The probability that at least 20 of the novels have fewer than 400 pages is given as follows:
0.0823 = 8.23%.
How to obtain probabilities using the normal distribution?The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution, depending if the obtained z-score is positive or negative.Using the z-score table, the p-value associated with the calculated z-score is found, and it represents the percentile of the measure X in the distribution.The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with [tex]\mu = np, \sigma = \sqrt{np(1-p)}[/tex].The parameters for the binomial distribution are given as follows:
p = 0.3, n = 50.
Hence the mean and the standard deviation for the approximation are given as follows:
[tex]\mu = 0.3 \times 50 = 15[/tex][tex]\sigma = \sqrt{0.3 \times 0.7 \times 50} = 3.24[/tex]Using continuity correction, the probability that at least 20 of the novels have fewer than 400 pages is P(x > 19.5), which is one subtracted by the p-value of Z when X = 19.5, hence:
Z = (19.5 - 15)/3.24
Z = 1.39
Z = 1.39 has a p-value of 0.9177.
1 - 0.9177 = 0.0823 = 8.23%.
More can be learned about the normal distribution at https://brainly.com/question/25800303
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