(choose )
Ramy covered a distance 3080 cm on foot. This distance is equivalent to.........


a) 0.03Km + 80cm

b) 0.3Km +8cm

c) 3Km + 8cm

d) 30Km + 80cm​

The watercraft with an initial velocity of 6.4 m/s and an average acceleration of 2.0 m/s2 [s] for 2.5 s will have a final velocity of: 11.4 m/s

The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

vf = vi + (a* t)

Where:

Information about the problem:

Applying the final velocity formula, we have:

vf = vi + (a* t)

vf = 6.4 m/s + (2.0 m/s²* 2.5 s)

vf = 6.4 m/s + 5 m/s

vf = 11.4 m/s

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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Answer:200N,  

Explanation:

the hammer exerts a force nail, then the nail will exert a force of equal magnitude and opposite direction back on the hammer.

The nail put back a force of 200 N on the hammer in opposite direction.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given that; hammer puts a force of 200 N on a nail.

According to Newton's Third Law of motion, every action has equal and opposite reaction.

So, the nail put back a magnitude of 200 N force on the hammer in opposite direction.

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Some of the coal's energy was turned into other forms of energy.

According to the first law of thermodynamics, energy can neither be created nor destroyed but is converted from one form to another. We know that from the first law of thermodynamics, the energy that originally in the coal does not  vanish into thin air but undergoes a conversion.

Thus, want to find out what accounts for the energy of the coal. Thus, we could say that some of the coal's energy was turned into other forms as this is in consonance with the first la of thermodynamics.

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A cylinder initially contains a liquid-vapor mixture of water. water has a total mass of 10 kg and a quality factor of x1= 0.8.

Numerous variables, including the quantity of salt (or salinity), bacteria levels, dissolved oxygen concentrations, and the number of debris suspended in the water, are used to determine the quality of water (turbidity). The individual index values of some or all of the parameters within the five categories of water quality parameters are averaged to create the WQI. Turbidity (NTU*) of the water and/or Secchi disk depth (in meters or feet); Oxygen that has been dissolved: Oxygen concentration in milliliters. They consist of nutrients, pH, temperature, salinity, and dissolved oxygen (nitrogen and phosphorus). One of the most crucial elements of water management is the assessment and management of water quality. With increasing worries and understanding about the effects on the environment and public health, this has gained substantial worldwide significance throughout time.

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The addition operation of the given figures is determined as 19.95 m in 4 significant figure.

A significant figure is a figure or a digit that contributes to how accurately something can be measured.

The given values;

2 m ------> 1 significant figure

9.35 m ---------> 3 significant figure

8.6 m -------------> 2 significant figure

Addition operator in mathematics is denoted by the symbol "+" and it implies summing the giving digits together.

2 m + 9.35 m + 8.6 m = 19.95 m (4 significant figure).

Thus, the addition operation of the given figures is determined as 19.95 m in 4 significant figure.

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The weight of steel can be pulled across a concrete floor by a winch with a capacity of 450 lbs to 1500 lb.

Around 7850 kg/m3, or 7.85 g/cm3, or 490 lbs/ft3, or 13231 lbs/yd3, is the unit weight of steel. The primary usage of the steel bars is as reinforcement to increase the tensile strength of concrete constructions. The weight of steel is typically expressed in kilogrammes, tonnes, and pounds.

Calculate the amount of steel in the slab as 1% of the concrete volume (0.01 x 7850 x 3 = 236kg):

Using the Thumb Rule Given that steel has a density of 7850 kg/m3, the amount of steel needed for an RCC slab should be 1% of the entire volume of concrete, or 236 kg.

The unit weight of structural steel is taken to be 7850 kg/m3 or 78.50 kN/m3 or 7.85 g/cm3 or 490 lbs/ft3 or 13,231 lbs/yd3 according to IS code and Indian standard.

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Complete Question -

(a) A car speedometer has a 5.0% uncertainty. What is the range of possible speeds when it reads 90 km/h? (b) Convert this range to miles per hour. (1 km=0.6214 mi)

a) 94.5 km/h to 85.5km/h

b) 58.7 mi/h to 53.1 mi/h

v = 67.0 km/h

dv/v %  = 5

dv/v = 0.05

dv= 0.05 * 67

dv = 3.35

lowest speed = v- dv

= 67-3.35

=63.65

so upto 1 decimal lowest speed is 63.6

highest speed = v +dv

= 67 + 3.35

= 70.35

so highest  speed  upto 1 decimal = 70.9

lowest speed = 63.6 km/h

= 63.6 * 5/18

= 17.1 m/s ( upto 1 decimal)

highest speed = 70.9 km/h

= 70.9 * 5/18

=19.1 m/s ( upto 1 decimal}

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The percentage of its surface area would be covered by glucose transporters is 100%.

As the cell is nearly spherical, the surface area of a cell with a diameter of 2.0 mm is equal to

A= 4πr^2 = 4 pi 1 x (10^-3)^2= 12.5 x 10^-6 m^2.

The area occupied by glucose transporters is approximately 12 nm^2 or 1.2 x 10^-6 m^2.

So, the %age of area covered by glucose transporters = Surface area of the cell/ Area occupied by glucose transporters= 12.5 x 10^-6 m^2/1.2 x 10^-6 m^2 x 100 = 100%.

Thus, the percentage of its surface area that would be covered by glucose transporters is 100%.

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We need photons of wavelength 0.0177 nm

When photons interact with matter, there are four competing processes. Compton scattering is one of them.

A photon can be completely absorbed, and its energy can eject an electron from its host atom at energies of a few eV to a few keV, which correspond to visible light through soft X-rays. This phenomenon is known as the photoelectric effect.

The Compton effect was discovered by Arthur Compton.

The Compton effect is the lengthening of electron-scattered X-ray and other electromagnetic wave wavelengths. It is the fundamental process by which matter absorbs radiating energy.

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The vehicle took 2.6 seconds to accelerate.

Acceleration is the rate at of change of velocity. It is a vector quantity. That is, it has both magnitude and direction.

Given that a vehicle accelerates to 22.60 m/s after being stopped at a red light. The vehicle travels 29.46 m while accelerating from the intersection. How fast was its acceleration?

The parameters to be considered are:

Let us first calculate the acceleration by using the formula

v² = u² + 2as

22.6² = 0 + 2 × a × 29.46

510.76 = 58.92a

a = 510.76 / 58.92

a = 8.67 m/s²

Now, we can know how fast was its acceleration by using the formula

v = u + at

22.6 = 0 + 8.67 × t

22.6 = 8.67t

t = 22.6 / 8.67

t = 2.61 s

Therefore, the vehicle took 2.6 seconds to accelerate.

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When burned with just the stoichiometric amount of air, under conditions where no heat is lost, the temperature range in which it will produce flames is around 2100 K to 2300 K.

Stoichiometric combustion, in which all available oxygen is fully used, is burning without excess or lack of air. The general equation of a stoichiometric combustion can be determined by presuming that nitrogen reacts in extremely small amounts and is discovered after combustion in molecule form.

Stoichiometric or theoretical air is the smallest amount of air required for a fuel to burn completely. Stoichiometric combustion theoretically gives the ideal fuel to air ratio, which reduces losses and gets all of the energy from the fuel; but, in practice, stoichiometric combustion is not possible due to a variety of different variables.

Since heat losses are unavoidable, 100% efficiency is not possible.

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The properties of aluminum are as follows:

Elements are pure substances which are composed of the same type of atoms.

Elements are the building block of all forms of matter.

Aluminum one of the known 118 elements.

In the period table, aluminum has the following properties:

In conclusion, aluminum is an element in the periodic table.

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A diode that has the iso=10 fa and a built-in voltage of 0.8 v, its reverse basis for 10v is 36.7fA

As rectifiers, signal limiters, voltage regulators, switches, signal modulators, signal mixers, signal demodulators, and oscillators, diodes are a versatile electrical component.

A diode’s propensity to transmit electric current solely in one direction is its fundamental characteristic.

An electrical device with two terminals is a diode. A semiconductor, most frequently silicon but occasionally germanium, is used to create diodes.

There are many different kinds of diodes, but the ones being addressed here include the silicon-controlled rectifier, TRIAC, transient voltage suppressor, Zener, rectifier, and Schottky diodes.

A diode’s most frequent use is to permit an electric current to flow in one direction while blocking it in another. This is known as the diode’s forward direction.

It is provided that

Vr = 10V

ϕj = 0.8 V

Iso = 10fA

The reverse current Is

Is = Iso sqrt [1 + Vr/ϕj]  → 1

Substituting all the values provided in question to equation 1, we have

Is = 10fA sqrt (1+10/0.8)

=(10fA) sqrt (13.5)

= 36.7fA

Thus Is = 36.7fA

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The average acceleration of the ball, while it is in contact with the wall, is -3969.27 m/s².

Acceleration is the rate of change of velocity per unit of time. Its S.I. unit is m/s². It is equal to the change in velocity divided by the time taken to change the velocity.

Acceleration a =  Change in velocity/ Time taken

Given in the question

Initial Velocity = u = + 20.6 m/s ( towards the wall is positive direction )

Final Velocity = v = - 11.948 m/s (away from the wall is negative direction)

Change in Velocity = Final Velocity - Initial Velocity

                                = (- 11.948) - ( + 20.6)

                                = -11.948 - 20.6

                                = -32.548 m/s

So Change in velocity = 32.548 m/s

Time Taken = Time of contact with the wall

                    = 0.0082 seconds

Put in the Formula: a =  Change in velocity/ Time taken

a = -32.548/0.0082

a = -3969.27 m/s²

Therefore the average acceleration of the ball, while it is in contact with the wall, is -3969.27 m/s².

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Yes, it is correct to say that if no net impulse is exerted on a system, then no change in the momentum of the system will occur.

Impulse is defined as the instantaneous force applied to the object for a very short duration. It is given by the product of force and time. The expression of the impulse is given by

I =  F × t where ,

F is the force

t is the time

The impulse is also defined as the change in the momentum of the object, that is,

[tex]I=Pf-Pi[/tex] where [tex]Pf[/tex] is the final momentum of the object [tex]Pi[/tex] is the initial momentum of the object

Hence, if the net impulse is zero, therefore

0=[tex]Pf[/tex]=[tex]Pi[/tex]

[tex]Pf[/tex]=[tex]Pi[/tex]

hence the momentum of the object will also not change.

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The distance traveled by the puck is 0.203 m.

This can be defined as the length between two points.

To calculate the distance which the puck accelerate, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the distance traveled by the puck is 0.203 m.

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The torque about the origin if the force points in (a) the x direction, (b) the y direction, and (c) the z direction are 12; 36; 37.9 respectively

Torque is a twisting force produced by applying a force at a distance from a point. We would need to choose a distance that is perpendicular to the force's direction. We apply the equation to determine torque,

T=Fd

where F is the force and d is the orthogonal distance to a central point.

i. If the force points in the x-direction, we need to use the y-distance to calculate torque.

T=Fxdy

T=12N *1m

T = 12 N.m

ii. If the force points in the y-direction, we need to use the x-distance to calculate torque.

T=Fxdy

T= 12N * 3m

T = 36 N.m

iii. If the force is directed in the z-direction, the straight-line distance from the origin to the point is orthogonal to the force. The magnitude of the distance will be used as the distance value. This may be determined using the equation.

||d||= √ (X2 + Y2)

where X and Y are the x and y coordinates.

T=Fz||d||

T=(12N) (√ (32 + 12)

T = 37.9 N.m

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When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet exhibits retrograde motion.

What do you mean by retrograde motion?

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When the magnitude remains came and the direction changes the particle is moving in a circular motion. Speed is equal to the arc length traveled (S) divided by the change in time (Δ),

A particle travels in a uniform circular motion while maintaining a constant speed. The radius R of the circle sweeps out the angle, and the particle's velocity vector v in the illustration has a constant magnitude but changes direction as it advances from location B to position C.

The isosceles triangles OBC and DEF are identical because OB and OC are perpendicular to the velocity vectors, and as a result, the ratio of the chord BC to the radius R is the same as the ratio of the magnitudes of v to v. The chord BC and the arc BC approach one another as approaches zero, and the chord can be replaced by the arc in the ratio.

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The stopping distance for a car traveling at a velocity of 20 m/s and acceleration of -4 m/s^2 is 50 m.

The above situation is a case of motion in one dimension, which is governed by the following equations,

V = u + at ..........(i)

V^2 - u^2 = 2as ..........(ii)

S = ut + 1/2 at^2 .........(iii)

As we are given the initial velocity, the final velocity, and the acceleration, therefore we have to apply the second equation to get the answer

v^2 - u^2 = 2as

Here v is the final velocity = 0 m/s

u is the initial velocity = 20 m/s

a is the acceleration = -4 m/s^2

And s is the distance traveled by car

Putting the given values in the above equation,

(0) ^2 - (20)^2 = 2(-4)s

-400 = -8s

S = 50 m

Hence, The stopping distance for a car traveling at a velocity of 20 m/s and acceleration of -4 m/s^2 is 50 m.

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The reason why the micropipette must be calibrated with oleic acid solution and not with water is that Oleic acid can spread out unlike water. Hence, the drop volume will be different skewing the volume.

Oleic acid does have the characteristic of spreading out across a monolayer with a measurable thickness. Water, on the contrary hand, contains a variety of drop sizes, which skews the volume and thus affects the calibration. Because of this, oleic acid is recommended.

Water repels the non-polar chain (it is hydrophobic), while water attracts the polar end (hydrophilic). A very dilute oleic acid solution in pentane shall be used. The pentane evaporates quickly, leaving behind a thin layer of plain oleic acid.

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Answer:

Доброе утро, ответ 5+5="4

Explanation:

The entropy change when 2.00 kg of water at 100°C is heated to form steam at 100°C is 12.1kJ/K.

Entropy is a metric for a system's unpredictability or disorder. The mass of a system affects the value of entropy. It has units of joules per kelvin and is represented by the letter S. The value of entropy can be either positive or negative.

Total energy change = latent heat of of vapourization × mass

Total energy change = [tex]2.26[/tex] × [tex]10^{6}[/tex] × 2

Total energy change = 4520kJ

Now, entropy change is given as:

Δ[tex]S = \frac{Total energy change}{Temperature}[/tex]

Δ[tex]S = \frac{4520}{273.15+100}[/tex]

Entropy = 12.1kJ/K

Therefore, the entropy change when 2.00 kg of water at 100°C is heated to form steam at 100°C is 12.1kJ/K.

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The electromagnetic energy emitted by an excited sodium atom is 3.47 x 10¯¹⁹ joules.

We need to know about electromagnetic energy to solve the problem. The electromagnetic energy of radiated photons can be calculated by wavelength. It can be determined as

E = h . c / λ

where E is energy, h is Max Planck's constant (6.6 x 10¯³⁴ Js), c is the speed of light (3 x 10⁸ m/s) and λ is the wavelength.

From the question above, the given parameter is

λ = 570 nm = 570 x 10¯⁹ m

By using the equation, we can calculate the energy generated from an sodium atom

E = h . c / λ

E = 6.6 x 10¯³⁴ . 3 x 10⁸ / 570 x 10¯⁹

E = 3.47 x 10¯¹⁹ joules

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Answer:

V = IR

V = voltage = 9 volts

I = current

R = resistance = 18 ohms

V = IR

9 = I·18

By using Hooke's Law, the spring constant is 0.62 lb/ft.

We need to know about Hooke's Law to solve this problem. Hooke's Law describes the force applied to spring (elastic materials) will proportional to spring constant and displacement under the elastic condition. It can be described as

F = k . x

where F is force, k is spring constant and x is displacement.

From the question above, we know that

F = 8 lb

x = 13 ft

By substituting the given parameters, we get

F = k . x

8 = k . 13

k = 8/13

k = 0.62 lb/ft

Hence, the spring constant is 0.62 lb/ft.

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The aqueous solution with a ph of 2.00 is diluted from 1.0 l to 3.0 l.The ph of the diluted solution will be 2.48.

The pH serves as a gauge for a solution's acidity or alkalinity, as well as its hydrogen ion concentration. The pH scale typically ranges from 0 to 14. Acidic aqueous solutions at 25 °C are those with a pH below 7, and basic or alkaline solutions are those with a pH above 7.

Anything that is acidic is below 7.0, while everything that is alkaline or basic is above 7.0. A pH scale that lists the pH values of common substances and ranges from 0 (extremely basic/alkaline) to 14 (very basic/alkaline).

A solution's pH is a significant indicator of its chemical composition. The pH can affect how readily available nutrients are, how biological processes work, how bacteria behave, and how chemicals behave.

Aqueous solutions are made up of water and one or more dissolved materials. Solids, gases, or other liquids can all dissolve in an aqueous solution.

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The stopping distance of the car is 49.9 m

The following data were obtained from the question:

The stopping distance can be obtained as illustrated below:

v² = u² + 2as

0² = 25.28² + (2 × -6.4 × s)

0 = 639.0784 - 12.8s

Collect like terms

-12.8s = 0 - 639.0784

-12.8s = -639.0784

Divide both sides by -12.8

s = -639.0784 / -12.8

s = 49.9 m

Thus, the stopping distance of the car is 49.9 m

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The density of cheese is 1.33 g/cm³ or 1.33 g/mL.

We need to know about the density to solve this problem. Density is a unit that measures how dense an object is. Density can be measured by dividing mass by volume. It can be written as

ρ = m / V

where ρ is density, m is mass and V is volume

From the question above, we know that

m = 44 g

V = 33 cm³

As we know that 1 cm³ is equal to 1 ml, hence the answer will be the same.

By substituting the following parameters, we get

ρ = m / V

ρ = 44 / 33

ρ = 4/3

ρ = 1.33 g/cm³

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