Can someone solve this?
25^2x-3=125^x+1

Answer:

im not so sure but here what i got

Step-by-step explanation:

(252)(x)−3=125x+1

125x=625x−4

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WILL GIVE 50 BRAINLY POINTS!!
PLEASEEE HELPPP ASAAPP WILL

Which equation justifies why ten to the one third power equals the cube root of ten?

A. to the one third power all raised to the third power equals ten to the one third plus three power equals ten
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C. ten to the one third power all raised to the third power equals ten to the three minus one third power equals ten
D. ten to the one third power all raised to the third power equals ten to the one third minus three power equals ten

plssss help giving brainly

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Look at the graph.

On a coordinate plane, a graph increases through (negative 1, 4), levels off at (0, negative 3), and then increases up through (2, 5).

Leslie analyzed the graph to determine if the function it represents is linear or non-linear. First she found three points on the graph to be (–1, –4), (0, -3), and (2, 5). Next, she determined the rate of change between the points (–1, –4) and (0, -3) to be StartFraction negative 3 minus (negative 4) Over 0 minus (negative 1) EndFraction = StartFraction 1 Over 1 EndFraction = 1. and the rate of change between the points (0, -3) and (2, 5) to be StartFraction 5 minus (negative 3) Over 2 minus 0 EndFraction = StartFraction 8 Over 2 EndFraction = 4. Finally, she concluded that since the rate of change is not constant, the function must be linear. Why is Leslie wrong?
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The expressions StartFraction negative 3 minus (negative 4) Over 0 minus (negative 1) EndFraction and StartFraction negative 3 minus (negative 5) Over 2 minus 0 EndFraction both equal 1.
She miscalculated the rates of change.
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Sian gets 3 chocolate bars from the shop using this offer.
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Hi. I need help with this question :

Question : y is such that
[tex]4y - 7 \leqslant 3y[/tex] and
[tex]3y \leqslant 5y + 8[/tex]:
I). What range of values satisfies both inequalities ?
II). Hence, express
[tex]4y - 7 \leqslant 3y \leqslant 5y + 8[/tex]
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[tex]a \leqslant y \leqslant b[/tex]
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Please show workings.

​

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