dfrac{1}{2} x - 5\;\dfrac{1}{2}x\\\\= \dfrac{7}{2}x - \dfrac{11}{2}x\\\\= \dfrac{7 - 11}{2} x\\\\= -\dfrac{4}{2}x \\\\= -2x\\\\[/tex]

[tex]\mathrm{For \;x =\dfrac{2}{5}},\\\\= -2x \\= - 2 \times \dfrac{2}{5}\\\\= -\dfrac{4}{5}[/tex]

The angle that the ladder makes with the ground is ∠B = 67.38°.

The distance between the ladder from the building is 5 feet.

A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.

Given that a 13-foot ladder is placed up against a wall.

The ladder's top touches the wall at a height of 12 feet.

As per the given question, we have the right triangle ΔABC

Using sine ratio to find angle ∠B as:

sin ∠B = AC/ AB

sin ∠B = 12/13

∠B = sin ⁻¹(12/13)

∠B = 67.38°

Now, using Pythagoras's theorem to find distance x as:

AC² + BC² = AB²

12² + x² = 13²

144 + x² = 169

x² = 169 - 144

x² = 25

x = 5

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The height of the flagpole is 110 feet.

There are three commonly used trigonometric identities.

Sin x = 1/ cosec x

Cos x = 1/ sec x

Tan x = 1/ cot x or sin x / cos x

Cot x = cos x / sin x

We have,

From the figure,

tan 19 = f/x

tan 21 = f/(600 - x)

Now,

tan 16 x = tan 21 x (600 - x)

0.34x = 0.38 x 600 - 0.38x

0.34x = 230 - 0.38x

0.34x + 0.38x = 230

0.72x = 230

x = 319

Now,

tan 19 = f/319

0.34 x 319 = f

f = 109.8

f = 110 feet

Thus,

110 feet is the height of the flagpole.

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Answer:

$1.89/gal

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

given sinΘ = - [tex]\frac{3}{5}[/tex] = [tex]\frac{opposite}{hypotenuse}[/tex]

the negative sign indicates sinΘ is in the third quadrant where sinΘ < 0

this is a 3- 4- 5 right triangle with opposite = 3 and hypotenuse = 5

then the adjacent side = 4

cosΘ = [tex]\frac{adjacent}{hypotenuse}[/tex] = - [tex]\frac{4}{5}[/tex] ( since cosΘ < 0 in third quadrant )

secΘ = [tex]\frac{1}{cos0}[/tex] = [tex]\frac{1}{-\frac{4}{5} }[/tex] = - [tex]\frac{5}{4}[/tex]

tanΘ

= [tex]\frac{sin0}{cos0}[/tex]

= [tex]\frac{-\frac{3}{5} }{-\frac{4}{5} }[/tex]

= - [tex]\frac{3}{5}[/tex] × - [tex]\frac{5}{4}[/tex]

= [tex]\frac{3}{4}[/tex]

In the given case where 860 observations are drawn from a bell-shaped distribution, there are 2 observations of more than 112.

Total number of observations = 860

Mean of the observations = 76

Standard deviation = 18

The amount of standard deviations by which the value of a raw score differs from or differs above the mean value of what is observed or measured is known as the z score or standard score in the z test. The z-score calculates how far an X-score deviates from the mean by standard deviations. Calculating the observations utilizing the Z- score -

Z = X - u/a

Calculating the observations -

Where X = 112 u = 76 and a = 18

Z = 112 - 76/18

= 36/18

= 2

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Using unit conversions the total height change from the top of mount Everest to the bottom of the Mariana trench is 12.3 miles

We know that 1 km = 0.62136 miles and 1 foot = 0.000189 miles

Depth of Mariana Trench (d) = 11 km = 11 × 0.62136

                                                          = 6.835 miles

Height of Mount Everest (h) = 29000 ft = 29000 × 0.000189

                                                              = 5.492 miles

Therefore the total height difference top of Mount Everest and to bottom of the Mariana Trench is given by

H = Depth of Mariana Trench + Height of Mount Everest

H = d + h

H = 6.835 miles + 5.492 miles

H = 12.327 miles

H = 12.3 miles

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The hare can afford to nap for approximately 3686.33 seconds if he does not want to lose the race.

We can use the time it takes the hare to run 100 m to determine how long he can afford to nap.

First, let's find the time it takes the hare to run the 100 m:

t = d / v

Where t is the time, d is the distance, and v is the velocity (speed) of the hare.

t = 100 m / 15 m/s

t = 6.67 s

Next, let's find the time it takes the tortoise to run 1 km (1000 m):

t = d / v

Where t is the time, d is the distance, and v is the velocity (speed) of the tortoise.

t = 1000 m / 0.27 m/s

t = 3700 s

So, the time it takes the tortoise to run the race is 3700 s. The time it takes the hare to run the first 900 m is 7 s. Therefore, the time the hare has left to nap is:

3700 s - 7 s = 3693 s

And the time it takes the hare to run the last 100 m is 6.67 s. Therefore, the hare can afford to nap for:

3693 s - 6.67 s = 3686.33 s

So, the hare can afford to nap for approximately 3686.33 seconds if he does not want to lose the race.

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Answer:

[tex]\frac{y^2}{4x^5}[/tex]

Step-by-step explanation:

Used Exponents Properties :

[tex]\blacksquare \left( a\times b\right)^{n} =a^{n}\times b^{n}\\\blacksquare \left( a^{n}\right)^{m} =a^{n\times m}\\\blacksquare \left( \frac{a}{b} \right)^{n} =\frac{a^{n}}{b^{n}}[/tex]

==========================

[tex]\begin{aligned}\left(\frac{256 \times x^{20}}{y^8}\right)^{-\frac{1}{4}} & =\left(\frac{y^8}{2^8 \times x^{20}}\right)^{\frac{1}{4}} \\& =\frac{\left(y^8\right)^{\frac{1}{4}}}{\left(2^8 \times x^{20}\right)^{\frac{1}{4}}} \\& =\frac{y^{8 \times \frac{1}{4}}}{\left(2^8\right)^{\frac{1}{4}} \times\left(x^{20}\right)^{\frac{1}{4}}} \\& =\frac{y^{\frac{8}{4}}}{2^{\frac{8}{4}} \times x^{\frac{20}{4}}} \\& =\frac{y^2}{2^2 x^5}\\& =\frac{y^2}{4 x^5}\end{aligned}[/tex]

The equation 5x + 6y = 4, 10x + 12y = 8 has infinitely many solution.

System of equation can be solved using elimination method, substitution method and graphical method.

Therefore, let's solve the system of equation using elimination method.

5x + 6y = 4

10x + 12y = 8

multiply equation(i) by 2

Hence,

10x + 12y = 8

10x + 12y = 8

subtract the equations

0 = 0

Therefore, the equation has infinitely many solution.

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Check the picture below.

so the polygon is really just a 5x7 rectangle with a triangle that has a base of 7 units(vertically) and a height of 2 units.

[tex]\stackrel{\textit{\LARGE Areas}}{\stackrel{rectangle}{(5)(7)}~~ + ~~\stackrel{triangle}{\cfrac{1}{2}(7)(2)}}\implies 35~~ + ~~7\implies \text{\LARGE 42}~units^2[/tex]

The correct option is a. The equation used to find Vanessa's age is v + 2 = 32.

A mathematical statement known as an equation utilises the equals sign to demonstrate the equality of two expressions. It may be used to address a variety of issues and can contain both numbers and variables. Algebraic operations including addition, subtraction, multiplication, division, and exponentiation are frequently used in equations.

In the given question, Vanessa's age may be calculated using the equation a. v+2=32. This equation shows that Vanessa's age plus 2 equals 32, implying that Vanessa's age is 30. We may solve this equation by removing 2 from both sides, yielding v=30. This equation is valid for determining Vanessa's age because it specifies that Vanessa's age plus Monique's age equals 32.

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Answer: 83 3/5

Step-by-step explanation:

hope this helps !! :3

Answer:

if the angle has the arrow on top pointing straight up thats a right angle if it is leaning towards the left instead it is obtuse and if is getting closer to the right side it is acute.

Step-by-step explanation:

i can't tell you anything else if there is no picture to base this question.

Answer:

83%

Step-by-step explanation:

To find the percentage divide 40 by 48

40/48 = 0.83333333333333

Round to 0.83

Multiply by 100

The patient has only eaten 83% of her daily intake.

Answer:

2x(5x+7)

Step-by-step explanation:

[tex]x^2+2x^2+14x+7x^2\\=10x^2+14x\\=2x(5x+7)[/tex]

To state the null hypothesis and alternative hypothesis for Megan's test, we need to know what type of data she will be collecting and what type of test she will be conducting.

Assuming she will be collecting data on the number of hours of sleep students are getting and conducting a one-tailed hypothesis test, the following are possible null and alternative hypotheses:

a.) Null hypothesis: The average amount of sleep students are getting is equal to or greater than eight hours per night.

Alternative hypothesis: The average amount of sleep students are getting is less than eight hours per night.

b.) Null hypothesis: Less than or equal to 50% of students are getting less than eight hours of sleep per night.

Alternative hypothesis: More than 50% of students are getting less than eight hours of sleep per night.

c.) Null hypothesis: There is no difference in the proportion of students getting less than eight hours of sleep between two groups (e.g., males vs. females, freshmen vs. seniors, etc.).

Alternative hypothesis: There is a difference in the proportion of students getting less than eight hours of sleep between two groups.

d.) Null hypothesis: The number of students getting less than eight hours of sleep is equal to or greater than a certain value (e.g., 30%).

Alternative hypothesis: The number of students getting less than eight hours of sleep is less than the specified value.

Note that in each case, the null hypothesis represents the status quo or the default assumption, while the alternative hypothesis represents Megan's research question or hypothesis. The choice of null and alternative hypotheses depends on the research question, the data being collected, and the type of hypothesis test being conducted.

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Answer:

37

Step-by-step explanation:

AAA   1 way

AAB, AAC, AAD      3 ways each     3*3=9  ways

ABB, ACC, ADD      3 ways each     3*3=9 ways

ABC, ABD, ACD       3*2=6 ways each     3*6=18ways

1+9+9+18 = 37 ways

The probability that the first box was the one selected given that the marble is white is [tex]\frac{7}{12}[/tex] .

Probability is the likelihood that an event will occur.

The likelihood of an occurrence A provided that an earlier event B has already happened is known as conditional probability.

the two boxes are marked as B1, B2

Number of black balls: 1

Number of white balls: 1

Number of black balls in the box: 2,

Number of white balls: 1.

B and W should stand for black and white marble.

Therefore, the likelihood that either box will be selected is [tex]\frac{1}{2}[/tex]

Probability of selecting a black ball from a box: [tex]\frac{1}{2}[/tex]

Probability of selecting a black ball from a box: [tex]\frac{2}{3}[/tex]

To determine: the likelihood that the marble is black.

Solution:

The likelihood that the marble being black is equal to

[tex]\frac{1}{2} (\frac{1}{2} ) + \frac{1}{2} (\frac{2}{3} )\\= \frac{7}{12}[/tex]

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The average rate of change of f(x) over the interval 3≤x≤4 is 15

From the question, we have the following parameters that can be used in our computation:

The table of values

On the table, we have

f(3) = -4

f(4) = 11

The average rate is then calculated as

Average rate = [f(4) - f(3)]/[4 - 3]

Substitute the known values in the above equation, so, we have the following representation

Average rate = (11 + 4)/(4 - 3)

Evaluate

Average rate = 15

Hence, the average rate is 15

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Complete question

Given the function defined in the table below, find the average rate of change, in simplest form, of the function over the interval 3\le x \le 43≤x≤4.

X f(x)

3 -4

4 11

5 8

6 10

7 11

8 14

Answer:

8

Step-by-step explanation:

8x3 = 24

24 + 4 = 28

(a) The number of possible schedules that the student can create from the offerings is 96.

(b) the number of possible schedules that the student can create from the offerings if two of the math 100 sections are closed is 48.

(c) the number of possible schedules that the student can create from the offerings if two of the math 100 sections and four of the English 105 sections are closed is 4.

(a) To find the total number of possible schedules, we need to multiply the number of choices for each class:

Number of schedules = 4 x 2 x 3 x 4 = 96

So, there are 96 possible schedules that the student can create from the offerings.

(b) If two of the math 100 sections are closed, then there are only two choices for that class. So, we have:

Number of schedules = 2 x 2 x 3 x 4 = 48

So, there are 48 possible schedules that the student can create from the offerings with two of the math 100 sections closed.

(c) If two of the math 100 sections and four of the English 105 sections are closed, then there are only two choices for math 100 and one choice for English 105. So, we have:

Number of schedules = 2 x 2 x 1 x 1 = 4

So, there are 4 possible schedules that the student can create from the offerings with two of the math 100 sections and four of the English 105 sections closed.

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